You drop a pencil from your desk, which is 1 meter above the floor. How long does it take for the pencil to hit the floor? How fast is it going just before it hits the floor?

Answer:

I don't understand

Explanation:

Explanation:

Momentum of an object is defined as the product of the mass of object and the velocity with which it is moving.

p = mv

where, p = momentum, m= mass and v= velocity

mass m = 0.7 Kg and v = 20 m/s

p = 0.7×20 = 14 Kg-m/sec

Therefore, momentum of the object  = 14 kg-m

False. In a parallel circuit, the current through each resistor is not directly proportional to the value of that resistor. Instead, the current through each resistor is inversely proportional to the value of the resistor. This means that as the resistance of a resistor increases, the current through it decreases, and vice versa.

In a parallel circuit, the voltage across each resistor is the same, but the current flowing through each resistor can be different. This is because each resistor provides a different path for the flow of electricity. The total current flowing into the parallel circuit is divided among the different resistors according to their individual resistance values.

In summary, in a parallel circuit, the current through each resistor is inversely proportional to its value. This is because the total current flowing into the parallel circuit is divided among the different resistors according to their individual resistance values, and the voltage across each resistor is the same.

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Answer:

two protons and two neutrons

it's the answer. hope it helps

Alpha particles have two protons and two neutrons. Therefore, option (D) is correct.

Alpha particles can be defined as positively charged particles released from the decay of several radioactive materials. The mass of the Alpha particle is because of the presence of two protons and two neutrons. Therefore, the Alpha particles nucleus is very similar to the nucleus of the Helium atom and are denoted by the Greek alphabet α.

An alpha particle or ray is also known as doubly ionized helium nuclei (He²⁺). The alpha particle's mass is equal to 6.64 × 10⁻²⁷ Kg. Alpha particles are generally generated during the standard radioactive decay of atomic nuclei.

Alpha particles contains the kinetic energy of 5MeV and a speed of 5 % of that of the speed of light. They are also formed in high-energy particle accelerators and are highly ionized particles with low penetration depth compared to other particles.

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Answer:

the ancer is c I know it because I had the same test or it might have been different but it looks familiar to me

Any considerable variation in seismic wave velocity in the crust occurs because there are different types of rocks in the crust.

Seismic waves are waves of energy that travel through the Earth's interior, including the crust. The speed of these waves varies depending on the type of rock they are travelling through. The Earth's crust is made up of a variety of different rocks, such as sedimentary, igneous, and metamorphic rocks, each with its own unique density, elasticity, and other properties that affect the speed of seismic waves.

As a result, seismic waves can be used to study the composition and structure of the Earth's crust, and the variation in their velocity is a crucial aspect of this study. Therefore, the correct answer is that any considerable variation in seismic wave velocity in the crust occurs because there are different types of rocks in the crust.

The complete question is:-

Any considerable variation in seismic wave velocity in the crust occurs because

Group of answer choices

there are different types of rocks in the crust

waves move slower the deeper they travel

waves move faster the deeper they travel

there is no variation of velocity in the crust.

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There are several factors that can cause significant variations in seismic wave velocity within the Earth's crust, including:

1) Rock type: Different types of rock have different physical properties, including density and elasticity, which affect the speed at which seismic waves travel through them. For example, dense, hard rocks like granite have higher seismic velocities than softer, more porous rocks like sandstone.

2) Temperature: Seismic wave velocity is also influenced by temperature, with higher temperatures generally resulting in lower velocities.

This is because hotter rocks tend to be more ductile and less rigid, which reduces their ability to transmit seismic waves quickly.

3) Pressure: Pressure can also affect seismic wave velocity, with higher pressures generally resulting in higher velocities.

This is because high pressure can cause rocks to become more compact and less porous, which increases their ability to transmit seismic waves.

4) Presence of fluids: The presence of fluids such as water or oil can also affect seismic wave velocity. Fluids tend to decrease seismic velocities by reducing the effective stress and increasing the porosity of rocks.

Overall, the complex interplay of these factors can result in significant variations in seismic wave velocity within the Earth's crust, which can provide important information about the geological structure and composition of the subsurface.

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Answer:

this is were you get everything

Explanation:

Answer:

that's crazy. people really do be thirsty for anything doe.

Explanation:

The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection (TIR).

In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle.

TIR only occurs when both of the following two conditions are met

Thus, the phases which include the TIR are the incident and the reflected phase and the incident light hits the surface while the reflected light reflects back.

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Answer:

it yields a derived unit known as Newton, which is the unit of Force.

Explanation:

The formula for force is given by Newton's Second Law, which states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body in the direction of force.

\(F = ma\\\)

where, F = Force

m = mass

a = acceleration

Now, we substitute the respective S.I units of each quantity in equation:

F = Newton (N)

m = kilogram (kg)

a = acceleration = m/s²

Therefore,

\(N = (kg)(m/s^2)\)

So, it is clear from above expression that:

When kilogram is multiplied by meter per second squared, it yields a derived unit known as Newton, which is the unit of Force.

Answer: gravitational and buoyant force

Troposphere, stratosphere, mesosphere, thermosphere and exosphere.

Earth's atmosphere has five major layers.

From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.

a) What are the conditions in the troposphere?

The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.

The temperature of troposphere decreases with an increase in height.

B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?

The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.

The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.

C)What sort of temperatures would she experience in the mesosphere?

The temperature in the mesosphere ranges from -2.5°C to -90°C

The temperature decreases because of a decrease in the absorption of penetrating solar radiation.

The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.

D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?

4,500°F is the temperature of thermosphere.

Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.

Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.

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Answer:

The toy car will fall off Katie's hands and onto the ground .

Explanation:

This happens due to gravity.

The minimum number of polarizers required to make the transmitted light through all the polarizing sheets have an intensity that is less than 18% of that striking the first polarizer is four.

Using Malus' Law, determine the intensity of light transmitted through a polarizer that is rotated at an angle θ relative to the incident polarization of the light.

Malus' Law: I = I₀cos²θ, Where, I₀ is the initial intensity of the light and θ is the angle of rotation.

Calculate the light intensity transmitted through each polarizer.

I₀ = Intensity of polarized light incident on the first polarizer = 100% = 1

I = I₀ cos²19° = 0.818 I₀

I = I cos²19° = 0.667 I₀

I = I cos²19° = 0.544 I₀

I = I cos²19° = 0.443 I₀

I = 0.18 I₀, where I is the intensity of the transmitted light

Determine the minimum number of polarizers required.The transmitted light has an intensity of 18% of that striking the first polarizer. Since the intensity of transmitted light is reduced to 18% after the fourth polarizer, the minimum number of polarizers needed is 4.

Therefore, the minimum number of polarizers required to make the transmitted light through all the polarizing sheets have an intensity that is less than 18% of that striking the first polarizer is four.

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Answer:

depends both on the density and temperature of the cloud.

For an organ pipe that is closed at one end and is 151 cm long:

Part A:

Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz

First overtone (second harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz

Second overtone (third harmonic) = 5 x fundamental frequency
= 5 x 113.91
= 569.55 Hz

Third overtone (fourth harmonic) = 7 x fundamental frequency
= 7 x 113.91
= 797.37 Hz


For an organ pipe that is open at both ends and is 151 cm long:

Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz

First overtone (second harmonic) = 2 x fundamental frequency
= 2 x 113.91
= 227.82 Hz

Second overtone (third harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz

Third overtone (fourth harmonic) = 4 x fundamental frequency
= 4 x 113.91
= 455.64 Hz

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The fundamental frequency (first harmonic) of a closed-end pipe is given by:

f1 = v/4L

where v is the speed of sound in air and L is the length of the pipe.

For a closed-end pipe with L = 151 cm and v = 343 m/s, we have:

f1 = 343/(4 x 151/100) = 571 Hz

The frequency of the first overtone (second harmonic) is:

f2 = 2f1 = 2 x 571 = 1142 Hz

The frequency of the second overtone (third harmonic) is:

f3 = 3f1 = 3 x 571 = 1713 Hz

The frequency of the third overtone (fourth harmonic) is:

f4 = 4f1 = 4 x 571 = 2284 Hz

For an open-end pipe, the fundamental frequency is given by:

f1 = v/2L

where L is the length of the pipe.

For an open-end pipe with L = 151 cm and v = 343 m/s, we have:

f1 = 343/(2 x 151/100) = 1136 Hz

The frequency of the first overtone (second harmonic) is:

f2 = 2f1 = 2 x 1136 = 2272 Hz

The frequency of the second overtone (third harmonic) is:

f3 = 3f1 = 3 x 1136 = 3408 Hz

The frequency of the third overtone (fourth harmonic) is:

f4 = 4f1 = 4 x 1136 = 4544 Hz

Therefore, for a closed-end pipe with a length of 151 cm, the fundamental frequency is 571 Hz, and the first three overtones are 1142 Hz, 1713 Hz, and 2284 Hz.

For an open-end pipe with a length of 151 cm, the fundamental frequency is 1136 Hz, and the first three overtones are 2272 Hz, 3408 Hz, and 4544 Hz.

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B) energy. An important underlying feature of hydraulic devices is the conservation of energy.

This is achieved through the transfer of energy from one point to another using a pressurized fluid, usually oil or water. The fluid is used to transmit force, and the conservation of energy ensures that the force applied at one end of the system is transferred to the other end without any loss of energy. This makes hydraulic devices highly efficient and effective for a wide range of applications, from construction machinery to aerospace engineering. Liquid fluid power is used by hydraulic machines to do operations. Heavy-duty construction vehicles are a typical illustration. Hydraulic fluid is pumped to numerous hydraulic motors and hydraulic cylinders located all around the machine in this type of machine and is pressurised in accordance with the resistance present.

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According to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

option B is the correct answer.

Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.

In other words, an object will maintain its state of motion (whether it is at rest or moving in a straight line at a constant speed) unless a force acts upon it.

Thus, according to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

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Answer:

its B

Explanation:

Answer: I think it's C.

Explanation:2D is only one side and 3D has length width and height

Answer:

3d

Explanation:

Answer:

Chemical energy is energy stored in the bonds of atoms and molecules. ...

Mechanical energy is energy stored in objects by tension. ...

Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together. ...

Gravitational energy is energy stored in an object's height.

Answer:

Nuclear power

Electricity

Mechanic

Gravity

Explanation:

If a cannonball of mass 25 kg is fired straight up at an initial velocity of 8 m / s, the maximum height it can reach is 3.27 m

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Distance

u = 8 m / s

a = - 9.8 m / s²

At maximum height,

v = 0

Using the equation from equations of motion,

0 = 8² + ( 2 * - 9.8 * s )

19.6 s = 64

s = 3.27 m

Therefore, the maximum height it can reach is 3.27 m

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Answer:

The answer of this question is

Explanation:

1.5 kg mass moving at 8.5 m/s (N).

The soil loss in  \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01  \(Mg m^{-3}\)  is option a. 0.202 Mg/ha.

For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.

Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.

Using the formula:

Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)

Substituting the values:

Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha

Calculating the result:

Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)

Therefore, the correct answer is option a. 0.202 Mg/ha.

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Answer:

17.3 miles

Explanation:

Answer:

the output rating that should the pump motor have is 83.30 Watt

Explanation:

Given that

The pump lift 20 kg of water per minute having a height of 25.50 m

We need to find out the output rating that should the pump motor have

As we know that

power = energy ÷  time

=  m g h ÷ t  

=   20.0 × 9.8 × 25.50 ÷ 60  

=  83.30 Watts

Hence, the output rating that should the pump motor have is 83.30 Watt

The simplest equation that describes the horizontal component of the velocity with a trebuchet will be  v cos (theta)

If the velocity of any object makes an angle theta with the horizontal , then

cos (theta ) = base / hypotenuse

base = horizontal component

hypotenuse = direction of object = velocity

cos (theta ) = horizontal component / v

horizontal component = v cos (theta)

The simplest equation that describes the horizontal component of the velocity with a trebuchet will be  v cos (theta)

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The uncertainty in the emitted wavelength is approximately: 0.013 nm.

The mean lifetime of an electronically excited state in a molecule is 5 ns. If this state emits at 500 nm, calculate the uncertainty in the emitted wavelength.

The uncertainty in the emitted wavelength can be calculated using the relation given below,Δλ = h/(4πmc)τ
Here, Δλ is the uncertainty in the emitted wavelength is Planck’s constant
m is the mass of an electron
c is the speed of light in vacuum
t is the lifetime of the excited state

Therefore, substituting the given values we have,Δλ = (6.626 × 10^-34)/(4π × 9.1 × 10^-31 × 3 × 10^8 × 5 × 10^-9)≈ 0.013 nm (approximately)

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Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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