Metabolism is slow and heat is generated. Endotherms use metabolic heat to maintain a stable body temperature, but not exogenous heat.
An animal's "baseline" metabolic rate is measured as the basal metabolic rate (BMR) for endotherms or as the standard metabolic rate (SMR) for exotherms. Among endotherms, smaller animals tend to have higher basal metabolic rates per gram than larger animals (“hotter” metabolism). The same applies to external temperature, although groups cannot be compared. Your metabolic rate depends on your activity level. A more active animal has a higher metabolic rate than a less active animal. Some animals go into a state of lethargy where their metabolism slows down. Winter hibernation and summer hibernation are forms of lethargy.
Ectotherms, however, lower their metabolic rate as the outside temperature drops in order to preserve body temperature.
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Assume you use a complete fertilizer containing urea, superphosphate, and potassium chloride. Describe what might happen to all the nutrients added. How might they be used, stored, or lost?
Fertilisers give crops vital nutrients like nitrogen so they may grow larger, more quickly, and yield more food.
However, using too much fertiliser can be harmful because it causes eutrophication and the emission of greenhouse gases.
Potassium (K)-rich fertilisers are regularly used to make up for plant deficiencies. Farmers must add this essential plant nutrient when soils are unable to provide crops with the K levels they require.When urea is added to the soil, it quickly turns into ammonium through a reaction with water and the soil enzyme urease.
The chemical reaction below illustrates this conversion, which is known as urea hydrolysis. The consumption of hydrogen ions (H+) in this reaction raises the pH of the soil close to the fertiliser.
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(b) (i) Describe the process by which lactic acid (lactate) is produced in muscle fibres.
Explanation:
while exercising............as Oxygen debt occurs
Can you apply your knowledge of reproduction and protein synthesis to explain why offspring and parents have similar traits?
Answer:
Offspring acquire a mix of traits from their biological parents. In each kind of organism there is variation in the traits themselves, and different kinds of organisms may have different versions of the trait.
Explanation:
Cell theory is the current leading theory used to describe characteristics of living things. Which of the following is NOT part of the Cell Theory?
Answer:
all cells have the ability to move
Explanation:
what are two use cases for executing anonymous apex code choose 2 answers
Executing anonymous apex code is a tool that allows users to interactively execute Apex code statements and queries. Given that, there are two use cases for executing anonymous apex code. They are: Use Case 1: Testing Snippets of Code and Use Case 2: Troubleshooting problems with a particular org.
What is anonymous apex code?
Anonymous Apex is a way to test code snippets, practice writing logic, and test governor limits quickly. Anonymous Apex is ideal for making immediate changes to the database for analysis purposes and automating one-time tasks. It is used to quickly test something that you are unsure of, to test a function or class that you've created, and also to verify the results of a particular query.
Use Case 1: Testing Snippets of CodeIt's a best practice to write test code to check that your app works properly, but it can be time-consuming to write test code to test a small part of it. Anonymous Apex is a great tool for quickly testing snippets of code. It's helpful for doing the following: Testing new functionality before incorporating it into a larger codebase. Testing code that was copied and pasted from an external source or developer forum. Testing whether certain code will work in the context of your Salesforce org.
Use Case 2: Troubleshooting problems with a particular org. There are instances when issues in a particular org will arise, and you will have to troubleshoot and find the cause of the problem. This is where anonymous Apex comes in. Because anonymous Apex runs within the context of an org, it can be used to test things like: Creating a record for a particular object Modifying a record for a particular object Deleting a record for a particular object Running a SOQL query Running a DML statement Running SOSL queries Running Apex Code
That's all about two use cases for executing anonymous apex code.
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Match each characteristic to bacterial protein synthesis or eukaryotic protein synthesis.
Answer Bank:
First AUG initiates translation.
Shine-Dalgarno sequence
80S ribosome.
70S ribosome.
simultaneous transcription
and translation possible
spatial separation of
transcription and translation
polycistronic mRNA
Polycistronic mRNA - Bacterial mRNA can contain multiple coding regions (cistrons), allowing for the synthesis of several proteins from a single mRNA molecule.
Bacterial Protein Synthesis:
1. Shine-Dalgarno sequence - This sequence is found in bacterial mRNA and helps with the binding of the ribosome to the mRNA.
2. 70S ribosome - Bacterial ribosomes are smaller, with a total size of 70S.
3. Simultaneous transcription and translation possible - In bacteria, transcription and translation can occur simultaneously in the cytoplasm.
4. Polycistronic mRNA - Bacterial mRNA can contain multiple coding regions (cistrons), allowing for the synthesis of several proteins from a single mRNA molecule.
Eukaryotic Protein Synthesis:
1. First AUG initiates translation - In eukaryotes, the first AUG codon signals the start of translation.
2. 80S ribosome - Eukaryotic ribosomes are larger, with a total size of 80S.
3. Spatial separation of transcription and translation - In eukaryotes, transcription occurs in the nucleus, while translation occurs in the cytoplasm, creating a spatial separation.
4. Monocistronic mRNA - Eukaryotic mRNA typically contains a single coding region, allowing for the synthesis of only one protein per mRNA molecule.
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what is element bond in simple words
Answer:
a chemical bond is a lasting attraction between atoms or molecules
help help help help e help.
Answer:
True!
Explanation:
Bile is a fluid that is made and released by the liver and stored in the gallbladder. Bile helps with digestion. It breaks down fats into fatty acids, which can be taken into the body by the digestive tract.
I posted this earlier but I am looking to check my work because I am very lost. this is what i have so far but it is all over the place ...
You survey a population of minnows in Hardy-Weinberg equilibrium and find that there are three different genotypes; Red, Purple, and Blue fins. The genotypes for Red (RR), Purple (Rr), and Blue (rr) fins have different survival rates at 0.7, 0.8, and 0.5, respectively. The size of the population does not decrease from generation to generation and all individuals lost to selection are replaced by new individuals being born. If the population starts with 30 Red, 30 Purple, and 40 Blue fins, what is the expected number of individuals of each genotype in the next generation (round to nearest whole individual)? Clearly show each step of your work. (20)
Heterozygote Advantage
Because the heterozygote has the highest fitness
• A1A2 is favored and it starts at p2 + 2pq + q2 = 1
w11 = 1-s1, w12 = 1, w22 = 1-s2
Red (RR) survival rate 0.7 = 30 individuals
Purple (Rr) survival rate 0.8 =30 individuals
Blue (rr) survival rate 0.5 = 40 individuals
W11 = 0.7/0.8 =0.875
W12 = 0.8/0.8 =1
W22 = 0.5/0.8 = 0.625
Genotype frequency ??
p = 0.45 or 0.4
q =0.55 or 0.3
RR = 30/100 = 0.3
Rr 40/100 = 0.4
Relative fitness to find the selection co efficient
S11 = 1-0.875 = 0.125
S12 = 1-1 = 0
S22 = 1-0.625 =0.375
Use p q and to find wbar
W(bar) = 1-(p)^2*(0.125)-(q^2)
W bar = 1 – (0.55)^2* (0.125) – (0.45)^2 * 0.375 = 0.86
Find relative preformance
q’ = q2-q2s2+pqw = 0.45^2 – 0.45^2 (0.375)+(0.45)(0.55) / (0.86) = 0.43
Find delta q
(0.45*0.55((0.55*0.125) – (0.45*0.375)))/0.86) = 0.028
The number the expected number of individuals of each genotype in the next generation wouldn’t that just be the survival rate * the number of individuals in that phenotype?
Total individuals = 100
p = the less fit allele = f(A1) Red = 0.7*30 =21
q= more fit allele = f(A2) Blue = 0.5*40=20
2pq = heterozygote allele = 30*0.8 = 24
This is in hardy weinberg equlibrium
I am just not sure I am even going the right way.
You are on the right track, but there are some errors in your calculations and some steps missing. I will guide you through the correct calculations step by step.
First, we need to calculate the allele frequencies in the population. Let p be the frequency of the dominant allele (A1), and q be the frequency of the recessive allele (A2). We can calculate these frequencies using the formula:
p^2 + 2pq + q^2 = 1
where p^2 is the frequency of homozygous dominant individuals (RR), 2pq is the frequency of heterozygous individuals (Rr), and q^2 is the frequency of homozygous recessive individuals (rr).
Substituting the given values, we get:
0.3 + 0.4 + 0.3 = 1
So, p^2 = 0.3, 2pq = 0.4, and q^2 = 0.3.
From these values, we can calculate the allele frequencies as:
p = sqrt(p^2) = sqrt(0.3) = 0.55
q = sqrt(q^2) = sqrt(0.3) = 0.55
Next, we need to calculate the selection coefficients (s) for each genotype. The selection coefficient (s) represents the reduction in relative fitness compared to the most fit genotype. We can calculate the selection coefficients as:
s11 = 1 - w11 = 1 - 0.7/0.8 = 0.125
s12 = 1 - w12 = 1 - 1 = 0
s22 = 1 - w22 = 1 - 0.5/0.8 = 0.375
where w11, w12, and w22 are the relative fitness values for the RR, Rr, and rr genotypes, respectively.
We can then calculate the average relative fitness (w-bar) of the population as:
w-bar = p^2(1 - s11) + 2pq(1 - s12) + q^2(1 - s22)
Substituting the values, we get:
w-bar = 0.55^2(1 - 0.125) + 2(0.55)(0.45)(1 - 0) + 0.45^2(1 - 0.375) = 0.862
Next, we can calculate the expected genotype frequencies in the next generation using the formula:
p^2 = expected frequency of RR genotype
2pq = expected frequency of Rr genotype
q^2 = expected frequency of rr genotype
We can calculate these values using the following equations:
expected frequency of RR genotype = p^2(1 - s11)/w-bar
expected frequency of Rr genotype = 2pq(1 - s12)/w-bar
expected frequency of rr genotype = q^2(1 - s22)/w-bar
Substituting the values, we get:
expected frequency of RR genotype = (0.55^2)(1 - 0.125)/0.862 = 0.232
expected frequency of Rr genotype = 2(0.55)(0.45)(1 - 0)/0.862 = 0.508
expected frequency of rr genotype = (0.45^2)(1 - 0.375)/0.862 = 0.26
Finally, we can calculate the expected number of individuals of each genotype in the next generation by multiplying the expected genotype frequencies by the total population size of 100. So, the expected number of individuals of each genotype in the next
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If T=tall and t=short which would would it be? ILL GIVE BRAINIEST AND 5 STARS AND A TY TO THE BEST ANSW3RRR
Do only cars produce Carbon dioxide? True or False? (Explain why?)
The marine biome _______. a. is a large ecosystem, but not larger than some terrestrial ecosystems b. is characterized by four different zones c. has little species diversity d. covers a small portion of the earth’s surface please select the best answer from the choices provided a b c d
Hello,
The marine biome is characterized by four different zones.
→ Answer B
Answer:
The answer is B- Is characterized by four different zones. :)
Explanation:
Why does it take longer for your body to break down complex carbohydrates than simple carbohydrates?
Explanation:
complex carb pack more nutrients are simple carbs that are high in fiber and digest more slowly this makes them more ceiling which means a good option to for weight control
The small intestine is where carbohydrates are chemically broken down, instead of the stomach. The disaccharides and pancreatic amylase complete the chemical cleavage of digestible carbs.
What are the complex carbohydrates in the body?The building blocks of large polysaccharides are lengthy, complicated chains of sugar molecules.
Peas, beans, whole grains, and vegetables are examples of foods that are sources of complex carbohydrates. The body converts simple and complex carbohydrates into glucose (blood sugar), which is then used as fuel.
Longer-lasting blood glucose increase and longer-lasting energy elevation are produced by complex carbs.
Therefore, complex carbs are more efficient in giving the body energy, which is the main purpose of carbohydrates.
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list 4 additional benefits of trees (different from what you already wrote in this lab) from this tedtalk:
In the TedTalk video, “The hidden life of trees”, the author mentioned several additional benefits of trees.
Here are four of them:
1. Trees create social benefits: Trees play a major role in creating a sense of community. They offer a natural gathering spot and can foster interaction between people. They also help to reduce crime rates by creating a sense of community ownership.
2. Trees offer health benefits: Trees are beneficial to the health of people who live in tree-lined areas. Trees help to clean the air by absorbing pollutants. This, in turn, can reduce respiratory problems such as asthma. Additionally, studies have shown that people who live in areas with more trees have lower levels of stress.
3. Trees provide economic benefits: Trees provide many economic benefits. They can help to reduce energy costs by providing shade and cooling. They can also increase property values by up to 15 percent. Trees are also used in many industries, such as furniture, paper, and construction.
4. Trees have ecological benefits: Trees play a crucial role in the ecological balance of the earth. They provide habitat for many species of animals and plants. They also help to prevent soil erosion and desertification. Finally, trees absorb carbon dioxide from the atmosphere and help to reduce the negative impact of climate change.
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Peptidyl transferase is an enzyme that functions to enable the creation of a polypeptide chain during the process of translation.
How does peptidyl transferase perform this function?
Answer
A
Peptidyl transferase decreases the amount of energy needed to create a peptide bond between amino acids.
B
Peptidyl transferase speeds up translation by allowing more codons into the ribosome.
C
Peptidyl transferase increases the length of the polypeptide chain by transferring energy to the amino acids.
D
Peptidyl transferase creates the mRNA from the information in the template strand of DNA.
Answer: D
Explanation: the image shows this. Let me know if I’m right.
A man and woman have a son who is color blind, a recessive sex-linked trait carried on the X chromosome, but neither parent is color blind. The woman is now pregnant with their second child. Which of the following statements is true about the second child?
eport developed by a pi team on the occurrence of methicillin-resistant staphylococcus aureus infection in a neonatal intensive care unit was subsequently used by the perinatal morbidity and mortality committee in a monthly review of infant morbidity. access to this report was possible because it was housed in the organization's:
Access to such reports is typically restricted to authorized personnel, such as healthcare providers, administrators, and quality improvement specialists, who are trained to handle sensitive patient information and maintain data privacy and security.
The report on the occurrence of methicillin-resistant Staphylococcus aureus infection in a neonatal intensive care unit was likely housed in the organization's electronic health record (EHR) system or other healthcare data management system. These systems are commonly used to store and manage patient health information, including clinical notes, laboratory results, radiology images, and other medical data.
In many healthcare organizations, EHR systems are also used to store and manage quality improvement and patient safety data, such as reports on adverse events, quality measures, and infection control. These data can be used by various committees and teams, including the perinatal morbidity and mortality committee, to identify opportunities for improvement and develop strategies to enhance patient care and outcomes.
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Cell shrinkage is to _____ as cell bursting is to _____.
Group of answer choices
crenation; lysis
hypotonic; isotonic
lysis; crenation
isotonic; hypotonic
Answer:
hypotonic , ostonic
Explanation:
because ubiqui tous characteristics of program the cell death
of cell membrane when the cell can no longer cointain the excessive inflows of water
Cell shrinkage is to crenation as cell bursting is to lysis by osmosis. Therefore, option A is correct.
What is osmosis?Osmosis is the process by which a solvent moves between two solutions with various solute concentrations over a semipermeable membrane. The solvent is transferred from the solution with the lower solute concentration to the solution with the greater solute concentration during osmosis.
There are three types of osmotic solutions and that is hypertonic, hypotonic, and isotonic. The nature of the solution is relative.
When a cell is kept in a hypertonic solution, water moves outside the cell causing the crenation of the cell. When it is kept in a hypotonic solution, water moves inside the cell causing lysis of the cell. Hence, option A is correct.
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Biomagnification is... concentration of a contaminant stays the same as you move to higher trophic concentration of a contaminant increases as you move to higher trophic level concentration of a contaminant increases as an individual grows concentration of a contaminant stays the same as an individual grows
Answer: Biomagnification refers to the process by which the concentration of a contaminant increases as you move to higher trophic levels in a food chain or food web. In other words, as organisms consume other organisms, the contaminants present in the prey accumulate and become more concentrated in the bodies of the predators.
To understand this process, let's consider an example involving a water ecosystem. Suppose a pollutant is released into the water, such as a pesticide or heavy metal. The primary producers, such as algae or aquatic plants, absorb small amounts of the contaminant from the water. As herbivorous organisms consume these primary producers, they ingest the contaminants along with their food.
Since the contaminant is not easily broken down or eliminated from the organisms' bodies, it accumulates over time. As a result, the concentration of the contaminant becomes higher in the herbivores than in the primary producers. Now, when carnivorous organisms consume the herbivores, they not only accumulate the contaminant from their own food but also from all the prey they have consumed. This leads to an even higher concentration of the contaminant in the carnivores.
Therefore, biomagnification describes the phenomenon where the concentration of a contaminant increases significantly as you move up the food chain or trophic levels. The highest concentration of contaminants is often found in top predators, such as large fish, birds of prey, or mammals, which can have adverse effects on their health and reproductive capabilities.
It's important to note that biomagnification primarily occurs for persistent and non-biodegradable contaminants that cannot be easily metabolized or excreted by organisms. These contaminants are often lipophilic (fat-soluble), which allows them to accumulate in fatty tissues and remain in the organism's body for long periods, leading to biomagnification.
Explanation:
what would you expect to occur if there was a mutation in an organism that did not allow the organism to make functional integrin proteins?
The organism would probably have problems with cell adhesion, migration, and signalling in the absence of functional integrin proteins, leading to a range of developmental and physiological abnormalities.
A class of transmembrane proteins known as integrins is essential for cell adhesion, motility, and signalling. They facilitate communication between cells as well as between cells and the extracellular matrix (ECM). Numerous biological processes, such as embryonic development, tissue repair, immunological response, and cancer spread, depend on these connections. An organism is likely to encounter serious developmental and physiological issues if it has a mutation that impairs the generation of functional integrin proteins. For instance, cells' inability to adhere to the ECM or to one another may hinder the development and upkeep of tissues. Additionally, cells may experience difficulties moving to the appropriate sites, which can result in immune system dysfunction or developmental flaws. Additionally, as integrins are essential components of signalling pathways.
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When a hypothesis is supported by the evidence, it is proved to be false. true or false?
Answer:
FALSE. because why would something be wrong of it is supported by credible evidence, but if it stated the hypothesis along with the evidence and the evidence isn’t as credible then it could be true but only in that case.
Explanation:
This question is really easy please help
Answer:
the answer is (b)
Explanation:
if it really easy why you didn't get it not being mean or nun anyways hope this helps
If the top level consumers were eliminated from a food web would the populations in the levels below them increase without bounds why or why not
If the top-level consumers were eliminated from a food web, then the populations in the levels below them would decrease due to the disequilibrium in the homeostasis of the ecosystem.
What does the homeostasis of the ecosystem mean?The expression homeostasis of the ecosystem makes reference to all relationships between biotic and abiotic factors in an ecosystem which are fundamental to maintaining the state of internal equilibrium of complex biological ecosystems.
The elimination of top consumers in a trophic chain will lead to the disequilibrium of the ecosystem because it would produce an increase in the organism located immediately below, and then organisms located at two trophic levels below would decrease as a consequence of the increase in the number of consumers.
Therefore, we can conclude that ecosystems are delicate complex biological systems where all trophic levels are related and maintain an equilibrium.
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how do the muscular and skeletal systems work together
Explanation:
how do your bones move? Moving your joints and you move your joints by using muscles.
What's holds up your bones? Muscles.
Answer:
well the skeletal system and the muscular system work together bc the skeletal system helps support the body frame and supports the weight and the muscular system attaches the bones together
Explanation:
In which structure are the major cardiac pacemaker cells located?
a.AV node
b.Bundle branches
c.SA node
d.Purkinje fibers
e.gap junctions
The major cardiac pacemaker cells are located in the SA node (sinoatrial node).
The SA node, located in the right atrium near the opening of the superior vena cava, serves as the natural pacemaker of the heart. It initiates the electrical signals that regulate the heart's rhythm and coordinate its contractions. The SA node generates electrical impulses that spread through the atria, causing them to contract and pump blood into the ventricles. From the SA node, the electrical signals travel to the AV node (atrioventricular node), which acts as a delay, allowing the atria to fully contract before the impulses reach the ventricles.
The SA node is composed of specialized cardiac muscle cells that have the unique ability to spontaneously depolarize, generating rhythmic electrical impulses. These cells possess a high concentration of pacemaker channels, such as funny current (If) channels, which allow the entry of sodium and calcium ions, leading to the depolarization of the cell membrane. This depolarization triggers the opening of voltage-gated calcium channels, causing an influx of calcium ions and the initiation of an action potential. The action potentials generated in the SA node propagate through the rest of the heart's conduction system, including the AV node, bundle branches, and Purkinje fibers, ultimately coordinating the sequential contraction of the atria and ventricles and ensuring efficient blood circulation.
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1. Digital signals carry less information per second.
2. Information can be stored for future recovery.
3. Digital signals can be transmitted over long distances.
4. Signal loss happens less frequently.
Which features are correct?
Answer:
2. Information can be stored for future recovery.
3. Digital signals can be transmitted over long distances.
Explanation:
This world is moving towards digitalization. The digital signals are able to transmit the data over long distance. This has squeezed the world information and the data are run to distant places within seconds. The information on digital signals can be stored for later use.
Matter is moved through the Earth by the interaction of Earth’s systems.
true or false.
Answer:
True.
Explanation:
Answer:
True
Explanation:
Edge 2020
Photosynthesis
Use respiration in a sentence.
Answer:
Respiration is one of the chemical reaction that happens in all living cells.
Explanation:
Answer:
rhwheveeyeweuxeyeyeyheve
When three-sectioning the facial area, the middle or second section includes:
a. the forehead
b. the tip of the nose to the tip of the chin
c. the front hairline to the middle of the eyebrows
d. the middle of the eyebrows to the tip of the nose
The middle or second section when three-sectioning the facial area includes: b. the tip of the nose to the tip of the chin.
How is the facial area three-sectioned?
When dividing the facial area into three sections, the middle or second section includes the area between the tip of the nose and the tip of the chin.
This section is often used as a reference point for various beauty and grooming techniques, such as applying makeup or shaving. The other two sections include the forehead and the top of the head, and the lower part of the face, respectively.
This method is commonly used in the beauty and skincare industry, as well as in medicine and plastic surgery. It is important to identify the correct section when performing various procedures to ensure the desired outcome and to avoid any potential complications.
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which is not a characteristic of stem cell?