Answers
The distance of center of gravity from tail. now torque balance about center of gravity 1.58m
Let the total weight be w.
Then weight carried by front leg=60% of w
=0.6w
weight carried by back leg
=w-0.6w
=0.4w
Here d is the distance of center of gravity from tail. now torque balance about center of gravity.
The torque or moment is the result of the force and the perpendicular distance from the center of gravity for an open object or from the pivot for a closed item to the pivot. In the same way that a force causes a translation, a torque, which is also a vector variable, causes a rotation.
T1=T2
F1 X L1=F2 X L2
0.40(d-0.5)=0.6w(0.5+1.8-d)
2(d-0.5)=3(2.3 - d)
2d - 1= 6.9-3d
5d=7.9
d=7.9/5=1.58m
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Related Questions
A student hangs a slinky over the edge of a stairwell. The slinky is stretched so that it is just above the ground. The student sends a pulse down the slinking and measures the speed to be 18m/s. The student then vibrates the slinky with a frequency of 4.5 Hz and notices that 4 nodes produced. The end near the floor is an open end and the end where the student his holding the slinking is a fixed end.] How high is the stairwell?
a) Calculate the wavelength of the slinky. (4.0 m)
b) Draw a well labelled diagram of the situation. (because of one open end, there are 3.5 loops)
c) Calculate the height of the stairwell. (h = 7 wavelength quarters, 7/4λ = h, h = 7.0 m)
Answers
The drawing of the wave in the slinky shows the node and antinode
in the form of a standing wave pattern.
The correct responses;a) 4.0 metersb) Please find attached the drawing of the wave motion in the slinkyc) 7.0 mMethod used to arrive at the response above:Given parameters;The speed of the wave pulse through the slinky, v = 18 m/s
The frequency with which the student vibrates the slinky, f = 4.5 Hz
Number of nodes in the slinky, n = 4 nodes
a) Wavelength of the slinky λ:
The wavelength of the slinky, λ, is given as follows;
\(\displaystyle \lambda = \mathbf{ \frac{v}{f}}\)
Therefore;
\(\displaystyle \lambda = \frac{18 \, m/s }{4.5 \, Hz} = \mathbf{4.0 \, m}\)
The wavelength of the wave formed on the slinky, λ = 4.0 metersb) Drawing of a well labelled diagram of the situation:The attached drawing of the situation shows the wavelength of the
wave equal to the distance between three consecutive nodes, N
The number of loops = 3 complete loops + Half of a loop = 3.5 loops
c) To calculate for the height of the stairwell:The length of the wavelength, λ = Length of two complete loops
Height of the stairwell = 3.5 loops
2 loops = λ
Therefore;
\(\displaystyle Height \ of \ stairwell = \frac{\lambda}{2 } \times 3.5 = \mathbf{1.75 \cdot \lambda}\)
Which gives;
Height of the stairwell, h = 1.75 × 4.0 m = 7.0 mLearn more about wave motion here:
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Explain the light detection technique of photovoltaic detection
Answers
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
Learn more about Photovoltaic detection
What three factors affect the viscosity of magma
Answers
2. The dissolved gases it contains
3. It’s chemical composition
The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.
What is magma?It is a mixture of solid, volatile and liquid materials.
Characteristics of the viscosity of magmaIt is a mixture of chemical components that form high-temperature silicates.It includes substance in solid, liquid and gaseous state due to the temperature of the magma which is above the melting points of certain components.Volcanic eruptions often occur when the vapor pressure of the gases becomes greater than the pressure exerted by the solid rocks that keep the magma confined.Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.
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A car is moving at 5 m/s. 2 seconds later, it is traveling at 17 m/s. How far did the car go?
Equation 1: Vf = Vo+at
Equation 2: Vf2=V0+2ad
Equation 3: Xf=X0+vot+12at2
Equation 4: Xf=X0+(vf+vo2)t
Answers
Answer:
gh
Explanation:
how is the study of physics applied in mining engineering
Answers
Answer:
I hope it's help
Explanation:
Brainliest me pls tysm
frequently in physics, one makes simplifying approximations. a common one in electricity is the notion of infinite charged sheets. this approximation is useful when a problem deals with points whose distance from a finite charged sheet is small compared to the size of the sheet. in this problem, you will look at the electric field from two finite sheets and compare it to the results for infinite sheets to get a better idea of when this approximation is valid.
Answers
The period which is expressed in units of years and D which is the distance from the earth to the sun is 8 years.
According to Kepler's Third Law, \(P^2 = D^{\frac{3}{2}}\)where, P the period which is expressed in units of years and D which is the distance from the earth to the sun which is expressed in units of AU
Thus, P =\(D^{\frac{3}{2}}\) .For a planet that has
D= 4AU,
P = \((4)^{\frac{3}{2}}\)
P=\((4 \times 4\times 4)^{\frac{1}{2}}\)
= 8years
The square of a planet's period of revolution around the sun in an elliptical orbit is directly proportional to the cube of its semi-major axis, states Kepler's law of periods. The time it takes for one rotation to complete depends on how closely the planet orbits the sun. With the use of the equations for Newton's theories of motion and gravitation, Kepler's third law assumes a more comprehensive shape.
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5. A tennis player hits a ball when it is at a height of 1.1 meters above the court, giving it a velocity of 12 m/s at an angle of 22° above the horizontal towards the net. The net is 1.81 meters high and stands 2.6 meters from the player.
a) Show that the ball will just pass over the net.
b) Find when and where the ball hits the ground.
Answers
According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).
How to determine if the ball will clear the net?To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.
How to find when and where the ball hits the ground?To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.
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If the wave pictured above oscillates up and down 25 time in 10
seconds, what is the frequency?
Answers
Answer:
Frequency = 25 / 10 = 2.5 Hz
Explanation:
If the wave oscillates up and down 25 times in 10 seconds, then the frequency can be calculated as follows:
Frequency = Number of oscillations / Time
In this case, the number of oscillations is 25, and the time is 10 seconds. Therefore, the frequency is:
Frequency = 25 / 10 = 2.5 Hz
So the frequency of the wave is 2.5 Hertz, which means it completes 2.5 cycles or oscillations in one second.
pls help me solve dis
Answers
Answer:
9 Ω
Explanation:
The following data were obtained from the question:
Resistor 1 (R1) = 3 Ω
Resistor 2 (R2) = 3 Ω
Resistor 3 (R3) = 3 Ω
Resistor 4 (R4) = 3 Ω
Resistor 5 (R5) = 3 Ω
Resistor 6 (R6) = 3 Ω
Resistor 7 (R7) = 3 Ω
Resistor 8 (R8) = 3 Ω
Resistor 9 (R9) = 3 Ω
Resistor 10 (R10) = 3 Ω
Resistor 11 (R11) = 3 Ω
Resistor 12 (R12) = 3 Ω
Equivalent Resistance (R) =.?
From the above diagram,
Resistor 1, 2, 3, 4, 5 and 6 are in series connection and in parralle connections with Resistor 7, 8, 9, 10, 11 and 12 which are also in series connection.
Thus we shall determine the equivalent resistance of Resistor 1, 2, 3, 4, 5 and 6
This is illustrated below:
Resistance Ra = R1 + R2 + R3 + R4 + R5 + R6
Ra = 3 + 3 + 3 + 3 + 3 + 3
Ra = 18 Ω
Next, we shall determine the equivalent resistance of Resistor 7, 8, 9, 10, 11 and 12.
This is illustrated below:
Resistance Rb = R7 + R8 + R9 + R10 + R11 + R12
Rb = 3 + 3 + 3 + 3 + 3 + 3
Rb = 18 Ω
Thus, Ra and Rb are in parallel connections. The equivalent resistance between A and B can be obtained as shown below :
Ra = 18 Ω
Rb = 18 Ω
Equivalent resistance R =?
1/R = 1/Ra + 1/Rb
1/R = 1/18 + 1/18
1/R = 2/18
1/R = 1/9
Invert
R = 9 Ω
Therefore, the equivalent resistance between A and B is 9 Ω.
Which of these accurately identify characteristics of light and mechanical waves? Select the TWO (2) that apply.
A. Light waves are electromagnetic waves that can travel through a vacuum.
B. Mechanical waves can travel through a vacuum
C. Light waves need a medium through which to travel.
D. Water waves are examples of mechanical waves.
Answers
The two correct statement are A and B. Light waves are electromagnetic waves that can travel through a vacuum. Mechanical waves can travel through a vacuum.
What is an electromagnetic wave?
EM waves are the electromagnetic radiations are made up of electromagnetic waves created when an electric field collides with a magnetic field.
Electromagnetic waves may alternatively be defined as the combination of oscillating electric and magnetic fields.
Electrically charged particles experiencing acceleration create electromagnetic waves, which can then interact with other charged particles and exert force on them.
The two correct statement is;
1. Light waves are electromagnetic waves that can travel through a vacuum.
2. Mechanical waves can travel through a vacuum.
Hence,two correct statement are A and B.
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A 2kg block on a horizontal table is pulled to the right by a constant force of 16N the acceleration of the block is 3m/s^ 2 Determined the coefficient of kinetic friction between the block and the table top
Answers
The coefficient of kinetic friction between the block and the table top is 0.204.
Kinetic friction calculation.
To determine the coefficient of kinetic friction, we can use the equation for the net force acting on the block:
F_net = ma
where F_net is the net force, m is the mass of the block, and a is the acceleration of the block. The net force is the difference between the applied force and the force of friction:
F_net = F_applied - F_friction
where F_applied is the applied force, and F_friction is the force of friction.
Since the block is moving with constant velocity, the force of friction is equal in magnitude but opposite in direction to the applied force:
F_friction = μ_k * N
where μ_k is the coefficient of kinetic friction, and N is the normal force (equal to the weight of the block, N = mg).
Substituting the expressions for F_net and F_friction into the first equation and solving for the coefficient of kinetic friction, we get:
F_applied - μ_k * N = ma
μ_k = (F_applied - ma) / N
Substituting the given values, we get:
μ_k = (16 N - 2 kg * 3 m/s^2) / (2 kg * 9.8 m/s^2)
μ_k = 0.204
Therefore, the coefficient of kinetic friction between the block and the table top is 0.204.
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A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
Answers
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
A driver travels northbound on a highway at a speed of 25.0 m/s. A police car, traveling southbound at a rate of 40.0 m/s, approaches with its siren producing sound at a frequency of 2500 Hz. (a) What frequency does the driver observe as the police car comes? (b) What frequency does the driver detect after the police car passes him? (c) Repeat parts (a) and (b) for the case when the police car is behind the driver and travels northbound.
Answers
a) The frequency the driver observes as the police car comes = 3036.3 Hz
b) The frequency the driver detects as the police car passes him = 2075.7 Hz
Explanation:The Frequency of the sound, fs = 2500 Hz
The speed of sound in air, v = 343 m/s
The speed of the driver Northbound, vo = 25 m/s
The speed of the driver Southbound, vs = 40 m/s
a) The frequency the driver observes as the police car comes is calculated below
\(\begin{gathered} f_0=f_s(\frac{v+v_0}{v-v_s}) \\ \\ f_0=2500(\frac{343+25}{343-40}) \\ \\ f_0=3036.3Hz \end{gathered}\)b) The frequency the driver detects after the police car passes him is calculated below
\(\begin{gathered} f_0=f_s(\frac{v-v_0}{v+v_s}) \\ \\ f_0=2500(\frac{343-25}{343+40}) \\ \\ f_0=2075.7\text{ Hz} \end{gathered}\)If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
Answers
Answer:
5 m/s
Explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.
A dentist causes the bit of a high speed drill to accelerate from an angular speed of 1.76 x 10^4 rads to an angular speed of 4.61 x 10^4 rat. In the process, the bit turns through 1.97 x 10 ^4 rad. Assuming a constant angular acceleration, how long would it take the reach its maximum speed of 7.99 x 10^4 rads starting from rest?
Answers
The time taken for the bit to reach the maximum speed is 1.35 seconds.
What is the angular acceleration of the bit?The angular acceleration of the bit is determined by applying the following kinematic equation as shown below.
ωf² = ωi² + 2αθ
where;
ωf is the final angular speedωi is the initial angular speedθ is the angular displacementα is the angular accelerationα = (ωf² - ωi²)/2θ
α = (46,100² - 17,600²) / (2 x 19,700)
α = 46,077.4 rad/s²
The time taken for the bit to reach the maximum speed is calculated as follows;
ωf = ωi + αt
t = (ωf - ωi) / α
t = (79,900 - 17,600) / (46,077.4)
t = 1.35 seconds
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Example 3 :
A liquid with relative density 0.9 and dynamic viscosity of 0.06 Pas
flows in a cast iron pipe of length 100 m and diameter 120 mm.
Determine the friction factor using formula method, and then
calculate the head loss using the answer obtained then using
friction factor formula when the velocity is:
a) 1 ms-1
b) 3 ms-1
Answers
The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.
How to determine the friction factorUsing the formula
μ = viscosity = 0. 06 Pas
d = diameter = 120mm = 0. 12m
V = velocity = 1m/s and 3m/s
ρ = density = 0.9
a. Velocity = 1m/s
friction factor = 0. 52 × \(\frac{0. 06}{0. 12* 1* 0. 9}\)
friction factor = 0. 52 × \(\frac{0. 06}{0. 108}\)
friction factor = 0. 52 × 0. 55
friction factor \(= 0. 289\)
b. When V = 3mls
Friction factor = 0. 52 × \(\frac{0. 06}{0. 12 * 3* 0. 9}\)
Friction factor = 0. 52 × \(\frac{0. 06}{0. 324}\)
Friction factor = 0. 52 × 0. 185
Friction factor \(= 0.096\)
Loss When V = 1m/s
Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter
Head loss = 0. 289 × \(\frac{1}{2*6. 6743 * 10^-11}\) × \(\frac{1^2}{0. 120}\) × \(\frac{1}{100}\)
Head loss = 1. 80 × 10^8
Head loss When V = 3m/s
Head loss = \(0. 096\) × \(\frac{1}{1. 334 *10^-10}\) × \(\frac{3^2}{0. 120}\) × \(\frac{1}{100}\)
Head loss = 5. 3× 10^8
Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.
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Help me please..
Speed is?
A) A measure of how fast something is moving
B) The distance covered per unit time
C) Always measured in terms of distance divided by time
D) All of the above
E) None of the above
Answers
C) Always measured in terms of distance divided by time.
A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey
Answers
i) The initial deceleration of the car is -1.6 m/s² and the time taken is 5 seconds
ii) The final deceleration is -1 m/s²
iii) The total dispalcement = 1016 m
What is the initial deceleration of the car?The initial deceleration of the car is given by the formula below:
v² = u² + 2as
where;
v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacementSolving for a;
12² = 20² + 2 * a * 80
a = -1.6 m/s²
Time taken, t = v - u / a
t = 12 - 20 / (-1.6)
t = 5 seconds
Final deceleration:
a = v - u / t
a = 0 - 12 / 12
a = -1 m/s²
iii) Displacement at constant velocity = 12 * 1 * 60
Displacement at constant velocity = 720 m
Final displacement, s = ut + 0.5at²
s = 12 * 12 + 0.5 * 1 * 12²
s = 216 m
Total dispalcement = 80 + 720 + 216
Total dispalcement = 1016 m
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A 75 kg student drives a 650 kg car. What is the applied force on the car if * 5 points the car starts from rest and accelerates to 60 m/s in 8 seconds?
Answers
Answer:
4500 N
Explanation:
Bc f is equal to mass times acceleration and the acceleration is 60
If a 75 kg student drives a 650 kg car, then the car starts from rest and accelerates to 60 m/s in 8 seconds, then the applied force on the car would be 5437.5 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = m × a
As given in problem an If a 75 kg student drives a 650 kg car, the car starts from rest and accelerates to 60 m/s in 8 seconds.
The acceleration of the car = 60 / 8
= 7.5 m / s²
The force applied on the car = 725 × 7.5
= 5437.5 Newtons
Thus, the applied force on the car would be 5437.5 Newtons.
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according to the lecture videos, light has no color, and color exists only in our minds. which of the following are reasons to believe this statement? group of answer choices
Answers
Light is perceived as having color because of the way our brains interpret the wavelengths of light that reach our eyes.
This statement above is based on the scientific understanding of color and light. Light is a type of electromagnetic radiation that travels through space in waves. The color we perceive depends on the wavelength of the light; different wavelengths are perceived as different colors. However, light itself does not have a color, it is simply a form of energy.
Our brain interprets the wavelength of light that enters our eye and assigns it a color based on past experiences and cultural norms. This means that the concept of color is a subjective interpretation, and is not inherent in the light itself. So, it can be said that color exists only in our minds.
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6. Two forces of 50 N and 30 N, respectively, are acting on an object. Find the net force (in N) on the object if … a. the forces are acting in the same direction b. the forces are acting in opposite directions.
Answers
Answer: So, if the forces are in the same direction, it'll be 50N+30N= 80N!
If the forces are in opprsite direction it'll be 50N-30N= 20N (or visa-versa)
Explanation: This is because if the forces are in the same direction, like 2 people are pushing a body with 0 mass (I know, weird but imagine it) and both the people are applying the force in the same direction, let's say East, so the total fore exerted on the body will add up to become 50N+30N=80N.
And if the forces are phusing the body in oposite direction, then, let's say the bigger guy is pushing on the West Direction with 50N of force and the weaker guy is pushing on the opposite direction with 30N of force, so this time their forces cancel out and it becomes 50N-30N= 20N (or 30N-50N= -20N).
Do you think Kepler will be able to detect Earth-sized planets in transit?
Answers
Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.
Explanation:
Air currents escape room level 3 how to do it
Answers
Answer:
just do it. it's simple be smart friends
What is the formula to finding your target heart rate
Answers
A 230,000 V-rms power line carries an average power PAV = 250 MW a distance
of 200 km. If the total resistance of the cables is 10 ohms, what is the resistive
power loss?
a. 1.0 MW
b. 2.5 MW
c. 5.4 MW
d. 12 MW
e. 10 kW
Answers
The power loss over the given distance in which the current is carried is 12 MW.
option D is the correct answer.
What is the current carried in the power line?
The current carried in the power line is calculated by applying Ohms law as follows;
V = IR
P = IV
I = P/V
where;
P is the average power of the lineV is the voltageI is the currentI = (250 x 10⁶) / (230,000)
I = 1,086.96 A
The power loss over the given distance in which the current is carried is calculated as;
P = I²R
where;
R is the resistance of the wireP = (1,086.96²) x 10
P = 11.8 x 10⁶ W
P ≈ 12 x 10⁶ W
P = 12 MW
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when a constant force is applied to an object the acceleration of the object varies inversely with its mass. when a certain constant force acts upon an object with mass 4kg, the acceleration of the object is 17m/s^2. when the same force acts upon another object, its acceleration is 2m/s^2. what is the mass of this object?
Answers
The mass of the the object, given that the same force acted upon it to accelerate at 2 m/s² is 34 Kg
How to determine the mass of the objectFirst, we shall determine the force. This can be obtained as follow:
Mass (a) = 4 KgAcceleration (a) = 17 m/s²Force (F) =?Force (F) = mass (m) × acceleration (a)
Force = 4 × 17
Force = 68 N
Finally, we shall determine the mass of the object that will accelerate at 2 m/s² when the force of 68 N is applied to it. Details below:
Acceleration (a) = 2 m/s²Force (F) = 68 NMass (m) = ?Force = mass × acceleration
68 = mass × 2
Divide both sides by 2
Mass = 68 / 2
Mass = 34 Kg
Thus, from the above calculation, we can conclude that the mass is 34 Kg
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6. Find the fundamental units involved in the following derived units.
(i) Newton(N)
(ii) Watt (W)
(iii) Joule (1)
(iv) Pascal (Pa)
(v) Cubic metre
Answers
Answer:
I. force
II. electricity.
III. energy.
iv. pressure.
v. volume.
The engine of a car is usually no more than 20% efficient. In other words, for every 100 J of energy produced by the engine, 20 J are
converted into kinetic energy of the car and 80 J are lost to heat.
Assuming 20% efficiency, the amount of energy needed to move a car 1 km with an average force of 2000 N is
Answers
The amount of energy needed to move the car is 4×10⁵ J
Determination of the energy produced.Force (F) = 2000 NDistance (d) = 1 Km = 1000 mEnergy (E) =?E = Fd
E = 2000 × 1000
E = 2×10⁶ J
Determination of the actual energy needed to move the car to 1 KmFrom the question given above,
For 100 J of energy produced by the engine, 20 J is needed.
Therefore,
For 2×10⁶ J of energy produced = (2×10⁶ × 20) / 100 = 4×10⁵ J is needed.
Thus, 4×10⁵ J of energy is needed to move the car.
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Miranda found four different bottles filled with unknown pure liquids. She measured the mass, volume, and boiling point of these liquids, and calculated the density which are displayed in Table 1.
What conclusion can you make on whether any of the liquids are the same. Explain based on the information in the table.
Answers
Answer:
Samples 2 and 4 are the same liquid
Explanation:
Samples 2 and 4 should be the same liquid because they have the same density as well as the same boiling point. The mass and volumes given do not matter in this case, however they could be used to calculate the density which was already given.
The liquid present in sample 2 and 4 is same as according to forces of attraction they have same density and boiling points.
What are forces of attraction?
Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
The physical properties such as melting point, boiling point, density are all dependent on forces of attraction which exists in the substances.
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Part A Is the electric field strength in (Figure 1) changing, or not changing? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help Ampere-Maxwell law, first half, According to the magnetic field Ampere-Maxwell law, second half, Faraday's law, can create the electric field, and not vice versa. So the figure doesn't make sense. is created by currents. Since there is no current, the figure doesn't make sense. can be created by the static electric field. So the electric field strength is not changing. can be created by the changing electric field. So the electric field strength is changing
Answers
According to Ampere Maxwell's law, the first half, the magnetic field can be created by the changing electric field. So, the electric field strength is changing.
In a static electric field, according to Ampere maxwell law, the divergence at one point is equal to the electric charge volume density ρ at that point divided by ε0. The physical meaning of this statement is that a circulating magnetic field is created by an electric current and also may be by an electric field that changes with time.
An electric current, or we can say a changing electric flux through a surface, has the ability to produce a circulating magnetic field around a path that bounds the given surface. The direction of the current and the induced magnetic field is known by the right-hand rule, as shown below.
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