For the first question, the projectile will strike the building at a height of 25.7 m above the ground. For the second question, the projectile's launch speed was 14.97 m/s.
In the first scenario, we can break down the initial velocity into its horizontal and vertical components. The horizontal component is given by v₀x = v₀ * cos(θ), where v₀ is the initial velocity and θ is the launch angle. In this case, v₀x = 53.7 m/s * cos(52.0°) = 33.11 m/s.
Next, we need to calculate the time it takes for the projectile to reach the building. Using the horizontal distance and the horizontal component of velocity, we can determine the time: t = d / v₀x = 21.7 m / 33.11 m/s = 0.656 s.
To find the height at which the projectile strikes the building, we use the equation: Δy = (v₀ * sin(θ)) * t + (1/2) * g * t², where Δy is the vertical displacement, v₀ is the initial velocity, θ is the launch angle, t is the time, and g is the acceleration due to gravity (-9.8 m/s²). Plugging in the values: Δy = (53.7 m/s * sin(52.0°)) * 0.656 s + (1/2) * (-9.8 m/s²) * (0.656 s)² = 70.4 m. Therefore, the projectile strikes the building at a height of 70.4 m above the ground.
In the second scenario, since the projectile is launched horizontally, its initial vertical velocity is 0 m/s. The horizontal distance between the buildings does not affect the launch speed. We can use the equation: h = (1/2) * g * t², where h is the vertical displacement, g is the acceleration due to gravity, and t is the time taken for the projectile to reach the second building. The vertical displacement is given by the height of the second building above the ground, which is 7.8 m. Rearranging the equation, we have: t = sqrt(2h / g) = sqrt(2 * 7.8 m / 9.8 m/s²) = 1.58 s.
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If the current in a wire which is placed perpendicular to a magnetic field increases the force on the wire
Answer:
The force on the wire increases
Explanation:
Since the force on the wire F = BILsinФ where B = magnetic field strength, I = current in wire, L= length of wire and Ф = angle between the magnetic field and the wire.
Given that the magnetic field and the wire are perpendicular, Ф = 90°
So, F = BILsin90° = BIL
Since B and L are constant, F ∝ I
So, if the current in the wire increases, the force on the wire also increases.
What is the number of
Protons-
Electrons-
Neutrons-
that are in bismuth?
Explanation:
Number of :
Protons - 83
Neutrons - 126
Electrons - 83
In Bismuth.
Also it has a atomic mass of 208.98038 units.
what is physical properties of matter
Answer:
A quality of matter that is unrelated to a change in its chemical makeup is called a physical property.
Examples of physical properties of matter:
DensityColorHardnessMelting PointBoiling PointElectrical ConductivityPhysical properties are any qualities of matter that may be felt or seen without changing the sample's chemical composition.
Due to the wide range of features that make up physical attributes, they are further separated into intensive and extensive as well as isotropic and anisotropic categories.
Any characteristic that can be recognized and measured by sight, hearing, touch, smell, or other senses without evoking a chemical reaction is referred to as a physical property. Examples of physical traits are:
Color, Shape, Volume, Density, Calorific value, Boiling point, Viscosity, Pressure, Solubility, electrical current
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In sea-floor spreading, molten material rises from the mantle and erupts in the...
Answer:
along mid ocean ridges
Explanation:
In 1960, Harry Hess came up with the discovery that the floor of the oceans undergoes a movement. This movement is similar to that of being a conveyor belt. In this movement, continents are moved along with the oceans. The molten materials moves up to the mid-ocean ridge where it spreads and erupts. In this process the molten materials pushes the rocks sideways thereby emerging out from the mantel. The freezing of the molten material formed new rocks. This process is termed to be sea-floor spreading.
Which characteristic is related to kinetic energy but not potential energy?
A. An object's shape
B. An object's mass
C. An object's speed
D. An object's height
Answer:
c
Explanation:
An object's speed is the characteristic which is related to kinetic energy but not the potential energy. Thus, the correct option is C.
What is Kinetic energy?The kinetic energy of an object is the energy which it possesses due to the motion of the object. Kinetic energy is defined as the work which is needed to accelerate an object of a given mass from rest position to its stated velocity. Having gained this amount of energy during the acceleration of the object, the object maintains this kinetic energy unless its speed changes or it experiences acceleration.
Kinetic energy is directly proportional to the mass of the object and to the square of the velocity of the object, the expression is:
K.E. = 1/2 m × v²
where, KE = Kinetic energy,
m = mass of the object,
v = velocity of the object.
Therefore, the correct option is C.
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vehicles with traction control system have an advantage in rear wheel skids. by accelerating gently, the tcs will kick in and assist in regaining steering.
Vehicles with a traction control system (TCS) do have an advantage in rear wheel skids. When the TCS detects a loss of traction in the rear wheels, it kicks in and assists in regaining steering control.
By accelerating gently, the TCS is more likely to engage and help prevent the skid. This is because the TCS monitors the rotation speed of each wheel and applies brake pressure to the slipping wheel(s) to regain traction. Additionally, the TCS may also reduce engine power to prevent the wheels from spinning excessively. Overall, the TCS helps to improve the vehicle's stability and control in slippery or skidding situations.
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a 1.2 x 10^4 kg railroad car is coasting along a level, frictionless track at a constant speed of 25m/s, when a 3000 kg load is dropped vertically onto the car from above. What will its new speed be assuming the load stays on the car??
Answer:
\(20\; \rm m \cdot s^{-1}\).
Explanation:
Because the track is level and frictionless, the net force on this car-load system will be zero in the horizontal direction. As a result, (by Newton's Second Law of mechanics,) the total momentum of this system in the horizontal direction will stay the same.
Momentum of the car-load system in the horizontal direction, before contact:
Car: \(m(\text{car}) \cdot v(\text{car, before}) = 1.2 \times 10^{4}\; \rm kg \times 25\; m \cdot s^{-1} = 3.0 \times 10^{6}\; \rm kg \cdot m \cdot s^{-1}\).Load: zero (for it is dropped "vertically.")Combine the two parts to obtain: \(p(\text{system, before}) = 3.0 \times 10^{6}\; \rm kg \cdot m \cdot s^{-1}\).
Because the load stays on the car, the car and the load should have the same horizontal velocity after contact. Let \(v(\text{system})\) denote that velocity. Momentum of the system after contact:
Car: \(m(\text{car}) \cdot v(\text{car, after}) = 1.2 \times 10^{4}\; \rm kg \times (\mathnormal{v}(\text{system}))\).Load: \(m(\text{load}) \cdot v(\text{load, after}) = 3000\; \rm kg \times (\mathnormal{v}(\text{system}))\).Combine to obtain:
\(p(\text{system, after}) =1.5\times 10^{4}\; \rm kg \times (\mathnormal{v}(\text{system}))\).
Because the total momentum of the system will stay the same:
\(\begin{aligned}&1.5\times 10^{4}\; \rm kg \times (\mathnormal{v}(\text{system}))\\ &= p(\text{system, after}) \\&= p(\text{system, before}) \\ &= 3.0\times 10^{6}\; \rm kg \cdot m \cdot s^{-1}\end{aligned}\).
Solve for \(v(\text{system})\) to obtain:
\(v(\text{system}) = 20\; \rm m\cdot s^{-1}\).
In other words, the new velocity of the system would be \(20\; \rm m \cdot s^{-1}\).
if a star was moved twice as far away, how bright would it appear?
If a star is moved twice as far away, it would appear one-fourth as bright.
The apparent brightness of a star depends on its distance and the inverse square law. According to the inverse square law, the brightness of an object decreases as the square of its distance increases. If a star is moved twice as far away, its distance from the observer would be doubled.
Applying the inverse square law, the brightness would decrease by a factor of four (2^2). This means the star would appear one-fourth as bright as before. The amount of light reaching the observer decreases as the distance increases, leading to a decrease in apparent brightness. Therefore, moving a star twice as far away reduces its apparent brightness to one-fourth of its original value.
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Levers pivot on the
A. fulcrum
B. resistance arm
C. effort arm
D.moon
Answer: it’s A
Explanation: hope this is right!!!!
This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?
ОА.
ice
lemonade
B.
lemonade -- air
. C.
air
lemonade
D.
ice - straw
E.
ice - air
Answer:
it A.
Explanation:
did the test on Edmentum and got it right
a heart pacemaker fires 89 times a minute, each time a 36.0-nf capacitor is charged (by a battery in series with a resistor) to 0.632 of its full voltage. what is the value of the resistance?
Answer:
The value of the resistance is 3.99 kΩ
Explanation:
The value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.
How to determine the value of the resistance?
We know that a pacemaker fires 89 times per minute, charging a 36.0-nf capacitor each time, and the capacitor is charged to 0.632 of its full voltage.
The formula for determining the time constant is: τ = RC and the formula for determining the voltage of a capacitor as it charges is: Vc = Vmax(1 - e^(-t/τ)) Using the following information, we can compute the value of the time constant:
τ = RCτ = (0.632Vmax * C) / IV max = 9 V The value of the time constant is τ = RC = (0.632Vmax * C) / I = (0.632 * 9 * 10^-3) / I = 5.67 * 10^-3 / I To find the value of the resistance, R, we'll use the frequency of the pacemaker (f = 89/60 Hz), which is the number of times it fires per second.
RC = 1/fRC = (5.67 × 10^-3)/IR = RCfR = [(5.67 × 10^-3)/I](89/60)R = 3.99 kΩ
Therefore, the value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.
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2. A roller coaster is at the top of a 72 m hill and weighs 150 kg. The coaster (at this moment) has
energy
anarov
Answer:
it is going down down down down the hill it goes so the roller coaster will then be down to a 0 m
A 55.0 kg runner who weighs 539.0 N is accelerating at 3.2 m/s2. After 2
seconds, she reaches a speed of 6.4 m/s. What is her momentum at this
point?
A. 176.0 kg-m/s
B. 8.6 kg-m/s
C. 352.0 kg-m/s
D. 84.0 kg-m/s
Answer:
C. 352.0 kg-m/s
Explanation: Took the test on APEX
Answer:
The answer is C. 352.0 kg-m/s
A constant force of 12 N acts for 5 s on a 5 kg object. What is the change in object’s velocity?
Answer:
"solve: given that F -12 N and time 4 seconds and let we have to find out the P.
F = 12 N
t = 4 s
p = ?
F = m×( v - u ) / t
12 = m×v / 4
m×v = 12× 4
p = 48 kg m/s
Linear momentum will be 48 kg m/s.
Explanation:
A 50 kg child is on a carnival ride with a radius of 5 meters. If the ride spins at a velocity of 5
m/s, what is the centripetal force on the child?
Explanation:
Find a force is F=mv^2/r, so F=50*5^2/5 = 250N
how much work is done by a person lifting a 2.0-kg object from the bottom of a well at a constant speed of 2.0 m/s for 5.0 s?
Work is the same as energy. With the use of energy formula, the work done is 4 J
What is Work ?The work done on an object can be defined as the product of force and distance in the direction of the force. It is synonymous to energy and it is measured in Joule.
Given that a person lifting a 2.0-kg object from the bottom of a well at a constant speed of 2.0 m/s for 5.0 s.
The given parameters are
Mass m = 2 KgSpeed v = 2 m/sTime t = 5 sWork = Energy = 1/2mv²
W = 1/2 × 2 × 2²
W = 0.5 × 2 × 4
W = 4 Joules
Therefore, the much work that is done by the person is 4 Joules.
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A plane took 3.55 hours to finish a journey. If the distance of
the journey was 2840 miles, at what average speed did the
plane travel?
mph
Answer:
800mph
Explanation:
Running water has materials such as dirt, sand, and dead plants and animals in it. When this water ends up in a lake, the materials it was carrying fall to the bottom of the lake and form layers. A layer is thicker when more water enters the lake. For example, thick layers form during times of heavy rain, and thin layers form during times of little rain. Sometimes lakes dry up. The bottoms of dry lakes can change into rock. This rock will still have layers. A geologist studied one of these rocks made from the bottom of a lake. Which rock layer formed during the wettest season? Layer
Answer:
The outside layer is the wettest.
Explanation:
7. Sketch a labeled history graph of a vibrating particle. Be sure to label the axis of the graph correctly, and point out
what qualities of the wave can be determined from the graph.
1. Gravity depends on two things. What two things does gravity depend on? 10pts
SCI
Gravity depends on the mass of objects and distance.
The more mass the more gravitational force, the more distance between two objects the less gravitational force.
A 1400 kg car is traveling at a rate of speed of 32 m/s for 2 hours. For the remaining 3 hours of the trip the car travels at an average rate of speed of 38 m/s. What was the average change in momentum?
The average change in momentum for the car during the trip is 8400 kg·m/s.
What is Momentum?
Momentum is a vector quantity, meaning it has both magnitude and direction. The direction of momentum is the same as the direction of velocity, and its magnitude is proportional to both the mass and the velocity of the object.
Then, we calculate the final momentum of the car during the remaining 3 hours:
Final momentum during the remaining 3 hours = mass × final velocity during the remaining 3 hours = m × v2
Now, we can calculate the average change in momentum:
Average change in momentum = Final momentum - Initial momentum
= (Final momentum during the first 2 hours + Final momentum during the remaining 3 hours) - Initial momentum
= [(m × v2) + (m × v2)] - (m × v1)
= 2m × v2 - m × v1
Plugging in the given values:
Mass of the car (m) = 1400 kg
Initial velocity (v1) = 32 m/s
Final velocity during the first 2 hours (v2) = 38 m/s
Average change in momentum = 2m × v2 - m × v1
= 2 × 1400 kg × 38 m/s - 1400 kg × 32 m/s
= 53200 kg·m/s - 44800 kg·m/s
= 8400 kg·m/s
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2. A mass spring damper system can be modelled by the following equation: dax dx m + C + kx = 0 dt Equation (2.1) dt2 Where m is the mass, x is displacement, t is time, c is the damping constant and k is the spring constant. (a) If the mass is 1 kg, the damping constant is 6 kg sé and the spring constant is 9 kg s?, write the auxiliary equation. (2 marks) (b) Give the general solution for equation 2.1. (4 marks) (c) What type of damping does the system described by equation 2.1 exhibit? (2 marks) A force of sint is applied to the system described by equation 2.1. (d) Write out the non-homogeneous second order differential equation that describes the mass spring damper system once the force is applied. (2 marks) (e) What is the form of the particular integral? (2 marks) (f) Find the particular integral. (4 marks) (8) If x = 0 and Cx = 0 at t = 0, find the particular solution to the non- homogeneous second order differential equation described in part d)
The auxiliary equation is given by d^2x/dt^2 + (c/m) dx/dt + (k/m) x = 0. This can be found by force substituting m = 1kg, c = 6 kg s−1 and k = 9 kg s−2 into the given differential equation.
The general solution for equation (2.1) is given by:$$x(t) = c_1 e^{r_1 t} + c_2 e^{r_2 t}$$where r1 and r2 are the roots of the auxiliary equation and c1 and c2 are arbitrary constants. We can find the roots of the auxiliary equation by solving the characteristic equation:$$r^2 + (c/m)r + (k/m) = 0$$Using the quadratic formula, we get:$$r_{1,2} = \frac{-p \pm \sqrt{p^2 - 4q}}{2}$$where p = c/m and q = k/m. Depending on the values of p and q, there are three cases for the roots:r1 and r2 are real and distinct;r1 and r2 are complex conjugates;r1 and r2 are equal and real.
The system described by equation (2.1) exhibits overdamping, as the damping constant c is greater than the critical damping constant, given by 2√km, where k is the spring constant and m is the mass. Overdamping occurs when the damping force is strong enough to prevent the mass from oscillating.(d) ExplanationOnce the force sint is applied, the non-homogeneous second order differential equation that describes the mass spring damper system is:d^2x/dt^2 + (c/m) dx/dt + (k/m) x = sint.(e).
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Which is true if we bring together a group of positively charged particles? Select one: a. The work done by us is negative; the potential energy of the system is negative. b. The work done by us is negative; the potential energy of the system is positive. c. The work done by us is positive; the potential energy of the system is negative. d. The work done by us is positive; the potential energy of the system is positive. e. None of these statements are correct.
If we bring together a group of positively charged particles, the statement that is true is: c. The work done by us is positive; the potential energy of the system is negative.
When positively charged particles are brought together, they repel each other and the potential energy of the system decreases. This is because the repulsion between the particles increases the distance between them, which reduces the attractive force between them. As a result, the system has a lower potential energy and more kinetic energy.
Therefore, the work done by us to bring together a group of positively charged particles is positive, and the potential energy of the system is negative.
It is important to note that the potential energy of a system is a measure of the energy that is available to do work on the system. The potential energy is positive if the system has the ability to do work, and it is negative if the system has the ability to be done work.
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Find the magnitude of the sum
of these two vectors:
B
3.14 m
2.71 m
30.0°
-60.0°
The magnitude of the sum of two vectors A and B is 4.13 m and the angle of the resultant vector is 10.86°.
From the given,
A = 3.14 m
B = 2.71 m
The resultant vector C= A + B
Vector A is resolved into its vertical and horizontal components,
Aₓ = 3.14 cos(30) = 2.71 m
Ay = 3.14 sin (30) = 1.57 m
Vector B is resolved into its vertical and horizontal components,
Bx = 2.71 cos(60) = 1.355 m
By = ₋2.71 sin (60) = -2.35 m
C = A + B
= (2.71+1.355) x + (1.57 -2.35) y
= 4.064 i - 0.78 j
the magnitude of C = √(4.06)² + ( 0.78)² = 4.13 m
The angle, tan α = 0.78 / 4.06
α = 10.8°
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Why do water molecules tend to stay together and hold their shape? Name and explain the phenomenon by which this happens
Answer:
because liquid and solid states of water possesses intermolecular force of attraction which held the molecules of water in fixed
Which of the following combinations would result in the least acceleration?
O 12N and 1.0 kg
O 60N and 2.0 kg
O IN and 0.20 kg
O5N and 0.35 kg
Answer:
I need to talk to somone about my confusing love life
Explanation:
WILLL GIVE 5 STARS BRAINIEST AND THANKS AND 20 POINTS EACH ANSWER!!!!
A diver performs a dive from a 10 m-platform. She
jumps vertically upwards at 3 m s initially.
Find the time she takes to reach the water surface
Answer:
The time she takes to reach the water from when she jumps off the platform is 1.71 s
Explanation:
According to the equations of motion, we have;
v = u - g·t
v² = u² - 2·g·s
s₁ = u₁·t₁ + 1/2·g₁·t₁²
The given parameters are;
The height of the platform (assumption: above the water) = 10 m
The velocity with which she jumps, u = 3 m/s
The acceleration due to gravity, g = 9.81 m/s²
The height to which she jumps, s, is found as follows;
v² = u² - 2·g·s
At maximum height, v = 0, which gives;
0 = 3² - 2×9.81×s
2×9.81×s = 3² = 9
s = 9/(2×9.81) = 0.4587 m
s = 0.4587 m
The time to maximum height, t, is found as follows;
v = u - g·t
0 = 3 - 9.81×t
9.81×t = 3
t = 3/9.81 = 0.3058 s
The total distance, s₁ from maximum height to the water surface = s + 10 = 0.4587 + 10 = 10.4587 m = 10.46 m
The time to reach the water from maximum height, t₁, is found as follows;
s₁ = u₁·t₁ + 1/2·g₁·t₁²
Where;
s₁ = The total distance from maximum height to the water surface = 10.46 m
u₁ = The initial velocity, this time from the maximum height = 0 m/s
g₁ = The acceleration due to gravity, g (positive this time as the diver is accelerating down) = 9.81 m/s²
t₁ = The time to reach the water from maximum height
Substituting the values gives;
s₁ = u₁·t₁ + 1/2·g₁·t₁²
10.46 = 0·t₁ + 1/2·9.81·t₁²
t₁²= 10.46/(1/2×9.81) = 2.13 s²
t₁ = √2.13 = 1.46 s
Total time = t₁ + t = 1.46 + 0.3058 = 1.7066 ≈ 1.71 s.
Therefore, the time she takes to reach the water from when she jumps off the platform = 1.71 s.
Lance is working in a library using a trolley to carry books. As he stacks books from the trolley on shelves, it gets easier to push or pull the trolley. Which part of Newton’s laws of motion explains the increased ease of moving the trolley?
Answer:
It is the law of f=ma because the lighter the trolley is, the easier it is to push it, because it doesn't have as much mass,
Explanation:
Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day :)
HURRY I NEED IT NOW What is the density at 20oC of 12.0 milliliters of a liquid that has a mass of 4.05 grams?
0.338 g/mL
2.96 g/mL
16.1 g/mL
48.6 g/mL
Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:
ρ = m/V
ρ = 4.05 g / 12 mL
ρ = 0.3375 g/mL
ρ ≅ 0.338 g/mLOPTION A
For tapping frequency (Hz), as numbers approach 0, it means
people are going slower.
Group of answer choices
True
False
The statement "For tapping frequency (Hz), as numbers approach 0, it means that people are going slower" is True.
The tapping frequency or rate is the number of times that one taps their finger in one second. It is measured in Hertz (Hz), which is the number of taps per second.According to the question, when tapping frequency (Hz) approach 0, it means that people are going slower. As the frequency of tapping approaches zero, the person is tapping less frequently and thus slowing down.Frequency is defined as the number of cycles completed per unit time. It also tells about how many crests go through a fixed point per unit time.
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