Which of these relations is a function?

Answer: 45

Step-by-step explanation:

The Median is the Middle # in the set.

I hope this helps!

The government of Smartypants would need to subsidize college education per student by $2,000.

The question is asking about how much the government of Smartypants would need to subsidize college education per student to achieve the socially optimal level of education.

As per the graph given below, the socially optimal level of education is where MSB = MPC.

So, the government of Smartypants would need to subsidize college education per student by $2,000 to achieve the socially optimal level of education.

The subsidy shifts the supply curve to the right, and so the equilibrium quantity demanded of education increases from QP to QS.

As a result, the market price decreases from PP to PS.The diagram below shows the effects of a subsidy on the market for education. The supply curve shifts to the right, which increases the quantity of education from Q1 to Q2.

The demand curve does not shift as the cost to consumers has not changed, and the price of education falls from P1 to P2. The subsidy per student is represented by the distance between the original MPC and the new MSC curves at the socially optimal level of education.

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Using Cramer's rule the values are:

a) b12 = -15/22

b) b22 = 1/22

c) bs2 = 5/22

d) b23 = -3/22

To find the entries of A-1, we can use Cramer's rule and the formula for computing inverse matrices. First, we need to compute the determinant of A using row reduction:

|1 0 5 3|

|0 1 3 2| = det(A)

|1 0 1 1|

|1 0 0 1|

We can reduce the matrix to upper triangular form by subtracting the first row from the third and fourth rows:

|1 0 5 3|

|0 1 3 2|

|0 0 -4 -2|

|0 0 -5 -2|

Now, the determinant of A is the product of the diagonal entries, which is (-4)(-2)(1)(1) = 8.

To find b12, we replace the second column of A with the column vector [0 1 0 0] and compute the determinant of the resulting matrix. We get:

|-15 0 5 3|

| 8 1 3 2| = b12 det(A)

|-11 0 1 1|

| 4 0 0 1|

Using the formula for 4x4 determinants, we can expand along the first column to get:

b12 = (-15)(-2)(1) + (8)(1)(1) + (-11)(0)(-2) + (4)(0)(5) = -15/22

Similarly, we can find b22, bs2, and b23 by replacing the corresponding columns of A with [0 1 0 0], [0 0 1 0], and [0 0 0 1], respectively, and computing the determinants of the resulting matrices using Cramer's rule. We get:

b22 = 1/22

bs2 = 5/22

b23 = -3/22

Therefore, the entries of A-1 are:

| -15/22 1/22 5/22 |

| 7/22 1/22 -3/22 |

| 1/22 -2/22 1/22 |

Note that we can also find A-1 directly using the formula A-1 = (1/det(A)) adj(A), where adj(A) is the adjugate matrix of A. The adjugate matrix is obtained by taking the transpose of the matrix of cofactors of A, where the (i,j)-cofactor of A is (-1)^(i+j) times the determinant of the submatrix obtained by deleting the i-th row and j-th column of A.

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Answer:

S(C(x)) = –0.14x2 + 140; $108.50 - On edgenuity the answer is D.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The value of the function at 870, the local maximum, is

= -0.02(870)2 + 34.80(870) - 4700

= -0.02(756900) + 30276 - 4700

=  -15138 + 25576

= 10438

So the vertex is (870, 10438)

The cost t the company to produce 870 widgets is  

C(870) = 4700 + 5.20(870) = 4700 + 4524 = 9224

So, the cost of the widgets plus the profit must be equal to the total sales, which is divided by the number of widgets reveal their individual price.

(10438 + 9224)/870 = 19662/870 = $22.60

P(x) = 7700

- 0.02x2 + 34.80x - 4700 = 7700

-0.02x2 + 34.80x -12400 = 0

x = {-34.80 ± √[(34.80)2 - 4(-0.02)(-12400)]}/2(-0.02)

x = [-34.80 ± √(1211.04 - 992)]/(-0.04)

x = (-34.80 ± √219.04)/(-0.04)

x = (-34.80 ± 14.8)/(-0.04)

x = 870 ± 370

so, $7700 in profits will be earned at either 500 widgets or 1240 widgets

Answer:

what can I help you

Step-by-step explanation:

bro tell me the question

By solving a quadratic equation we can see that the width of the path measures 20 meters.

We know that the pool measures 18 meters by 20 meters, then the area of the pool alone is:

A = 18m*20m = 360 m^2

Now, if the path has a width x, then the rectangle that includes the path and the pool has dimensions:

(18m + 2x) and (20m + 2x)

And its area is given by:

(18m + 2x)*(20m + 2x)

And we know it is equal to 1520 m^2, then (i'm not writting the units in the computation):

(18 + 2x)*(20 + 2x) = 1520

360 + 4x^2 + 76x = 1520

Now we just need to solve that quadratic equation:

4x^2 + 76x - 1520 + 360 = 0

4x^2 + 76x - 1160 = 0

The solutions are:

x = (-76 ± √(76^2 - 4*4*(-1160))/(2*4)

x = (-76 ± 156)/4

We only care for the positive solution, which gives:

x = (-76 + 156)/4 = 20

We conclude that the width of the path measures 20 meters.

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Answer:

B

median

hope its help you

Answer: B. Median

Step-by-step explanation:

its the middle line.

Answer:

(3) 36

Step-by-step explanation:

3x + 1 = 9

Minus 1 from both sides.

3x = 8

Divide both sides by 3.

x = 2 2/3

Plug it in.

12 (2 2/3) + 4

32 + 4

36

Answer:

a. 12 students had received college credit for math

b. 26 students had received college credit for science

The postulate that can be used to prove the two triangles are congruent is (c) None of the other answers are correct

The figure represents the given parameter

There are two triangles in the figure

Such that the triangles are similar triangles or congruent

From the question, we understand that the triangles are congruent

Also, we know that

UQ ≅ AC and QD ≅ AU

There is no point C on any of the triangles

This means that we cannot ascertain the congruency of the triangles

Hence, the true statement is (c)

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Step-by-step explanation:

The -5   makes the waveform amplitude of 5  the wave goes down to -5  and up to +5   BUT the -10 shifts the whole wave down 10

so it goes from -15  to -5    and the midline is then   y =  -10

The length of TS is 30.

When on comparing the properties of two or more triangles, if a common relations holds, then they are said to be similar.

Note that similarity is NOT congruency.

In the diagram given in the question, let the length of TS be represented by x. So that;

TS/ QS = SU/ SR

But, we have;

TS = x

SU = TS - 6 = x - 6

So that;

x/ 55 = (x - 6)/ 44

44x = 55(x - 6)

      = 55x - 330

330 = 55x - 44x

330 = 11x

x = 330/ 11

 = 30

x = 30

Therefore, the length of TS is 30.

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The 99% confidence interval for the proportion of executives who want to strengthen innovation is: CI = (0.199, 0.261)

What is confidence interval?

A confidence interval is a statistical measure that provides a range of values within which the true population parameter, such as the mean or proportion, is estimated to lie with a specified level of confidence.

To find the confidence interval for a proportion, we need to use the formula:

CI = p ± z\(\sqrt{(pq/n)\)

where:

CI: confidence interval

p: sample proportion

q: 1 - p

z: z-score from the standard normal distribution for the desired confidence level (99% in this case)

n: sample size

From the problem statement, we know that p = 0.23, n = 1,379, and we want a 99% confidence interval. To find the z-score, we can use a standard normal distribution table or calculator, which gives us a value of 2.576.

Substituting the values into the formula, we get:

CI = 0.23 ± 2.576\(\sqrt{(0.230.77/1379)\)

CI = 0.23 ± 0.031

Therefore, the 99% confidence interval for the proportion of executives who want to strengthen innovation is:

CI = (0.199, 0.261)

This means we can be 99% confident that the true proportion of executives who want to strengthen innovation falls within this range.

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The value of x is either 3 or -5 based on the distance formula.

What is a co-ordinate system?

In pure mathematics, a coordinate system could be a system that uses one or additional numbers, or coordinates, to uniquely confirm the position of the points or different geometric components on a manifold like euclidean space.

Main body:

according to question

Given points A(-1,4) and B(x,7)

Also AB = 5 cm

Formula of distance = \(\sqrt{(y1-y2)^{2}+(x1 -x2)^{2} }\)

here by using points ,

5 = \(\sqrt{(x+1)^{2} +(7-4)^{2} }\)

taking square on both side ,'

25 = \((x+1)^{2} +3^{2}\)

25-9 = (x+1)²

16 = (x+1)²

taking square root on both sides,

x+1= ±4

x = 4-1 = 3                                  or              x = -4-1 = -5

Hence value of x is either 3 or -5.

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all even except 4th equation

Step-by-step explanation:

an even equation is the one who proves that f(-x) = f(x)

Answer:

read below

Step-by-step explanation:

its 38 :)

brainliest me

Answer:

All I know is the y-intercept which is 300

Answer:

I need help to

Step-by-step explanation:

let the numbers be x and y

x + y = 5

x - y = 5/3

from above eqn,

x = 5/3 + y

then, on substituting to the 1st eqn,

5/3 + y + y = 5

5/3 + 2y = 5

2y = 5 - 5/3

2y = 10/3

y = 5/3 or 1 1/3

then,

x will be

x = 5/3 + 5/3

x = 10/3 or 3 1/3

Using the expected value of a discrete distribution, it is found that the game would be fair with a cost of 3 tokens for 1 game.

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Considering the situation described in this problem, that a dice has 6 sides, and x as the price in tokens, the distribution of prizes in this problem is given as follows:

The game is fair when E(x) = 0, hence:

1/6(2 - x + 4 - x + 6 - x + 8 - x + 10 - x) - 1/6(12 + x) = 0.

30 -5x - 12 - x = 0

6x = 18

x = 3.

The cost should be of 3 tokens for 1 game.

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Answer:

Step-by-step explanation:

1.

Equation one:

x = -5, x = -1 (Both are real)

Equation two:

No real solutions

Equation three:

x = -3 (Real)

Equation four:

No real solutions

2.

The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.

Answer:

8/4 < 5/2 is true

Step-by-step explanation:

8/4 = 2

5/2 = 2.5 or 2 1/2

Answer: D

Step-by-step explanation: 8/4 = 1/2  so 5/2 is over 1/2

The 11-4 skills practice areas of regular polygons and composite figures involve finding the areas of different geometric shapes using specific formulas and methods.

To find the area of regular polygons, you can use the formula (1/2) x apothem x perimeter.

For composite figures, you can break the shape into smaller, more manageable shapes like rectangles, triangles, or circles, and then calculate the area of each component before adding them together.

Hence, The 11-4 skills practice areas of regular polygons and composite figures teach you to find areas using the appropriate formulas and methods, improving your geometry understanding and problem-solving abilities.

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t = 0:0.001:0.2;

xa = 5 * cos(120 * pi * t + pi/6);

plot(t, xa); This MATLAB code will plot the signal \( x_{a}(t) = 5 \cos(120 \pi t + \pi / 6) \) for \( 0 \leq t \leq 0.2 \).

To plot the given signal \( x_{a}(t) = 5 \cos(120 \pi t + \pi / 6) \) for \( 0 \leq t \leq 0.2 \) using MATLAB, follow these steps:

Step 1: Define the time axis

```matlab

t = 0:0.001:0.2; % time vector from 0 to 0.2 with a step of 0.001

```

Step 2: Define the signal equation

```matlab

xa = 5 * cos(120 * pi * t + pi/6);

```

Step 3: Plot the signal

```matlab

plot(t, xa);

xlabel('Time (s)');

ylabel('Amplitude');

title('Signal xa(t)');

```

Step 4: Customize the plot (optional)

You can customize the plot by adjusting the axis limits, adding a grid, legends, etc., based on your preference.

Step 5: Display the plot

```matlab

grid on;

legend('xa(t)');

```

By running the MATLAB code, you will obtain a plot of the signal \( x_{a}(t) \) with the time axis ranging from 0 to 0.2 seconds. The amplitude of the signal is 5, and it oscillates with a frequency of 60 Hz (120 cycles per second) and a phase shift of \(\pi/6\) radians. The plot will show the waveform of the signal over the specified time interval, allowing you to visualize the behavior of the signal over time.

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Answer:

There are 20 students. Of those 20 students, 4 knew 15 capitals. We have:

4/20 = 20/100 = 20% of the students knew 15 capitals.

A minimum sample size of 121 individuals needs to be surveyed, ensuring a rounded-up value to estimate the proportion of non-graduates within the 25 to 30 age group with a 10% margin of error and 90% confidence.

To determine the sample size required to estimate the proportion of non-graduates within the 25 to 30 age group with a certain level of confidence and margin of error, we can use the formula:

n = (Z^2 * p * (1 - p)) / E^2

Where:

n is the required sample size

Z is the Z-score corresponding to the desired confidence level (90% confidence corresponds to a Z-score of approximately 1.645)

p is the estimated proportion of non-graduates (0.21 based on the information provided)

E is the desired margin of error (10% or 0.10)

Substituting the values into the formula:

n = (1.645^2 * 0.21 * (1 - 0.21)) / 0.10^2

n ≈ 120.41

Rounding up to the nearest integer, the required sample size is 121.

Therefore, you would need to survey at least 121 individuals in the 25 to 30 age group to estimate the proportion of non-graduates within 10% margin of error with 90% confidence.

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The solution is Option A.

The translation of the center of circle is given by ( x , y ) ⟶ ( x - 15 , y + 1 )

A circle is a closed two-dimensional figure in which the set of all the points in the plane is equidistant from a given point called “center”. Every line that passes through the circle forms the line of reflection symmetry. Also, the circle has rotational symmetry around the center for every angle

The circumference of circle = 2πr

The area of the circle = πr²

where r is the radius of the circle

The standard form of a circle is

( x - h )² + ( y - k )² = r²,

where r is the radius of the circle and (h,k) is the center of the circle.

Given data ,

Let the equation for the circle A be represented as

( x - 7 )² + ( y - 1 )² = 16

Now , the equation is of the form ( x - h )² + ( y - k )² = r²

So , the radius of the circle is 4 and the center of the circle is ( 7 , 1 )

Let the equation for the circle A be represented as

( x + 8 )² + ( y - 2 )² = 16

Now , the equation is of the form ( x - h )² + ( y - k )² = r²

So , the radius of the circle is 4 and the center of the circle is ( -8 , 2 )

So , the translation of circle A to B is given by

( 7 , 1 ) to ( -8 , 2 )

So , the x coordinate is translated by 15 units to left and the y coordinate is translated by 1 unit up

Hence , the translation is given by ( x , y ) ⟶ ( x - 15 , y + 1 )

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The trigonometric identity, (sec(x) ÷ cos(x)) - (tan(x) ÷ cot(x)) is equivalent to the Pythagorean identity sec²(x) - tan²(x) = 1, therefore;

(sec(x) ÷ cos(x)) - (tan(x) ÷ cot(x)) = sec²(x) - tan²(x) = 1

A trigonometric identity is an equation involving trigonometric ratio which is correct for possible values of the input variables.

The specified trigonometric identities can be presented as follows;

sec(x) ÷ cos(x) - tan(x) ÷ cot(x) = 1

cos(x) = 1/sec(x)

tan(x) = 1/cot(x)

cot(x) = 1/tan(x)

Therefore; sec(x) ÷ cos(x) - tan(x) ÷ cot(x) = sec(x) ÷ (1/sec(x)) - tan(x) ÷ (1/tan(x)) = 1

Therefore;

sec(x) ÷ cos(x) - tan(x) ÷ cot(x) = sec²(x) - tan²(x)

The Pythagorean identities, indicates that we get;

sec²(x) - tan²(x) = 1

Therefore; sec(x) ÷ cos(x) - tan(x) ÷ cot(x) = sec²(x) - tan²(x) = 1

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The angle β, given the terminal point(sqrt(2)/2, sqrt(2)/2) on a unit circle, is equal to π/4 radians or 45 degrees.

To determine the angle β given the terminal point on a unit circle, we can use the trigonometric functions sine and cosine.

The terminal point of β is (sqrt(2)/2, sqrt(2)/2). Let's denote the angle β as the angle formed between the positive x-axis and the line connecting the origin to the terminal point.

The x-coordinate of the terminal point is cos(β), and the y-coordinate is sin(β). Since the terminal point issqrt(2)/2, sqrt(2)/2). we have:

cos(β) = sqrt(2)/2

cos(β) = sqrt(2)/2

We can recognize that sqrt(2)/2 is the value of the cosine and sine functions at π/4 (45 degrees) on the unit circle. In other words, β is equal to π/4 radians or 45 degrees.

So, β = π/4 or β = 45 degrees.

In summary, the angle β, given the terminal point (sqrt(2)/2, sqrt(2)/2) on a unit circle, is equal to π/4 radians or 45 degrees.

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