write a balanced chemical equation for the reaction between a metal carbonate mco3 and hydrochloric acid (hcl) and m2co3 and hcl.

1 mole of So2 is produced in the formation of 1 mole of I2.

Oxidation and reduction is based on the addition or removal of oxygen or hydrogen atoms.so in the terms of oxygen and hydrogen the oxidation and reduction can be defined. The addition of oxygen to substances is called oxidation or the removal of hydrogen from a substance is also called oxidation. similarly, addition of hydrogen to a substance is called reduction or the removal of oxygen from a substance is called reduction.

Here in the process of oxidizing i- to i2,so42- is reduced to so2.so the required reaction becomes,

      2I-(aq) +So42- (aq) +4H+ --> I2(s) +So2(g) +2H2O

From the reaction it can be seen that 1 mole of So2 is produced in the formation of 1 mole of I2 .

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Answer:

See explanation

Explanation:

The number of electrons in each principal energy shell increases as the number of shells increases because more electronic orbitals become available to accommodate the electrons.

For instance, the n= 2 level only accommodates eight electrons in the s and p orbitals whereas the n=3 level accommodates 18 electrons in s, p and d orbitals respectively.

Each principal level accommodates 2n^2 electrons where n= the principal energy shell.

The increase in the number of shell leads to increase in the number of electrons.

The number of electrons in each principal energy shell increase as the number of the shell increases because each cell can accommodate 8 electrons except the first shell which has only 2 electrons. The number of electrons increases when we go down the group due to addition of new shells.

The atom added new shells in the atom if the existing shells fill with electrons and no place is available for the remaining electrons so we can conclude that the increase in the number of shell leads to increase in the number of electrons.

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A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, a reaction occured between ammonia gas and oxygen gas to produce nitrogen gas and water.

Based on the equation, 4 moles of ammonia requires 3 moles of oxygen gas to react.

This means that 3.53 moles of ammonia will require 3.53 × ¾ = 2.65 moles of oxygen gas.

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D. Able to answer for one's conduct and obligations

The amygdala is a pair of almond-shaped structures located in the brain's temporal lobes. It is part of the limbic system, which is involved in the processing of emotions and memory. The amygdala is involved in the formation of memories associated with emotional events, as well as the reaction to those memories.

The amygdala also plays a role in the regulation of the body's fight-or-flight response, which is the autonomic nervous system's response to danger or perceived danger. It is thought to be involved in the formation of fears and phobias, as well as the development of aggressive behaviors. In addition, the amygdala is believed to be involved in the processing of social cues, such as facial expressions and body language.

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The experimental molarity of HCl will be skewed, causing the observed reaction to potentially be less intense or slower than it would have been at the original molarity.

In order to address your question about how the experimental molarity of HCl will be skewed when a student adds deionized water to the Erlenmeyer flask, consider the following:

1. The student has an initial molarity (concentration) of HCl in the Erlenmeyer flask.
2. By adding deionized water to the flask, the student increases the total volume of the solution.
3. Molarity is defined as the number of moles of solute (in this case, HCl) per liter of solution.

When the volume of the solution increases due to the addition of deionized water, the molarity (concentration) of HCl will decrease. This is because the number of moles of HCl remains the same, but the total volume of the solution has increased.

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Answer:

1. Cl2 becoming Cl–

2. Yes, it does because hydrogen (H) undergoes reduction and silver (Ag) undergoes oxidation.

3. a covalent compound

4. an object that produces electrical energy through redox reactions

Explanation:

I actually got a %100 even though I guessed!

Oxidation implies electron gain while reduction implies electron loss.

Reduction is a process by which a chemical specie gains electrons. We can tell that reduction has occurred when there is a decrease in oxidation number. This is clearly shown in the transformation; Cl2 becoming Cl–. The oxidation number of chlorine decreased from 0 to -1.

The equation; 2Ag(s) + H2S(g) → Ag2S(s) + H2(g) represents a redox reaction because the oxidation number of silver increased from zero to +1 while the oxidation number of hydrogen decreased from +1 to zero. Hence silver was oxidized and hydrogen was reduced.

The product forms when two or more nonmetal atoms share valence electrons,  is a covalent compound. Covalent compounds are formed by sharing of electrons between atoms.

A galvanic cell produces electrical energy through redox reactions.

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3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I.

When 3C⁻⁻ is reacted with HI, the reaction product obtained is I⁻⁻⁻ as the main product. The C₂H₅I and H⁻ are not produced in significant quantities and cannot be considered the main product.The 3C⁻⁻ compound reacts with HI in the presence of a solvent to produce hydrogen gas, H⁻, C₂H₅I, and I⁻⁻⁻. The primary product obtained is I⁻⁻⁻ because it is stable and has a higher energy than C₂H₅I and H⁻.However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions. The reaction must be carried out in anhydrous conditions and at a low temperature so that the reaction proceeds in the desired direction.

3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I. However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions.

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The addition of NaOH will shift the equilibrium to the left, while the addition of HCl will shift the equilibrium to the right. The direction of the shift depends on the reactants added and their reaction with the components of the equilibrium.

If NaOH is added to the solution, it will react with HNO2 to form the conjugate base NO2^- and water. This will increase the concentration of NO2^- and decrease the concentration of HNO2, causing the equilibrium to shift towards the left to restore equilibrium.

As a result, there will be a decrease in the concentration of H3O+ ions and an increase in the concentration of NO2^- ions.

On the other hand, if HCl is added to the solution, it will react with the conjugate base NO2^- to form HNO2 and chloride ions. This will increase the concentration of HNO2 and decrease the concentration of NO2^-, causing the equilibrium to shift towards the right to restore equilibrium.

As a result, there will be an increase in the concentration of H3O+ ions and a decrease in the concentration of NO2^- ions.

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Answer:

In simple terms, the endothermic reactions absorb energy from the surrounding that is in the form of heat. On the other hand, an exothermic reaction releases energy into the surrounding of the system.

The Li 2CO 3, lithium carbonate, an inorganic chemical, is the lithium salt of carbonic acid.

Thus,The processing of metal oxides makes extensive use of this white salt. Due to its effectiveness in treating mood disorders, notably bipolar disorder, it is listed on the WHO's list of essential medicines and lithium carbonate,

Another crucial industrial chemical is lithium carbonate. Its primary function is as an ingredient in the substances used to create lithium-ion batteries.

Lithium carbonate glasses work well for ovenware. Ceramic glazes that are fired at low and high temperatures frequently contain lithium carbonate. When mixed with silica and other minerals, it produces low-melting fluxes.

Thus, The Li 2CO 3, lithium carbonate, an inorganic chemical, is the lithium salt of carbonic acid.

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Answer:

your answer gonna be 20 miles

Answer:

a. moles divide by volume

Explanation:

Molarity, denoted by symbol M, refers to the molar concentration of a solution. It is calculated using the formula as follows:

Molarity = number of moles of a solute ÷ volume of the solvent

Since, number of moles (n) has the unit: moles and volume (V) has the standard unit: Litres, then the unit for molarity is moles/litre or M.

A solution is prepared by dissolving 1.0 g of NaOH in a total of 250 mL of solution. Then 10.0 mL of this solution is withdrawn and added to 90.0 mL of water. The pH of the final solution is 11. Here option D is the correct answer.

To determine the pH of the final solution, we need to calculate the concentration of hydroxide ions (OH-) first.

1.0 g of NaOH is dissolved in a total volume of 250 mL of solution, which is equivalent to 0.004 moles of NaOH (since the molar mass of NaOH is 40.0 g/mol). Therefore, the concentration of NaOH in the original solution is:

c(NaOH) = 0.004 moles / 0.250 L

= 0.016 M

When 10.0 mL of this solution is added to 90.0 mL of water, the resulting concentration of NaOH is diluted by a factor of 10. Therefore, the concentration of NaOH in the final solution is:

c(NaOH) = 0.016 M / 10

= 0.0016 M

Since NaOH is a strong base, it completely dissociates in water to form one mole of hydroxide ions (OH-) for every mole of NaOH. Therefore, the concentration of hydroxide ions in the final solution is also 0.0016 M.

To calculate the pH of the solution, we use the following equation:

pH = 14 - pOH

Since the concentration of hydroxide ions is 0.0016 M, the pOH is:

pOH = -log[OH-]

= -log(0.0016)

= 2.80

Therefore, the pH of the solution is:

pH = 14 - pOH

= 14 - 2.80

= 11.20

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The correct statements are that a rock is considered an ore when it contains at least one metallic mineral in sufficient amounts to be extracted profitably and when it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably.

Step-by-step explanation:

When it occurs in sufficient amounts to be used to build roads and buildings: This statement is incorrect. Rocks that are used for construction purposes, such as limestone or sandstone, are not considered ores unless they also contain economically valuable minerals.

Only when it contains lead: This statement is incorrect. Ores are not limited to containing only lead. Ores can contain various metallic minerals, not just lead.

When it contains at least one metallic mineral in sufficient amounts to be extracted profitably: This statement is correct. Ores are rocks that contain valuable metallic minerals in concentrations that make extraction economically feasible. These minerals can include gold, silver, copper, aluminum, zinc, and many others.

Only when it contains iron: This statement is incorrect. While iron ores are commonly known and widely used, ores are not limited to containing only iron. There are numerous other metallic minerals that can be extracted profitably from rocks.

When it contains fluorite or sulfur minerals in sufficient amounts to be extracted profitably: This statement is correct. Fluorite and sulfur are examples of non-metallic minerals that can be extracted profitably from rocks, and if a rock contains these minerals in sufficient quantities, it can be considered an ore.

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Answer:

Chromium, calcium, and osmium

Explanation:

These elements are metals, considering this, these elements electron shells(orbitals) are further away from the nucleus, with this, their attractions are not as strong as non-metals, so some of their electrons are able to move freely.

When you accumulate many atoms, these metals can form a "sea of electrons"  because they all have loose electrons interacting with each other. This allows easy conduction of heat and electricity.

Answer:

Chromium

Calcium

Osmium

Explanation:

The elements likely conduct electricity well are chromium, calcium and osmium. As these are metals and are observed to be good conductors of heat and electricity. They have extra electrons to donate and hence flow of electrons cause them to be a good conductor of electricity. Rest iodine is a non-metals which is not good conductors of electricity. Carbon is not itself a good conductor but one of its allotrope which is graphite is a good conductor of electricity.

In the reaction PCl3 + Cl2 → PCl5, the rate of disappearance of each reactant is related to the rate of appearance of the product.

You can express this relationship using the following equation:

Rate = - (1/1) * (d[PCl3]/dt) = - (1/1) * (d[Cl2]/dt) = (1/1) * (d[PCl5]/dt)

Here, d[PCl3]/dt, d[Cl2]/dt, and d[PCl5]/dt represent the rate of change of concentrations of PCl3, Cl2, and PCl5, respectively. The negative signs for the reactants indicate their concentrations are decreasing, while the positive sign for the product indicates its concentration is increasing. The coefficients (1/1) account for the stoichiometry of the reaction.

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Answer:

Q1: Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Q2: Mass is how much stuff something is made of. Volume is how much space an object takes up.

Answer:

it would increase to twice what it was

Let's see that the STP represents the conditions for the temperature of 0°C (273 K) and for the pressure of 1 atm.

We have this initial data and a volume of 3.20 x 10 ^(2) mL. To solve this problem, we need to use the ideal gas formula:

where T is temperature, P is pressure, and V volume. Subindex 1 is the initial data and subindex 2 is the final data.

We want to find the final volume, so clearing for V2 in the formula, we're going to obtain:

And the final step is replacing the data that we have, where the final data is 425.0 K and 3.50 atm (remember that the volume must be in liters, 1 liter is 1000 mL, so 3.20 x 10^2 mL is 0.32 L):

The answer is that the new volume of the sample of helium would be 0.14 L.

To determine the number of moles of the gaseous organic compound, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

First, we need to convert the density to mass per volume. The density of the gas is given as 340g/L. Therefore, the mass of 1 L of the gas is 340 g.

Next, we need to use the ideal gas law to calculate the number of moles. We know that the pressure is 1.7 atm, the temperature is 45°C (which is 318 K), and the volume can be calculated using the density and the molar mass of the compound. The molar mass can be determined from the molecular formula of the compound.

Assuming the compound is a hydrocarbon, we can use an average molar mass of 28. Thus, the volume of 1 mole of the gas can be calculated as follows:

V = (molar mass/density) × 1000 ml/L = (28/340) × 1000 = 82.35 ml/mol

Using the ideal gas law equation and plugging in the given values, we get:

n = (PV) / (RT) = (1.7 atm × 82.35 ml) / (0.0821 L atm/mol K ×318 K) = 0.839 mol

Therefore, the number of moles of the gaseous organic compound is 0.839 mol

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Explanation:

The composition of the gases never changes until the mesosphere and the thermosphere. -carbon dioxide, oxygen, and methane are only found in the troposphere. -Permanent gases stay the same until you reach the thermosphere.

Answer herbert

Explanation:

cause he did not do any of the safety precautions and he was prob not listening to the teacher  

Answer:

it's a chemical Element

Explanation:

symbol He

atomic number 2.

The mass of the cell wall, assuming the cell is spherical and the wall is a thin spherical shell, is approximately 0.91 milligrams.

To calculate the mass of the cell wall, we first need to determine the volume of the wall.

The given diameter of the cell is 0.00 μm, which means the radius (r) of the cell is half of that, so r = 0.00/2 = 0.00 μm = 0.00 nm.Now, we need to find the volume of the cell wall, which can be approximated as a thin spherical shell. The volume of a thin spherical shell can be calculated using the formula:

V = 4/3 * π * (r_outer^3 - r_inner^3)

Since the cell is spherical, the inner radius of the shell is the same as the radius of the cell (r), and the outer radius of the shell is the sum of the radius of the cell (r) and the thickness of the wall (60.0 nm). Thus, the outer radius (r_outer) of the shell is:

r_outer = r + thickness = 0.00 + 60.0 = 60.0 nm

Substituting the values into the formula, we have:

V = 4/3 * π * (60.0^3 - 0.00^3)

= 4/3 * π * (216,000 nm^3)

= 288,000 π nm^3

Next, we need to calculate the mass of the cell wall using the density of pure water. The density (ρ) is given as 1000 kg/m^3, which is equivalent to 1000 kg/1,000,000,000 nm^3 since 1 m = 1,000,000,000 nm. Thus, the mass (m) of the cell wall is:

m = ρ * V

= 1000 kg/1,000,000,000 nm^3 * 288,000 π nm^3

= 0.000288 π kg

Now, we can calculate the mass of the cell wall by substituting the value of π (pi) as 3.14159:

m = 0.000288 * 3.14159 kg

= 0.000905 kg

≈ 0.91 mg

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Answer:

Stem

Explanation:

Answer:

option-(d) stem

Explanation:

Stems have four main functions which are: Support for and the elevation of leaves, flowers and fruits. The stems keep the leaves in the light and provide a place for the plant to keep its flowers and fruits. Transport of fluids between the roots and the shoots in the xylem and phloem...

I hope it help you

Answer:

the correct answer is D) a decrease in decrease in temperature

have a good day! :)

Explanation:

The factor that decreases the rate of solution is a decrease in temperature. Details about rate of a solution can be found below.

A solution is a homogeneous mixture, which may be liquid, gas or solid, formed by dissolving one or more substances.

The rate at which a solution moves can be affected by the following:

This means that the factor that decreases the rate of solution is a decrease in temperature.

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a)The IUPAC name for the compound (CH3CH2)3CCH2CH2CH(CH3)2 is 2,2,3-trimethylpentane.

b) The IUPAC name for the compound (CH3)2CHC(CH3)2CH2CH2CH3 is 3,3-dimethyl-2-methylbutane.

a) The compound (CH3CH2)3CCH2CH2CH(CH3)2 is named 2,2,3-trimethylpentane. The name is derived by identifying the longest continuous carbon chain, which is five carbons in this case.

The substituents are then listed in alphabetical order, preceded by their respective position on the main chain. The compound contains a tert-butyl group [(CH3)3C-] attached to the second carbon atom, and a methyl group (CH3) attached to the fourth carbon atom.

The presence of the three ethyl groups [CH2CH3] on the third carbon and two methyl groups [CH3] on the fifth carbon is indicated by the prefix "trimethyl" and "pentane" signifies the parent alkane with five carbon atoms.

b) The compound (CH3)2CHC(CH3)2CH2CH2CH3 is named 3,3-dimethyl-2-methylbutane. The name is determined by identifying the longest continuous carbon chain, which is six carbons in this case.

The substituents are then listed in alphabetical order, preceded by their respective position on the main chain. The compound contains two methyl groups (CH3) attached to the third carbon atom, denoted as "3,3-dimethyl."

Additionally, there is a methyl group (CH3) attached to the second carbon atom and an ethyl group (CH2CH3) attached to the fourth carbon atom. The name "2-methylbutane" indicates the parent alkane with four carbon atoms, bearing the methyl group on the second carbon atom.

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