When an object is rotating with a constant angular velocity about a fixed axis, the angular momentum (C) and the moment of inertia (D) about that axis remain constant. Therefore, the orientation of the object at different points along the arc will not change these values.

d) The significance of the main effects is not related to the significance of the interaction. The presence of a significant interaction indicates that the effect of one factor on the dependent variable depends on the level of the other factor. It does not necessarily indicate whether either or both of the main effects are significant.

A significant interaction means that the relationship between the factors A and B is not constant across levels of the other factor. However, this does not necessarily imply anything about the significance of the main effects for factors A and B. The main effects can still be significant, not significant, or one can be significant while the other is not. d) The significance of the main effects is not related to the significance of the interaction.

To know more about significant interaction click here:

https://brainly.com/question/31385713

#SPJ11

Answer:

Dispersion

Explanation:

dispersion

[diˈspərZHən, diˈspərSHən]

NOUN

the action or process of distributing things or people over a wide area.

"some seeds rely on birds for dispersion"

the state of being dispersed over a wide area.

"the general dispersion of Hellenistic culture"

ecology

the pattern of distribution of individuals within a habitat.

(Dispersion)

another term for diaspora.

a mixture of one substance dispersed in another medium.

physics

the separation of white light into colors, or the separation of any radiation according to wavelength.

statistics

the extent to which values of a variable differ from a fixed value such as the mean.

https://www.bing.com/search?q=dispersion+definition&cvid=293d01094a47488e8fa9919708bffe09&aqs=edge.2.69i57j0l8.1396j0j1&pglt=169&FORM=ANNTA1&PC=HCTS&adlt=strict&toWww=1&redig=FB19F11E98CD4962B2F34295172E44F7

In order to determine the value of n, the dimensions of each of the variables need to be found first. Then, it can be determined which terms to raise to the nth power to make the equation dimensionally consistent.

the RHS has dimensions of g mph in².Since the LHS and RHS of an equation must have the same dimensions, we can equate the dimensions of the RHS to those of the LHS\(g mph in²= [lbf]\)The dimensions of mass, length, and time are missing from both sides of the equation.

The dimensions are now consistent, except for the coefficient 2 in the original equation, which has the dimension of [dimensionless]. To eliminate this coefficient, we need to raise the RHS to the power of \(([g mph in²] / lbf)² = (kg m/s²)² = kg² m²/s⁴\)

To know more about determine visit:

https://brainly.com/question/29898039

#SPJ11

The magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.

The rotational analog of linear momentum is angular momentum also known as moment of momentum or rotational momentum.

It is significant in physics because it is a conserved quantity. the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.

The magnitude of the angular momentum of the two-satellite system is best represented as;

L=∑mvr

L=m₁v₁r₁-m₂v₂r₂

Hence, the magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.

To learn more about the angular momentum, refer to the link;

https://brainly.com/question/15104254

#SPJ4

Answer:

Option A. a

Explanation:

Motion variables include:

1. Final velocity (vf).

2. Initial velocity (vi).

3. Time (t).

4. Acceleration (a)

5. Distance (x)

Considering the equation given in the question:

Δx = ½(vf + vi) t

We can see that the acceleration (a) is missing in the equation.

The expression for gravitational potential energy at distance r in terms of gravitational potential is U = -G × M × m / r + V

The gravitational potential energy (U) of an object of mass (m) at a distance (r) from a central mass (M) can be expressed in terms of the gravitational potential (V) as

U = -G × M × m / r + V

where G is the universal gravitational constant. The term -G × M × m / r represents the gravitational potential energy of the object in isolation, while the term V represents the contribution to the potential energy due to the presence of other masses in the system.

Note that the negative sign in front of the gravitational potential energy term is due to the fact that work must be done to move the object away from the gravitational field, and therefore the potential energy is defined as negative.

Learn more about gravitational potential energy here

brainly.com/question/19768887

#SPJ4

Answer:

The value of \(\theta=63.43^0\)

Explanation:

Range of projectile \(\mathrm{R}=\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}\)

Height of projectile \(\mathrm{h}=\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}\)

Here we have

\(R=2h\\\\\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}=2\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}\\\\\sin 2 \theta=\sin ^{2} \theta\\\\2\sin \theta\cos \theta=\sin ^{2} \theta\\\\\tan \theta=2\\\\\theta=63.43^0\)

Range be R and height be h

\(\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}\)

\(\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}\)

ATQ

\(\\ \sf\longmapsto R=2h\)

\(\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}\)

\(\\ \sf\longmapsto sin^2\theta=sin2\theta\)

\(\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta \)

\(\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2\)

\(\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2\)

\(\\ \sf\longmapsto tan\theta=2\)

\(\\ \sf\longmapsto \theta=tan^{-1}(2)\)

\(\\ \sf\longmapsto \theta=63.4°\)

The series of wavelike contractions of the smooth muscles in a single direction is known as peristalsis

To learn more about peristalsis with the given link

https://brainly.com/question/15265456

#SPJ4

Answer:

Explanation:

The sum of all the forces acting on an object is the net force or resultant force. If all the forces cancel out, the resultant force is zero, else, the unbalanced force will cause acceleration of the object. Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity. Once we know all the forces that are acting on a body, we resolve all of them into components (typically horizontal and vertical) and take summation of forces in each direction. If such forces cancel out (in each direction), the object maintains its state of rest or constant motion. If however, forces do not cancel out, there is a net resultant force on the object that will cause acceleration of the object (as given by Newton's second law of motion).  

Hope this helps.

The sum of all of the forces acting on an object is called net force. It is categorized as a vector quantity because it has both direction and magnitude to be considered.

Force may be defined as the process of pushing or pulling on an object with mass provoking it to change its velocity. It is an external agent capable of altering a body's state of rest or motion. It has a magnitude and a direction, so it is a vector quantity.

Net force in a case where forces of different magnitude and opposite directions will be the difference between greater and lesser force. The combination of the resultant of all the forces acting on an object is called Net Force, which is basically the sum of all the forces acting on that object.

Therefore, the sum of all of the forces acting on an object is called net force.

To learn more about Net force, refer to the link:

https://brainly.com/question/20795823

#SPJ2

EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

More on energy cost can be found here: https://brainly.com/question/32407557

#SPJ4

Answer:

To solve this problem, you can use the following formula:

v = sqrt(k / m) * A

In this formula, v is the velocity of the mass, k is the spring constant, m is the mass of the object, and A is the amplitude of the oscillation.

Since you know the velocity of the mass at 0.25 seconds, you can substitute this value into the formula and solve for A:

2.3 m/s = sqrt(200 N/m / 3.00 kg) * A

A = 2.3 m/s / sqrt(200 N/m / 3.00 kg)

= 0.23 m

So, the amplitude of the oscillation is approximately 0.23 meters.

To find the maximum velocity of the mass, you can substitute the values for k, m, and A into the formula for velocity:

v = sqrt(200 N/m / 3.00 kg) * 0.23 m

= 2.75 m/s

So, the maximum velocity of the mass is approximately 2.75 m/s.

In an open system, both energy and matter are exchanged with the surroundings.

In a closed system, only energy is exchanged with the surroundings.

In an isolated system, neither matter nor energy is exchanged with the surroundings.

In the greenhouse, only energy is exchanged with the surroundings.

Thus, the greenhouse is a closed system.

Answer:

F_B = 0.12N

Explanation:

In order to calculate the magnetic force on the charge, you use the following formula:

\(\vec{F_B}=q\vec{v}\ X\ \vec{B}\)          (1)

q: charge of the particle = 4μC = 4*10^-6 C

v: speed of the charge = 7.5*10^4 m/s

B: magnitude of the magnetic field = 0.4T

The direction of the motion of the charge is perpendicular to the direction of the magnetic field. Then, the magnitude of the magnetic force is:

\(F_B=qvBsin90\°\\\\F_B=(4*10^{-6}C)(7.5*10^4 m/s)(0.4T)=0.12N\)

The magnetic force on the charge is 0.12N

What are the following statements?

Answer:At momentum = mass • velocity impulse = Force • Time Interval i. [kg•m/s] [kg] [m/s] ... IFK To determine which formula to use, find your knowns and unknowns. ... A deer with a mass of 146 kg is running head-on toward you with a speed of 17 m/s. You are going north. ... At=1.5 5 3(1.5) =0.5( VF-D) 4.5= 0.5 VE VE = 9 m/s.

The wind turbine with a blade diameter of 25 m and an average wind velocity of 6 m/s has an average electric power output of 172.34 kW. For an annual operating time of 8000 hours, the turbine will produce approximately 1,378,720 kWh of electricity.

If sold at a price of $0.09/kWh, the revenue generated from the electricity produced by the turbine would be approximately $124,086.72. To calculate the average electric power output, we can use the formula:

\(\[P = \frac{1}{2} \times \text{{density of air}} \times A \times v^3 \times \text{{efficiency}}\]\)

Substituting the given values into the formula, we can calculate the average electric power output:

\(\[P = \frac{1}{2} \times 1.3 \, \text{{kg/m}}^3 \times \left(\frac{\pi}{4} \times (25 \, \text{{m}})^2\right) \times (6 \, \text{{m/s}})^3 \times 0.34 \approx 172340 \, \text{{watts}} \approx 172.34 \, \text{{kW}}\]\)

To determine the amount of electricity produced for an annual operating time of 8000 hours, we multiply the average electric power output by the operating time:

\(\[\text{{Electricity produced}} = P \times \text{{operating time}} = 172.34 \, \text{{kW}} \times 8000 \, \text{{h}} = 1,378,720 \, \text{{kWh}}\]\)

Finally, to calculate the revenue generated, we multiply the electricity produced by the selling price per kilowatt-hour:

\(\[\text{{Revenue}} = \text{{Electricity produced}} \times \text{{price per kWh}} = 1,378,720 \, \text{{kWh}} \times \$0.09/\text{{kWh}} \approx \$124,086.72\]\)

To learn more about power refer:

https://brainly.com/question/1634438

#SPJ11

Answer:

\(9.8\; {\rm J}\), assuming that the gravitational field strength is \(g = 9.8\; {\rm N \cdot kg^{-1}}\).

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be \(0\). External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let \(m\) denote the mass of this block. It is given that \(m = 1\; {\rm kg}\). The weight of this block would be:

\(\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}\).

Hence, the force that the boy applies on this block would be upward with a magnitude of \(F = 9.8\; {\rm N}\).

The mechanical work that a force did is equal to the product of:

The displacement of this block (upward by \(s = 1\; {\rm m}\)) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

\(\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}\).

Answer:

Fractional error = 0.17

Percent error = 17%

F = 112 ± 19 N

Explanation:

Plug in the values to find the force:

F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N

Find the fractional error:

ΔF/F = Δm/m + 2Δv/v + Δr/r

ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5

ΔF/F = 0.17

Multiply by 100% to find the percent error:

ΔF/F × 100% = 17%

Solve for the absolute error:

ΔF = 0.17 × 112 N = 19 N

Therefore, the force is:

F = 112 ± 19 N

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

Learn more about orbit period:

https://brainly.com/question/30205659

#SPJ1

Answer:

I think he answer is C but I could be wrong

Explanation:

brainliest plz

Answer:

d mark brainlyest

Explanation:

The speed of the saw is 5710 rpm.

#SPJ4

Answer:

V is changing

\(as \: skater \: moves : \: there \: is \: displacement \\ from \: third \: equation \: of \: motion \\ {v}^{2} = {u}^{2} + 2as \\ {( \delta \: V})^{2} = 2as \\ V \: \alpha \: s\)

The numerical value for the magnitude of the tire's forward momentum is 96 kg m/s.

Momentum is the measurable quantity of movement in a body or object and is used in science to define the quantity of motion.

Momentum if determined from the product of mass and velocity of a body.

P = mv

where;

The numerical value for the magnitude of the tire's forward momentum is calculated as follows;

P = 12 kg x 8 m/s

P = 96 kg m/s

Thus, the numerical value for the magnitude of the tire's forward momentum is 96 kg m/s.

Learn more about momentum here: https://brainly.com/question/1042017

#SPJ1

The water takes approximately 1.98 hours to fall a distance of 0.250d from its highest level.

In simple harmonic motion, the displacement from the mean position can be expressed as x(t) = A * cos(ωt + φ), where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase angle.

For the given problem, A = d/2 and the period T = 11.9 hours.

Angular frequency ω = 2π/T. When x(t) = 0.250d, we can solve the equation for t.

After substituting the given values and solving for t, we find that it takes approximately 1.98 hours for the water to fall 0.250d from its highest level.

For more such questions on distance, click on:

https://brainly.com/question/26550516

#SPJ11

2.47 m/s²  is the magnitude of his centripetal acceleration as he runs the curved portion of the track.

The feature of an object's motion when it travels across a circular path is known as centripetal acceleration. Centripetal acceleration refers to the motion of any item in a circular with an accelerating vector that points in the direction of the center of the circle.

a = v²/r

v is the velocity of runner

v = 200/23.2

v = 8.62 m/s

Centripetal acceleration,

a = (8.62)²/30

a =  2.47 m/s².

The centripetal acceleration of the runner is 2.47 m/s². Hence, this is the required solution.

To know  more about Centripetal acceleration visit:

https://brainly.com/question/14465119

#SPJ4

Answer:

hope you like

Explanation:

A unit of time is any particular time interval, used as a standard way of measuring or expressing duration.Its SI unit is second

A unit of length refers to any arbitrarily chosen and accepted reference standard for measurement of length. Its SI unit is meter

200 MeV of energy is the energy released per kilogram of fuel used. 
E1/E2=7.61=8 (E1 , E2 are energies)

U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.

As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8

In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.

To learn more about Fission please visit -
https://brainly.com/question/27923750
#SPJ1

Answer:

200 MeV of energy is the energy released per kilogram of fuel used.

E1/E2=7.61=8 (E1 , E2 are energies)

U is equal to 1 kilogram or 1000 g.

There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.

It is understood that one atom releases 200 MeV of energy during its fission.

As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8

In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.

Given,

The initial height of the soccer ball, h₁=6 ft

The initial velocity of the ball, u=96 ft/s

The acceleration due to gravity, g=-32 ft/s

When the ball reaches the maximum height, its velocity will reduce to zero.

Thus the velocity of the ball when it is at its maximum height is v=0 ft/s

From the equation of motion,

Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.

On substituting the known values,

Thus the maximum height reached by the ball is,

Thus the maximum height reached by the ball is 150 ft.

Answer:

amu is atomic mass unit

All of elements hydrogen is the lightest.

Hydrogen is taken as a basic unit so it happened 1amu

So 1 amu must be hydrogen mass

If I am wrong,Pls tell me the true answer....