when a nebula contracts a ___ forms at the center and emits ___ energy
Answers
When a nebula contracts, a protostar forms at the center, which emits thermal energy as it gravitationally attracts more gas and dust.
This energy causes the protostar to heat up and increases the rate of contraction, leading to the formation of a dense core surrounded by a disk of gas and dust.
The energy emitted by the protostar is produced by the conversion of gravitational potential energy into thermal energy as the material falls onto the surface of the protostar.
As the protostar continues to contract and its temperature and pressure increase, it reaches a point where nuclear fusion can occur, and a star is born.
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Related Questions
is -3 a solution to equation 3x -5 = 4+ 2x
Answers
Answer:
No!
Explanation:
The correct answer is x = 9.
Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 22. 5° when falling on a single slit of width 1. 31 µm. Nm
Answers
When the light waves pass through the slit, the wave spreads, diffracting into a pattern on a screen behind it. The diffraction pattern is characterized by a series of bright fringes interspersed with dark ones.
We can calculate the distance between each dark fringe using the formula:dsinθ = mλ, where d is the width of the slit, θ is the angle of the dark fringe, m is the order of the fringe, and λ is the wavelength of the light.Let's now use this formula to solve the given problem. The first minimum occurs when m = 1. Therefore,1 × λ = d sinθ. The slit width is given as 1.31 µm = 1.31 × 10⁻⁶ m, and the angle of the dark fringe is 22.5°.We can convert this angle to radians as follows:θ = 22.5° = 22.5 × π/180 = 0.3937 radians.
Substituting the values into the formula, we get:λ = d sinθ / m= (1.31 × 10⁻⁶) × sin 0.3937 / 1= 7.52 × 10⁻⁷ m = 752 nmTherefore, the wavelength of light that produces its first minimum at an angle of 22.5° when falling on a single slit of width 1.31 µm is 752 nm (more than 100 words).
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Question 4 of 5
The picture shows a model of a cell.
W
What is the main function of the part labeled Win the model?
Answers
Explanation:
it is not clear. I can't see w.
What happens in terms of energy when a moving car hits a parked car, causing the parked car to move?
Answers
if a body starts from rest and attains a velocity of 20 metre per second in 8 seconds find the acceleration produced in the body
Answers
Answer:
2.5 m/s^2
Explanation:
the equation to find acceleration is \(\frac{v - v_{0} }{t}\) where \(v_{0}\) is the initial velocity, v is the current velocity, and t is the total time
so plug in your values: \(\frac{20 - 0}{8}\)
that turns into 20 ÷ 8
this equals 2.5 m/s^2
An object of mass 50 g and density 5 g/cm3 is carefully lowered into a measuring cylinder containing 50 cm3 of water. What will the final volume reading be?
Answers
Answer: 60cm^3
Explanation:
Here we can use the relationship:
Density = mass/volume.
We know that density = 5g/cm^3 and mass = 50g, then we have:
5g/cm^3 = 50g/V
V = 50g/5g/cm^3 = 10cm^3
Then, when we introduce it in a cylinder with 50cm^3 of water, this is heavier than water (the density of the water is 1g/cm^3) it will sink, and the complete volume will be equal to the volume of the water plus the volume of the object:
Total Volume = 50cm^3 + 10cm^3 = 60cm^3
The second is a flexible _________.
Answers
Answer:
static stretching
Explanation:
hope this helped ^^
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answers
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
Radio stations can broadcast their signals over great distances. Which property enables a radio station signal to travel far from the source?.
Answers
The property that makes the radio waves to travel over a very large distance is the fact that it has a long wavelength.
What are radio waves?We know that radio communication have given birth to the modern communication gadgets that we have now that involves the fact that we can be able to send signals over a very long distance.
It should be noted that the use of the radio waves is made quite easy because the radio waves can be able to travel across a very large distance and can be able to move at a very fast pace from one place to the other.
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Answer:
Explanation:
a
Look at the circuit diagram.
What type of circuit is shown?
open series circuit
open parallel circuit
closed series circuit
closed parallel circuit
Answers
The type of circuit shown in the diagram is a closed series circuit. The Option C.
What type of circuit is depicted in the circuit diagram?The circuit diagram illustrates a closed series circuit, where the components are connected in a series, forming a single loop. In a closed series circuit, the current flows through each component in sequence, meaning that the current passing through one component is the same as the current passing through the other components.
The flow of current is uninterrupted since the circuit forms a complete loop with no breaks or open paths. Therefore, the correct answer is a closed series circuit.
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Blood enters the right side of the heart and travels to the lungs. There, the lungs eliminate carbon dioxide and exchange it for more oxygen. The oxygen-rich blood enters the left side of the heart. Then, arteries carry blood away from the heart. What process is being described?
Answers
Answer:
Blood circulation
Explanation:
The process being described is the circulation of blood.
Oxygen-rich blood leaves the heart through arteries and is transported to various cells and tissues where the exchange of oxygen for carbon dioxide takes place. Thereafter, the oxygen-deficient/carbon dioxide-rich blood moves into the veins and returns to the right side of the heart before traveling to the lung. In the lung, the carbon dioxide in the blood is exchanged for oxygen before the blood enters the left side of the heart and circulated all over again.
The equation y = 5 Sin (3x - 4t), where
y is in millimeters, x is in metres and t
is in seconds, represents a wave motion.
Determine the (i) frequency (ii) period
(iii) speed of the wave.
Answers
Answer:
Frequency, f = 0.63 Hz
Period, T = 1.58 s
Speed of a wave, v = 1.34 m/s
Explanation:
The equation of a wave is given by :
\(y = 5 \sin (3x - 4t)\) ...(1)
y is in mm
x is in meters
t is in seconds
The general equation of a wave is given by :
\(y=A\sin(kx-\omega t)\) ...(2)
(i) Compare equation (1) and (2) we get :
\(k=3\\\\\omega=4\)
Since,
\(\omega=2\pi f\\\\f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\f=0.63\ Hz\)
(ii) Period of wave is :
\(T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.63}\\\\T=1.58\ s\)
(iii) Speed of a wave,
\(v=\dfrac{\omega}{k}\\\\v=\dfrac{4}{3}\\\\v=1.34\ m/s\)
A uniform solid sphere rolls down an incline. a) What must be the incline angle (in degrees) if the linear acceleration of the center of the sphere is to have a magnitude of 0.23g? b) If a frictionless block were to slide down the incline at that angle, would its acceleration magnitude be more than, less than, or equal to 0.23g?
Answers
The incline angle should be about 4.7 degrees and the block's acceleration would be greater than that of the rolling sphere.
a) Let M be the mass of the sphere, R be its radius, and θ be the incline angle. When the sphere rolls down the incline without slipping, the friction force acting on it causes a torque about its center of mass, which results in a rotational acceleration. If a is the linear acceleration of the center of mass, and α is the angular acceleration, then we have:
a = α R
Also, the torque τ caused by the friction force is given by:
\(τ = I α\)
where I is the moment of inertia of the sphere about its center of mass. For a solid sphere, I is given by:
\(I = (2/5) M R^2\)
Since the sphere rolls without slipping, the friction force is related to the normal force N by:
\(f = μ N\)
where f is the friction force, and μ is the coefficient of static friction. The normal force is related to the weight of the sphere by:
N = M g cos θ
where g is the acceleration due to gravity.
The net force acting on the sphere down the incline is given by:
\(Fnet = M g sin θ - f\)
The linear acceleration of the center of mass is given by:
\(a = Fnet / M\)
Substituting for f and N, we get:
\(a = g (sin θ - μ cos θ)\)
Equating this to α R, we get:
g (sin θ - μ cos θ) = α R
Substituting for α using the expression for I and τ, we get:
\(g (sin θ - μ cos θ) = τ / (2/5 M R)\)
Substituting for τ using the expression for f and N, we get:
\(g (sin θ - μ cos θ) = (μ M g cos θ) R / (2/5)\)
Simplifying, we get:
\(tan θ = (5/7) μ\)
Substituting the given values, we get:
tan θ = (5/7) (0.23)
\(θ = arctan(0.082)\)
θ = 4.7 degrees (approximately)
Therefore, the incline angle should be about 4.7 degrees
b) Since the block is frictionless, its acceleration down the incline is given by:
a' = g sin θ
Substituting the value of θ obtained in part a), we get:
a' = g sin(4.7) ≈ 0.41 g
Since this is greater than 0.23g, the block's acceleration would be greater than that of the rolling sphere.
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the amount of energy used to heat a home can be measured using?a. Wattb. Kilowatt hoursc. Joule
Answers
Kilowatt hours are a unit of measurement for the energy required to heat a house. It is the amount of energy used every hour. Hence option B.
Power is a tangible measure of how much work or energy is expended in a certain amount of time. Therefore, power is the rate at which an object expends energy or performs work. Watt is the definition of power. The joule is a unit of both work and energy.
Kilowatts are the unit of measurement for power for higher energy usage. Power input and time are the components of work or energy.
W in J hence equals power in Watt/time in hours.
Kilowatts hours are the unit used to measure domestic energy use. Hence, option B is our answer.
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Korbel pushes a 15 kg chair for a distance of 30 meters. How much
work did he do?
Answers
The work that has been done by the Korbel is 4.41kJ.
What is the work done?We have to note that we define work in physics as the product of the force and the distance. In the case of the chair in the question, we have been told that Korbel pushes a 15 kg chair for a distance of 30 meters.
The force in this case would be the weight of the chair that we have and we can write that;
W = mgh
m = mass
g = acceleration due to gravity
h = height
Thus
W = 15 * 9.8 * 30
W = 4.41kJ
Thus a work of about 4.41kJ is done.
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Una cuerda de 20 pies se estira entre dos arboles. Un peso W cuelga del centro de la cuerda hace que el punto medio de la misma y baja 2 pies. Si la tensión resultante en la cuerda es de 200 lb,¿cual es la manigtud de la masa?
Answers
Answer:
La magnitud de la masa del peso es 78.447 libras-masa.
Explanation:
La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.
Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:
\(\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N]\) (1)
Donde:
\(\vec T_{1}\), \(\vec T_{2}\) - Tensiones a cada lado de la cuerda, en newtons.
\(\vec W\)- Peso, en newtons.
Si sabemos que \(\vec T_{1} = T\cdot (\cos \alpha, \sin \alpha)\), \(\vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha)\) y \(\vec W = W\cdot (0, -1)\), entonces tenemos la siguiente ecuación vectorial:
\(T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)\)
\(T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)\)
Esto permite reducir la anterior expresión a una fórmula escalar:
\(2\cdot T\cdot \sin \alpha = W\)
Donde \(\alpha\) es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.
El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:
\(\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)\)
\(\alpha \approx 11.310^{\circ}\)
Si conocemos que \(\alpha \approx 11.310^{\circ}\) y \(T = 200\,lbf\), entonces la magnitud del peso es:
\(W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}\)
\(W \approx 78.447\,lbf\)
En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es \(78.447\,lbm\).
La magnitud de la masa del peso es 78.447 libras-masa.
Velocity is a: a) Fundamental quantity b) MKS system c) Standard system d) Derived quantity
Answers
Velocity is a derived quantity, which is derived from two fundamental quantities ilength ( displacement ) and time
it can be depicted as :
\( \boxed{ \boxed{velocity = \dfrac{displacement}{time} }}\)Jose conducted an experiment to measure the rate of minerals dissolving in water and changed the temperature of the water for each trial.
What is the independent variable in this experiment?
A: number of trials being tested
B: temperature of the water
C: type of minerals used for each trial
D: rate the minerals dissolved
Answers
The temperature of the water is the independent variable because it is being deliberately changed by the experimenter to see how it affects the rate of mineral dissolution. Option B.
What is an independent variable?The independent variable is the variable that the researcher intentionally changes or manipulates in an experiment in order to observe its effect on the dependent variable.
In this case, the independent variable is the temperature of the water because it is what Jose is changing in each trial to see how it affects the rate at which the minerals dissolve.
The dependent variable, on the other hand, is the rate at which the minerals dissolve, because it is what is being measured and expected to change based on the independent variable.
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Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.
Answers
Answer:
Sound waves bend around the corners of various obstacles.
Explanation:
I took the test
Which of the following is a real-life example of a rotation?
a ceiling fan
a butterfly's wings
O going down a slide
opening a sliding glass patio door
None of the other answers are correct
Answers
Answer:
a ceiling fan a ceiling fan
if a man pushes a lawn mower with a force of 20 lb a distance of 60 feet down a yard how many ftlbs of work did he do
Answers
The work is given by:
\(W=Fd\)Plugging the values given we have:
\(W=(20)(60)=120\)Therefore the man do 120 ft*lb of work
which of the following is not a lever?
a. winch
b. scissors
c. can openers
d. tweezers
Answers
Answer:
a?
Explanation:yes it is a
how much energy is transported across a 1.45 cm2 area per hour by an em wave whose e field has an rms strength of 30.3 mv/m
Answers
The amount of energy transported across a given area by an electromagnetic (EM) wave can be calculated using the formula: Energy = Power x Time.
In this case, we are given the area (1.45 cm²), the RMS strength of the electric field (30.3 mV/m), and the time (1 hour). We can calculate the power using the formula: Power = (E-field RMS)² / (2 x Z₀), where Z₀ is the impedance of free space (approximately 377 ohms). Once we have the power, we can multiply it by the time to obtain the energy transported.
Using the given information, we can calculate the power as (30.3 mV/m)² / (2 x 377 ohms), which is approximately 0.2442 mW. Multiplying this power by the time (1 hour = 3600 seconds), we find that the energy transported across the given area per hour is approximately 878.88 mJ.
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In a dentist's office an X-ray of a tooth is taken using X-rays that have a frequency of 4.99 × 1018 Hz. What is the wavelength in vacuum of these X-rays?
Answers
The wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. In a dentist's office, an X-ray of a tooth is taken using X-rays that have a frequency of 4.99 × 10^18 Hz. To calculate the wavelength in vacuum of these X-rays, we can use the equation:
wavelength = speed of light / frequency
The speed of light in vacuum is approximately 3 × 10^8 meters per second. Plugging in the given frequency, we get:
wavelength = (3 × 10^8 m/s) / (4.99 × 10^18 Hz)
Simplifying this expression, we get:
wavelength = 6.01 × 10^-11 meters
Therefore, the wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. It's important to note that X-rays have a very short wavelength, which allows them to penetrate through tissues and bones. However, this also means that they can be harmful if not used carefully and with proper shielding.
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An object with a charge of -3C is touched to an object with a charge of -1C. What is the new charge on each object?
Answers
After connecting the conducting wire, the spheres will redistribute charges until they both have a charge of -1C.
To determine the new charges on the spheres, we need to consider the principle of charge conservation, which states that the total charge before and after an interaction remains the same.
Let's assume that the spheres have charges Q1 and Q2 initially. In this case, Q1 = -3C and Q2 = +1C.
When a conducting wire is connected between the spheres, charge can redistribute until the system reaches equilibrium. Since the spheres are conducting, charges are free to move within them.
In the final state, the charges on the spheres will redistribute to reach a new equilibrium. Let's assume the new charges on the spheres are Q1' and Q2'.
According to the principle of charge conservation, the total charge before and after the connection remains the same:
Initial total charge = Q1 + Q2 = -3C + 1C = -2C
Final total charge = Q1' + Q2'
Since the total charge remains the same, we can write the equation:
Q1' + Q2' = -2C
Since the spheres are of equal size, we can assume that the charges redistribute equally:
Q1' = -1C
Q2' = -1C
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The question probable may be:
A conducting wire is connected between two conducting spheres of equal size have a charge of -3C and +1C respectively. Find out the new charge on each sphere ?
Un globo es inflado hasta obtener 1.5 atm, con un volumen de 500 cm³ a 273 K. Luego, es colocado en el frezzer ¿Cuál será su temperatura, con 1.2 atm y 300 cm³?
Answers
Respuesta: T2 = 131.04K
Explicación: Dado lo siguiente:
Presión, P1 = 1.5 atm = 1.5 × 760 = 1140 mmHg
Presión, P2 = 1.2 atm = 1.2 × 760 = 912 mmHg
Volumen, V1 = 500cm3 Volumen, V2 = 300cm3
Temperatura, T1 = 273K Temperatura, T2 =?
Usando la fórmula de gas combinada:
P1V1 / T1 = P2V2 / T2
Ingresando nuestros valores:
(1140 × 500) / 273 = (912 × 300) / T2
T2 × (1140 × 500) = 912 × 300 × 273
T2 = 74692800/570000 T2 = 131.04K
Find an analytic expression for the transfer function H()H(ω) of a high pass RC filter in terms of R and C.
Answers
The transfer function H(ω) of a high pass RC filter can be expressed as: H(ω) = -jωRC / (1 - jωRC)
where R is the resistance and C is the capacitance of the filter. This expression represents the ratio of the output voltage to the input voltage at a given frequency ω. As the frequency increases, the impedance of the capacitor decreases, allowing more signal to pass through to the output. This causes the transfer function to approach a value of 1, indicating that the filter is no longer attenuating high frequency signals. At low frequencies, the impedance of the capacitor is high, causing the output to be attenuated.
This results in a transfer function that approaches 0, indicating that low frequency signals are being filtered out. The high pass RC filter is a common type of filter used in audio and signal processing applications to remove unwanted low frequency noise.
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Complete the statement below with all that apply.
Acceleration is
A. the slope of a velocity vs. time graph
Pector
B. a Vector
C. measured in m/s
D. the change in displacement divided by the change in time
Answers
Answer:
Acceleration is a vector, is measured in m/s, and A.
Explanation: SO BASICALLY, the answer to this question is A, B, and C. The last one would not fit the description of acceleration because it is describing Velocity.
rank the light intensity, from largest to smallest, at the point p in the figures.
Answers
The light intensity from largest to smallest ranking will be :B > D > A=C > E. where the area is measured on the plane perpendicular to the direction .
In physics, the intensity is the amount of energy that is transmitted per unit area, and the area is measured on a plane perpendicular to the direction that the energy equation will propagate. I = P/ 4(d2), with P denoting power. Let power of 1 bulb equal = P where I = intensity, d = distance at which the intensity must be determined.
case A = I = P / (1) (1) 1 = P case with 2 = P In the situation B = I = 2P/(0.5)2 = 8P C = I = 4P / (2) (2) ^2 = P case Case (1)2 = 3P: D = I = 3P E = I = 2P /(1.5) (1.5) ^2 = 0.8 P
B > D > A=C > E will be the order of light intensity, from greatest to least.
rank the light intensity, from largest to smallest, at the point p in the figures?
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About atoms and molecules plz!?
Answers
Answer:
Atoms: They are the smallest part of matter that may or may not exist independently. When atoms come together they form molecules.
Molecules: Many atoms combined either chemically or naturally form molecules. They are the smallest unit of matter that exist independently.
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