You explored the relationship between molarity, the number of moles, and solution volume. However, when you prepare a solution, you are unable to directly measure the number of moles of solute. Instead, you can mass the solute and convert between the number of moles and mass using the molar mass of a substance as a conversion factor. The molar mass of a substance can be calculated based on its molecular formula; otherwise, it can be calculated from the mass and number of moles as follows: Molar Mass = Mass solute (in g)Moles solute In order to prepare a certain volume of solution with a desired concentration, you would need to determine the required mass of solute. What mass of CaCl2 would you need to prepare a 100. mL solution at a concentration of 0.240 M ? Express the mass in grams to three significant figures.

Pressure and volume have an indirectly proportional relationship

Ideal gas laws can help us describe the relationship between different values for gases.

Boyle's Law

The ideal gas law that connects pressure and volume given a constant temperature is Boyle's law. Boyle's law is represented as:

This equation shows that pressure and volume have an indirectly proportional relationship. This means that as pressure increases, volume decreases and vice versa. So, pressure and increase opposite of each other.

Indirect Relationships

Indirect relationships occur when one value and the reciprocal of another are proportional. For example, pressure and 1/volume are directly proportional. This function looks like a decreasing exponential function. Attached is an example of a volume vs. pressure graph.

The percent by mass of sulfur is  20.1%.

Here, we need to find the percent by mass of the sulfur atom and we have to do that by first obtaining the molar mass of the compound as we can see it from the question.

Hence;

Molar mass of the compound = 63.55 + 32.07 + 4( 16.00 )

=  63.55 + 32.07 + 64

= 159.62

We now have to find the percent by mas of sulfur;

32.07/159.62  * 100

= 20.1%

The compound contains 20.1% of sulfur by mass of the compound as shown in the calculation.

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Answer:

11280

Explanation:

A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

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Answer:

1.2029 J/g.°C

Explanation:

Given data:

Specific heat capacity of titanium = 0.523 J/g.°C

Specific heat capacity of 2.3 gram of titanium = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

1 g of titanium have 0.523 J/g.°C specific heat capacity

2.3  × 0.523 J/g.°C

1.2029 J/g.°C

Answer:

a.) x = 5

Explanation:

Answer:

+2.

Explanation:

Hello,

In this case, since chromium has six valence electrons in its outer shell, when it loses four electrons it remains with two of them, therefore it charge as chromium ion is +2, so it is written as Cr⁺² and named as chormium (II) or hypochromous ion.

Best regards.

Answer:

both increase the rate at which the solute particles dissolve in the solvent.

Explanation:

The Impact of stirring and increasing the temperature during solution formation is that they both increase the rate at which the solute particles dissolve in the solvent.

Ideal gas law is valid only for ideal gas not for vanderwaal gas. To solve such, we need to know the relation between rate of effusion and molar mass of gases. Therefore, the new volume V₂ is 18L.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. an ideal gas on the walls of the container is inversely proportional to the volume occupied that gas.

Mathematically, Boyle's law can be written as

P₁V₁ = P₂V₂

P₁=initial pressure=342 torr

P₂=final pressure=1710 torr

V₁ = initial volume= 29.0 L

V₂=final pressure=?

Substituting all the given values in the above equation, we get

V₂ = P₁V₁/P₂

V₂ = (342 × 29.0)/1710

V₂ = 18L

Therefore, the new volume V₂ is  18L.

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The percent of histidine side chains would be deprotonated at pH 7.5  is 5.77 %.

The term pKa refers to the negative logarithm of the acid dissociation constant (Ka). The pH is the negative logarithm of the hydrogen ion concentration.

Hence;

Ka = Antilog (-6) =\(1 * 10^-6\)

[H^+] = Antilog (-7.5) = \(3 * 10^-8 M\)

We now have to use the formula;

α = \(\sqrt{} \frac{Ka}{[H^+] }\)

α = \(\sqrt{} \frac{ 1 *10^-6}{3 *10^-8 }\)

α = 5.77 %

Hence, the percent of histidine side chains would be deprotonated at pH 7.5  is 5.77 %.

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The reaction's overall chemical equation: 2 HBr(g) + O₂(g)  Br₂ + 2H₂O(g) These intermediates are known as species

In this mechanism, species are formed in one step of the reaction and consumed in another. These intermediates are known as species. BrO and HO₂ serve as intermediaries in this mechanism. As a result, the intermediates have the chemical formulas HO₂ and BrO.

Chemical species that are produced during a chemical reaction but are not the reaction's final products are called intermediates.

By providing a route for the reactants to transform into products, intermediates play an important role in numerous chemical reactions. They can also assist in explaining the mechanism of the reaction.

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Answer:

B

Explanation:

Not C or D becuase it is data would not show a conclusion and observations does show the conclsuion of the scientists.  Not A becuase explanation does not mean they have data to support their conclusion.  Therefore, it would be B becuase results show what was the effect of something and is often supported with data

Hope that helped :)

b. testing the hypothesis

250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.

w/v = [ mass of solute (g) / volume of solution (mL) ] × 100

5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100

volume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100

volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100

volume of solution (mL) = [ 125 g / 0.05 ] x 100

The molarity is an important method which is used to determine the concentration of a solution. So the term molarity is also known as the concentration. Here the grams of Kr which occupies a volume of 42.6 mL is

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. Its unit is mol L⁻¹ and it is essential to calculate the concentration of a binary solution.

Here M₁V₁ = M₂V₂

M₂ = M₁V₁ /  V₂

25.7 mL = 0.0257 L

42.6 mL = 0.0426 L

M₂ =  5.10 × 0.0257 / 0.0426  = 3.076 g

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Answer:

Number of moles of H₂S gas = 0.0183 moles

Note: The question is incomplete. The complete question is given below:

How many moles of hydrogen sulfide H2S are contained in a 327.3 mL bulb at 48.1°C if the pressure is 149.3 kPa?

Explanation:

The following values are given in the question :

Volume of H₂S gas = 327.3 M = 0.3273 L

Temperature of gas = 48.1°C = (273.15 + 48.1) K = 321.25 K

Pressure of gas = 149.3 kPa

1 kPa = 0.00987 atm; 149.3 kPa = 149.3 × 0.00987 atm = 1.474 atm

Molar gas constant, R = 0.0821 liter·atm/mol·K.

number of moles, n = ?

Using PV = nRT

n = PV/RT

n = (0.3273 × 1.474)/(0.0821 × 321.25)

n = 0.0183 moles

Therefore, number of moles of H₂S gas = 0.0183 moles

Answer:

Answer:

2.77 mol/kg

Explanation:

Molality is a sort of concentration that indicates the moles of solute in 1kg of solvent. In this case our solvent is water and, if we consider water's density as 1g/mL, we determine that the mass of solvent is 750 g.

We convert the mass to kg → 750 g . 1kg /1000g = 0.750 kg

Our solute is the NaOH → 83 g.

We convert the mass to moles → 83 g . 1mol /40g = 2.075 mol

Molality (mol/kg) = 2.075 mol / 0.75kg = 2.77 m

A balloon is filled with 500.0 mL of helium at a temperature of 27 degrees Celsius and 755 mmHg. 3.4 liters is the volume in milliliters will it have when it reaches an altitude where the temperature is -33 degree Celsius and the pressure is 0.65 atm.

A measurement of three-dimensional space is volume. It is frequently expressed in numerical form using SI-derived units or different imperial or US-standard units (such the gallon, quart, and cubic inch). Volume and length (cubed) have a symbiotic relationship.

The volume much a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the volume of fluid (liquid or gas) that the container may hold.

PV/T = constant

(755 x 500) / (27 + 273) = (494 x V) / (-33 + 273)

V = 3396 ml = 3.4 liters

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The kinetic equation for the given reaction is first-order with respect to the reactant, and the rate constant is zero.

To determine the kinetic equation and rate constant for the given data, we need to analyze the relationship between the concentration of the reactant and time.

The general form of a first-order reaction is given by the equation:

Rate = k[A]^n

Where:

Rate is the rate of the reaction

k is the rate constant

[A] is the concentration of the reactant

n is the order of the reaction with respect to the reactant

By analyzing the given data, we can calculate the reaction rate and determine the order of the reaction and the rate constant.

Let's first calculate the reaction rate using the initial and final concentrations and the corresponding time intervals:

Rate = (Change in concentration) / (Change in time)

For the first time interval (0 to 10 min):

Rate = (13.2 kg·m^(-3) - 16.0 kg·m^(-3)) / (10 min - 0 min) = -2.8 kg·m^(-3)·min^(-1)

Similarly, we can calculate the rates for the other time intervals:

10 to 20 min: Rate = (11.1 kg·m^(-3) - 13.2 kg·m^(-3)) / (20 min - 10 min) = -2.1 kg·m^(-3)·min^(-1)

20 to 35 min: Rate = (8.8 kg·m^(-3) - 11.1 kg·m^(-3)) / (35 min - 20 min) = -2.3 kg·m^(-3)·min^(-1)

35 to 50 min: Rate = (7.1 kg·m^(-3) - 8.8 kg·m^(-3)) / (50 min - 35 min) = -1.7 kg·m^(-3)·min^(-1)

By observing the rates for different time intervals, we can see that the rate of change in concentration does not remain constant. This suggests that the reaction is not first-order with respect to the reactant.

To determine the order of the reaction, we can examine how the rate changes with the concentration. Let's calculate the rate ratios for the different time intervals:

Rate ratio (10/0) = (-2.8 kg·m^(-3)·min^(-1)) / (-2.8 kg·m^(-3)·min^(-1)) = 1

Rate ratio (20/10) = (-2.1 kg·m^(-3)·min^(-1)) / (-2.8 kg·m^(-3)·min^(-1)) ≈ 0.75

Rate ratio (35/20) = (-2.3 kg·m^(-3)·min^(-1)) / (-2.1 kg·m^(-3)·min^(-1)) ≈ 1.10

Rate ratio (50/35) = (-1.7 kg·m^(-3)·min^(-1)) / (-2.3 kg·m^(-3)·min^(-1)) ≈ 0.74

By observing the rate ratios, we can see that they are not constant, indicating that the reaction is not a simple integer order (e.g., first-order or second-order). However, we can approximate the order of the reaction by calculating the average rate ratio:

Average rate ratio = (1 + 0.75 + 1.10 + 0.74) / 4 ≈ 0.897

The order of the reaction can be approximated as the exponent that gives this average rate ratio. In this case, the order is approximately 0.897, which we can round to 1. Therefore, the kinetic equation for the reaction is:

Rate = k[A]^1.5

Now, to determine the rate constant (k), we can choose any set of data points and solve for k. Let's use the first data point at time = 0 min:

16.0 kg·m^(-3) = k * (0 min)^1.5

Since (0 min)^1.5 is zero, the right side of the equation is zero. Therefore, k must be zero as well.

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Answer:

\(x_{He}=0.975\\x_{O_2}=0.025\)

Explanation:

Hello.

In this case, since we know the mass of both helium and oxygen, in order to obtain the mole fractions we first need the compute the moles by using their atomic masses, 4.00 g/mol and 32.00 g/mol respectively as shown below:

\(n_{He}=23.6gHe*\frac{1molHe}{4.00gHe}=5.90molHe\\ \\n_{O_2}=4.85gO_2*\frac{1molO_2}{32.00gO_2}=0.152molO_2\\\)

Therefore, the mole fractions are:

\(x_{He}=\frac{n_{He}}{n_{He}+n_{O_2}}=\frac{5.90}{5.90+0.152} \\\\x_{He}=0.975\\\\x_{O_2}=\frac{n_{O_2}}{n_{He}+n_{O_2}} =\frac{0.152}{5.90+0.152} \\\\x_{O_2}=0.025\)

Best regards!

The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.

Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.

Balanced reaction equation

2CH₄(g)⇌C₂H₂(g)+3H₂(g)

The initial concentration of the CH₄ = 0.093 M

The equilibrium concentration of the H = 0.017 M

Equilibrium constant = ?

Let's make the ice table

2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)

0.093 M 0 0

-2x +x +3x

0.093-2x x 0.017 M

3x = 0.017 M

Therefore, x =0.017 M /3 = 0.00567 M

Therefore, the equilibrium concentration of CH₄ =

0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M

Equilibrium concentration of the C₂H₄ = x = 0.00567 M

Let's write the equilibrium constant expression

Kc= [C₂H₄[H2]³/[CH₄]²

Let's put the values in the formula

Kc= [0.00567][0.017]³/[0.0817]²

Kc= 4.17 x 10⁻⁶

Therefore, the equilibrium constant is 4.17 x 10⁻⁶.

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Answer:

Pp, Pp, pp, pp, 50% chance at purple and 50% chance at white

Explanation:

Answer:

which one you didnt explain or added attachment?

Exothermic means that the temperature rises. The following equation represents the freezing of water to make ice. H2O(l) → H2O (s) Exothermic; energy is generated as water molecules form bonds during the phase transition.

An exothermic phase transition occurs when the sample loses energy (heat) to the environment. Condensation is the right answer since it is the phase transition from gas to liquid.

Condensation is the phase shift that occurs when a material transitions from a gas or vapour to a liquid. The process of condensation is exothermic.

When the energy created in an exothermic reaction is released as heat, the temperature rises.

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Answer:

Sculptures rarer than paintings.

Explanation:

Answer:

C. Sculptures rather than paintings

Explanation:

Taking into account definition of percent yield, the percent yield for the reaction is 54.22%.

In first place, the balanced reaction is:

CH₄+ 2 O₂ → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 36 grams of H₂O, 5 grams of CH₄ form how much mass of H₂O?

mass of H₂O= (5 grams of CH₄×36 grams of H₂O) ÷16 grams of CH₄

mass of H₂O= 11.25 grams

Then, 11.25 grams of H₂O can be produced when you burn 5.00 g of methane

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)× 100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yields:

percent yield= (6.10 grams÷ 11.25 grams)× 100

Solving:

percent yield= 54.22%

Finally, the percent yield when methane reacts with oxygen to form carbon dioxide and water is 54.22%.

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Answer:

option C 5

hope this answer helps you dear! take care

Answer:

5, the coefficient is the number right before the variable. The ² and ³ (even though Mines on top and yours is on the bottom) are not coefficient because. . . well it just doesn't make sense.

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?