which characteristics are common to amphibians, lemurs, and humans?

vertebrae, tetrapod, hair
amniotic egg, hair, biped
tetrapod, vertebrae
tetrapod, hair

The magnification is approximately 0.1047 or 0.105, given an object 1.60 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high.

The magnification is the ratio of the height of the image to the height of the object. In this case, the height of the object is 1.60 cm and the height of the image is 0.167 cm. Therefore, the magnification can be calculated as:

Magnification = height of image / height of object
Magnification = 0.167 cm / 1.60 cm

Simplifying this fraction gives a magnification of approximately 0.1047 or 0.105, to three significant figures.

This means that the image appears smaller than the actual object, as the magnification is less than 1. In other words, the image is reduced in size when it is reflected off the cornea.

It is worth noting that this question relates to the field of optics, which involves the study of light and how it interacts with different materials. The measurement of the reflected image in this question is an example of how light can be reflected off surfaces and used to create images, which is a key concept in optics.

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Answer:

Do you have a list of all the energies?

Bomb exploding would use chemical reaction (ammonium nitrate for ex), then thermal energy from heat generated, then kinetic energy from the blast overpressure/schockwave.

Answer:

it was equal to the weight of the object

hope it helped ☺️

The angle of the second-order bright fringe in a double-slit experiment. A monochromatic beam of light with a wavelength of 500nm illuminates a double slit with a separation of 2.00x10⁻⁵m. The possible answer choices for the angle are given.

In a double-slit experiment, when a monochromatic beam of light passes through two slits, it creates an interference pattern of bright and dark fringes on a screen. The angle at which the bright fringes occur can be determined using the formula for fringe spacing, given by dsinθ = mλ, where d is the slit separation, θ is the angle, m is the order of the fringe, and λ is the wavelength of light.

In this case, we are interested in the second-order bright fringe, so we set m = 2. The wavelength of light is given as 500nm (or 500x10⁻⁹m), and the slit separation is 2.00x10⁻⁵m.

Rearranging the formula, we have sinθ = (mλ) / d. Plugging in the values, we get sinθ = (2 * 500x10⁻⁹m) / (2.00x10⁻⁵m).

Now, we can find the angle θ by taking the inverse sine (or arcsine) of sinθ. Using a calculator, we can calculate the inverse sine of the value obtained and convert it to radians.

By comparing the calculated angle with the answer choices provided, we can determine the correct answer.

In summary, to find the angle of the second-order bright fringe in a double-slit experiment, we use the formula dsinθ = mλ, where d is the slit separation and λ is the wavelength of light. By substituting the given values and solving for θ, we can determine the angle of the second-order bright fringe.

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Option C, an object moving with a constant velocity, is not an example of accelerating motion.

Acceleration refers to the rate at which an object changes its velocity. An object is said to be in a state of accelerating motion if its speed, direction, or both change over time. Acceleration is represented by the symbol a, which is measured in meters per second squared (m/s²).

Constant velocity refers to an object that is moving with a constant speed in a straight line. The object maintains a constant speed because it is not accelerating. In other words, its speed does not change, and it moves in a straight line with a constant speed. Therefore, option C, which describes an object moving with a constant velocity, is not an example of accelerating motion.

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Answer:

I think true..... :))))))))))

Answer:

“Eat more delicious whole-food plants at every meal and snack. Fruits, vegetables, whole grains, nuts and seeds are packed with nutrients and contain satisfying fiber that is good for digestion, disease prevention and sustained energy.

Explanation:

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy (\(K\)), in joules, is entirely translational, whose formula is:

\(K = \frac{1}{2}\cdot m\cdot v^{2}\) (1)

Where:

\(m\) - Mass, in kilograms.

\(v\) - Speed, in meters per second.

If we know that \(m = 0.5\,kg\) and \(v = 35\,\frac{m}{s}\), then the kinetic energy of the baseball thrown by the player is:

\(K = \frac{1}{2}\cdot m \cdot v^{2}\)

\(K = 306.25\,J\)

The kinetic energy of the baseball is 306.25 joules.

Answer:

social justice is the correct answer

Explanation:

The exercise tells us that the electric field is given by the following equation:

And it also gives us, A and Q. Thus, our electric field inside the capacitor is:

As we know, the electric force can be written as:

The charge of an electron is a constant, which is q=1.6*10^(-19) C.

Finally, our force can be written as:

Our final answer is 0.00001149 micro Newtons

The momentum and direction of the third piece with respect to the 100 g piece is 0.11 kgm/s at 11 degrees.

The momentum and direction of the third piece with respect to the 100 g mass is determined by applying the principle of conservation of linear momentum.

Pi = Pf

where;

0 = P₁ + P₂ + P₃

where;

-P₃ = P₁ + P₂

-P₃x = P₁cosθ + P₂Cosθ  --(1)

-P₃y =  P₁sinθ + P₂sinθ  --(2)

-P₃x = (0.1 x 1.2 x cos0) + (0.03 x 0.8 x cos120)

-P₃x = 0.12 - 0.012

-P₃x = 0.108 kgm/s

P₃x = -0.108 kgm/s

-P₃y =   (0.1 x 1.2 x sin0) + (0.03 x 0.8 x sin120)

-P₃y =  0.0208 kgm/s

P₃y =  -0.0208 kgm/s

\(P_3 = \sqrt{P_3x^2 + P_3y^2} \\\\P_3 = \sqrt{(-0.108)^2 + (-0.0208)^2} \\\\P_3 = 0.11 \ kgm/s\)

\(tan \ \theta = \frac{P_3y}{P_3x} \\\\\theta = tan^{-1} (\frac{P_3y}{P_3x} )\\\\\theta = tan^{-1} (\frac{-0.0208}{-0.108} )\\\\\theta = 11\ ^0\)

with respect to 100 g, direction of third piece is 11⁰

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Answer:

collision between truck

Explanation:

Answer. Collision between trucks, because more is the mass, more is the inertia and therefore more is the momentum. Mass of the trucks is more than that of cars so collision of trucks will cause more damage.

Answer:

Average velocity = 82.22 km/h

Explanation:

Average Velocity = (Total distance)/(Total time)

When the car was first driven for 1 h with a velocity of 100 km/h towards the south

Velocity = Distance/time

Distance = Velocity * time

Distance covered, D1 = 100 * 1 = 100 km

When the car was driven for 0.50 h with a velocity of 50 km/h towards the north

Distance = Velocity * time

Distance covered, D2 = 50 * 0.5 = 25 km

When the car was driven for 0.75 h with a velocity of 80 km/h towards the south

Distance = Velocity * time

Distance covered, D3 = 80 * 0.75 = 60 km

Total distance traveled = D1 + D2 + D3

Total distance traveled = 100 + 25 + 60

Total distance traveled = 185 km

Total time taken = 1 + 0.5 + 0.75

Total time taken = 2.25 h

Average velocity = Total distance/ total time

Average velocity = 185/2.25

Average velocity = 82.22 km/h

Answer:

Density Definition: Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol: D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Answer:

Answer :-  150.79cm2

Explanation:

                                               A=2πrh+2πr2

                                                 2·π·2·10+2·π·22

                                                    150.79645cm²

Answer:

the TSA of the cylinder is 150.8 square cm

Answer:

The value  is  \(a = 6.676 \ m/s^2\)  

Explanation:

From the question we are told that  

  The length of the runways is  \(l =145 \ m\)

  The required ground of a small plane is  \(v = 44 \ m/s\)

Generally from kinematics equation

       \(v^2 = u^2 + 2as\)

Here u  is the initial speed of the plane which is 0 m/s

so

      \(44^2 = 0^2 + 2 * a* 145\)

=>  \(a = 6.676 \ m/s^2\)  

Answer:

yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!

Explanation:

Answer:

the answer to this would be D.

Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck

Explanation:

Mass, m of the computer is 0.82kg.

Given the following data:

Weight of computer = 8N

Acceleration due to gravity = 9.8m/s

Weight is the product of the mass of an object or body multiplied by gravity.

Mathematically, weight is:

\(\text{W = mg}\)

Where:

W represents the weight of a computer measured in Newton.

m represents the mass of a computer measured in kilograms.

a represents acceleration due to gravity measured in meter per seconds.

\(\text{m}=\frac{\txet{W}}{9}\)

\(\text{m}=\dfrac{8}{9.8}\)

\(\text{m}=0.81632653\thickapprox0.82\)

Mass, m = 0.82kg.

Therefore, the mass of the computer is 0.82kg.

The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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Answer: The cost of using the microwave oven for 30 minutes every day for 9 days is $0.57

Explanation: The GRASS method is used to calculate the cost of using an appliance by multiplying the power rating of the appliance (in kW) by the hours of use, and then multiplying that by the rate per kWh.

Here's the calculation:

Power rating: 0.62 kW

Time of use: 30 minutes/day for 9 days = 30/60*9 = 13.5 hours

Cost per hour = 0.62 * 6.8 / 100 = 0.04236

Total cost = 0.04236 * 13.5 = $0.57

The  magnitude of the maximum transverse velocity of the medium at a given point along the wave depends on the amplitude of the wave and the frequency of the wave, and can be calculated using the formula v_max = 2πfA.

The magnitude of the maximum transverse velocity of the medium at a given point along the wave depends on the amplitude of the wave and the frequency of the wave.

The formula for the velocity of a wave is given by:

v = λf

where v is the velocity of the wave, λ (lambda) is the wavelength of the wave, and f is the frequency of the wave.

The formula for the amplitude of a wave is given by:

A = y_max - y_min

where A is the amplitude of the wave, y_max is the maximum displacement of the medium from its equilibrium position, and y_min is the minimum displacement of the medium from its equilibrium position.

The maximum transverse velocity of the medium at a given point along the wave can be calculated using the following formula:

v_max = 2πfA

where v_max is the maximum transverse velocity of the medium, f is the frequency of the wave, and A is the amplitude of the wave.

Therefore, the magnitude of the maximum transverse velocity of the medium at a given point along the wave depends on the amplitude of the wave and the frequency of the wave, and can be calculated using the formula v_max = 2πfA.

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To determine the coefficient of friction for the box weighing 18 Newtons and requiring a force of 3 Newtons to drag it after being coated with Teflon®, you can use the formula:

Coefficient of friction (μ) = Force of friction (F_ friction) / Normal force (F_ normal)

In this case, the Force of friction (F_ friction) is the force required to drag the box, which is 3 Newtons. The Normal force (F_ normal) is equal to the weight of the box, which is 18 Newtons.

Plug these values into the formula:

μ = 3 N / 18 N
μ = 0.1667

The coefficient of friction for the box coated with Teflon® is approximately 0.1667.

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The uneven surface of a broken quartz crystal is a description of its "fracture" property.

Fracture refers to the way a mineral breaks or cleaves when subjected to external forces or stress.

Unlike minerals that exhibit cleavage, which break along planes of weakness, minerals with fracture do not break along smooth, flat surfaces.

In the case of quartz, which is a crystalline mineral, its fracture can be described as conchoidal.

Conchoidal fracture is characterized by the production of curved, shell-like surfaces when the mineral breaks. These surfaces may appear uneven, jagged, or curved, resembling the shape of a shell or a broken piece of glass.

The conchoidal fracture property of quartz is a result of its atomic structure and the arrangement of its silicon and oxygen atoms.

When external forces cause the crystal lattice of quartz to break, the fracture occurs along irregular paths, resulting in the characteristic uneven surface.

The conchoidal fracture property of quartz is not unique to this mineral and can be observed in other materials like glass, obsidian, and flint.

It is a valuable diagnostic property used by geologists and mineralogists to identify and distinguish different minerals based on their fracture patterns.

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The current drawn by a microwave is greater than the amount of current used by an electric bulb, hence the microwave consumes more power.

The amount of energy dissipated by an electrical appliance is the calculated using the following formulas;

P = I²R

where;

The current drawn by a microwave is greater than the amount of current used by an electric bulb, hence the microwave consumes more power.

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1) The number of photons in each beam is what determines the amount of energy each beam carries. A beam of red light contains more photons than a beam of blue light, but each photon in the blue beam carries more energy than each photon in the red beam. Therefore, the two beams can carry the same amount of energy despite having different energies per photon.

2) Reflecting telescopes have two advantages over refractors. They are cheaper to manufacture, and they do not suffer from chromatic aberration.

3) Refraction is the bending of light as it passes from one medium to another. Refraction occurs because light waves travel at different speeds through different materials. The amount of refraction depends on the angle at which the light passes through the medium.

4) The image of a star is larger in the focal plane of the larger telescope. This is because the larger telescope collects more light than the smaller telescope, which means that the image is brighter and has a higher signal-to-noise ratio.

5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals. A higher quantum efficiency means that more of the incoming

photons are detected, which makes it easier to detect faint astronomical objects.

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1) The number of photons in each beam is what determines the amount of energy each beam carries.

2) Reflecting telescopes have two advantages over refractors.

3) Refraction is the bending of light as it passes from one medium to another.

4) The image of a star is larger in the focal plane of the larger telescope.

5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals.

1) The number of photons in each beam is what determines the amount of energy each beam carries. A beam of red light contains more photons than a beam of blue light, but each photon in the blue beam carries more energy than each photon in the red beam. Therefore, the two beams can carry the same amount of energy despite having different energies per photon.

2) Reflecting telescopes have two advantages over refractors. They are cheaper to manufacture, and they do not suffer from chromatic aberration.

3) Refraction is the bending of light as it passes from one medium to another. Refraction occurs because light waves travel at different speeds through different materials. The amount of refraction depends on the angle at which the light passes through the medium.

4) The image of a star is larger in the focal plane of the larger telescope. This is because the larger telescope collects more light than the smaller telescope, which means that the image is brighter and has a higher signal-to-noise ratio.

5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals. A higher quantum efficiency means that more of the incoming

photons are detected, which makes it easier to detect faint astronomical objects.

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