Answer:
the answer is cell division
Explanation:
cell division is the process by which a present cell divides into two or more daughter cells.
the process can also be called cell cycle
how to find h3o from ka of a weak acid
The H₃O from ka of the weak acid is as follows :
[H₃O⁺] = √ Ka × [Ha]
The Ka for the weak acid is as follows :
Ka = [H₃O⁺]² / [HA]
[H₃O⁺] = √ Ka × [Ha]
The Weak acids are the acids that does not completely dissociate or it will be partially dissociates in to the solution. The weak acids can also be defined as the acid that will not the strong acid. The strength of the weak acid will be depends on that the how much it will dissociates as the more it will dissociates, the stronger will be the acid.
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Which skill in the science process contains the units,number, and conversion?
The skill of Dimensional Analysis in the science deals with the conversion of units and numbers.
The physical quantities are only seven in basic. All the other quantities that we see are just derived quantities in one or the other.
While checking the correctness of a formula or while analyzing the reliability of an equation, we use dimensional analysis and convert the units into the dimension form.
Every fundamental quantity is given a Special notation like M for kg and L for meter.
Converting a bigger quantity into a smaller one is also a part of the dimensional analysis. As we know, we can measure the distance between our houses in meter but thing are different when it comes to astronomical distances.
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Which of the following best describes the impact of glaciers upon the surface of the earth?
a.
Ice buried continents under a few hundred feet of ice.
b.
Glaciers scraped across the surface and altered landscapes and the course of rivers.
c.
The passage of glaciers created new ecosystems.
d.
All of the above.
Answer:
New Answer is : B - Glaciers scraped across the surface and altered landscapes and the course of rivers.
Explanation:
Edge 2020
The impact of glaciers on the surface is that glaciers scraped across the surface and altered landscapes and the course of rivers.
What is a glacier?A glacier refers to a heap of ice that has stayed there for a large number of years. The earth is filled with many glaciers and about 90% of fresh water are trapped in glaciers.
The impact of glaciers on the surface is that glaciers scraped across the surface and altered landscapes and the course of rivers.
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To increase the gravitational attraction between two masses, you need to
A.
rotate the objects
B.
increase the distance between the objects
C.
decrease the distance between the objects
D.
interchange the objects
Answer:
option C is correct answer of this question
decrease the distance between the object
hope it helps
What do weather scientists
do?
What are they called?
If 30g of Al2(No3)3 are reacted with 25g of H2So4 to produce Al2(So4)3 what is the limiting reactant
In the chemical equation of aluminium nitrate and sulfuric acid limiting reactant is sulfuric acid as it is present in small quantity.
What is chemical equation?Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
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If the solid, liquid, and gas forms of a substance
are made up of the same type of particles, How
could a substance change from one state to
another?
presence of heat can change solid tu liquid
and liquid to gas
1. What class of drugs are being investigated in this study, and how do they get into our waterways? 2. What is a C-start and why is it important for larval fish survival? 3. What hypotheses are being tested in this investigation? 4. Briefly describe what the researchers found when they exposed larval fathead minnows to levels of antidepressants found in our waterways.
The effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.
1. The class of drugs being investigated in this study is antidepressants. They enter our waterways through excretion by individuals taking the medication, and disposal of unused medication into toilets or sinks that are connected to wastewater treatment plants.
2. C-start is an evasive maneuver that young fish use when they perceive a predator. This is important for larval fish survival because it helps them to avoid being eaten by predators.
3. In this investigation, researchers are testing two hypotheses. The first is that exposure to low levels of antidepressants can affect larval fathead minnows' behavior, and the second is that the effects of exposure will be more pronounced in fish that have been raised in a less stressful environment.
4. The researchers found that exposure to antidepressants at levels found in waterways can have a significant impact on the behavior of larval fathead minnows. Specifically, they found that the fish exposed to antidepressants were less likely to respond to the presence of predators, which could increase their risk of being eaten.
They also found that the effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.
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(27) Heat from the
enters the atmosphere as radiation in the
form of energetic rays
How have the people in Australia been affected by rabbits in Australia? Choose all that apply Rabbits might eat farmers' crops. O Rabbits eat vegetative cover, which has caused a decreased amount of food available for grazing livestock. O Their tax dollars have been used to try to control the rabbit population. Rabbits are a food source for grazing livestock
Rabbits eat vegetative cover, which has caused a decreased amount of food available for grazing livestock, Their tax dollars have been used to try to control the rabbit population are all ways by which Australians are affected by rabbits in Australia.
History of rabbits in AustraliaRabbits were introduced to Australia by European settlers in the mid-19th century for hunting and as pets. However, their populations soon spiraled out of control, and they have since become a major environmental and agricultural pest in Australia.
The overpopulation of rabbits has caused extensive damage to Australia's native vegetation, leading to soil erosion, loss of habitats for native species, and altered ecosystems. This has had a significant impact on the environment, with many native species struggling to survive.
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Why do animals eyes like dogs or cats sometimes glow when you take photos?
I’m confused on this what do I do??
Answer:
yes
Explanation:
Answer:
Alpha is the most harmful, Gamma is the least harmful.
Explanation:
From skimming over your answer I have noticed this mistake. You are correct in saying alpha is the least penetrating but incorrect in saying alpha is the least ionising. Same for Gamma.
Consider the sublimation of iodine at 25.0 °C.I2(s) → I2(g)Find ΔG°rxn at 25.0 °C.Find ΔGrxn at 25.0 °C under the following nonstandard conditions:PI2 = 1.00 mmHgPI2 = 0.100 mmHgExplain why iodine spontaneously sublimes in open air at 25 °C.
Iodine will spontaneously sublime in open air at 25 °C to achieve a state of equilibrium between the solid and gaseous phases.
To calculate ΔG°rxn at 25.0 °C for the sublimation of iodine, we need to use the equation:
ΔG°rxn = ΔH°rxn - TΔS°rxn
Where:
ΔH°rxn is the standard enthalpy change of the reaction
T is the temperature in Kelvin
ΔS°rxn is the standard entropy change of the reaction
The values for ΔH°rxn and ΔS°rxn for the sublimation of iodine can be found in reference tables or experimental data.
To find ΔGrxn at 25.0 °C under nonstandard conditions, we use the equation:
ΔGrxn = ΔG°rxn + RT ln(Q)
Where:
R is the gas constant (8.314 J/(mol·K))
Q is the reaction quotient, which is calculated based on the given pressures of iodine (PI2)
To explain why iodine spontaneously sublimes in open air at 25 °C, we need to consider the thermodynamic factors. At 25 °C, the sublimation of iodine is favored due to the positive entropy change (ΔS°rxn > 0). The increase in disorder upon sublimation contributes to the spontaneous nature of the process.
Additionally, the vapor pressure of iodine (PI2) at 25 °C is higher than the pressure of iodine in the surrounding air. This pressure difference drives the sublimation of iodine as it tends to reach equilibrium by moving from a higher pressure region (solid) to a lower pressure region (gas).
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Which is the balanced chemical equation showing hydrogen peroxide (H2O2) decomposing into hydrogen (H2) and oxygen (O2)? Multiple Choice H2O2 → H2 + O2 H2 + O2 → H2O2 2 H2 + O2 → 2 H2O2 2 H2O2 → 2 H2 + O2 PrevQuestion 13 of 14 Total13 of 14Visit question mapNext
Answer: \(H_2O_2\rightarrow H_2+O_2\)
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for showing hydrogen peroxide decomposing into hydrogen and oxygen is:
\(H_2O_2\rightarrow H_2+O_2\)
Which of the following gases would have a similar rate of effusion to N2 at 350 K (molar mass of H: 1 g/mol) (molar mass of C: 12 g/mol) (molar mass of N: 14 g/mol) (molar mass of O: 16 g/mol) (molar mass of Ne: 20 g/mol) A. CH4 B. СО C. CO2 D. H2 E. Ne
The rate of effusion of a gas is inversely proportional to its molar mass.
Therefore, the gas with the molar mass closest to that of nitrogen (14 g/mol) will have the most similar rate of effusion to nitrogen at 350 K.
The gas with the molar mass closest to that of nitrogen is hydrogen (1 g/mol). Therefore, the gas with the most similar rate of effusion to nitrogen at 350 K is hydrogen (H2). The other gases (CH4, CO, CO2, and Ne)
all have molar masses significantly higher than nitrogen, and therefore they will have slower rates of effusion than nitrogen at 350 K.
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What causes the high luster of a metal?
a
excitation of electrons into empty orbitals
b mobility of electrons
C easily ionizable metal atoms
d their low melting points
Answer:
When light is shone on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals. The electrons immediately fall back down to lower energy levels and emit light. This process is responsible for the high luster of metals.
Explanation:
Your well-wisher :-)
how many moles of H are there in 39.2g of H
Answer:
39.2 g
Explanation:
because moles = mass / mr (mr of h is 1)
so 39.2/1= 39.2 moles
hope this helps you to understand :)
một nguyên tử có tổng số hạt cơ bản là 24. Trong hạt nhân số proton bằng số nơ tron. Xác định số khối của nguyên tử đó
Answer:
i dont understand sorry
Why was anhydrous CaCl2 added to the organic extract? O To allow CaCl2 to undergo chemical reaction with the compounds extracted. O To dry the organic extract. O To identify the correct layer. O To give better separation between the organic and aqueous layers.
Being a desiccant, \(CaCl_2\) can efficiently remove any last water molecules from the organic extract because of its high affinity for water.
Anhydrous \(CaCl_2\) was added to the organic extract in order to dry it. \(CaCl_2\) is a desiccant, meaning it has a strong affinity for water and can effectively remove any remaining water molecules from the organic extract. This is important because water can interfere with subsequent analytical or synthetic steps, and drying the extract can improve the yield and purity of the desired product. Adding \(CaCl_2\) also helps to give better separation between the organic and aqueous layers, as any remaining water in the organic layer can cause it to mix with the aqueous layer. However, it does not undergo chemical reaction with the compounds extracted and is not used to identify the correct layer.
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Which of the following phenotypes is most indicative of a natural killer cell?
a. CD2+ CD3+ CD5+ CD7+
b. CD2+ CD3- CD11b+ CD16+
c. CD11b+ CD16+ CD33+ CD56-
d. CD19+ CD20+ CD22+ CD57-
The phenotype that is most indicative of a natural killer cell is b. CD2+ CD3- CD11b+ CD16+.
Natural killer cell are characterized by the lack of CD3, expression of CD16 and CD56, and the presence of CD2 and CD11b. CD33 is a marker for myeloid cells, and CD57 is a marker for mature NK cells and T cells. CD19, CD20, and CD22 are markers for B cells.
An immune system component called a lymphocyte, or natural killer (NK) cell, is a type of white blood cell. They are referred to as "natural" killers because they can recognise and kill target cells without the need for antigen activation. Instead, they can quickly identify and destroy diseased, cancerous, stressed, or otherwise damaged cells. To destroy their prey, NK cells employ a number of techniques, including as the production of poisonous granules and the triggering of apoptosis. They can create cytokines that stimulate other immune cells, and they also play a part in controlling the immunological response.
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Question 9 (1 point)
If a mylar balloon is filled with gas to a volume of 2.9 L at a temperature of 20 degrees celcius and then heated with a heat gun to 150 degrees
celcius, what is the new volume (assume no air escapes the balloon)?
Answer:I’m not sure
Explanation:free trial
I am a celestial body that does not produce light. I orbit a planet
In which cell is there is an absence of homologous chromosomes?
The cell where there is an absence of homologous chromosomes is Gamete.
Chromosomes in a couple – commonly one inherited from the mother and one from the daddy. For example, the two copies of Chromosome 1 in a cell could be called homologous chromosomes.
This organism is diploid, however only has a 1 pair of chromosomes. these are homologous chromosomes, because they create the same genes. however, they can deliver distinct alleles of every gene, proven by their inner pattern.
Homologous chromosomes are matched pairs containing the identical genes in equal places along their period. Diploid organisms inherit one reproduction of every homologous chromosome from every discern; all together, they may be considered a complete set of chromosomes.
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Use the drop-down menus to name these
structures.
cis-3-decene
cis-3-nonene
trans-3-decene
trans-3-nonene
Using drop-down menu , IUPAC name is as follows :
cis-3-decene: (Z)-3-decene , cis-3-nonenetriene: (Z,Z,Z)-3-nonenetriene
trans-3-decene: (E)-3-decene , trans-3-nonene: (E)-3-nonene
cis-3-decene is an alkene with a double bond between carbon atoms 3 and 4, and both alkyl groups (attached to the double bond) on the same side of the double bond. Therefore, its IUPAC name is (Z)-3-decene.
cis-3-nonenetriene is a triene with three double bonds. The double bonds are between carbon atoms 3 and 4, 6 and 7, and 9 and 10. Since all the alkyl groups attached to the double bonds are on the same side of the double bonds, the compound is named as (Z,Z,Z)-3-nonenetriene. trans-3-decene is an alkene with a double bond between carbon atoms 3 and 4, and both alkyl groups (attached to the double bond) on opposite sides of the double bond. Therefore, its IUPAC name is (E)-3-decene. trans-3-nonene is an alkene with a double bond between carbon atoms 3 and 4, and both alkyl groups (attached to the double bond) on opposite sides of the double bond. Therefore, its IUPAC name is (E)-3-nonene.
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Discuss why Feldman and Frydman consider molecular chaperones critical for protein folding. Use at least two specific examples in detail
Feldman and Frydman consider molecular chaperones critical for protein folding because they play crucial roles in ensuring proper folding and preventing protein misfolding and aggregation.
One specific example is the chaperone Hsp70. Hsp70 binds to hydrophobic regions of unfolded or misfolded proteins, preventing their aggregation and assisting in their correct folding. Hsp70 accomplishes this by utilizing ATP hydrolysis to undergo conformational changes that allow it to bind to client proteins and facilitate their folding. Without Hsp70, misfolded proteins could aggregate and form toxic species associated with various diseases, such as neurodegenerative disorders.
Another example is the chaperonin GroEL/GroES system. GroEL is a large, multi-subunit complex that provides a confined environment for the folding of newly synthesized or stress-denatured proteins. GroES acts as a lid, enclosing the substrate protein within the GroEL cavity. The GroEL/GroES system facilitates protein folding by preventing misfolding and promoting proper folding through cycles of substrate binding and release. This chaperonin system is essential for the folding of many proteins, including enzymes involved in critical cellular processes.
Overall, molecular chaperones like Hsp70 and the GroEL/GroES system are crucial for protein folding because they help prevent protein misfolding, promote correct folding, and protect against protein aggregation, ensuring proper protein function and maintaining cellular homeostasis.
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Name the following alkyne:
CH3CH2C = C - CI
Answer:
The answer was be 1-chloro-1-butyne
Explanation:
In other words the answer is option letter A
You welcome have a nice day.
The name of the given alkyne, CH₃CH₂C = C – CI is 1 chloro 1 butyne.
The correct option is A.
What are alkynes?Alkynes are unsaturated hydrocarbons, that have carbon-carbon triple bonds.
Chlorobutyne is colorless and is liquid at room temperature and pressure.
It is polar, but still slightly soluble in water.
Thus, the correct option is A, 1 chloro 1 butyne.
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Sn + 2 H2SO4 → SnSO4 + SO2 + 2 H2O If 219.65 grams of SnSO4 are produced, how many moles of H2SO4 were reacted?
Answer:
2.05moles
Explanation:
The balanced chemical equation in this question is as follows;
Sn + 2H2SO4 → SnSO4 + SO2 + 2H2O
Based on the above equation, 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
However, the mass of SnSO4 produced is 219.65 grams. Using mole = mass/molar mass, we can find the number of moles of SnSO4 produced.
Molar mass of SnSO4 where Sn = 118.7, S = 32, O = 16
= 118.7 + 32 + 16(4)
= 150.7 + 64
= 214.7g/mol
mole = 219.65/214.7
mole = 1.023mol
Therefore, if 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
1.023 mol of SnSO4 produced will cause: 1.023 × 2/1
= 2.046moles of H2SO4 to react.
All weather is energy in motion. Where does the energy come from
Answer:
The Sun radiates huge amounts of energy. Only a small portion of that energy hits the Earth, but it is enough to light our days, heat our air and land, and create weather systems over the oceans. Most of the energy you will learn about comes from the Sun. The Earth also gives off energy.
Explanation:
Answer:
"The Sun radiates huge amounts of energy. Only a small portion of that energy hits the Earth, but it is enough to light our days, heat our air and land, and create weather systems over the oceans. Most of the energy you will learn about comes from the Sun. The Earth also gives off energy."
By the way I got this off thee internet and copy and pasted it so don't write it just look and write in your own words please. Please do not copy and paste or write what i wrote because this is someone else's explanation or answer
Hope this helps!! Also please rank thank you.
Explanation:
The half-life of radium-226 is 1,600 years. It decays into radon-222. What fraction of the original amount of radium-226 in a sample will still be radium
after 8,000 years?
A.1/8
B.1/4
c.1/32
D.1/16
Answer:
Your answer will be C. 1/32
Answer:
C. 1/32
Explanation:
when the paraffin of a candle (typical formula C21H44) burns are as follows:(1) Complete combustion forms CO2 and water vapor.(2) Incomplete combustion forms CO and water vapor.(3) Some wax is oxidized to elemental C (soot) and water vapor.(a) Find ΔH∘rxn of each reaction (ΔH∘f of C21H44=−476kJ/mol; use graphite for elemental carbon).(b) Find q (in kJ) when a 254-g candle bums completely.(c) Find q (in kJ) when 8.00% by mass of the candle burns incompletely and another 5.00% undergoes soot formation.
The enthalpy of reaction for complete combustion, incomplete combustion, and formation of soot for a candle made of paraffin wax (C21H44) were calculated. The heat released when a 254-g candle burns completely was found to be -34679 kJ. The heat released when 8.00% by mass of the candle burns incompletely and another 5.00% undergoes soot formation was found to be -3404 kJ.
(a) The balanced chemical reactions and their enthalpies of reaction are:Complete combustion: \(C21H44(l) + 63/2 O2(g) → 21 CO2(g) + 22 H2O(g) ΔH°rxn = -30961 kJ/mol\)Incomplete combustion: \(2 C21H44(l) + 61 O2(g) → 42 CO(g) + 44 H2O(g) ΔH°rxn = -29384 kJ/mol\)Formation of soot: \(C21H44(l) + 21 O2(g) → 21 C(s, graphite) + 22 H2O(g) ΔH°rxn = -13962 kJ/mol\)(b) The heat released when the candle burns completely can be calculated using the heat of reaction for complete combustion:\(q = nΔH°rxn = (254 g / 226.4 g/mol) * (-30961 kJ/mol) = -34679 kJ\)(c) To find the heat released when only part of the candle burns, we first calculate the mass of the candle consumed in each reaction. For incomplete combustion, 8.00% of the mass is consumed, while for soot formation, 5.00% of the mass is consumed. The mass of the candle consumed in each reaction is:Incomplete combustion: 0.08 * 254 g = 20.32 gSoot formation: 0.05 * 254 g = 12.70 gThe heat released in each reaction can then be calculated:Incomplete combustion: \(q1 = nΔH°rxn = (20.32 g / 226.4 g/mol) * (-29384 kJ/mol) = -2619 kJ\)Soot formation: \(q2 = nΔH°rxn = (12.70 g / 226.4 g/mol) * (-13962 kJ/mol) = -785 kJ\)The total heat released is the sum of q1 and q2:\(q = q1 + q2 = -2619 kJ - 785 kJ = -3404 kJ\)Summary: The enthalpy of reaction for complete combustion, incomplete combustion, and formation of soot for a candle made of paraffin wax (C21H44) were calculated. The heat released when a 254-g candle burns completely was found to be -34679 kJ. The heat released when 8.00% by mass of the candle burns incompletely and another 5.00% undergoes soot formation was found to be -3404 kJ.For more such question on combustion
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