12
Select the correct answer.
What creates an electric force field that moves electrons through a circuit?
ОА.
energy source
B.
load
O c.
metal wires
OD.
resistance

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.

using work energy theorem ,

change in kinetic energy = work done by frictional force

\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) =  μmghcos30°

where mass is m=200g

x is speed with which it slides back

y is speed at top of metal ramp=3.8 m/s

μ is coefficient of kinetic friction=0.3

g is gravity = 9.8m/\(s^{2}\)

h is height to which hockey puck is reached on metal ramp=1.18m

Substituting the values and solving for speed x,

x=2.36m/s

speed  it will have when it slides back down to its starting point is 2.36m/s

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Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

The relative change in the spring constant (∆k/k) is approximately 0.11. Option A

To find the relative change in the spring constant (∆k/k) of the NaCl crystal under pressure, we can use the equation :

Δf/f = -Δk/k

where Δf is the change in frequency, f is the initial frequency, Δk is the change in the spring constant, and k is the initial spring constant.

Given that the initial frequency is f = 5.3x10^15 Hz and the change in frequency is Δf/f = 0.11, we can rearrange the equation to solve for Δk/k:

0.11 = -Δk/k

Now we can solve for Δk/k:

Δk/k = -0.11

Since the value is negative, we can consider the absolute value to obtain the relative change in the spring constant:

Δk/k ≈ 0.11.

Option A is correct.

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Answer:

2560m or 2.56km (rounded to 3 significant figures)

Explanation:

First, list all known and desired values/variables (initial vertical velocity is 0 as the plane is kept level and vertical acceleration is just gravity):

\(Vertical \ velocity \ (\frac{m}{s} ) = u_{v} = 0 \\\\ Horizontal \ velocity \ (\frac{m}{s} ) = u_{h} = 200\\\\ Vertical \ acceleration \ (\frac{m}{s^{2} } ) = a_{v} = 9.8 \\\\ Horizontal \ acceleration \ (\frac{m}{s^{2} } ) = a_{h} = 0 \\\\ Vertical \ displacement \ (m) = s_{v} = 800 \\\\ Horizontal \ displacement \ (m) = s_{h}\)

The horizontal displacement is going to be the distance travelled, horizontally of course, once the package is released;

First thing to understand is that the vertical and horizontal components are to be dealt with separately because they don't affect each other;

Since there is no horizontal acceleration (ignoring air resistance), we simply require a velocity and time to find the horizontal displacement, using the formula v = d/t (or speed = distance/time);

What we have is the horizontal velocity but we don't have the time taken;

One thing we know is that the time elapsed for the vertical fall of 800m and for the horizontal displacement must be the same;

What we do, therefore, is find the time taken for the vertical displacement using the formula, s = ut + ¹/₂·at², since we know the vertical velocity, height and acceleration:

800 = (0)t + ¹/₂·(9.8)t²

800 = 4.9t²

t² = 163.26...

t = 12.77...

We now have the time taken for the vertical fall and the horizontal displacement, we can use this with the horizontal velocity we know already and get the horizontal displacement:

\(u_{h} = \frac{s_{h} }{t} \\\\ 200 = \frac{s_{h} }{12.77...} \\\\ s_{h} = 200(12.77...) \\\\ s_{h} = 2555.5...\)

For the work, applicate formula:

\(\boxed{\boxed{\green{\bf{W = F\times d}}}}\)

According our data:

W = 12000 N * 1,5 m

W = 18000 J

The work done is 18000 Joules.

Answer:

13671

Explanation:

(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

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Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

The voltage drop across R3 is 34.5 volts.

Voltage, also known as electric potential difference, is a measure of the difference in electric potential energy between two points in an electrical circuit, and it is measured in volts. It is the driving force that moves electric charges through a circuit, from a higher potential to a lower potential.

To determine the voltage drop across R3 in this circuit, we need to first find the equivalent resistance of R2, R3, and R4, since they are connected in parallel. We can then find the total resistance of the circuit by adding the equivalent resistance in series with R1, and finally use Ohm's Law to calculate the voltage drop across R3.

The equivalent resistance of R2, R3, and R4 in parallel can be calculated as:

1/R_parallel = 1/R2 + 1/R3 + 1/R4

1/R_parallel = 1/20 + 1/25 + 1/10

1/R_parallel = 0.15

R_parallel = 1/0.15

R_parallel = 6.67 ohm

The total resistance of the circuit can be found by adding R1 and the equivalent resistance in series:

R_total = R1 + R_parallel

R_total = 15 + 6.67

R_total = 21.67 ohm

Now we can use Ohm's Law to calculate the current flowing through the circuit:

I = ET / R_total

I = 30 / 21.67

I = 1.38 A

Finally, we can use Ohm's Law again to calculate the voltage drop across R3:

V_R3 = I * R3

V_R3 = 1.38 * 25

V_R3 = 34.5 V

Therefore, the voltage drop across R3 is 34.5 volts.

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Answer:

salts do not conduct electricity. unless u try to dissociate its ions,it cannot.

metals are good conductors of electricity.

acids also conduct electricity if you dissociate them into ions.

a)

We have the next forces

Fd that is the air drag force that is acting upward

Fd gravitation force that is acting downward

in other words

his weight is the force that acts downward and the force of the air resistance with the parachute act upward

b)

In this case, because he is falling at a constant velocity it means

So the net force on the skydiver is 0

therefore both forces are equal amount in other words the forces are equal in magnitude

Answer:

C. 22 m/s

Explanation:

Ignoring air friction....all of the Potential energy will be converted to Kinetic Energy

mgh = 1/2 m ^v^2

gh = 1/2 v^2

sqrt (2 gh) = v   =   ~ 22.1 m/s

Answer:

15 kJ absorbed

Explanation: a p e x

Answer:

Option A is correct. 15kJ is absorbed

Explanation:

Using the formula;

Total energy=potential energy+ absorbed energy.

41=26+absorbed energy

absorbed energy is 15kJ.

The energy possessed to a body due to position is called Potential energy.

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Answer:

Organizing and making sense of behavioral observations is central to psychology’s goal of explanation.

Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m

The net force will be equal to 4915.5 N when the elevator accelerates upward with an acceleration of 1.50 m/s².

Tension can be described as a force along the length of a flexible medium such as a cable, rope, etc. Tension is a pulling force but it can not be a pushing force.

When the elevator moves upward with acceleration (a). The net force will be equal to:

Fₙ = mg + ma

Where m is the mass of the object and 'g' is the gravitational acceleration.

Given the total mass of three people = 185 Kg

The mass of the elevator = 250 Kg

Then the total mass, m = 185 + 250 = 435 Kg

The acceleration of the elevator, a = 1.50 m/s²

The net force of the elevator will be: F = 435 × 9.8 + 435 × 1.50

F = 4915.5 N

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In order to determine the coefficient of linear expansion of this metal, we can use the following formula:

Where DeltaL is the change in length, alpha is the coefficient, L0 is the initial length and DeltaT is the change in temperature.

So, for DeltaL = 0.002 m, L0 = 3.521 m and DeltaT = 88°C , we have:

Therefore the coefficient is 6.45 * 10^-6 °C^-1.

The magnitude of the force on the 4.00-kg block is 3.47 N.

The given parameters:

\(a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2\)

The magnitude of the force on the 4.00-kg block is calculated as follows;

F = ma

F = 4 x 0.867

F = 3.47 N

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Given data:

* The mass of the Moon is 0.0123 times of mass of Earth as,

where M_E is the mass of Earth,

* The radius of the Moon is 0.272 times the mass of Earth as,

where R_E is the radius of Earth,

Solution:

The escape velocity of the object from the surface of the Moon is,

where G is the gravitational constant, M' is the mass of Moon, and R' is the radius of Moon,

Substituting the known values,

Thus, the escape velocity on the Moon is 2.37 Kilometers per second.

Answer:

It could be a stringed instrument or an open pipe.

Explanation:

Let v be the speed of sound, y be wavelength and f be frequency.

v = yf

f= v/y; v is constant.

In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l

f′= v/2l

The second harmonic is heard when l= y

f"= v/y

...

f'''= 3v/2l

We can infer that f"= 2f'

f'''= 3f'

This is similar to the values in the question as;

523.26 =2(261.63) and so on.

Same thing happens with open pipes.

Answer:

200

Explanation:

Answer:

i think its c

Explanation:

trust me

Explanation:

Which of the following best defines self-efficacy? The belief in one's ability to cause an intended event to happen. ... If Bobby does not value athletic skill, his lack of talent will have less impact on his self-esteem than if he highly values athleticism.

Q1: A: The force applied would be the same, but the distance would be shorter.

Q2: D: mechanical advantage

Q3: A: Both levers place the fulcrum in between the applied force and the object being lifted.

Q4: C: The man is farther from the fulcrum than the rock is.

Q5: 96.1%

Q6: the friction of the individual pulleys

Q7: 10 kg moving at 5 m/s

Q8: The first rider has more mass.

Q9: mass and speed

Q10: The kinetic energy of the 15 balls will be greater than the kinetic energy of one ball.

Q11: from the electric fields of charged subatomic particles

If the racer keeps the same speed, it would take her approximately 71.94 seconds to run the next 400 meters.

If the racer keeps the same speed, it would take her approximately 289.56 seconds to run one mile.

FIRST CASE: To solve this problem, we can use the formula for average speed, which is:

average speed = distance / time

We can rearrange this formula to solve for time:

time = distance / average speed

In the first part of the problem, the racer ran 100 meters in 18 seconds. We can calculate her average speed as:

average speed = distance / time = 100 meters / 18 seconds ≈ 5.56 m/s

Now we can use this average speed to find the time it would take her to run the next 400 meters:

time = distance / average speed = 400 meters / 5.56 m/s ≈ 71.94 seconds.

SECOND CASE: We need to find the time it would take the racer to run the next mile. One mile is equal to 1609.34 meters. We can use the same formula as before, but this time we need to use the distance of one mile:

time = distance / average speed = 1609.34 meters / 5.56 m/s ≈ 289.56 seconds

Therefore, if the racer keeps the same speed, it would take her approximately 289.56 seconds to run one mile.

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The frequency of the 5 waves with a length of 4m hit the shore every 2 seconds is 2.5 Hz.

This is the number of cycles completed by a wave in one second. The s.i

unit of frequency is Hert (Hz).

From the question, to calculate the frequency of 5 waves with length of 4 m that hit the shores every 2 seconds, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The frequency of the wave is 2.5 Hz.

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Answer:

I was also going to ask same question edited:ok i found its true