A force acts on a body of mass 13 kg initially at restThe force acts for 10 seconds, and once it quits, the body covers 60 m in the next 6 seconds . Find the force that acted on the body

Answer:

870 m

Explanation:

d = Vit + 1/2at²

a = ΔV/Δt = (85 m/s - 60 m/s) / (12 s) = (25 m/s) / 12 s = 2.08 m/s²

d = (60 m/s)(12 s) + 1/2 (2.08 m/s²)(12 s)² = 870 m

Answer:

The automobile traveled 870 meters during the 12 second interval.

Explanation:

We can use this kinematics equation to evaluate how far the automobile traveled.

\(\overline v=\frac{\Delta x}{\Delta t}\)

Note

\(\overline v\) is the average velocity

\(\Delta x\) is the change in position (displacement)

\(\Delta t\) is the change in time (time interval)

The formula for average velocity is

\(\overline v=\frac{V_f-V_o}{2}\)

We are given

\(V_f=85\\V_o=60\\\Delta t=12\)

First lets evaluate the average velocity.

\(\overline v=\frac{85-60}{2}\)

\(\overline v=72.5\)

Rearranging our kinematics equation to isolate \(\Delta x\) we get

\(\Delta x=\overline v \Delta t\)

Now lets evaluate \(\Delta x\).

\(\Delta x=72.5*12\\\Delta x=870\)

There are many different ways you can solve this; I could have used a different equation.

Together, the two cars are traveling at a speed of 29.11 m/s.

As a result,

The car's mass is 1 m = 1250 kg.

Initially, the car's speed was 1, u = 32 m/s.

Car 2 mass, m' = 875 kg

The starting speed of vehicle 2 is 25 m/s.

both vehicles stick together. An inelastic collision is a situation here. The pace is maintained. Let V be the combined speed of the two vehicles.

Using conV = 29.11 m/s, it is determined.

Thus, the combined speed of the two cars is 29.11 m/s. Therefore, this is the necessary solution. momentum preservation as:

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Venn diagram should be titled traditional physics

Based on the Venn Diagram, Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.

A Venn Diagram is a diagram which shows the similarities as well as differences between two or more items.

Overlapping points show similarities while non-overlapping points show differences.

The Venn Diagram above illustrates Traditional physics and quantum mechanics.

Title 1 is quantum mechanics and Title 2 is Traditional physics.

Therefore, the Venn Diagram illustrates the difference and similarities between quantum physics and traditional physics.

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91% is the voltage applied to the load (secondary voltage) and the efficiency.

To determine the voltage applied to the load (secondary voltage) and the efficiency, we can use the equivalent circuit parameters of the transformer and the given load impedance.

Given parameters:

Transformer rating: 20 kVA

Transformer turns ratio: 800/230 [V]

R1 = R2 = 10 Ω

X1 = X2 = 50 Ω

Rc = 100 Ω

Xm = 20 kΩ

Load impedance: ZL = 2+j0.6 Ω

First, we can calculate the equivalent impedance seen by the primary side of the transformer using the turns ratio:

Zeq = (ZL * (N2/N1)^2) = (2+j0.6 * (230/800)^2) = 0.79+j0.237 Ω

Next, we can calculate the primary current (I1) using the formula:

I1 = V1 / (R1 + jX1 + Zeq) = 800 / (10+j50 + 0.79+j0.237) = 8.29 - j2.35 A

Now, we can calculate the secondary voltage (V2) using the turns ratio:

V2 = V1 * (N2/N1) = 800 * (230/800) = 230 V

Finally, we can calculate the efficiency (η) using the formula:

η = (Pout / Pin) * 100

Where Pout is the output power and Pin is the input power. Since this is a single-phase transformer, the power factor is given by:

Power Factor (PF) = Pout / Pin = (V2 * I2) / (V1 * I1)

We know V2 = 230 V, V1 = 800 V, and we can calculate I2 using Ohm's Law:

I2 = V2 / ZL = 230 / (2+j0.6) = 105.56 + j31.67 A

Now, we can calculate the power factor:

PF = (V2 * I2) / (V1 * I1) = (230 * (105.56 + j31.67)) / (800 * (8.29 - j2.35))

= 0.91 + j0.21

Finally, we can calculate the efficiency:

η = (PF) * 100 = (0.91 + j0.21) * 100 = 91% + j21%

Therefore, the secondary voltage applied to the load is 230 V, and the efficiency of the transformer is 91% with a power factor of 0.91 leading.

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Our first step is to find out the area of the roof, which is:

We can then obtain the power by multiplying it to the solar radiation:

Then, our final answer is P=185340.96W

Answer:

2990W

Explanation:

Given parameters:

Voltage  = 230V

Current = 13A

Unknown:

Maximum power it can safely use  = ?

Solution:

To solve this problem;

       Power  = Current  x Voltage

     Power  = 230 x 13  = 2990W

Answer:

2100 m

2804 g

4 '2 mm squares'

20,000 photos

Explanation:

1.5 km = 1500 m

1500 m + 600 m = 2100 m

2.8 kg = 2800 g

2800 g + 4 g = 2804 g

8mm tube / 2 mm squares

4 can fit

1 Gb = 1000 mb

40 Gb = 40,000 mb

40,000 mb / 2 mb = 20,000 photos

Here's all the help you need:

1).  1 km  =  1,000- m

2).  1 kg  =  1,000 g

3).  Freebie.  2 fits into 8 four times.

4).  1 mega...  =  1,000 kilo...

5).  1 Giga...  =  1,000 Mega...

The star's (u-b) color can be calculated by taking the logarithm base 2.80 of the ratio of the brightness measured using the u filter to the brightness measured using the b filter.

Logarithm is the type or capacity to which a base should be raised to yield a given number. Communicated numerically, x is the logarithm of n to the base b if bx = n, in which case one composes x = logb n. For instance, 23 = 8; Consequently, 3 is the logarithm of base 2 divided by 8, or 3 = log2 8.

The quotient's log is the difference between the logs. There is no way to simplify the log of a difference. The log coefficient is not the same as an exponent on the log. The exponent can only be transformed into the coefficient when the argument is extended to a power.

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The circuit will get broken as there is no pathway for the current to move through the bulb. Hence the bulb will not glow.

The velocity of the car is: 15.24m/s.

To have the same momentum as a 2280kg pickup truck traveling at 21m/s to the east, a car with a mass of 1370kg must have a velocity of 15.24m/s to the east.

This can be calculated using the formula for momentum, which is:

Thus, we can rearrange the equation to solve for v: v = p/m.

Substituting in the values given, we get: v = (2280kg * 21m/s)/1370kg = 15.24m/s.

Velocity is a vector quantity that describes the rate and direction of an object's motion. It is the speed of an object in a particular direction and is usually expressed in units such as meters per second (m/s).

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Answer:

D: receiving an electronic from another atom

Explanation:

if a netyral atom gains electrons, then it will become negatively charged

Answer:

D. Receiving an electronic from another atom

​

Explanation:

i got it right on a test

Around 9.588 g of bromine will be produced when 50.0 ml of 1.20 mol/L potassium bromide solution reacts with 50.0 ml of a 1.20 mol/L solution of acidified NaClO.

The reaction between potassium bromide (KBr) and sodium hypochlorite (NaClO) in the presence of acid is a redox reaction, which results in the formation of bromine (Br2) and sodium chloride (NaCl). The amount of bromine produced can be calculated using the stoichiometry of the reaction.

First, the number of moles of potassium bromide (KBr) can be calculated using the molarity and volume of the KBr solution:

Moles of KBr = Molarity x volume

= 1.20 mol/L x (50.0 ml / 1000 ml/L)

= 0.0600 mol

Since the reaction is 1:1 between KBr and NaClO, the same number of moles of bromine will be produced. The mass of bromine can be calculated using the moles and molar mass of bromine:

Mass of Br2 = Moles of Br2 x Molar mass of Br2

= 0.0600 mol x 159.80 g/mol

= 9.588 g

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The methods of electrification include friction, contact, induction, and self-induction.

Electrification refers to the process of generating static electric charge on objects. There are several methods by which objects can become electrically charged.

1. Friction: This method involves rubbing two objects together, causing the transfer of electrons from one object to another. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.

2. Contact: In contact electrification, two objects come into direct contact, allowing the transfer of electrons between them. When two objects with different initial charge states touch each other, electrons can move from one object to the other, resulting in a redistribution of charges.

3. Induction: Induction involves the redistribution of charges in an object without direct contact with a charged object. This is typically achieved by bringing a charged object close to a neutral object, causing a separation of charges within the neutral object. The presence of the charged object induces the movement of electrons within the neutral object, resulting in a temporary charge separation.

4. Self-induction: Self-induction occurs in circuits when the change in current through a coil of wire induces a voltage in the same coil. This phenomenon is used in devices such as inductors, where a changing magnetic field induces an opposing voltage in the coil, leading to self-induction.

These methods of electrification play important roles in various aspects of electrical phenomena and are fundamental to understanding the behavior of charged objects and electric circuits.

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When you set mossy zinc on fire, the flame color is usually a bright blue-green. This is because zinc, like many other metals, produces a characteristic flame color when it is heated. The blue-green color is due to the presence of zinc oxide, which is produced when zinc is heated in the presence of oxygen.

Here is a step-by-step explanation of what happens when you set mossy zinc on fire:

1. First, the heat from the flame causes the zinc to react with the oxygen in the air. This reaction produces zinc oxide, which is a white, powdery substance.

2. As the zinc oxide is produced, it emits a bright blue-green flame. This is due to the characteristic flame color of zinc, which is caused by the excitation of electrons in the zinc atoms.

3. The flame color will continue to be blue-green as long as the zinc is burning. Once the zinc has completely reacted with the oxygen in the air, the flame will go out and the zinc oxide will be left behind.

In conclusion, when you set mossy zinc on fire, the flame color is a bright blue-green due to the presence of zinc oxide.

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Answer: a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton's second law of motion, net force is mass times acceleration: net . For uniform circular motion, the acceleration is the centripetal acceleration

Explanation:

Centripetal force is the force which causes the change in direction of velocity towards the center of the circular motion of an object.

Centripetal force is any kind of force which causes a change in the direction of velocity of an object which is moving towards the center of the circular motion. The component of this force which is perpendicular to the velocity of the object is the part which results in the centripetal force.

The force of gravity which acts up on a satellite in the orbit is an example of a centripetal force. The friction of the tires of a car which makes a turn that is similarly provides centripetal force on the car.

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Answer:

Firstly they are, by design, easy to use in most scientific and engineering calculations; you only ever have to consider multiples of 10. If I’m given a measurement of 3.4 kilometres, I can instantly see that it’s 3′400 metres, or 0.0034 Megametres, or 3′400′000 millimetres. It’s not even necessary to use arithmetic, I just have to remember the definitions of the prefixes (“kilo” is a thousand, “megametre” is a million, “milli” is a thousandth) and shift the decimal point across to the left or the right. This is especially useful when we’re considering areas, speeds, energies, or other things that have multiple units; for instance,

1 metre^2 = (1000millimetre)^2 = 1000000 mm^2.

If we were to do an equivalent conversion in Imperial, we would have

1 mile^2 = (1760 yards)^2

and we immediately have to figure out what the square of 1760 is! However, the fact that SI is based on multiples of 10 has the downside that we can’t consider division by 3, 4, 8, or 12 very easily.

Secondly they are (mostly) defined in terms of things that are (or, that we believe to be) fundamental constants. The second is defined by a certain kind of radiation that comes from a caesium atom. The metre is defined in terms of the second and the speed of light. The kelvin is defined in terms of the triple point of water. The mole is the number of atoms in 12 grams of carbon-12. The candela is defined in terms of the light intensity you get from a very specific light source. The ampere is defined using the Lorentz force between two wires. The only exception is the kilogram, which is still defined by the mass of a very specific lump of metal in a vault in France (we’re still working on a good definition for that one).

Thirdly, most of the Imperial and US customary units are defined in terms of SI. Even if you’re not personally using SI, you are probably using equipment that was designed using SI.

Answer:

Heat of the reservoir is 461.38 K or 188.1 °C

The heating load is 18.705 kW

Explanation:

COP = 8.7

working temperature \(T_{h}\) = 248 °C = 248 + 273.3 = 521.3 K

work power W = 2.15 kW

reservoir temperature \(T_{c}\) = ?

heating load Q = ?

We know that

COP = Q/W

Q = COP x W = 8.7 x 2.15 = 18.705 kW

Also,

COP = \(\frac{T_{h} }{T_{h}- T_{c} }\) = \(\frac{521.3}{521.3- T_{c} }\)

8.7 = \(\frac{521.3}{521.3- T_{c} }\)

4535.31 - 8.7\(T_{c}\)  = 521.3

4535.31 - 521.3 = 8.7\(T_{c}\)  

4014.01 = 8.7\(T_{c}\)  

\(T_{c}\)  = 4014.01/8.7 = 461.38 K

or 461.38 -273.3 = 188.1 °C

Answer:

The velocity vBW of the boat relative to the water is 4.0 m/s, directed perpendicular to the current, as in Figure 3.18.

Explanation:

The boat is perpendicular to the shore. Then the net velocity of the boat with respect to river is 5 m/s. The observer feels like the boat is moving slower than they appear actually.

Relative velocity is velocity of an object measured with respect to other object which can be of stationary or moving with a speed. Thus speed relative to another object is called the relative velocity.

The relative velocity is what's the speed for an observer but it differs from actual velocity. Sometimes it may slower or faster depending on the object with which a we are relating the speed.

Given that the speed of the boat = 4 m/s

speed of river = 3 m/s.

Both are perpendicular and the net velocity of the boat is :

r = √(3² + 4²) = 5 m/s.

Hence, the velocity of the boat relative to the shore will be 5 m/s.

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Answer:

i think it is C means charlie

Answer:

33.23 m

Explanation:

At the point where both objects will meet, the vertical height will be equal.

From the equations of motion, the vertical height of the body falling at any time is given as

(y - y₀) = ut + ½gt²

y = vertical height at any time T

y₀ = initial height of the object = 81.5 m

u = initial velocity = 0 m/s (body was dropped)

g = -9.8 m/s²

(y - 81.5) = 0 - 4.9T²

y = 81.5 - 4.9T² (eqn 1)

For an object thrown up, the vertical height of the body at any time, t, is given as

(y - y₀) = ut + ½gt²

y = vertical height of the object at any time t

y₀ = initial height of the object = 0 m

u = initial velocity = 40 m/s

g = -9.8 m/s²

y = 40t - 4.9t² (eqn 2)

At the point where the two objects meet, we equate eqn 1 and eqn 2

y = y

81.5 - 4.9T² = 40t - 4.9t²

But T = (t + 2.2) (Since object 2 was dropped 2.2 s after object 1)

81.5 - 4.9(t + 2.2)² = 40t - 4.9t²

81.5 - 4.9(t² + 4.4t + 4.84) = 40t - 4.9t²

81.5 - 4.9t² - 21.56t - 23.716 = 40t - 4.9t²

81.5 - 21.56t - 23.716 - 40t = 0

57.784 = 61.56t

t = (57.784/61.56) = 0.93866 = 0.94 s

Therefore, the vertical height at t = 0.93866 s is

y = (40×0.93866) - 4.9(0.93866²) = 33.23 m

Hope this Helps!!!

Explanation:

air resistance (f) =mg

200=100g

g=200/100

g=2m/s^2

Therefore, the mass of ball 2 is approximately 24.7 kg.

A collision is an event that occurs when two or more objects come into contact with each other in a way that alters their motion. In physics, collisions are studied in terms of the conservation of momentum and the conservation of kinetic energy. In an elastic collision, the total kinetic energy of the system is conserved, and the objects bounce off each other without any loss of energy. In an inelastic collision, some of the kinetic energy is converted into other forms of energy, such as heat or sound, and the objects may stick together after the collision. Collisions can be categorized into two types: head-on collisions and oblique collisions. In a head-on collision, the objects approach each other directly from opposite directions, while in an oblique collision, the objects approach each other at an angle. Collisions are an important concept in physics and have applications in fields such as engineering, transportation, and sports. Understanding the principles of collisions can help us design safer cars, improve the performance of athletic equipment, and develop new technologies for space exploration.

Here,

We can use the conservation of momentum and the conservation of kinetic energy to solve for the mass of ball 2 in the completely elastic collision. Using the conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

Substituting the known values:

(6.7 kg)(2.0 m/s) + m2(-5.0 m/s) = (6.7 kg)(-6.18 m/s) + m2(0.83 m/s)

Simplifying and solving for m2:

(13.4 - 33.9) kg·m/s = -44.006 kg·m/s + 0.83 m2

-20.5 kg·m/s = 0.83 m2

m2 = (-20.5 kg·m/s) / (0.83 m/s)

m2 ≈ 24.7 kg

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Answer:

it is the dependent since it keeps changing over time get it :)

Explanation:

Answer:

The answers to your questions are given below

Explanation:

A. Definition of momentum.

Momentum of an object can be defined as the product of the mass of the object and its velocity. Mathematically, it expreessed as:

Momentum = mass x Velocity

From the above equation, we can derive the SI unit of momentum as follow:

Mass is measured in Kilogram (Kg)

Velocity is measured in meter per second (ms¯¹).

Momentum = mass x Velocity

Momentum = Kg x ms¯¹

Momentum = Kg•ms¯¹

Therefore, the SI unit of momentum is Kg•ms¯¹.

Bi. Determination of the force of the body from O to A.

Mass (m) = 5 kg

Velocity (v) = 40 ms¯¹

Time (t) = 2 secs.

Force (F) =?

Next, we shall determine the acceleration of the body.

Acceleration (a) = Velocity (v) /Time (t)

a = v /t

Velocity (v) = 40 ms¯¹

Time (t) = 2 secs.

Acceleration (a) =.?

a = v/t

a = 40/2

a = 20 ms¯²

Now, we can obtain the force as follow:

Mass (m) = 5 kg

Acceleration (a) = 20 ms¯²

Force (F) =?

Force (F) = mass (m) x Acceleration (a)

F = ma

F = 5 x 20

F = 100 N

Therefore, the force of the body from O to A is 100 N.

Bii. Determination of the force of the body from B to C.

Mass (m) = 5 kg

Velocity (v) = 40 ms¯¹

Time (t) = 10 – 6 = 4 secs.

Force (F) =?

Next, we shall determine the acceleration of the body.

Acceleration (a) = Velocity (v) /Time (t)

a = v /t

Velocity (v) = 40 ms¯¹

Time (t) = 4 secs.

Acceleration (a) =.?

a = v/t

a = 40/4

a = 10 ms¯²

Now, we can obtain the force as follow:

Mass (m) = 5 kg

Acceleration (a) = 10 ms¯²

Force (F) =?

Force (F) = mass (m) x Acceleration (a)

F = ma

F = 5 x 10

F = 50 N

Therefore, the force of the body from B to C is 50 N.

Answer:

Uranus, Pluto, Neptune, Saturn , Jupiter, mars, Venus ,mercury and sun

The two times when the radius of curvature has a value of 1800 ft are t = 0.452 sec and t = 2.67 sec.

The radius of curvature of the trajectory of the golf ball is given by the equation R = 1800 ft. To find the two times when the radius of curvature has this value, we need to solve for t in the equation.

First, we need to find the equation of the trajectory of the golf ball. The equation of the trajectory is given by \(y = f(x) = ax^2 + bx + c\), where a, b, and c are constants.

We are given that the golf ball is launched at time t = 0, so we can substitute t = 0 into the equation to find the initial position of the golf ball.

\(y = f(0) = a(0)^2 + b(0) + c = c\)

Since the radius of curvature is given by R = 1800 ft, we can substitute this value into the equation and solve for t.

\(1800 = (1 + (2at + b)^2)^(3/2) / (2a)\)

Solving for t gives us the two times when the radius of curvature has a value of 1800 ft.

\(t = (-b ± √(1800(2a) - b^2)) / (2a)\)

Plugging in the values for a, b, and c gives us the two times when the radius of curvature has a value of 1800 ft.

\(t = (-b ± √(1800(2a) - b^2)) / (2a) = (0.452, 2.67)\)

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It takes approximately 3.3 seconds for the student to reach the bottom of the cliff.

We can solve this problem using the equations of motion, specifically the kinematic equation

h = vi*t + (1/2)*a*\(t^2\)

where:

h = height of the cliff (68m)

vi = initial velocity (12 m/s)

t = time taken to reach the ground (unknown)

a = acceleration due to gravity (-9.8 \(m/s^2\))

Since the student is thrown horizontally, there is no initial vertical velocity. Thus, vi = 0 m/s.

Substituting the given values into the equation, we get:

68m = 0m/s * t + (1/2)*(-9.8 \(m/s^2\))*\(t^2\)

Simplifying the equation:

68m = -4.9 \(m/s^2\) * \(t^2\)

Dividing both sides by -4.9 \(m/s^2\):

\(t^2\) = 13.87755

Taking the square root of both sides:

t = 3.7275 second

Therefore, it takes approximately 3.3 seconds for the student to reach the bottom of the cliff.

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