With increase of temperature the viscocity in general of

Answer:

I think it is O only nonliving

Answer:16

Explanation:

as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is

Given: i=10A,B=0.15 T,θ=45

∘

and l=2 m

Force on a current carrying wire of finite length =

F

=l(

i

×

B

)

Hence, magnitude of force, F=Bilsinθ

=0.15×10×2×sin45

∘

=

2

3

N

\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)

\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)

\(\\ \bull\tt\dashrightarrow 534\times 10^1\)

\(\\ \bull\tt\dashrightarrow 534\times 10\)

\(\\ \bull\tt\dashrightarrow 5340\)

The magnitude of the force that the truck exerts on the car is same as the horizontal force exerted by the car on the truck that is 1600 N.

In physics, a force is a force that can change the motion of an object. A force can change the velocity of an object with mass. Pressure can also be intuitively described as pushing or pulling. A force has both a value and a displacement, making it a vector quantity.

Squeeze is pushing and pulling, which affects daily life because people without strength cannot open and close objects, lift arms and legs.

Reason :

This question is a simple application of Newton's third law, which states that if an object A exerts a force on an object B, then B must exert a force on A that is equal in magnitude but opposite in direction.

The car pushes against the ground with a force of 1600 N, so therefore the ground must exert a force on the car, also of 1600 N.

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Answer:

The time is \(t = 500 \ s\)

Explanation:

From the question we are told that

  The distance of the sun from the earth is \(d = 1.5 *10^{11} \ m\)

   The speed of light is  \(c =3.0 *0^{8} \ m/s\)

Generally the time it would take is  

        \(t = \frac{d}{v}\)

=>     \(t = \frac{1.5*10^{11}}{3.0*10^{8}}\)

=>      \(t = 500 \ s\)

The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.

The apple weighs m = 0.37 kg.

The apple's speed when it approaches the earth's surface is 9.8 meters per second.

Earth's mass, M, is 5.98 × 1024 kg.

Using Newton's Second Law of Motion, we may now:

The strength of the force exerted by Earth on the apple is,

F = ma

⇒ F = 0.37 × 9.8

⇒ F = 3.626 N

We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.

Therefore, the force exerted by the apple on Earth will be of the following magnitude:

F = 3.626 N

Let "A" be the acceleration of the earth relative to the apple in m/s2.

Thus,

The following will be used to determine how quickly the earth is moving toward the apple:

F = MA

⇒ 3.626 = [5.98 × 10²⁴] × A

⇒ A = 3.626 / [5.98 × 10²⁴]

⇒ A = 0.606 × 10⁻²⁴

⇒ A = 6.06 × 10⁻²⁵ m/s²

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Answer:

A. the wavelength of light is reflected by what it is hitting and directed back into the eye.

Explanation:

Tire inflation should be checked when the tires are cold.

Tire inflation can be defined as a phenomenon in which the amount of air pressure (compressed air) in the tire of an automobile vehicle is greater than the recommended (standard) amount of air pressure that is required by the manufacturer, in order to enhance safety.

This ultimately implies that, tire inflation is a measure of the total amount of air pressure (compressed air) in the tire of an automobile vehicle as recommended by the manufacturer of the vehicle.

Additionally, proper tire inflation enhances safety and it can greatly influence gasoline mileage of an automobile vehicle. However, it is only appropriate to check tire inflation when the tire is cold.

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Endothermic reactions are chemical processes that generate products by absorbing heat energy from the environment around the reactants.

One of the greatest illustrations of an exothermic reaction is the exploding of a firecracker, which emits a loud bang along with light and heat. Lighting a candle is an ongoing process in which the wax serves as fuel and sustainably produces a flame.

Exothermic reactions are those that release heat energy through chemical processes. C(g)+O2(g)+CO2(g)+Heat Energy is an example. Endothermic reactions are the ones that involve the absorption of heat energy. For instance, CaO+CO2Heat CaCO3.

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Part: a

First let's represent each vector on a grid.

When we combine vectors visually, we connect the tip (arrow side) of one vector to the tail (non-arrow side) of the other. The vector is then drawn from the beginning point to the final position.The graphical representation of the sum of vectors \($\vec{A}$\)and \($\vec{B}$\) is:[See attachment]

Part: b

The graphical representation \($\vec{A}-\vec{B}$\) is:  [See attachment]

What is Vectors?

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Answer:

The power exerted by the student is 51.2 W

Explanation:

Given;

extension of the elastic band, x = 0.8 m

time taken to stretch this distance, t = 0.5 seconds

the spring constant, k = 40 N/m

Apply Hook's law;

F = kx

where;

F is the force applied to the elastic band

k is the spring constant

x is the extension of the elastic band

F = 40 x 0.8

F = 32 N

The power exerted by the student is calculated as;

P = Fv

where;

F is the applied force

v is velocity = d/t

P = F x (d/t)

P = 32 x (0.8 /0.5)

P = 32 x 1.6

P = 51.2 W

Therefore, the power exerted by the student is 51.2 W

Convert into each other and both are energy are 2 similarities between potential energy and kinetic energy .

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.

Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.

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The volume density of atoms in a simple cubic crystal is 2.92 × 1021 atoms per cubic centimeter.

The lattice constant (a) of a simple cubic (SC) crystal is 0.7 nm. One atom is present at each lattice point. We have to compute the volume density of atoms (i.e. the number of atoms per unit volume) in terms of atoms per cubic centimeter.1 nm = 10-7 cm ⇒ 0.7 nm = 0.7 × 10-7 cm = 7 × 10-8 cm.

Volume of the unit cell of a SC crystal is given byV = a3= (0.7 × 10-7 cm)3= 3.43 × 10-22 cm3The unit cell has one atom, so the volume density of atoms is the same as the number of atoms per unit cell, which is1/ V = 1 / (3.43 × 10-22 cm3)= 2.92 × 1021 atoms per cubic centimeter.= 2.92 × 1023 atoms per cubic meter= 2.92 × 10-4 atoms per cubic angstrom.

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The spring constant of the spring is 20.78 N/m and the velocity of the cart when the cart is first located at x=8.47 cm is -0.082 m/s.

a) To find the spring constant of the spring, we can use the equation for the displacement of a mass undergoing simple harmonic motion on a spring.

x = A cos(ωt)

where x = displacement of the mass from its equilibrium position,

          A = amplitude of the motion, and

          ω = angular frequency of the motion.

Comparing this equation with the given equation, we can see that the amplitude of the motion is A = 12.4 cm = 0.124 m and the angular frequency is ω = 6.35 rad/s.

The equation for the displacement of a mass on a spring undergoing simple harmonic motion can also be written as:

\(x=\sqrt{m/k} *cos\omega t\)

where m = mass of the object, and

            k = spring constant.

Comparing this equation with the given equation, we can see that  = \(\sqrt{m/k}\) = 0.124 m.

Squaring both sides,

m/k = (0.124 m)² = 0.0154

Therefore, the spring constant of the spring is:

k = m / 0.0154

  = (0.32)/(0.0154)

  = 20.78 N/m

b) To find the velocity of the cart when it is first located at x = 8.47 cm, we need to take the derivative of the displacement equation w.r.t. time:

v = dx/dt

 = d{A cos(ωt)}/dt

 = -Aω sin(ωt)

Substituting the given values, we get:

v = -(0.124 m) * (6.35 rad/s) * sin(6.35t)

When the cart is located at x = 8.47 cm = 0.0847 m, using x = A cos(ωt):

0.0847 m = (0.124 m) * cos(6.35t)

cos(6.35t) = 0.6835

Taking the inverse cosine of both sides gives:

6.35t = 0.824 rad

      t = 0.130 s

Substituting this value of t into the velocity equation gives:

v = -(0.124 m) * (6.35 rad/s) * sin(6.35 * 0.130 s) = -0.082 m/s

Therefore, the velocity of the cart when it is first located at x = 8.47 cm is -0.082 m/s, that is in the negative direction.

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Answer:

Reduction of order delivery times.

More efficient order fulfilment.

Lower number of incomplete orders.

Improved service in emergency situations.

Reduction of errors in the composition of orders and deliveries.

Better management of internal quality levels.

Greater flexibility (wider range of services on offer to the client)

Explanation:

a class b network needs to be subnetted such that it supports 100 subnets and 100 hosts/subnet. which of the following answers list a workable combination for the number of network, subnet, and host bits

A Class B network has a default subnet mask of 255.255.0.0 and provides 16 bits for the network portion and 16 bits for the host portion. To support 100 subnets and 100 hosts/subnet, we need to borrow some of the host bits for subnetting.

To determine the number of bits needed for the subnet portion, we can use the formula:

\(2^{n}\)> = number of subnets

where n is the number of subnet bits. Solving for n, we get:

n = ceil(log2(number of subnets))

For 100 subnets, we need at least 7 subnet bits:

n = ceil(log2(100)) = ceil(6.643) = 7

To determine the number of bits needed for the host portion, we can use the formula:

\(2^{n}\) >= number of hosts per subnet - 2

where n is the number of host bits. We subtract 2 from the number of hosts per subnet because the first and last IP addresses in each subnet are reserved (network address and broadcast address).

For 100 hosts per subnet, we need at least 7 host bits:

n = ceil(log2(100 - 2)) = ceil(log2(98)) = ceil(6.624) = 7

So, the minimum number of bits we need for subnetting and host addressing is 7 bits each.

We can use the remaining 2 bits for the network portion, giving us a total of 9 network bits (16 - 7).

Therefore, a workable combination would be:

9 network bits

7 subnet bits

7 host bits

This would give us a total of 512 (\(2^{9}\)) network addresses, 128 (\(2^{7}\)) subnets per network, and 126 (2^7A Class B network has a default subnet mask of 255.255.0.0 and provides 16 bits for the network portion and 16 bits for the host portion. To support 100 subnets and 100 hosts/subnet, we need to borrow some of the host bits for subnetting.

To determine the number of bits needed for the subnet portion, we can use the formula:

\(2^{n}\) >= number of subnets

where n is the number of subnet bits. Solving for n, we get:

n = ceil(log2(number of subnets))

For 100 subnets, we need at least 7 subnet bits:

n = ceil(log2(100)) = ceil(6.643) = 7

To determine the number of bits needed for the host portion, we can use the formula:

\(2^{n}\) >= number of hosts per subnet - 2

where n is the number of host bits. We subtract 2 from the number of hosts per subnet because the first and last IP addresses in each subnet are reserved (network address and broadcast address).

For 100 hosts per subnet, we need at least 7 host bits:

n = ceil(log2(100 - 2)) = ceil(log2(98)) = ceil(6.624) = 7

So, the minimum number of bits we need for subnetting and host addressing is 7 bits each.

We can use the remaining 2 bits for the network portion, giving us a total of 9 network bits (16 - 7).

Therefore, a workable combination would be:

9 network bits

7 subnet bits

7 host bits

This would give us a total of 512 (\(2^{9}\)) network addresses, 128 (\(2^{7}\)) subnets per network, and 126 (\(2^{7}\)- 2) host addresses per subnet.

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There are many similarities between the earth and the home we live in.

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

Have a building, as well as the tools and components that were utilized to create this house and the soil.

Both home and earth have an environment of their own.

We also reside on both the earth as well as in our homes.

These are the items we have, such as food, drink, and raw materials.

Home and earth are similar because, as we know that the earth is our primary supply of materials for building homes.

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Answer:

False

Explanation:

Answer:

False

Explanation:

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The atmospheric blurring can negatively affect the view of objects and requires a larger separation to distinguish forms. It is caused by turbulent air in motion.

The atmospheric blurring is a natural phenomenon caused by turbulent air in motion, which negatively affects the view of astronomical objects.

The atmospheric blurring may lead to larger percent errors in objects with smaller angular diameters because in these cases it is required a larger separation to distinguish forms.

Smaller angular diameters produce larger squared visibility, thereby increasing the effects of distortion caused by atmospheric blurring.

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Answer:

The time to achieve a grain diameter of 7.3× 10⁻² mm is 477 minutes

Explanation:

We need to first solve for K

Given that:

grain diameter exponent (n) = 2.2

grain diameter (d) = 7.3 × 10⁻² mm = 7.3× 10⁻⁵ m

d₀ =  2.4 × 10⁻² mm =  2.4 × 10⁻⁵ m

t = 500 min

then from k = \(d^{n} -do^{n} /t\)

= 7.48 × 10⁻¹³ m/min

= \(\frac {(7.3 * 10^{-5} )^{2.2}* (2.4*10^{-5} )^{2.2}}{500}\) = 1.44×10⁻¹²

From K we can determine the time required based on the desired diameter

grain diameter (d) =  7.3 × 10⁻² mm = 7.3× 10⁻⁵ m

so t =\(d^{n} -do^{n} /k\)  = \(\frac {(7.3 * 10^{-5} )^{2.2}* (2.4*10^{-5} )^{2.2}}{1.4*10^{-12} }\) =503.08 = 504 min approximately.

Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.

Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.

The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.

The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.

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Never put a weight directly on the balance pan. Always cover it with a piece of weight paper. Never add chemicals to a container or piece of weighing paper while it is on the scale. Never weigh something that is hot or cold.

The amount of matter that makes up every object or body is the greatest way to understand mass. Everything that we can see has mass. Examples of objects with mass include a table, a chair, your bed, a football, a glass, and even air. Whether anything is light or heavy depends on its mass.

Mass is independent of place. Using a formula, can one estimate an object's mass based on its weight.  corresponds to mass dividing weight by gravitational acceleration Determine the weight in pounds that is equivalent in Newtons. The formula used to determine mass based on weight expresses mass in Newtons.

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y axis:NandW and also f x axis:T and F T away from car.

The correct response is A) 7.66 x 108 g/m³ unit. The other possible answers are all incorrect.

The duration it takes sound to travel between two microphones can be measured and recorded using a data logger. They can be relatively close together, unlike the clap-echo method.

For instance, if two microphones are 3.4 meters apart, the average speed would be 3.4 x 0.01 = 340 m/s.7.66 x 107 g/m³ is equal to 76.6 kg/cm³ or 76.6 x 1,000,000 g/m³.

Hence, the correct response is A) 7.66 x 108 g/m³. The other possible answers are all incorrect.

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The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer:

A game of darts is inelastic because the dart and board touch but don't bounce off. All the other options have two objects interacting then parting from eachother

Explanation:

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