When metallic substances lose electrons, they are trying to achieve the electron configuration of what?A. The metal immediately before it on the periodic table.B. The metal immediately after it on the periodic table.C. The nearest halogen.D. The previous noble gas.

Answers

Answer 1

When metallic substances lose electrons, they are trying to achieve the electron configuration of D.

This is because the noble gases have completed outer electron shells, making them stable and unreactive. By losing electrons, metals can achieve a similar electron configuration and become more stable. The previous noble gas. When metallic substances lose electrons, they are trying to achieve the electron configuration of the previous noble gas. This is because noble gases have a stable electron configuration with full outer energy levels, making them less reactive. Metals lose electrons to attain this stable state.

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Related Questions

(1.5 x 10 squared)x(3.5 x 10 to the fifth power)

Answers

Answer:   2.03259656 × 10^8

Explanation:

1.5 x 10 = 15

√(15) = 3.87

put this to the side until we sum everything up..

3.5 × 10 = 35

35 ^ 5 = 52521875

So, now lets sum it all up....

(3.87) x (52521875) = 203259656.25

but in scientific notation it is:  2.03259656 × 10^8

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What is a human and plant example of an organ?​

Answers

Answer: Human organs include the brain, stomach, kidney, and liver. Plant organs include roots, stems, and leaves.

Explanation:

A block with mass = 12 kg rests on a frictionless table and is accelerated by a spring with spring constant k = 4,539 N/m after being compressed a distance x1=0.443m from the spring's unstretched length. The floor is frictionless except for a rough patch a distance d = 2.7 m long. For this rough path, the coefficient of friction is μk=0.4
How much work is done by friction as the block crosses the rough spot?

Answers

The work done by friction as the block crosses the rough spot is approximately 19.6 J.

How did we get the value?

To solve this problem, we need to find the speed of the block when it reaches the end of the rough patch, and then use the work-energy principle to calculate the work done by friction.

First, let's find the maximum compression of the spring using Hooke's Law:

F = -kx

where F is the force exerted by the spring, k is the spring constant, and x is the compression distance.

At maximum compression, the force exerted by the spring is equal and opposite to the weight of the block:

F = mg

where m is the mass of the block and g is the acceleration due to gravity.

Thus, we have:

-kx1 = mg

Solving for x1, we get:

x1 = -mg/k = - (12 kg)(9.81 m/s^2) / (4539 N/m) ≈ -0.246 m

Note that x1 is negative because the spring is compressed.

Now, let's find the speed of the block when it reaches the end of the rough patch. We can use conservation of energy to relate the potential energy stored in the spring to the kinetic energy of the block:

(1/2)kx1^2 = (1/2)mv^2

where v is the speed of the block.

Solving for v, we get:

v = sqrt[(k/m)x1^2] = sqrt[(4539 N/m) / (12 kg)] x 0.246 m ≈ 1.61 m/s

Now we can calculate the work done by friction using the work-energy principle:

W_friction = ΔK = (1/2)mv^2 - 0

where ΔK is the change in kinetic energy of the block.

Since the block starts from rest and ends with speed v, we have:

ΔK = (1/2)mv^2 - 0 = (1/2)(12 kg)(1.61 m/s)^2 ≈ 19.6 J

Therefore, the work done by friction as the block crosses the rough spot is approximately 19.6 J.

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To what temperature will 7900 J of heat raise 3.5 kg of water that is initially at 20.0 ∘ C ? The specific heat of water is 4186 J/kg⋅C ∘ Express your answer using three significant figures. X Incorrect; Try Again; 3 attempts remaining

Answers

The temperature will increase by approximately 0.559 °C.

The temperature to which 7900 J of heat will raise 3.5 kg of water initially at 20.0 °C can be calculated using the equation:

Q = m * c * ΔT,

where Q is the heat energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Rearranging the equation, we have:

ΔT = Q / (m * c).

Substituting the given values:

ΔT = 7900 J / (3.5 kg * 4186 J/kg⋅°C).

Calculating the result:

ΔT ≈ 0.559 °C.

Therefore, the temperature will increase by approximately 0.559 °C.

The specific heat capacity of water represents the amount of heat energy required to raise the temperature of a unit mass of water by one degree Celsius.

In this case, we are given the amount of heat energy (7900 J), the mass of water (3.5 kg), and the specific heat capacity of water (4186 J/kg⋅°C).

By applying the equation for heat transfer, we can solve for the change in temperature (ΔT). Dividing the given heat energy by the product of mass and specific heat capacity gives us the change in temperature.

The result represents the increase in temperature, in degrees Celsius, that will occur when the given amount of heat energy is transferred to the water.

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The gravitational force is 2336 N for an object that is 4.15 x 10^6 m above the surface of the Earth? The radius of the Earth is 6.378 x 10^6 m. (Earth's mass is 5.97 x 10^24 kg) What is the mass of the object above earth?

Answers

Answer:

34kg

Explanation:

what is molecular theory of magnetism

Answers

Answer:

According to this theory:

Each and every molecule of a magnetic substance is a complete magnet in itself, having a north pole and a south pole of equal strength.

In an unmagnetized substance, the molecular magnets are randomly oriented such that they form closed chains.

When the substance is magnetized, the molecular magnets are realigned so that north poles of all molecular magnets point in one direction and south poles of all molecular magnets point in the opposite direction.

When all the molecular magnets are fully aligned, the substance is said to be saturated with magnetism

During heating the magnetized specimen, molecular magnets acquire some kinetic energy. Some of the molecules may get back to the closed chain arrangement. That is why magnetism of the specimen would reduce on heating.

1)A 25 kg air compressor is dragged up a rough incline from r⃗ 1=(1.3ı^+1.3ȷ^)m to r⃗ 2=(8.3ı^+2.6ȷ^)m, where the y-axis is vertical. How much work does gravity do on the compressor during this displacement?
2)A 25 kg box sliding to the left across a horizontal surface is brought to a halt in a distance of 55 cm by a horizontal rope pulling to the right with 16 N tension.How much work is done by tension?How much work is done by gravity?

Answers

As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. Therefore, the total work done by tension is 8.8 Joules.

What is the work done by gravity?

To calculate the work done by gravity on the air compressor during its displacement up the incline, we need to determine the change in gravitational potential energy.

The gravitational potential energy (PE) of an object is given by the equation  \(PE = mgh\), where m is the mass of the object, g is the acceleration due to gravity, and h is the change in height.

Given:

Mass of the air compressor, \(m = 25 kg\)

Acceleration due to gravity, \(g = 9.8 m/s^2\)  (assuming Earth's gravity)

Initial position, \(r⃗ = (1.3ı^ + 1.3ȷ^) m\)

Final position, r⃗\(2 = (8.3ı^ + 2.6ȷ^) m\)

Change in height, h = Final y-coordinate - Initial y-coordinate \(= y2 - y1 = 2.6 m - 1.3 m = 1.3 m\)

Therefore, the work done by gravity on the air compressor is:

\(W = \Delta PE = mgΔh = 25 kg * 9.8 m/s^2 * 1.3 m = 318.5 J\) (rounded to one decimal place)

So, the work done by gravity on the air compressor during its displacement up the incline is approximately 318.5 Joules.

The work done by tension can be calculated using the equation \(W = Fd\), where F is the force applied and d is the displacement.

Given:

Tension force,  \(F = 16 N\) (in the opposite direction of displacement)

Displacement, \(d = 55 cm = 0.55 m\)

Therefore, the work done by tension is:

\(W = Fd = 16 N \times 0.55 m = 8.8 J\)

Therefore, As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction.  the work done by tension is  \(8.8\) Joules.

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The solubility of PbBr2 in water is 4.33 g in 1.0 L of water at 25 °C. What is the value of Ksp for PbBr2?

Answers

The value of Ksp for PbBr2 is 322.6.

How to calculate the value of Ksp for PbBr2?

The solubility product constant Ksp, for PbBr2 can be calculated from the solubility of PbBr2 in water.

The equation for the dissociation of PbBr2 in water is:

PbBr2(s) ⇌ Pb2+(aq) + 2Br-(aq)

The solubility of PbBr2 in water is 4.33 g/L, which means that at equilibrium, the concentration of Pb2+ ion in solution is:

[Pb2+] = solubility of PbBr2 = 4.33 g/L

Since each PbBr2 molecule dissociates into one Pb2+ ion and two Br- ions, the concentration of Br- ions in solution is:

[Br-] = 2 × [Pb2+] = 2 × 4.33 g/L = 8.66 g/L

The Ksp expression for PbBr2 is:

\(Ksp = [Pb2+][Br-]^2\)

Substituting the concentrations of Pb2+ and Br- ions into this expression, we get:

\(Ksp = (4.33 g/L) × (8.66 g/L)^2 = 322.6\)

Therefore, the value of Ksp for PbBr2 is 322.6.

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Three liquids are at temperatures of 2°C, 21°C, and 34°C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 5 C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 30.1°C.
Find the equilibrium temperature when equal masses of the first and
third are mixed.
Answer In units of 'C.

Answers

Answer:

m - mass of each liquids (all masses are equal )

C_1C 1 - specific heat of the first third C_2C 2 - specific heat of the second  liquid

C_3C 3- specific heat of the third liquid

Temperature of liquids: T_1=7 ◦C,T_2=20◦C, T_3=34◦CT

1 =7◦C,T 2 =20◦C,T 3=34◦C

Temperature of 1+2 liquids mix: T_{12}=11^oCT

12 =11 oC

Temperature of 2+3 liquids mix: T_{23}=22.6^oCT

23=22.6 oC

Temperature of 1+3 liquids mix: T_{13} - ?T 13 −?

When the first two are mixed:

m C₁ (T₁ − T_{12}) + m C₂ (T₂ − T_{12}) = 0 \\ C₁ (7− 11) + C₂ (20 − 11) = 0\\ 4C_1=9C_2\\ C_1=2.25C_2mC₁(T₁−T 12)+mC₂(T₂−T 12 )=0C₁(7−11)+C₂(20−11)=04C \1=9C 2C 1 =2.25C 2

​When the second and therd are mixed:

m C_2 (T_2 − T_{23}) + m C_3 (T_3 − T_{23}) = 0 \\ C_2 (20−22.6) + C₂ (34 −22.6) = 0\\ 2.6C_2=11.4C_3\\ C_2=4.38C_3mC 2 (T 2 −T 23 )+mC 3 (T 3 −T 23 )=0C 2(20−22.6)+C₂(34−22.6)=02.6C 2 =11.4C 3C2 =4.38C 3

​When the first and therd are mixed:

m C_1 (T_1 − T_{13}) + m C_3 (T_3 − T_{13}) = 0 \\ C_1 (7−T_{13}) + C_3 (34 −T_{13}) = 0\\ C_1=2.25C_2=2.25(4.38C_3)=9.86C_3\\ 9.86C_3 (7−T_{13})=-C_3(34 −T_{13})\\ 9.86 (7−T_{13})=-(34 −T_{13})\\ T_{13}=9.5^oCmC 1(T1 −T13)+mC 3(T3−T13 )=0C1 (7−T13 )+C 3(34−T 13 )=0C1 =2.25C2=2.25(4.38C3 )=9.86C39.86C3 (7−T13 )=−C3(34−T13 )9.86(7−T13)=−(34−T13 )T13 =9.5 oCT_{13}=9.5^oCT 13 =9.5 o C:

apply the necessary conversions to find: a) the speed in m/s equal to 78.0 mi/h b) the area in ft2 of a rectangle with sides 18.6 m and 3.82 m. c) the height in cm of a person who is 5 ft 7 in tall.

Answers

The speed in m/s equal to 78.0 mi/h AND  the area in ft2 of a rectangle with sides 18.6 m and 3.82 m AND the height in cm of a person who is 5 ft 7 in tall.

a) To find the speed in m/s equal to 78.0 mi/h, we use the conversion factor,

1 mi = 1609.344 meters and 1 h = 3600 s.78.0 mi/h = (78.0 mi/h) x (1609.344 m/mi) x (1 h/3600 s)= 35.0 m/s

Therefore, the speed in m/s equal to 78.0 mi/h is 35.0 m/s.

b) The area in ft2 of a rectangle with sides 18.6 m and 3.82 m is calculated as follows:

First, we convert the sides from meters to feet using the conversion factor

1 m = 3.281 ft.18.6 m = 18.6 m x (3.281 ft/m) = 61.024 ft3.82 m = 3.82 m x (3.281 ft/m) = 12.532 ft

The area is given by the formula A = L x W, where L is the length and W is the width.

A = (61.024 ft) x (12.532 ft)A = 765.69 ft2Therefore, the area in ft2 of a rectangle with sides 18.6 m and 3.82 m is 765.69 ft2.

c) The height in cm of a person who is 5 ft 7 in tall can be found by converting the height to inches and then to centimetres.

1 ft = 12 in5 ft = 5 ft x 12 in/ft = 60 in5 ft 7 in

= 60 in + 7 in = 67 in1 in = 2.54 cm67 in

= 67 in x (2.54 cm/in) = 170.18 cm

Therefore, the height in cm of a person who is 5 ft 7 in tall is 170.18 cm.

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Stars which never disappear below the horizon are called__stars. A. Polaris B. visible C. constellation D. circumpolar

Answers

Answer:

D. circumpolar

Explanation:

A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.

-Wikipedia

The cabin of a small freight elevator is secured to a
motor by a cable and is moving upward while slowing
down. There is no contact between the cabin and the
elevator shaft. Ignore air resistance.

Answers

The motor is providing the force necessary to move the cabin of the freight elevator upward and slow it down.

What is elevator?

An elevator is a type of vertical transportation device designed to move people and goods from one floor to another within a building or structure. It is typically composed of a cab, a motor, a counterweight, cables, and other components. Elevators are the most common form of vertical transportation for multi-story buildings, and are used for both commercial and residential buildings.

The cable connecting the motor to the cabin is providing the mechanical connection that allows the motor to exert the force necessary to move the cabin. Since there is no contact between the cabin and the elevator shaft, the cabin is being accelerated and decelerated solely due to the force exerted by the motor. Air resistance has no effect on the motion of the cabin since it is not in contact with the shaft.

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Which of the following light waves have the highest frequency?infrared lightmicrowavesX-rays

Answers

The correct answe is X-rays

The infrared waves have a frequency range of 10¹

A toy car rolls down a hill starting from rest. After 4.2 seconds its velocity is 18 meters per second. What is the acceleration of the car?

Answers

Answer:

I think it’s 24

Explanation:

It is 24 hope this helps

What duty cycle should transformer-rectifier units have (at least) for CAC-A?
Made from graphite, copper coated, and operated on direct type current.
Should be three phase units with at least a 60% duty cycle
No--trash containers are not fabricated to the quality of a nuclear power plant

Answers

Transformer-Rectifier units for CAC-A (Constant Current Arc Welding) should have a minimum of 60% duty cycle, with at least three-phase units.

Constant Current Arc Welding is also known as "stick welding." The acronym CAC stands for "constant current," which means the power source must be able to produce a constant output current, regardless of the resistance of the welding arc.

To create the appropriate current for the welding, a transformer-rectifier is used. A transformer-rectifier unit comprises of a transformer and a rectifier. The transformer converts high voltage, low current AC electricity from the power source to low voltage, high current AC electricity, which is then supplied to the rectifier. The rectifier transforms the AC input into a direct current (DC) output that the welding equipment requires.

The duty cycle is defined as the amount of time during which the machine can operate without overheating. The transformer-rectifier should have a 60% duty cycle or higher because welding generates a lot of heat and needs a lot of power. If the duty cycle is too low, the unit will shut down too often and be unable to perform effectively.

A 60% duty cycle ensures that the welding machine can run continuously for six minutes out of every ten minutes. It is recommended that you choose a transformer-rectifier with a duty cycle that meets your requirements, as a higher duty cycle would allow you to weld for longer periods of time before requiring a cool down period.

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When does an object moving in a straight line at constant speed have a non-zero angular momentum?
a) never
b) always
c) sometimes

Answers

Answer: Yes, it can be  possible that an object have non zero angular momentum.

Explanation:

There is a concept of frame of reference.

When your frame of reference is not on that straight line where the object is moving then the object will have non zero angular momentum .

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The half life of
40
K is approximately 1.3 billion years, and it decays to
40
Ar, which is trapped in igneous rocks as
40
K decays. If we find a sample of granite in which the ratio of
40
Ar/
40
K is 3/1, then how old is the sample?

Answers

The half-life of 40K is approximately 1.3 billion years. Given a ratio of 40Ar/40K as 3/1 in a granite sample, we can estimate the age of the sample by understanding the decay process.  Based on the given 40Ar/40K ratio, the age of the sample is approximately 650 million years.

Since the half-life of 40K is 1.3 billion years, this means that after each half-life, half of the 40K atoms will have decayed into 40Ar. Therefore, if the ratio of 40Ar/40K is 3/1, it suggests that three-quarters (or 75%) of the original 40K atoms have decayed into 40Ar.

To determine the age, we can calculate the number of half-lives that have occurred based on the remaining 25% of 40K. Since each half-life is 1.3 billion years, dividing the remaining 25% by 50% (half) gives us 0.5. Thus, the sample has undergone 0.5 half-lives.

Multiplying 0.5 by the half-life of 1.3 billion years gives us an estimated age of 0.65 billion years, or 650 million years, for the granite sample.

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A jogger runs 3 miles east then 7 miles west what is her displacement

Answers

Answer: 4 miles.

Explanation:

Let's use the rectangular coordinates (x,y)

And define:

East as the positive x-axis.

North as the positive y-axis.

We know that, if the jogger starts at the point (0mi, 0mi):

"Runs 3 miles East"

Then the new position is (3mi, 0mi)

"Then 7 miles west"

The new position is (3mi - 7mi, 0mi) = (-4mi, 0mi)

Now, the displacement is calculated as the difference between the initial position and the final position, and this can be written as:

D = I (-4mi, 0mi) - (0mi, 0mi)I = √( (-4mi - 0mi)^2 + (0mi - 0mi)^2) = 4mi

The total displacement is 4 miles.

methods to reduce the frictional force between the an object and surface which it is in contact.

Answers

Use of lubricant
Use of ball bearers
Use of streamlined body
Use of graphite

Differentiate Equation 29.12 with respect to x and Equation 29.13 CH with respect to t. Then, using the fact that mixed derivatives are aaB а /ав = equal (e.g., combine the resulting equations at dx dx dt and show that the result is the wave equation (Equation 14.5) for I/VEOMO. waves with speed c = JE ав = (29.12) ax at (29.13) ƏB ax = -EOMO JE at

Answers

By differentiating Equation 29.12 with respect to x and Equation 29.13 with respect to t, and then combining the resulting equations, we can derive the wave equation for electromagnetic waves with speed c.

Equation 29.12: E = -∂A/∂t

Equation 29.13: B = ∇ x A

Differentiating Equation 29.12 with respect to x:

∂E/∂x = -∂²A/∂t∂x

Differentiating Equation 29.13 with respect to t:

∂B/∂t = ∂(∇ x A)/∂t

Using the fact that ∂/∂t and ∂/∂x commute (mixed derivatives are equal), we can rewrite the above equation as:

∂B/∂t = ∇ x (∂A/∂t)

Taking the curl of both sides of Equation 29.12:

∇ x E = -∇ x (∂A/∂t)

Using the vector identity ∇ x (∇ x A) = ∇(∇ · A) - ∇²A, we can rewrite the equation as:

∇ x (∇ x A) = -∇²A - ∂(∇ · A)/∂t

Substituting Equation 29.13 into the equation:

∇ x B = -∇²A - ∂(∇ · A)/∂t

Since ∇ · A = 0 for electromagnetic waves (divergence-free property), the equation simplifies to:

∇ x B = -∇²A

Comparing this equation with the wave equation for electromagnetic waves:

∇²A - (1/c²)∂²A/∂t² = 0

We can see that the two equations are equivalent, where c is the speed of the electromagnetic waves.

By differentiating Equation 29.12 with respect to x and Equation 29.13 with respect to t, and then combining the resulting equations, we have derived the wave equation for electromagnetic waves. This demonstrates the relationship between the wave equation and the equations for electric and magnetic fields in electromagnetism.

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Complete each statement with the word that makes it true.

The noble gases are the least
of any elements on the periodic table.

The
form acidic compounds with hydrogen.

The halogens are the most reactive among all the
.

Answers

Answer:

reactive

halogens

nonmetals

Explanation:

Noble gases are the least reactive of all elements on the periodic table. The halogens form acidic compounds with hydrogen. Halogens are most reactive among all the nonmetals.

What are halogens?

Halogens are the chemical elements placed in group 7 of the modern periodic table, which contains five elements: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At).

Halogens can be described as nonmetals among which fluorine and chlorine (Cl) are gases and bromine (Br) is a liquid, and iodine (I) and astatine (At) are solids at room temperature. Halogens are generally the most reactive among the nonmetals and their reactivity decreases from F to At.

The word ‘halogen’ means “salt-forming“. Halogens exist in the form of ions or compounds because of their high reactivity.

Halogens are generally homonuclear diatomic so one molecule exists with two halogen atoms each. Halogens possess seven valence electrons because halogens have a deficiency of one electron to get a noble gas configuration. Therefore, they form negative ions, highly reactive due to high electronegative.

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What is the mass of an object on the moon whose weight sitting on the Earth is 1900 N?

Answers

Fg=mg
Fg/g=m
m=(1900N) / (9.81N/kg)
m=193.68kg

Somatic versus Sex Cells


2. How do the chromosomes in most cells of an organism, such as the leaf cells of a plant, compare to the chromosomes in its reproductive cells, which are sperm and egg cells?

Answers

Most cells in an organism, such as leaf cells in a plant, are somatic cells. Somatic cells contain two sets of chromosomes, one inherited from each parent, and are diploid. In humans, for example, somatic cells contain 46 chromosomes, arranged in 23 pairs.

On the other hand, reproductive cells, such as sperm and egg cells, are sex cells or gametes. Gametes are haploid, which means they contain only one set of chromosomes, half the number found in somatic cells. In humans, gametes contain 23 chromosomes, which are not arranged in pairs.

The purpose of gametes is to combine during fertilization to produce a zygote, which contains a complete set of chromosomes (i.e., diploid). This ensures that the offspring will have genetic diversity and not be identical to either parent.

The process of reducing the number of chromosomes in gametes from diploid to haploid is called meiosis. Meiosis is a type of cell division that occurs only in gamete cells, and results in the production of four haploid daughter cells, each containing a unique combination of chromosomes.

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why is it easier for red giants to lose mass than main sequence stars?

Answers

It is easier for red giants to lose mass than main sequence stars because though red giants are larger in size but their linear mass is less than sequence stars.

Red giant stars are the stars on which nuclear fusion process takes place. The gases involved in nuclear fusion are lighter in nature. Hence, the liner mass of red giant stars are less than that of sequence stars. Red giant stars are red in color because they constantly radiate heat and light like Sun. All through the star's life after it first started nuclear reactions, it has been losing mass as it converted some mass to energy and other mass was lost in the winds. This means that even though a red giant is large in terms of linear size, it is less massive than the main sequence star it came from.

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Which statement describes the reason for the change in the velocity of waves as temperature decreases?

O The particles of the medium move faster and there are fewer chances to transfer energy.
O The particles of the medium move faster and there are more chances to transfer energy.
O The particles of the medium move more slowly and there are more chances to transfer energy.
O The particles of the medium move more slowly and there are fewer chances to transfer energy.

Answers

Answer:

O The particles of the medium move more slowly and there are fewer chances to transfer energy.

Explanation:

Various media are made up of particles. These particles are in constant motion according to the kinetic theory of matter. Recall that temperature has been defined as the average kinetic energy of the particles in a medium. Hence, for any given medium, the velocity of particle motion increases or decreases linearly with temperature.

The speed of particles in any medium increases or decreases as the temperature of the medium increases or decreases as emphasised above. Hence, at low temperature, the velocity of waves set up by the motion of particles in a medium decreases and transfer the wave energy to neighbouring particles occurs more slowly than at high temperatures.

Answer:

Person who answerd first you could have said D

Explanation: DDDDDDDDDDDDDDDD

I really need help.

I really need help.

Answers

yeah i did, hope you understand

I really need help.

what is the value of sin square 60​

Answers

\( \sin(60 ) {}^{2} = \frac{3}{4} \)

Explanation:

\( \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(60 ) {}^{2} = ( \frac{ \sqrt{3} }{2} ) {}^{2} \\ \\ \sin(60 ) {}^{2} = \frac{3}{4} \)

how do protons indentify hydrogen?

•will mark brainest​

Answers

Answer: Hydrogen is a chemical element with atomic number 1 which means there are 1 protons in its nucleus. Total number of protons in the nucleus is called the atomic number of the atom and is given the symbol Z.

Explanation: hope this helps

Question 27
What would be easier for someone with a negative Weber slope for weight detection?
A. Telling the difference between 1 pound and 2 pounds
B. Telling the difference between 10 pound and 11 pounds
C. Telling the difference between 20 pound and 21 pounds
D. No weight discriminations could be made

Answers

For someone with a negative Weber slope for weight detection, it would be easier to tell the difference between 20 pounds and 21 pounds.

The Weber's Law states that the just noticeable difference (JND) between two stimuli is proportional to the magnitude of the stimuli. A negative Weber slope indicates that the JND decreases as the magnitude of the stimuli increases. In this case, as the weight increases, the person's ability to discriminate between the weights becomes easier.

Therefore, option C, telling the difference between 20 pounds and 21 pounds, would be easier for someone with a negative Weber slope for weight detection.

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6. Dentists use a soft, clay-like material to make a filling for a cavity. The filling stays soft under the
light of the dentist's lamp, but it hardens when the dentist shines an ultraviolet flashlight on it. Why
does light from the ultraviolet flashlight harden the filling when light from the lamp does not?

Answers

Because ultraviolet light may be absorbed by the filler substance, but not by the lamp's light. Because UV light extracts energy from the filler substance while lamp light does not.

What is ultravoilet ray?

Ultraviolet Rays in the electromagnetic Spectrum Ultraviolet rays are a kind of electromagnetic radiation that extends from the visible light spectrum to the X-ray area.

Harmful rays have a long-term effect on humans, causing skin and eye problems. It is also a source of Vitamin C.

Because ultraviolet light may be absorbed by the filler substance, but not by the lamp's light. Because UV light extracts energy from the filler substance while lamp light does not,

Hence light from the ultraviolet flashlight harden the filling when light from the lamp does not.

To learn more about the ultravoilet ray refer to thr link;

https://brainly.com/question/25780677

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