Which number is greater?

A. 3.33 x 10^7
B. 2.34 x 10^5

The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

The time taken by substance to reduce to its half of its initial concentration is called half life period.

We will use the half- life equation N(t)

N e^{(-0.693t) /t½}

Where,

N is the initial sample

t½ is the half life time period of the substance

t2 is the time in years.

N(t) is the reminder quantity after t years .

Given

N = 13g

t = 350 years

t½ = 1599 years

By substituting all the value, we get

N(t) = 13e^(0.693 × 50) / (1599)

= 13e^(- 0.368386)

= 13 × 0.691

= 8.98

Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

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Answer:

2x-1=5x

-1=3x

1.A. we take away 2x from both sides

2.A they are the same sine they both have the same solution of -1/3

Hope This Helps!!!

Answer:

Rewrite one side by combining like terms                                                                       A yes the equations are equivalent meaning they have the same solution

Step-by-step explanation:

Hope this helped

if the bird goes down it's might be 8 above

Answer:

Please help me now Solve

Answer:

2. one angle is 108, and other is 72

3. x is 12

Step-by-step explanation:

the ratio is 3:2.

3x + 2x = 180

5x = 180

x = 36

36 x 3 = 108

36x 2 = 72

so that is why the two angles re 108and 72.

for the last question, 37 plus 41 plus x = 90

37 plus 41 is 78

90 - 78 = 12

so that is why x is 12.    

Using the permutation formula, it is found that Emily can make 120 arrangements with 1 plant in each spot.

We are working with an arrangement, which means that the order in which the plants are inserted is important, hence the permutation formula is used to solve this question.

The number of possible permutations of x elements from a set of n elements is given by:

\(P_{(n,x)} = \frac{n!}{(n-x)!}\)

In this problem, 3 plants are selected from a set of 6, hence the number of arrangements is given by:

\(P_{(6,3)} = \frac{6!}{3!} = 120\)

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The probability that a randomly selected female high school basketball player will be drafted by a WNBA team is 0.000351 or approximately 0.04%.

The probability of a female high school basketball player being drafted into the WNBA can be taken as a combination of two probabilities.

The probability that she will play basketball in the NCAA, which is equal to 3.9%, and the probability that she will be drafted into the WNBA given that she plays in the NCAA, which is equal to 0.9%, are both equal.

The probability can be calculated by using the formula:

P(WNBA draft) = P(NCAA) × P(WNBA draft | NCAA)

Where, P(NCAA) = 3.9 ÷ 100 which is equal to 0.039
and, P(WNBA draft | NCAA) = 0.9 ÷ 100 which is equal to 0.009

Hence, by substituting the values in the equation we get

P(WNBA draft) = 0.039 × 0.009

Which is equal to 0.000351 or approximately 0.04%

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70% chance that tomorrow (day 1) will be sunny and a 30% chance that it will be cloudy, we can start to model the problem using probability theory and Markov chains.

Assuming that the weather is independent from day to day, we can use the probabilities given to construct a transition matrix, which shows the probability of going from one state (sunny or cloudy) to another over time. Let's denote the transition matrix as P, where P(i, j) represents the probability of going from state i to state j.

Using the probabilities given in the question, we can construct the following transition matrix:

P = [[0.7, 0.3], [0.2, 0.8]]

unny state (s) and the second row corresponds to the cloudy state (c).

We can use this transition matrix to calculate the probability of the weather being sunny or cloudy on any given day t. Let z(t) be a column vector representing the probabilities of the weather being sunny or cloudy on day t. Then, we have:

z(t+1) = P * z(t)

For example, if we know that today (day 0) is sunny, we can use the transition matrix to calculate the probability of it being sunny or cloudy on day 1:

z(0) = [1, 0] (since we know today is sunny)
z(1) = P * z(0) = [[0.7, 0.3], [0.2, 0.8]] * [1, 0] = [0.7, 0.3]

So there is a 70% chance that tomorrow (day 1) will be sunny and a 30% chance that it will be cloudy.

We can continue to use this transition matrix to model the weather over multiple days, and we can also modify the matrix if we have additional information about the probabilities of transitioning between states.

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Answer: Intersect at one point and exactly one solution.

Step-by-step explanation: I answered it right now in the assignment and it was correct.

Step-by-step explanation:

Sample response: Marcus is correct. Jeremy squared -5 instead of 5. The negative is not within parentheses, so it is not squared.

Answer:

sup

Step-by-step explanation:

Marcus is correct. Jeremy squared -5 instead of 5. The negative is not within parentheses, so it is not squared.

sample response on edge

see ya

Answer:

I think the answer is 5a^2+8

Step-by-step explanation:

\(12a^{2} + 6 - 7a + 2 \\ 5a^{2} + 6 + 2 \\ 5a^{2} + 8\)

Considering the rectangle graphed on the coordinate grid side r has points (4, 1) and (6, 3). The equation of a side that is perpendicular to side r is y = x + 3

Information gotten from the question include

side p has points (1, 4) and (3, 6)

side q has points (3, 6) and (6, 3)

side r has points (4, 1) and (6, 3)

side s has points (4, 1) and (1, 4)

A linear function consists of functions where the variables has exponents of 1. The graph of linear functions is a straight line graph and the relationship is expressed in the form.

y = mx + c

Definition of variables to suit the problem to be solved

y = output function

m = slope

x = input function

c = intercept

The slope, m of r

m = (3 - 1) / (6-4)

m = 2/2

m = 1

slope of perpendicular line

slope of line, m = -1/slope of perpendicular line, m'

m' = -1/m

using points (4, 1)

(y - y') = -1/m(x - x')

y' = 4  

m = 1

x' = 1

(y - 4) = -1(x - 1)

y = -x - 1 + 4

y = -x + 5

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Answer:

Kirsten has 45 books in her home library. She will purchase 5 books every month. Kirsten purchases books for r months. For what values of r will Kirsten have at least 95 books?

Step-by-step explanation:

I took the test

The number of significant figures in the given numbers are 7 significant figures, and 6 significant figures respectively.

a) The number 1.023400 has 7 significant figures. Significant figures are the digits that carry meaningful information in a number. In this case, all the digits from 1 to 4 after the decimal point are considered significant because they contribute to the precision of the measurement.

b) The number 11.4500 has 6 significant figures. The zeros at the end of the number after the decimal point are considered significant because they are trailing zeros and indicate the precision of the measurement. In this case, the zeros indicate that the measurement was made to a high degree of precision.

When determining the number of significant figures, it is important to consider all the non-zero digits, zeros between non-zero digits, and trailing zeros after a decimal point. Trailing zeros in a whole number may or may not be significant depending on the context or additional information provided.

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Answer:

They-intercept of the linear function that is represented by the graph is (0,-2)

Step-by-step explanation:

it is where the line meets with the y-axis at a single point, in this case the point is (0,-2)

I hope that this helped

have a good day

Answer:

Slope: 2/3; y-intercept: -2

Answer:

1/4 is the answer for this because the slope is 1 and 4 so this means it is going up at a 1/4 slope.

Answer:

The slope = 1/4

The upper bound of the 95% confidence interval for the average age in the U.S. is 48.29 years.

To determine the upper bound of the 95% confidence interval for the average age in the U.S., we can use the sample data from the survey. The sample size is 1072 people, randomly selected from the U.S. population, with a minimum age of 12. By calculating the average age of the respondents, we can estimate the average age of the entire U.S. population.

Using the given information that the average age of the respondents is 43.56 years, and assuming that the sample is representative of the population, we can calculate the standard error. The standard error measures the variability of the sample mean and indicates how much the sample mean might deviate from the population mean.

Using statistical methods, we can calculate the standard error and construct a confidence interval around the sample mean. The upper bound of the 95% confidence interval represents the highest plausible value for the population average age based on the sample data.

Therefore, based on the provided information and calculations, the upper bound of the 95% confidence interval for the average age in the U.S. is 48.29 years.

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The amount of tax owed by a head-of-household taxpayer with a taxable income of $27,811 is given as follows:

$3,062.

The amount of tax is obtained identifying the correct position in the table in this problem.

The person in this problem is the head of the household, meaning that we should observe the last column of the table.

As income of $27,811 is between $27,800 and $27,850, hence, looking at the fourth-to-last row, the amount of tax owed by a head-of-household taxpayer with a taxable income of $27,811 is given as follows:

$3,062.

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The correct answer is B. F(t) = 75t - 2000: -∞ < t < ∞, where t is a real number.

This problem requires the creation of a linear function that represents the funds raised from ticket sales for the prom. The function must consider the cost of hiring the photographer, which is $2,000. Option B is the correct answer because it provides a linear function that takes into account the photographer's cost, represented by the constant term -2000. The domain of the function is all real numbers since it does not have any restrictions.

Option A is incorrect because it only represents the revenue generated by each ticket sale without considering the cost of hiring the photographer. Option C is incorrect because it restricts the domain of the function to integers, which is not appropriate for this problem. Option D is incorrect because it represents the total revenue generated by ticket sales and the photographer's cost but restricts the domain of the function to integers.

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The minimum sample size needed to estimate u for the given values of c, o, and E is `39`.

Given that the level of confidence is `c = 0.98`, the margin of error is `E = 2`, and the standard deviation is `σ = 7.6`.The formula to find the minimum sample size is: `n = (Zc/2σ/E)²`.Here, `Zc/2` is the critical value of the standard normal distribution at `c = 0.98` level of confidence, which can be found using a standard normal table or calculator.Using a standard normal calculator, we have: `Zc/2 ≈ 2.33`.

Substituting the values in the formula, we get:n = `(2.33×7.6/2)²/(2)² ≈ 38.98`.Since the sample size should be a whole number, we round up to get the minimum sample size as `n = 39`.

Therefore, the minimum sample size needed to estimate u for the given values of c, o, and E is `39`.

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the mass of the thin plate occupying the smaller region cut from the ellipse is 5/21 units.

We can use double integration to find the mass of the thin plate. The mass of the thin plate can be given as:

m = ∬R δ(x, y) dA

Where R is the region cut by the ellipse x^2 + 4y^2 = 12 and the parabola x = y^2, and δ(x, y) is the density per unit area given by δ(x, y) = 5x.

To solve this integral, we need to convert the equation of the ellipse and the parabola to polar coordinates. We can use the transformation x = r cos(θ) and y = (1/2) r sin(θ) to get:

r^2 cos^2(θ) + 2r^2 sin^2(θ) = 12

r cos(θ) = (1/2) r^2 sin^2(θ)

Simplifying the second equation, we get:

r = 2 sin^2(θ)

Substituting r and δ(x, y) into the double integral, we get:

m = ∫[0,2π] ∫[0,2sin^2(θ)] 5r cos(θ) r dr dθ

Solving the inner integral first, we get:

∫[0,2sin^2(θ)] 5r^2 cos(θ) dr = [5/3 sin^6(θ)] cos(θ)

Substituting this back into the double integral and solving the outer integral, we get:

m = ∫[0,2π] [5/3 sin^6(θ)] cos(θ) dθ

Using a trigonometric identity, we can simplify this integral as:

m = [5/3] ∫[0,2π] sin^6(θ) d(sin(θ)) = [5/3] ∫[0,1] u^6 du

Solving the integral, we get:

m = [5/3] [1/7] = 5/21

Therefore, the mass of the thin plate occupying the smaller region cut from the ellipse x^2 + 4y^2 = 12 by the parabola x = y^2 is 5/21 units.

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Answer:

a = 70 degrees.

Step-by-step explanation:

Use this circle angle theorem:

The angle subtended by an arc at the center of a circle = 2 times the angle subtended by the arc on the circumference.

So m < a = 1/2 * 140 = 70 degrees.

Answer:

B on EDGE Perform Muscular Fitness training

Step-by-step explanation:

Answer:

B. perform  muscular fitness testing

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

Value of (256)0.16 X (256)0.0 = 0

Answer:

the answer is 9

check the picture for workings

(a) The doubling time of the population is approximately 13.86 years., (b) It takes approximately 23.10 years for the population to triple in size, (c) It takes approximately 27.72 years for the population to quadruple in size.

To calculate the doubling time of the population, we need to find the time it takes for the population to double from its initial value. In this case, the initial population is 9 million.

(a) Doubling Time:

Let's set up an equation to find the doubling time. We know that when the population doubles, it will be 2 times the initial population.

2P(0) = P(t)

Substituting P(t) = 9e^(0.05t), we have:

2 * 9 = 9e^(0.05t)

Dividing both sides by 9:

2 = e^(0.05t)

To solve for t, we take the natural logarithm (ln) of both sides:

ln(2) = 0.05t

Now, we can isolate t by dividing both sides by 0.05:

t = ln(2) / 0.05

Using a calculator, we find:

t ≈ 13.86

Therefore, the doubling time of the population is approximately 13.86 years.

(b) Time to Triple the Population:

Similar to the doubling time, we need to find the time it takes for the population to triple from its initial value.

3P(0) = P(t)

3 * 9 = 9e^(0.05t)

Dividing both sides by 9:

3 = e^(0.05t)

Taking the natural logarithm of both sides:

ln(3) = 0.05t

Isolating t:

t = ln(3) / 0.05

Using a calculator, we find:

t ≈ 23.10

Therefore, it takes approximately 23.10 years for the population to triple in size.

(c) Time to Quadruple the Population:

Similarly, we need to find the time it takes for the population to quadruple from its initial value.

4P(0) = P(t)

4 * 9 = 9e^(0.05t)

Dividing both sides by 9:

4 = e^(0.05t)

Taking the natural logarithm of both sides:

ln(4) = 0.05t

Isolating t:

t = ln(4) / 0.05

Using a calculator, we find:

t ≈ 27.72

Therefore, it takes approximately 27.72 years for the population to quadruple in size.

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Therefore, the maximum size for the building on the one-acre site would be 0.15 acres.

If the setback requirements and necessary parking spaces limit the building footprint (or foundation) to 15% of the land area, and the site is one acre in size, we can calculate the maximum size for the building by multiplying the land area by the allowed building footprint percentage.

Maximum size for the building = 1 acre * 15%

= 0.15 acres

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Answer:

11.424 is the product of 22.4 x 0.51