Given
The fixed charge is q=62.92 mC
The other charge is q'=7.21 mC
The distance is r=8.57 cm=0.0857 m
To find
The work done
Explanation
The potential is
\(\begin{gathered} V=\frac{kq}{r} \\ \Rightarrow V=9\times10^9\frac{62.92\times10^{-6}}{0.0857} \\ \Rightarrow V=6.6\times10^6V \end{gathered}\)Work done is
\(\begin{gathered} W=q^{\prime}V \\ \Rightarrow W=7.21\times10^{-6}\times6.6\times10^6=47.586\text{ J} \end{gathered}\)Conclusion
The work done is 47.586 V
A capacitor has plates of area8.89 x 10-4 m2. To create acapacitance of 1.11 x 10-8 F, howfar apart should the plates be?[?][?] × 10¹²¹ m
The capacitance of a capacitor is calculated based on 3 values, area of plates, distance between them and epsilon zero, which is the electric permitivity at vacum.
\(\begin{gathered} C=\frac{A}{d}\cdot\xi0 \\ 1.11\cdot10^{-8}F=\frac{8.89\cdot10^{-4}m^2}{d}\cdot8.854188\cdot10^{-12}F/m \\ d=7.091\cdot10^{-7}m \end{gathered}\)The environment of Ecology is made up of how many levels?
Answer:
There are 5 general layers; organism, population, community, ecosystem, and biosphere.
Explanation:
Hope this helps!
What is not a type of electromagnetic wave?
Explanation:Beta Rays are not Electromagnetic Waves
Beta rays also known as beta radiation is obtained through the emission of an electron. Beta rays are not electromagnetic waves because they are charged particles and are capable of getting deflected by the magnetic field.
Microwaves are a form of "electromagnetic" radiation; that is, they are waves of electrical and magnetic energy moving together through space. Electromagnetic radiation spans a broad spectrum from very long radio waves to very short gamma rays. ... But the most common consumer use of microwave energy is in microwave ovens.
Visible light is carried by photons, and so are all the other kinds of electromagnetic radiation like X-rays, microwaves and radio waves. In other words, light is a particle.
So the answer is sound.
The sound wave is not an electromagnetic wave
What are electromagnetic waves?In terms of science, electromagnetic radiation is made up of electromagnetic field waves that travel over space while carrying electromagnetic radiant energy and velocity. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves.
In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Given data ,
Let the electromagnetic wave be represented as A
Now , when A = microwaves
Microwaves are waves of electrical and magnetic energy traveling across radio waves and infrared radiation on the electromagnetic spectrum combined. There is a wide range of electromagnetic radiation, from very lengthy radio waves to very brief gamma rays.
And , when A = x-rays
X-rays are high-frequency, and thus high-energy, electromagnetic radiation
They are found to reside between ultraviolet radiation and gamma rays on the electromagnetic spectrum.
X-rays are more energetic because they have shorter wavelengths. When discussing X-rays, we frequently refer to their energy rather than its wavelength.
Now , the sound waves are not electromagnetic waves as sound waves are examples of mechanical waves
Hence , sound waves are not electromagnetic waves
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A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is ___ Newton.
A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.
The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:
Fx = F⊥ cosθ and Fy = F⊥ sinθ.
Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:
T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N
Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.
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what is the specific gravity of a seawater?
Answer:
1.025
Explanation:
Although the density of seawater varies at different points in the ocean, a good estimate of its density at the ocean's surface is 1025 kilogram per cubic meter. Its specific gravity is therefore 1.025.
Answer:
see below
Explanation:
The specific gravity of surface seawater ranges from about 1.020 to 1.029
At the bottom of the oceans the specific gravity increases up to about 1.070
The colder the seawater the more dense.
The saltier the seawater the more dense.
The salilinty changes the specific gravity far more than the temperature does.
Tropical fresh water, like in Gatun Lake on the Panama Canal, has a specific gravity of only 0.9954
The Red Sea, hot, landlocked and arid has a specific gravity of about 1.029
460miles per hour with the wind nd 420 per hour gainst the wind
The speed of the wind is 20 miles per hour.
To solve this problem, we can use the formula:
Speed = Distance/Time
Let's assume that the speed of the wind is x miles per hour.
With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:
460 = Airspeed + x
Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:
420 = Airspeed - x
We can solve this system of equations to find the airspeed of the plane:
460 = Airspeed + x
420 = Airspeed - x
Adding the two equations gives:
880 = 2Airspeed
Dividing both sides by 2 gives:
Airspeed = 440 miles per hour
Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:
460 = Airspeed + x
460 = 440 + x
x = 20
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Three swimmers who all swim at the same speed discuss how to cross a river in the shortest amount of time. Swimmer A will swim straight across the river at a right angle to the current. Swimmer B reasons that the current will carry A downstream, meaning that A will cover a greater distance to get across and therefore will take a longer time interval. B says he will aim at an upstream angle such that, allowing for the current, he will reach the other side directly across from where he starts, thus covering the shortest distance and arriving first. Swimmer C, reasoning that the time interval needed for B to cross will be longer than B expects because some of B’s effort will be spent battling the current, plans to aim at a downstream angle, so that the current assists rather than opposes him. This way he will be traveling at the highest speed and get across first. Which swimmer gets across first?
Answer:
Swimmer A
Explanation:
The time required for a swimmer to cross a river is equal to the width of the river which is divided by the magnitude of the component of the velocity which is parallel to the width of the river.
In the given context, all the three swimmers A, B and C swims in a different angle relative to the direction of the flow of river. The swimmer A swims straight at a direction perpendicular to the direction of current of the river across the width of the river, so A will have the largest velocity component which is parallel to the width of the river. So the time taken by swimmer A will be the least to cross the river.
The circuit to the right consists of a battery (0=1.50 V) and five resistors (1=511 Ω, 2=182 Ω, 3=663 Ω, 4=234 Ω, and 5=565 Ω). Determine the current point passing through each of the specified points.
The battery V subscript 0 is connected in series via its positive terminal with resistor R subscript 1. R sub 1 is connected in series with the parallel combination of resistors R subscript 2, R subscript 3, R subscript 4, and R subscript 5. The parallel resistor combination is connected to the negative terminal of the battery.
The parallel resistor combination is configured as a rectangle with a total of four vertical branches. Each vertical branch contains a resistor. The resistors are in numerical order, with R sub 2 on the leftmost branch and R sub 5 on the rightmost branch. Resistor R sub 1 connects to the parallel combination at the midpoint of the upper horizontal leg, between the central parallel branches containing R sub 3 and R sub 4.
The circuit contains eight points labeled A through H. Point A is located on the upper horizontal leg between the parallel branches containing R sub 2 and R sub 3. Point B is located on the upper horizontal leg between the central parallel branches containing R sub 3 and R sub 4, and is to the left of the junction leading to R sub 1. Point C is located on the same horizontal leg as point B, but is to the right of the junction. Point D is located on the upper horizontal leg between the parallel branches containing R sub 4 and R sub 5. Point H is located on the lower horizontal leg between the parallel branches containing R sub 4 and R sub 5, and is opposite point D. Point G is located on the lower horizontal leg between the central parallel branches containing R sub 3 and R sub 4, opposite the junction leading to R sub 1. Point F is located on the lower horizontal leg between the parallel branches containing R sub 2 and R sub 3, opposite point A. Point E is located between the parallel resistor combination and the negative terminal of the battery.
D=
mA
G=
mA
F=
mA
Answer:
D: 0.346 mAG: 1.182 mAF: 1.478 mAExplanation:
You want the current in various circuit branches of a series-parallel circuit with a battery voltage V0 = 1.5V, a series resistor of R1 = 511 Ω, and four parallel resistors, R2–R5 = 182, 663, 234, and 565 Ω, respectively.
SolutionThere are a number of ways to solve the circuit. The one shown in the second attachment finds the combination of the parallel resistors, then determines how the total current is split among them. The values of interest include the current through R5 (node D), the sum of currents through R5 and R4 (node G), and the sum of currents through R5, R4, and R3 (node F).
If Rx is the effective resistance of the parallel combination of R2–R5, then the battery current is
I = V/R = (1.50)/(511 +Rx) ≈ 2.55254 mA
The current in any resistor Rn is this value multiplied by the fraction Rx/Rn for n=2 to 5.
Mesh CurrentsPerhaps more directly, we can write "mesh current" equations for the circuit. Letting I1–I4 represent the currents through nodes D, G, F, and E, respectively, we can write the equations ...
I1(0.565 +0.234) -I2(0.234) = 0I1(-0.234) +I2(0.234 +0.663) -I3(0.663) = 0I2(-0.663) +I3(0.663 +0.182) -I4(0.182) = 0I3(-0.182) +I4(0.511 +0.182) = 1.50The solution to these equations is shown in the first attachment. Resistances are given in kΩ so currents will be in mA.
The currents in the listed nodes are ...
D: 0.346 mAG: 1.182 mAF: 1.478 mA__
Additional comment
The third attachment shows the circuit as we understand it. The currents labeled I1–I4 are within the local loop. The "mesh current" equations match Kirchoff's Voltage Law: the sum of voltage differences around any closed loop is zero. Where a resistor is shared between loops, the voltage across it will be the (signed) sum of the two loop currents times that resistance.
If
y
=
s
i
n
a
x
, then
y
'
is
Differentiation
DerivativesDerivative NotationDerivative Rule [Basic Power Rule]:
\(\displaystyle\begin{aligned}f(x) & = cx^n \\f'(x) & = c \cdot nx^{n - 1} \\\end{aligned}\)
Derivative Rule [Chain Rule]:
\(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)
Let's define what the problem gives us:
We are given a function \(\displaystyle y = \sin ax\)Step 2: WorkWe know from our trigonometric derivatives that the derivative of \(\displaystyle \sin x\) is equal to \(\displaystyle \cos x\). However, since we have some arbitrary constant \(\displaystyle a\) multiplying \(\displaystyle x\) inside our \(\displaystyle \sin x\) function, we will have to apply the derivative rule of Chain Rule:
\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \boxed{ \cos (ax) (ax)' } \\\end{aligned}\)
To further simply the derivative, we now apply the derivative rule of Basic Power Rule and simplify:
\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \cos (ax) (ax)' \\& = (ax)' \cos ax \\& = 1 \cdot ax^{1-1} \cos ax \\& = ax^0 \cos ax \\& = \boxed{ a \cos ax } \\\end{aligned}\)
Answer∴ the derivative of the function \(\displaystyle y = \sin ax\) is equal to \(\displaystyle \boxed{ y' = a \cos ax }\).
___
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___
Topic: Calculus
Unit: Differentiation
The work done is a vector quantity and SI base unit is J
Answer:
Is this your question? Also I think work done is a scalar quantity.
Explanation:
which type of electromagnetic radiation is most likely to cause skin cancer as a result of sun exposure over time?
Answer:
Ultraviolet radiation
Explanation:
The type of electromagnetic radiation most likely to cause skin cancer as a result of sun exposure overtime is the ultraviolet radiation.
Electromagnetic radiation occurs with a broad spectrum starting from gamma rays to the radio waves.
From one end to the other, their energy decreases as the wavelength increases.
Within this broad spectrum, the ultraviolet rays which are before the visible rays are very energetic and can cause skin cancer.
Answer:
ultraviolet i think sorry if im wrong :/
Explanation:
How many meters are there in 20kilometers?
There are 20,000 meters in 20 kilometers. , we can represent this as:
$20 \, \text{km} = 20,000 \, \text{m}$
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
Answer:20000 metres i think
Explanation:
I KM should have 1000m please vote for brainliest
Question 3 of 15
Which of the following statements are not true about gravity? Check all that
apply.
A. Gravity exists in the whole universe.
B. Gravity exists only on Earth.
C. Gravity is a force that pulls two objects together.
D. Gravity exists between two objects that have mass.
E. Gravity doesn't exist between Earth and the sun.
The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun" is not true about gravity.
Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.
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John is riding Supreme Scream at Knotts. If John free falls for 3.6 seconds, what
will be his final velocity? Write only the numerical answer rounded to 3 digits.
Answer:
Vf = 35.28 m/s
Explanation:
The final velocity of John can easily be determined by applying first equation of motion:
Vf = Vi + at
where,
Vf = Final Velocity of John = ?
Vi = Initial Velocity of John = 0 m/s (Since Supreme Scream stops for a brief moment before coming down)
a = acceleration = g (for free fall motion) = acceleration due to gravity = 9.8 m/s²
t = time taken = 3.6 s
Therefore, using the respective values in equation, we get:
Vf = 0 m/s + (9.8 m/s²)(3.6 s)
Vf = 35.28 m/s
What is an atomic nucleus
Answer:
The atomic nucleus is the small, dense region consisting of protons and [[]]s at the center of an atom
Explanation:
PLEASE HELP ON QUESTION ASAP. if answer is correct i will rate you five stars a thanks and maybe even brainliest.
Alex drove for 3 hours at average speed of 60mph and for 2 hrs at 45 miles per hour. Whats his average speed for the whole journey.
also could you please show me how our working out should look like in an exam
The average speed of the whole journey is 54 mph.
To find the average speed of the entire journey, you will need to use the formula, Average speed = Total distance ÷ Total time. So, in this case, the total distance is the sum of the distances traveled at 60 mph and 45 mph, and the total time is the sum of the times taken to cover these distances. Let's calculate:Distance covered at 60 mph = 60 mph × 3 hours = 180 milesDistance covered at 45 mph = 45 mph × 2 hours = 90 milesTotal distance covered = 180 miles + 90 miles = 270 milesTotal time taken = 3 hours + 2 hours = 5 hoursTherefore, the average speed for the whole journey will be:Average speed = Total distance ÷ Total time= 270 miles ÷ 5 hours= 54 miles per hourSo, the average speed of the whole journey is 54 mph.In an exam, it is important to show all the necessary steps and calculations, as demonstrated above. It is also essential to label the units clearly, and write down the formula used. Lastly, a summary statement or answer to the question should be provided.For more questions on average speed
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The diagram below shows snapshots of an oscillator at different times . What is the frequency of the oscillation ?
In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.
How to calculate the periodThe period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,
Period of oscillation = 1.80s.
From here, finding the frequency is simple as, Frequency = 1/Period. Hence,
Frequency = 1/1.80
= 0.555 Hz (3 sf).
The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.
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Would a human feel more gravity on a bigger planet or less gravity
Answer: you would feel more gravity
Explanation: the more mass of an object the more pull
A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
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Determine the initial velocity of the ball if it reaches a height of 15 meters.
O 8.6 m/s
O 11.5 m/s
O 17.1 m/s
O 294 m/s
Answer:
the initial velocity of the ball is 17.14 m/s
Explanation:
Given;
maximum height reached by the ball, h = 15 m
let the initial velocity of the ball = u
at maximum height, the final velocity of the ball is zero, v = 0
The initial velocity of the ball is calculated by using the following upward motion kinematic equation;
v² = u² - 2gh
0 = u² - 2(9.8 x 15)
u² = 294
u = √294
u = 17.14 m/s
Therefore, the initial velocity of the ball is 17.14 m/s
How do most black holes form?
A charge +Q and a charge -2Q are a distance 3x apart. Point P is on the line joining the charges, at a distance x from +Q.
The magnitude of the electric field produced at P by the charge +Q alone is E.
What is the total electric field at P?
The total electric field at point P, taking into account both charges, +Q and -2Q, is given by:
E_total = k * |Q| * [(1 / x²) - (4 / (9x²)]).
To determine the total electric field at point P, we must consider the contributions of both charges, +Q and -2Q.
The electric field (E) at P due to a single charge can be calculated using Coulomb's law. An electric field is defined as the force per unit positive charge at a given point. Mathematically, it is expressed as follows:
E = k * (|q| / r²),
where k is the electrostatic constant, q is the charge, and r is the distance from the charge to the point where the electric field is measured.
In this case we have a charge +Q at a distance x from point P. The electric field at point P due to +Q alone can be calculated as:
E1 = k* (|Q|/x2).
Similarly, the electric field at P due to -2Q can be calculated as:
E₂ = k * (|-2Q| / (3x)²) = 4k * (|Q| / (9x²)).
The total electric field (E_total) at point P is the vector sum of the electric fields produced by +Q and -2Q. Because they have opposite charges, the electric fields will have opposite directions.
E_total = E1 - E₂.
By substituting the expressions for E₁ and E₂:
E_total = k * (|Q| / x²) - 4k * (|Q| / (9x²)).
Further simplification:
E_total = k * |Q| * [(1 / x²) - (4 / (9x²)]).
Please note that the direction of the electric field will depend on the signs of the charges (+Q and -2Q) and their relative positions with respect to point P.
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A flea jumps straight up to a maximum height of 0.490 m . What is its initial velocity v0 as it leaves the ground?
Answer:
\(\huge\boxed{\sf v_o=3.1\ m/s}\)
Explanation:
Given Data:
Acceleration due to gravity = g = -9.8 m/s²
Maximum Height = h = 0.490 m
At h, \(v_f\) = 0
Required:
\(v_o=?\)
Formula:
\(2gh=v_f^2-v_o^2\)
Solution:
Put the givens
\(2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}\)
I want you to think about each of these scenarios, what do you think will happen after? I just want you to think about it, and write a little about what is going to happen.
2. A truck is moving at 20 mph. Your car is standing still at a light and the truck crashes into you before the driver has a chance to step on the brakes.
3. You are driving your car at 20 mph. A bicycle right ahead of you suddenly stops and you crash into it before you have a chance to step on the brakes.
4. A bicycle is moving at 20 mph. Your car is stopped for a light and the bicycle crashes into you.
can the average speed ever be zero explain
Explanation : The average speed of a moving body can never be zero but the average velocity of a moving body can be zero.
27. The number of coils of wire through which a bar magnet is moved is increased. The
amount the needle on the meter is deflected
A. increases
B. decreases
C. shows no change
D. does not move at all
The amount the needle on the meter is deflected A. increases
This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.
The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.
By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.
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You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A Ferris wheel with 60 spokes has a diameter of 100 m. It makes one rotation every 60 seconds. Find the speed of the passengers when the Ferris wheel is rotating at this rate.
A. 5.24 m/s
B. 6.23 m/s
C. 7.45 m/s
D. 8.01 m/s
Answer:
v = 5.24 m/s
Explanation:
Given that,
No of spokes of a Ferris wheel = 60
The diameter of a wheel, d = 100 m
Radius, r = 50 m
It makes one rotation every 60 seconds.
We need to find the speed of the passengers when the Ferris wheel is rotating at this rate. Let it is v. It can be calculated as follows :
\(v=r\omega\\\\=\dfrac{2\pi r }{T}\\\\=\dfrac{2\pi \times 50 }{60}\\\\v=5.235\ m/s\)
or
v = 5.24 m/s
So, the speed of the passengers is 5.24 m/s. Hence, the correct option is (A).
A 60.0-kg and a 90.0-kg skydiver jump from an airplane at an altitude of , both falling in the pike position. Make some assumption on their frontal areas and calculate their terminal velocities. How long will it take for each skydiver to reach the ground (assuming the time to reach terminal velocity is small)
Answer:
The terminal velocity for both skydiver are 99.58 m/s and 121.9 m/s.
The time for both skydiver are 60.25 sec and 49.22 sec
Explanation:
Given that,
First mass = 60 kg
Second mass = 90 kg
Suppose, altitude \(h=6.00\times10^{3}\ m\)
Area =.14 m²
C= .7
Density = 1.21 kg/m³
We need to calculate the terminal velocity
Using formula of terminal velocity
\(v_{1}=\sqrt{\dfrac{2m_{1}g}{\rho\times C\times A}}\)
For first mass,
Put the value into the formula
\(v_{1}=\sqrt{\dfrac{2\times60\times9.8}{1.21\times.14\times.7}}\)
\(v_{1}=99.58\ m/s\)
For second mass,
Put the value into the formula
\(v_{2}=\sqrt{\dfrac{2\times90\times9.8}{1.21\times.14\times.7}}\)
\(v_{2}=121.9\ m/s\)
We need to calculate the time of first skydiver
Using formula of time
\(t_{1}=\dfrac{h}{v_{1}}\)
Put the value into the formula
\(t_{1}=\dfrac{6.00\times10^{3}}{99.58}\)
\(t_{1}=60.25\ sec\)
We need to calculate the time of second skydiver
Using formula of time
\(t_{2}=\dfrac{h}{v_{2}}\)
Put the value into the formula
\(t_{2}=\dfrac{6.00\times10^{3}}{121.9}\)
\(t_{2}=49.2\ sec\)
Hence, The terminal velocity for both skydiver are 99.58 m/s and 121.9 m/s.
The time for both skydiver are 60.25 sec and 49.22 sec