a sample of 63.6 grams of copper completely reacted with oxygen to form 71.6 grams of a copper oxide product. how many grams of oxygen must have reacted?

Answer:

Hard water is water that has high mineral content, Soft water is free from dissolved salts of such metals as calcium, iron, or magnesium

Explanation:

The correct answer is D. addition of Br₂ to trans-2-butene (trans-CH₃CH=CHCH₃).

To form a racemic mixture, the starting compound should be an asymmetric molecule or a compound with an asymmetric center. In this case, 2,3-dibromobutane (CH₃CHBrCHBrCH₃) is an asymmetric molecule because it has two different bromine atoms attached to the central carbon.

The addition of bromine (Br₂) to trans-2-butene will result in the formation of 2,3-dibromobutane. Since trans-2-butene is an asymmetric starting material, the addition of bromine from both sides of the double bond will give rise to both possible enantiomers, leading to a racemic mixture.

Option A (photochemical bromination of 2-bromobutane) and option B (addition of HBr to 3-bromo-2-butene) do not involve an asymmetric starting material, so they won't result in a racemic mixture.

Option C (addition of Br₂ to cis-2-butene) also won't give a racemic mixture because cis-2-butene does not have an asymmetric carbon.

Therefore, the best method to make a racemic mixture of 2,3-dibromobutane is option D, the addtion of Br₂ to trans-2-butene.

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Answer:Mn+Ni2+-->Mn2+ + Ni

Explanation:

Castle Learning said it

How do you determine if the reaction is spontaneous?

If ΔH is negative, and –TΔS positive, the reaction will be spontaneous at low temperatures (decreasing the magnitude of the entropy term).

What is the meaning of spontaneous reaction?

When both of these conditions are met, the reaction occurs naturally. A spontaneous reaction is a reaction that favors the formation of products at the conditions under which the reaction is occurring.

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By ideal gas approximation, the volume change is 230.2 liters.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

n₁ = 1 mol

n₂ = 1 + 9 mol = 10 mol

P₁ = P₂ = 100 kPa = 100000 Pa

T₁ = 74⁰ C = 347 K

Find the initial volume

P₁ . V₁ = n₁ . R . T₁

100000 . V₁ = 1 . 8.31 . 347

V₁ = 0.0288 m³

When the initial and final temperature and pressure are the same, we can use the ratio of the number of moles and volume as

V₁ / n₁ = V₂ / n₂

0.0288 / 1 = V₂ / 9

V₂ = 0.25952 m³

V₂ = 259.52 liters

The volume change is

ΔV = V₂ - V₁

ΔV = 259.52 - 28.8

ΔV = 230.2 liters

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Answer:30 moles of oxygen are required if 12 moles of  are consumed.

Explanation:The given balanced equation is:

From this balanced equation, there is 2:5 mol ratio between  and  .

We are asked to calculate the moles of  required to react with 12 moles of .

It's a mol to mol conversion and the set up for this would be as:

=

So, 30 moles of oxygen are required to react with 12 moles of  .

Answer:

composition of N₂S₂, you divide the total mass of each atom by the molecular mass and multiply by 100 %. Mass of 2 N atoms = 2 N atoms × 14.01u1N atom = 28.02 u.

While cirrocumulus clouds may have some minor impact on the Earth's energy balance by reflecting sunlight, their role in the greenhouse effect is negligible compared to the greenhouse gases themselves.

Cirrocumulus clouds do not directly play a significant role in the greenhouse effect. The greenhouse effect refers to the process by which certain gases in the Earth's atmosphere trap heat from the sun, leading to an increase in the planet's temperature. The primary greenhouse gases responsible for this effect are carbon dioxide, methane, and water vapor.Cirrocumulus clouds, also known as high-level clouds, are composed of ice crystals and form at altitudes above 20,000 feet. They are thin, white, and often appear as small, rounded puffs or ripples in the sky. While these clouds can reflect some sunlight back into space, their overall impact on the greenhouse effect is minimal.In contrast, low-level clouds such as stratus or cumulus clouds can have a more significant influence on the greenhouse effect. These clouds have a higher potential to reflect incoming solar radiation and cool the Earth's surface, thus partially counteracting the warming effect caused by greenhouse gases.

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Answer:

A. 7

(assuming the water is neutral)

Answer:

A base is weak when only a little of it is dissolved in water

Explanation:

Answer: B.) A base is weak when only a little of it is dissolved in water

Hope this helps :)

a. 2.0 miles downhill

This is because the path taken by the camper appears to go primarily downhill and is relatively short in distance. However, the actual distance may be more or less than 2.0 miles depending on the scale of the diagram.

Answer:

yay well done good job keep going

6.0 × 10²³​ are the molecules  in 17 amu of ammonia, NH\(_3\). Therefore, the correct option is option D among all the given options.

The smallest recognizable unit in which a pure material may be split while retaining its composition and chemical characteristics is a molecule, which is a collection of two or more atoms.

Until portions made up of single molecules are reached, the split of a sample of a substance into increasingly smaller parts does not result in a change in either its makeup or its chemical characteristics.

molar mass of 1 mole of ammonia = 17 amu

1 mole of any substance contains 6.0 × 10²³​

6.0 × 10²³​ are the molecules  in 17 amu of ammonia, NH\(_3\).

Therefore, the correct option is option D among all the given options.

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To solve this problem, we need to set up an ICE (Initial, Change, Equilibrium) table and use the given equilibrium constant (Kc) to determine the equilibrium concentrations. Let's start with the initial concentrations:

[CO2] = 3.50 mol / 7.00 L = 0.50 M (since the volume is given as 7.00 L)

[CO] = 0 M (since no CO is initially present)

[O2] = 0 M (since no O2 is initially present)

Next, let's assume that x mol/L of CO and O2 are formed at equilibrium. Since the stoichiometry of the reaction is 2:2:1 (2 CO2 : 2 CO : 1 O2), the change in concentration of CO and O2 will be equal to x mol/L.

Now, we can fill in the equilibrium concentrations in the ICE table:

        | 2CO2(g) ⇌ 2CO(g) + O2(g)

--------------------------------------

Initial  |   0.50     |     0       |   0

Change  |   -2x       |    +2x     |   +x

Equilibrium| 0.50 - 2x |    2x       |   x

According to the equilibrium constant expression (Kc), we have:

Kc = [CO]^2 * [O2] / [CO2]^2

Plugging in the equilibrium concentrations:

Kc = (2x)^2 * (x) / (0.50 - 2x)^2

Given that Kc = 3.2 × 10^(-8), we can set up the equation:

3.2 × 10^(-8) = (2x)^2 * (x) / (0.50 - 2x)^2

Solving this equation will give us the value of x, which represents the equilibrium concentration of O2. Once we have the value of x, we can calculate the equilibrium concentrations of CO and CO2 using the equilibrium expressions:

[CO] = 2x

[CO2] = 0.50 - 2x

Please note that solving the equation may involve using numerical methods, such as the quadratic formula or an equation solver.

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To find the mass in grams of 52.9 moles of Xenon, multiply the number of moles (52.9) by the molar mass of Xenon. The molar mass of Xenon is 131.293 g/mol. So, 52.9 moles of Xenon would have a mass of:

52.9 moles * 131.293 g/mol = 6,938.72 grams

The remaining mass of radioactive elements with 60 years of half-life is 1000 particles.

We need to know about the half-life of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation

N = No(1/2)^(t/t'')

where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.

From the question above, we know that

t'' = 60 years

No = 2000 particles

t = 60 years

Calculate the remaining mass

N = No(1/2)^(t/t'')

N = 2000 x (1 / 2)^(60 / 60)

N = 1000 particles

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The ways to use of the water left after mopping is by using it to clean the gutters or drainage around your house or use it to water plants.

The function of water in plants is that it aid in photosynthesis.

The values of Ayan that is shown here is efficient use of water/ water sustainability

Water is essential for healthy ecosystems, socioeconomic development, and human life, and it is at the heart of sustainable development.

It is essential for enhancing population health, welfare, and productivity as well as lowering the worldwide disease load. The ability to meet current water needs without compromising the capacity of future generations to do the same is known as sustainable water management.

Therefore, Photosynthesis, the process by which plants harness solar energy to make their own sustenance, requires water. Plants utilise hydrogen from water absorbed through their roots and carbon dioxide from the air during this process, releasing oxygen as a byproduct. Through pore-like stomas on the leaves, this exchange takes place.

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Answer:

1)RADICLE ->It is the embryonic root of the plant.

PLUMULE ->It is the embryonic shoot of the plant.

2)RADICLE ->It grows downwards into the soil.

PLUMULE ->It grows upwards into the air.

3)RADICLE ->Radicle is the first part of the seedling.

PLUMULE -> Plumule grows after the radicle.

4)Radicles are negatively phototropic. Plumule is positively phototropic.

i am glad i helped

Answer: \(232.8\ K\)

Explanation:

Given

The volume of Nitrogen gas is \(V_1=3.5\times 10^{-2}\ m^3\)

Pressure is \(P_1=10^5\ Pa\)

Temperature \(T_1=291\ K\)

When the pressure and temperature changes i.e.

\(P_2=10^5\ Pa\)

\(V_2=2.8\times 10^{-2}\ m^3\)

Temperature is given by

\(\Rightarrow \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\\\Rightarrow T_2=\dfrac{P_2V_2}{P_1V_1}\times T_1\)

Insert values

\(\Rightarrow T_2=\dfrac{2.8\times 10^{-2}\times 10^5}{3.5\times 10^{-2}\times 10^5}\times 291\\\\\Rightarrow T_2=291\times 0.8\\\Rightarrow T_2=232.8\ K\)

At a high altitude, water boils at a lower temperature than at sea level because the atmospheric pressure is lower. Option B

The atmospheric pressure decreases with increasing altitude because there is less air pressing against the water's surface.

When a liquid's vapor pressure reaches the same level as air pressure, boiling takes place. At sea level, the atmospheric pressure is 1 atm, hence for water to boil at 100°C, the vapor pressure must also be 1 atm. In contrast, the vapor pressure of water exceeds atmospheric pressure at lower temperatures at high elevations when the atmospheric pressure is lower.

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9 pennies contain approximately \(2.13 x 10^23\) atoms of copper.

To solve this problem, we need to use the following steps:

Determine the molar mass of copper.

Convert the mass of 9 pennies from grams to moles.

Use Avogadro's number to calculate the number of atoms of copper.

Step 1: The molar mass of copper (Cu) is approximately 63.55 g/mol.

Step 2: The mass of 9 pennies is:

9 pennies x 2.5 g/penny = 22.5 g

Converting this mass to moles, we get:

22.5 g / 63.55 g/mol = 0.354 moles

Step 3: Using Avogadro's number (\(6.022 x 10^23 atoms/mol)\), we can calculate the number of atoms of copper:

Therefore, 9 pennies contain approximately\(2.13 x 10^23 a\)toms of copper.

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Nova's personality can be described as adventurous, problem-solving oriented, and driven by the pursuit of optimal solutions.

Nova's preference for unpredictable days and her enjoyment of solving puzzles suggests that she has an adventurous and curious nature. She thrives on the excitement and challenges that come with unexpected situations, finding them stimulating rather than overwhelming. Nova's ability to solve problems indicates a strong analytical and logical mindset. She enjoys the process of dissecting complex issues, identifying potential solutions, and engaging in trial and error to find the best fit.

This demonstrates her determination, perseverance, and willingness to explore different paths to achieve her goals. Nova's inclination towards testing out various solutions implies that she values experimentation and creativity, embracing the opportunity to think outside the box and discover innovative approaches. Her personality traits align with those of a problem-solver who actively seeks intellectual stimulation and embraces the satisfaction of finding optimal solutions to the challenges she encounters.

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Answer:

Choice A. \(x\) electrons would be required for displacing \(9\; \rm g\) of aluminum from a solution of \(\rm Al^{3+}\) ions.

Assumption: by "\(\rm Ag\) ions" the question meant \(\rm Ag^{+}\) with a charge of \(+1\) on each ion.

Explanation:

The question states that the relative atomic mass of \(\rm Ag\) is \(108\). In other words, each mole of

Therefore, that \(108\; \rm g\!\) of silver that were formed would contain \(1\; \rm mol\) of silver atoms.

Metallic silver would precipitate out of this \(\rm Ag^{+}\) solution only after these ions are turned into \(\rm Ag\) atoms.

One \(\rm Ag^{+}\) ion carries one unit of positive electrical charge. On the other hand, each  \(e^{-}\) carries one unit of negative electrical charge.

Therefore, each \(\rm Ag^{+}\!\) ion will need to gain one electron to form a neutral \(\rm Ag\) atom.

\({\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s)\).

At least  \(1\; \rm mol\) of electrons would be required to turn \(1\; \rm mol\!\) of \(\rm Ag^{+}\) ions into that \(1\; \rm mol\!\!\) of silver atoms (which have a mass of \(108\; \rm g\!\).)

Hence, \(x = 1\; \rm mol\).

Unlike \(\rm Ag^{+}\) ions, each aluminum ion \(\rm Al^{3+}\) carries three units of positive electrical charge. That is three times the amount of charge on one \(\rm Ag^{+}\!\) ion. Therefore, three electrons will be required to turn one \(\rm Al^{3+}\!\) ion to an \(\rm Al\) atom.

\({\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)\)

The question states that the relative atomic mass of \(\rm Al\) is \(27\). Therefore, each mole of \(\rm Al\!\) atoms would have a mass \(27\; \rm g\). There would be \(\displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol\) of atoms in that \(9\; \rm g\) of \(\rm Al\!\!\).

It takes \(3\; \rm mol\) of electrons to turn one mole of \(\rm Al^{3+}\) ions to one mole of \(\rm Al\) atoms. Hence, \(\displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol\) of electrons would be required to produce that \(\displaystyle \frac{1}{3}\; \rm mol\) of \(\rm Al\!\) atoms (which has a mass of \(9\; \rm g\)) from \(\rm Al^{3+}\!\) ions.

That corresponds to the first choice, \(x\) electrons.

To make a 0.2 M NaOH (aq) solution, we will need to dilute 6 M NaOH (aq). we need approximately 11.67 mL of 6 M NaOH to make the diluted solution.

To determine the volume of 6 M NaOH required for the dilution, we can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. In this case, we know the final concentration (0.2 M) and the final volume (350 mL). Therefore, we can rearrange the equation to solve for V1, the initial volume of 6 M NaOH needed for the dilution.
0.2 M * 350 mL = 6 M * V1
V1 = (0.2 M * 350 mL) / 6 M
V1 = 11.67 mL
Therefore, we need approximately 11.67 mL of 6 M NaOH to make the diluted solution.

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\(\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)

When water freezes, it is an exothermic change. The oranges absorb this energy which is an endothermic change and do not freeze.

Answer:

where the slope of the titration curve is the greatest

The titration curve can be used to identify the equivalency point of the titration.The volume of titrant is where the titration curve has the steepest slope.

How do you find the equivalence point on a titration curve?

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The empirical formula of the hydrocarbon is CH2, and the molecular formula of the hydrocarbon is C2H4.

From the given data, we can obtain the empirical formula and molecular formula of hydrocarbon.

The given mass of hydrocarbon (CxHy) = 3.164 g

Given mass of CO2 formed = 9.929 g

Given mass of H2O formed = 4.065 g

First, we need to find out the number of carbon and hydrogen atoms in the given hydrocarbon.

To calculate the number of carbon atoms, we use the formula:

number of moles of CO2 formed = number of moles of carbon present in CxHy

Moles of CO2 = 9.929 g / 44.01 g/mol = 0.2258 mol

Thus, the number of moles of carbon present in CxHy is 0.2258 mol.

Also, each mole of carbon contains one mole of C atoms.

Hence, the number of carbon atoms in CxHy is also 0.2258 mol. Next, we calculate the number of hydrogen atoms using the formula: number of moles of H2O formed = number of moles of hydrogen present in CxHy

Moles of H2O = 4.065 g / 18.015 g/mol = 0.2258 mol

Thus, the number of moles of hydrogen present in CxHy is 0.2258 mol. Also, each mole of water contains two moles of hydrogen atoms. Hence, the number of hydrogen atoms in

CxHy is 2 × 0.2258 mol = 0.4516 mol

Empirical formula of the hydrocarbon = CH2

To find the molecular formula of the hydrocarbon, we need to know its molecular mass. The molar mass of the compound is given as 28.05 g/mol.

The empirical formula mass of CH2 is 14.03 g/mol.

Thus, the molecular formula of the hydrocarbon = (28.05 g/mol) / (14.03 g/mol) = 2 times the empirical formula

Therefore, the molecular formula of the hydrocarbon = C2H4

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The mileage rate of the car is approximately 52,383.55 meters per deciliter (m/dL) when given the average of 32.5 miles per gallon (mi/gallon).

To convert the mileage rate from miles per gallon (mi/gallon) to meters per deciliter (m/dL) using dimensional analysis, we need to apply conversion factors that relate the given units to the desired units.

Given:

Mileage rate = 32.5 mi/gallon

We can set up the dimensional analysis as follows, using the conversion factors:

32.5 mi/gallon * (1609.34 m/1 mi) * (1 gallon/3.78541 dL)

Let's break down the conversion factors used:

1 mi = 1609.34 m (conversion factor to convert miles to meters)

1 gallon = 3.78541 dL (conversion factor to convert gallons to deciliters)

Now, we can multiply the given mileage rate by the conversion factors:

32.5 mi/gallon * (1609.34 m/1 mi) * (1 gallon/3.78541 dL) = (32.5 * 1609.34) m/dL ≈ 52,383.55 m/dL

Therefore, the mileage rate of the car is approximately 52,383.55 meters per deciliter (m/dL) when given the average of 32.5 miles per gallon (mi/gallon).

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