WORTH 40 POINTS HELLPPPP
What class of element is Astatine (At)?

Answer:

The sky looks different in each nighttime section of the artifact because the artifact sections represent different seasons. ... Different constellations are visible on different nights throughout the year because of the earth's orbit. The Earth orbits around the sun. A full orbit is 365 days or one year.

Explanation:

2) The heat capacity of aluminum is 219.44 J/mol.°C.

3) a) the experimental ΔHs of ice is -0.154 kJ/mol.

b) too high

Calculate the heat released by the aluminum:

q = mcΔT

where q = heat released, m = mass of aluminum, c = specific heat capacity of water and ΔT = change in temperature.

q = (24.7 g) (0.903 J/g°C) (100.0°C - 23.4°C)

q = 18643.26 J

Next, calculate the heat absorbed by the calorimeter:

q = mcΔT

q = (99.5 g + 24.7 g) (15.8 J/°C) (23.4°C - 19.5°C)

q = 4009.92 J

The heat released by the aluminum is equal to the heat absorbed by the calorimeter and water:

18643.26 J = 4009.92 J + q3

where q3 = heat absorbed by the water.

q3 = 14633.34 J

Calculate the molar heat capacity of aluminum:

Cp,m = q3 / (nΔT)

where Cp,m = molar heat capacity, n = number of moles of aluminum, and ΔT = change in temperature.

n = m / M

where m = mass of aluminum and M = molar mass of aluminum (26.98 g/mol).

n = 24.7 g / 26.98 g/mol

n = 0.916 mol

Cp,m = 14633.34 J / (0.916 mol * 76.6°C)

Cp,m = 219.44 J/mol.°C

Therefore, the heat capacity of aluminum is 219.44 J/mol.°C.

3) (a) To calculate the experimental ΔHs of ice, we first need to calculate the heat gained by the water and the heat lost by the ice during the process.

Heat gained by water = mass of water × specific heat capacity of water × change in temperature

= 100.0 g × 4.184 J/g·°C × (-20.1°C)

= -8,423.84 J

Heat lost by ice = mass of ice × heat of fusion of ice

= 25.6 g × 6.01 kJ/mol

= 154.496 J

Since the process is assumed to be adiabatic (no heat exchange with the surroundings), the heat gained by the water must be equal to the heat lost by the ice.

Thus, -8,423.84 J = 154.496 J = -8,269.344 J

The negative sign indicates that the process is exothermic. Therefore, the experimental ΔHs of ice is:

ΔHs = -154.496 J/mol = -0.154 kJ/mol

(b) If the student forgets to include the calorimeter term in the calculation, the calculated ΔHs of ice will be too high. This is because the heat absorbed by the calorimeter during the process is not accounted for, leading to an overestimation of the heat gained by the water and underestimation of the heat lost by the ice.

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Answer:

nothing

Explanation:

Answer:

The traditional vision of the role science should play in policy making is of a two stage process of scientists first finding out the facts, and then policy makers making a decision about what to do about them.

Explanation:

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The frequency of gamma radiation is calculated to be = 1.11 *10^20 Hz.

A gamma radiation is also known as gamma ray. It is a penetrating form of electromagnetic radiation arising from radioactive decay of atomic nuclei. It consists of shortest wavelength electromagnetic waves, even shorter than X-rays.

Gamma rays can pass through the human body completely and as they pass through, they cause ionizations that damage tissue and DNA.

As we know that E= hf

Hence, f= E/h

Given E=  6.96 x 10-14 J

And, Planck's constant, h = 6.626 *10^-34 m² kg/s

f = 6.96 * 10^-14J  +/6.626 *10^-34

f = 1.11 *10^20 Hz

Hence, frequency of gamma radiation = 1.11 *10^20 Hz.

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Answer: 380 J. Please mark

Explanation:

Answer:

0.36 mol/L

Explanation:

The formula for molarity M=m/L

m stands for moles

L stands for liters

Plug it into the equation...

M=1.25 mol/3.5 L

M=0.35714285714

ANSWER

The molar mass of Fluticasone is 443.995 g/mol

EXPLANATION:

Given below is the molecular formula for Fluticasone

To find the molar mass of the above molecular formula, we need to find the molar mass of the individual element first

According to the periodic table, the molar mass of the following elements is given below as

Carbon (C) = 12 g/mol

Hydrogen (H) = 1 g/mol

Fluorine (F) = 18.99 g/mol

Oxygen (O) = 15.99 g/mol

Sulfur (S) = 32.065 g/mol

Since we have forgotten the molar mass of each element, then, we can now find the molar mass of the compound below

Answer:

strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.

Explanation:

In liquids, the attractive intermolecular forces are strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.

Intermolecular forces are the forces of repulsion or attraction.

Intermolecular forces lie between atoms, molecules, or ions. Intramolecular forces are strong in comparison to these forces.

In liquids, the attractive intermolecular forces are strong enough to hold

molecules relatively close together but not strong enough to keep

molecules from moving past each other.

Liquid is a state of matter in which the atoms are relatively close to each

other but less than that of solids which are densely and tightly packed.

The intermolecular force in liquids are strong enough to hold them together

which makes them less easily compressible but not strong enough to keep

them from moving or gliding past each other because they aren't tightly

packed.

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The compound name for the compound structure given in the question is 2, 3-dimethlypentane

The international union of pure and applied chemistry (IUPAC) has organised a principle by which organic compounds are named. This principle includes:

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Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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The chemical formula of aspartame is C₁₄H₁₈N₂O₅ and it's relative molecular mass is 294.30 g/mol which is calculated as (12×14)+(1×18)+(14×2)+(16×5).

Molecular  mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molecular mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molar mass and formula mass are used as synonym for the molecular mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molecular masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.In case of aspartame it is calculated as,(12×14)+(1×18)+(14×2)+(16×5)=294.30 g/mol.

Thus , relative molecular mass or molecular mass of aspartame is 294.30 g/mol.

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To solve this question, we need to follow 2 steps:

Step 1 - Transform atoms into moles, using the avogadro's constant: 6.02214086 × 10^23 mol^-1

Step 2 - Transform moles into grams, using the molar mass of the compound and the following formula: mass = moles x molar mass

a) Here we have 4.25 x 10^24 atoms of nitrogen - N.

Step 1:

6.02214086 × 10^23 atoms ---- 1 mol

4.25 x 10^24 atoms of nitrogen ---- x moles of nitrogen

6.02214086 × 10^23 x = 4.25 x 10^24

x = 4.25 x 10^24/6.02214086 × 10^23

x = 7.06 moles of nitrogen

Step 2:

The molar mass of nitrogen is 14 g/mol.

Moles = 7.06

mass of nitrogen = 7.06 x 14

mass of nitrogen = 98.8 g

Answer a) mass of nitrogen = 98.8 g

b) We follow the same steps. Here we have 1.75 x 10^23 atoms of Pb.

Step 1:

6.02214086 × 10^23 atoms ---- 1 mol

1.75 x 10^23 atoms of Pb---- x moles of Pb

6.02214086 × 10^23 x = 1.75 x 10^23

x = 1.75 x 10^23 /6.02214086 × 10^23

x = 0.291 atoms of Pb

Step 2:

The molar mass of Pb is 207.2 g/mol.

moles = 0.291

mass of Pb = 0.291 x 207.2

mass of Pb = 60.2 g

Answer: b) mass of Pb = 60.2 g

c) Here we have 8.45 x 10^23 molecules of CH4.

Step 1:

6.02214086 × 10^23 molecules --- 1 mol

8.45 x 10^23 molecules of CH4---- x moles of CH4

6.02214086 × 10^23 x = 8.45 x 10^23

x = 8.45 x 10^23 /6.02214086 × 10^23

x = 1.403 moles of CH4

Step 2:

The molar mass of C is 12 g/mol and of H is 1 g/mol. We need to calculate the molar mass of CH4:

(1x12) + (4x1) = 16 g/mol

moles = 1.403 moles of CH4

mass of CH4 = 1.403 x 16

mass of CH4 = 22.5 g

Answer: c) mass of CH4 = 22.5 g

The coordinates of point W are (xW, yW), where xW = (x1 + x2) / 2 and yW = (y1 + y2) / 2.

Theorem 8.6 states that if a quadrilateral is a parallelogram, then its diagonals bisect each other. In the given quadrilateral STUV, the diagonals intersect at point W. Therefore, according to Theorem 8.6, point W is the midpoint of the diagonals TV and SU.To find the coordinate of W, we need to determine the midpoint of the line segments TV and SU. The midpoint of a line segment is the average of the coordinates of its endpoints.Let's assume the coordinates of point T are (x1, y1), the coordinates of point V are (x2, y2), the coordinates of point S are (x3, y3), and the coordinates of point U are (x4, y4).

To find the coordinates of point W, we can use the midpoint formula:

xW = (xT + xV) / 2

yW = (yT + yV) / 2

Substituting the coordinates, we have:

xW = (x1 + x2) / 2

yW = (y1 + y2) / 2

Using this formula, we can calculate the coordinates of point W by plugging in the specific values for the coordinates of points T and V.

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Answer:

Clear quartz-

Jasper-

Amethyst-

Explanation:

Rock Salt The elements in rock salt are not integrated into the salt's crystal grid, but cling to the outside surface and crevices of the crystalline structure. This is the fundamental difference between rock salt and crystal salt. A salt crystal manifests a superior structure.

If a teacher showed an animal to students on a field trip. The  tool will allow the students to best see the animal up close is the hand lens.

Option D is correct.

A hand lens is known as a magnifying glass  which is a convex lens that is used to produce a magnified image of an object. The lens is usually mounted in a frame with a handle.

A hand lens  has two essential properties which are its focal length and its diameter.

The students will therefore require a hand lens to look up the animal close.

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#complete question:

A teacher showed this animal to students on a field trip. Which tool will allow the students to best see the animal up close? O A Tape measure O B Graduated cylinder O c. Notebook O D. Hand lens

Answer:

no, and next time take it right

Explanation:

Answer:

ok

Explanation:

Answer: The Ka expression for an aqueous solution of hypochlorous acid is \(K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}\).

Explanation:

The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.

\(HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}\)

When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.

Hence, the expression for acid dissociation constant of this reaction is as follows.

\(K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}\)

Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is \(K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}\).

Answer:

98

Explanation:

Based on the reaction:

NaOH + H2SO4 → NaHSO4 + H2O

Where 1 mole of the base (NaOH) reacts per mole of the acid (H2SO4)

The formula of equivalent weight is:

Equivalent weight = Molecular mass / Number of equivalent moles

Where Molecular mass of sulfuric acid is 98g/mol

And number of equivalent moles = 1 -Because 1 mole of acid reacts per mole of base

Equivalent weight is:

98 / 1 =

98

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Water has three states of matter namely gas, solid or ice form and liquid. Molecules in solid state are not able to move since they are tightly packed.

Molecules can move in liquid state and they moves easily in gaseous state.

Every substance have three states, that are gas, liquid and solid. In solid state, molecules are tightly packed and are unable to move apart. In liquid state, molecules have some space to move and motion of liquid is easy.

The movement of molecules in a substance depends on the space allotted for them or called the volume. More volume between molecules, easy to move apart.

Gaseous state is composed of molecules located far apart from each other and they diffuse easily. Therefore, motion in three states of water is different and moves faster in gaseous state.

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The statement that corresponds to an alpha particle is a helium nucleus, with an atomic number of 2 and an atomic mass of 4.

Alpha particle is a positively charged nucleus of a helium-4 atom (consisting of two protons and two neutrons), emitted as a consequence of radioactivity.

The alpha(α) particle has a symbol of 4/2He; suggesting that the atomic number is 2 and the atomic mass is 4.

Therefore, the statement that corresponds to an alpha particle is a helium nucleus, with an atomic number of 2 and an atomic mass of 4.

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A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

We want to calculate the mass of CaCO₃ in a 1.60 g supplement. We need to consider the following relationships.

\(1.60gSup \times \frac{37.8gCa}{100gSup} \times \frac{1molCa}{40.08gCa} \times \frac{1molCaCO_3}{1molCa} \times \frac{100.09gCaCO_3}{1molCaCO_3} = 1.51gCaCO_3\)

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

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A 1.60 g calcium supplement contains 37.8% Ca by mass. The calcium is present in the supplement as CaCO₃(s) (molar mass 100.09 g/mol). How many grams of CaCO₃(s) are in the calcium supplement?

Answer:

The answer is

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

Reduce the fraction with 10,000

We have the final answer as

Hope this helps you

Answer:

2 CM/year just now got 100 Edge.

Explanation:

Answer:

3...... 1L = 1000ml

4. 1000g = 1 kg

Explanation:

mark me as brainliest ❤️

Answer:

Sunlight is used to break water down into oxygen and hydrogen.

I did think about the statements of climate change as a result of the scientific course.

Science lectures frequently discuss the value of both natural and manufactured resources. where the change in the climate may be a shared factor. The phenomena of climate change is brought on by the planet's rapid increase in temperature.

The goal of the science seminar is to instill in young children a spirit of scientific inquiry and analytical thinking. Each State and Union Territory holds a competition for the science seminar. The National Council of Science Museum, Kolkata, selects a topic each year.

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