A person walks 60 meters in 1 minute. Then walks 30 meters in 2 minutes. What is thier average speed over the 3 minute walk?

Answer:

Explanation:

The word force has a precise meaning. A force is exerted on one object by another. The idea of a force is not limited to living things or non-living things. All objects (living and non-living) can apply a force on or to another object also all objects (living and non living) can be affected by forces.

Explanation: It's really blurry and sideways

The mass of the second box car from the calculation is  22317 Kg.

We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;

The momentum before Collison = Momentum after collision

We would then have from the question;

(10300 * 19) + (M * 0) = (10300 + M) * 6

Let the mass of the second box car be M

Then;

195700 = 61800 + 6M

M = 22317 Kg

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The friction from the ice causes a skater weighing 68.5 kg who is initially moving at 2.40 m/s to come to a uniform stop in 3.52 s. The force of friction that the ice exerts on the skater is then 46.7 N.

The force that opposes motion when the surface of one object rubs against the surface of another is known as friction. Friction, or more specifically, a reduction in the ratio of output to input, reduces a machine's mechanical advantage.

The resistive force of friction (Fr), which pushes the objects together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. It is represented by the equation: fr = Fr/N.

a = ∆v/∆t = 2.40 m/s /3.52 s

F = ma = 68.5 kg (0.681818 m/s²)

a = 0.681818 m/s²

F = 46.704545 N

Round to 3 sigfigs: 46.7 N

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Correct Question:

A 68.5-kg skater moving initially at 2.40 m/s on rough horizontal ice comes to rest uniformly in 3.52 s due to friction from the ice. What force does friction exert on the skater?

hope this helps........

Answer:

endoplasmic reticulum

Answer:

product

Explanation:

Answer:

product

Explanation:

You find the product when you multiply two or any number of factors.

Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s

According to the given statement ,we can use the equations of motion and the concept of free fall.  Therefore, the height of the table is approximately 0.085 meters.

To determine the height of the table, we can use the equations of motion and the concept of free fall.

First, let's identify the known values:
- The distance the soda can rolled horizontally, 0.225 m.
- The time it took for the soda can to land, 0.416 s.
- The acceleration due to gravity, which is approximately 9.8 m/s².

Since the can was rolling horizontally, we can ignore any initial vertical velocity and consider only the vertical motion of the can.

Using the equation of motion for vertical displacement:
s = ut + (1/2)at²

Where:
- s is the vertical displacement
- u is the initial vertical velocity (which is zero in this case)
- t is the time
- a is the acceleration due to gravity

In this case, we want to find the height of the table, which is the vertical displacement. So we can rearrange the equation to solve for s:

s = (1/2)at²

Plugging in the values:
s = (1/2) * 9.8 m/s² * (0.416 s)²

Simplifying:
s = (1/2) * 9.8 m/s² * 0.173056 s²

s = 0.085 m

Therefore, the height of the table is approximately 0.085 meters.

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Answer: They are all easy to perform as they are bodyweight exercises.

Explanation:

no difficult exercise so NA. Yes I was plenty of online video to watch to address issues

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

ANSWERS:

A. 38.3 m/s
B. Yes. 38.3 m/s is a very high speed and could potentially cause serious injury or death
C. 656.1 m
D. Not very realistic. The resisting force depends on the speed of the skydiver.

EXPLANATIONS:

(A) To solve for the speed of the skydiver when he lands on the ground, we can use conservation of energy. The initial potential energy of the skydiver is equal to the final kinetic energy plus the final potential energy.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x 1000 m = 784000 J

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 200.0 m = 156800 J

With the parachute closed, the total resisting force is 50.0 N, so we can use the work-energy principle to find the final kinetic energy:

Work done by resisting force = Fd = 50.0 N x (1000 m - 200 m) = 40000 J

Final kinetic energy = Initial potential energy - Work done by resisting force - Final potential energy

Final kinetic energy = 784000 J - 40000 J - 156800 J = 587200 J

Finally, we can solve for the speed using the equation for kinetic energy:

Final kinetic energy = (1/2)mv^2

587200 J = (1/2)(80.0 kg)v^2

v = sqrt(1468 m^2/s^2) = 38.3 m/s

Therefore, the speed of the skydiver when he lands on the ground is 38.3 m/s.

(B) It's difficult to say whether the skydiver will get hurt based solely on the speed of impact. However, 38.3 m/s is a very high speed and could potentially cause serious injury or death. Other factors, such as the angle of impact and the condition of the ground, would also affect the outcome.

(C) We can use the same conservation of energy equation as in part (A), but solve for the height at which the parachute should be opened to achieve a final speed of 5.00 m/s.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x h1

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 0

With the parachute open, the total resisting force is 3600 N, so we can use the work-energy principle to find the work done by the resisting force:

Work done by resisting force = Fd = 3600 N x (h1 - 0) = 3600h1 J

Then we can solve for the height using the equation:

Initial potential energy - Work done by resisting force = Final kinetic energy + Final potential energy

mgh1 - 3600h1 = (1/2)mv^2 + 0

Simplifying and solving for h1:

h1 = (v^2)/(2g) + 3600/g = (5.00 m/s)^2 / (2 x 9.8 m/s^2) + 3600/9.8 = 656.1 m

Therefore, the parachute should be opened at a height of 656.1 m to achieve a final speed of 5.00 m/s.

(D) The assumption that the total resisting force is constant is not very realistic because the resisting force depends on the speed of the skydiver. As the skydiver falls faster, the resisting force will increase due to air resistance. Therefore, the actual speed of the skydiver with the parachute closed and the actual speed with the parachute open would not be constant.

The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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Answer:huh

Explanation:

Answer:

Explanation:

The vertical velocity changes because gravity is what brings the ball downwards, since gravity is what cause acclereation in free fall, acclereatiin will make the velocity become more negative.

There is no force happening on the ball in the horinzontal direction so according to Newton 1st law, the ball will remain in constant velocity n the horinzotnal direction.

The total internal energy of the gas is 5104 Joule.

Internal energy of helium gas=

3/2 × 1.3 × 8.31 × 315

= 5104 joule

Thus, we can conclude that the internal energy of the helium gas is 5104 Joule.

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David's investment strategy should reflect his financial goals, time horizon, and risk tolerance.

David is a 60-year-old individual with moderate financial health, meaning he has a stable financial situation but may have some debt or other financial obligations. He has a short time horizon, which suggests he may need his funds in the near future for retirement or other expenses.

He has a low risk tolerance, indicating that he is unwilling to take significant risks with his investments and may prefer safer, more conservative options. Based on these factors, David may want to consider investments that prioritize capital preservation, such as bonds or fixed-income securities. He may also want to work with a financial advisor to create a diversified portfolio that balances his need for stability with potential returns.

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Is a barred spiral galaxy

Because of it's bar form at the center of the disc

Recent observations seem to indicate that, rather than being a spiral galaxy, the Milky Way may be a barred spiral galaxy.

The key difference between these two types of galaxies is the presence of a central bar-shaped structure composed of stars, gas, and dust in barred spiral galaxies. This bar is thought to play a crucial role in the galaxy's evolution and star formation processes.

The revised classification of the Milky Way is based on data collected from various sources, such as infrared and radio telescopes. These advanced observation tools have enabled astronomers to penetrate through the dust and gas that obscure our view of the Milky Way's central region. The detection of the bar-like structure has provided insights into the gravitational forces influencing the movement and distribution of stars, gas, and dust within our galaxy.

In summary, recent observations have led scientists to conclude that the Milky Way is likely a barred spiral galaxy, characterized by a central bar-shaped structure. This discovery enhances our understanding of the galaxy's dynamics and its role in the evolution of stars and other celestial bodies.

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Explanation:

To accurately determine the contents of the accumulator after the second execution phase (t5), I would need more specific information regarding the context or program being executed. The term "accumulator" typically refers to a register or storage location in a computer system that temporarily holds data during arithmetic or logical operations. The specific value or contents of the accumulator at a given time depend on the instructions executed and the data processed during that phase of the program. Without additional details, it is not possible to provide a specific answer.

Answer: Stars are formed in dust clouds and are found in most galaxies.

Explanation:

Answer: Stars form inside relatively dense concentrations of interstellar gas and dust known as molecular clouds.

Explanation:

As the spring is compressed, it performs

-1/2 (252 N/m) (0.118 m)² ≈ -1.75 J

of work on the clay, while gravity does

(0.263 kg) (9.80 m/s²) (0.118 m) ≈ 0.304 J

on it. Then the total work W performed on the clay ball is approximately -1.45 J.

By the work-energy theorem, W is equal to the change in the clay ball's kinetic energy ∆K. If v is the speed with which it hits the spring, then

W = ∆K

-1.45 J = 0 - 1/2 mv²

Solve for v :

-1.45 J = -1/2 (0.263 kg) v²

v² ≈ 11.0 m²/s²

v ≈ 3.32 m/s

The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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Digital stopwatches and mechanical stopwatches are two types of stopwatches that can be used for timing events. Digital stopwatches use electronic circuits to measure time, while mechanical stopwatches use a mechanical mechanism.

There are a few key differences between these two types of stopwatches.

Firstly, digital stopwatches tend to be more accurate than mechanical stopwatches. Digital stopwatches can measure time with greater precision, often down to hundredths or even thousandths of a second. Mechanical stopwatches, on the other hand, are typically only accurate to within a few tenths of a second.

Secondly, digital stopwatches are generally easier to read. They have a digital display that shows the elapsed time in clear, easy-to-read numbers. Mechanical stopwatches, meanwhile, use rotating dials or hands that can be more difficult to read, especially when the stopwatch is in motion.

Thirdly, digital stopwatches tend to be more reliable than mechanical stopwatches. Mechanical stopwatches rely on a series of delicate springs, gears, and levers to function. These can be prone to wear and tear, and can malfunction if they are not maintained properly. Digital stopwatches, on the other hand, use solid-state electronics that are less susceptible to damage.

In summary, while both digital and mechanical stopwatches can be used for timing events, digital stopwatches tend to be more accurate, easier to read, and more reliable than mechanical stopwatches. However, some people may prefer the aesthetic or tactile experience of using a mechanical stopwatch.

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AnswerAnswer: 49 h

Explanation:

You would have to work at an activity of 1000 J/s for 50 hours to lose 4.5 kg. The correct answer is C. 50 h.

According to the law of conservation of energy, the amount of energy used must equal the amount of energy lost.

So, we can use the equation

E = m × c × ΔT,

where E is the amount of energy used, m is the mass of the object, c is the specific heat capacity of the object, and ΔT is the change in temperature.

In this case, we are trying to find the amount of energy required to lose 4.5 kg, so we can plug in the values and solve for E:

E = 4.5 kg × 1000 J/kg°C × ΔT

We can rearrange the equation to solve for ΔT:

ΔT = E / (4.5 kg × 1000 J/kg°C)

We are told that the activity uses 1000 J/s, so we can plug in this value for E:

E = 1000 J/s × t,

where t is the amount of time in seconds

Now we can plug this value of E back into the equation for ΔT:

ΔT = (1000 J/s × t) / (4.5 kg × 1000 J/kg°C)

Simplifying the equation gives us:

ΔT = t / (4.5 × 1000 s)

We can rearrange the equation to solve for t:

t = ΔT × 4.5 × 1000 s

Since we are trying to find the amount of time in hours, we can divide by 3600 s/h to convert from seconds to hours:

t = (ΔT × 4.5 × 1000 s) / 3600 s/h

Simplifying the equation gives us:

t = ΔT × 1.25 h

Finally, we can plug in the value of ΔT that we are given (4.5 kg) and solve for t:

t = 4.5 kg × 1.25 h

t = 5.625 h.

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Answer:

The velocity of a water wave depends on the properties of the medium through which it is propagating, such as the density and elasticity of the medium. It does not depend on the wavelength of the wave.

Therefore, if the wavelength of a water wave decreases, its velocity does not change. However, the frequency of the wave will increase, as frequency and wavelength are inversely proportional to each other for a wave with a constant velocity. This means that more waves will pass through a given point in a unit of time, which can affect other properties of the wave, such as its intensity and energy.