What was the revolution in atomic theory produced by the discovery of the electron?

Answer:

Explanation:

Use the one-dimensional equation:

\(v_f=v_0+at\) which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:

-14.5 = 0 - 9.8t and

-14.5 = -9.8t so

t = 1.5 seconds

Sea creature that has the most momentum is Sea Turtle.

Momentum, manufactured from the mass of a particle and its pace. Momentum is a vector amount; i.e., it has each significance and route. Isaac Newton's 2nd regulation of movement states that the time fee of extrude of momentum is same to the pressure appearing at the particle. See Newton's legal guidelines of movement.

Momentum is described as the amount of movement of the frame.

It is measured by “mass × pace”, as momentum relies upon upon pace, and it relies upon at the route of the movement of the frame as well. Momentum is a vector amount due to the fact that pace is a vector at the same time as mass is scalar.

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1. Diagram and Variables:

                                   Maximum Height

                                          |

                                          |

                                          |

                                          |

                                          |

                                          |

                                          |

                                          |

                                          |

------------------------ Ground ------------------------>

Variables:

Initial velocity (v₀) = 90 m/s

Launch angle (θ) = 45°

Maximum height (H)

Time of travel at maximum height (t_max_height)

Horizontal displacement at maximum height (d_max_height)

Time of travel at maximum range (t_max_range)

Horizontal displacement at maximum range (d_max_range)

2. For when the round reaches maximum height:

a) Time of travel (t_max_height):

At the maximum height, the vertical velocity (v_y) becomes zero. To find the time it takes for the round to reach the maximum height, we can use the equation for vertical motion:

v_y = v₀ * sin(θ) - g * t

0 = v₀ * sin(θ) - g * t_max_height

Solving for t_max_height:

t_max_height = v₀ * sin(θ) / g

Substituting the values:

t_max_height = 90 m/s * sin(45°) / 9.8 m/s²

Calculating the value:

t_max_height ≈ 6.12 s

b) Horizontal displacement (d_max_height):

The horizontal displacement at maximum height can be calculated using the equation:

d_max_height = v₀ * cos(θ) * t_max_height

Substituting the values:

d_max_height = 90 m/s * cos(45°) * 6.12 s

Calculating the value:

d_max_height ≈ 385.94 m

Therefore, at the maximum height, the time of travel is approximately 6.12 seconds, and the horizontal displacement is approximately 385.94 meters.

3. For when the round reaches maximum range:

a) Time of travel (t_max_range):

To find the time it takes for the round to reach the maximum range, we can consider the symmetry of projectile motion. The time of flight (t_flight) is twice the time it takes to reach maximum height:

t_flight = 2 * t_max_height

Substituting the value of t_max_height:

t_max_range = 2 * 6.12 s

Calculating the value:

t_max_range ≈ 12.24 s

b) Horizontal displacement (d_max_range):

The horizontal displacement at maximum range can be calculated using the equation:

d_max_range = v₀ * cos(θ) * t_max_range

Substituting the values:

d_max_range = 90 m/s * cos(45°) * 12.24 s

Calculating the value:

d_max_range ≈ 868.63 m

Therefore, at the maximum range, the time of travel is approximately 12.24 seconds, and the horizontal displacement is approximately 868.63 meters.

When a mortar is fired at an angle of 45 degrees, it will reach its maximum height in 6.49 seconds and its maximum range in 12.98 seconds. The horizontal displacement of the mortar when it reaches its maximum height will be 413.02 meters, and its horizontal displacement when it reaches its maximum range will be 826.53 meters.

1. To draw a diagram of the described scenario, you can start by drawing a coordinate system. The x-axis represents the horizontal direction, and the y-axis represents the vertical direction. Place the origin (0, 0) at the point of launch. Since the mortar is angled 45 degrees from the horizontal, you can draw a line representing the initial direction of the round at a 45-degree angle from the x-axis.

Next, label the variables along the x and y dimensions. For the x-dimension, you can label the variable as "horizontal displacement" or simply "x." For the y-dimension, you can label the variable as "vertical displacement" or "height" and indicate that it is measured in meters.

2. When the round reaches maximum height:

a)

The time of ascent  can be calculated using the following formula:

time = ( initial velocity * sin(angle)) / acceleration due to gravity

In this case, the initial velocity is 90 meters per second, and the angle is 45 degrees. The acceleration due to gravity is typically considered to be approximately 9.8 meters per second squared.

Plugging in the values:

time = (90 * sin(45)) / 9.8  = 6.49s

b) The horizontal displacement at maximum height is :

horizontal displacement = initial velocity * cos (45) * time of ascent

Plugging in the values:

horizontal displacement=90* cos (45) * 6.49s= 413.02m

3. When the round reaches maximum range:

a) The time of travel can be calculated using the following formula:

time = (2 * initial velocity * sin(angle)) / acceleration due to gravity

The initial velocity and angle remain the same.

Plugging in the values:

time = (2 * 90 * sin(45)) / 9.8= 12.98s

b) The horizontal displacement at maximum range can be calculated using the following formula:

horizontal displacement = (initial velocity^2 * sin(2*angle)) / acceleration due to gravity

Plugging in the values:

horizontal displacement = (90^2 * sin(2*45)) / 9.8= 826.53m

Therefore, A mortar will reach its maximum height and distance when shot at a 45-degree angle in 6.49 and 12.98 seconds, respectively. When the mortar achieves its maximum height, its horizontal displacement will be 413.02 meters, and when it reaches its maximum range, it will be 826.53 meters.

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Answer:

we don't have that's bevause in our english physics and I have some ego problems and we are going out with a family emergency so no worries if we can fix the phone on your phone at a reasonable time please send.

Explanation:

it's a bit of an issue with my life insurance and the insurance is going out for a day in the world school fees of my life.I and I have to pay for my whole entire month for my whole entire month but will not have any further to do you have the money in my account so I need for the rest in the world school to get broken down on my side of my life.I and the rest in the world school and the school physics will talk about the future of my life.I and I don't want you don't.

Answer:

The answer is flint glass.

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer: 1/gk

Explanation: 15(22/330kg) (330/330gk) = 1/gk

Answer:

mooses                                                           .

Explanation:

because i searched it up for you

Answer:

A. Trees

Explanation:

got 100 on progress learning because im just that guy.

Answer:

c. Was an idea created and supported by Congress.

Explanation:

The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803) was an idea created and supported by Congress.

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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Answer:

The ozone layer is like the Earth's sunscreen, as it absorbs some of the sun's radiation hitting our planet

Explanation:

Answer:

The length of the spring is 44.92 cm

Explanation:

Hooke's Law

Suppose a spring of constant k and natural length x0. If a force F is applied to the spring and it stretches to a distance x1. Hooke's Law states that:

\(F=k.x\)

Where x is the elongation of the spring:

\(x=x1-x0\)

We are given the characteristics of a spring of x0=31 cm. When a mass of m=8 Kg is hung from the spring, it stretches to x1=36.9 cm. We need to calculate the force of the mass of 8 Kg. It can be done by calculating the weight:

\(F = m.g=8\ Kg\cdot 9.8\ m/s^2\)

\(F=78.4\ N\)

The elongation of the spring is

\(x=36.9\ cm - 31\ cm = 5.9\ cm\)

Converting to meters:

\(x=5.9/100=0.059\ m\)

(a)

From Hooke's Law, we solve for k:

\(\displaystyle k=\frac{F}{x}=\frac{78.4}{0.059}\)

\(k=1,329\ N/m\)

(b) With the value of k, the equation for the spring is:

\(F=1,329.x\)

Now if a weight of F=185 N is hung from the spring, the elongation is:

\(\displaystyle x=\frac{F}{1,329}=\frac{185}{1,329}\)

\(x=0.1392\ m=13.92\ cm\)

Thus, the length of the spring is:

\(x1=xo+x=31\ cm+13.92\ cm=44.92\ cm\)

The length of the spring is 44.92 cm

(a)The spring constant will be 1,329 N/m.

(b)The length of the spring will be 44.92 cm.

Spring constant is defined as the ratio of force per unit displaced length. The spring force is balanced by the weight;

The given data in the problem is;

L₁  is the long spring is hung vertically from a ceiling= 31.0 cm

L₂  = 36.9 cm

m is the mass= 8.00 kg

The net elongation of the spring is

x= 36.9-31 =5.9 cm = 0.059 m

The force acted on the spring due to which the elongation is done;

F=mg

F= 8 × 9.81

F=78.4 n

From the Hooke's law the spring constant is found as;

\(\rm K = \frac{F}{x} \\\\ \rm K = \frac{78.4}{0.059} \\\\ \rm K = 1,329 \ N/m\)

Hence the spring constant will be 1,329 (in N/m).

(b) The length of the spring will be 44.92 cm.

For the  weight of F=185 N is hung from the spring, the elongation is:

\(\rm x= \frac{185}{1,329} \\\\ \rm x=0.10392 m = 13.92 \ cm\)

The length of spring is;

\(\rm x_1 = x_0+x \\\\ \rm x_1 = 31+13.92 \\\\ \rm x_1=44.92\ cm\)

Hence the length of the spring will be 44.92 cm.

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Answer:

7 degree

Explanation:

given data

width = 4.1 inches

length = 35.4 inches

solution

we consider as per fig

O is mid point of BC

so  OB  = 2.05 inches

and

AB = \(\sqrt{OB^2 + OA^2}\)

AB = \(\sqrt{2.05^2 + 35.4^2}\)

AB = 35.078 inches

so

\(sin \frac{\alpha }{2} = \frac{OB}{AB}\)

\(sin \frac{\alpha }{2} = \frac{2.05}{35.078}\)

\(\alpha = 7 degree\)

If the bullet lost 1960 J of kinetic energy and high-speed photos of the bullet show that it was moving at 965 m/s just as it struck the absorber, then the mass of the bullet would be  4.2 grams.

As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.

ME = KE + PE

As given in the problem bullet is fired into a large stationary absorber and comes to rest. Temperature measurements of the absorber show that the bullet lost 1960 J of kinetic energy and high-speed photos of the bullet show that it was moving at 965 m/s just as it struck the absorber.

The total kinetic energy of the bullet is given by

KE = 1/2mv²

1960= 0.5*m*965²

m = 1960 / (0.5*965*965)

   =.0042 Kilograms

   = 4.2 grams

Thus, the mass of the bullet would be  4.2 grams.

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Answer:

If an object gains electrons it becomes positively charged.

Explanation:

Electrons negatively charge.

A 90.0 kg skler glides down a slope with an incline of 17.0°. Uniform frictional force is needed for the skier to move at a constant velocity.

Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, like the traction required to walk without slipping, may be advantageous, they also pose a significant amount of resistance to motion. Automobile engines need around 20% of their output to overcome frictional forces in moving components.

The adhesion forces between the contact zones of the surfaces, which are always microscopically uneven, appear to be the primary cause of friction between metals. Shearing these "welded" joints and the action of the tougher surface's imperfections scrubbing against the softer surface cause friction. Friction is resistance tot he velocity.

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ANSWER

The mass of the student is 53.00kg

EXPLANATION

Given that;

The weight of the student = 520N

Follow the steps below to find the mass of the student

Step 1: Define weight

Weight s defined as the force acting on an object due to acceleration due to gravity

Step 2: Write the formula linking the mass and the acceleration due to gravity together

Where

W is the weight of the body

m is the mass of the body

g is the acceleration due to gravity

Step 3: Substitute the given data into the formula in step 2

Hence, the mass of the student is 53.00kg

Answer: las respuestas correctas son b, c y  d.

indican cantidad

The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm

Formula Used: Resistivity (ρ) = (RA)/L

Where, R is resistance, A is the area of cross-section, L is the length of the wire.

Resistance (R) = ρ (L/A)

Multiplying A on both sides, we get

Resistance (R) x A = ρ L ... equation (1)

Area of the cross-section of a wire of radius (r) is given by, A = πr^2

where, π is a constant whose value is 3.14

Substituting the given values, we get

A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2

Substituting the values of R, A and ρ in equation (1), we get

Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m

Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

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The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Answer:

The wavelengths are

     \(\lambda_1  =  614\ nm \)

     \(\lambda_2  =  687\ nm \)

\(\lambda_3 = 975\ nm \)

Explanation:

From the question we are told that

The number of slits per mm is N = 1200

The distance of the screen is \(D = 79.0 \ cm = 0.79 \ m\)

The first distance where First-order maxima is observed is \(y_1 = 58.2 cm = 0.582 \ m \)

The second distance where First-order maxima is observed is \(y_2 = 65.2 \ cm = 0.652 \ m \)

The second distance where First-order maxima is observed is \(y_2 = 92.5 \ cm = 0.925 \ m \)

Generally the distance of separation between the slits is mathematically represented as

\(d = \frac{1}{1200}= 8.33 *10^{-4} \ mm = 8.33 *10^{-7} \ m\)

Considering the first distance where First-order maxima is observed

Generally the the first distance where First-order maxima is observed is mathematically represented as

\(y_1 = \frac{\lambda_1 * D}{d}\)

=> \(\lambda_1 = \frac{0.582 * 8.33 *10^{-7} }{0.79}\)

=>     \(\lambda_1  =  6.14 *10^{-7} m \)

=>     \(\lambda_1  =  614\ nm \)

Considering the second distance where First-order maxima is observed

Generally the the second distance where First-order maxima is observed is mathematically represented as

\(y_2 = \frac{\lambda_2 * D}{d}\)

=> \(\lambda_2 = \frac{0.652 * 8.33 *10^{-7} }{0.79}\)

=>     \(\lambda_2  =  6.87 *10^{-7} m \)

=>     \(\lambda_2  =  687\ nm \)

Considering the third distance where First-order maxima is observed

Generally the the third distance where First-order maxima is observed is mathematically represented as

\(y_3 = \frac{\lambda_3 * D}{d}\)

=> \(\lambda_3 = \frac{0.925 * 8.33 *10^{-7} }{0.79}\)

=>     \(\lambda_3  =  9.75 *10^{-7} m \)

=>     \(\lambda_3 =  975\ nm \)

The word or phrase that should be emphasized in the given step to convey order is "Immediately after you pop." Hence, option B  is correct

The phrase "Immediately after you pop" indicates the precise timing for the next step, which is to drag the front foot up and jump forward. It is important to follow this sequence of actions in order to execute the trick correctly.

By emphasizing "Immediately after you pop," the reader or listener will understand that this is a crucial step that should not be delayed or performed out of order. This will help them focus on the timing and make sure they do not miss this important step.

While the other phrases are also important, emphasizing "Immediately after you pop" will ensure that the reader or listener understands the correct sequence of actions and is able to execute the trick properly.

Correct answer is Option B) Immediately after you pop.
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Answer:

−10.1−3.−7VX,2

Explanation:

Answer:

Evaluate (2 - 3)4(4) - 9 ÷ 3.

-7

-2

1

2

Explanation:

answer is 1

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The tower's height would be around 143 m tall.

Solve for the length of the pendulum using the equation for the period of a simple pendulum.

T = 2π√(l/g)

where l = length of pendulum which is equal to height of tower because it touches the almost the floor

T = time, 24 seconds and

g = acceleration due to gravity 9.8 m/s².

Substitute the given values:

24s = 2π√(l/ 9.8 m/s²)

24/2π = √(l/ 9.8 m/s²)

l = (24/2π)² x 9.8 m/s²

l = (12/π)² x 9.8 m/s²

l = 14.59 x 9.8 m/s²

l = 142.982

Therefore, the height of the tower would be 143 m approximately.

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