Answer:
Explanation:
actually , the acceleration due to gravity depends on the distance from it's center of the earth.
when the distance from the earth increases , the acceleration due to gravity decreases as a result . The value of gravity in space is zero.
An example of an energy conversion from kenetic to thermal energy would be
Answer: For example, if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy.
Explanation: When the temperature of an object increases, the average kinetic energy of its particles increases. When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.
If a car is traveling on a highway and arrives at its destination 56 miles away after 4 hours, what is its speed?
Answer:
14 miles per hour
Explanation:
You have to divide 56 miles by four hours to get 14 miles per hour
how do i graph distance and displacement
Answer:
Explanation:'Distance' is the total length travelled by an object. The standard unit is the 'metre'.
A distance-time graph shows how far an object has travelled in a given time.
Distance is plotted on the Y-axis (left) and Time is plotted on the X-axis (bottom)
Two point charges of +2.00 μC and -2.00 μC are 0.100 m apart. What is the electric field at the point midway between the two charges?Group of answer choices2.88 x 107 N/C1.44 x 107 N/C7.19 x 106 N/C0 N/C
Take into account that the magnitude of electric field at point P, produced by a charge q is given by:
\(E=k\frac{q}{r^2}\)where k (9*10^9 N/m^2C^2) is the Coulomb's constant, r is the distance from the charge to the point P and q is the magnitude of the charge.
An illustration of the given situation is shown below:
As you can notice, at point P the electric fields generated by each charge point to the negative charge. The signs of the charge determine the direction of the electric field.
The magnitude of each electric field is the same, due to the distance to each charge is the same and the magnitude of the charge is equal. Then, The magnitude of the total electric field is:
\(\begin{gathered} E=E_1+E_2=2(9\cdot10^9\frac{N}{m^2C^2})(\frac{2.00\cdot10^{-6}C}{(0.05m)^2}) \\ E\approx1.44\cdot10^7\frac{N}{C} \end{gathered}\)Hence, the electric field at a point midway the given charges is approximately 1.44*10^7N/C
for a system in thermal contact with a heat reservoir at a fixed temperature t, fixedvolume v , and fixed number of particles n, what is the probability of finding thesystem in a particular microstate?
A system has an equal chance of being in any microstate that corresponds to its current macrostate. Equilibrium is defined as an isolated system that meets the postulate of equal a priori probabilities.
The probability of discovering a system in a specific microstate is simply one divided by the total number of microstates.
The thermodynamic probability (denoted by W) is equal to the number of microstates that realise a given macrostate, so W = 1.
To put it simply, the microcanonical ensemble is defined as assigning an equal probability to every microstate whose energy falls within a range centred on E. The probability of all other microstates is set to zero.
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A current filament carrying 15 A in the a, direction lies along the entire z axis. Find H in rectangular coordinates at: (a) PA(/20,0,4); (b) PB(2,-4,4). Ans. 0.534ay A/m; 0.477ar 0.239ay A/m.
A current filament carrying 15 A in the a, direction lies along the entire z axis so H rectangular coordinates are 0.534ay A/m and 0.477ar 0.239ay A/m.
For part (a), we can use the formula:
H = (I/4πr) x φ
where I is the current, r is the distance from the filament to the point of interest, and φ is the unit vector in the direction of the current.
Using rectangular coordinates, we can write the position vector of point PA as:
rPA = (x,y,z) = (0.05, 0, 0.4)
The distance from the filament to point PA is:
r = √(x² + y² + z²)
= √(0.05² + 0² + 0.4²)
= 0.401 m
The unit vector in the direction of the current is:
a = (1,0,0)
Therefore, we can calculate H at point PA as:
H = (15/4π x 0.401) x
a = 0.534ay A/m
For part (b), we need to use the same formula, but we have to take into account the fact that the point of interest is not on the z-axis. We can write the position vector of point PB as:
rPB = (x,y,z) = (2, -4, 4)
The distance from the filament to point PB is:
r = √(x² + y² + z²)
= √(2² + (-4)² + 4²)
= 6
The unit vector in the direction of the current is still:
a = (1,0,0)
However, we also need to take into account the fact that the current filament is along the z-axis. We can do this by introducing a unit vector in the z-direction:
b = az = (0,0,1)
Then, the unit vector in the direction of the current at point PB is:
φ = b x a = ay
Therefore, we can calculate H at point PB as:
H = (15/4π x 6) x φ = 0.477ar + 0.239ay A/m
Note that the x-component of H is zero, which makes sense since the current filament does not have any component in the x-direction.
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Find the acceleration due to gravity on the surface of Mars. The
mass of Mars is 6.42x102kg and its radius is 3370km.
Please Help Me Its Really needed urgently
Answer:
The acceleration due to gravity on the surface of Mars is approximately 3.773 m/s²
Explanation:
The given parameters for Mars with guidance from online search are;
The mass, m = 6.42 × 10²³ kg
The given radius of Mars, r = 3,370 km = 3,370,000 m
The gravitational constant, G = 6.674 × 10⁻¹¹ N·m²/kg²
Therefore, we have, the acceleration due to gravity on the surface of Mars, \(g_{Mars}\) given as follows;
\(g_{Mars}\) = G × m/r² = 6.674 × 10⁻¹¹ × 6.42 × 10²³/(3,370,000)² ≈ 3.773
The acceleration due to gravity on the surface of Mars, \(g_{Mars}\) ≈ 3.773 m/s².
Civil engineers calculate suggested speeds around corners (those yellow signs) when designing roads based upon the ability of a car to remain upon the road. The ability of the car to remain upon the road when taking a corner is determined by the centripetal acceleration of your car around the corner. If you are driving a car around a flat circular turn with a suggested speed of 15 mph, how much more likely is it that your car does not successfully take the corner (ends up in the ditch) if you were to instead drive 45 mph? Cite an equation to back up your thinking.
The car shall not be successful since the corner must have a radius as nine times as the real corner designed for a suggested speed of 15 miles per hour.
By definition of centripetal acceleration, the square of the velocity taken by the vehicle (\(v\)), in miles per hour, is directly proportional to the radius of the corner (\(R\)), in meters. Then, we have the following relationship:
\(\frac{v_{A}^{2}}{R_{A}} = \frac{v_{B}^{2}}{R_{B}}\) (1)
Where:
\(v_{A}\) - Suggested velocity.\(v_{B}\) - Real velocity. \(R_{A}\) - Real radius of the corner.\(R_{B}\) - Expected radius of the corner.If we know that \(v_{A} = 15\,\frac{mi}{h}\), \(v_{B} = 45\,\frac{mi}{h}\) and \(R_{A} = k\), then the expected radius of the corner is:
\(R_{B} = k\cdot \left(\frac{v_{B}}{v_{A}} \right)^{2}\)
\(R_{B} = 9\cdot k\)
In order to successfully take a corner at 45 miles per hour, the corner must have a radius as nine times as the real corner designed for a suggested speed of 15 miles per hour. Thus, the car shall not be successful at a speed of 45 miles per hour.
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assume that you have three tuning forks with frequencies of 270, 273, and 275 hz. what beat frequencies would be possible with these three tuning forks?
Suppose you have three tuning forks that have the frequency 270, 273, and 275 hz. The last beat frequency is 30. Each pair will have a different beat frequency if there are more than two sources.
Since there are three sources of frequency, there are six possible combinations. A tuning fork is a two-pronged acoustic resonator made of tines, which are produced from a U-shaped bar of elastic metal (usually steel). When it is struck against a surface or with an object, it vibrates and resonates at a predetermined steady pitch. Called tuning fork.
The frequency of an event is its repetitions per unit of time. Sometimes it is also referred to as temporal frequency to stress the difference from spatial frequency.
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What are the three forms of water discussed in the passage?
Answer:
The three forms of water are gas, liquid, and ice, I'm not sure if these were mentioned in the passage since you did not attach a picture.
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When a particle with charge q moves across a magnetic field of magnitude B, it experiences a force to the side. If the proper electric field E is simultaneously applied, the electric force on the charge will be in such a direction as to cancel the magnetic force with the result that the particle will travel in a straight line. The balancing condition provides a relationship involving the velocity of the particle. In this problem you will figure out how to arrange the fields to create this balance and then determine this relationship.
PART-A:- Using right-hand rule, the direction of B is \(\hat k\).
PAR-B:- The expression of balanced magnetic field is \(B_{bal}=\frac{E}{v}\)
PART-C:-To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) we would want to use particles with q large and m small.
PART - A
Assume the charge is a sign. Because both the electric and magnetic forces are dependent on, they are also dependent on its sign. So the sign is irrelevant here. Apply the right-hand rule to the magnetic force equation.,\(F_m=q\overrightarrow v\ X\ \overrightarrow B\)
Curl your right hand's fingers from the first vector to the second in the product. The direction of the cross product vector is then indicated by your outstretched thumb.
Hence, the by using right hand thumb rule, it is observed that the direction of B is at z-direction i.e. \(\hat k\)
PART - B
The magnitude of force, \(F_M\) due to a magnetic field \(\overrightarrow B\) interacting with a charge q moving at velocity \(\overrightarrow v\) is expressed as,
\(F_m=qBv...i\)
The magnitude of force on charge q due to an applied electric field \(\overrightarrow E\)is expressed as.
\(F_E=qE....ii\)
on comparing eq.i and eq. ii, we get,
\(E=Bv\\\B=\frac{E}{v}\)
Here, B is balanced as electric field is applied to it.i.e.,\(B_{bal}=\frac{E}{v}\)
PART - C
If the velocity is incorrect, forces will not balance, and the resulting transverse force will cause a transverse acceleration. Use \(a=\frac{F}{m}\) to calculate how this acceleration varies with q and m. Particles with the incorrect velocity should have the greatest possible deviation in the y direction so that they do not pass through a slit at the correct end. This means that the acceleration should be as high as possible.
Particles with the incorrect velocity should have the greatest possible deviation in the y direction so that they do not pass through a slit at the correct end. When the acceleration is greatest, the deviation is greatest.
The acceleration is directly proportional to q and inversely proportional to m:
\(a=\frac{F_E+F_M}{m}=\frac{q}{m}(\overrightarrow E+\overrightarrow v X \overrightarrow B)\)
As a result, for maximum deviation, q should be large and m should be small.
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Your question is incomplete, the complete question is shown in the figure.
When a particle with charge moves across a magnetic field of magnitude , it experiences a force to the side. If the proper electric field is simultaneously applied, the electric force on the charge will be in such a direction as to cancel the magnetic force with the result that the particle will travel in a straight line. The balancing condition provides a relationshipinvolving the velocity of the particle. In this problem you will figure out how to arrange the fields to create this balance and then determine this relationship
a car is driving around a skid pad on a test track, which is a circular path to test how well a car can grip the road while turning. it manages to round a 700 foot radius skid pad with a lateral (centripetal) acceleration of 1.07g (multiples of gravitational acceleration). how fast is the car going?
The car is travelling on the skid pad of the test track with a speed of 47.3m/s.
The radius of the skid pad on which the car is driving is 700 foot.
The lateral centripetal acceleration of the car is 1.07g.
g is the acceleration due to gravity(gravitational acceleration)
one foot is equal to 0.3048m.
So, 700 foot is equal to 213.36m.
Relation between the radius of the track the centripetal acceleration and the speed of the car is,
a = v²/r
Where,
a is the centripetal acceleration(lateral acceleration), v is the velocity, r is the radius.
Putting values,
1.07×9.8 = v²/213.36
v = 47.3 m/s.
The car is travelling with a speed of 47.3m/s.
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A 8.0-kg chunk of putty moving at 4m / s collides with and sticks to a 7.0-kg 1 bowling ball that is initially at rest. The bowling ball with its putty passenger will then be set in motion with a velocity of (round to the hundredths)
The velocity of the bowling ball with its putty passenger will be 2.28 m/s.
Velocity of the moving chunk = \(V_{c}\) = 4 m/s
Mass of the chunk = \(M_{c}\) = 8 kg
Mass of the bowling ball = \(M_{b}\) = 7 kg
Velocity of the bowling ball = \(V_{b}\) = 0
Since this is the perfect inelastic collision, so according to the law of conservation of momentum
Conservation of momentum is a fundamental law of physics that states that the total momentum of an isolated system is conserved in the absence of an external force.
Mathematically, it is p = m*v\(p_{initial} = p_{final}\)
\(p_{initial}\) = \(V_{c}\) * \(M_{c}\) + \(M_{b}\) * \(V_{b}\)
\(p_{initial}\) = 8*4 + 7*0
\(p_{initial}\) = 32 + 0
\(p_{initial}\) = 32 kg.m/s
\(p_{final}\) = ( \(M_{c}\) + \(M_{b}\) ) \(V_{final}\)
\(p_{final}\) = ( 8 + 7 ) \(V_{final}\)
\(p_{final}\) = 14 \(V_{final}\) kg.m/s
\(p_{initial} = p_{final}\)
32 = 14 \(V_{final}\)
\(V_{final}\) = \(\frac{32}{14}\)
\(V_{final}\) = 2.28 m/s
The bowling ball with its putty passenger will then be set in motion with a velocity of 2.28 m/s.
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An ice skater skates around a circular rink with a diameter of 20 m. If it takes her 62. 8 s to go around the rink once, what is the coefficient of friction of the ice?
The friction factor of the ice is M = 0.0102. The resistive friction force (Fr) defined either by ordinary or perpendicular force (N) pushing the particles close yields the coefficient of friction (fr), a numerical value.
The formula fr = Fr/N serves as a representation of it. By figuring out the greatest frictional force, someone can employ the frictional coefficient calculation to calculate the least force necessary to get an item going on a ground.
The item will advance whenever a force given to it that is larger than just the frictional force; as force is measured in newtons, as well as typical, which is a force, newtons are additionally utilized to measure normal. It's going to be cancelled out by the two military units. This coefficient of friction does not have a unit. It is a dimensionally and unitlessly empty quantity.
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A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0
seconds. What is the skateboarder's acceleration?
The acceleration of the skateboarder is calculated out to bbe -2.33 m/s^2, when travelled at 7 meters per second.
What is acceleration and how it calculated out to be -2.33 m/s^2?As we have studied earlier also acceleration is the measure of change in velocity per unit time.Here is given the initial velocity 7 m/s , it is coming to a stop at the top of a ramp . And the time is given 3 seconds.Using the equation a = final velocity - initial velocity / time , we get the acceleration to be -2.33 m/s^2.The skateboarder's acceleration when travelled at 7 meters per second rolls to a stop at the top of a ramp in 3 seconds is calculated out to be -2.33 m/s^2.To know more about acceleration visit:
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If 29.5 ml of 0.150 m hcl neutralizes 25.0 ml of a basic solution, what was [oh] in the basic solution
The concentration of [OH] in the basic solution is 0.177 mol/L.
To find the concentration of [OH] in the basic solution, we first need to use the balanced chemical equation for the neutralization reaction between HCl and OH-:
HCl + OH- -> H2O
We can see from the equation that 1 mole of HCl reacts with 1 mole of OH-. Therefore, the number of moles of HCl used in the reaction is equal to the number of moles of OH- in the basic solution.
First, let's calculate the number of moles of HCl used:
n(HCl) = c(HCl) x V(HCl)
n(HCl) = 0.150 mol/L x 0.0295 L
n(HCl) = 0.004425 mol
Since 1 mole of HCl reacts with 1 mole of OH-, the number of moles of OH- in the basic solution is also 0.004425 mol.
Next, we can use the volume and number of moles of OH- to calculate its concentration:
c(OH-) = n(OH-) / V(OH-)
c(OH-) = 0.004425 mol / 0.0250 L
c(OH-) = 0.177 mol/L
Therefore, the concentration of [OH] in the basic solution is 0.177 mol/L.
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A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?
(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.
(2) The velocity of the center of mass at position 2.
(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.
The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.
(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.
Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.
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A yoyo can be approximated as a solid cylinder of mass m, radius R and thickness d. Two identical such yoyos have their strings tied together and are wound so that the two yoyos are touching each other. These stuck together yoyos are ejected into deep space far from any other objects. Shortly after being ejected, the center of mass of the yoyos have an initial velocity ū as indicated in the diagram. At this instant, the stuck together yoyos are rotating about the center of mass counterclockwise with an angular speed Wil. As the yoyos fly through space the strings unwind so that at some later time all of the string has unwound from each yoyo. At this time, the velocity of the center of mass is ū and the distance between the center of the yoyos is d. Determine the unknown angular velocity (magnitude and direction) of the center of mass for the tied together yoyos. You can neglect the mass of the string and you can assume that the yoyos are tied to the string so that the string is not slipping on the axle of the yoyo
Answer:
I don't understand what your asking
Explanation:
I really don't know
Johnny is always wide awake first thing in the morning. This would be a good time for him to study because it is when he has the most energy.
True, mornings are often considered the best time to study for some people as they tend to have the most energy and focus during this time. Additionally, starting the day with productive activities like studying can set a positive tone for the rest of the day.
What productive activities can be done in the morning?There are many productive activities that can be done in the morning, including:
Exercise: This can help you start the day with more energy and focus.
Meditation or mindfulness practice: This can help you clear your mind and feel more relaxed and focused for the day ahead.
Planning and goal-setting: This can help you prioritize your tasks for the day and feel more organized.
Study or work: Dedicating the first part of your day to work or study can help you be more productive and focused on your tasks.
Reading: This can help you learn new things, improve your vocabulary, and start the day with a positive and stimulating experience.
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You want to push a table 5 feet across the floor. How would a decrease in the resistance caused by friction change the amount of force needed to move an object? Write 1-2 sentences. ANSWER QUICKLY PLS
A decrease in the resistance caused by friction would reduce the amount of force required to move the object.
With less friction, there is less opposition to the motion, allowing for easier and smoother movement of the table across the floor.
This means that you would need to exert less force to achieve the desired displacement of 5 feet.
The decrease in friction enables the object to slide more easily, requiring less effort to overcome the resistance and accomplish the task.
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Of the following numbers: 0.0034 m, 45.6 m, and 1234 m, _____ is the least precise.1) 0.0034 m2) 45.6 m3) 1234 m4) none
ANSWER:
3) 1234 m
STEP-BY-STEP EXPLANATION:
Precision refers to how close two measurements are to one another. The highest number with a significant digit is the most precise, the number that has the most significant figures. Therefore, the less accurate is the opposite.
Which means that in this case, the least precise number is 1234 m.
An electron at point A in the figure (Figure 1) has a speed v0 of 1.10×106 m/s . Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
The magnitude of the magnetic field required to make the electron follow a semicircular path from point A to B is 0.073 T.
When an electron moves through a magnetic field, it experiences a force given by the formula:
F = qvB
where:
F is the force on the electron (in newtons)q is the charge of the electron (in coulombs)v is the speed of the electron (in meters per second)B is the magnetic field strength (in teslas)In order for the electron to follow a semicircular path, the force on the electron must be directed towards the center of the circle. This means that the force must be perpendicular to the velocity of the electron.
Therefore, we can set the magnetic force equal to the centripetal force:
F = ma = (mv²)/r
where:
m is the mass of the electron (in kilograms)
a is the acceleration of the electron (in meters per second squared)
r is the radius of the semicircular path (in meters)
We can substitute F = qvB into the above equation and solve for B:
qvB = (mv²)/r
B = (mv)/(qr)
Plugging in the given values:
m = 9.11 x 10⁻³¹ kg (mass of an electron)
q = -1.6 x 10⁻¹⁹ C (charge of an electron)
v = 1.10 x 10⁶ m/s (given speed)
r = unknown
We need to find the radius r of the semicircular path in order to calculate the magnetic field strength B. To do this, we can use the formula for the centripetal force:
F = ma = (mv²)/r
Solving for r:
r = (mv²)/F
We can use the fact that the magnetic force is equal to the centripetal force to get:
F = qvB
Plugging this into the equation for r:
r = (mv²)/(qvB)
Plugging in the given values and solving for r:
r = (9.11 x 10⁻³¹ kg) x (1.10 x 10⁶ m/s)^2 / ( -1.6 x 10⁻¹⁹ C x B)
r = 0.0511 / B
Now we can substitute this value of r into the equation for B:
B = (mv)/(qr)
B = (9.11 x 10⁻³¹ kg x 1.10 x 10⁶ m/s)/( -1.6 x 10⁻¹⁹ C x 0.0511 m)
B = 0.073 T (tesla)
Therefore, the magnitude of the magnetic field required to make the electron follow a semicircular path from point A to B is 0.073 T.
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joule is a unit of_____and_____
Answer:
Energy and work
.........
Answer:
Work EnergyExplanation:
Joule is a unit of Work and energy .Hope my answer is helpful to you ✌️❣️☪️❇️☪️❣️✌️
Why is the magnetic force considered to be an action datance force
A Magnets in de bo exert a force
B. Magnets do not have to touch each other to experience a force.
C. Magnets push each other apan to increase the distance between them.
D Magnets mast be large in sire in onder to eden a force that is strong enough to notice
a coal power plant consumes 100,000 kg of coal per hour and produces 500 mw of power. if the heat of combustion of coal is 30 mj/kg, what is the efficiency of the power plant?
The efficiency of the coal power plant is approximately 16.67%. To determine the efficiency of the coal power plant, we need to calculate the useful output energy and compare it to the input energy.
Given:
Coal consumption rate: 100,000 kg/hour
Power output: 500 MW (500,000,000 watts)
Heat of combustion of coal: 30 MJ/kg
First, let's calculate the input energy, which is the energy provided by the coal combustion:
Input energy = Coal consumption rate * Heat of combustion of coal
Since the coal consumption rate is given in kilograms per hour and the heat of combustion is given in megajoules per kilogram, we need to convert the units:
Coal consumption rate = 100,000 kg/hour
Heat of combustion of coal = 30 MJ/kg
Input energy = (100,000 kg/hour) * (30 MJ/kg)
Input energy = 3,000,000 MJ/hour
To calculate the efficiency of the power plant, we need to compare the useful output energy (power) to the input energy.
Efficiency = (Useful output energy / Input energy) * 100%
Since power is given in watts and energy is given in joules, we need to convert the units:
Power output = 500 MW = 500,000,000 watts
Now we can calculate the efficiency:
Efficiency = (Power output / Input energy) * 100%
Efficiency = (500,000,000 watts / 3,000,000,000 watts) * 100%
Efficiency = 16.67%
Therefore, the efficiency of the coal power plant is approximately 16.67%.
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Which of the following is a physical property of wood?
A.wood is harder than stone
B. Wood has a rough texture
C.wood is a liquid a room temperature
D.wood melts at 100c
a light beam in air has an angle of incidence of 35 degrees at the surface of a glass plate. what are the angles of reflection and refraction respectively? the index of refraction for glass is 1.50.
The angle of reflection is 35°.
The angle of refraction is 59.36°.
What is reflection?It is referred to as light reflection when a light ray hits a polished, smooth surface and bounces back. The incident light rays hit the surface and are reflected off of it. The beam that returns is referred to as the reflected ray.
Given that: a light beam in air has an angle of incidence of 35 degrees at the surface of a glass plate.
The index of refraction for glass is = 1.50.
Hence, angle of reflection is = angle of incident = 35°.
The angle of refraction is = sin⁻¹(μsini)
= sin⁻¹(1.50sin35°)
= 59.36°
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list sources of noise pollution in your surroundings
-Sounds of Vehicles
-Speakers or TV's at High Volume
-Kitchen Appliances
-Electronic Appliances
-Barking of dogs
Answer:
there are many
Explanation:
includeing planes
loud music
cars
traffic noise
law of conservation of mass states that
Answer:
In any chemical reaction, mass is never created nor is it destroyed.
A plane flies with an average velocity of -98 m/s for 45.0 s. What was its displacement
Answer:-4410 m
Explanation:
Displacement = velocity*time
Displacement = -98 m/s * 45 s
Displacement = -4410 m