Which of these is a biotic factor?

Answer:

621.83grams

Explanation:

Using the formula;

Mole = mass ÷ molar mass

Where;

Mole = mol

Mass = grams

Molar mass = g/mol

According to the information given in this question, number of moles = 3.1mol, mass of Hg = ?, Molar mass (MM) of Hg = 200.59g/lol

Hence, using mole = mass/MM

3.1 = mass / 200.59

mass = 200.59 × 3.1

Mass = 621.829

Mass = 621.83grams

The  reaction forces are as follows:

Reaction forces are the force which act in an opposite direction to an applied force.

According to Newton's third law of motion, action and reaction are equal but oppositely-directed.

Considering the given forces, the reaction forces are as follows:

A baseball bat hits a ball = the reaction force is that of the ball hitting the bat

A bowling ball pushes up against the pins = the pins pushing against the bowling ball

Air particles push outward against a balloon = the walls of the balloon pushing against the air particles

During an earthquake, tectonic plates move = the weight of the tectonic plates.

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When rock on Earth's surface is broken into smaller pieces, forming loose material  is called Weathering.

Physical weathering and chemical weathering are the two basic types of weathering. On this page, we discuss mechanical weathering (and more).

Rocks naturally fracture at a number of different levels. The borders between mineral grains can be a source of weakness in the rock. Sedimentary rocks are frequently stratified, and the layers are occasionally not tightly bonded together. As larger, more massive rocks are exposed by erosion, joints (cracks with no relative motion across them, merely spreading) may form in the rocks. These rock fissures become wider due to physical deterioration. Of course, biological weathering refers to weathering caused by living creatures.

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Answer:

The answer should be 100 if not try 200

Explanation:

d=v x t

400m=4m/s x t

/4           /4

100=t

Answer:

116°

Explanation:

REFER TO THE GIVEN ATTACHMENT

HOPE THIS HELPS!

Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction \(= u\cos\theta\)

and the speed in the vertical direction is \(= u\sin\theta\) upward.

For A:

The speed in the horizontal direction \(= u\cos75^{\circ}\)

and the speed in the vertical direction is \(= u\sin75^{\circ}\) upward.

For B:

The speed in the horizontal direction \(= u\cos15^{\circ}\)

and the speed in the vertical direction is \(= u\sin15^{\circ}\) upward.

Let \(t_A\) and \(t_B\) are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A \(= u\cos75^{\circ}\times t_A\cdots(i)\)

The range for the projectile B = \(u\cos15^{\circ}\times t_B\cdots(ii)\)

At the highest point, the vertical velocity is 0.

Bu using the equation of motion \(v^2=u^2 +2a s.\)

Here, the final velocity v=0, the initial velocity \(u = u \sin \theta\) , h= vertical distance up to the highest point, and \(a= -g\) (as per sign convention).

So, \(s= \frac{u^2\sin^2 \theta}{2g}\)

For projectile A: The maximum height attained.

\(s_A= \frac{u^2\sin^2 75^{\circ}}{2g}\)

For projectile B: The maximum height attained.

\(s_B= \frac{u^2\sin^2 15^{\circ}}{2g}\)

As \(\sin^2 75^{\circ} > \sin^2 15^{\circ}\), the height of A is attained by A is more than the heigHt attained by B.

Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.

So, the total time of flight = 2 x (Time to reach the highest point)

In a similar way, by using the equation of motion v=u+at,

The time to reach the highest point \(=\frac {u\sin\theta}{g}\)

where g is the acceleration due to gravity.

So, the total time of flight

\(= 2 \times \frac {u\sin\theta}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin75^{\circ}}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin15^{\circ}}{g}\)

Now, from equations (i) and (ii),

The range for the projectile A =

\(u\cos75^{\circ}\times \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}\)

The range for the projectile B =

\(u\cos15^{\circ}\times \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.\)

Both the projectile have the same range.

Hence, option (A) is correct.

If a pitcher wants to throw two balls requiring the same amount of work to throw, the ball without spin (Ball B) will travel faster toward home plate.

(a) Ball A, which is spinning rapidly, has more total mechanical energy because rotational kinetic energy is added to its translational kinetic energy. The spin contributes to the overall energy of the ball.

(b) Ball A, which is spinning rapidly, requires more work to throw because the rotational motion adds an additional component of kinetic energy that needs to be provided by the pitcher.

(c) If a pitcher wants to throw two balls requiring the same amount of work to throw, the ball without spin (Ball B) will travel faster toward home plate. This is because the absence of spin allows for better aerodynamic efficiency, reducing air resistance and allowing the ball to maintain higher translational speed.

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Answer:

9600

Explanation:

Answer:

Hey... your answer is 9,600

Explanation:

Hope this helps :)

Here is prove just in case...

Best of luck <3

Answer:

920 kg

Explanation:

\(kinetic \: energy = 222640j \\ \frac{1}{2} mv {}^{2} = 222640 \\ \frac{1}{2} m(22) {}^{2} = 222640 \\ m = 920kg\)

The resistor of the electric lamp is marked at 240 volts and 60 watts is 960 ohms. Thus, option D is correct.

The resistance is a property that gives obstruction the current flow.  It blocks the current flow in the circuit. The unit of resistance is the ohm.    

From the given,

The voltage of the electric lamp (E) = 240 volt

Power in the circuit (P) = 60 watt

Resistance =?

Power (P) = E² / R

R = E²/P

   = 240×240/60

  = 960 Ω

The resistance of the electric lamp with a given voltage and power is 960 Ω. Thus, the ideal solution is D.

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The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.

Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.

However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.

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Tyler wants to learn about the types of insects in the soil near his house. He could collect a large amount of data for a low cost.

Descriptive investigation, comparative investigation, and experimental investigation are the three types of investigations that scientists use to research and create explanations for events in nature.

Providing descriptions is the aim of descriptive research. It should describe phenomena in a factual, precise, and organized manner without attempting to infer their causes. It does not provide an explanation for the how, when, or reasons why a specific phenomenon occurred.

In various situations, scientists employ a variety of investigational techniques. These techniques include fair testing, identifying and classifying, modeling, pattern seeking, and researching (in no particular order). According to research, fair testing dominates science instruction.

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Answer:

true

Explanation:

as long as it is the right conductive material

The angular momentum of the earth-moon system measured from the center of the earth is approximately 7.07 x 10^33 kg m^2/s. The angular momentum of the earth-moon system can be estimated by multiplying the moment of inertia of the system by the angular velocity.

The moment of inertia for a solid sphere is (2/5)mr^2, where m is the mass of the sphere and r is the radius.

For the earth, the moment of inertia is (2/5)m_eR_e^2, where R_e is the radius of the earth. For the moon, the moment of inertia is (2/5)m_mR_m^2, where m_m is the mass of the moon and R_m is the radius of the moon.

Assuming that both the earth and moon are rotating in the same sense, the angular velocity of the system can be calculated by dividing the angular displacement (2π radians) by the time it takes for one complete revolution, which is the sidereal month of about 27.32 days.

Using the values for the moment of inertia and angular velocity, the angular momentum of the earth-moon system can be estimated as:

L = (2/5)m_eR_e^2ω + (2/5)m_mR_m^2ω

where ω is the angular velocity. Plugging in the values and solving for L, we get:

L = (2/5)m_eR_e^2(2π/27.32 days)

L = (2/5)m_e(6.371 x 10^6 m)^2(2π/27.32 x 24 x 60 x 60 seconds)

L = 7.07 x 10^33 kg m^2/s

Therefore, the angular momentum of the earth-moon system measured from the center of the earth is approximately 7.07 x 10^33 kg m^2/s.

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The number of circular pieces of filter paper used in Experiment 2 was 15.

The third option is correct.

Filter paper is described as a semi-permeable paper barrier placed perpendicular to a liquid or air flow which is used to separate fine solid particles from liquids or gases.

The various properties of filter paper includes:

The number of circular pieces of filter paper used in Experiment 2 taking note of the number of trials is 15.

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Explanation:

average speed=91.67km/hr

Aerobic exercise helps you lose weight and keep it off when combined with a good diet.

When you first begin regular aerobic exercise, you could feel exhausted. But over time, you'll benefit from more endurance and less weariness.

Over time, you can also improve your bone and muscle strength as well as your heart and lung health.

Regular aerobic exercise like walking, cycling, or swimming can improve your health and length of life.

You repeatedly contract your arms, legs, and hip muscles when engaging in aerobic exercise. You'll become aware of your body's reactions immediately.

You'll deepen and speed up your breathing. The amount of oxygen in your blood is increased as a result. As a result of your heart beating more quickly, more blood will reach your muscles and return to your lungs.

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Answer:

A rain guage is used to measure the precipitating rain in a given amount of time.

A thermometer is used to measures temperature.

A barometer is used to measure atmospheric pressure.

A anemometer is used to calculate wind speed

Explanation:

Answer:

B i think

Explanation:

Answer:

I can tell you that the pressure in a gas in inversely proportional to the volume, so it should be reversible. So I think the volume of a gas is inversely proportional to the pressure.

Explanation:

The acceleration of the plane will be −8 m/s²

How to find the acceleration of a plane?

Acceleration is the rate of change in velocity over time (Δv/t).

Given, that the initial velocity of the plane u=480 m/s

The final velocity of the plane is zero after landing, v= 0 m/s

t= 1 minute= 60 seconds

we know, v=u + at

0= 480 + 60a

a=\(\frac{-480}{60}\)  = -8m/s²

Thus, the acceleration of the plane is -8 m/s²

(negative acceleration implies that the object is slowing down)

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The magnitude of the force per unit length that one wire exerts on the other is 8.88 x 10^-5 N/m times the length of the wires.

To find the magnitude of the force per unit length that one wire exerts on the other, we can use the formula:

F = μ0 * I1 * I2 * L / (2 * π * d)

where F is the force per unit length, μ0 is the permeability of free space (4π x 10^-7 T*m/A), I1 and I2 are the currents in the two wires, L is the length of the wires, and d is the distance between the wires.

Plugging in the values given, we get:

F = (4π x 10^-7 T*m/A) * (1.50 A) * (3.40 A) * L / (2 * π * 0.0260 m)
F = 8.88 x 10^-5 N/m * L

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Answer:

The frequency at which the string will create a standing wave be  with three loops is 8.6 Hz

Explanation:

The speed of the of the wave, v = 12.9 m/s

The number of loops of the standing wave = 3 loops

The length of the string = 2.00 m

Given that one loo = half of the wavelength, we have;

Three loops = 3 × half = One and half wavelength  = 1.5·λ

The frequency of a wave = f = v/λ

Therefore, we have;

The frequency, f = 12.9/1.5 = 8.6 Hz

The frequency at which the string will create a standing wave be  with three loops = 8.6 Hz.

Answer:

9.675

Explanation:

got it right on acellus

Answer:

Fricción.

Explicación:

Caminando con otro compañero al mismo tiempo y al mismo ritmo, el movimiento se produce debido a la fricción del suelo y la suela de los zapatos porque la fricción es la fuerza que ayuda en el movimiento de los objetos de un lugar a otro. Si no hay fricción entre el suelo y la suela de los zapatos, no podemos dar un paso por lo que podemos decir que la fricción nos mueve hacia adelante.

Answer:

true

Explanation:

1. Stance

2. Nock

3. Set Draw Hand

4. Set Bow Hand

5. Pre-Draw

6. Draw

7. Anchor

8. Aim

9. Shot Set Up

10. Release

11. Follow-Through & Reflect

An astronomer looking at the observatory's plate collection will be examining a set of photographic plates. These plates are glass or film sheets that have been used to capture images of celestial objects and events. They serve as valuable data sources for astronomical research and analysis.

When an astronomer involved in a research project says he is going to look at the observatory's plate collection, he is most likely referring to photographic plates that were used to capture images of the night sky before the advent of digital cameras. These plates were essentially sheets of glass coated with light-sensitive chemicals and placed in a camera mounted on a telescope. The telescope would then be pointed at a specific area of the sky and the plate would be exposed to the light for a set period of time. After the exposure, the plate would be developed and the resulting image would be visible on the plate. Astronomers would use these plates to study a variety of celestial objects such as stars, galaxies, and nebulae. Today, many observatories have digitized their plate collections, making them more accessible for researchers to study and analyze.

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Answer:

Gravitational Energy

The spacecraft Clementine was named after the classic folk song "Oh My Darling, Clementine."

It was named after the folk song "Oh My Darling, Clementine." The song tells the story of a miner's daughter named Clementine who drowned in a river.

The spacecraft was named after the song because it was designed to study the Moon's surface, particularly its mineral content.

And the name "Clementine" was thought to be a fitting tribute to the miners who work to extract valuable minerals from the Earth.

The mission was a joint project between the Department of Defense and NASA and was launched on January 25, 1994.

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Answer:

a:s

b:s

c:r

d: r

e: s

f:  s

g: s

Explanation:

The distance from the axis of the force applied is 2.05 m.

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

Another formula for torque is given as;

τ = Iα

where;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice. is most likely describe the three surfaces.

Friction, force that resists the sliding or rolling of one solid object over another. Frictional forces, such as the traction needed to walk without slipping, may be beneficial, but they also present a great measure of opposition to motion. About 20 percent of the engine power of automobiles is consumed in overcoming frictional forces in the moving parts.

The major cause of friction between metals appears to be the forces of attraction, known as adhesion, between the contact regions of the surfaces, which are always microscopically irregular. Friction arises from shearing these “welded” junctions and from the action of the irregularities of the harder surface plowing across the softer surface.

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