A net force of 200 N is applied to a 20 kg cart that is already moving at 3
m/s. The final speed of the cart was 8 m/s. For how long was the force
applied? *

Answer:33

Explanation:

F = frequency

N =  Node count

w = wave lenght

v = wave velocity

L = distance wave traveled

First find wave length of laser

w = (2/(N))*(L)

w = (2/(10))*(8)

w = 1.6

then using (w), find velocity

V =  (w)(F)

V = (1.6)*(108)

V = 288

Plug in V and the new frequency to solve for new node count

F = NV/2L

(600) = (N)*(288) / 2 * (8)

(N) = 33.33

there are 33 nodes

Answer:

jenny

Explanation:

In this case, we need to calculate the weight

then we calculate the force in the y-axis

and then we use the formula to calculate the work

where W is the work, F is the force and d is the distance

therefore the correct choice is 13,700 J

Normal force exerted on the person by the bench as she passes through the highest point of her motion is 736.5 N.

The force that surfaces exerts to prevent solid objects from passing through each other is called normal force .

To find force of gravity acting on the person, we use the equation:

Fg = mg

Fg is force of gravity, m is mass of the person, and g is acceleration due to gravity.

Force of gravity on the person :

Fg = (75 kg) x (9.81 m/s^2) = 736.5 N

Given, radius 9.0 m and a period of 8.0 s. Speed of the person can be found using equation:

v = 2πr/T

v is speed of the person, r is radius of the Ferris wheel, and T is period.

v = 2π(9.0 m)/8.0 s ≈ 7.07 m/s

normal force is: Fn = Fg = 736.5 N

Therefore, the normal force exerted on the person by the bench as she passes through the highest point of her motion is 736.5 N.

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Answer:

Answer C. 18.0km/h hope this helps you :)

Explanation:

Answer:

Its rotation will be 3.89x10⁴ rad/s.

Explanation:

We can find the rotation speed by conservation of the angular momentum:

\( L_{i} = L_{f} \)

\( I_{i}\omega_{i} = I_{f}\omega_{f} \)   (1)

The initial angular speed is:

\( \omega_{i} = \frac{1 rev}{7 d} = 0.14 \frac{rev}{d} \)

The moment of inertia (I) of a sphere is:

\( I = \frac{2}{5}mr^{2} \)    (2)

Where m is 9 times the sun's mass and r is the sun's radius

By entering equation (2) into (1) we have:

\( \frac{2}{5}m_{i}r_{i}^{2}\omega_{i} = \frac{2}{5}m_{f}r_{f}^{2}\omega_{f} \)

\(9m_{sun}(696342 km)^{2}0.14\frac{rev}{d} = \frac{3}{4}9m_{sun}(13 km)^{2}\omega_{f}\)

\(\omega_{f} = \frac{4}{3}*0.14 \frac{rev}{d}(\frac{696342 km}{13 km})^{2} = 5.36 \cdot 10^{8} \frac{rev}{d}*\frac{1 d}{24 h}*\frac{1 h}{3600 s}*\frac{2\pi rad}{1 rev} = 3.89 \cdot 10^{4} rad/s\)          

Hence, its rotation will be 3.89x10⁴ rad/s.

I hope it helps you!                                                        

Answer:

emergencies

Explanation:

This is what I got when I unscrambeled it

i think that would be magnetesium

Answer:the gravitational force is always directed towards the centre of the earth

Explanation:

Answer:

19600 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 2000 kg.

w = m x g

w = 2000 kg x 9.8 m/s^2

w = 19600 N

The weight of the object is 19600 N (newtons).

Answer:

the answer i 2000kg

Explanation:

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer:

The surface is rough, because the work-energy theorem indicates the block should be traveling faster at point  K .

Explanation:

Correct. Using the work-energy theorem, the speed at point K would be U1+K1=U2+K2

0+1/2mv^21=mgh2+1/2mv^22

v2= square root v^21−2gh2

=square root (7ms)^2−(2)(10)(2m)(sin30)

v2=5.4ms.

Since the actual speed at point K is slower than this value, there must have been friction between the block and surface.

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

The theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

The theory of uniform accelerated motion is a scientific statement regarding the acceleration of an object in steady conditions.

This theory (uniform accelerated motion) is fundamentally applied in physic and astrophysics.

In conclusion, the theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

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(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.

(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.

Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

average velocity = total distance / total time

v = (d)/(0.5d/v₁ + 0.5d/v₂)

where;

90 km/h = (d) / (0.5d/48 + 0.5d/v₂)

90(0.5d/48 + 0.5d/v₂) = d

0.9375d + 0.5d/v₂ = d

d(0.9375 + 0.5/v₂) = d

0.9375 + 0.5/v₂ = 1

0.5/v₂ = 0.0625

v₂ = 0.5/0.0625

v₂ = 8 km/h

Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.

The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.

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Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Answer:

45,000 J

General Formulas and Concepts:

Energy

Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)

Explanation:

Step 1: Define

Identify variables

[Given] m = 900 kg

[Given] v = 10 m/s

Step 2: Solve for KE

Take into account that pressure at a depth h due to the weight of a fluid in a recipient is given by the following formula:

where ρ is the density of water, g is the gravitational acceleration constant and h os the depth at which we are interested in calculating the pressure.

As you can notice, the pressure does not depend of the area of the mouth of the container. The pressure depends on density and depth. Then, for containers with different motuh areas but the same depth, the pressure will be the same.

Hence, the answer is:

E) none of these

The impact speed of the mouse is 23.3 m/s as per the data given in the question.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

To solve for the impact speed, we can use the following equation:

\(v^2 = u^2 + 2as\)

Where:

v = impact speed,

u = initial speed (which is the horizontal speed of the owl),

a = acceleration due to gravity (9.8 m/\(s^2\)), and

s = vertical distance fallen (15.0 m).

Substituting the known values, we get:

\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)

\(v^2\) = 256 + 294

\(v^2\) = 550

v = sqrt(550 )

v = 23.3 m/s

Thus, the impact speed of the mouse is 23.3 m/s.

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Answer:

The maximum speed is  \(u = 22 \ m/s\)

Explanation:

From the question we are told that

   The distance covered by the debris is \(R = 50 \ m\)

The maximum range of the debris projectile is mathematically represented as

      \(R = \frac{ u^2 sin^2 \theta }{g}\)

At maximum  \(\theta = 90 ^o\)

Now making u which is the maximum speed at which debris was blown outward by the explosion.

  we  have

      \(u = \sqrt{\frac{R * g }{ sin ^2 \theta } }\)

substituting values

          \(u = \sqrt{\frac{50 * 9.8 }{ [sin 90] ^2} }\)

        \(u = 22 \ m/s\)

Answer:

a. \(3.04\times 10^{-8}m\)

b. = 40 km/ million years

Explanation:

The computation is shown below;

According to the question, Data provided in the question

Average speed = 4.0 cm / per year

Distance move in 1 second at this speed

Based on the above information

a. For distance move in 1 second is

As we know that

\(d_1 = v_g \times t\\\\ = 4\ cm \times \frac{1}{100\times 365.25\times 3,600} \times 1\s\\\\= 3.04\times 10^{-8}m\)

b. For speed per kilometer per million years is

\(v_1 = 4\times \frac{10^6}{10^5} \\\\\)

= 40 km/ million years

Answer:

n/a

Explanation:

this question is not feasible

Answer:

SO I TESTED POSITIVE FOR CORONA IS A SIMPTOM DIEURREUH C SINCE I GOT CORNA I HAVE BEEN HAVE big DIEURREE UH

Explanation:

The output at which MC and MR are equal is the maximum profit.

When the final unit of sales (marginal revenue) equals the final unit of production's cost, the management has maximized profit (marginal cost). The production level at which MC = MR is known as maximum profit.

Profit = Total Revenue - Total Cost is a key component of the profit maximisation formula. In light of the fact that the first order—MR = MC—and subsequent orders are dependent upon one another, a company maximizes profit when MR = MC.

As an illustration, let's say you believe that at a price of $10, you can sell 200 items while racking up $1,000 in fixed expenses and $800 in variable costs. At this pricing point, there is a total revenue of $2,000 ($200 x $10). The profit is $200 due to the $1,800 total in expenses.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Answer:

There are stars in our galaxy that appear to be over 15 billion years old.

Explanation:

Answer:

B. 23 kg*m/s north

Explanation:

p_1 = p_2

(m*v)_1 + (m*v)_2 = (m*v)_1' + (m*v)_2'

(70kg*1.4m/s)+(75kg*-1.0m/s) = p_2

(98kg*m/s)+(-75kg*m/s) = 23kg*m/s north

B. 23 kg*m/s north

Two hockey players are about to collide on the ice, so the total momentum of the system when they collide is  23 kg m/s. Hence, option B is correct.

The result of a particle's mass and velocity is momentum. It has both magnitude and direction because momentum is a vector quantity. According to Isaac Newton's second law of motion, the force pushing a particle has an equal and opposite effect on the temporal rate at which its momentum changes.

\(Momentum (p)= Mass(m)*Velocity(v)\)

The given values according to the question is :

p₁ = p₂

(m × v)₁+ (m × v)₂ = (m × v)₁' + (m × v)₂'

(70 kg × 1.4 m/s) + (75 kg) × (-1.0 m/s) = p₂

(98 kg m/s) + (- 75 kg m/s) = 23 kg m/s North

Therefore, the total momentum after collision is 23 kg m/s North.

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Answer:

18.36 m/s

Explanation:

We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:

1/2mv^2=mgh

m=mass

g=gravity

h=height

v=velocity

We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.

19m-1.8m=17.2m

Now we can plug in our variables to solve for velocity.

First we negate mass since its on both sides and cancels out leaving us with.

1/2v^2=gh

Plug in.

1/2v^2=(9.8)(17.2)

1/2v^2=168.56

v^2=337.12

v=18.36m/s