Answer: the middle
Explanation:
Drag each tile to the correct location.
The image shows the Moon orbiting Earth. Match each Moon phase to the correct location, as seen by an observer on Earth.
Answer: Third Option: Top
First Option: Top Right
Second Option: Right Middle
Last/Fourth Option: Bottom
Explanation:
Answer:
1st one is top right
2nd one is right, directly across from the full moon
3rd one is bottom
4th one is top
Explanation:
It is just a cycle of the moon you can see the way it goes with the shadows.
Which process is represented by the picture below?
A. Vegetative Propagation
B. Meiosis
C. Fertilization
D. Binary Fission
HELPP MEEE
Answer:
Meiosis is the correct answer
QUESTION 11 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the allele's frequencies experimentally derived, calculate the frequency of the H4/H5 genotype that would be expected if the class were a population in Hardy-Weinberg equilibrium. 1. 0.28 2. 0.51 3. 0.19 4. 0.72 5. 0.14 6. 0.24 7. 0.41 QUESTION 12 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the genotype frequencies derived assuming that the class were a population in Hardy-Weinberg equilibrium, calculate the number of H4/H4 individuals that would be expected in the class (rounded numbers). 1. 19 2. 57 3. 72 4. 147 5. 171 6. 120 7. 96 QUESTION 13 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and comparing the observed and the expected number of individuals for the three genotypes, calculate the value of the Chi-square statistic 1. 2.69 2. 0.05 3. 28.67 4. 14.59 5. 0.50 6. 22.31 7. 3.84 QUESTION 14 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium, which is the (correct) null hypothesis tested by Chi-square? 1. The whole class represents a population that is in Hardy-Weinberg equilibrium 2. The whole class represents a population that may not be in Hardy-Weinberg equilibrium 3. The whole class represents a population that is not in Hardy-Weinberg equilibrium 4. The whole class represents a population that may be in Hardy-Weinberg equilibrium QUESTION 15 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and calculating the Chi-square statistic, do you reject or fail to reject the null-hypothesis? 1. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis. 2. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom, I conclude that P>0.05. Hence, I fail to reject the null hypothesis. 3. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I reject the null hypothesis. 4. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I fail to reject the null hypothesis.
According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.
When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.
A) Option 7 is the correct answer ⇒ 0.41
B) Option 6 is the correct answer ⇒ 120
C) Option 7 is the correct answer ⇒ 3.84
D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium
E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.
-------------------------------------------
Allelic frequencies in a locus are represented as p and q, referring to the
allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us dominant), 2pq (H3ter0zygous), q² (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same
allelic frequencies generation after generation.
The sum of the allelic frequencies equals 1, this is p + q = 1.
In the same way, the sum of genotypic frequencies equals 1, this is
p² + 2pq + q² = 1
Being
p the dominant allelic frequency,
q the recessive allelic frequency,
p² the h0m0zyg0us dominant genotypic frequency
q² the h0m0zyg0us recessive genotypic frequency
2pq the h3ter0zyg0us genotypic frequency
Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:
H4/H4 = 125 individuals;
H4/H5 = 85 individuals;
H5/H5=24 individuals.
⇒ Total number of individuals= 125 + 85 + 24 = 234
⇒ Genotypic frequencies, F(xx):
F(H4/H4) = 125/234 =0.534
F(H4/H5) = 85/234 = 0.363
F(H5/H5) = 24/234 = 0.102
⇒ Allelic frequencies, f(x):
f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716
f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284
Questions:
A) According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,
F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.
-------------------------------------------------------------------------------------------------------------
B) According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,
p = 0.716
p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.
To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of
individuals.
H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120
Option 6 is the correct answer.
-----------------------------------------------------------------------------------------------------------
C) Up to here we know that 2pq = 0.41 and p² = 0.513
Now we need to calculate q ²
q = 0.284, then q² = 0.284² = 0.08
These are the expected frequencies if the population was in H-W equilibrium.
The expected number of individuals with each genotype are:
H4/H4 = 0.513 x 234 = 120 individuals
H4/H5 = 0.41 x 234 = 96 individuals
H5/H5= 0.08 x 234 = 18 individuals
The observed number of individuals with each genotype are:
H4/H4 = 125 individuals
H4/H5 = 85 individuals
H5/H5=24 individuals
X² = ∑ (Observed - Expected)²/Expected)
X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)
X² = 0.21 + 1.26 + 2 =
X² = 3.47
The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.
-------------------------------------------------------------------------------------------------------------
D) The correct answer is 1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium
The null hypothesis always predict that populations are in H-W equilibrium.
-----------------------------------------------------------------------------------------------------------
E)
X² = 3.47
Freedom degrees = n - 1 = 3 - 1 = 2
Table p value: 7.82
Significance level, 5% = 0.05
Table value/Critical value = 5.991
5.991 > 0.347
Meaning that the difference between the observed individuals and the expected individuals is statistically significant. Not probably to have differe by random chances. There is enough evidence to reject the null
hypothesis.
Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.
Related Link: https://brainly.com/question/419732?referrer=searchResults
A water-soluble hormone approaches its target cell. What can we conclude about this hormone?
The hormone originated in the ovaries or testes
The hormone will be a non-steroid
The hormone is hydrophobic and will need to combine with protein molecules to enter the cell
The hormone released will signal the beginning of puberty
If a water-soluble hormone approaches its target cell, it can be concluded that the hormone will be a non-steroid (option B).
What is an hormone?An hormone is any substance produced by one tissue and conveyed by the bloodstream to another to effect physiological activity.
Hormones are usually proteinous in nature and can either be water-soluble or fat-soluble depending on whether it can dissolve in water or fat respectively.
According to this question, a water-soluble hormone approaches its target cell. This suggests that that hormone must be a non-steroid i.e. does not contain fat.
Learn more about water-soluble hormones at: https://brainly.com/question/14267093
#SPJ1
GIVING BRAINLIEST..
1.Scientists have evidence that the universe is [expanding/shrinking].
2.Objects moving away from Earth appear [blue/red], and objects moving toward Earth appear [blue/red].
3.Light from most other galaxies appears [blue/red], which makes sense if the universe is [collapsing inward/spreading out]
Answer:
(1) expanding
(2) red, blue
(3) red, spreading out
hope it helps you
Review the equations below used to describe photosynthesis and respiration (as provided in the background section of this experiment). Why was it important to use germinated seeds without leaves for this experiment? The equation used to describe the process of photosynthesis is shown below: 6 CO 2 (Carbon Dioxide) + 6 H 2 O (Water) + Light Energy (Sunlight) → C 6 H 12 O 6 (Glucose) + O 2 (Oxygen) The general equation used to describe the overall process of cellular respiration is shown below, where glucose and oxygen react to produce carbon dioxide, water, and ATP (Energy). C 6 H 12 O 2 + 6 O 2 → 6 CO 2 + 6 H 2 O + Energy ⎛ ⎝ Energy = 36-38 molecules ATP 1 molecule of C 6 H 12 O 6 ⎞ ⎠
Answer:
Germinated seeds without leaves are used in the experiment in order to find good results.
Explanation:
It is very important to use germinated seeds without the presence of leaves in order to carried out the experiment because if the leaves are present, the process of photosynthesis started which automatically increases the rate of respiration of the seed. This test is performed in order to determine the rate of respiration not photosynthesis. So leaves will not used in the experiment in order to avoid any problem with the results.
The cheek smear slide is made by taking a q-tip or toothpick, rubbing it on the inside of your mouth (to remove cells) and then wiping or smearing it onto a blank slide. A stain is used on the cells so that you can see them, otherwise, they would be see-through. Look at the cheek smear slide using the 10x objective (total magnification of 100x). Approximately how many cells do you see inside the red circle
Answer:
The number of cells that will be viewed will depend on the size of the cells and the size of the red circle on the slide.
Explanation:
The cells have different sizes and this influences the number of cells that you will be able to view under a microscope.
The intensity with which the smear was made will also influence the number of cells viewed, as well as the quality and quantity of dye you used on the slide.
In summary, we can say that the number of cells that you will be able to visualize is relative and only the experience, in itself, will be able to determine a number.
what is your mother name
Answer:
my mother's name is sophia
Answer:
UR MOM
Explanation:
Explain the light detection technique of photo emissive detection
Photo emissive detection converts light energy into electrical signals using a photo cathode that emits electrons when photons strike it, allowing for light intensity measurement.
Light detection using photo emissive detection involves the conversion of light energy into electrical signals through a photo emissive material. This technique is based on the phenomenon of the photoelectric effect, where photons of light can cause the emission of electrons from a material's surface.
Photo emissive detectors typically consist of a photo cathode made of a material with low work function, such as cesium or potassium compounds. When photons of sufficient energy strike the photo cathode, they transfer their energy to the electrons within the material, causing some electrons to be emitted from the surface.
The emitted electrons are then accelerated towards an anode electrode by an electric field, creating a current flow. This current is directly proportional to the intensity of the incident light, allowing for the measurement of light levels.
To improve the efficiency of the photo emissive detection, a voltage bias can be applied between the photo cathode and the anode. This accelerates the emitted electrons and increases the overall sensitivity of the detector.
Photo emissive detection is commonly used in applications such as photomultiplier tubes (PMTs) and image intensifiers. PMTs are used to detect low levels of light and are widely employed in scientific research, medical imaging, and night vision devices. Image intensifiers amplify incoming light to produce brighter images in night vision goggles and other imaging systems.
In summary, photo emissive detection is a light detection technique that relies on the photoelectric effect to convert light energy into electrical signals. It utilizes a photo cathode, which emits electrons when exposed to photons, and an anode to collect these emitted electrons, resulting in a measurable current.
For more such questions on light energy, click on:
https://brainly.com/question/28892150
#SPJ8
Food grain are stored in the blank for future use
Food grains are stored in the warehouse or granary for future use to maintain the production and supply of food in the country and it is also considered as a security measure for the farmers and government agencies.
The grain storage system is important to preserve the nutritional value of the food grains and avoid the losses incurred due to pests, rodents, and other natural calamities such as floods and droughts.
Food grains are the essential components of the human diet, and they need to be stored with utmost care and caution. The quality of food grains plays a crucial role in ensuring the food security of the country. The farmers and the government agencies take care of storing the food grains in the warehouses, which are usually built in the proximity of the grain-producing areas. These warehouses should be equipped with the latest technologies and tools to ensure the safe storage of food grains.
The government also provides subsidies and financial support to the farmers to build their warehouses to store the food grains. The food grain storage system is crucial for ensuring the continuous supply of food and for the survival of the farmers, especially in the developing countries.
For more such questions on production , visit:
https://brainly.com/question/16755022
#SPJ8
How does carbon dioxide affect the earth and Its atmosphere?
Increasing carbon dioxide in the earth's atmosphere is responsible for the greenhouse effect.
Decreasing carbon dioxide in the earth's atmosphere is responsible for the increase in sea levels.
Increasing carbon dioxide in the earth's atmosphere reduces the temperature on the earth.
Decreasing carbon dioxide in the earth's atmosphere is responsible for melting the polar ice caps.
Answer:
Increasing carbon dioxide in the earth's atmosphere is responsible for the greenhouse effect.
Explanation:
Carbon dioxide is a greenhouse gas. Greenhouse gases trap heat in the Earth's atmosphere which causes the earth to warm up. This is called the greenhouse effect.
How do you feel about the way people worldwide view the problem of Climate Change?
Answer:
There is a wide range of views on climate change across the world. While many people understand and acknowledge the scientific evidence that climate change is happening and that human activities are contributing to it, others are more skeptical and deny the reality of climate change altogether. Some people may also acknowledge climate change but are unsure of how to address it, while others may recognize the issue but feel that it is not a priority compared to other pressing problems.
Overall, the level of concern and action taken on climate change varies greatly between different countries and communities. Some countries have made significant strides in reducing their carbon emissions and adopting more sustainable practices, while others have been slower to act or have even actively resisted climate action.
It is clear, however, that climate change is a global problem that affects us all, and concerted global action is needed to mitigate its effects and ensure a sustainable future for all.
What is some strengths as a math learner
Help stepbro im stuck in the washer
Answer:
I'LL HELP YOU......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................NOT
Which of the following cells do not have specialized tasks in an organism? 1.) prokaryotic cells 2.) eukaryotic cells 3.) animal cells 4.) plant cells
Answer:
A. Prokaryotic cells
Explanation:
Prokaryotic cells don't have organelles
Which of the following did you include in your response? Check all that apply.
In type 1, the body does not produce insulin.
In type 2, the body does produce insulin, but the body’s cells do not recognize its presence or the body doesn’t produce enough insulin.
Type 1 is diagnosed in children and is fairly rare.
Type 2 is the most common type of diabetes.
The pancreas is no longer able to create insulin in people with type 1 diabetes.
When you have type 2 diabetes, your pancreas initially generates insulin, but your body's cells can't effectively utilize it. Insulin resistance is what causes this.
Your pancreas naturally produces the hormone insulin, which regulates how your body consumes and stores blood sugar (glucose). It works like a key to letting glucose into your body's cells.
A crucial component of metabolism is insulin. Your body couldn't function without it.
Your pancreas releases insulin when you eat to assist your body in converting glucose, a form of sugar contained in carbohydrates, into energy. It also facilitates energy storage.
Insulin-dependent diabetes or juvenile diabetes were previous names for type 1 diabetes. Though it typically appears in kids, teens, and young adults, it can occur at any age.
About 5–10% of patients with diabetes have type 1 diabetes, which is less frequent than type 2.
Learn more about Diabetes here:
https://brainly.com/question/10495158
#SPJ9
_ is a pesticide that caused serious problems for birds insects and people
Answer: Carbamates
Explanation: Carbamate insecticides have a mode of action similar to the organophosphates and, like the organophosphates, some kill birds at low doses. Carbofuran, which has been estimated to kill one to two million birds annually in the U.S., is probable the best known example.
and
wans
Using the 10% rule when
studying trophic pyramids, if
the primary consumers obtain
100 Joules of energy from the
autotrophs, how much energy
is then passed on to the
carnivores?
A. 100 Joules
B. 0.1 Joules
C. 10 Joule
Using the 10% rule when studying trophic pyramids, if the primary consumers obtain 100 Joules of energy from the autotrophs Carnivores receive an energy transfer of 10 Joules.
Trophic level is referred to as the level of an ecosystem as well as a nutritive chain or food chain.
What does the trophic level 10% rule mean?
The trophic level 10% rule states that only 10% of the energy in an ecosystem will be transferred from one trophic level to the next.
Based on their eating habits, a chain of organisms is separated into various tiers. The producers, or green plants, make up the first and lowest stratum, the primary consumers or the herbivores make the 2nd trophic level and the carnivores or secondary consumers make up the 3rd trophic level and within these energy is transferred.
In this question, the herbivores obtain 100J of energy from autotrophs now according to 10% law only 10% of this energy will be transferred to carnivores thus,
10 = \(x\)/100 ×100
\(x\)= 10J
For more information regarding 10% rule in trophic level, visit:
brainly.com/question/11665402
#SPJ1
Different cell types and tissues express different sets of genes; for example, some genes are expressed primarily in the heart, others primarily in the brain, and still others primarily in the liver. This is possible because all of these cell types have ____________.
a. different sequence variants that control gene expression
b. different ordering of genes on chromosomes
c. different histone and DNA modifications
d. different sets of genes
Answer:
d.Different sets of genes.
Explanation:
A cell normally only expresses a percentage of its genes and various cell types are created by the expression of distinct gene sets. In addition, in response to changes in their environment, cells can alter the pattern of genes they express, such as signaling from neighboring cells.
Ld50 is 20 mg per kilogram what for this mean?
Answer: LD means lethal dose. LD50 is the amount of a material, administered at once to cause the death of half (50%) of a group of test organisms. A test which shows that LD50 of a certain chemical is 20 mg per kg means that 20 milligrams of that chemical for every 1 kilogram body weight of the test animal when administered in one dose, causes the death of 50% of the test group.
Explanation:
Four cells are produced at the
end of meiosis II.
Which of the following is
TRUE about these cells?
A. They are genetically identical.
B. They each have 46 chromosomes.
C. Each cell has 23 chromosomes and is
genetically different from the others.
1. Muscles move tendons attached to bone by performing an action called _______.
2. Myosin and ______ are two proteins that interact to contract muscles.
3. _______ connect muscles to bones.
4. The layer of skin that grows new cells rapidly is called the _______.
5. The _______ is the layer of skin that regulates body temperature.
6. _______ can occur when pores become clogged with dirt or oil, or become infected.
7. Explain what happens at a microscopic level inside a muscle fiber during contraction, beginning with the nerve impulse.
1. Contraction
2. Actin
3. Tendons
4. Epidermis
5. Dermis
6. Acne
7. A nerve signal from the brain arrives at the intersection of the nerve and muscle cells and releases acetylcholine from the neuron. This triggers chemical changes in the muscle cell involving ions, including Ca2+. Calcium triggers the thick filaments, made of myosin, to attach to the thin filaments, made of actin, in the muscle cell, and the myosin pulls the actin toward the center of the muscle cell. ATP causes the release of the actin fibers, allowing the muscle to relax and the process to begin again.
For Penn Foster.
Answer:
1. Contraction
2. Actin
3. Tendons
4. Epidermis
5. Dermis
6. Acne
7. A nerve signal from the brain arrives at the intersection of the nerve and muscle cells and releases acetylcholine from the neuron. This triggers chemical changes in the muscle cell involving ions, including Ca2+. Calcium triggers the thick filaments, made of myosin, to attach to the thin filaments, made of actin, in the muscle cell, and the myosin pulls the actin toward the center of the muscle cell. ATP causes the release of the actin fibers, allowing the muscle to relax and the process to begin again.
Explanation:
pppp
Two genes affect nest-building behavior in a rodent, but a dihybrid cross (SsBb x SsBb) produces only three phenotypes, nests built in trees, nests built on the ground, and nests built underground. Which of the following might explain this result? Choose all that apply. O duplicate dominant epistasis O dominant epistasis O recessive epistasis O duplicate recessive epistasis
In the question, three phenotypes describe the observation of dominant epistasis or recessive epistasis because all can create three phenotypes ( Dominant epistasis 12:3:1 and recessive epistasis 9:3:4 ), hence options B and C are correct.
What is epistasis?It is the kind of interaction in which the effect of the gene mutation depends on the mutation of another gene.
In normal crossing over in a dihybrid cross it represents the ratio of (SsBb x SsBb) makes four phenotypes (9:3:3:1), but here it produces nests built in trees, nests built on the ground, and nests built underground, which are three phenotypes shows epistasis.
Therefore, dominant epistasis and recessive epistasis is the correct observation.
Learn more about epistasis, here:
https://brainly.com/question/30651608
#SPJ1
PLEASE HELP ANSWER THESE TWO QUESTIONS! Thanks
1. Briefly describe the process of the dehydration synthesis for carbohydrates illustrated above:
2. Briefly describe the process of the hydrolysis reaction for carbohydrates illustrated above:
Explanation:
Dehydration Synthesis : Two monosaccharides (simple sugars) are joined together to form a disaccharide (double sugar) molecule. During this reaction, a molecule of water is removed, and a covalent bond is formed between the two monosaccharides. One monosaccharide loses a hydroxide group (-OH) from its carbon atom, while the other monosaccharide loses a hydrogen ion (H+), and the two react to form a covalent bond between the two carbon atoms. This process requires energy to occur.
Hydrolysis : Opposite process of dehydration synthesis, and it is the chemical reaction by which a disaccharide is broken down into two monosaccharides. During hydrolysis, a molecule of water is added to the disaccharide, causing the covalent bond between the two monosaccharides to break. One monosaccharide molecule gains a hydroxide group (-OH), while the other gains a hydrogen ion (H+), which were previously lost during dehydration synthesis. This process releases energy in the form of ATP
Plz help me well mark brainliest if correct!!...
Quagga mussels, an invasive species of mollusk originally from
Russia, have been introduced to the lake after being carried in on
the hulls of boats. An assessment of the size of the quagga
mussel problem is needed, along with suggestions to curb their
population growth.
what field of science is this?
This is a problem in the field of ecology.
The problem of quagga mussels in the lake is an ecological issue that requires scientific assessment and management.
It falls under the discipline of ecology, which studies the relationships between organisms and their environment.
Ecologists investigate the impacts of invasive species on the ecosystem and devise strategies to control their spread and minimize their effects.
In this case, scientists will need to examine the size of the quagga mussel population, their distribution, and their ecological interactions with native species.
They will also need to recommend measures to prevent further introduction of quagga mussels and to manage their population growth, such as using chemical treatments or biological controls.
For more such questions on ecology, click on:
https://brainly.com/question/842527
#SPJ11
Photosynthesis makes glucose; cellular respiration breaks glucose
Answer:Photosynthesis makes the glucose that is used in cellular respiration to make ATP. The glucose is then turned back into carbon dioxide, which is used in photosynthesis. While water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.
Explanation:
Answer:
Correct. The answer to 'Photosynthesis makes the glucose that is used in cellular respiration to make ATP' is True.
-Ck-12, 2022
Have a great day! (:
describe a mercurial clinical thermometer.
Answer:
➢ In a mercury thermometer, a glass tube is filled with mercury and a standard temperature scale is marked on the tube. With changes in temperature, the mercury expands and contracts, and the temperature can be read from the scale. Mercury thermometers can be used to determine body, liquid, and vapor temperature.
\(Into \: your Arms\)
#CarryOnLearning
Matter moves in the same direction as wave travels
Answer:
Not all matter and waves move the same direction, some do though
Explanation:
transverse wave--matter in the medium moves back and forth at right angles to the direction that the wave travels
compressional wave--matter in the medium moves back and forth along the same direction that the wave travels
HELP PLEASE I don’t have the book so if anyone has read this book Assignment Overview
Identify 10 sustainable living goals from The Green Book by Elizabeth Rogers and Thomas M. Kostigen, you must track your progress toward achieving these goals over a period of two weeks.
Note: Tracking your progress over a period of two consecutive weeks is preferred. If you need to break up your time, make sure you track your progress for a minimum of 14 days total.
Instructions
Submit your tracking spreadsheet or journal (whatever you do to track how well you are achieving your ten actions). VERY IMPORTANT TO INCLUDE A FULLY STATED ACTION ON WHAT YOU ARE DOING, not just "napkins"!
You can use a journal. Eg. for two activities over two days (need to continue for 14 days total and mention all 10 activities each day).
For example
Day 1
I used cloth napkins all 3 meals
I took a 5 min shower today
Day 2
I used 20 paper napkins (forgot to bring mine)
I didn't take a shower today
**Example Tracking Journal**
Day 1:
1. I used cloth napkins for all 3 meals today.
2. I took a 5-minute shower today.
3. I turned off lights when not in use throughout the day.
4. I used reusable grocery bags for shopping.
5. I turned off the tap while brushing my teeth.
6. I carpooled to work today.
7. I unplugged electronics when not in use.
8. I composted food scraps from dinner.
9. I set the thermostat to an energy-efficient temperature.
10. I chose items with minimal packaging at the grocery store.
Day 2:
1. I used 20 paper napkins (forgot to bring mine).
2. I didn't take a shower today.
3. I turned off lights when not in use throughout the day.
4. I used reusable grocery bags for shopping.
5. I turned off the tap while brushing my teeth.
6. I walked to work today.
7. I unplugged electronics when not in use.
8. I composted food scraps from dinner.
9. I set the thermostat to an energy-efficient temperature.
10. I chose items with minimal packaging at the grocery store.
...
Day 14:
1. I used cloth napkins for all 3 meals today.
2. I took a 5-minute shower today.
3. I turned off lights when not in use throughout the day.
4. I used reusable grocery bags for shopping.
5. I turned off the tap while brushing my teeth.
6. I carpooled to work today.
7. I unplugged electronics when not in use.
8. I composted food scraps from dinner.
9. I set the thermostat to an energy-efficient temperature.
10. I chose items with minimal packaging at the grocery store.
You can continue to use this template for each day, ensuring that you track your progress for a minimum of 14 days total and mention all 10 activities each day.