Write an equation for the nth term of the arithmetic sequence.
17, 12, 7, 2, ...
an=

The grand mean of the process mean of the samples taken  by  the workers is 12.072

The mean is the numerical average of a set of two or more numbers. The equation for calculating the mean is by adding up the numbers in a set and dividing by the entire amount of numbers within the set. A mean makes a difference in you evaluate a set of numbers by telling you the average, making a difference to contextualize each information point. Here the grand mean will be the average mean of the total means obtained from the samples.

SIince we are given the means obtained by the workers which are 12.08, 12.07, 12.07, 12.07, and 12.07.

So considering  T to  be the grand mean and number of observations are 5,

So,

T =12.08 +12.07+ 12.07 +12.07+ 12.07/5

 =  12.072

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Answer:

Step-by-step explanation:

35: 1, 5, 7, 35

125: 1, 5, 25, 125

GCF: 5

Answer:

.

Step-by-step explanation:

Answer:

Rectangle

Step-by-step explanation:

You graph them. From Point A to Point B it's rise 2 run 6 just like Point C to Point D. From Point D to Point A it's rise 3 run -1 just like Point C to Point B

To find graph this, you need to understand the equation.

The formula is y=mx+b, m being slope and b being y-intercept.

We start out graphing by finding where the y-intercept is--and we see that our intercept is 2. Place a point on (0, 2).

Now, we need to add our slope. Start at (0, 2) and go up 4 units. Next go to the LEFT (we have a negative slope, remember?). Continue this pattern.

It should look like this once it's done:

Answer:

To find graph this, you need to understand the equation.

The formula is y=mx+b, m being slope and b being y-intercept.

Step-by-step explanation:

Answer:

Puede ser Asi:

\( {10}^{6} = 1000000\)

Tambien puede ser:

\(1000000 \div 10 = 100000\)

Answer:

The constant of proportionality for the table will be: k=6

Thus, the equation becomes

\(y=kx\)

Step-by-step explanation:

The constant of proportionality, k, is the constant value of the ratio of two proportional quantities y and x.

We know the equation

\(y=kx\)

where k is the constant of proportionality.

Looking at the graph,

at x=7, the value of y=42

so the ratio of y/x = 42/7 = 6

at x=14, the value of y=84

so the ratio of y/x = 84/14 = 6

at x=21, the value of y=126

so the ratio of y/x = 126/21 = 6

at x=28, the value of y=168

so the ratio of y/x = 168/28 = 6

We observe that the ratio of y/x remains constant which y/x=6

so using the equation

\(y=kx\)

take any point let say (7, 42)

42 = k(7)

42/7=k

6 = k

Therefore, the constant of proportionality for the table will be: k=6

Thus, the equation becomes

\(y=kx\)

\(y=6x\)

Answer:

21

Step-by-step explanation:

subtract 9 on both sides to make your x axis by itself

y=mx+b

since -3y and -63 will cancel out each other and make a positive when you divide

-3y /63

y=21

also your when the x is alone it is always 1

rise

-------

run

The value of the variables are y = 2 and x = 1

From the information given, we have that;

y= 6x-11

-2x-3y =-7

Using the substitution method, we have;

Substitute the value of y in equation (2)

-2x - 3(6x - 11) = -7

expand the bracket

-2x - 18x + 33 = -7

collect the like terms

-20x = -7 - 33

subtract the values

-20x = -40

Make 'x' the subject

x = 2

Substitute the values of x in equation 1

y = 6(2) - 11

expand the bracket

y = 12 - 11

y = 1

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Step-by-step explanation:

Your question isn't complete.

But if you are asking for finding the value of variable then, you should follow these things

x+2=6

x+2-2=6-2

x=4

Hence, positive number is cancelled

x-3=1

x-3+3=1+3

x=1

Hence, negative number is cancelled

3x=6

3x/3=6/3

x=2

Hence, the number in product form is cancelled

y÷3=1

y÷3×3=1×3

y=3

Hence, the number in divide form is cancelled

Answer:

2 x 3.14 = 6.28

6.28 divided by 3 = 2.093 around 2.1

The estimated area of the circle is then: Estimated area = 0.7 x 4r²= 2.8r²

To estimate the area of a circle with the center at origin and radius r, there are various methods you can use.

One of them is Monte Carlo Integration.

Monte Carlo Integration is a numerical technique used to calculate an estimate of an area by performing a probability simulation. In this case, the simulation involves generating a random sample of points within the circle, and then counting the number of points that lie within it.

Here is a simple method for using Monte Carlo Integration to estimate the area of a circle with center at origin and radius r:

Step 1: Create a square of side length 2r centered at the origin, with vertices (r, r), (r, -r), (-r, r), and (-r, -r). This square completely encloses the circle.

Step 2: Generate a large number of random points within the square, using a uniform distribution. For example, you could use a computer program to generate 10,000 random points with x and y coordinates between -r and r.

Step 3: Count the number of points that lie within the circle. To do this, you can use the Pythagorean theorem to check if each point is inside or outside the circle. If a point has coordinates (x, y), then it lies within the circle if x^2 + y^2 ≤ r^2.

Step 4: Estimate the area of the circle by multiplying the proportion of points that lie within the circle by the area of the square. The proportion of points that lie within the circle is equal to the number of points within the circle divided by the total number of points generated.

The area of the square is 4r^2.

The estimated area of the circle is then:

Estimated area = Proportion of points in circle x Area of square

= Number of points in circle / Total number of points x 4r²

For example, if 7,000 of the 10,000 random points lie within the circle, then the proportion of points within the circle is 0.7.

The estimated area of the circle is then:

Estimated area = 0.7 x 4r²

= 2.8r²

This method is easy to use, and it becomes more accurate as the number of random points generated increases.

For best results, you should generate at least 10,000 points.

The estimated area may not be precise like the known formula, but the result would be quite close to the actual area of the circle.

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Answer:

A is 5

B is 3

C is 2

D is 4

E is 3

F is 5

Answer:

( 3, 7)

Step-by-step explanation:

x= 3 Y = 7. The origin is (0, 0)

Answer:

\({ \tt{ {x}^{6} - \frac{x}{4y} }} \\ = { \tt{ {( - 4)}^{6} - \frac{ - 4}{4(4)} }} \\ \\ { \tt{ = 4096 + 4}} \\ \\ = 4100\)

The value of the equation ( x⁶ - x ) / 4y = 1025/4 when x = -4 and y = 4

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

A = ( x⁶ - x ) / 4y   be equation (1)

The value of x = -4

The value of y = 4

Substituting the values of x and y in equation (1) , we get

A = ( ( -4 )⁶ - ( -4 ) ) / ( 4 x 4 )

On simplifying the equation , we get

A = ( 4096 + 4 ) / 16

A = 4100 / 16

A = 1025 / 4

Therefore , the value of A is 1025/4

Hence , the value of the equation is 1025/4

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Answer:

there are no numbers....

9514 1404 393

Explanation:

General information

All of these questions have to do with various translations of the square root function. The first problem deals with the basic function. Other problems translate the graph in various ways.

The basic square root function has its vertex at (0, 0) and is defined for x-values (domain) that are 0 or positive. The resulting y-values (range) are also zero or positive.

The basic function intercepts the x- and y-axes only at the point (0, 0), so both intercepts are 0. Unless the function is reflected vertically or horizontally, its minimum will be at the left end of any interval, and its maximum will be at the right end.

The transformation of a function g(x) to f(x) = g(x -a) +b causes it to be translated 'a' units to the right and 'b' units up. For the functions here, that means the vertex is translated from (0, 0) to (a, b). For the functions here, the vertex values are the limits of the domain and range, so those will be altered accordingly.

Problems

1.

a) The graph is shown in the attachment as f1 (orange).

b) vertex: (0, 0); domain: [0, ∞); range: [0, ∞)

c) x-intercept: 0; y-intercept: 0

d) On the interval [1, 4], the minimum is √1 = 1, and the maximum is √4 = 2.

__

2.

a) The graph is shown in the attachment as f2 (green). The basic function is translated left 1 and down 2.

b) vertex: (-1, -2); domain: [-1, ∞); range: [-2, ∞)

c) x-intercept: 3; y-intercept: -1 (read from the graph)

d) On the interval, [0.5, 5], the minimum is √1.5 -2 ≈ -0.78; the maximum is √6 -2 ≈ 0.45. Min and max values are shown in the table in the second attachment.

__

3.

a) The graph is shown in the attachment as f3 (purple). The basic function is translated up 3.

b) vertex: (0, 3); domain: [0, ∞); range: [3, ∞)

c) x-intercept: (none); y-intercept: 3 (the vertex)

d) On the interval, [2, 4], the minimum is √2 +3 ≈ 4.41; the maximum is √4 +3 ≈ 5. Min and max values are shown in the table in the third attachment.

__

4.

a) The graph is shown in the attachment as f4 (red). The leading multiplier of -2 causes the graph to be reflected over the x-axis and vertically expanded by a factor of 2 before being translated right 2 and up 3.

b) vertex: (2, 3); domain: [2, ∞); range: (-∞, 3]. Note the range is all y-values less than or equal to 3 because of the vertical reflection.

c) x-intercept: 4.25; y-intercept: (none). The x-intercept is found by solving ...

  0 = -2√(x -2) +3

  (-3/-2)² = x-2

  2 +2.25 = x = 4.25

d) On the interval, [4, 7], the minimum is -2√(7 -2)+3 = 3-2√5 ≈ -1.47; the maximum is -2√(4-2)+3 = 3-2√2 ≈ 0.17. Min and max values are shown in the table in the second attachment.

Using the P-value method of testing hypotheses with a significance level of 0.05, the sample provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

To test the claim that the mean score of job applicants from the university is greater than 160, we will perform a one-sample t-test using the P-value method. The null hypothesis (H0) assumes that the mean score is equal to 160, while the alternative hypothesis (Ha) assumes that the mean score is greater than 160.

First, we calculate the test statistic, which is the t-value. The formula for the t-value is:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

Plugging in the given values, we have:

t = (183 - 160) / (12 /   √(25))

  = 23 / (12 / 5)

  = 23 * (5 / 12)

  ≈ 9.58

Next, we find the P-value associated with the test statistic. The P-value represents the probability of obtaining a test statistic as extreme as the observed value, assuming the null hypothesis is true. Since the alternative hypothesis is one-sided (greater than 160), we calculate the P-value by finding the probability of the t-distribution with 24 degrees of freedom being greater than the calculated t-value.

Consulting statistical tables or using software, we find that the P-value is very small (less than 0.0001).

Since the P-value (less than 0.0001) is less than the significance level (0.05), we reject the null hypothesis. This provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

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Answer:

y=5x-13

Step-by-step explanation:

1. (3,2) = x,y

2. substitute each x and y digit into y=mx+b format

3. 2=5(3)+b

4. solve for 2=5(3)+b which equals b=-13

5. ANSWER IS SOLVED WHEN ANSWERED IN y=mx+b FORMAT

5. y=5x-13

Answer:

3/4 +3/4 =

as a mixed number=

Answer:

A regular pentagon

Step-by-step explanation:

A pentagon has 5 sides. There are 5 tick marks.

The answer polygon is a Hexagon.

A hexagon is a six-sided polygon. Hexagon has some special properties when we are talking about inscribed polygons.

Two vertices of the hexagon lie on the corners of the diameter of the circumscribing circle.

Given that, Stella is using her compass and straightedge to complete the construction of a polygon inscribed in a circle.

We are asked which polygon is she in the process of constructing.

Since, there are 6 marks on the circle, which is one of the step for constructing a hexagon.

So, We can say that she is constructing a regular hexagon inside the circle.

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Answer:

x<13

Step-by-step explanation:

x < 13 is the solution of the inequality; 6x + 11 > 7x - 2

A relationship between two expressions or values that are not equal to each other is called 'inequality'.

Given that, an inequality 6x + 11 > 7x - 2

On solving for x, we get,

6x + 11 > 7x - 2

6x + 11 +2 > 7x

13 > x

x < 13

Hence, x < 13 is the solution of the inequality; 6x + 11 > 7x - 2

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The correct statements about omitted variable bias are:

1. If the omitted variable and included variable are correlated, there is a bias.

2. If the omitted variable is relevant, there is a bias.

Omitted variable bias refers to the bias introduced in an econometric model when a relevant variable is left out of the analysis. The bias occurs when the omitted variable is correlated with both the dependent variable and the included variables in the model.

If the omitted variable and included variable are correlated, there is a bias because the included variable may capture some of the effects of the omitted variable. In this case, the estimated coefficient of the included variable will be biased, as it will include the influence of the omitted variable.

Similarly, if the omitted variable is relevant, there is a bias because it has a direct impact on the dependent variable. By excluding the relevant variable, the model fails to account for its influence, leading to biased estimates of the coefficients of the included variables.

Random assignment of included variables does not eliminate omitted variable bias. While random assignment may help control for confounding factors and reduce bias in certain experimental designs, it does not address the issue of omitting a relevant variable from the analysis. Omitted variable bias can still exist even with random assignment of included variables.

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The probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 11/12

To calculate the probability of rolling two fair six-sided dice and getting a sum of 4 or higher, we first need to calculate the total number of possible outcomes.

The number of possible outcomes when rolling two dice is 6 × 6 = 36, since each die has 6 possible outcomes.

Now, let's find the number of outcomes that result in a sum of 4 or higher. We can do this by listing all the possible outcomes:

Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes

Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes

Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes

Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes

Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes

Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes

Sum of 10: (4, 6), (5, 5), (6, 4) = 3 outcomes

Sum of 11: (5, 6), (6, 5) = 2 outcomes

Sum of 12: (6, 6) = 1 outcome

Therefore, the number of outcomes that result in a sum of 4 or higher is 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 33.

Therefore, the probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 33/36 = 11/12.

To find the probability of getting a sum of 44 or higher, we need to subtract the probability of getting a sum of 43 or lower from 1:

Sum of 2: (1, 1) = 1 outcome

Sum of 3: (1, 2), (2, 1) = 2 outcomes

Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes

Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes

Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes

Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes

Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes

Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes

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