On a television game show, contestants earn 5 points for each correct answer, but lose 2 points for each wrong answer. On last week's show, the winning contestant earned 80 points and answered 30 questions.

Given that x represents the number of questions answered correctly, and y represents the number of questions answered incorrectly, determine which system of equations correctly represents this situation.
A. 5x-2y=30
x+y=80
B. 5x-2y+80
x+y=30
C. 5x+2y=80
x-y=30
D. 5x+2y=30
x+y=80

Answer:

see below

Step-by-step explanation:

n > 3

Since there is no equals sign, there is an open circle at 3

N is greater so the line goes to the right

Answer:

r p q

Step-by-step explanation:

The tangents of the acute angles in the right triangle gives:

tan(G) = 2

tan(H) = 1/2

It should be noted that tangent is the ratio of opposite over adjacent. Thus:

tan(angle) = opposite/adjacent

So for reference angle G, we say,

tan(G) = JH/GJ = 2/1 = 2

We'll treat tan(H) in a similar fashion, but the opposite and adjacent sides swap roles. That means we'll apply the reciprocal to the result above to get 1/2 for tan(H)

So we have this interesting property where

tan(G)*tan(H) = 2*(1/2) = 1

In general,

tan(A)*tan(B) = 1 if and only if A + B = 90 degrees

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Answer: 54.2241

Step-by-step explanation:

You multiply 9.513 by 5.3 which gives you an answer of 54.2241. (Hope this helped)

Answer:

24

Step-by-step explanation:

The formula for area of any triangle is (length * width) * 1/2. This makes the angle of 90 degrees irrelevant.

6 x 8 = 48

48 / 2 = 24

Answer:

I believe the answer is A

Answer:

A is your answer I think

Step-by-step explanation:

maybe wait for someone else to answer as well haha

Given that cos (0) = 0, we can use the Pythagorean identity sin^2(x) + cos^2(x) = 1 to find the value of sin (0).

sin^2(0) + cos^2(0) = 1

sin^2(0) = 1 - cos^2(0)

sin^2(0) = 1 - 0^2

sin^2(0) = 1

So, sin (0) = sqrt(sin^2(0)) = sqrt (1) = 1.

However, the given value is sin (0) = v3/6. This means that sin (0) = sqrt (3)/2, which is the value of sin (60). Therefore, the correct value of sin (0) is sqrt (3)/2, not 1.

trigonometry, the branch of mathematics deal with specific functions of angles and their application to calculations. There is total six functions of an angle commonly used in trigonometry.

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As given that Material A has a higher thermal conductivity than Material B, the material that will transfer energy by conduction faster is the Material A because it is a good thermal conductor.

A thermal conductivity means the rate at which heat is transferred by conduction through a unit of a material when a temperature gradient exits perpendicular to the area.

By having a high thermal conductivity means that the material can effectively transfer heat and readily take up heat from their environment. An example of these materials are copper and aluminum.

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A)
i) the inequality to show the number of ballons that the dance committee can buy is: 0.80b + 65 ≤ 125

ii)  solving the inequality above, we arrive at b ≤ 75
B) The graph is attached accordingly.

C) See the description of the solution below.

Let's start by defining our variables. Let b be the number of balloons that the dance committee could buy.

The cost of b balloons is $0.80b. We want to make sure that the cost of the balloons plus the amount already spent on decorations ($65) is less than or equal to the budget of $125. So we can write the following inequality:

0.80b + 65 ≤ 125

Now we can solve for b:

0.80b + 65 ≤ 125

0.80b ≤ 125 - 65

0.80b ≤ 60

b ≤ 75

Therefore, the dance committee can buy up to 75 balloons to stay within their budget.

To graph the solution set, we can plot b on the horizontal axis and shade the region to the left of b = 75, since b must be less than or equal to 75.

The solution set represents all possible values of b that satisfy the inequality. In this case, the solution set is b ≤ 75, which means that the dance committee can buy up to 75 balloons and still stay within their budget.

As the number of balloons increases, the cost of the balloons also increases, and the amount of money left in the budget decreases.

Therefore, the more balloons the dance committee buys, the less money they will have left for other decorations or expenses.

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Full Question:


Since the above question is incomplete, it appears you are referring to the question below.


The dance committee has a budget of $125 to decorate the gym for a spring dance. They already spent $65. Some members want to buy helium balloons that cost $0.80 each.

A) Write and solve an inequality to show the number of balloons that the dance committee could buy.

B) Graph the solution set for the inequality.
C) Describe what the solution means and how the number of balloons affects the amount in the budget.

Si Verónica, Ana y Luis están pintando una barda y se les paga un total de 300 unidades monetarias (por ejemplo, dólares, pesos, etc.), para determinar cuánto dinero debería recibir cada uno, necesitamos más información sobre cómo se distribuye el trabajo entre ellos.

Si los tres contribuyen de manera equitativa y realizan la misma cantidad de trabajo, podrían dividir el pago de manera igualitaria. En ese caso, cada uno recibiría 100 unidades monetarias (300 dividido entre 3).

Sin embargo, si uno de ellos realiza más trabajo o tiene una mayor responsabilidad en la tarea, podría ser justo que reciba una porción mayor del pago. En ese caso, la distribución de los 300 unidades monetarias dependerá de un acuerdo previo entre ellos sobre cómo se divide el pago en función de la cantidad o calidad del trabajo realizado.

Es importante tener en cuenta que la asignación exacta de dinero puede variar dependiendo de las circunstancias y el acuerdo al que lleguen Verónica, Ana y Luis.

Answer:

\(BC=5.1\)

\(B=23^{\circ}\)

\(C=116^{\circ}\)

Step-by-step explanation:

The diagram shows triangle ABC, with two side measures and the included angle.

To find the measure of the third side, we can use the Law of Cosines.

\(\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}\)

In this case, A is the angle, and BC is the side opposite angle A, so:

\(BC^2=AB^2+AC^2-2(AB)(AC) \cos A\)

Substitute the given side lengths and angle in the formula, and solve for BC:

\(BC^2=7^2+3^2-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-42\cos 41^{\circ}\)

\(BC^2=58-42\cos 41^{\circ}\)

\(BC=\sqrt{58-42\cos 41^{\circ}}\)

\(BC=5.12856682...\)

\(BC=5.1\; \sf (nearest\;tenth)\)

Now we have the length of all three sides of the triangle and one of the interior angles, we can use the Law of Sines to find the measures of angles B and C.

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c} $\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

In this case, side BC is opposite angle A, side AC is opposite angle B, and side AB is opposite angle C. Therefore:

\(\dfrac{\sin A}{BC}=\dfrac{\sin B}{AC}=\dfrac{\sin C}{AB}\)

Substitute the values of the sides and angle A into the formula and solve for the remaining angles.

\(\dfrac{\sin 41^{\circ}}{5.12856682...}=\dfrac{\sin B}{3}=\dfrac{\sin C}{7}\)

Therefore:

\(\dfrac{\sin B}{3}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin B=\dfrac{3\sin 41^{\circ}}{5.12856682...}\)

\(B=\sin^{-1}\left(\dfrac{3\sin 41^{\circ}}{5.12856682...}\right)\)

\(B=22.5672442...^{\circ}\)

\(B=23^{\circ}\)

From the diagram, we can see that angle C is obtuse (it measures more than 90° but less than 180°). Therefore, we need to use sin(180° - C):

\(\dfrac{\sin (180^{\circ}-C)}{7}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin (180^{\circ}-C)=\dfrac{7\sin 41^{\circ}}{5.12856682...}\)

\(180^{\circ}-C=\sin^{-1}\left(\dfrac{7\sin 41^{\circ}}{5.12856682...}\right)\)

\(180^{\circ}-C=63.5672442...^{\circ}\)

\(C=180^{\circ}-63.5672442...^{\circ}\)

\(C=116.432755...^{\circ}\)

\(C=116^{\circ}\)

\(\hrulefill\)

Additional notes:

I have used the exact measure of side BC in my calculations for angles B and C. However, the results will be the same (when rounded to the nearest degree), if you use the rounded measure of BC in your angle calculations.

Answer:

-9/11

Step-by-step explanation:

slope is change in y/change in x

change in y is 9 (12-3)

change in x is -11 (-17--8)

slope is -9/11

Answer:

The exponential function is

\(y = {2}^{x} \)

The integers that -3.425 lie between are -3 and -4.

The rational numbers  that -3.425 lie between to the nearest tenth are -3.4 and -3.5.

The rational numbers  that -3.425 lie between to the nearest hundredth are -3.42 and -3.43.

Integers are numbers without decimals and fractions. They are whole numbers. Integers can either be positive, negative or zero. Examples of integers are -5 and 10.

A rational number is a number that can be expressed as a fraction of two integers. Examples of rational numbers are 1/4, -2/3  

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Answer: y

Step-by-step explanation:

For this, you would just add everything and then tag a y on the end.

3y-10y=-7y

-7y+y= -6y (y is the same thing as 1y)

-6y+7y= 1y which is just y

It is important to understand that you can only do this with like terms. So for example if you were asked to simplify:

5x+2x+3y+5y

the answer would be 7x+8y (you cannot combine x and y)

Hope this helps :)

Answer: y

Step-by-step explanation: I personally like to combine all the +y values first, which is equal to 11y. And then I minus 10y.

Answer:

1) 2+3*4= 14

2) (2+3)(4)= 20

3) -10

4) -5

5) -5

Step-by-step explanation:

Answer: 5/2

Step-by-step explanation:

slope equation: (y2-y1)/(x2-x1)

13-3/5-1 = 10/4 or 5/2

Answer:

2.5

Step-by-step explanation:

Gradient (slope) =

\(m = \frac{y2 - y1}{x2 - x1} = \frac{13 - 3}{5 - 1} = \frac{10}{4} = 2 \frac{1}{2} \)

The value of R(A) = 4, N(AT ) = 3, R(AT ) = 4, and N (A) = 3.

Given that

Dimension of matrix  = 7×5

Rank of matrix = 4

The range space of A,

Which is a subspace of R, is known as R(A).

It is made up of all conceivable linear combinations of A's columns.

The dimension of R(A) =  rank of A,

Which is 4 in this case.

The null space of the transpose of A,

Which is also a subspace of R, is designated as N(AT).

All potential answers to the equation ATx = 0,

Where x is a R column vector, are included in it.

N(AT) has a dimension = nullity of A,

which in this case is 3 in this example.

The range space of the transposition of A, is designated as R(AT).

The rows of A are arranged in all conceivable linear configurations.

The rank of A = 4

Thus it equal to dimension of R(AT).

N(A) is the null space of A.

Axe = 0, where x is a column vector in R, are included in it.

The nullity of AT, which is three, is likewise equivalent to the dimension of N(A).

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Answer:

Step-by-step explanation:

360² + y² = 369²

y² = 369² - 360² = 136,161 - 129,600 = 6,561

y = 81

360² + z² = 1640²

z² = 1640² - 360² = 2,689,600 - 129,600 = 2,560,000

z = 1600

Answer:

Sorry but this makes no scine sorry

Answer:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

0.00885... < 0.01

The test statistic of 46 is significant

There is sufficient evidence to reject H₀ and accept H₁

Air bags are more effective as protection than safety belts

Step-by-step explanation:

821 crashes

46 hospitalisations where car has air bags

7.8% or 0.078 probability of hospitalisations in cars with automatic safety belts

α = 0.01 or 1% ← level of significance

One-tailed test

We are testing whether hospitalisations in cars with air bags are less likely than in a car with automatic safety belts;

The likelihood of hospitalisation in a car with automatic safety belts, we are told, is 7.8% or 0.078;

So we are testing if hospitalisations in cars with air bags is less than 0.078;

So, firstly:

Let X be the continuous random variable, the number of hospitalisations from a car crash with equipped air bags

X~B(821, 0.078)

Null hypothesis (H₀): p = 0.078

Alternative hypothesis (H₁): p < 0.078

According to the information, we reject H₀ if:

P(X ≤ 46 | X~B(821, 0.078)) < 0.01

To find P(X ≤ 46) or equally P(X < 47), it could be quite long-winded to do manually for this particular scenario;

If you are interested, the manual process involves using the formula for every value of x up to and including 46, i.e. x = 0, x = 1, x = 2, etc. until x = 46, the formula is:

\(P(X = r) = nCr * p^{r} * (1 - p)^{n - r}\)

You can find binomial distribution calculators online, where you input n (i.e. the number of trials or 821 in this case), probability (i.e. 0.078) and the test statistic (i.e. 46), it does it all for you, which gives:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

Now, we need to consider if the condition for rejecting H₀ is met and recognise that:

0.00885... < 0.01

There is sufficient evidence to reject H₀ and accept H₁.

To explain what this means:

The test statistic of 46 is significant according to the 1% significance level, meaning the likelihood that only 46 hospitalisations are seen in car crashes with air bags in the car as compared to the expected number in car crashes with automatic safety belts is very unlikely, less than 1%, to be simply down to chance;

In other words, there is 99%+ probability that the lower number of hospitalisations in car crashes with air bags is due to some reason, such as air bags being more effective as a protective implement than the safety belts in car crashes.

Answer:linear binomial

Step-by-step explanation:

Answer:

B) Linear binomial.

Step-by-step explanation:

????

Answer:

0.292 rad/s

Step-by-step explanation:

\(b=\text{Distance of rocket from your feet}=20\ \text{ft}\)

\(\dfrac{dp}{dt}=\text{Rate of change of height}=19\ \text{ft/s}\)

\(p=\text{Distance of the rocket from the ground}=30\ \text{ft}\)

Finding distance between the feet and when the rocket is 30 ft in the air

\(d=\sqrt{b^2+p^2}\\\Rightarrow d=\sqrt{20^2+30^2}\\\Rightarrow d=36.1\ \text{ft}\)

\(\tan\theta=\dfrac{p}{b}=\dfrac{p}{20}\)

Differentiating with respect to time

\(\sec^2\theta\dfrac{d\theta}{dt}=\dfrac{1}{20}\dfrac{dp}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{\cos^2\theta}{20}\dfrac{dp}{dt}\)

\(\cos\theta=\dfrac{b}{h}\\\Rightarrow \cos\theta=\dfrac{20}{36.1}\\\Rightarrow \cos^2\theta=\dfrac{20^2}{36.1^2}\)

\(\dfrac{d\theta}{dt}=\dfrac{\dfrac{20^2}{36.1^2}}{20}\times 19\\\Rightarrow \dfrac{d\theta}{dt}=0.292\ \text{rad/s}\)

Rate of change of the angle is 0.292 rad/s.

The Nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

To determine the time the flag is in the air before Zack catches it, we can use the kinematic equation for vertical motion:

h = 16t^2 + vt + s

Where:

h is the height of the flag,

t is the time in seconds,

v is the initial vertical velocity of the flag,

s is the initial height of the flag.

In this case, the flag is thrown into the air from a height of 5 feet (s = 5) with an initial vertical velocity of 30 feet per second (v = 30). Zack catches it at a height of 7 feet (h = 7).

We can rewrite the equation as:

7 = 16t^2 + 30t + 5

To find the time (t) when the flag is at a height of 7 feet, we can rearrange the equation and solve for t. However, since this is a quadratic equation, we can also use the quadratic formula.

The quadratic equation in this case is:

16t^2 + 30t + 5 - 7 = 0

16t^2 + 30t - 2 = 0

Now, we can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Applying the values from the quadratic equation, we have:

t = (-30 ± √(30^2 - 4 * 16 * (-2))) / (2 * 16)

Simplifying further:

t = (-30 ± √(900 + 128)) / 32

t = (-30 ± √1028) / 32

Using a calculator, we find two solutions:

t ≈ -1.08 seconds or t ≈ 0.06 seconds

Since time cannot be negative in this context, we discard the negative solution.

Therefore, to the nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

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Answer: search

Step-by-step explanation: look up the question on your browser and the answer will pop up

Answer: -24

Step-by-step explanation: negative times a negative is a positive times a negative is a negative

The possible perimeters are 140 feet, 148 feet and 160 feet.

In order to determine the width that would be used to determine the possible perimeters, the formula for the area would have to be rewritten.

A rectangle is a 2-dimensional quadrilateral with four right angles and two diagonals that bisect each other at right angles.

Area of a rectangle = length x width

Width = area / length

1200 / 40 = 30 feet

1200 / 50 = 24 feet

1200 / 60 = 20 feet

Perimeter of a rectangle = 2 x (length + width)

Perimeter when width is 30 feet : 2(40 + 30) = 140 feet

Perimeter when width is 24 feet : 2(24 + 50) = 148 feet

Perimeter when width is 20 feet : 2 (20 + 60) = 160 feet

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The line which is on the same plane can be parallel, two lines are never parallel when they are in different planes, so option C is correct.

An object having an endless length and no width, depth, or curvature is called a line. Since lines can exist in two, three, or higher-dimensional environments, they are one-dimensional things.

Given:

The given planes are A and B,

A new line, p, is drawn parallel to line l,

Line l in the diagram is located on plane A. Line p must be drawn on plane A in order to be parallel to line l. As a result, line p, which is located on plane B, will be perpendicular to line n and parallel to lines l and n.

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The image of the remaining question is attached below.