Which of the following has kinetic energy? (1 point)

Answer:

4.9 km

Explanation:

\(\sqrt{4.2^2+2.6^2}=4.9 km\)

Answer:

Explanation:

We can use the equation for the wavelength of light that passes through a double-slit interference pattern

λ = (d * sinθ) / m

where λ is the wavelength of light

d is the distance between the two slits

θ is the angle between the m=0 and m=1 interference lines

m is the order of the interference line.

Given that

d = 6 X 10^-5 meters

θ = 10 degrees

Interference between the m=0 and m=1 interference lines, so m = 1

Converting θ to radians:

θ = 10 degrees = 0.174533 radians

Put the values in given equation

λ = (6 X 10^-5 meters * sin(0.174533 radians)) / 1

λ ≈ 6.89 X 10^-7 meters

Therefore, the wavelength of light that shines on two slits that are 6 X 10^-5 meters apart and that angle between m=0 and m=1 interference lines is 10 degrees is approximately 6.89 X 10^-7 meters.

Answer:

b

Explanation:

convert heat energy into mechanical

Decrease.

Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.

Note that your body itself does not change.

Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.

In short, a trip to the equator is not a viable long-term weight-loss program.

Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.

We experience as "something pulling you down" is actually the total of all the forces and not just gravity.

The four dominant large-scale, long-term forces are:

The earth's gravity

The sun's gravity

The moon's gravity

The earth's centrifugal force

Hence, the weight of a body at the equator will be less than at the Poles.

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Answer:

212N/m

Explanation:

First of all, what is spring constant
As per Hooke's law, The restoring force applied by the spring is proportional to the change in length, and restoring force is directed towards the equilibrium position. The proportionality constant is called the spring constant and it is a measure of the stiffness of the spring. So as Hooke's law

F = -Kx

Where

F -> Restoring force

K-> Spring constant

x -> change in length

the negative sign indicates it is acting toward the center

Rearranging this for the Spring constant, Spring constant formula is given by

k = Fx

Unit of Spring Constant is Newton/meter

Answer:

Gironde Ecosystem is an important biological and cultural area.

Explanation:

Answer:

60°

Explanation:

It will be equilateral triangle, you can prove with the cosine theorem.

1)P^2=P^2+P^2 - 2×P×P× cos A

2) cos A= P^2 / 2× P^2 = 1/2

cos A = 1/2

A = 60°

If you wrote this question right,it will be solved like this :)

Answer:

600

Explanation:

Resistors that are connected in series are simply added. So three 200 ohm resistors connected in series make 200 + 200 + 200 = 600

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Answer:

Explanation:

a. The X and Y components of the velocity can be found using trigonometry:

X = V * cos(θ) = 15 m/s * cos(38°) ≈ 11.63 m/s

Y = V * sin(θ) = 15 m/s * sin(38°) ≈ 9.14 m/s

b. The time the ball is in the air can be found using the Y component of the velocity and the acceleration due to gravity:

Y = V * sin(θ) * t - (1/2) * g * t^2

where g = 9.8 m/s^2 is the acceleration due to gravity

Solving for t, we get:

t = 2 * Y / g ≈ 1.87 s

c. The distance the ball travels can be found using the X component of the velocity and the time in the air:

distance = X * time = 11.63 m/s * 1.87 s ≈ 21.78 m

If the mass of the cart was halved, the magnitude of the centripetal acceleration would decrease.

Centripetal force is a force that causes a change in velocity that undergoes motion in a circular path.

Centripetal force can be expressed by using the formula:

\(F = \frac{mv^2}{r}\)

Where;

m = mass of the cart

r = radius of the circular path

v = speed of the cart

Now, since F ∝ m, if the mass (m) is halved, then the magnitude of the centripetal force acting on the cart will also be halfved.

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Answer:

C

Explanation:

Because they both received the same temperature

Answer:

B and D is the answer

Explanation:

I took the assignment <3

Answer:

B and D is the correct answer.

Explanation:

To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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The relationship between the temperature of an object and the frequency of electromagnetic waves generated by the object is described by the concept of blackbody radiation.

A blackbody is an idealized object that perfectly absorbs all electromagnetic radiation that falls on it and emits radiation in a continuous spectrum over a range of frequencies.

According to Planck's law, the spectral distribution of blackbody radiation depends on the temperature of the object. As the temperature of the object increases, the peak of the spectral distribution shifts towards higher frequencies.

This relationship is known as Wien's displacement law, which states that the wavelength at which the spectral radiance of a blackbody is maximum is inversely proportional to the temperature of the object.

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Answer:

The answer is within the picture.

Explanation:

Answer:

1 N = 1 kg·m/s2

Explanation:

You can see if the person your talking to and being mindfull they  will see respect towards you or they see you as a mindful person.It shows a person that you care.

Explanation:

The maximum acceleration attained on the interval 0 ≤ t ≤ 3 by the particle is equal to 21 m/s².

Acceleration of an object can be described as the change in velocity of the object with respect to time. Acceleration can be described as the first derivative of the velocity of an object with respect to time.

The expression for the acceleration in terms of velocity can be represented as:

\({\displaystyle a =\frac{dv}{dt}\)

Given the expression of the velocity is v (t) = t³ - 3t² + 12t +4

dv/dt = v'(t) = d/dt(t³ - 3t² + 12t +4)

a(t) = 3t² - 6t +12

At time t = 0 , a(0) = 3(0)² - 6(0) +12 = 12

At time t = 3s, a(3) = 3(3)² - 6(3) +12 = 21

Therefore, the maximum acceleration attained on the interval 0 ≤ t ≤ 3 is equal to 21.

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Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

Answer:

0.033 seconds

Explanation:

Period = 1/30 = 0.033 seconds

Answer:

The answer is 0.03 s

Explanation:

A.P.E.X.

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Red hot is not as hot as blue hot because as the temperature increases the frequencies of light emitted becomes higher leading to emission of smaller wavelength lights.

All objects emits light, even at room temperature. But it cannot be seen with human eyes as the wavelength is too high. When heated the wavelength starts to decrease ( reaching the visible spectrum ) as high heat produce high frequency lights.

The wavelength of colour visible to human eyes starting from highest wavelength to lowest wavelength is as follows: Red, Orange, Yellow, Green, Cyan, Blue and violet.

Therefore, "Red hot" is not as hot as "blue hot"

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The velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

The given parameters;

The resultant vertical velocity of the boat is calculated as;

\(v_y = 8 \ - \ 5 sin(30)\\\\v_y = 8 - 2.5\\\\v_y = 5.5 \ km/h\)

The resultant horizontal velocity of the boat is calculated as;

\(v_x = -2 \ + 5cos(30)\\\\v_x = 2.33 \ km/h\)

The resultant boat velocity is calculated as follows;

\(v = \sqrt{v_x^2 + v_y^2} \\\\v = \sqrt{2.33^2 + 5.5^2} \\\\v = 5.97 \ km/h\)

The direction of the velocity;

\(\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{5.5}{2.33} )\\\\\theta = 67 \ ^0\)

Thus, the velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

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a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Answer:

\((a) 189.23 N\), \((b) 47.31 N\) and \((c) 141.92 N\).

Explanation:

Three balls are shown in figure having charge \(q=1.45 \mu C\). The middle ball, \(B\), is positively charged having charge \(+q\), and the remaining two outside balls, \(A\) and \(C\), are negatively charged having charged \(-q\) as shown.

\(AC=20 cm\) and \(AB=BC=10\) cm as B is the mid-point of AC.

Let \(d_1=AC=20\times 10^{-3}m\) and \(d_2=AB=BC=10\times 10^{-3}m\)

From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance, \(d\), is

\(F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)\)

where, \(\epsilon_0\) is the permittivity of free space and

\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.

This force is repulsive for the same nature of charges and attractive for the different nature of charges.

Now, Using equations(i),

(a) The magnitude of attraction force between balls A and B is

\(F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}\)

\(\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AB}=189.23 N\)

(a) The magnitude of the repulsive force between balls A and C is

\(F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}\)

\(\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AC}=47.31 N\)

(c) The magnitude of the net force, \(F_{net}\), on the outside of the ball is,

\(F_{net}=189.23-47.31 N\)

\(\Rightarrow F_{net}=141.92 N\)

Answer:

A.The tortoise is moving at a constant speed

Explanation:

The chart shows the tortoise covering a distance of 0.5 meters every 60.0 seconds. Since this rate of motion is not changing, the tortoise is moving at a constant speed.

The diagram shows the tortoise moving at a constant speed. Thus the correct option is option A.

Speed is defined as how far the object travels. It is also defined as the rate of change of distance per unit of time. Speed is the scalar quantity and the unit of speed is m/s.

Speed is denoted by the letter v. v = s/t, where s is the distance traveled along the path and t is the time taken by the object to move along the path.   The SI unit of distance is meter and the unit of time is seconds.

When the object covers an equal distance at equal intervals of time is called uniform speed. When the object covers unequal distance with equal intervals of time or equal distance with unequal intervals of time is called Non-uniform speed.

The graph shows the Tortoise covers 0.5 m in 60 seconds is called uniform speed. Thus, option A is correct.

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