The conditions for the continuity of a functions requires the function to be defined at a point. The specified function is not defined at x = π. Therefore, the reason why the function is discontinuous is first option
Condition 2 fails; f(π) does not exist
What are the conditions for the continuity of a function?The conditions for a function to be continuous at a point are;
The function must be defined at the point; f(a) existsThe limit of the function must exist at the point; \(\lim\limits_{x \to a}\) f(x) existsThe value of the limit at the point is equivalent to the value of the function at the point; f(a) = \(\lim\limits_{x \to a}\) f(x)The specified piecewise function can be presented as follows;
f(x) = sin(x), x < π, f(x) = tan(x), x > π
The above function is not defined for x = π, therefore, f(π), does not exist, and first condition above, and condition 2 in the option fails
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What is the cardinal number of the set containing all negative integers greater than −8?
Answer: positive 7
Step-by-step explanation:
Cardinal number of the set containing all negative integers greater than −8 is 7.
What are cardinal number?In mathematics,cardinal numbers or cardinals for short, are generalization of the natural numbers used to measure the cardinality of sets. The cardinality of a finite set is a natural number: the number of elements in the set.
Now the given set is all negative integers greater than -8.
Let S be the set,so
S = {-7,-6,-5,-4,-3,-2,-1}
now to find the cardinality, we see that set S has 7 elements.
Cardinality of Set S is 7.
Hence, cardinal number of the set containing all negative integers greater than −8 is 7.
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\(\frac{x+4}{3} =7\)
\(\dfrac{x+4}{3} =7\)
Multiply both sides by 3:
\((\dfrac{x+4}{3} )\times3=(7)\times3\)
\(x+4=21\)
Subtract 4 from both sides:
\(x+4-4=21-4\)
\(\boxed{x=17}\)
What is the magnitude (size) of 3.7
No links please…. NEED HELP!!!
Problem 1. (Solution of Linear System of Equation) Describe the solution of the following linear system of equations in parametric vector form x1+2x2+3x3 = 6
4x1+5x2+6x3 = 15
The required parametric vector form of the given linear System of Equation solution is given by x1 = (3 + 2t)/2 , x2 = t , x3 = (3 - 2t)/2.
System of linear equations is equals to,
x1 + 2x2 + 3x3 = 6
4x1 + 5x2 + 6x3 = 15
In augmented matrix as,
\(\left[\begin{array}{cccc}1&2&3|6\\4&5&6 |15\\\end{array}\right]\)
Use row operations to transform the augmented matrix into row echelon form or reduced row echelon form,
To get the solutions to the system of equations.
Using row operations,
Subtract four times the first row from the second row to get,
\(\left[\begin{array}{cccc}1&2&3|6\\0&-3&-6 |-9\\\end{array}\right]\)
Further simplify the matrix by dividing the second row by -3,
\(\left[\begin{array}{cccc}1&2&3|6\\0&1&2 |3\\\end{array}\right]\)
Now, use back substitution to solve for the variables.
Starting from the last equation, we have,
2x3 = 3 - x2
Substituting this into the first equation, we have,
x1 + 2x2 + 3(3 - 2x2)/2 = 6
⇒2x1 + 4x2 + 9 - 6x2 = 12
⇒ 2x1 - 2x2 = 3
⇒x1 = (3 + 2x2)/2
Solution of the system of equations in parametric vector form is,
x1 = (3 + 2t)/2
x2 = t
x3 = (3 - 2t)/2
where t is any real number.
Therefore, the parametric vector form of the system of equation is equal to x1 = (3 + 2t)/2 , x2 = t , x3 = (3 - 2t)/2.
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The mug is 5/8 full, the mug contains 3/4 of water find the capacity of the mug
The capacity of the mug is 1.2. The capacity of the mug can be found by using the equation C = (3/4) ÷ (5/8).
What is capacity?It is the maximum amount of output that can be produced in a given period of time. Capacity is usually expressed in terms of units per unit of time, such as gallons per minute or passengers per hour.
In this equation, 3/4 represents the amount of water in the mug, and 5/8 represents the amount the mug is full.
Let the capacity of the mug be x.
Given,
Mug is 5/8 full and contains 3/4 of water
So, 5/8 of the mug is filled with water
Therefore,
5/8 of x = 3/4
(5/8 )x = (3/4)
x = (3/4) × (8/5)
x = (24/20)
x = 1.2
Therefore, the capacity of the mug is 1.2.
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The state population for the year was 20 million live births in the same year total of 324,600 deaths were as follows fetal deaths 3244 neonatal death 2200 Post neonatal doves 2700 and infant deaths 4900 calculate the post neonatal mortality rate for the year
The post-neonatal mortality rate for the year is 1.1×10⁻⁷.
What is the post-neonatal mortality rate?The post-neonatal mortality rate in a year is applicable when the death day lies between 28 and 364. First, divide the number of post-neonatal deaths by the number of live births. Then multiply the obtained value by 1000 to get the post-neonatal mortality rate.
It is known that 1 billion units = 10⁹ units. So, 20 billion live births will be 20×10⁹ live births. Also, the number of post-neonatal deaths is 2200.
So, use the formula, post-neonatal mortality rate = (the number of post-neonatal deaths)/(the number of live births).
post-neonatal mortality rate = 2200/(20×10⁹)
= 110×10⁻⁹
= 1.1×10⁻⁷
Therefore, the obtained answer is 1.1×10⁻⁷.
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PLEASE HELP 40 POINTS!!! For what value of x is line a parallel to line b?
Enter your answer in the box.
x =
Answer: 22
Step-by-step explanation:
Answer:
22
Step-by-step explanation:
Don't worry, don't worry child. Oh, geometry. How lucky are you: finally knowing this treasury of humanity. I'm jealous now. Haha.
In the annex, you can see what is happening :)
Look that, if a and b are paralels, 4x + 28 is External Alternate of the Opposite Vertex of 116, which is also 116. Then, they have the same value: 4x + 28 = 116.
If you don't remember those concepts, review the initial part of geometry. The proof of that is quite simply, moreover is easy to mentally deduce that.
Question 1 of 17
W
Given a sphere with a radius of 3 cm, find its volume to the nearest whole
number.
O A. 38 cm3
B. 113 cm3
C. 13 cm3
D. 36 cm3
Answer:
B. 113 cm^3
Step-by-step explanation:
marcels financial goal is to purchase a house to make Marcels financial goal of purchasing a house a specific goal he can
Marcel can set a goal of purchasing the house in 5 years. The timeframe Factor enables Marcel to work towards his financial goal within a specified period.
Marcel's financial goal is to purchase a house. To make Marcel's financial goal of purchasing a house a specific goal, he can identify the following factors:
Specificity: Marcel should specify the type of house he wants to purchase. This includes the size of the house, the number of rooms, the location, the neighborhood, and the amenities he wants in the house. For instance, Marcel can specify that he wants to purchase a 3-bedroom bungalow house located in a suburban area.
Measurability: Marcel should identify how much money he needs to purchase the house. This means that he should set a financial target that he wants to achieve to be able to purchase the house. For instance, Marcel can set a target of saving $100,000 in 3 years to purchase the house. The measurability factor enables Marcel to track his progress toward achieving his financial goal.
Attainability: Marcel should set a financial goal that is achievable based on his income and financial situation. For instance, if Marcel's current income cannot enable him to save $100,000 in 3 years, he can adjust his financial goal to suit his financial situation.
Realistic: Marcel should set a realistic financial goal that he can achieve given his resources and time frame. For instance, Marcel should not set a financial goal that is too high that he cannot achieve it or too low that it does not challenge him.
Time-bound: Marcel should set a timeframe within which he wants to achieve his financial goal. This means that Marcel should set a specific date by which he wants to purchase the house.
For instance, Marcel can set a goal of purchasing the house in 5 years. The timeframe factor enables Marcel to work towards his financial goal within a specified period.
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If ZACD = ZBCD, which of the following relationships can be proved andwhy?ABDO A. AACD = ABCD, because of SAS.B. AACD = ABCD, because of AAS.There is not enough information to prove a relationship.D. AACD - ABCD, because of ASA.
If angle ACD is congruent to angle BCD, then angle CAD is congruent to angle DBC as both triangles are right triangles. We know that the triangles share side CD. We also know that angle ACD is congruent to angle BCD and angle CDA is congruent to CDB. Then, we can prove that both triangles are congruent using the ASA theorem. The answer would be the option D.
HELP ME SOLVE THUS PLEASE! 50 POINTS WILL BE REWARDED!!!!
Solve the equation for x.
2(x−1)/4=2(x+8)/13
Answer:
x=5
Step-by-step explanation:
2(x−1)/4=2(x+8)/13
Step 1: Cross-multiply:
2(x−1)*(13)=2(x+8)*(4)
26x−26=8x+64
Step 2: Subtract 8x from both sides.
26x−26−8x=8x+64−8x
18x−26=64
Step 3: Add 26 to both sides.
18x−26+26=64+26
18x=90
Step 4: Divide both sides by 18.
18x/18= 90/18
x=5
~Hope this helps~
\( \huge \boxed{\mathbb{QUESTION} \downarrow}\)
\( \tt\frac { 2 ( x - 1 ) } { 4 } = \frac { 2 ( x + 8 ) } { 13 } \\ \)
\( \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}\)
\( \tt\frac { 2 ( x - 1 ) } { 4 } = \frac { 2 ( x + 8 ) } { 13 } \\ \)
Cross multiply the equations on both sides.
\( \tt13\times 2\left(x-1\right)=4\times 2\left(x+8\right) \)
Multiply 13 and 2 to get 26.
\( \tt26\left(x-1\right)=4\times 2\left(x+8\right) \)
Use the distributive property to multiply 26 by x-1.
\( \tt26x-26=4\times 2\left(x+8\right) \)
Multiply 4 and 2 to get 8.
\( \tt \: 26x-26=8\left(x+8\right) \)
Use the distributive property to multiply 8 by x+8.
\( \tt \: 26x-26=8x+64 \)
Subtract 8x from both sides.
\( \tt \: 26x-26-8x=64 \)
Combine 26x and -8x to get 18x.
\( \tt \: 18x-26=64 \)
Add 26 to both sides.
\( \tt \: 18x=64+26 \)
Add 64 and 26 to get 90.
\( \tt \: 18x=90 \)
Divide both sides by 18.
\( \tt \: x=\frac{90}{18} \\ \)
Divide 90 by 18 to get 5.
\( \boxed{ \boxed{ \bf \: x=5 }}\)
Find the product of (4z2 + 7z – 8) and (–z + 3).
The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 +
z2 +
z – 24.
Answer:
-4z^3 + 5z^2 + 29z -24
Step-by-step explanation:
(4z^2 + 7z-8) (-z+3)
would equal -4z^3 + 12z^2 - 7z^2 + 21z + 8z - 24
and simplified to -4z^3 + 5z^2 + 29z -24
Answer:
5
29
Step-by-step explanation:
93°
65°
m
X
finding the angle of x
The measure of angle C is,
⇒ x = 22°
We have to given that,
In a triangle ABC,
Angle A = 65 degree,
Angle B = 93 degree.
Now, Let us assume that,
Measure of angle C = x
Hence, We get;
⇒ ∠A + ∠B + ∠C = 180°
Substitute all the values,
⇒ 65 + 93 + x = 180
⇒ 158 + x = 180
⇒ x = 180 - 158
⇒ x = 22
Therefore, The measure of angle C is,
⇒ x = 22°
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Complete question is,
In Triangle ABC, Angle A = 65 degree, B=93 degree. Find Angle C?
Find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer below.
Answer:
2,044
Step-by-step explanation:
S9=G1 (1r^n)/1-r
G9=G1r^8, r=2
S9=(4)(-511)/-1=2,044
Answer: 2,044
Step-by-step explanation:
I just took the quiz!
Let h=vo^2/4.9 sin 0 cos 0 model the horizontal distance in meters traveled by a projectile. If the initial velocity is 44 meters/ second, which equation would you use to find the angle needed to travel 150 meters?
The equation that would be used to find the angle needed to travel 150 meters is 150 = 197.55 sin (2θ).
option D.
What is the equation of the horizontal motion of the projectile?The equation that would be used to find the angle needed to travel 150 meters is calculated as follows;
h = (v₀²/4.9) sinθcosθ
where;
v₀ is the initial velocity = 44 m/sSubstitute the value of v₀ in the given equation;
h = (44²/4.9) sinθcosθ
h = 395.1 sinθcosθ
In trig identity, 2sinθcosθ = sin (2θ)
h = ¹/₂ [395.1 (2sinθcosθ)]
h = ¹/₂ [395.1 sin (2θ)]
h = 197.55 sin (2θ)
150 = 197.55 sin (2θ)
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Find the z-scores for the two normally distributed random variables, measured using different units of length.
a) x = 22 in, where X comes from N (15, 2.5)
b) y = 55.88 cm, where Y comes from N (38.1, 6.35)
Using the normal distribution, the z-scores are given as follows:
a) Z = 2.8.
b) Z = 2.8.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean \(\mu\) and standard deviation \(\sigma\) is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.Item a:
The parameters are:
\(\mu = 15, \sigma = 2.5\)
Hence the z-score is:
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{22 - 15}{2.5}\)
Z = 2.8.
Item b:
The parameters are:
\(\mu = 38.1, \sigma = 6.35\)
Hence the z-score is:
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{55.88 - 38.1}{6.35}\)
Z = 2.8.
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Plzz answers its easy points!!!! im just really dumb!!!!
Answer:
see below
Step-by-step explanation:
V = Bh where B is the area of the base and h is the height
Divide each side by h
V/h = Bh/h
V/h = B
36/6 = B
6 = B
The area of the base is 6 in^2
An archer shoots an arrow up towards a target located on a hill, which is shown by the graph
G16,43)
Which set of equations best models the point of intersection of the arrow and the target?
Oy=0.002x² +0.15x + 2 and y=x
Oy=-0.002x²+0.15x+2 and y=-x
Oy=0.002x²+0.15x + 2 and y=0,2x
Oy=-0.002x² +0.15x+2 and y = 0.2x
y=0.002x² +0.15x + 2 and y=x set best models the point of intersection of the arrow and the target because it accounts for the fact that the arrow is travelling in a parabolic arc, while the target is located on a straight line.
What is parabolic arc?A parabolic arc is defined by its vertex, focus, and directrix. The arc can be used to describe the trajectory of a projectile, the shape of a satellite dish, or the shape of some suspension bridges.
The equation y=0.002x² +0.15x + 2 models the parabolic arc of the arrow's trajectory and the equation y=x models the straight line of the target.
This equation set is the only one that correctly models both the parabolic arc of the arrow and the straight line of the target.
To better understand why this equation set is the correct answer, let's look at the other equation sets.
The equation set y=-0.002x²+0.15x+2 and y=-x does not work because the equations do not model a parabolic arc and a straight line, respectively.
The equation set y=0.002x²+0.15x + 2 and y=0,2x does not work because the second equation, y=0.2x, does not model a straight line, but rather a line with a slope of 0.2.
Finally, the equation set y=-0.002x² +0.15x+2 and y = 0.2x does not work because the first equation, y=-0.002x² +0.15x+2, does not model a parabolic arc.
Therefore, the equation set y=0.002x² +0.15x + 2 and y=x is the correct answer because it is the only equation set that accurately models both the parabolic arc of the arrow and the straight line of the target.
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Find the measures of x and y
Step-by-step explanation:
x+45=180 [v.o.a]
x=180-45
.°.x=95
y+90=180°[v.o.a]
y=180-90
.°.y=90
(a) Write a formula for the distance between the points (x,y) and (4,6)
(b) If the distance
between above points is 9 units, write an equation.
Combine the likes terms to create an equivalent expression y - (-3y)
Answer:
4y
Step-by-step explanation:
y - (-3y)
y + 3y
4y
When you see two negatives they basically become an addition symbol. In this case you then add the like terms which are y and 3y to get 4y. Hope this helps!!
In the following diagram, what is the value of x?
x=[x]
Answer:
x=90°
Step-by-step explanation:
Too much work............. ....
Evaluate the Riemann sum for f(x) = 3 - 1/2 times x between 2 and 14 where the endpoints are included with six subintervals taking the sample points to be the left endpoints. Explain, with aid of a diagram, what the Riemann sum represents.
Answer:
-6
Step-by-step explanation:
Given that :
we are to evaluate the Riemann sum for \(f(x) = 3 - \dfrac{1}{2}x\) from 2 ≤ x ≤ 14
where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.
The Riemann sum can be computed as follows:
\(L_6 = \int ^{14}_{2}3- \dfrac{1}{2}x \dx = \lim_{n \to \infty} \sum \limits ^6 _{i=1} \ f (x_i -1) \Delta x\)
where:
\(\Delta x = \dfrac{b-a}{a}\)
a = 2
b =14
n = 6
∴
\(\Delta x = \dfrac{14-2}{6}\)
\(\Delta x = \dfrac{12}{6}\)
\(\Delta x =2\)
Hence;
\(x_0 = 2 \\ \\ x_1 = 2+2 =4\\ \\ x_2 = 2 + 2(2) \\ \\ x_i = 2 + 2i\)
Here, we are using left end-points, then:
\(x_i-1 = 2+ 2(i-1)\)
Replacing it into Riemann equation;
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} \begin {pmatrix}3 - \dfrac{1}{2} \begin {pmatrix} 2+2 (i-1) \end {pmatrix} \end {pmatrix}2\)
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2(i-1))\)
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2i-2)\)
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 -2i\)
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 2i\)
\(L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - 2 \lim_{n \to \infty} \sum \imits ^{6}_{i=1} i\)
Estimating the integrals, we have :
\(= 6n - 2 ( \dfrac{n(n-1)}{2})\)
= 6n - n(n+1)
replacing thevalue of n = 6 (i.e the sub interval number), we have:
= 6(6) - 6(6+1)
= 36 - 36 -6
= -6
4. Leo is taking an algebra test containing computation problems worth
5 points each and application problems worth 8 points each. Leo
needs to score at least 83 points on the test to maintain his B average.
Let c represent the number of computation problems he answers
correctly and a represent the number of application problems he
answers correctly. Write an inequality to represent the constraint.
The inequality that represents the constraint faced by Leo in needing to score at least 83 points is 5 c + 8 a ≥ 83.
How to find the inequality ?Let's first find the total number of computation and application problems that Leo needs to answer correctly to score at least 83 points on the test.
Let c be the number of computation problems that Leo answers correctly, and let a be the number of application problems that he answers correctly.
Total points is therefore :
= 5 c + 8 a
To maintain his B average, Leo needs to score at least 83 points on the test. Therefore, we can add the inequality part to make it:
5 c + 8 a ≥ 83
This shows that Leo needs to score either 83 points or above that in the test.
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On a test, you earn 92% of the possible points by correctly answering 6 five-point questions and 8 two-point questions. How many points $p$ is the test worth?
The test is worth p= points.
Step-by-step explanation:
(6×5)+(8×2)=46
92℅=46points
100℅=x
criss cross
92℅x=46
92℅. 92℅
and this is the answer
Answer:
50 Points Total
Step-by-step explanation:
You only got 92% right on the test to that means you missed some questions. So 6x5=30, 18x2=16, 16=30=46 100%-92%=8%, 8%=4 points.
You bought some grapes at a farm stand. You paid $2.48 per pound. The pounds are (3.25). What was the total amount that you paid for the grapes?
Answer:
You paid $8.06
Step-by-step explanation:
3.25 pounds times $2.48 per pound is 8.06.
Can I have brainliest pls :D
Hope this helps
3/5 x 1/7 please help
Answer:
3/35
Step-by-step explanation:
3*1=3
5*7=35
3/35
Question 2 (15 points )
Determine the scale factor from circle A to circle B.
O
Scale factor =
B
30
Thus, the scale factor from circle A to circle B is found to be 2.
Explain about the scale factor:The ratio between comparable measurements of just an element and a portrayal of that element is known as a scale factor in mathematics. The copy will be larger if the scaling factor is a whole number. A fractional scaling factor means that the duplicate will be smaller.
You must first choose which direction we are scaling in order to determine the scale factor:
Scale Up = larger measurement / smaller measurement (smaller to larger).Smaller measurement equals greater measurement when scaling down.The radius of circle A = 2 units
The radius of circle B = 4 units.
So, there is a dilation with the scale factor of 2 units as 2*2 = 4 units.
Thus, the scale factor from circle A to circle B is found to be 2.
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This velocity-time graph shows 8 seconds of a car journey.
What was the total distance travelled by the car during this time?
If your answer is a decimal, give it to 1 d.p.
Velocity (m/s)
20
15
10
5
0
Time(s)
The distance covered by the car in 8 seconds of the journey is 100 meters.
What is the distance?The complete movement of an object, regardless of direction, is referred to as distance. The amount of ground a thing travels from its starting point to its destination is also referred to as distance.
Given:
Velocity (m/s) = 20, 15, 10, 5, 0
Calculate the distance as shown below,
\(Distance = velocity \times time\)
Distance = 0 × 20 + 15 × 2 + 10 × 4 + 5 × 6 + 0 × 8
Distance = 0 + 30 + 40 + 30 + 0
Distance = 100 meter
Thus, the distance covered by the car is 100 meters.
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The following scatterplot shows two variables, x and y, along with a least-squares model.
Which of the following is a high leverage point with respect to the regression?
A (5,8)(5,8)
B (20,31)(20,31)
C (27,22)(27,22)
D (30,60)(30,60)
E (80,70)
Answer:
D(30,60)
Step-by-step explanation:
It was way outside the other points that are around the line.
The point (30,60) is a high leverage point on the regression plot.
What is High leverage points?High leverage points are those that are extreme but follow the regression equation's trend.
High leverage points are distinct from outliers, which deviate from the graph's or plot's pattern or trend.
Looking closely at the regression plot, the coordinate (30,60) follows the trend of the plot, however, it is farther from the majority of the points on the graph.
Hence, the point (30,60) is a high leverage point on the regression plot.
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