A 30 kg is placed on a skateboard and pushed across the room with a velocity of 4 m/s. the pusher applies more force, increase the velocity to 10 m/s. How much work was done to move the box ?

Given that distance of moon from the earth is, R= 3.84 x 10^8 m

Also, time taken to complete one revolution is, T= 23.7 days = 2047680 seconds

Mass of the moon is, m= 7.347 Kg

To find the centripetal acceleration,

Substituting the values, we get

Answer:

its should be 2.0 and 4.5 on it

Explanation:

Average velocity = displacement / time

v = (25 m − 2 m) / 4.5 s

v = 5.11 m/s

Explanation:

Here,

Mass=16,500kg.

speed=14 m/s.

we know that,

\(\tt{ p=m×v }\) ⠀

where,

p=momentum

m=mass

v=velocity

according to the question,

\(\tt{ momentum =mass×velocity }\) ⠀

\(\tt{ 16500×14 }\) ⠀

\(\tt{ 231000~kg.m/s }\) ⠀

so,

velocity of the car is 231000kg.m/s

The work is given by:

Plugging the values given we have:

Therefore the man do 120 ft*lb of work

Answer:

the answer to your question is c

The density of the white dwarf is 1.08 x 10³ kg/m³.The escape velocity from the surface of the second white dwarf is 15.8 km/s.

To find the density of the white dwarf, we can use the formula:

density = mass / volume

The volume of a sphere (which approximates the shape of the white dwarf) is:

volume = (4/3) x pi x radius³

Plugging in the given values for the first white dwarf, we get:

volume = (4/3) x pi x (7.00 x 1\(0^{8}\) cm)³
volume = 1.38 x 1\(0^{27}\) cm³

The mass of this white dwarf is 0.75M Sun, or 0.75 x 1.99 x 1\(0^{30}\) kg = 1.49 x 1\(0^{30}\) kg. Therefore:

density = 1.49 x 1\(0^{30}\) kg / 1.38 x 1\(0^{27}\) cm³
density = 1.08 x 10³ kg/m³

For the second white dwarf, we can use the formula for the escape velocity of an object:

escape velocity = (2GM/r)

where G is the gravitational constant, M is the mass of the object, and r is its radius. Plugging in the given values, we get:

escape velocity = (2 x 6.67 x 1\(0^{-11}\) N m²/kg² x 1.2 x 1.99 x 1\(0^{30}\) kg / (7.00 x 1\(0^{8}\) cm))
escape velocity = 1.58 x 1\(0^{4}\) m/s
escape velocity = 15.8 km/s

Therefore, the escape velocity from the surface of the second white dwarf is 15.8 km/s.

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Answer:When an egg is dropped from a higher height, it reaches a greater speed before hitting the ground. So the egg dropped from 5 meters has a greater velocity when it strikes the ground. It thus experiences the greater velocity change during the collision.

Explanation:

Answer:

  large-scale natural disasters

Explanation:

The niceties of civilization are generally unavailable over wide areas when they are affected by ...

Such situations often require rescue workers.

Situations such as:

First, we wonder, who are rescue workers? Basically speaking, a rescue worker is anyone who is trained to bring people out of any harm, danger, or threat that may come their way.

|n such emergency situations, power lines are usually down, and so it may be difficult for them to get the energy needed to power their  electrical devices.

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Answer:

Vx = 3.10 [m/s]

Vy = 11.59 [m/s]

Explanation:

To solve this problem we must decompose the velocity vector by means of the angle on the horizontal.

v = 12 [m/s]

Vx = 12*cos (75) = 3.10 [m/s]

Vy = 12*sin (75) = 11.59 [m/s]

Given values:

Mass of the steel ball, m = 100 g = 0.1 kg

Height of the steel ball, h1 = 1.8 m

Rebound height, h2 = 1.25 m

a.  PE= mgh

0.1 x 9.8 x 1.8 =

1.764 Joules

b. KE = PE ->

1.764 Joules

c. KE= 1/2 mv square

so v = square root 2ke/m

square root 2 x 1.764/ 0.1

= 5.93 m/s

d. KE=PE=mgh square

0.1 x 9.8 x 1.21 =

1.186 joules

velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s

It makes a distinct "clang", even if there is nobody there to hear it.

Answer:

No machine is free from the effects of gravity, and even with wonderful lubrication, friction always exists. The energy a machine produces is always less than the energy put into it (energy input). ... That is why 100% efficiency in machines shall not be possible.

Answer:The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent.

Explanation:

Answer:

E = 1/2 * k x^2 is the energy stored in the spring

E = 1/2 * 260 N/m * .08^2 m = .832 Joules

The measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

Option C.

The median is the middle point in a dataset—half of the data points are smaller than the median and half of the data points are larger.

To find the median: Arrange the data points from smallest to largest. If the number of data points is odd, the median is the middle data point in the list.

So from the given data of the 100 meter dash, the measure of central tendency that should be used to calculate the cutoff time for the final race is the median.

The median will help to separate half of the data points that are smaller than the cutoff time and half of the data points are larger than the cutoff time.

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Here is your Answer:

Answer:tublar

Explanation:tublar bikes usaly cost 30-40% more

Answer:

Tubular

Explanation:

In terms of puncture resistance, tubular tyres also rank better than clincher tyres which are prone to pinch flats. However, one staple, nail, or piece of glass can be the end of your tubular tyre, whereas a punctured clincher can be reused with a new inner tube. A tubular tyre can also be ridden safely while flat

The speed of the roller coaster at point E is 40 m/s.

The speed of the roller coaster at point F is 49 m/s.

The speed of the roller coaster at point E is calculated by applying the following formula as shown below.

v = √ ( 2gΔh )

where;

At point E, the change in height of the coaster, Δh  = 120 m - 40 m = 80 m

v = √ ( 2gΔh )

v = √ ( 2 x 10 x 80 )

v = 40 m/s

At point F, the change in height of the coaster, Δh  = 120 m - 0 m = 120 m

v = √ ( 2gΔh )

v = √ ( 2 x 10 x 120 )

V = 49 m/s

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To solve this problem, we need to use the kinematic equations of motion to determine the hang time of the Cuban tree frog during a single jump.

What is Velocity?

It is defined as the displacement of an object per unit time in a particular direction.

In other words, velocity is the speed of an object in a given direction. It is a vector quantity because it has both magnitude (the speed) and direction.

First, we need to find the vertical component of the initial velocity vector (v0) using the sine function:

sin(26°) = vy / 4.5 m/s

vy = 4.5 m/s sin(26°) = 1.98 m/s

The vertical component of the velocity vector determines how high the frog will jump.

Next, we can use the following kinematic equation to solve for the hang time (t) of the frog:

Δy = v0yt - 1/2 gt^2

where Δy is the vertical displacement (i.e., how high the frog jumps), v0y is the vertical component of the initial velocity vector, g is the acceleration due to gravity (9.8 m/s^2), and t is the hang time.

Since the frog jumps on level ground, its vertical displacement is zero (i.e., it returns to its original height). Therefore, we can simplify the equation as follows:

0 = v0yt - 1/2 gt^2

t(1/2 g t - v0y) = 0

t = 0 or t = 2v0y / g

We can discard the solution t = 0 because it is not physically meaningful. Therefore, the hang time of the Cuban tree frog during a single jump is:

t = 2v0y / g = 2(1.98 m/s) / 9.8 m/s^2 = 0.40 s

Therefore, the answer is (d) 0.40 s.

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In T-ball, batters hit a ball that is placed on a T-shaped stand  is that the Batter B will likely hit the ball the greater distance than Batter A in T-ball.

It is more likely that Batter B will hit the ball the greater distance than Batter A in T-ball.

This is because Batter B is using the bat's maximum potential energy to hit the ball.

Batting directly behind the ball gives Batter B more control over the swing's direction and ensures the maximum potential energy transfer to the ball.

Let us understand how it happens, the baseball bat has the most potential energy when it is at a right angle to the ground.

The maximum potential energy of the bat is equal to the product of its mass, the gravitational force acting on it, and the height of the bat above the ground.

By holding the bat directly behind the ball, Batter B has a higher chance of creating a larger potential energy by using the bat's maximum potential energy to hit the ball.

This, in turn, will help the ball go further.

The batter who is hitting the ball with the bat directly behind it is the best way to hit the ball in T-ball.

Hitting the ball in this way enables the batter to get the most control over the direction and distance the ball travels.

In conclusion, Batter B will likely hit the ball the greater distance than Batter A in T-ball.

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Answer:

im saying 4. its just a guess it makes sense tho

Explanation:

sorry for getting this wrong.

Answer:

longitudinal waves

Explanation:

I got it right

Answer:

ΔP = - 689.92 Pa

Explanation:

This is a fluid mechanics exercise, let's use Bernoulli's equation, where subscript 1 is for the wide part and subscript 2 is for the narrow part

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

suppose the venturi tube is level, y₁ = y₂

Now let's use the continuity equation

         A₁ v₁ = A₂ v₂

         v₂ = \(\frac{A_1}{A_2} \ v_1\)

we substitute

         P₁ + ½ ρ v₁² = P₂ + ½ ρ v₁² (\frac{A_1}{A_2} \ v_1 )²

         P₂ = P₁ + ½ ρ v₁² ( \(1 - \frac{A_1}{A_2}\) )

we have assumed that the density of the air does not change,

         ρ (air) = 1,225 kg / m³

         P₁ = P_{atm}

the relation of the entry and restriction area is

         A₂ / A₁ = 0.85

Thus

         A₁ / A₂ = 1,176

let's calculate

         P₂ - P₁ =  ½ 1,225 80² (1- 1,176)

         ΔP = - 689.92 Pa

The pressure in the reservoir will spread the amount of 689.92 Pa of its initial pressure

The solid cylinder's ultimate linear velocity is roughly 6.57 m/s.

We may use the concept of conservation of energy to calculate the final linear velocity of the solid cylinder. The system's initial potential energy is turned into the solid cylinder's ultimate kinetic energy.

Let us indicate the mass of the cylindrical shell and solid cylinder as m, the radius as R, the inclined plane's height as h, and the solid cylinder's ultimate linear velocity as v.

The potential energy at the inclined plane's top is provided by the formula:

Potential energy equals m * g * h.

where g is gravity's acceleration. Because they have the same mass and height, the potential energy for the cylindrical shell and solid cylinder is the same in this example.

The solid cylinder's kinetic energy is provided by the formula:

(1/2) * m * \(v^2\) = kinetic energy

The cylindrical shell has a larger moment of inertia than the solid cylinder since it is a hollow cylinder. This means that the solid cylinder will have a larger linear velocity for the same kinetic energy.

Adding potential energy to kinetic energy:

m * g * h = (1/2) * m * \(v^2\)

Simplifying the equation:

g * h = (1/2) *\(v^2\)

Now we can solve for v:

\(v^2\) = 2 * g * h

v = √(2 * g * h)

Plugging in the values:

v = √(2 * 9.8 * 2.2)

v ≈ √(43.12)

v ≈ 6.57 m/s

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The answer shud be 31 . 14m

a. Waxing crescent moon - visible near eastern horizon just before Sunrise

b. Waning crescent moon - occurs 14 days after the new moon

c. Full moon - rises at about the time the Sun sets

a. Waxing gibbous moon - sets 2-3 hours after the Sunsets

b. Waxing gibbous moon - visible near western horizon about an hour after sunset

c. Third quarter moon - visible due south at midnight.

Listed following are locations and times at which different phases of the Moon are visible from Earth's Northern Hemisphere.

Match these to the appropriate moon phase.

1. occurs 14 days after the new moon - waning crescent moon

2. visible near eastern horizon just before Sunrise - waxing crescent moon

3. rises at about the time the Sun sets - full moon

4. sets 2-3 hours after the Sun sets - waxing gibbous moon

5. visible near western horizon about an hour after sunset - waxing gibbous moon

6. occurs about 3 days before new moon - waning crescent moon

7. visible due south at midnight - third quarter moon

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Option A: Chromatic aberration is a problem with reflecting telescopes. Large glass lenses with flawless interiors are challenging to produce. There are various surfaces to shape and polish on refractive telescopes.

Compared to huge mirrors, large glass lenses are more challenging to support. Telescopes are instruments used to observe and study celestial objects such as stars, planets, galaxies, and nebulae. They work by collecting and focusing electromagnetic radiation from these objects, allowing astronomers to study their properties and characteristics. Telescopes come in a variety of designs, such as refracting, reflecting, and catadioptric telescopes. Refracting telescopes use lenses to bend and focus light while reflecting telescopes use mirrors to do the same. Catadioptric telescopes use both lenses and mirrors to focus light. Modern telescopes can also operate in a variety of wavelengths, including visible light, radio waves, and X-rays. In recent years, the development of space telescopes has enabled astronomers to observe the universe beyond the limitations of the Earth's atmosphere. Telescopes have played a crucial role in advancing our understanding of the universe and continue to be an essential tool in modern astronomy.

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Answer:

d

Explanation:

Answer:true

Explanation:

Given that the object is moving due north at 32 m/s, this simply expresses the velocity of the object.

This is a quantity that has magnitude but no direction. Examples include energy, work, speed, distance etc

This is a quantity which have both magnitude and direction. Example include acceleration, velocity, moment, displacement etc

Velocity is the rate of change of displacement with time.

Velocity = displacement / time

Velocity can be written as 4 m/s due east

This the distance travelled per unit time.

Speed = distance / time

Speed can be written as 4 m/s

Considering the question given above, we were told that the object is moving due north. This simply talks about the velocity.

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The minus 12000 N force acts on the 1800 kg object for 1.95 seconds in order to bring it to a stop from an initial velocity of 13 m/s.

Stationary refers to a state of rest or lack of motion.

We can use the following kinematic equation to solve for the time (t) that the force acts on the object:

vf = vi + at

Where

Using Newton's second law, we can find the acceleration (a) of the object:

F = ma

Where

a = F/m = -12000 N / 1800 kg = -6.67 m/s^2 (the negative sign indicates that the acceleration is in the opposite direction of the force)

Substituting the values into the kinematic equation:

0 = 13 m/s + (-6.67 m/s^2) × t

Solving for t:

t = 13 m/s / 6.67 m/s^2 = 1.95 s

Therefore, the minus 12000 N force acts on the 1800 kg object for 1.95 seconds in order to bring it to a stop from an initial velocity of 13 m/s.

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The student should have controlled the power of the mains supply, as this affects the amount of energy transferred to the heating element and the rate at which it increases in temperature.

A heating element is a device that produces heat by converting electrical energy into heat energy. It is commonly found in electric heaters, stoves, ovens, toasters, and other appliances. The heating element works by passing an electric current through a coil of wire or metal, typically made of nickel-chromium or iron-chromium alloy. When the current passes through the coil, it produces heat as a result of resistance to the flow of current. The heat is then transferred through the surrounding material and into the air. Heating elements are usually designed to operate at a certain temperature, and when this temperature is reached, the element turns off automatically. Heating elements are important components of many household appliances and are used to provide a safe and efficient source of heat.

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