Answer:
1) Decreases
2) Inverse Proportionality
3) 1 A
Explanation: Just Did Em'
Answer:
Decreases
Inverse Proportionality
1 A
Explanation:
correct on quiz EDGE2021
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A block of mass 10 kg on a 30° inclined plane is being pushed by a horizontal force F as shown in the figure below. Find: 1) II) iii) the time it takes to move the block up the incline by a distance of 2 m, if the block starts from rest and the surface of the inclined plane is smooth and F = 100 N. [5] the horizontal force needed to move the block 2 m up the incline in a time of 1 s, if the surface is rough with coefficient of kinetic friction of 0.2 between it and the block and the block starts from rest. [8] the time the block will take to reach a speed of 5 ms¹ starting from rest at the top when the force F is removed and the surface is smooth. [7] F=100N 10 kg 30
The diagram and specific values for angle, mass, and force are missing from the question, making it difficult to provide exact numerical solutions. However, the provided solution approach should help you solve the problem once you have the necessary values.
To solve the given problems, we need to use principles of Newton's laws of motion and the equations of motion. Here are the solutions to each part:
To find the time it takes to move the block up the incline by a distance of 2 m, we need to consider the forces acting on the block. The force component acting parallel to the incline is F_parallel = F * sin(30°). The force component perpendicular to the incline is F_perpendicular = F * cos(30°). The net force acting up the incline is F_net = F_parallel - frictional force.
Using Newton's second law, F_net = m * a, we can calculate the acceleration of the block. Then, we can use the equation of motion, d = v_i * t + (1/2) * a * t^2, where d is the distance (2 m) and v_i is the initial velocity (0 m/s) to solve for time (t).
To find the horizontal force needed to move the block 2 m up the incline in 1 second, considering a rough surface with a coefficient of kinetic friction (μ = 0.2), we need to calculate the frictional force. The frictional force can be determined as F_friction = μ * N, where N is the normal force. The normal force can be found as N = m * g * cos(30°). Then, we can find the net force acting up the incline as F_net = F - F_friction and use the same approach as in part 1 to find the required force.
To find the time it takes for the block to reach a speed of 5 m/s starting from rest at the top, when the force F is removed and the surface is smooth, we need to use the equation of motion, v_f = v_i + a * t, where v_f is the final velocity (5 m/s), v_i is the initial velocity (0 m/s), and a is the acceleration due to gravity (g). Rearranging the equation, we can solve for time (t).
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Waste of points. Claim if you want.
In 2012, NASA sent the 900kg Curiosity robot to Mars to study the planet. a) Recall the relationship between the weight P and the mass m. Specify the units. b) What is the weight of Curiosty on Mars? c) Compare the weight of Curiosity on Earth and on Mars. Why is it more important on Earth
(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
(b)The weight of Curiosity on Earth is approximately 8820 Newtons.
a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.
c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.
The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.
It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.
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Classify the following situations into contact and non-contact forces.
(a) Applying brakes in a vehicle
(b) a coconut falling from a coconut tree
(c ) the planets revolving around the sun
(d) a ball is rolling on ground.
Answer: Contact force
a. Applying break in a vehicle.
d. The speed of ball rolling on ground is reduced
Non contact force
b. A coconut falling from a coconut tree.
c. The planets revolving around the sun.
Explanation:
The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.
The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.
A satellite of mass M2 orbits a planet of mass M1 in a uniform circular orbit with a constant tangential velocity, v. The distance between the satellite and the center of the planet is d. If the satellite is moved such that the distance between the satellite and the center is doubled, what is the new gravitational field strength compared to the original gravitational field strength?
The gravitational field strength of the moon at this new distance is gr/4
What is meant by gravitational field ?The gravitational field is the amount of gravitational force that would be applied to a little mass at that location per unit of mass. It is a vector field that is oriented in the mass's expected direction of force.
A gravitational field is the force field that surrounds any mass or collection of masses in space. Although this field spreads out in all directions, the gravitational force becomes weaker the further an object is from the source. This is a method of calculating the gravitational pull. Weight divided by mass equals the strength of the gravitational field. Strength of gravitational field = mass/weight in kilograms, or N/kg.
The complete question is : A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v.
The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?
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In order to use a crowbar, you apply 12 N of force. The crow bar applies 38 N of force. What is the mechanical advantage of the crowbar?
The mechanical advantage of the crowbar is 3.1667.
What is mechanical advantage of inclined plane ?The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane.
The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.
Given parameters:
Input force by you= 12 N.
Output force from the crowbar = 38 N.
Then, the mechanical advantage of the crowbar = Output force from the crowbar / input force by you.
= 38N/12N.
=3.1667.
Hence, the mechanical advantage of the crowbar is 3.1667.
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A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.
Figure 4.29
(a) Calculate the minimum force F he must exert to get the block moving.
40.873
(b) What is its acceleration once it starts to move, if that force is maintained?
m/s2
(a) The minimum force F he must exert to get the block moving is 38.9 N.
(b) The acceleration of the block is 0.79 m/s².
Minimum force to be applied
The minimum force F he must exert to get the block moving is calculated as follows;
Fcosθ = μ(s)Fₙ
Fcosθ = μ(s)mg
where;
μ(s) is coefficient of static frictionm is mass of the blockg is acceleration due to gravityF = [0.1(36)(9.8)] / [(cos(25)]
F = 38.9 N
Acceleration of the blockF(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32
a = F(net)/m
a = 28.32/36
a = 0.79 m/s²
Thus, the minimum force F he must exert to get the block moving is 38.9 N.
The acceleration of the block is 0.79 m/s².
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the surface of a mirror is flat.
Answer:
plane on edge
Explanation:
Please why does a simple pendulum graph fail to pass through the origin ?
Answer:
The friction of the string and its pivotal anchor point cannot be eliminated. The precise measurement of the length of the pendulum is difficult to take by using meter sticks or rulers. The value of the acceleration due to gravity g in the locality is not constant and must be obtained from reliable sources.
You cannot completely remove the friction between the string and its key anchor point. Using meter sticks or rulers makes it challenging to take an accurate measurement of the pendulum's length. Since it is not constant, it is necessary to get accurate information on the local gravity acceleration related to g.
What is a pendulum?The body is suspended from a central object to act as a pendulum that swings back and forth as a result of gravity. Because the period—the amount of time between each full oscillation—is constant, pendulums are employed to control the movement of clocks. The formula for a pendulum's period T is T = 2 Square root of L/g, where L is the pendulum's length and g is the acceleration brought on by gravity.
Galileo, an Italian scientist, made the first observation about the consistency of a pendulum's period by contrasting the motion of a swinging lantern in a cathedral in Pisa with his heart rate.
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An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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for stairway lighting, a typical installation is to install a 3-way switching system. for a dwelling, for stairway lighting control. t/f
True. A 3-way switching system is a common installation for stairway lighting control.
This system allows you to control the lights from two locations. For example, if you want to turn the lights on at the bottom of the stairs, you can use the switch at the top of the stairs. This allows you to turn the lights on when you come down the stairs and off when you go up the stairs.
It also allows you to turn the lights off at the bottom of the stairs, which is convenient if you are leaving the house. Additionally, it allows you to have a light on at the bottom of the stairs to provide a safety measure at night. The 3-way switching system is an effective and efficient way to control lighting in a dwelling.
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who discovered the law of gravity and motion?
Answer:
Physically, Sir Isaac Newton was not a large man. However, he had a large intellect, as shown by his discoveries on gravity, light, motion, mathematics, and more. Legend has it that Isaac Newton came up with gravitational theory in 1665, or 1666, after watching an apple fall.
Explanation:
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Study the diagram and calculate the effort required to balance the load
Answer:
Solution given;
load =600N
effort=?
load distance: 0.6m
effort distance;2.6m
we have
load *load distance :effort *effort distance
0.6*600=effort *2.6
360/2.6=effort
effort:138.46N
Required effort is 138.5N.
Calculate the extension of a 20cm spring that has a spring contrast of 45000N/m and 1500N of elastic potential energy.
Answer:
See the answer below
Explanation:
The elastic potential energy can be calculated by means of the following equation:
\(E_{el}=\frac{1}{2} *k*x^{2}\)
where:
Eel = elastic energy = 1500 [J]
k = spring constant = 45000 [N/m]
x = extension [m]
\(1500=\frac{1}{2} *45000*x^{2} \\3000=45000*x^{2} \\x=\sqrt{0.06666}\\x=0.258[m] = 25.8 [cm]\)
A superelastic collision is one in which...
A. kinetic energy before the collision equals kinetic energy after the collision.
B. kinetic energy after the collision is zero.
C. kinetic energy before the collision is less than kinetic energy after the collision.
D. kinetic energy before the collision is greater than kinetic energy after the collision.
Answer: ~Y/n here~ Your answer I believe would be:
A. kinetic energy before the collision equals kinetic energy after the collision.
(Hope this helps!)
a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity
Answer:
v = 1.098 m/s
Explanation:
Given that,
A person walks 750m due north then 250 m due east of the entire walk takes 12 min.
We need to find the average velocity of the person.
Displacement,
\(d=\sqrt{750^2+250^2} \\\\d=790.56\ m\)
Average velocity = displacement/time
\(v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s\)
So, the average velocity of the person is 1.098 m/s.
Help me out on this? Grades due in a couple days and I need to get everything done on time-
Answer:
75mL
...............
The question is full of inconsistencies and conceptual errors. Students should not waste their time trying to answer it ... it will only mislead and confuse them.
The question is poor. It was written by someone unclear on the concepts. It should be ignored.
A proton is released in a uniform electric field, and it experiences an electric force of 1.86x10-14 N toward the south. Find the magnitude and direction of the electric field.
The magnitude and direction of the electric field is 1.05×10^5N/C
The Electric Field is described as the electric force per unit charge.
E=\(\frac{F}{q}\)
Here, F is an electric force,E is the Electric Field and q is a charge. charge is measured in coloumb.
For finding the magnitude, the expression can be use as follows,
E=\(\frac{F}{q}\)
now put all the values given
F= 1.86x10^-14 N
q=1.6×10^-19C
E= 1.86x10^-14 N÷1.6×10^-19C
E=1.05×10^5N/C
Since the charged particle is positive electric field and Electric Field will have the same directions. Proton has positive charge hence here the direction of the electric field is the same as the direction of electric force. Hence towards South for both.To know more about Electric Field visit : https://brainly.com/question/26690770
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If a stone dropped into a well reaches the waters surface after 3.0 seconds how far did the stone drop before hitting the water
Stone travels at the distance of 44.1 meters far did the stone drop before hitting water.
What is the distance ?
Distance is a numerical and sometimes qualitative measure of how far apart an object or point is. In physics or everyday use, distance can refer to estimates based on physical length or other criteria.
How can distance used in real life?
I am using it in my navigation. Airplane pilots use distance formulas to calculate the distance between their plane and other planes. Find the coordinates of the plane and then apply the distance formula to get the distance.
What is the use of distance?
(i) indicate body position at any point in time; (ii) You can see a graph of the distance your body has moved in a certain period of time. (iii) The object's velocity can be determined at any point in time.
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A container contains a number of marbles each having a mass 80 mg. If the total mass of the marbles in the container is 2 kg. find the numbers in the container
Answer:
There are 25,000 marbles in the container
Explanation:
There is a certain number of marbles in a container.
We know each marble has a mass of 80 mg and we also know the total mass of the marbles in the container is 2 Kg.
Since the data is given in different units of mass, we convert them into one unit in common.
Let's convert 2 Kg to milligrams. There are 1,000 grams in a kilogram, and there are 1,000 milligrams in a gram, thus there are one million milligrams in one kilogram, that is:
1 Kg = 1,000,000 mg
And 2 Kg = 2,000,000 mg
The number of marbles can be found by dividing the total mass by the individual mass:
No. of marbles = 2,000,000 / 80 = 25,000
There are 25,000 marbles in the container
The stage in cell division in which chromosomes replicate themselves.*
Interphase
Metaphase
Telophase
Anaphase
Answer:
interphase
Explanation:
Hydropower is alternative source of energy
Answer:
Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.Answer:
because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.
Explanation:
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A spherical convex mirror has a radius of 30 cm. An object with a height of 0.30 m is placed 20 cm from the mirror. Note that in +/- sign conventions, f is negative (–) if the mirror is a convex mirror. a. Calculate the image distance. b. Calculate the image height. c. Calculate the magnification. d. Summarize the properties of the image formed in terms of its LOST (location, orientation, size, and type). e. Draw the set-up using graphical methods (ray diagramming). Apply scale drawing. Make sure that your illustration matches well with what you have calculated and presented in a-d.
a)A spherical convex mirror form the image at image distance is 8.57cm.
b) Mirror forms the image of height is 12.855 cm.
c)The magnification of the spherical convex lens is 0.4285.
What is convex mirror?The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.
The focal length of convex lens, f = R/2
Given , the radius of mirror is R =30cm, the focal length will be
f =30cm/2 = 15cm
a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.
1/15 = 1/20 + 1/v
v= 8.57 cm
Thus, the image distance is 8.57cm.
b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.
Substitute the values into the expression, we get the image height as
h(image) = 8.57/20 x 30
h(image) = 12.855 cm
Thus, the image height is 12.855 cm.
c) The magnification is the ratio of image height to the object height.
Putting the values, we have
= 12.855/30
= 0.4285
Thus, the magnification is 0.4285.
d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.
e) The setup drawing is attached.
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define refractive index.
mention the formula used to calculate it.
tysm~
Answer:
Explanation:
Refractive index refers to the ratio between the speed of an electromagnetic wave in a vacuum and its speed in another medium. It indicates the degree of refraction that would occur in a particular material. Furthermore, the refractive index through a vacuum is 1. One can define the normal as the perpendicular line to the surface of the interface. In such a case, a higher value of refractive index would certainly mean that the bend of the ray is towards the normal.
n = c/v
n = refractive index of the medium
c = speed of light when in vacuum
v = speed of light when in medium
now that you know about newton's first law of motion, how might you use it to ride a skateboard safely?
Answer:
newton's first law of motion was developed by English scientist Isaac Newton around 1700. Newton was one of the greatest scientists of all time. He developed three laws of motion and the law of gravity, among many other contributions.
Explanation:
Using the following picture, who has a higher kinetic energy, the woman or the rabbit? How do you know?
We will have the following:
We determine both kinetic energies:
*Person:
\(k_p=\frac{1}{2}(60kg)(5m/s)^2\Rightarrow k_p=750J\)*Rabbit:
\(k_r=\frac{1}{2}(4kg)(5m/s)^2\Rightarrow k_r=50J\)So, the person has a greater kinetic energy than the rabbit. And we know it by running the calculations and seeing that the values of energy are greater for the person.
A white flower (rr) is crossed with a white flower (rr) (purple is dominant). What percent will be purple?
Answer:
0%
Explanation:
There is no purple geneotype with either parents so there will be 0 purple and 100% white
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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which wavelengths does nitrogen catch ?
Answer:
The strongest lines are at 337.1 nm wavelength in the ultraviolet. Other lines have been reported at 357.6 nm, also ultraviolet. This information refers to the second positive system of molecular nitrogen, which is by far the most common.
Explanation: