Why is ΔSvap of a substance always larger than ΔSfus ?

Answer:

What are you a 6 yo? Anyways, the most common properties are, They are good conductors of electricity, They are lustrous and They are sonorous.

If you draw the table of the Hess law, you can use that table to obtain the enthalpy of reaction

A table called the "Hess's law table" can be created to depict how Hess's law is used. The reactants, intermediates, products, and related enthalpy changes (H) of each reaction that takes place during a chemical reaction are listed in the table.

Hess's law indicates that you can add the enthalpy changes of the separate reactions to get the total reaction's enthalpy change (H). By eliminating common species between neighboring reactions in the table, the overall reaction is achieved.

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• Answer:

m = 3,045.15 g mercur

• Explanation:

Hi there !

density formula

d = m/V =>

=> m = d×V

d(mercury) = 13.534 g/cm3

1ml = 1cm3

V = 225ml = 225cm3

replace

m = 13.534g/cm3×225cm3

m = 3,045.15 g mercur

Good luck !

Answer:

25 PRECENT

Explanation:

If 2.00 tons of coal is burned, then the mass of nitrogen in the form of nox gases, is produced by this combustion is 400134 g of nitrogen.

The chemical reaction equation can be written as

C135H96O9NS + 156O2 ------- 135CO2 + 48H2O + NO + SO2

Mass of 2.0 tons of coal in gram = 1.814 × 10^(6) g

Molar mass of C135H96O9NS can be calculated as = 135(12) + 96(1) + 14 + 32 = 1904 moles of coal

Now, number of moles of coal burned = 1.814 × 10^(6) g / (1906 g/mol) = 952.7 moles of coal

If 1 mole of coal produced 1 mole of NO

Total 952.7 moles of coal produced 952.7 moles of NO

Mass of NO can be calculated as

Mass of NO produced = 952.7 × 30 = 28581 g

1 mole of NO = 30 g of NO

Thus, 14 g of nitrogen is contained in 30 g of NO

Let xg of nitrogen is contained in 28581 g of NO

Then,

x = 14 × 28581 = 400134 g of nitrogen.

If 2.00 tons of coal is burned, then the mass of nitrogen in the form of nox gases, is produced by this combustion is 400134 g of nitrogen.

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Answer:

The flash of green light may give off some type of energy that only emits from green light which probably energizes the Flubber

Explanation:

A flubber is a rubber like polymer that absorbs and amplifies energy. A flubber absorbs energy from a light source and electrons present in it are excited in order to emit light of higher wavelength. The green light absorbed by the flubber to emit longer wavelength of light emitting more energy.

Air would be the most likely candidate for the can with the greatest change in temperature

Recall that the change in the heat capacity would be related to the heat capacity.

Since it has a relatively low specific heat capacity compared to the other options listed (iron filings, water, and sand). However, it's important to note that this is a simplified explanation and there may be other factors at play depending on the specific conditions of the experiment.

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Answer:

33 minutes

Explanation:

60 km/h = 37.28 mi/h

20/37.28 = 0.5364 h

0.5364 * 60 min = 32.2 minutes

Molecules with the molecular formula C6H6Cl6 have one element of unsaturation. This means that the compound contains one double bond, one ring, or a combination of both. The molecular formula C6H6Cl6 represents a compound with six carbon atoms, six hydrogen atoms, and six chlorine atoms.

The degree of unsaturation is a measure of the presence of multiple bonds or rings in a compound. It can be calculated using the formula: Degree of unsaturation = (2C + 2 - H - X + N)/2

Where C is the number of carbon atoms, H is the number of hydrogen atoms, X is the number of halogen atoms (in this case, chlorine atoms), and N is the number of nitrogen atoms.
In the case of C6H6Cl6, the formula becomes: Degree of unsaturation = (2(6) + 2 - 6 - 6 + 0)/2
Degree of unsaturation = (12 + 2 - 6 - 6)/2
Degree of unsaturation = 2/2
Degree of unsaturation = 1

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A contact burn occurs when a child's skin comes into contact with a flame or a hot solid object, such as a stove or curling iron.

This type of burn can result in tissue damage and requires proper care to prevent infection and promote healing. A contact burn is a type of burn that occurs when a child's skin comes into contact with a flame or a hot solid object. This can happen when a child touches a hot stove, grill, or even a candle flame. Contact burns can range from mild to severe depending on the temperature and duration of contact. It is important to immediately cool the burned area with cool water for at least 10-15 minutes and seek medical attention if necessary. Prevention is key in avoiding contact burns, so make sure to keep hot objects out of reach of children and teach them about the dangers of touching hot surfaces.

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Answer:

Calcium, potassium, aluminum, chlorine, bromine

Explanation:

I do not know all of them, but here are some.

Answer:

Refer the attachment for answer..

hope it helps you..

Answer:

it's definitely a oxidation reaction because here the oxygen contained OH group present in yeild

Answer: 1. Crest  2. Trough 3. Wave Length 4. Amplitude

Explanation:

Answer: The final volume in the balloon is \(68.818cm^3\)    

Explanation:

Charles' Law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

\(\text{Volume}\propto \text{Temperature}\)

Or,

\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)   (At constant pressure and number of moles)

\(V_1\) = initial volume = 52000 L

\(V_2\) = final volume = ?

\(T_1\) = initial temperature = \(500^0C=(500+273)K=773 K\)

\(T_2\) =  final temperature = \(750^0C=(750+273)K=1023 K\)

\(\frac{52000}{773}=\frac{V_2}{1023}\)

\(V_2=68818L=68.818ml=68.818cm^3\)       \((1L=1000ml=1000cm^3)\)

Thus final volume in the balloon is \(68.818cm^3\)    

Answer:

so that the can keep reusing it and reusing it instead of wasting materials

Explanation:

you very welcome have a good day

Answer:

c

Explanation:

you took the test on edge

The statement describes the cause for sibling rivalry between both brothers is The younger son expressed feelings about his parents showing favoritism to his older sibling. Hence , Option (C) is correct.

Sibling rivalry is the jealousy, competition and fighting between brothers and sisters.

It is a concern for almost all parents of two or more kids.

Problems often start right after the birth of the second child.

Sibling rivalry usually continues throughout childhood and can be very frustrating and stressful to parents.

Therefore, The statement describes the cause for sibling rivalry between both brothers is The younger son expressed feelings about his parents showing favoritism to his older sibling. Hence , Option (C) is correct.

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The wavelength of one 19 f 1 ion that is moving with a speed of 4.936 x 10 -14 m

λ = h/p = h/mv = 6.625 × \(10^{-34}\) / 3.15 × \(10^{-26}\) = 4.936 x 10 -14 m

The length that a periodic wave travels across in order to replicate its shape is known as its wavelength. It is the distance between two successive corresponding wave points of the same phase, such as two neighboring crests, troughs, or zero crossings, and it is a feature of b0th traveling waves and standing waves and spatial wave patterns. The spatial frequency is defined as the wavelength's inverse. The Greek letter lambda, or "wavelength," is frequently used to represent it. Additionally, sinusoid wave envelopes, modulated waves, and waves created by the interference of several sinusoids are also commonly referred to as having a wavelength.

Wavelength and frequency are inversely related, assuming a sinusoidal wave traveling at a constant speed: in waves.

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"The amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ."

To calculate the amount of heat required to convert ice at 0°C to water at 70°C, we need to consider two steps:

Heat required to raise the temperature of ice from 0°C to its melting point (0°C).

Heat required to melt the ice at its melting point (0°C) and raise the temperature of water from 0°C to 70°C.

Let's calculate the heat for each step:

Step 1: Heating ice from 0°C to its melting point (0°C)

The specific heat capacity of ice is 2.09 J/g°C.

Heat = mass × specific heat capacity × change in temperature

Heat = 108 g × 2.09 J/g°C × (0°C - 0°C)

Heat = 0 kJ (No heat is absorbed as there is no change in temperature)

Step 2: Melting ice and heating water from 0°C to 70°C

The enthalpy of fusion (heat of fusion) for ice is 334 J/g, which represents the amount of heat required to melt ice at 0°C.

Heat for melting ice = mass × enthalpy of fusion

Heat for melting ice = 108 g × 334 J/g

Heat for melting ice = 36,072 J

Next, we need to calculate the heat required to raise the temperature of the water from 0°C to 70°C.

The specific heat capacity of water is 4.18 J/g°C.

Heat = mass × specific heat capacity × change in temperature

Heat = 108 g × 4.18 J/g°C × (70°C - 0°C)

Heat = 32,043.6 J = 32.04 kJ

Now, we can sum up the heat required for both steps:

Total heat = Heat for melting ice + Heat for raising water temperature

Total heat = 36,072 J + 32,043.6 J

Total heat = 68,115.6 J = 68.12 kJ

Therefore, the amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ.

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45 ml of  0.100M NaOH is required to completely neutralize 15.00mL of 0.100M H₃PO₄.

A neutralization reaction is when an acid and a base react to shape water and salt and includes the aggregate of H+ ions and OH- ions to generate water. The neutralization of a robust acid and strong base has a pH same to 7.

Neutralization is a chemical reaction in which acid and a base react quantitatively with each different. In a response in water, neutralization results in there being no extra hydrogen or hydroxide ions present within the solution.

Given;

M₁ = 0.100M NaOH

valance factor n₁ = 1

V₁ = ?

M₂ = of 0.100M H3PO4

valance factor n₂ = 3

V₂ = 15.00mL

M₁n₁V₁ = M₂n₂V₂

V₁ = M₂n₂V₂/M₁n₁

    = 0.1 × 3 × 15 / 0.1 × 1

     = 45 ml

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The concentration of OH- in the aqueous solution is approximately 1.3 × 10-6 M, which corresponds to option D.

To find the concentration of OH- in an aqueous solution when the concentration of H3O+ is 7.6 × 10-9 M, we can use the ion product constant for water (Kw):

Kw = [H3O+][OH-]

Kw is a constant value at 25°C, equal to 1.0 × 10-14.

Given [H3O+] = 7.6 × 10-9 M, we can solve for [OH-]:

1.0 × 10-14 = (7.6 × 10-9)[OH-]

To find [OH-], divide both sides of the equation by the [H3O+] value:

[OH-] = (1.0 × 10-14) / (7.6 × 10-9)

[OH-] ≈ 1.3 × 10-6 M

So, the concentration of OH- in the aqueous solution is approximately 1.3 × 10-6 M, which corresponds to option D.

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Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.

Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.

When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.

One sodium and fluorine each totaling 2 atoms are enough to make the bond.

As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.

The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.

The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.

The name of the compound is sodium fluoride with formula NaF.

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A vacuum is a volume in which no matter exists. It is essentially an empty space with no particles or atoms present. In the natural world, a perfect vacuum does not exist, but we can create near-vacuum conditions in a laboratory setting. In addition, vacuums can be created artificially using various techniques, such as pumping out all the air from a container or using high-powered vacuum pumps. In space, there are areas with very low densities of particles, which are often referred to as vacuum environments. However, even if these areas contain no matter, it still has properties such as pressure, temperature, and energy, which can be measured and manipulated. #SPJ11

Answer: a. 2 C3H7OH + 9 O2 →  6 CO2(g)  + 8 H2O(g)

b. C6H12O6 + 6 O2 →  6CO2(g)  + 6 H2O(g)

Explanation:

Alcohols and sugars combust or when burned with oxygen forms carbon dioxide and water.

Answer:

Explanation:

approx 30%

Reaction

C₃H₄ + 4O₂ → 3CO₂ + 2H₂O

20% purity = 20% x 200 = 40 g

mole C₃H₄ = mass : molar mass = 40 : 40 g/mole = 1

mole H₂O from reaction coefficient (C₃H₄ limiting reactant) = 2/1 x 1 mole = 2 mole

mass H₂O = mole x molar mass = 2 x 18 g/mole = 36 g

for 60% yield, H₂O produced  = 60% x 36 g = 21.6 g

You can see that Ms and Vs correspond to the stock solution, whereas Md and Vd corresponds to the dilute solution. The word 'M' means concentration and 'V' means volume. We want to know what is the volume of the stock solution (Vs). So, we have to use the following formula:

Where C is concentration and V volume. We can write this formula in our terms, like this:

Let's solve for 'Vs':

The given data is:

So, replacing these values in the last formula, we're going to obtain:

The answer is that we have 19.2 milliliters (mL) in the stock solution.

The concentration of Cl- ion in the resulting solution is 6.12 M.

This can be calculated by finding the moles of Cl- ion in each solution, adding them together, and dividing by the total volume of the combined solutions. To find the moles of Cl- ion in the iron (III) chloride solution, we can use the formula: moles = concentration x volume. Thus, moles of Cl- ion = 4.25 M x 0.075 L = 0.31875 moles. Similarly, for the calcium chloride solution, we have moles of Cl- ion = 3.50 M x 0.081 L = 0.2835 moles.

Adding these two moles together gives a total of 0.60225 moles of Cl- ion in the combined solution. Dividing this by the total volume of the combined solutions (75 mL + 81 mL = 156 mL = 0.156 L) gives a concentration of 6.12 M. Therefore, the resulting solution has a Cl- ion concentration of 6.12 M, which is higher than the individual concentrations of the original solutions. This is because the two solutions have been mixed together, leading to an increase in the total number of Cl- ions in the resulting solution.

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Answer:

rusting, cooking and burning wood