If f(x) = cos x - 7 tanx, then find:
f'(x)

Answer:

4x2−12x+9=0

Step-by-step explanation:

The equation, 2x2+x+3=0, does not have a solution

The equation, x2+5x−3=0, equals -5/2+1/2√37 and -5/2+-1/2√37

The equation, x2−5x+4=0, equal 1 and 4

The equation, 4x2−12x+9=0, equals only 3/2

Hope this Helps

The range of Axel's training zone, assuming a moderate exercise intensity, would be approximately 123 to 164 beats per minute (BPM).

To calculate this range, we use the Karvonen formula, which takes into account Axel's resting heart rate (RHR) and desired training intensity. Assuming a moderate-intensity workout, we can use a target heart rate range of 60% to 80% of his MHR.

Target Heart Rate = ((MHR - RHR) x %Intensity) + RHR

Assuming a resting heart rate of 65 BPM and moderate intensity of 60% to 80% of his MHR, Axel's target heart rate range would be approximately 123 to 164 BPM.

Therefore, the range of Axel's training zone would be approximately 123 to 164 BPM.

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Answer:

$53.22

Step-by-step explanation:

$53.22

Sorry If I am wrong

\(\fbox{20.25}\)

To find her miles per hour, we need to divide the total miles by the total hours to find how many miles she drives in each hour.

\(162\div8\)

\(=20.25\)

Step-by-step explanation:

3x-12=0

Therefore, 3x= 0-12

Therefore, x= -12/3

Therefore, x= - 4

X=-4

PLZZ GIVE ME BRAINLIEST TAG

THANK YOU....

Answer:

Step-by-step explanation:

The relationship between the number of cups of water, w, and the number of cups of

lemon juice, j, used in a recipe is described by the equation shown.

j = 2w

To evaluate the number of cups pr cup of juice, find the value of w given j=1

1=2w

w=1/2

iHalf a cup of water is needed for each cup of lemeonce ju

Answer:

Hope this helps!!!!

Step-by-step explanation:

The order of the combination of the pouches is

1 pouch of 25 marbles

7 pouches of 10 marbles

5 pouches of 1 marbles

This question can be solved by using theoretical analysis

Firstly consider,

We can collect 100 marbles in

4 pouches if we consider 25 marbles pouches

10 pouches if we consider 10 marbles pouches

20 pouches if we consider 5 marbles pouches

100 pouches if we consider 1 marble pouches

But We need 100 marbles in 13 pouches

So first we take a pouch of 25 marbles

Now

Number of marbles we need is 100 - 25=75

Numbers of bags else we need to pick is 13- 12= 1

Now,

We can take

3 pouches if we consider 25 marbles pouches (don’t reach the limit of 13 pouches)

7 pouches if we consider 10 marbles pouches (5 remaining)

15 pouches if we consider 5 marbles pouches (exceeds the limit of 13 pouches)

75 pouches if we consider 1 marble pouches (exceeds the limit of 13 pouches)

So, If we take 7 pouches of 10 marbles we can easily collect 70 marbles in 7 pouches

Number of marbles we need is 75- 70= 5

Numbers of bags else we need to pick is 12 - 7= 5

So,

Now we need to pick 5 marbles in 5 pouches

We can take,

1 pouches if we consider 5 marbles pouches (do not reach the limit of 13 pouches)

5 pouches if we consider 1 marble pouches (exactly 13 pouches)

So, If we take 5 pouches of 1 marble we can easily collect 5 marbles in 5 pouches

Number of marbles we need is 5 -5 = 0

Numbers of bags else we need to pick is  5 -5 = 0

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The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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Answer:

9.45

Step-by-step explanation:

6 2/6 = 6.3

1 1/2 = 1.5

6.3 * 1.5 = 9.45

9.45

Using ratios, the height of the tree is 18 feet

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity. This is a term that is used to compare two or more numbers. It is used to indicate how big or small a quantity is when compared to another.

In this question, we can set two ratios, and find the height of the tree.

6 / 11 = x / 33

Cross multiply both sides and solve for x

x × 11 = 6 × 33

11x = 198

Divide both sides by coefficient of x

11x / 11 = 198 / 11

x = 18

The height of the tree is 18 feet

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Answer:

60 miles per hour

Step-by-step explanation:

360 miles / 6 hours = 60 miles per hour

Answer:

60, I hope this helped and please mark brainliest!

Step-by-step explanation:

This would be 60 miles per hour since you divide 360 by 6. So the rate is 60.

To design the compensator, we can employ a lead compensator with a transfer function of the form: C(s) = (s+z)/(s+p), where z and p are the zero and pole locations, respectively. The compensator's transfer function is multiplied with the plant transfer function to achieve the desired system response.

To design a compensator for the unity feedback control system with the given plant transfer function, we need to follow these steps:

Step 1: Analyze the Plant Transfer Function

Let's analyze the given plant transfer function:

G(s) = (s+2) * (\(s^2\) + 8s + 15) / (s+6) * K

The plant has three poles: -2, -3, and -5, and one zero at -6. The compensator needs to modify the system to achieve the desired specifications.

Step 2: Determine the Desired Settling Time and Overshoot

According to the problem statement, we want to reduce the settling time by a factor of 2 while maintaining the overshoot at 5%. The desired specifications are:

Settling Time (Ts) = Ts_original / 2

Overshoot (OS) = 5%

Step 3: Determine the Dominant Poles

To reduce the settling time, we need to introduce dominant poles. Let's assume the compensator introduces two dominant poles at s = -p1 and s = -p2, where p1 and p2 are real values.

Step 4: Determine the New Pole Locations

To reduce the settling time by a factor of 2, the new pole locations should be chosen such that Ts_new = Ts_original / 2. The relationship between the natural frequency (ωn) and the settling time (Ts) is given by:

Ts = 4 / (ζ * ωn)

where ζ is the damping ratio.

Since the overshoot is desired to be maintained at 5%, we can use the damping ratio (ζ) to determine the new pole locations. For a damping ratio of 0.6 (which yields an overshoot of approximately 5%), the settling time is:

Ts_original = 4 / (0.6 * ωn_original)

For Ts_new = Ts_original / 2, we have:

Ts_new = Ts_original / 2 = 4 / (0.6 * ωn_new)

ωn_new = 2 * ωn_original

Step 5: Determine the Compensator Transfer Function

The compensator transfer function can be determined based on the desired pole locations. Since we want two dominant poles, the compensator transfer function can be written as:

C(s) = (s + p1) * (s + p2)

Step 6: Determine the Gain (K)

To determine the gain (K), we can use the desired overshoot of 5%. The damping ratio (ζ) and overshoot (OS) are related as follows:

OS = exp((-ζ * π) / sqrt(1 - ζ^2)) * 100

Solving for ζ:

ζ = -ln(OS / 100) / sqrt(pi^2 + ln(OS / 100)^2)

Step 7: Combine the Compensator and Plant Transfer Functions

Finally, we can combine the compensator transfer function and the plant transfer function to form the overall transfer function:

Gc(s) = C(s) * G(s)

H(s) = Gc(s) / (1 + Gc(s))

This completes the design process for the compensator.

Note: The exact numerical calculations for the poles, gain, and transfer functions require specific values for the settling time and overshoot. The steps provided here outline the general approach to design a compensator with the given requirements. To obtain precise numerical values, you will need to substitute the desired specifications into the calculations.

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Answer:

1138.5$

Step-by-step explanation:

10% of 1035 is 103.5.  (1035 divided 10).    

Then you add 1035 and 103.5 and get the answer.

Answer:

C. All real numbers except \(\frac{3}{4}\).

Step-by-step explanation:

The domain of all polynomials is the set of all real numbers, whereas the domain of rational-polynomic functions are the set of all numbers expect for those values of \(x\) so that denominator becomes zero. Hence, we need to solve for \(x\) from following expression:

\(4\cdot x - 3 = 0\)

\(4\cdot x = 3\)

\(x = \frac{3}{4}\)

The domain of the function is all real numbers except \(\frac{3}{4}\). (Right answer: C)

5 yards is equal to 4.57 meters when rounded to the nearest hundredth.

One yard is equal to 0.9144 meters.

To convert 5 yards into meters, we can simply multiply 5 by 0.9144.

5 yards × 0.9144 meters/yard = 4.572 meters

Therefore, 5 yards is equal to 4.572 meters.

To round the answer to the nearest hundredth, we can look at the third digit after the decimal point, which is 2.

Since 2 is less than 5, we can round down and keep the second digit after the decimal point as is. Thus, the final answer is 4.57 meters.

In summary, 5 yards is equal to 4.57 meters when rounded to the nearest hundredth.

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Hey there! I'm happy to help!

If the model airplanes flies 22 feet in 2 seconds, it travels 11 feet in 1 second.

There are 60 seconds in one minute. We multiply 11 by 60, giving 660 feet in 1 minute.

There are 60 minutes in one hour. We multiply 660 by 60, giving us 39600 feet in 1 hour.

There are 5280 feet in a mile. To find our speed in mph, we divide 39600 by 5280, giving us 7.5 mph.

Have a wonderful day! :D

Answer:

The linear equation that represents the value shown below is \(\mathbf{y=4x+6}\)

Option D is correct option.

Step-by-step explanation:

We need to find the linear equation that represents the value shown below.

X l Y

0 l 6

1 l 10

2 l 14

3 l 18

4 l 22

The equation will be of form \(y=mx+b\) where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding slope

Using points (0,6) and (1,10) we can find slope by formula: \(Slope=\frac{y_2-y_1}{x_2-x_1}\)

Putting values and finding slope

\(Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{10-6}{1-0}\\ Slope=\frac{4}{1}\\Slope=4\)

So, we get slope m = 4

Now finding y-intercept

When x=0, the value of y is y-intercept

So, y-intercept b = 6

So, the equation having slope m= 4 and y-intercept b=6

\(y=mx+b\\y=4x+6\)

So, The linear equation that represents the value shown below is \(\mathbf{y=4x+6}\)

Option D is correct option.

Herman Hollerith proposed the use of punched cards for counting the census.

The punched card system for counting the census was proposed by Herman Hollerith. Hollerith was an American inventor and statistician who developed the punched card tabulating machine. He presented his idea in the late 19th century as a solution to the challenge of processing and analyzing large amounts of data efficiently.

Hollerith's system involved encoding information on individual cards using punched holes to represent different data points. These cards were then processed by machines that could read and interpret the holes, enabling the automatic counting and sorting of data. The punched card system revolutionized data processing, making it faster and more accurate than manual methods.

Hollerith's invention laid the foundation for modern computer data processing techniques and was widely adopted, particularly by government agencies for tasks like the census. His company eventually became part of IBM, which continued to develop and refine punched card technology.

In summary, Herman Hollerith proposed the use of punched cards for counting the census. His invention revolutionized data processing and laid the groundwork for modern computer systems.

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The candy store will use 103 grams of sugar in 10 hours.

To find out how many grams of sugar the store will use in 10 hours, we can simply multiply the amount of sugar used in one hour (10.3 grams) by the number of hours (10).

To solve the problem, we use a simple multiplication formula: the amount used per hour (10.3 grams) multiplied by the number of hours (10) to find the total amount of sugar used in 10 hours.

We can interpret this problem using a rate equation: the rate of sugar usage is 10.3 grams/hour, and the time period is 10 hours. Multiplying the rate by the time gives the total amount of sugar used.

So the calculation would be:

10.3 grams/hour x 10 hours = 103 grams

Therefore, the candy store will use 103 grams of sugar in 10 hours.

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Answer:

ANSWER=64

Step-by-step explanation:

-4* 2^3= - 32

6*4^2=96

total= 64

Answer:

Step-by-step explanation:

to buy a monthly pass

Answer:

6 days. please see the pic including proof check for 5 day vs 6 day. hope it helps.

Answer: x = 4; x = 5

Step-by-step explanation:

The directions specify to solve by factoring

x^2 - 9x + 20 = 0

To factor, find two numbers that add to -9 and multiply to 20

-5 and -4 work

-5 + (-4) = -9

-5 * -4 = 20

(x - 4)(x - 5) = 0

x = 4, x =5

\(\qquad \qquad \textit{combined proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with }\underline{z^5} \end{array} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}x}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill\)

\(\begin{array}{llll} \textit{"y" varies}\\ \textit{directly with "x"}\\ \textit{inversely with "z"} \end{array}\qquad y=\cfrac{kx}{z}\hspace{5em}\textit{we also know that} \begin{cases} x=10\\ z=4\\ y=15 \end{cases} \\\\\\ 15=\cfrac{k(10)}{4}\implies \cfrac{4}{10}\cdot 15=k\implies 6=k\hspace{8em}\boxed{y=\cfrac{6x}{z}} \\\\\\ \textit{when x = 20 and z = 6, what's "y"?}\qquad y=\cfrac{6(20)}{6}\implies y=20\)

Answer:

I think is 500 hope it helps

The mass of water vapor (g) / mass of dry air (kg) is the humidity measure of  the mixing ratio

The mixing ratio is defined as the mass of water vapor in grams divided by the mass of dry air in kilograms in a mixture of air and water vapor. It is a useful parameter for meteorologists and atmospheric scientists to describe the amount of water vapor in the atmosphere, particularly in the upper atmosphere where the relative humidity may be very low.

Relative humidity is the ratio of the partial pressure of water vapor in the air to the equilibrium vapor pressure at a given temperature and pressure, expressed as a percentage. Vapor pressure is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature in a closed system. Absolute humidity is the mass of water vapor per unit volume of moist air.

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a)

answer: 1

b)

answer: 5/4

Answer:

use long divison  ike this

      16

  -------

8 | 132

    8

  -----

    52

    48

  -----

     4

Step-by-step explanation:

Answer:

Step-by-step explanation:

                                         132/8 = 16 with 4 leftover

                                             32 divided by 8 is 4, 96 divided by 8 is 12, the                                                                  

                                                  extra 4 left over

Answer:

6.   A    5c + 3e + 2

7.   A    w = P/2 - 125

8.   D   point S

Step-by-step explanation:

6.

3 triangles + 5 hexagons + 2 squares =

= 3e + 5c + 2(1)

= 5c + 3e + 2

7.

perimeter = P

length = 250 m

width = w

P = 2L + 2W

P = 2(250) + 2w

2w = P - 500

w = (1/2)(P - 500)

w = (P - 500)/2

w = P/2 - 250

Incorrect expression: w =  P/2 - 125

8.

X = 5

Y = -25

X - Y = 5 - (-25) = 5 + 25 = 30

S = 30