Which solution has the higher boiling point?
(a) 38.0 g of C₃H₈O₃ in 250. g of ethanol or 38.0 g of C₂H₆O₂ in 250. g of ethanol

CuCl2, BaCl2, and AgCl will be formed as solids and will precipitate out of solution.

An aqueous solution is a solution in which the solvent is water. It is mostly shown in chemical equations by appending (aq) to the relevant chemical formula. For example, a solution of table salt, or sodium chloride (NaCl), in water would be represented as Na +(aq) + Cl −(aq).

When HCl is added to an aqueous solution containing Cu2+, Ba2+, and Ag+ ions, a precipitation reaction occurs. The net precipitation reaction can be written as follows:

2H+ (aq) + Cu2+ (aq) + 2Cl- (aq) → CuCl2(s) + 2H+ (aq)

Ba2+ (aq) + 2Cl- (aq) → BaCl2(s)

Ag+ (aq) + Cl- (aq) → AgCl(s)

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Answer:

hypothalamus

Explanation:

Answer:

These are called cis-but-2-ene (where the groups are on the same side) or trans-but-2-ene (where they are on opposite sides). Cis-but-2-ene is also known as (Z)-but-2-ene; trans-but-2-ene is also known as (E)-but-2-ene. For an explanation of the two ways of naming these two compounds, follow the link in the box below.

Explanation:

A supersaturated solution can be made to precipitate out by either agitating the solution or adding more solute. Therefore, the correct answer is option C) Both (A) and (B).

A supersaturated solution is a solution that contains more solute than it can dissolve under the given conditions. As a result, it is an unstable solution that can precipitate out by various means, including agitation and adding more solute. Let's look at how this process works in more detail.

Agitating the Solution
Agitation, also known as stirring or shaking, can trigger the precipitation of a supersaturated solution. When a supersaturated solution is agitated, the solute particles suspended in the solution collide with each other and begin to clump together. These clusters of particles gradually grow larger and heavier, causing them to fall out of the solution and form a precipitate.

Adding More Solute
Another way to precipitate a supersaturated solution is to add more solute to the solution. When more solute is added, the supersaturated solution becomes even more supersaturated, reaching a state of higher instability. As a result, the solution is more likely to drop out of the solution and form a precipitate.

Both Agitating the Solution and Adding More Solute
When a supersaturated solution is both agitated and has more solute added to it, the precipitation process is accelerated. Agitation can cause solute particles to clump together, and adding more solute creates more particles that can join in the clustering process. These two processes combined can cause the supersaturated solution to reach a critical point, at which it can no longer hold all the solute in the solution and must precipitate out.

In conclusion, a supersaturated solution can be precipitated out by both agitating the solution and adding more solute. Agitation causes solute particles to collide and clump together, while adding more solute increases the instability of the solution. When these two factors are combined, they can accelerate the precipitation process and cause the supersaturated solution to fall out of the solution.The correct answer is option c.

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The amount of litters of O2 measured for the reaction of one gram of glucose if the conversion were 90% complete in the human body is 24 liters.

Aerobic respiration is a metabolic process in which oxygen is utilized to convert glucose into ATP, which is the main source of energy for the cells.

The equation for aerobic respiration is: C6H12O6 + 6O2 → 6CO2 + 6H2O + 36-38 ATPOne mole of glucose reacts with six moles of oxygen in this process.

The molar volume of oxygen is 22.4 L, thus the amount of oxygen required to completely convert one mole of glucose is:6 moles of oxygen × 22.4 L/mole = 134.4 L of oxygenHowever, since the conversion is only 90% complete, the amount of oxygen required would be:134.4 L of oxygen × 0.9 = 120.96 L of oxygen Since we are dealing with only one gram of glucose, we need to convert the above calculation into liters of oxygen per gram of glucose:120.96 L of oxygen ÷ 6 moles of oxygen ÷ 1000 g/mole of glucose = 0.02016 L of oxygen/g of glucose Therefore, the answer to the question is 0.02016 L of oxygen or 24 liters of oxygen for 1.2 kg of glucose.

In summary, the amount of litters of O2 measured for the reaction of one gram of glucose if the conversion were 90% complete in the human body is 0.02016 L or 24 L of oxygen for 1.2 kg of glucose.

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1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ is the electronic configuration of Cr. the correct answer is D.

There are 24 electrons in all, according to the electron arrangement. A neutral atom will contain 24 protons if it has 24 electrons. The element is determined by its proton count. Chromium, symbol Cr, is the 24th element.

Since Cr contains 24 protons and the +2 charge would result in the nucleus having 26 protons, Cr²⁺ is invalid.  Cu is made up of 29 protons. The copper would be Cu⁵⁺ as there are only 24 electrons. Cu²⁺ was rejected for the same reason.

Therefore, 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ is the electronic configuration of Cr.

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Answer:

She needs 1.19 moles of potassium hydroxide.

Explanation:

Being the molar mass of the elements:

then the molar mass of potassium hydroxide is:

KOH= 39 g/mole + 16 g/mole + 1 g/mole= 56 g/mole

Being the mass of one mole of a substance, which can be an element or a compound, you can apply the following rule of three: if 56 g of KOH are present in 1 mole, 66.48 g of KOH in how many moles of the compound are they?

\(moles of KOH=\frac{66.48 grams*1 mole}{56 grams}\)

moles of KOH= 1.19

She needs 1.19 moles of potassium hydroxide.

Answer:

89.4%

Explanation:

We'll begin by obtaining the actual yield of CO2. This can be obtained calculating the number of mole of CO2 produced from the reaction as follow:

Volume (V) = 1.44 L

Temperature (T) = 293 K

Pressure (P) = 0.984 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =..?

PV = nRT

0.984 x 1.44 = n x 0.0821 x 293

Divide both side by 0.0821 x 293

n = (0.984 x 1.44) / (0.0821 x 293)

n = 0.059 mole

Therefore, the actual yield of CO2 is 0.059 mole.

Next we shall the theoretical yield of CO2. This can be obtained as follow:

First, we shall determine the number of mole in 5.97 g of glucose, C6H12O6.

Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 180 g/mol

Mass of C6H12O6 = 5.97 g

Mole of C6H12O6 =?

Mole = mass /molar mass

Mole of C6H12O6 = 5.97/180

Mole of C6H12O6 = 0.033 mole

Now, we can calculate the theoretical yield of CO2 as follow:

C6H12O6(s) → 2C2H5OH(l) + 2CO2(g)

From the balanced equation above,

1 mole of C6H12O6 produced 2 moles of CO2.

Therefore, 0.033 mole of C6H12O6 will produce = 0.033 x 2 = 0.066 mole of CO2.

Therefore, the theoretical yield of CO2 is 0.066 mole.

Finally, we shall determine the percentage of CO2 as follow:

Actual yield = 0.059 mole

Theoretical yield = 0.066 mole.

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 0.059/0.066 x 100

Percentage yield = 89.4%

Therefore, the percentage yield of the reaction is 89.4%

Answer: A covalent bond that has an equal sharing of electrons (part (a) of Figure 4.4. 1) is called a nonpolar covalent bond. Figure 4.4. 1 Polar versus Nonpolar Covalent Bonds. (a) The electrons in the covalent bond are equally shared by both hydrogen atoms.

Explanation:

We are told that starch consists of glucose polymer, so we can assume that the caloric value of starch will be equal to the caloric value of glucose, that is, 3.9kcal/g.

Now to determine the kcal and kJ there were in the potato we must calculate the mass of starch present in that potato. We are told that it is 92% starch, therefore the mass of starch in the potato will be:

We have that in the potato there are 160.08 grams of starch. By multiplying it by the caloric value we will have the kcal that were in the potato, assuming that the rest of the ingredients do not contribute caloric value, or it is insignificant.

To calculate the kJ we must make the conversion using the relationship that 1 cal is equal to 4.184 joules:

In the potato, there were 624 kcal of energy or 2612kJ of energy.

Answer:

 Then, multiply the number of moles of Na by the conversion factor 6.02214179×1023 atoms Na/ 1 mol Na, with 6.02214179×1023 atoms being the number of atoms in one mole of Na (Avogadro's constant), which then allows the cancelation of moles, leaving the number of atoms of Na.

Explanation:

shoot

The balanced molecular equation for complete neutralization of H2SO4 by KOH in aqueous solution is :

E: H2SO4 (aq) + 2KOH (aq) → 2H2O (l) + K2SO4 (aq).

This is because neutralization is a chemical reaction between an acid and a base, which produces a salt and water.

In a reaction with water, neutralization leaves the solution with too many hydrogen or hydroxide ions. The amount of acid or base present in the neutralized solution determines its pH.

A strong acid and a strong base together will result in a neutral salt. When a strong acid and a weak base are combined, acid is created. Similar to this, when a weak acid is combined with a strong acid, a basic salt is created. There are numerous applications for neutralization.

In this case, H2SO4 is the acid and KOH is the base, and when they react in aqueous solution, they produce K2SO4 (salt) and H2O (water).

The balanced molecular equation represents the chemical reaction in terms of the molecular formulae of the reactants and products involved.

Thus, the correct option is : (E).

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Both option C (NH3(aq) with HClO3(aq)) and option D (LiOH(aq) with HClO4(aq)) will result in a titration curve with an equivalence point with pH > 7.

This is because the strong acid (HClO3 and HClO4) will be neutralized by the weak base (NH3 and LiOH) resulting in a basic solution at the equivalence point. The other options (A and B) will result in an acidic solution at the equivalence point since the strong acid will fully ionize and neutralize the weak base. It's important to note that the pH at the equivalence point depends on the strength of the acid and base used in the titration. NH3(aq) with HClO3(aq). This is because NH3 is a weak base and HClO3 is a strong acid. At the equivalence point, the weak base NH3 will react with the strong acid HClO3, forming NH4+ and ClO3- ions. The NH4+ ion can partially hydrolyze water, producing OH- ions, which increases the pH above 7. The other reactions involve strong acids with strong bases or weak acids with strong bases, resulting in pH levels around 7 or lower.

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Answer:

5 on k-12 that's the answer

Explanation:

Explanation:

nah so easy

it's a direction of electron spinning in the shell

+½ means electron spinning in clockwise direction

-½ means electron spinning in anticlockwise direction

Engineers wanted to redesign a mouse that was more reliable and that was cheaper.

The engineers understood that in order to make the mouse significantly less expensive and more dependable, they would need to drastically simplify its fundamental mechanical design, employ more durable but less expensive materials, and streamline manufacturing.

The mouse developed by Xerox PARC was an expensive, fragile, and failure-prone work of high-concept technology that had no chance of being successful as a commercial product. The state of the art in plastic moulding was pushed due to the size of some of the parts and the tolerances required in the final design. A skilled manufacturer might produce plastic with tolerances of a thousandth of an inch for a reasonable price.

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When diluting a strong acid with water, it is recommended to add the acid to the water and not the other way around. The statement is true.

This is because adding water to the acid can cause a rapid and exothermic reaction, leading to splattering and potential injury.

When the acid is added to the water, the heat generated is absorbed by the water, reducing the potential for splattering. Additionally, adding the acid to water allows for better mixing and reduces the risk of creating concentrated acid pockets that can be dangerous.

Overall, it is important to follow safe laboratory practices when working with acids and to consult with a trained professional if you are unsure about the proper procedures.

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The equator of the sun rotates faster than the poles.

The equator of the sun rotates faster than its poles. This is known as differential rotation, and it is due to the fact that the sun is not a solid body, but is composed of gas and plasma. The equatorial regions of the sun rotate faster because they are farther from the center of the sun, where the gravitational pull is stronger, and thus experience less resistance to their motion.

The period of rotation of the equator of the sun is shorter than that of the poles. The equator rotates once every 25.4 days, while the poles rotate once every 36 days.

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Answer:

It lies in in the visible region.

Frequency: is 7.407 × 10^-14 Hz

\({ \bf{V = f \lambda}} \\ { \tt{3.0 \times {10}^{8} = f \times (405 \times {10}^{ - 9}) }} \\ { \tt{f = 7.407 \times {10}^{14} \: hertz}}\)

Explanation:

V is speed of light.

f is frequency

lambda is the wavelength

For the complex [Co(CO)5]x, the unknown charge (z) would be +1 based on the application of the 18 electron rule.

To find the charge (z) of the complex [Co(CO)5]x using the 18 electron rule, we can follow the steps below:

Identify the metal: In this case, the metal is cobalt (Co).

Determine the number of valence electrons of the metal: Cobalt is a transition metal with atomic number 27. In its neutral state, it has 27 electrons. However, in a complex, cobalt typically contributes all of its valence electrons to bonding, which is 9 electrons (2 from the 4s orbital and 7 from the 3d orbital).

Calculate the total number of electrons contributed by ligands: The ligand in this case is carbon monoxide (CO), which is a strong-field ligand. Each CO ligand contributes 2 electrons (one from the carbon lone pair and one from the oxygen lone pair) for a total of 5 ligands × 2 electrons/ligand = 10 electrons.

Add the valence electrons of the metal and the ligands: Cobalt contributes 9 electrons, and the CO ligands contribute 10 electrons, giving a total of 9 + 10 = 19 electrons.

Apply the 18 electron rule: According to the 18 electron rule, most stable transition metal complexes have 18 valence electrons. However, there can be variations depending on the ligands and the metal's oxidation state.

Determine the charge (z): Since the complex [Co(CO)5]x has 19 valence electrons, which is more than the expected 18 electrons, it suggests that the complex has a positive charge to balance the extra electron(s). Therefore, the charge (z) of the complex would be +1.

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Answer:

I think it's B

Explanation:

apologies if I get this wrong

Answer:

The correct answer is B. The force of gravity.

Explanation:

Gravity affects all objects falling through the Earth's atmosphere. Gravity pulls down on a falling object.

( I got it on study Island as well )

Answer:

B

Explanation:

I believe it is B but I am not entirely sure! don't do this is B doesn't sound or look right to you!

Answer:

Its D

Explanation:

Larger atoms in group 8A require higher boiling points for the molecules to separate from each other than smaller atoms in group 8A.

Two ways to tell that the steel wool in the video underwent a chemical reaction are the production of heat and the change in color of the steel wool.

The production of heat during a chemical reaction is a result of the energy released or absorbed during the chemical reaction. The heat generated during the chemical reaction with steel wool can be observed as the steel wool becomes hot to the touch.

Additionally, chemical reactions often result in a change in the color of the reactants or products, as the steel wool changes from its original silver color to a black color due to the formation of new compounds. This change in color is an indicator that a chemical reaction has occurred.

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The percentage of chloride in the unknown sample is approximately 15.93%.

To calculate the percentage of chloride in the unknown sample, you can use the mass of silver chloride obtained to determine the number of moles of chloride in the original sample, and then convert that to a percentage.

First, calculate the number of moles of silver chloride by dividing the mass by its molar mass:

0.7332 g / 143.32 g/mol = 0.00513 mol AgCl

Next, calculate the number of moles of chloride in the original sample by assuming a 1:1 ratio of chloride ions to silver ions in the reaction:

0.00513 mol AgCl * 1 Cl- / 1 Ag+ = 0.00513 mol Cl-

Finally, divide the number of moles of chloride by the mass of the original sample and multiply by 100 to convert to a percentage:

(0.00513 mol Cl- / 0.3221 g) * 100 = 15.93%

So, the percentage of chloride in the unknown sample is approximately 15.93%.

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Dividing both variables by the population of the city before determining a relationship makes sense because it allows for normalization and enables a more accurate comparison between different cities.

By dividing the total beer sales and number of highway deaths by the population, we obtain per capita values that reflect the specific impact on individuals within each city. This adjustment accounts for variations in city size and ensures a fair assessment of the relationship between beer sales and highway deaths. Without normalizing the data, larger cities with higher populations would naturally have higher total sales and deaths, but it may not necessarily indicate a stronger relationship between the two variables. Normalization allows us to assess the impact relative to the population and provides a clearer understanding of any potential correlation between beer sales and highway deaths across different cities.

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The molar mass of the unknown gas is approximately 47.007 g/mol.

To solve this problem, we can use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

Let's assume the molar mass of the unknown gas is M_2. According to the problem, the rate of effusion for argon (M_1) is 0.849 times that of the unknown gas:

Rate of argon (M_1) / Rate of unknown gas (M_2) = 0.849

By rearranging the equation, we get:

Rate of unknown gas (M_2) = Rate of argon (M_1) / 0.849

Since the molar mass of argon (M_1) is given as 39.948 g/mol, we can substitute the values into the equation:

Rate of unknown gas (M_2) = 39.948 g/mol / 0.849

Calculating this expression gives us the molar mass of the unknown gas:

M_2 = 47.007 g/mol

Therefore, the molar mass of the unknown gas is approximately 47.007 g/mol.

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The molar mass of the unknown gas is approximately 27.17 g/mol.

At a given temperature, the rate at which a gas effuses (passes through a small opening) can be determined by using Graham's Law of Effusion. Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. In this case, we are comparing the effusion rates of an unknown gas and neon gas.

The given information states that the rate of effusion of the unknown gas is 0.849 times that of neon gas. Let's denote the rate of effusion of the unknown gas as r_unknown and the rate of effusion of neon gas as r_neon.

We can express this relationship mathematically as:

r_unknown = 0.849 * r_neon

Now, Graham's Law tells us that the rate of effusion is inversely proportional to the square root of the molar mass. Let's denote the molar mass of the unknown gas as M_unknown and the molar mass of neon gas as M_neon.

Using Graham's Law, we can write:

r_unknown / r_neon = sqrt(M_neon / M_unknown)

Since we know that r_unknown = 0.849 * r_neon, we can substitute this value into the equation:

0.849 * r_neon / r_neon = sqrt(M_neon / M_unknown)

Simplifying the equation:

0.849 = sqrt(M_neon / M_unknown)

To solve for M_unknown, we need to isolate it on one side of the equation. Squaring both sides of the equation, we get:

0.849^2 = M_neon / M_unknown

M_unknown = M_neon / 0.849^2

Now, the molar mass of neon gas (M_neon) is approximately 20.18 g/mol. Let's substitute this value into the equation:

M_unknown = 20.18 g/mol / 0.849^2

Calculating this value, we find:

M_unknown ≈ 27.17 g/mol

So, the molar mass of the unknown gas is approximately 27.17 g/mol.

Please note that the given information does not mention the temperature explicitly. However, the molar mass of a gas is constant at a given temperature. Therefore, we can use the given information to determine the molar mass of the unknown gas regardless of the temperature.

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Answer:  A

Explanation:

Sample should fill the distillation flask about 1/3 to 1/2 full. Always secure the distilling flask with an extension clamp. To the flask, add just few hot stones or perhaps a stir bar.

The thermometer, that is used to gauge the vapor's temperature as it condenses, is located in the top of the this connector. Because the temperature of a vapour going through is equal to the boiling point of a substance being collected under normal circumstances, the actual temperature is crucial.

In a straightforward distillation, the liquid combination is heated to a boiling point and the resultant vapours are quickly condensed. Only mixes where the boiling temperatures of the liquids are noticeably different are suitable for this technique .

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Answer:

37

Explanation:

( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37

When choosing a substance for use in a cooling system, we want a substance that can absorb a large amount of heat without undergoing a significant temperature change. This is where the specific heat capacity of a substance comes into play.

The specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of one unit of mass of the substance by one degree Celsius (or Kelvin). A substance with a high specific heat capacity requires more heat to raise its temperature by a certain amount than a substance with a low specific heat capacity. Therefore, a substance with a high specific heat capacity would be best for use in a cooling system.

Out of the options given, a liquid with a high specific heat would be the best choice for use in a cooling system. Liquids have a higher specific heat than gases, which makes them better at absorbing and storing heat. Additionally, liquids have a higher thermal conductivity than solids, which means they can more efficiently transfer heat from one location to another.

Moreover, among the liquids, water is a commonly used coolant due to its high specific heat capacity, which means it can absorb a large amount of heat without undergoing a significant temperature change. Additionally, water has a high boiling point, which makes it effective at absorbing heat from high-temperature sources without boiling and evaporating.

In summary, a liquid with a high specific heat, such as water, would be the best choice for use in a cooling system due to its ability to absorb and store heat efficiently.

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