Which of the following describes ice changing the Earth's surface by erosion?



Water freezes in the cracks of a rock causing bigger cracks to form.


A mound of rock is left as glacier ice melts and the glacier retreats


Sediment frozen in the ice of a glacier moves as the glacier moves.




Heavy ice presses on sediment causing the formation of sedimentary rock

Answer:

The freezing of water into ice causes the cracks to widen because it occupy more space.

Explanation:

When the water change its state of liquid to solid state due to decrease in temperature, it contracts means occupy less space but when the temperature reaches to 4 degree Celsius, it starts to expand. When the temperature goes below 0 degree Celsius, it will cause more expansion and occupy more space that causes the cracks to widen.

Answer:

Explanation:

The circulatory system is made up of blood vessels that carry blood away from and towards the heart The circulatory system carries oxygen, nutrients, and hormones to cells, and removes waste products, like carbon dioxide.....etc

The most important thing in the circulatory system is The heart.

It pumps blood around the body. It sits inside the chest, in front of the lungs, and slightly to the left side. The heart is a double pump made up of four chambers, with the flow of blood going in one direction due to the presence of the heart valves.

The chief function of the circulatory system is,

Oxygen and Carbon Dioxide Transport.

(Circulates OXYGEN and removes Carbon Dioxide)

Other functions of the circulatory system are:

Nutrient and Waste Product Transport.

Disease Protection and Healing.

Hormone Delivery.

Body Temperature Regulation.

Explanation:

What's Your Question ??..

Answer:

True

Explanation:

Answer:

c. The rusting of the joints of a metal children’s swing set.

Explanation:

By definition, chemical property describes the ability of a substance to undergo a specific chemical change.

In the definition above, the key words are; "Chemical change".

Generally, chemical changes are irreversible. This means we just have t observe the options and pick the one that contains an irreversible change.

Upon doing ths, the correct option is;

c. The rusting of the joints of a metal children’s swing set.

This is because rusting is a chemical change and is irreversible.

Moles of gold present in a ring that contains 3.4x10¹⁹ gold atoms is  5.64x10⁻⁵. The correct option is (d).

The thin coating of gold metal on a ring contains 3.4x10¹⁹ gold atoms. We need to find how many moles of gold is this.

Gold (Au) is a chemical element with the symbol Au (from Latin: aurum) and atomic number 79. It is a soft, dense, yellow metal with a bright, metallic luster. Gold has an atomic mass of 196.967 g/mol. Hence one mole of gold atoms will have a mass of 196.967 grams.

The number of moles of gold can be calculated as follows.

Calculate the number of grams of gold present in the ring coating.

Avogadro's number (N) is a physical constant defined as the number of atoms or molecules in one mole of a substance. Its value is 6.02214076 × 10²³ mol⁻¹.

There are 3.4x10¹⁹ gold atoms present in the ring coating.

Moles of gold atoms = Number of gold atoms / Avogadro's number

The number of gold atoms = 3.4x10¹⁹ atoms; Avogadro's number (N) = 6.02214076 × 10²³ mol⁻¹

∴Moles of gold atoms = 3.4x10¹⁹ / 6.02214076 × 10²³ = 5.64x10⁻⁵

Hence the number of moles of gold is 5.64x10⁻⁵.

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There are approximately 1.5951 moles of oxygen atoms in 53.20 g of CaCO₃. Oxygen atoms are fundamental particles that make up the element oxygen and are essential for supporting life and combustion.

To determine the number of oxygen atoms in 53.20 g of CaCO₃ (calcium carbonate), we need to use the concept of moles and Avogadro's number.

First, we calculate the molar mass of CaCO₃ by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms. The atomic masses are approximately: Ca = 40.08 g/mol, C = 12.01 g/mol, and O = 16.00 g/mol.

Molar mass of CaCO₃ = (1 × Ca) + (1 × C) + (3 × O) = 40.08 g/mol + 12.01 g/mol + (3 × 16.00 g/mol) = 100.09 g/mol.

Next, we calculate the number of moles of CaCO₃ using the given mass and the molar mass.

Number of moles = Mass (g) / Molar mass (g/mol) = 53.20 g / 100.09 g/mol = 0.5317 mol.

Since there are three oxygen atoms in one molecule of CaCO₃, we can multiply the number of moles by the number of oxygen atoms per molecule to find the total number of oxygen atoms.

Number of oxygen atoms = 0.5317 mol × 3 = 1.5951 mol.

Conclusively, there are approximately 1.5951 moles of oxygen atoms in 53.20 g of CaCO₃.

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A substance that is impenetrable by x-rays is described as being radiopaque.

Radiopaque substances will not allow x-rays and or other forms of radiations to pass through them.

Instead, they absorb or block the rays and when used in radiology, they appear white or light gray on photographic films.

Radiopaque materials are applied in generating ultrasound images and other forms of clinical procedures.

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The breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

The approximate energy yield through aerobic metabolism of a 22-carbon fatty acid involves a series of major reactions within the mitochondria of cells. The process is known as beta-oxidation, and it generates acetyl-CoA molecules that enter the citric acid cycle (also known as the Krebs cycle) to produce ATP.

First, the 22-carbon fatty acid undergoes a series of four reactions in the beta-oxidation pathway. Each cycle of beta-oxidation removes a two-carbon acetyl-CoA molecule from the fatty acid chain, generating one molecule of NADH and one molecule of FADH2 in the process. These high-energy electron carriers will later enter the electron transport chain to produce ATP.

After the beta-oxidation process, the resulting acetyl-CoA molecules enter the citric acid cycle. In this cycle, each acetyl-CoA molecule is oxidized, leading to the production of three molecules of NADH, one molecule of FADH2, and one molecule of GTP (which can be converted to ATP). These electron carriers (NADH and FADH2) will transfer their electrons to the electron transport chain for ATP synthesis.

Finally, the electron transport chain, located in the inner mitochondrial membrane, utilizes the high-energy electrons from NADH and FADH2 to pump protons across the membrane. This establishes an electrochemical gradient that drives ATP synthesis through oxidative phosphorylation. The exact number of ATP molecules generated depends on several factors, but on average, the complete oxidation of a 22-carbon fatty acid yields approximately 129 molecules of ATP.

Overall, the breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

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In future purification procedures, adjusting the pH and using different column matrices could be effective in sharpening peak 2 like peak 1.

Peak 1 appears to be sharper than peak 2, which could indicate differences in the physical properties of the molecules being separated or differences in the purification protocol. Adjusting the pH of the mobile phase or buffer system could affect the retention time and selectivity of the column, potentially leading to sharper peaks.

Additionally, using a different column matrix with a higher resolution could improve peak separation and sharpen the peaks. It may also be helpful to optimize the sample preparation or injection volume to ensure the highest possible resolution. Overall, it is important to carefully evaluate and troubleshoot the purification protocol to identify potential areas for improvement in order to obtain sharper and more accurate separation of the target molecules.

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The energy change for the given reaction is -200 kJ.

The energy change for a reaction is given by the difference between the energy of the products and the energy of the reactants. In this case, the energy change can be calculated using the standard enthalpy of formation values of the reactants and products. The standard enthalpy of formation of Br2(l), 2I-(aq), Br-(aq) and I2(s) are 0 kJ/mol, -151 kJ/mol, -121 kJ/mol, and 62 kJ/mol, respectively. Using these values, we can calculate the energy change as:

ΔH = (2 x ΔHf°(Br-) + ΔHf°(I2) - 2 x ΔHf°(I-) - ΔHf°(Br2)) kJ/mol
   = (2 x (-121) + 62 - 2 x (-151) - 0) kJ/mol
   = -200 kJ/mol

Therefore, the energy change for the given reaction is -200 kJ, which means that the reaction is exothermic as it releases energy.

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The correct order of the increasing polarity of the analyte functional group isEthers < Esters.

The given statement is "Polarities of analyte functional group increase in the order of hydrocarbon ethers < esters."  The order of polarities of functional groups is the order of their increasing polarity (i.e., less polar to more polar) based on their electron-donating or withdrawing ability from the rest of the molecule.Polarity of analyte: The analyte's polarity is directly proportional to the dipole moment of the functional group, which is associated with a difference in electronegativity between the atoms that make up the functional group.The electronegativity of an element is its ability to attract electrons towards itself. The greater the difference in electronegativity between two atoms, the more polar their bond, and hence the greater the polarity of the molecule.

To find the correct order of the increasing polarity of the analyte functional group, let's first compare the two groups: hydrocarbon ethers and esters. Here, esters have a carbonyl group while ethers have an oxygen atom with two alkyl or aryl groups. The carbonyl group has more electronegative oxygen, which pulls electrons away from the carbon atom, resulting in a polar molecule. On the other hand, ethers have a less polar oxygen atom with two alkyl or aryl groups, making them less polar than esters. Therefore, the correct order of the increasing polarity of the analyte functional group isEthers < Esters.

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Answer:

The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore they rarely react with other elements since they are already stable

It will take 185.7 years for 99% of the strontium  - 90 in a rock specimen to decay completely.

Given the half- life of the strontium-90 rock = (t1/2)

                                                                          = 28 years

Since the given reaction follows first-order kinetics, the rate constant (k) will be given by k = ln(2)/(t1/2).

  t1/2 = half life of strontium-90  

         = 28 years

  k = ln(2)/28  ≅ 0.0248.

   Q(T) = \(Q_{0}\) \(e^{kt}\)

   Q(T) =  \(Q_{0}\) \(e^{-0.0248t}\)                                                    [Q(T) = \(Q_{0}\) /100 ]

   (1/100) \(Q_{0}\)  = \(Q_{0}\)  \(e^{-0.0248t}\)

for    

Divide both sides by \(Q_{0}\)  to get

(1/100)=  \(e^{-0.0248t}\)

Take the natural log of   both sides to get 

ln (1/100)= −0.0248 

Divide both sides by −0.0248  to    get

    =    ln (1/100)/ (−0.0248)   ≅  185.7  Years

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To obtain the equilibrium molarity of a substance, the initial molarity is taken and the change in molarity is expressed as x. At equilibrium, 1.24 moles of A and 4.28 moles of B were obtained.

At equilibrium, both reactions proceed at the same rate (or velocity), so there is no difference in the quantities of substances.

For example, if K > Q, the reaction proceeds forward to transform reactants into products; if K < Q, then the reaction proceeds backward to transform products into reactants; and if Q = K, then the system is in equilibrium.

Given [A] =0.720 mole and [B] =2.490 mole

Equilibirium constant (K) = [B]/[A]

K= 2.490/0.720 = 3.46

For a reaction A     ⇆      B

Initial conc. 0.42            5.1

Final conc.  0.42- x        5.1 + x

K= 3.46 = 5.1 + x/ 0.42- x

   x =  -0.8

At equilibrium A = 0.42- x = 0.42 - (-0.8) = 1.24 mole

                        B  = 5.1 + x = 5.1 +( -0.8) = 4.28 mole

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Answer:

P=9

Explanation:

Formula: P = M/V
First, we need to find the volume. This can be done by: 5 x 3 x 2 which will give us 30

Now we can plug it in
P= 270/30

P=9!  

Answer:

oxygen consists of 3 isotopes and carbon consists of 2 isotopes

Explanation:

oxygen: O16, O17 and O18

Carbon: C12 and C13

A sociologist studying New York City ethnic groups wants to determine if there is a difference in income for immigrants from four different countries during their first year in the city. The degrees of freedom for the Between (BET) and Within (W) groups are d f BET = 3 and d f W = 13, respectively. The calculated F statistic is approximately 0.577.

To perform the ANOVA test and calculate the relevant values, let's first organize the data into a table:

Country I: 12.9, 9.8, 10.7, 8.5, 16.9

Country II: 8.8, 17.9, 19.8, 10.3, 19.3

Country III: 20.6, 16.8, 22.6, 5.8, 19.5

Country IV: 17.7, 8.7, 14.1, 21.7

To calculate the necessary values, we will use the following formulas:

SSTOT = SSBET + SSW

d f BET = k - 1

d f W = N - k

MSBET = SSBET / d f BET

MSW = SSW / d f W

F = MSBET / MSW

Where:

k = number of groups (countries)

N = total number of observations

SSBET = sum of squares between groups

SSW = sum of squares within groups

Now let's calculate the values step by step:

Calculate the mean for each group:

Country I: Mean-I = (12.9 + 9.8 + 10.7 + 8.5 + 16.9) / 5

Country II: Mean-II = (8.8 + 17.9 + 19.8 + 10.3 + 19.3) / 5

Country III: Mean-III = (20.6 + 16.8 + 22.6 + 5.8 + 19.5) / 5

Country IV: Mean-IV = (17.7 + 8.7 + 14.1 + 21.7) / 4

Calculate the overall mean:

Overall Mean = (Sum of all observations) / (Total number of observations)

Calculate SSTOT (Total Sum of Squares):

SSTOT = Σ(xi - Overall Mean)²

Calculate SSBET (Sum of Squares Between Groups):

SSBET = Σ(Ni × (Mean-i - Overall Mean)²), where Ni is the number of observations in each group.

Calculate SSW (Sum of Squares Within Groups):

SSW = Σ(xi - Mean-i)², where xi is each individual observation.

Calculate the degrees of freedom:

d f BET = k - 1

d f W = N - k

Calculate MSBET (Mean Square Between Groups) and MSW (Mean Square Within Groups):

MSBET = SSBET / d f BET

MSW = SSW / d f W

Calculate the F statistic:

F = MSBET / MSW

Now let's perform the calculations:

Calculate the means:

Mean-I = (12.9 + 9.8 + 10.7 + 8.5 + 16.9) / 5 ≈ 11.76

Mean-II = (8.8 + 17.9 + 19.8 + 10.3 + 19.3) / 5 ≈ 15.22

Mean-III = (20.6 + 16.8 + 22.6 + 5.8 + 19.5) / 5 ≈ 17.06

Mean-IV = (17.7 + 8.7 + 14.1 + 21.7) / 4 ≈ 15.55

Calculate the overall mean:

Overall Mean = (12.9 + 9.8 + 10.7 + 8.5 + 16.9 + 8.8 + 17.9 + 19.8 + 10.3 + 19.3 + 20.6 + 16.8 + 22.6 + 5.8 + 19.5 + 17.7 + 8.7 + 14.1 + 21.7) / 17 ≈ 14.618

Calculate SSTOT (Total Sum of Squares):

SSTOT = (12.9 - 14.618)² + (9.8 - 14.618)² + (10.7 - 14.618)² + (8.5 - 14.618)² + (16.9 - 14.618)² + (8.8 - 14.618)² + (17.9 - 14.618)² + (19.8 - 14.618)² + (10.3 - 14.618)² + (19.3 - 14.618)² + (20.6 - 14.618)² + (16.8 - 14.618)² + (22.6 - 14.618)² + (5.8 - 14.618)² + (19.5 - 14.618)² + (17.7 - 14.618)² + (8.7 - 14.618)² + (14.1 - 14.618)² + (21.7 - 14.618)²

SSTOT ≈ 199.760

Calculate SSBET (Sum of Squares Between Groups):

SSBET = (5 × (11.76 - 14.618)²) + (5 × (15.22 - 14.618)²) + (5 × (17.06 - 14.618)²) + (4× (15.55 - 14.618)²)

SSBET ≈ 23.484

Calculate SSW (Sum of Squares Within Groups):

SSW = (12.9 - 11.76)² + (9.8 - 11.76)² + (10.7 - 11.76)² + (8.5 - 11.76)² + (16.9 - 11.76)² + (8.8 - 15.22)² + (17.9 - 15.22)² + (19.8 - 15.22)² + (10.3 - 15.22)² + (19.3 - 15.22)² + (20.6 - 17.06)² + (16.8 - 17.06)² + (22.6 - 17.06)² + (5.8 - 17.06)² + (19.5 - 17.06)² + (17.7 - 15.55)²+ (8.7 - 15.55)² + (14.1 - 15.55)² + (21.7 - 15.55)²

SSW ≈ 176.276

Calculate the degrees of freedom:

d f BET = k - 1 = 4 - 1 = 3

d f W = N - k = 17 - 4 = 13

Calculate MSBET (Mean Square Between Groups) and MSW (Mean Square Within Groups):

MSBET = SSBET / d f BET

MSW = SSW / d f W

MSBET ≈ 23.484 / 3 ≈ 7.828

MSW ≈ 176.276 / 13 ≈ 13.559

Calculate the F statistic:

F = MSBET / MSW

F ≈ 7.828 / 13.559 ≈ 0.577

Now, let's summarize the ANOVA test results in a table:

Source SS d f MS F

Between 23.484 3 7.828 0.577

Within 176.276 13 13.559

Total 199.760 16  

The degrees of freedom for the Between (BET) and Within (W) groups are d f BET = 3 and d f W = 13, respectively. The calculated F statistic is approximately 0.577.

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Answer:

Tissues And Organ Systems

Explanation:

The pressure of the carbon dioxide that is allowed to sublime in atm, is 2.463 atm

The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 1 = 0.1 × 0.0821 × 300

P = 2.463 atm

Thus, the pressure of the gas is 2.463 atm

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Answer: I don't know try your best

Explanation:

The first atomic model to adequately explain the radiation spectra of atomic hydrogen was Bohr's model of the hydrogen atom. The atomic Hydrogen model was first presented by Niels Bohr in 1913. Here the energy is -4.6 × 10⁻¹⁹ J. The correct option is C.

The planetary model was first put forth by the Bohr Model of the hydrogen atom, however an assumption regarding the electrons was later made. The atoms' structure being quantized was the underlying presumption. Bohr proposed that electrons moved in predetermined orbits or shells with defined radii around the nucleus.

The equation used here to calculate the energy is Rydberg equation.

1 / λ = R . (1 / n²₂ - 1 / n²₁)

R = 1.0974 × 10⁷ m⁻¹

1 / λ =  1.0974 × 10⁷ ( 1 / 5² - 1 / 2²)

1 / λ = -2304, 540

λ = -4.33 × 10⁻⁷ m

E = hc / λ

E = 6.626 × 10⁻³⁴ × 3 × 10⁸ / -4.33 × 10⁻⁷  = -4.6 × 10⁻¹⁹ J

Thus the correct option is C.

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When you use a soap or detergent to wash, the surfactant molecules will interact with the dirt and oils to help wash them away. During this interaction, something called a micelle is formed.

A micelle is a cluster of surfactant molecules that are formed when soap or detergent molecules are mixed with water. When soap or detergent is added to water, the hydrophobic tails of the molecules (which do not mix with water) cluster together, while the hydrophilic heads (which are attracted to water) point outwards towards the water.

Micelles are formed by the hydrophobic tails of the surfactant molecules clustering together in the center, with the hydrophilic heads facing outward.

The soap or detergent's molecules' hydrophobic tails attract oils and dirt, while the hydrophilic heads attract water molecules. The hydrophobic tails of the detergent molecules encircle the dirt and oil particles, while the hydrophilic heads point outward toward the water, creating a micelle.

The micelles disperse the dirt and oil particles throughout the water so that they can be washed away.

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Answer: I believe the correct answer is D) Monetary policy

i would appreciate brainliest

Approximately 1.375 grams of sodium-24 remains after 60 hours.

The half-life of sodium-24 is 15 hours, which means that after every 15 hours, half of the remaining sodium-24 will decay.

To calculate the amount of sodium-24 remaining after 60 hours, we can divide the total time (60 hours) by the half-life (15 hours) to determine the number of half-life intervals.

Number of half-life intervals = 60 hours / 15 hours = 4 intervals

Since each half-life interval results in a halving of the amount, we can calculate the remaining amount of sodium-24 by multiplying the initial amount (22 grams) by (1/2) four times:

Remaining amount of sodium-24 = 22 grams * (1/2)^4 = 22 grams * (1/16) ≈ 1.375 grams

Therefore, approximately 1.375 grams of sodium-24 remains after 60 hours.

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a. The equilibrium constant for the reaction at 25 °C from the reaction A(aq) ⥫⥬  enzyme B (aq) and the Δ° of the reaction is -5.540 kJ·mol⁻¹ is 2.98 × 10³.

b. The Δ for the reaction at body temperature (37.0 °C) if the concentration of A is 1.5 M and the concentration of B is 0.60 M is  -8.020 kJ·mol⁻¹.

To calculate the equilibrium constant (K'eq) for the reaction at 25°C, we have the relation:

Δ° = -RT ln K'eq

Where R is the universal gas constant, T is the temperature in Kelvin, and ln is the natural logarithm.

Therefore, K'eq = e-Δ°′/RT

Substituting the given values, we have:

K'eq = e-(-5540 J/mol)/(8.314 J/mol K × 298 K)

= 2.98 × 10³

The Δ for the reaction at body temperature (37.0 °C) is given by the relation:

Δ = Δ° + RT ln(Q)

where Q is the reaction quotient at the given concentration of reactants and products.

Q = [B] / [A] = 0.60 / 1.5 = 0.4

Substituting the given values, we have:

Δ = -5540 J/mol + (8.314 J/mol K × 310 K) ln (0.4)

= -8020 J/mol

Therefore, the Δ for the reaction at body temperature is -8.020 kJ·mol⁻¹.

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The synthesis of nylon requires solutions of 5% hexamethylenediamine and 5% adipoyl chloride. This polymer will form between layers of the solutions. To remove the nylon, one can choose to dissolve it in the 5% hexamethylenediamine or in the 5% adipoyl chloride.

Nylon, a synthetic polymer, is produced from the combination of adipoyl chloride and hexamethylenediamine. This process is called the synthesis of nylon. Nylon is a highly flexible material that is resistant to wear and tear, as well as chemical and heat degradation. The synthesis of nylon requires solutions of 5% hexamethylenediamine and 5% adipoyl chloride, respectively, for the two reactants to be mixed together.

The reaction between these two chemicals is exothermic, which means that it releases heat. The heat generated in the reaction drives the reaction forward, resulting in the formation of nylon. The chemical formula for nylon is (-CO-NH-)n, where n is a large number that reflects the degree of polymerization. To remove the nylon, it is soaked in an acid solution. The acid dissolves the nylon, separating it into its constituent components, which can then be purified and reused.

The most commonly used acid for this process is hydrochloric acid. The process of removing nylon from its solvent is called the "acid-catalyzed hydrolysis of nylon." Nylon is used in a variety of applications, including textiles, packaging materials, and electrical components, among others. Its properties make it ideal for use in applications that require durability, strength, and flexibility. Nylon's physical properties, including its resistance to heat and chemical degradation, make it ideal for use in applications such as electrical insulation, packaging materials, and textiles.

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