Answer:
Potential energy
Kinetic energy
Gravitational energy.
Explanation:
The potential energy is the stored energy, it is the energy and object posses at rest. When the base jumper is still at rest i.e without motion, she has potential energy.
Gravitational energy this refer to the potential energy an object or body with mass posses in relation to another object due to gravity.
This is seen when the base number is still at rest and the force of gravity on the Earth acting on her.
Kinetic energy is the energy posses by an object or body in motion.
As the base jumper falls to the ground, she posses kinetic energy which is the energy in motion.
Answer: potential energy, kinetic energy, and gravitational energy
Explanation:
got it right on ap.ex
a solid sphere and a solid cube are made from the same material. the sphere would just fit within the cube, if it could. both begin at the same temperature, and both are heated to the same temperature. which object, if either, has the greater change in volume?
Answer:
Explanation:
The sphere would have a greater change in volume, because its shape is more spherical, meaning it has more surface area and therefore more space for expansion. The cube, on the other hand, has less surface area, so its increase in volume would be less.
the focal length of the lens of a simple camera is 40.0 mm. how far must the lens be moved to change the focus of the camera from a person 25 m away to one that is 4.0 m away? select one: a. 0.5 mm b. 0.2 mm c. 0.3 mm d. 0.7 mm
The lens must be moved by 22.3 mm to change the focus of the camera from a person 25 m away to one that is 4.0 m away.
We can use the thin lens equation to solve this problem:
1/i + 1/o = 1/f
where i is the image distance, o is the object distance, and f is the focal length of the lens. At the initial position, the object distance is 25 m, so we can write:
1/i + 1/25m = 1/40mm
Solving for i, we get:
i = 27.8 mm
At the new position, the object distance is 4.0 m, so we can write:
1/i' + 1/4.0m = 1/40mm
Solving for i', we get:
i' = 5.5 mm
The change in position of the lens, Δx, is equal to the difference in image distances:
Δx = |i - i'| = |27.8 mm - 5.5 mm| = 22.3 mm
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--The complete question is, the focal length of the lens of a simple camera is 40.0 mm. How far must the lens be moved to change the focus of the camera from a person 25 m away to one that is 4.0 m away? Moving the lens allows the distance from lens to the film remain equal to i as i changes.--
a spherical cavity is hollowed out of the interior of a neutral conducting sphere. at the center of the cavity is a point charge, of positive charge q.
Only the charge present inside the cavity can explain the electric field that exists there. The electric field inside the hollow would remain unchanged as a result.
Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field. To predict what would happen to electric charges nearby a specific point, one only needs to be aware of the value of the electric field there, without having any precise knowledge of what generated the field.
When one charge is thought of as the generator of an electric field that spreads outward into the surrounding space, the electric force is not thought of as a direct interaction of two electric charges that are separated from one another.
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With friction turned on, let the skater do one back-and-forth on the half pipe. Use
the grid. Does he reach the same height as when he started?
The skater does indeed reach the same height on either side of the track With friction turned on.
The only thing that will change is how long it takes for the skater to come to a rest during the scenario. Only the skater's initial height when placed onto the track affects the overall energy, which remains constant.Potential energy is transformed into kinetic energy as the skateboarder descends the ramp. Some of the system's energy is changed into heat energy by friction. The energy cannot be returned to the system's potential or kinetic energy once the kinetic energy has been transformed into heat.For more information on friction kindly visit to
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Four states of matter and describe the particles arrangement of each
Answer:
There are four natural states of matter: Solids, liquids, gases and plasma.
Explanation:
The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.
Multiplying a vector with another vector results in what type of answer.
A) a direction
B) a vector
C) either a vector or a scalar
D) a scalar
multiplication of two vectors yields a vector oroduy
It takes 100 N to move a box 10 meters in 5 seconds. How much power is
required?
A. 1,000 W
O B. 200 W
C. 5,000 W
O D. 20 W
Answer:
200W
Explanation:
W=F*d
P=W/t
P=(100)(10)/5
P=200
When an object's momentum changes, usually that means its velocity has charged. What must happer fo
an object's velocity to change?
a. Its mass increases
b. An outside force acts upon it
c. Its mass decreases
d. Its momentum must stay the same
Answer:
b. An outside force acts upon it
Explanation:
Can anyone help in this question please
As a result, it splits into two smaller nuclei, krypton-92 and barium-141. The reaction also releases three neutrons and a great deal of energy. It can be represented by this nuclear equation:
92235 U + 1 neutron → 36 92 K r + 56 141 B a + 3 neutrons + energy
the distance between pole and position of image can denoted by___
a)u. b)v. c)R. d)C
Answer:
b) v
Explanation:
the distance between pole and position of image can denoted by v
Astronauts brought back 500 lb of rock samples from the moon. how many kilograms did they bring back? 1 kg = 2.20 lb
A. 227 kg
B. 498 kg
C. 500 kg
D. 1,100 kg
Answer:
1100 kg
Explanation:
500 lb x 2.20lb (1kg) =1100kg
A satellite 1000 km above Mars is orbiting Mars every 15 hours.
The radius of Mars is approximately equal to 3,300 km. How far does
the satellite travel in 1 hour?
The satellite travels approximately 1,798.07 km in 1 hour. The circumference of the satellite's orbit is 8,600π km, and the satellite orbits Mars every 15 hours.
To find out how far the satellite travels in 1 hour, we need to determine its orbital circumference.
The circumference of a circular orbit can be calculated using the formula:
C = 2πr
where C is the circumference and r is the radius of the orbit.
In this case, the satellite is orbiting Mars, which has a radius of approximately 3,300 km. The satellite is 1,000 km above the surface of Mars. Therefore, the radius of the satellite's orbit is the sum of the radius of Mars and the distance above the surface:
r = 3,300 km + 1,000 km = 4,300 km
Now we can calculate the circumference:
C = 2π(4,300 km) = 8,600π km
Since the satellite orbits Mars every 15 hours, the distance traveled in 1 hour is 1/15th of the circumference:
\(\begin{equation}\text{Distance traveled in 1 hour} = \frac{1}{15} \cdot 8600\pi \text{ km}\)
Calculating this value gives us:
Distance traveled in 1 hour ≈ 1,798.07 km
Therefore, the satellite travels approximately 1,798.07 km in 1 hour.
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While looking at calcium (Ca) on the periodic table, a student needs to find an elRounded to the nearest whole number, how many electrons are in an atom of zirconium?
There are 40 electrons in Zr.
How many electrons are in Zr?The number of electrons in the element Zirconium (Zr) is 40. In the periodic table, Zr is located in period 4 and group 4 (also known as group IV), and it has an electron configuration of [Kr] 4d2 5s2. This means that it has two electrons in its 4d orbital and two electrons in its 5s orbital, giving it a total of 40 electrons.
We have to note that number of the protons in the nucleus would also be the number of the electrons that we can be able to find in the neutral atom.
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The rate at which a certain balloon travels is inversely proportional to the amount of weight attached to it if the balloon travels at 10 in./s and then there is a 2nd g weight attached to it approximately how much weight must be attached to the balloon for it to travel 18 in./s
The rate at which a certain balloon travels is inversely proportional to the amount of weight attached to it if the balloon travels at 10 in./s and then there is a 2nd g weight attached to it approximately the weight must be attached to the balloon for it to travel 18 in./s is 1.1 grams.
When 2 grams are added, the rate moves at 10 in/sec.
Since the weight and the distance traveled are inversely proportional, the expression can be written as
d= k/W
10 =k/2
k= 20
When 2 grams are attached, the rate moves at a speed of 10 in/second.
Given that the relationship between the weight and the traveled distance is inverse, this can be expressed as,
d= k/W
18= k/w
w= k/18
Substitute value of k in the above expression.
W= 20/18
W=1.11 gram
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please someone help me understand this question
\(\\ \sf\longmapsto F=\dfrac{Gm_1m_2}{r^2}\)
m1 and m2 has same units let both be m\(\\ \sf\longmapsto F=\dfrac{Gm^2}{r^2}\)
\(\\ \sf\longmapsto G=\dfrac{Fr^2}{m^2}\)
SI units:-
F=Newton (N)r=metre(m)mass=m=kg\(\\ \sf\longmapsto G=\dfrac{Nm^2}{kg^2}\)
Option C is correct
What is the mass and charge of a proton, neutron, and electron?
Answer:
The answer is
proton- mass-1,charge+
Neutron-mass-1,charge-no charge
electron-mass-1/1840,charge-
IikiiiijjjjjHunnish uh uh Veg f to tcHelp me I have inserted a picture of the question
Answer:
I think this is correct
Explanation:
frequency definition is the number of complete waves produced per second so if you have 100Hz, it is 100 complete waves produced in 1 seconds, and when it says vibrates 300 times in 3 seconds, you find for 1 second
vibrations is most probably the frequency in one second
1 second -----100 vibrations
thus the frequency = 100 Hz
hope this helps!!!!!!
each item below can be used to measure the distances of astronomical objects. rank them according to how far away each method works, from nearest to farthest. (that is, put the method that works only in our solar system at the far left, and the method that can be used for the most distant galaxies at the far right.)
Here's a ranking of how well each method works, from closest to furthest:
Radar rangingParallaxCepheidsWhite dwarf supernovaeWhat are astronomical objects?A celestial body, celestial body, star object, or celestial body is a naturally occurring physical entity, association, or structure that exists in the observable universe. However, while a celestial body or celestial body is a single, closely connected and coherent entity, a celestial body or celestial body may be composed of multiple celestial bodies or other objects with substructures, complex and connected low structure.
Examples of celestial bodies are planetary systems, star clusters, nebulae, and galaxies, while asteroids, moons, planets, and stars are celestial bodies. Comets can be identified both as objects and as objects.
It is the body when referring to the frozen core of ice and dust, and the object when referring to the entire comet with its diffuse coma and tail.
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A train stops at two stations A and B. It accelerates from rest from station A to a speed of 144 km h^-1 in 3 minutes and maintains this speed for 10 minutes. It then decelerates for 2 minutes and comes to rest at station B. Find the total distance between A and B.
Show work please, really need the help.
Answer:
The total distance between A and B is 30 km
Explanation:
The given information are;
The time duration of the acceleration of the train from station A = 3 minutes = 0.05 hours
The speed attained by the train after the acceleration = 144 km/h
The time duration the train maintains the speed = 10 minutes = 0.1\(\bar 6\) hours
The time duration in which the train decelerates to station B = 2 minutes = 0.0\(\bar 3\) hours
The equation of motion required are;
The initial acceleration, a = (144 - 0)/0.05 = 2,880 km/h²
The distance covered, s = u·t + 1/2·a·t²
Where;
u The initial velocity = 0
∴ s₁ = 0 × 0.05 + 1/2 × 2880 × 0.05² = 3.6 km
s₁ = 3.6 km
The distance, s₂ the train covers at the constant speed 144 km/h for 10 minutes (1/6 hours) is given as follows;
s₂ = Velocity Time = 144 × 1/6 = 24 km
s₂ = 24 km
The deceleration, a₂ that brings the train to a stop in 2 minutes (1/30 hours) is given as follows;
a₂ = (0 - 144)/(1/30) = -4320 km/h²
The distance covered, s₃ by the train as it decelerates to rest from the initial constant speed is given as follows;
s₃ = u·t + 1/2·a·t²
Where;
u = The initial velocity =144 km/h
We have;
s₃ = 144×1/30 - 1/2 × 4320 × (1/30)² = 2.4
s₃ = 2.4 km
The total distance between A and B, s = s₁ + s₂ + s₃ = 3.6 + 24 + 2.4 = 30 km
The total distance between A and B = 30 km.
How can we relate density and pressure in liquids ??
How can we relate density and pressure in liquids ??
\( \huge{ \texttt{ \red{answers}}}\)
It is the pressure at each point of a static fluid. When we immerse ourselves in a liquid, the pressure increases with depth.In the case of a liquid (constant density) the pressure increases linearly with depth.⭐ ----------------------------------------------------------------------------------⭐
\( \bold{BRAINLY MENTALMENTE}\)
now assume that the baggage handler pushes a third box (figure 2) of mass m/2 so that it accelerates at a rate of 2a . how does the magnitude of the force f3 that the handler applies to this box compare to the magnitude of the force f1 applied to the first box?
The correct answer is that the magnitude of the force F3 applied to the third box is equal to the magnitude of the force F1 applied to the first box.
The magnitude of the force F3 that the handler applies to the third box can be compared to the magnitude of the force F1 applied to the first box by using the equation F = ma.
For the first box, the force F1 is equal to the mass of the box (m) multiplied by the acceleration of the box (a), or F1 = ma.
For the third box, the force F3 is equal to the mass of the box (m/2) multiplied by the acceleration of the box (2a), or F3 = (m/2)(2a).
Simplifying the equation for F3 gives us F3 = ma.
Therefore, the magnitude of the force F3 applied to the third box is equal to the magnitude of the force F1 applied to the first box.
In other words, F3 = F1.
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A 1250 kg truck is moving down the highway with a velocity of 2. 0 m/s crashes head-on with another car with a mass of 875 kg and a velocity of 6. 0 m/s. After the collision, the two vehicles bounce off each other and the truck has a new velocity of 1. 0m/s. What is the new velocity of the car?
Together, the two cars are traveling at a speed of 29.11 m/s.
As a result,
The car's mass is 1 m = 1250 kg.
Initially, the car's speed was 1, u = 32 m/s.
Car 2 mass, m' = 875 kg
The starting speed of vehicle 2 is 25 m/s.
both vehicles stick together. An inelastic collision is a situation here. The pace is maintained. Let V be the combined speed of the two vehicles.
Using conV = 29.11 m/s, it is determined.
Thus, the combined speed of the two cars is 29.11 m/s. Therefore, this is the necessary solution. momentum preservation as:
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what is the process where dna can change in many ways?
Answer:
process of recombination
Explanation:
this process happens when 2 molecules of DNA exchange pieces of their genetic material with each other
A person seated on a tree branch is at rest with reference to
A person seated on a tree branch can be at rest with reference to various objects or frames of reference, depending on what is being considered as the fixed point.
For example, if we consider the person as being at rest with respect to the tree branch, then the branch and the person are in the same reference frame, and the person is stationary with respect to the branch.
If we consider the person as being at rest with respect to the ground, then the person's velocity relative to the ground is equal to the velocity of the tree branch relative to the ground. This means that if the branch is stationary with respect to the ground, then the person is also stationary with respect to the ground. If the branch is moving with respect to the ground, then the person is also moving with the same velocity as the branch relative to the ground.
In addition, the person may also be at rest with respect to the surrounding environment, such as the air, nearby objects, or the Earth's gravitational field. However, it's important to note that different reference frames may give different descriptions of the same physical situation. Therefore, when describing motion, it's essential to specify the reference frame being used to make accurate observations and measurements.
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You are investigating the eruption history of a volcano. You find that the volcano has generated multiple lava flows that spread over large areas over the past 10,000 years. There is very little tephra. People in the nearby town remember the last eruption, when lava flows caused some forest fires. Based on this description, how would you classify the state of the volcano?
O Active Recently Erupting
O Active-Dormant
O Lurking
O Extinct
Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."
The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.
Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.
The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.
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please HELP ME!! i will give brainliest :)
Medical imaging of your bones and some other body parts uses a type of electromagnetic wave that
can pass through matter and produce two-dimensional images on a detector behind the body part. What
type of electromagnetic radiation does this process use? How is the image produced?
Answer:
It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.
Answer:
It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.
haha ctrl + v go brrrrrrrrrrrrrr
A hiker walks 5.0 kilometers due north for twenty minutes. He turns due west and travels 12 kilometers in 60 more minutes. Then he walks 7.0 kilometers due north in forty minutes. What is the average speed of the hiker when traveling north?
Answer:
The hikers average speed due north is 0.2 km per minute.
Explanation:
Speed is the ratio of distance moved by a body to the time taken.
i.e speed = \(\frac{distance}{time}\)
Since the hiker walks due north and due west, then his average speed due north can be determined by;
Average speed = \(\frac{total distance due north}{total time taken}\)
Total distance due north = 5.0 + 7.0
= 12.0 km
Total time taken = 20 + 40
= 60 minutes
= 1 hour
Average speed due north= \(\frac{12}{60}\)
= \(\frac{1}{5}\)
= 0.2
Average speed due north = 0.2 km/minute
The hikers average speed due north is 0.2 km per minute.
QUESTIONS 1. Do thick beds require more time to accumulate than thin beds or laminations?
It's important to note that the time required for bed accumulation can vary greatly depending on the specific depositional setting and the geological context. Therefore, while thick beds generally suggest longer deposition periods, the exact relationship between bed thickness and time can be influenced by a range of geological factors.
The time required for the accumulation of sedimentary beds, whether thick or thin, can vary depending on various factors. Thick beds generally represent a longer period of sediment deposition compared to thin beds or laminations. This is because thick beds typically result from the continuous or episodic deposition of sediment over an extended period of time, whereas thin beds or laminations may form more rapidly or in a shorter time span.
The formation of thick beds can be influenced by factors such as sediment supply, depositional environment, and sedimentation rates. For example, in environments with high sediment input, such as river deltas or turbidite systems, thick beds may accumulate relatively quickly due to the large volume of sediment being transported and deposited.
On the other hand, thin beds or laminations often result from more rapid or intermittent sedimentation processes. These thinner layers can be associated with processes like periodic flooding events, storm deposition, or the settling of fine-grained sediments in calm environments.
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Q- Do car brakes work as well in the wet?
they work less effectively due to the lack of friction on the road when it is wet
pls mark brainliest
Answer: Not really
Explanation: When it's wet, and you slam on the brakes, there's not enough friction with the ground for it to not go spiraling out of control.
which of the following events does not take place in the light reactions?
The event that does not take place in the light reactions is the synthesis of glucose.
The light reactions of photosynthesis occur in the thylakoid membranes of the chloroplasts and involve the capture and conversion of light energy into chemical energy in the form of ATP and NADPH. The primary events that take place in the light reactions include the absorption of light by chlorophyll, the generation of ATP through photophosphorylation, and the production of NADPH through the transfer of electrons.
One of the key products of the light reactions is ATP, which serves as an energy carrier. ATP is generated through the process of chemiosmosis, where the energy from light is used to pump protons across the thylakoid membrane, creating an electrochemical gradient. This gradient drives the synthesis of ATP by ATP synthase.
Another important product of the light reactions is NADPH, which is an electron carrier. NADPH is formed when light energy is used to excite electrons in chlorophyll, which are then passed through a series of electron carriers, ultimately reducing NADP+ to NADPH.
However, the synthesis of glucose, a carbohydrate molecule, does not occur in light reactions. Glucose synthesis takes place during the subsequent dark reactions, also known as the Calvin cycle or the light-independent reactions, where carbon dioxide is fixed and converted into glucose using the ATP and NADPH produced in the light reactions.
In summary, the event that does not take place in the light reactions of photosynthesis is the synthesis of glucose. Glucose synthesis occurs in the subsequent dark reactions of photosynthesis.
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