Answer:
$95.88
Step-by-step explanation:
multiply 6 by 17 and get 102
multiply 102 by 0.94 and get 95.88
Find the value of x. Pythagorean theorem and its converse
Evaluate |-11| What’s the answer
Answer:
11
Step-by-step:
|-11| = 11
what multiplies to -65 and adds to -8
Answer: The two numbers that multiply to -65 and add to -8 are -13 and 5.
Steps: Here are the steps to find two numbers that multiply to -65 and add to -8:
Write down the equation x * y = -65 where x and y are the two numbers you’re looking for.
Write down the equation x + y = -8.
Solve for one of the variables in one of the equations. For example, solving for x in the second equation gives us x = -8 - y.
Substitute this expression for x into the first equation: (-8 - y) * y = -65.
Solve this quadratic equation for y: -y^2 - 8y + 65 = 0.
Use the quadratic formula to find the values of y: y = (-(-8) +/- sqrt((-8)^2 - 4 * (-1) * 65)) / (2 * (-1)).
This gives us two possible values for y: -13 and 5.
Substitute these values back into one of the original equations to find the corresponding values of x. For example, when y = -13, we have x = -8 - (-13) = 5. When y = 5, we have x = -8 - 5 = -13.
So, the two numbers that multiply to -65 and add to -8 are -13 and 5.
PLEASE HURRY WILL MARK BRAINLEST
If the odds of being born on each day of
the week is equal, what is the probability
of two separate babies both being born
on a school day? (Monday through
Friday)
Answer:
1/25
Step-by-step explanation:
days in a week is 7
odds of being born on each 7 days is equal
x born = 7 days
pr(one separate baby) = 1 ÷ 5
pr(second separate baby) = 1 ÷ 5
pr(both being born on a school day) = 1/5 × 1/5
= 1/25
A ( x ) = 4 − ( x + 3 )^5
The solution for A(3) in the function when the function A(x) = 4 − (x + 3)⁵ is -772
How to determine the solution for A(x) in the function?From the question, we have the following equation that can be used in our computation:
A ( x ) = 4 − ( x + 3 )^5
To make the equation legible, we need to rewrite it
So, we have the following representation
A(x) = 4 − (x + 3)⁵
Also from the question, we have
A(3)
This means that the value of x is 3, and we calculate A(x) when x = 3
Substitute the known values in the above equation, so, we have the following representation
A(3) = 4 − (x + 3)⁵
So, we have the following equation
A(3) = 4 − (3 + 3)⁵
There are constants to add or subtract to both sides of the equation
However, there is no factor to multiply or divide from both sides of the equation
So, we have the following representation
A(3) = 4 − (6)⁵
Solving further, we have
A(3) = 4 − 7776
Evaluate the difference
A(3) = −7772
Hence, the solution is −7772
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Possible question
Given A ( x ) = 4 − ( x + 3 )^5, find A(3).
Help pls George is building a fence around a rectangular dog run. He is using his house as one side of the run. The area of the dog run will be 240 square feet. The length of the run is 30 feet, and the width is (30 minus x) feet. The diagram below shows his plan.
Recall the formulas for area and perimeter: A = lw and P = 2l + 2w.
The width of the dog run is 20 feet.
In the given problem, the length of the dog run is given as 30 feet.
The area of the dog run is also given as 240 square feet.
Using the formula for the area of a rectangle (A = lw), we can solve for the width (w).
Rearranging the formula, we have w = A / l.
Plugging in the values, we get w = 240 / 30 = 8 feet.
Since the width is given as (30 minus x) feet, we can set up an equation:
30 - x = 8. Solving for x, we find x = 22.
Therefore, the width of the dog run is 20 feet (30 - 22 = 8).
In this problem, the length and width of the dog run are defined by the dimensions of the fence being built around it.
The area of the dog run is given as 240 square feet.
By using the formula for the area of a rectangle, we can solve for the width. We are also given that the length is 30 feet.
Setting up an equation with the given width (30 minus x) and solving for x, we find that x is equal to 22.
This means that the width of the dog run is 8 feet. The main answer to the problem is that the width of the dog run is 20 feet (30 - 22 = 8).
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District size in 1790
The U.S. population in 1790 was 3,615,920, and the House size was set at 105.
The ideal congressional district size (Standard Divisor) in 1790 was [answer].
(Give your answer rounded to one decimal place.)
The ideal congressional district size (Standard Divisor) in 1790 was 34437.33.
What is Standard divisor?The number of persons each House of Representatives seat represents is known as the "Standard Divisor" (SD). By dividing the total population of all the states by the total number of seats available for voting, the SD is determined. SD is calculated as Total U.S. Population / Total Number of Voting Seats.
The ratio of the entire population to the available seats (or other allocations) is known as the standard divisor. • The Hamilton system divides up any extra seats among the states with the largest fractional parts after allocating each state its lower quota initially.
Given,
population in 1790 was 3,615,920,
number of objects = 105
⇒ Standard divisor = total population / number of objects
⇒ Standard divisor = 3,615,920 / 105
⇒ Standard Divisor = 34437.33
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What is the square root of 1748? (simplify)
Answer:
Step-by-stepcarry the 18975327834783578 explanation:
please help me 10 points
Answer:B
Step-by-step explanation:
A diagonal divides a square into two isosceles right triangles
Always True
Sometime True
Never True
Answer:
always true I think hope it helps
WHAT IS THE VALUE OF B helpppp plz ?
ILL GIVE BRAINLIEST IF YOU CAN GUESS MY AGE
Answer:
sixteen i guess?
Step-by-step explanation:
abcdefghijklmnop
Not a Function
input
0
1
2
3
1
output
1
2
4
Function
Answer:
Not a Function
Step-by-step explanation:
there are 2 same inputs for different outputs
Gina Wilson Unit 10: Circles Homework 9: Standard Form of a Circle
The standard form (SF), center (C) and radius (R) are given as follow: (13) SF: (x + 4)² + (y - 3)² = 50, Center: (-4, 3), R: √50 (14) SF: (x - 2)² + (y - 6)² = 169, C: (2, 6), R: 13 (15) SF: (x + 7)² + (y + 5)² = 1, C: (-7, -5), R: 1 (16) SF: (x - 8)² + y² = 225, C: (8,0), R: 15 (17) SF: (x - 12)² + (y - 2)² = 63, C: (12, 2), R: √63 (18) SF: (x - 5)² + (y + 4)² = 100 , C: (5, -4), R: 10
Understanding Equation of CircleThe general form of a circle is given as:
(x - h)² + (y - k)² = r²
where:
(h, k) represents the center of the circle
r represents the radius.
Now we can use the above information to solve the following questions:
13. x² + y² + 8x - 6y - 25 = 0
Rearranging the equation:
x² + 8x + y² - 6y = 25
Completing the square for x terms:
(x² + 8x + 16) + y² - 6y = 25 + 16
Simplifying:
(x + 4)² + (y² - 6y) = 41
(x + 4)² + (y² - 6y + 9) = 41 + 9
(x + 4)² + (y - 3)² = 50
Center: (-4, 3)
Radius: √50
14. x² + y² - 4x - 12y - 129 = 0
Rearranging the equation:
x² - 4x + y² - 12y = 129
Completing the square for x terms:
(x² - 4x + 4) + y² - 12y = 129 + 4
Simplifying:
(x - 2)² + (y² - 12y) = 133
(x - 2)² + (y² - 12y + 36) = 133 + 36
(x - 2)² + (y - 6)² = 169
Center: (2, 6)
Radius: 13
15. x² + y² + 14x + 10y + 73 = 0
Rearranging the equation:
x² + 14x + y² + 10y = -73
Completing the square for x terms:
(x² + 14x + 49) + y² + 10y = -73 + 49
Simplifying:
(x + 7)² + (y² + 10y) = -24
(x + 7)² + (y² + 10y + 25) = -24 + 25
(x + 7)² + (y + 5)² = 1
Center: (-7, -5)
Radius: 1
16. x² + y² - 16x - 161 = 0
Rearranging the equation:
x² - 16x + y² = 161
Completing the square for x terms:
(x² - 16x + 64) + y² = 161 + 64
Simplifying:
(x - 8)² + y² = 225
Center: (8, 0)
Radius: 15
17. x² + y² = 24x + 4y - 85
Rearranging the equation:
x² - 24x + y² - 4y = -85
Completing the square for x and y terms:
(x² - 24x + 144) + (y² - 4y + 4) = -85 + 144 + 4
Simplifying:
(x - 12)² + (y - 2)² = 63
Center: (12, 2)
Radius: √63
18. x² + y² - 9x + 2y = x - 6y + 59
Rearranging the equation:
x² - 9x - x + y² + 2y + 6y = 59
Combining like terms:
x² - 10x + y² + 8y = 59
Completing the square for x and y terms:
(x² - 10x + 25) + (y² + 8y + 16) = 59 + 25 + 16
Simplifying:
(x - 5)² + (y + 4)² = 100
Center: (5, -4)
Radius: 10
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Choose the inequality that represents the following graph.
A x<-5
B x≤-5
C x>-5
D x≥-5
Answer:
x > -5, so the correct answer is C.
For the arithmetic sequence beginning with the terms {-1, 2, 5, 8, 11, 14...}, what is the sum of the first 16 terms?
Answer:
S₁₆ = 344
Step-by-step explanation:
the sum to n terms of an arithmetic sequence is
\(S_{n}\) = \(\frac{n}{2}\) [ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
here a₁ = - 1 and d = a₂ - a₁ = 2 - (- 1) = 2 + 1 = 3 , then
S₁₆ = \(\frac{16}{2}\) [ (2 × - 1) + (15 × 3) ]
= 8 (- 2 + 45)
= 8 × 43
= 344
Find the value of x and y that satisfy both of the equalities x /y= 2/3 and y/12 = 3/4.
Answer:
x=6;y=9
Step-by-step explanation:
First you try to find y in the second equation --> y/12=3/4
You divide 12 by 4 to see how many times y/12's denominator and numerator is bigger. 12/4 is 3, so to find y you multiply 3*3. so 9/12=3/4. To check this, you multiply 3 on each side of the fraction -->
3*3=9 4*3=12.
Then, you can just put y into the first equation, which is x/y=2/3. Pluck that in, and you get x/9=2/3. Do the same thing you did in the first step, and you should get 6/9=2/3. Hope this helped :)
Answer:
x=6; y=9
Step-by-step explanation:
Write a story that can be represented by the equation
y=x+
5*.
The entries in Table I are the probabilities that a random variable having the standard normal distribution will take on a value between 0 andz. They are given by the area of the gray region under the curve in the figure. TABLET NORMAL-CURVE AREAS 2 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.1 0.2 0.3 0.4 0.5 0.0000 0.0398 0.0793 0.1179 0.1554 0.1915 0.0080 0.0478 0.0871 0.1255 0.1628 0.1985 0.0120 0.0517 0.0910 0.1293 0.1664 0.2019 0.2357 0.2673 0.2967 0.3238 0.3485 0.0160 0.0557 0.0948 0.1331 0.1700 0.2054 0.2389 0.2704 0.2995 0.3264 0.3508 0.0199 0.0596 0.0987 0.1368 0.1736 0.2088 0.0239 0.0636 0.1026 0.1406 0.1772 0.2123 0.0279 0.0675 0.1064 0.1443 0.1808 0.2157 0.0319 0.0714 0.1103 0.1480 0.1844 0.2190 0.0359 0.0753 0.1141 0.1517 0.1879 0.2224 0.2549 0.2852 0.3133 0.3389 0.3621 0.2257 0.0040 0.0438 0.0832 0.1217 0.1591 0.1950 0.2291 0.2611 0.2910 0.3186 0.3438 0.3665 0.3869 0.4049 0.4207 0.4345 0.4463 0.4564 0.4648 0.4719 0.4778 0.6 0.7 0.8 0.9 1.0 0.2580 0.2881 0.3159 0.3413 0.2324 0.2642 0.2939 0.3212 0.3461 0.2422 0.2734 0.3023 0.3289 0.3531 0.2454 0.2764 0.3051 0.3315 0.3554 0.2517 0.2823 0.3106 0.3365 0.3599 0.2486 0.2794 0.3078 0.3340 0.3577 0.3790 0.3980 0.4147 0.4292 0.4418 1.1 1.2 1.3 1.4 1.5 0.3749 0.3944 0.4113 0.4265 0.4394 0.3770 0.3962 0.4131 0.4279 0.4406 0.3810 0.3997 0.4162 0.4306 0.4429 0.3643 0.3849 0.4032 0.4192 0.4332 0.4452 0.4554 0.4641 0.4713 0.4772 0.3686 0.3888 0.4066 0.4222 0.4357 0.4474 0.4573 0.4656 0.4725 0.4783 0.3708 0.3907 0.4082 0.4236 0.4370 0.4484 0.4582 0.4664 0.4732 0.4788 0.3729 0.3925 0.4099 0.4251 0.4382 0.4495 0.4591 0.4671 0.4738 0.4793 0.3830 0.4015 0.4177 0.4319 0.4441 0.4545 0.4633 0.4706 0.4767 0.4817 1.6 1.7 1.8 1.9 2.0 0.450S 0.4599 0.4678 0.4744 0.4798 0.4515 0.4608 0.4685 0.4750 0.4803 0.4525 0.4616 0.4692 0.4756 0.4808 0.4535 0.4625 0.4699 0.4761 0.4812 2.1 2.2 2.3 2.4 2.5 0.4826 0.4864 0.4896 0.4920 0.4940 0.4830 0.4868 0.4898 0.4922 0.4941 0.4834 0.4871 0.4901 0.4925 0.4943 0.4850 0.4884 0.4911 0.4932 0.4949 0.4854 0.4887 0.4913 0.4934 0.4951 0.4857 0.4890 0.4916 0.4936 0.4952 0.4821 0.4861 0.4893 0.4918 0.4938 0.4953 0.4965 0.4974 0.4981 0.4987 0.4838 0.4875 0.4904 0.4927 0.4945 0.4959 0.4969 0.4977 0.4984 0.4988 0.4842 0.4846 0.4878 0.4881 0.4906 0.4909 0.4929 0.4931 0.4946 0.4948 0.4960 0.4961 0.4970 0.4971 0.4978 0.4979 0.4984 0.4985 0.4989 0.4989 2.6 2.7 2.8 2.9 3.0 0.4955 0.4966 0.4975 0.4982 0.4987 0.4956 0.4967 0.4976 0.4982 0.4987 0.4957 0.4968 0.4977 0.4983 0.4988 0.4962 0.4972 0.4979 0.4985 0.4989 0.4963 0.4973 0.4980 0.4986 0.4990 0.4964 0.4974 0.4981 0.4986 0.4990 Also, for 3 - 4.0, 5.0 and 6.0, the areas are 0.49997, 0.4999997, and 0.499999999. ^ The entries in Table II are values for which the area to their right under the 1 distribution with given degrees of freedom (the gray area in the figure) is equal toa. TABLE II VALUE OF d.f. Fo.050 os 0.005 d.. 63.657 9.925 1 2 3 4 6.314 2.920 2.353 2.132 2.015 12.706 4.303 3.182 2.776 2.571 0.010 31.821 6.965 4.541 3.747 3.365 1 2 3 4 5.841 4.604 4.032 S S 6 7 6 7 8 1.943 1.895 1.860 1.833 1.812 2.447 2.365 2.306 2.262 2.228 3.143 2.998 2.896 2.821 2.764 3.707 3.499 3.355 3.250 3.169 8 9 9 10 10 11 12 1.796 1.782 1.771 1.761 1.753 13 14 15 2.201 2.179 2.160 2.145 2.131 2.718 2.681 2.650 2.624 2.602 3.106 3.055 3.012 2.977 2.947 11 12 13 15 16 16 17 18 19 20 1.746 1.740 1.734 1.729 1.725 2.120 2.110 2.101 2.093 2.086 2.583 2.567 2.552 2.921 2.898 2.878 2.861 2.845 17 18 19 2.539 2.528 20 21 22 23 24 25 1.721 1.717 1.714 1.711 1.708 2.080 2.074 2.069 2.064 2.060 2.518 2.508 2.500 2.831 2.819 2.807 2.797 2.787 21 22 23 24 25 2.492 2.485 2.056 2.052 26 27 28 29 Inf. 1.706 1.703 1.701 1.699 1.645 2.479 2.473 2.467 2.462 2.326 2.779 2.771 2.763 2.048 26 27 28 29 Inf. 2.045 2.756 2.576 1.960 Question 2 (20 marks) A tutorial school has been running IELTS mock examination for many years. Below is the summary presented by the tutorial school related to the IELTS mock examination in one of the many online classes selected randomly in year 2022. IELTS score in mock examination Number of students <4 0 5 2 6 7 5 15 8 10 3 9 A report presented by this tutorial school 5 years ago indi that the population mean score of IELTS mock examination was 7.05 points and the population proportion of students got 7 points or above was 0.67. (a) Construct a 95% confidence interval estimate of population mean score a student get in the IELTS mock examination in 2022. (b) Test, at 1% level of significance, if the population proportion of students get 7 points or above in 2022 is higher than that in year 2017. (The report must include the (i) null hypothesis and alternative hypothesis, (ii) rejection region(s), (iii) calculation of test statistics, and (iv) conclusion.) (c) If the confidence interval estimate in part (a) is constructed at 99% instead of 95%, would the interval be (1) wider, (II) narrower, or (III) no change in width? (State your answer, no explanation is needed in part (C).)
What is the greatest integer that satisfies the inequality 3x - 4(equal to or less than) 8?
The given inequality is
\(3x-4\leq8\)Remember that we need to isolate the variable in order to solve the inequality.
First, we sum 4 to each part of the inequality
\(3x-4+4\leq8+4\text{ }\rightarrow3x\leq12\)Second, we divide each side by 3
\(\frac{3x}{3}\leq\frac{12}{3}\rightarrow x\leq4\)This result means that the set of solutions for this inequality is all numbers equal to or less than 4.
Therefore, the greatest integer that satisfies the inequality is 4.
2y = 4x - 12
Find the x and the y intercept of the line.
a thief uses a bag of sand to replace a gold statue that sits on a weight-sensitive, alarmed pedestal. the bag of sand and the statue have exactly the same volume, 1.90 ll. (assume that the mass of the bag is negligible.) part a calculate the mass of each object. (densityofgold
4.65 kg the mass of each item (assuming the bag's mass is negligible). (Sand density is 3.00 g/cm3, while the density of gold is 19.3 g/cm3)
Given that,
A gold statue that is perched on a pedestal with a weight-sensitive alarm is replaced by a thief using a bag of sand. The statue and the bag of sand have the exact same volume, 1.55 L.
We have to calculate the mass of each item (assuming the bag's mass is negligible). (Sand density is 3.00 g/cm3, while the density of gold is 19.3 g/cm3)
We know that,
Mass of gold = Volume × Density
= 1.55×1000 cc × 19.3
= 29915 grams
= 29.915 Kg
Mass of sand = 1.55×1000×3
= 4650g
= 4.65 Kg
Volume = 1.55 L
= 1.55 × 1000 cc
= 1550 cc
Mass = Volume × Density
Mass of gold = 1550 × 19.3
= 29915 grams
= 29.915 kg
Mass of sand = 1550 × 3
= 4650 grams
= 4.65 kg
Therefore, 4.65 kg the mass of each item (assuming the bag's mass is negligible). (Sand density is 3.00 g/cm3, while the density of gold is 19.3 g/cm3)
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Taylor is playing a video game. She eams 15 points when she completes Level 1. Each time she completes a level, she earns three
times as many points as the previous level.
How many points will Taylor earn when she completes Level 6?
3645 points will Taylor earn when she completes Level 6.
What is a permutation?Permutation is the arrangement of items in which order matters. In this situation order matters repetition allowed.
According to the question,
Taylor is playing a video game. She earns 15 points when she completes Level 1.
Each time she completes a level, she earns three times as many points as the previous level.
= 15 × \(3^{6-1}\)
= 15 × \(3^{5}\)
= 15 × 243
= 3645
Hence, 3645 points will Taylor earn when she completes Level 6.
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Find the horizontal asymptotes: y=2x^2/3x^3 You must show your work and enter your answer below.
Answer:
y = 0
Step-by-step explanation:
You want the horizontal asymptote of y=2x^2/3x^3.
Horizontal asymptoteDegree of numerator: 2
Degree of denominator: 3
When the degree of the denominator (3) is greater than the degree of the numerator (2), the horizontal asymptote is ...
y = 0
__
Additional comment
This reduces to (2/3)(1/x). The value of 1/x approaches zero when the magnitude of x gets large.
<95141404393>
Savannah drove 716 miles on Monday. She drove another 572 miles one Tuesday. About how many more miles did she
drive on Monday than Tuesday?
400
300
200
100
the answer is 144 not sure what you're supposed to do with that. 144 rounded would just be 100.
716 - 572 = 144
Find the area of the shaded shape
Answer:
105
Step-by-step explanation:
yeah-ya............. right?
each day on the way to work emily stops to get a large latte and a scone the latte cost $4.85 the scone cost $2.25 she works 20 days a month
How much she spend each month?
Frank exercises no less than 40 minutes per day use t to represent Frank's amount of exercise minutes per day.
9514 1404 393
Answer:
t ≥ 40
Step-by-step explanation:
"No less than" is the same as "greater than or equal to".
t ≥ 40
4) Find the total cost of a $0.95 pen with a 60% markup.
linear inequalities.tyy²-x+1Ty<2x+1-242-2-424xWhich ordered pairs make both inequalities true?Check all that apply.(-2,2)☐ (0,0)(1,1)(1,3)(2, 2)
The ordered pair that makes both inequalities true are in the shaded area below:
From the options, the point (2, 2) is the only which is true for both equations.
Answer: (2, 2).