Which landscape will erode more quickly? Assume the same precipitation and average temperature in each landscape.

A. Landscape A.
B. Landscape B.
C. The rates of erosion will be the same.
D. Impossible to determine.

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Answer:

Below

Expetion:

The SLOPE of the tim-position graph is the velocity at a given time....

   Slope = rise / run    

 From graph at  t =     6 sec =   (4 -8) / (7-5) = -2  m/s

From the graph, the position of the object at 6 seconds is 8.33 m. Then the velocity taken to cover this distance is 1.38 m/s.

Velocity is a physical quantity used to express distance covered by object per unit time. Velocity is a vector quantity thus, having both magnitude and direction.

Velocity is the rate of speed and mathematically it is the ratio of distance to the time. As more distance covered within less time, the velocity is higher.

From the graph, after a time of 6 seconds, the position of the object is 8.33 m. Then, the velocity of the object is:

velocity = distance/ time

             = 8.33 m / 6 s

             = 1.38 m/s.

Therefore, the velocity of the object at 6 s is 1.38 m/s.

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As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of R such that

R - 50 N - (3 kg) g = 0   =>   R = 79.4 N

As soon as you remove your hand, the block has acceleration a such that, by Newton's second law,

R - (3 kg) g = (3 kg) a   =>   a = (79.4 N - (3 kg) g) / (3 kg) ≈ 16.7 m/s^2

pointing upward.

The frictional force of the wind on water produces surface currents that travel in a pattern analogous to "wind currents".

Wind, temperature, water density, and the moon's gravitational pull may all affect ocean currents.

Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface. When wind constantly disturbs the surface of an ocean or lake, a wave crest is created.

Friction slows the wind, which also changes its direction. This phenomenon might lead to surface roughness variations along regional boundaries or turbulence in winds near the surface. Turbulence stirs the lower atmosphere.

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According to Coulomb's law, the force between the given charges is 0.225N which is explained below.

Force on two identical charges q separate by a distance of r is given by:

F = kq²/r²

where k is Coulomb's constant

q is the charge

r is the separation between the charges

Given that q = 1×10⁻⁵C,

and r = 2m

So, the force between the given charges will be:

F = (9×10⁹)(1×10⁻⁵)²/2²

F = 0.225N is the required force.

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1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.

To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.

The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.

The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.

Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.

Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.

Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.

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Answer:

organizing

Explanation:

thinking about where things should go, to make it so that everybody has an easy experience when inside of my store.

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

Answer:

In which way are electromagnetic waves different from mechanical waves?Electromagnetic waves can travel through empty space

Explanation:

I took A P E X Quiz.

Answer: Net electrostatic force on C is 24.2×\(10^{-2}\) Newtons.

Explanation: Coulomb's Law is used to determine Electrostatic Force. Its formula is:

F = k.\(\frac{q_{0}.q_{1}}{r^{2}}\)

where:

k is electrostatic constant (k = 8.987×\(10^{9}\) Nm²/C²);

q is the charge of the object in Coulumb;

r is the distance between charges;

The net force is the sum of all the forces acting on C, so:

Force B on C:

They are both positive, so there is a relpusive force acting between them on the y-axis.

\(F_{BC} = 8,987.10^{9}.\frac{4.35.10^{-3}.9.67.10^{-4}}{(6.14.10^{2})^{2}}\)

\(F_{BC} = 10.03.10^{-2}\) N

Force D on C:

There is an atractive force between them on the x-axis.

\(F_{CD} = 8.987.10^{9}.\frac{9.67.10^{-4}.1.92.10^{-3}}{(1.42.10^{3})^{2}}\)

\(F_{CD} = 13.64.10^{-4}\) N

Force A on C:

First, find the distance between objects:

The distance is a diagonal line that divides the rectangle into a right triangle. Distance is square of the hypotenuse .

\(r^{2} = (6.14.10^2)^{2} + (1.42.10^{3})^{2}\)

\(r^{2} = 37.72.10^{4}\)

and hypotenuse: r = \(6.14.10^2\)m

There is an atractive force between charges, but there are components of the force in x- and y-axis. So, because of that, force will be:

\(F_{CA} = F_{CA}\).sinα + \(F_{CA}.\)cosα

\(F_{CA} = 8.987.10^{9}.\frac{3.12.10^{-3}.9.67.10^{-4}}{37.72.10^{4}}\)

\(F_{CA} = 7.2.10^{-2}\)

The trigonometric relations is taken from the rectangle:

sinα = \(\frac{6.14.10^{2}}{6.14.10^{2}}\)

cosα = \(\frac{1.42.10^{3}}{6.14.10^{2}}\)

\(F_{CA}.\)cosα = \(7.2.10^{-2}(\frac{1.42.10^{3}}{6.14.10^{2}})\) = 0.17

\(F_{CA}.\)sinα = \(7.2.10^{-2}.(\frac{6.14.10^{2}}{6.14.10^{2}} )\) = 0.072

\(F_{CA} =\) 0.17î + 0.072^j

Now, sum up all the terms in its respective axis:

X: \(13.64.10^{-4} + 0.17 =\) 0.1714

Y: \(10.03.10^{-2} + 7.2.10^{-2}\) = 0.1723

These forms another right triangle, whose hypotenuse is the net electrostatic force:

\(F_{net} = \sqrt{(0.1714)^{2} + (0.1723)^2}\)

\(F_{net} = 24.3.10^{-2}\) N

The net electrostatic force acting on C has magnitude \(F_{net} = 24.3.10^{-2}\) N.

Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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Answer:

the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.

Explanation:

mass of the cannon ball, m₁ = 26 kg

initial velocity of the cannon ball, u₁ = 8.5 m/s

mass of the elderly performer, m₂ = 65 kg

Let the velocity of the elderly performer after catching the cannon ball = u₂

Apply the principle of conservation of linear momentum to determine the velocity of the elderly performer after catching the cannon ball.

m₁u₁ = m₂u₂

\(u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{26 \times 8.5}{65} \\\\u_2 = 3.4 \ m/s\)

Therefore, the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.

The negative outcome indicates a flaw in the information provided or how the issue was put up because the flow rate cannot be fictional or negative.

It can be expressed as:

P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2

the terms involving h cancel out in the equation, and we can solve for v1:

P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2

v1 = √(P2 - P1))/ρ)

Substituting the given values for P1, P2, and ρ into the equation,

\(v1 = \sqrt(1.22 x 10^5 - 1.65 x 10^5))/1000) = \sqrt(-0.43)\)

B) The same formula (v2) may be used to get the flow rate in the top part.

v2 = sqrt((2(P1 - P2))/ρ)

\(v2 = \sqrt{2} (1.65 x 10^5 - 1.22 x 10^5))/1000) =\sqrt(0.86) ≈ 0.93 m/s\)

C) The following formula may be used to get the volume flow rate (Q) via the pipe:

Q = Av

A1 = πr1\(1^{2}\); at point 2, the cross-sectional area A2 = πr\(2^2\).

we get:

Q = A1v1 = πr1^2v1

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Answer:

The value is \(F =13.27 \ N\)

Explanation:

From the question we are told that

     The mass is \(m = 3200 \ g = 3.2 \ kg\)

     The speed is \(v = 7.2 \ m/s\)

     The radius is \(r = 12.5 \ m\)

Generally the centripetal force is mathematically represented as

        \(F = m * \frac{v^2}{r}\)

=>     \(F = 3.2 * \frac{7.2^2}{12.5}\)

=>     \(F =13.27 \ N\)

Answer:

10.88kJ

Explanation:

Given data

mass= 10kg

heigth= 111m

Applying

PE= mgh

assume g= 9.81m/s^2

substitute

PE= 10*9.81*111

PE=10889.1 Joules

PE=10.881kJ

Hence the potential energy is 10.88kJ

Given,

The spring constant of the spring, k=27.4 N/m

The stretch in the spring, x=2.1 m

The magnitude of the restoring force of the spring is given by,

Where F is the force required to stretch the given spring 2.1 m

On substituting the known values,

The force required to stretch the spring is 57.54 N

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Answer:

19

Explanation:

I legit did this and it took 19.

A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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Answer:

Weathering and erosion are processes by which rocks are broken down and moved form their original location. They differ based on whether a rock's location is changed: weathering degrades a rock without moving it, while erosion carries rocks and soil away from their original locations.

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer:

\(\mathbf{\alpha = 25.88 \ rad/s^2 }\)

Explanation:

Consider the force due to friction:

\(F = \mu_kN -------- (1)\)

where;

N = normal reaction

\(\mu_k\) = coefficient of kinetic friction.

Via the horizontal direction, the forces of equilibrium are:

\(\sum F_x = \sum(F_x) _{eff} \\ \\ N- F_{AB} \ cos \theta = 0 \\ \\ F_{AB} \ cos \theta = N ------ (2)\)

where;

\(\theta\) = angle of AB is associated with the horizontal;

\(F_{AB}\) = force exerted by AB

Let's take a look at the equilibrium of forces along the vertical direction.

\(\sum F_y = \sum (F_y)_{eff} \\ \\ F+F_{AB} sin \theta - W = 0\\ \\ \mu_k N + F_{AB} sin \theta -mg =0 \\ \\ F_{AB} sin \theta = mg - \mu_kN-------(3)\)

By dividing (3) by (2), we get:

\(\dfrac{F_{AB} sin \theta }{F_{AB} cos \theta} = \dfrac{mg - \mu_k N}{N} \\ \\ tan \theta = \dfrac{mg-\mu_kN}{N} \\ \\ Ntan \theta = mg - \mu_kN \\ \\ N(tan \theta + \mu_k ) = mg \\ \\ N = \dfrac{mg}{tan \theta + \mu_k}\)

By replacing the obtained value of N into:

\(F = \mu_k N\)

we have:

\(F = \mu_k (\dfrac{mg}{tan \theta + \mu_k}) \\ \\ \\ F = \dfrac{mg \mu_k}{tan \theta + \mu_k}\)

Moment about center A can be expressed as:

\(\sum M_A = \sum (M_A) _{eff} \\ \\ Fr = I \alpha\\ \\ \alpha = \dfrac{Fr}{I}\)

where;

\(\alpha\) = angular acceleration of the disc

I = mass moment of inertia

r = radius of disc

By replacing F and I; ∝ becomes:

\(\alpha = \dfrac{\bigg( \dfrac{mg \mu_k}{tan \theta + \mu_k} \bigg) r}{\dfrac{1}{2}mr^2}\)

\(\alpha = \dfrac{2g}{r} \dfrac{\mu_k}{tan \ \theta + \mu_k}------- (4)\)

where;

g = 9.8 m/s²

r = 0.18 m

\(\mu_k = 0.54\)

θ = 60°

\(\alpha = \dfrac{2(9.8)}{0.18} (\dfrac{0.54}{tan \ 60+ 0.54})\)

\(\mathbf{\alpha = 25.88 \ rad/s^2 }\)

Answer:

c = 3.00E8 m/s      speed of light

c = f * λ        frequency ^ wavelength

f = c / λ  = 3.00E8 m/s / .01 m = 3.00E10 / sec

f = 30,000,000,000 /sec

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

true

Explanation:

True since coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.

coulombs formula is given by

\(F= \dfrac{K\times q_{1} \times q_{2}}{r^{2} }\)

Now it states that if two charged particles are separated by the distance r and having same or opposite charge will attract or repel each other.

The intensity of the force depend upon the distance and the nature of the charge.

Hence coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.

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Answer:

Not one of your choices .....closest is 90 N

Explanation:

Saturn g = 10.44 m/s^2

10 kg * 10.44 m/s^2 = 104.4 N

The Environmental Justice Movement recognizes that historically environmental burdens are often borne by economic, social and environmental justice.

In order words, it gives fair treatment of justice to its system socially, economically, racially and environmental wise

Environmental justice can simply be defined as the act of being fair to everyone in the environment in aspect of life; be it economically, socially, racially, or even origin wise

This movement of environmental justice is characterized by treating everyone equally regardless of the similarities and differences which exist between nations, countries, individuals, organizations.

For every system who obvserves this impartial movement, they usually, frequently and most of the time gives balanced humanitarian service which helps to promote them in aspect of life as this does not discriminate anyone in any manner

So therefore, the Environmental Justice Movement recognizes that historically environmental burdens are often borne by economic, social and environmental justice.

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Answer:

D.-4.798m/s

Explanation:

Greetings !

Given values

\(u= 4ms \\ a = 0.21ms {}^{2} \\ t = 3.8sec\)

Solve for V of the given expression

Firstly, recall the velocity-time equation

\(v = u + at\)

plug in known values to the equation

\(v = (4) + (0.21)(3.8)\)

solve for final velocity

\(v = 4.792ms\)

Hope it helps!