What type of elements can react with metals to form salts

Maximum number of electrons in nth energy level

\(\\ \sf\longmapsto 2n^2\)

Now

Max electrons

\(\\ \sf\longmapsto 2(1)^2\)

\(\\ \sf\longmapsto 2e^-\)

Answer:

at their own state.

That leaves only five elements: carbon, phosphorus, sulfur, selenium, and iodine, which are all non-metals and are solid at room temperature.

Answer:

2.040 cm

Explanation:

If we study the options closely, we will discover that the chosen option is exactly the same as the actual value of the length of the test tube.

Hence it follows that the option chosen in the answer represents the actual measurement of the length of the test tube as stated above

The relative speed of diffusion of ethene to phosgene is approximately 1.878. The relative speed of diffusion can be calculated using Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

The formula for Graham's law is:

Rate1/Rate2 = √(MolarMass2/MolarMass1)

Given:

Molar mass of ethene (C2H4) = 28.0 g/mol

Molar mass of phosgene (COCl2) = 98.9 g/mol

Let's calculate the relative speed of diffusion:

Rate of ethene diffusion / Rate of phosgene diffusion = √(Molar mass of phosgene / Molar mass of ethene)

Rate of ethene diffusion / Rate of phosgene diffusion = √(98.9 g/mol / 28.0 g/mol)

Rate of ethene diffusion / Rate of phosgene diffusion = √(3.532)

Rate of ethene diffusion / Rate of phosgene diffusion ≈ 1.878

Therefore, the relative speed of diffusion of ethene to phosgene is approximately 1.878.

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Answer: Argon (Ar)

Explanation:

Of the noble gases, Argon (Ar) is present in highest concentration in dry air at sea level.

Answer:

12.66g

Explanation:

42.2% of 30.0g

=42.2/100 * 30.0

=0.422*30.0

12.66g

The command that allows moving a file from one location to another is the "mv command".

The mv command renames or transfers files and folders from one directory to another. A file or directory keeps its base file name when moved to a new directory. All links to other files are preserved when you transfer a file, with the exception of when you move it to a different file system. A directory and its contents are added beneath the existing directory when you transfer a directory into it.

The TargetDirectory option of the mv command allows you to provide a new file name or a new directory path name when renaming a file or directory.

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The relative rates of alkyl halides from fastest sn 1 to slowest sn1 mechanism is CH3 H3C. CH3 H3C. H₂C₂ CH3 CH3.

Alkyl halides can go through one of two different sorts of significant reactions: substitution or elimination.

Nucleophilic Substitution reaction occurs when the halogen at the alpha-carbon is replaced by a nucleophile after the electrophilic alkyl halide forms a new bond with it.

The SN1 reaction mechanism proceeds step-by-step, starting with the formation of the carbocation through the elimination of the leaving group. The nucleophile then attacks the carbocation. Ultimately, the protonated nucleophile is deprotonated to produce the desired product.

Alkenes are formed by the E1 mechanism while substitution products are produced by the Sn1 process.

The rate law in an SN1 reaction is first order. In other words, the concentration of just one component—the alkyl halide—determines the reaction rate.

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Answer:

record

Explanation:

Learn more about distillation and condensation process.

What is distillation?

Distillation is a process in which a liquid is transformed into a vapor and then condensed back into a liquid state. The simplest illustration of it is when distilled water drops are left on a chilly surface after being deposited as steam from a kettle.

What is condensation?

The process by which matter transitions from its initial gaseous form into its liquid state is known as condensation. For instance, condensation happens when airborne water vapor (in its gaseous form) makes the transition to liquid water upon coming into contact with a cooler surface.

Given density of isoamyl acetate = 0.88g/ml

volume of isoamyl acetate = 75 ml

MW of  isoamyl acetate = 130.2g/ml

Therefore, no.of moles =mass/ molar mass

and mass = density*volume

Therefore, no.of moles = density*volume/molar mass

= 0.88g/ml*75 ml/130.2g/ml

=0.55 moles

similarly for methyl benzoate

no. of  methyl benzoate = 1.09g/ml*115ml/136.2gml

=0.92 moles.

Boiling point of isoamyl acetate = 142°c (vaporize first)

Boiling point of methyl benzoate= 199.6°c (moves down)

mole fraction of isoamyl acetate = 0.51/0.57+0.92

=0.357

mole fraction of the methyl benzoate = 0.643

%of isoamyl acetate= 35.7%

%of methyl benzoate= 64.3%

mole ratio= 35.7:64.3

Initial boiling point 166°c

composition of vapor in equilibrium with liquid  75: 25 (using theoretical plate1)

                                                                                ↓     ↓

                                                                              IA      MB

Re vaporization at 145°c

composition of vapor, at 145°c

95:5 ( using theoretical plate 2)

↓     ↓

IA MB

Condensate⇒ low density mixture

% composition of Condensate= 95%

(IA) using two theoretical plates

Therefore, Condensate is 95%

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The mass of an oxygen atom is C.) approx. 16 units. Oxygen is the chemical element with symbol as O and has atomic number as 8.

Gram atomic mass of oxygen is 16 g.  Oxygen is a gas that our body needs to work properly and cells need oxygen to make energy. Our lungs absorbs oxygen from the air that we breathe. Oxygen enters our blood from the lungs and travels to our organs and body tissues.

Oxygen is a member of the chalcogen group in the periodic table. It is a highly reactive nonmetal and an oxidizing agent that readily forms oxides with most of the elements and also with other compounds.

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The pH of the resulting solution is 9.96 that can be calculated by using the using the pOH values.

Buffer Solution is a water solvent primarily based totally answer which includes a combination containing a vulnerable acid and the conjugate base of the vulnerable acid, or a vulnerable base and the conjugate acid of the vulnerable base. They face up to a alternate in pH upon dilution or upon the addition of small quantities of acid/alkali to them.

Millimoles of NH3 = 0.316 x 250 = 79

Millimoles of NH4Br = 0.339 x 250 = 84.75

Millimoles of KOH = 57.3

pOH  = pKb + log [salt - C / base + C]

       = 4.74 + log [84.75 - 57.3 / 79 + 57.3]

      = 4.04

pH + pOH=14

pH=14-4.04

pH = 9.96

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The correct options are A, C, and D.

The constitutional isomers of octane are: A. 3-ethyl-2-methylpentaneC. 2,2-dimethylpropaneD. 2,3,3-trimethylpentaneThe isomers of a molecule can have different physical and chemical properties from each other. Constitutional isomers, also known as structural isomers, are compounds that have the same molecular formula but differ in how their atoms are arranged.

They can have different physical properties, chemical properties, boiling points, and melting points. Octane has the molecular formula C8H18, which means it has eight carbon atoms and eighteen hydrogen atoms. The possible constitutional isomers of octane are numerous.

The four options given in the question as below: A. 3-ethyl-2-methylpentaneB. 2-methylpropaneC. 2,2-dimethylpropaneD. 2,3,3-trimethylpentaneOut of the given options, 3-ethyl-2-methylpentane, 2,2-dimethylpropane and 2,3,3-trimethylpentane are the constitutional isomers of octane. Therefore, the correct options are A, C, and D. Answer: A, C, and D

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The \([OH^-]\) of a \(0. 255 M\) solution of pyridine, \(C_5H_5N\) is \(4.30 * 10^{-10} M\).

The pH of a \(0. 400 M\) solution of aniline, \(C_6H_5NH_2\) is \(9.98.\)

1]  Pyridine \((C_5H_5N)\) is a weak base, and its Kb value is given as \(1.69 * 10^{-9}\). To find the \([OH^-]\) of a \(0.255 M\) solution of pyridine, we can use the following equation:

\(Kb = [OH^-][C_5H_5N]/[C_5H_5NH^+]\)

where \([C_5H_5NH^+]\)represents the concentration of the conjugate acid of pyridine, which is negligible compared to the concentration of pyridine.

Rearranging the equation and plugging in the values, we get:

\([OH^-] = Kb[C_5H_5N] / [C_5H_5NH^+]\\= (1.69 * 10^{-9})(0.255) / 1\\= 4.30 x 10^ {-10} M\)

Therefore, the \([OH^-]\) of the solution is \(4.30 * 10^{-10} M.\)

2] Aniline \((C_6H_5NH_2)\) is also a weak base, and its Kb value is given as \(4.27 * 10^{-10}.\) To find the pH of a  \(0.400 M\) solution of aniline, we can use the following equation:

\(Kb = [OH^-][C_6H_5NH_2]/[C_6H_5NH_3^+]\)

where\([C_6H_5NH_3^+]\)represents the concentration of the conjugate acid of aniline, which is formed when aniline accepts a proton from water.

We can assume that \(x\) moles of aniline react with water to form \(x\) moles of \(C_6H_5NH_3^+\) and \(x\) moles of \(OH^-\). Therefore, the initial concentration of aniline, \([C_6H_5NH_2]\), will decrease by \(x\), while the concentrations of \([C_6H_5NH_3^+]\) and \([OH^-]\) will increase by \(x\). At equilibrium, we can express the concentrations as given follows:

\([C_6H_5NH_2] = 0.400 - x\)

\([C_6H_5NH_3^+] = x\)

\([OH^-] = x\)

The value of \(x\) can be determined using the Kb expression:

\(Kb = [OH^-][C_6H_5NH_2]/[C_6H_5NH_3^+]\\\\x = \sqrt{(Kb[C_6H_5NH_2]/[C_6H_5NH_3^+])} \\= \sqrt{((4.27 * 10^{-10})(0.400) / 1)}\\= 1.04 * 10^{-5} M\)

Therefore, the \([OH^-]\) of the solution is\(1.04 * 10^{-5} M,\) and the pH can be calculated using the expression:

\(pH = 14 - pOH\\= 14 - log([OH^-])\\= 14 - log(1.04 * 10^{-5})\\= 9.98\)

Therefore, the pH of the solution is \(9.98\).

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Answer:

it is (Ferric Nitride)

There are several methods for producing nitric acid from nitrogen, but two common methods are:

1. Ostwald process:

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)

2 NO(g) + O2(g) → 2 NO2(g)

3 NO2(g) + H2O(l) → HNO3(aq) + HNO2(aq)

Overall equation:

4 NH3(g) + 3 O2(g) + H2O(l) → 2 HNO3(aq) + 2 NO(g)

2. Birkeland-Eyde process:

N2(g) + 3 H2(g) → 2 NH3(g)

2 NH3(g) + 3 O2(g) → 2 NO(g) + 3 H2O(g)

2 NO(g) + O2(g) → 2 NO2(g)

3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Overall equation:

N2(g) + 3 O2(g) + 3 H2(g) → 2 HNO3(aq)

Answer:

See explanation

Explanation:

For the equilibrium; A + B ⇄C + D

At time = 0 secs, the concentration of products is zero while the concentration of reactants decreases steadily.

As time goes on, the concentration of the reactants continues to decrease while the concentration of products increases.

At equilibrium the concentration of both reactants and products are now the same because the rate of forward reaction is equal to the rate of reverse reaction are now the same.

True. The formation of an ionic compound from the metal strontium and the nonmetal chlorine can be represented using electronic configurations, orbital rotation, and electron dot structures.

Strontium is a metal that has the electronic configuration of [Kr] 5s2, and chlorine is a nonmetal with the electronic configuration of [Ne] 3s2 3p5. When they form the ionic compound, strontium will lose two electrons from its outer shell to become a positively charged ion (Strontium ion), while chlorine will gain one electron from its outer shell to become a negatively charged ion (Chloride ion). This will result in the formation of the ionic compound, Strontium Chloride, with the electronic configuration of [Kr] 5s1 and [Ne] 3s2 3p6, respectively.

The electron dot structure of Strontium Chloride is written as [Strontium] + [Chlorine] -, indicating that the Strontium ion is surrounded by the Chloride ion. The orbital rotation of Strontium Chloride shows how the two atoms of Strontium and Chlorine are held together by ionic bonds.

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Answer:

density = 5 g/ml

Explanation:

D=m/v. Mass=30g and Volume=6mL

SO solve for D when m = 30 and v = 6

D=m/v

D = 30/6

density = 5 g/ml

Answer:

Gas

Explanation:

If you move a substance from one container to another and its volume changes, the substance is a gas. This is because, gases do not have fixed volume and shape; their shape and volume depend on the container used.

Answer:

I think gas.

Explanation:

Because gas doesn't have fixed shape and size.

The mass of salt in the tank after t minutes can be determined using the formula: Mass of salt = concentration of salt × volume of solution.

To find the mass of salt in the tank after t minutes, we need to multiply the concentration of salt by the volume of the solution. The concentration of salt is given as 0.03 kg/L, and the volume of the solution is given as kg. Therefore, the mass of salt can be calculated by multiplying 0.03 kg/L by kg.

The concentration of salt in the tank will reach 0.03 kg/L after minutes. This means that at this time, the amount of salt in the tank will be such that if it is divided by the volume of the solution, it will equal 0.03 kg/L. To calculate the time it takes for the concentration of salt to reach 0.03 kg/L, we need to divide the mass of salt by the volume of the solution and then multiply it by 1/L. This will give us the time in minutes.

In the second part of the question, a cold drink initially at 35°F warms up to 38°F in 3 minutes while sitting in a room of temperature 72°F. To find how warm the drink will be if left out for 30 minutes, we need to consider the rate at which the drink warms up and the time it is left out.

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Answer:

pee

Explanation:

ppppppppppppppppppppppppppppppppppppp

Answer: the answer is A

Explanation: its alot to put down

The new absolute temperature, when the average speed of the molecules in a certain sample of ideal gas is doubled from v to 2v, can be calculated using the formula T2 = (4/3)T1, where T1 is the original absolute temperature and T2 is the new absolute temperature.

The absolute temperature of a gas is directly proportional to the average kinetic energy of its molecules. This means that as the average speed of the molecules in the gas increases, so does its absolute temperature.

In this case, when the average speed of the molecules is doubled from v to 2v, the absolute temperature of the gas also doubles.
To calculate the new absolute temperature, we can use the formula T2 = (4/3)T1, where T1 is the original absolute temperature and T2 is the new absolute temperature. This formula assumes that the gas behaves as an ideal gas, which means that its molecules have negligible volume and do not interact with each other.
When the average speed of the molecules in a certain sample of gas is doubled from v to 2v, the new absolute temperature can be calculated using the formula T2 = (4/3)T1. This formula is based on the assumption that the gas behaves as an ideal gas.

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The molecular formula for the compound is \(C_{4} H_{8}\) .

% of C = 79.85%

% of H = 20.15%

Let the mass of the compound be 100g, then

Mass of C = 70.85 g

Mass of H = 20.15 g

Molar mass = 60.15 g/mol

Moles of Carbon = \(\frac{79.85}{12.01 g/mol}\)

                             = \(6.64 mol\)

Moles of Hydrogen = \(\frac{20.15}{1.00794 g/mol}\)

                                 = \(19.99 mol\)

And we divide both sides by the lower quantity;

\(C_{\frac{6.64 mol}{6.64 mol} } H_{\frac{19.99 mol}{6.64 mol} }\) ≅ CH₂

And \((empirical formula)_{n} = molecular formula\)

60.15 g/mol = n × ( 12.01 + 2 × 1.00794)

n = 4

Therefore, the molecular formula for the compound is \(C_{4} H_{8}\) .

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The correct options for naming an ionic compound are:

The cation is named first and the anion second.

For a monatomic cation, the element name is unchanged.

For a monatomic anion, the element name is changed to end in -ide.

When naming an ionic compound, the cation (positive ion) is always named first, followed by the anion (negative ion). For monatomic cations, the element name remains the same. For example, Na^+ is simply called sodium.

On the other hand, for monatomic anions, the element name is modified to end in -ide. For example, Cl^- is named chloride. Greek prefixes are not used to indicate the number of atoms of a particular element present in ionic compounds.

Therefore, the correct options are: the cation is named first and the anion second, and for monatomic anions, the element name is changed to end in -ide.

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Based on Coulomb s law, the following anion most likely to have the strongest interactions with nearby water molecules in an aqueous solution is (C) S²⁻

Coulomb's law states that the electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Anions with higher charges and smaller sizes will have stronger interactions with water molecules.

Option (B), "=", seems to be an error and cannot be considered. Among the remaining options, Cl⁻ (A) has a charge of -1, S²⁻ (C) and Te²⁻ (D) both have charges of -2. Therefore, S²⁻ and Te²⁻ will have stronger interactions with water molecules compared to Cl⁻ due to their higher charges. Between S²⁻ and Te²-, S²⁻ is smaller in size than Te²⁻, resulting in even stronger interactions with water molecules. So therefore, the most likely anion to have the strongest interactions with nearby water molecules in an aqueous solution is S²⁻ (C).

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The RAM of element V can be calculated using the atomic masses of its two isotopes and their respective natural abundances by using the formula

RAM = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2)

The RAM (relative atomic mass) of element V can be calculated by taking the weighted average of the masses of its two isotopes, which are present in the natural abundance ratio of two-thirds and one-third, respectively. Isotopes are atoms of the same element that have different numbers of neutrons, and thus different mass numbers.

To calculate the RAM of element V, we can use the following formula:
RAM = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2)

In this case, we know that the two isotopes of element V are present in the natural abundance ratio of two-thirds and one-third, respectively. Let's assume that the mass of isotope 1 is x and the mass of isotope 2 is y. Then, we can set up two equations based on this information:

(2/3)x + (1/3)y = atomic mass of element V
x + y = atomic mass of element V (since the total abundance of the two isotopes is 1)

Solving for x and y, we get:

x = atomic mass of element V - (1/3)(atomic mass of element V - atomic mass of isotope 2)
y = (2/3)(atomic mass of element V - atomic mass of isotope 2)

Substituting these values into the formula for RAM, we get:

RAM = (x)(2/3) + (y)(1/3)
RAM = [(2/3)(atomic mass of element V - (1/3)(atomic mass of element V - atomic mass of isotope 2))] + [(1/3)(2/3)(atomic mass of element V - atomic mass of isotope 2)]

Simplifying this expression, we get:

RAM = (2/3)(atomic mass of element V) + (1/3)(atomic mass of isotope 2)

Therefore, the RAM of element V can be calculated using the atomic masses of its two isotopes and their respective natural abundances.

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Answer: The statement, chemicals that you begin with found on the left side of the equation, describes reactant and where they are in a chemical equation.

Explanation:

An equation that includes symbolic formulas and represents chemical reaction between the substances initially present forming new substances is called a chemical equation.

For example, \(N_{2} + 3H_{2} \rightarrow 2NH_{3}\)

Here, substances \(N_{2}\) and \(H_{2}\) are the reactants. Reactants in a chemical equation are always present on the left side as these are the chemicals we begin with.

Also here, \(NH_{3}\) is the product. Product(s) in a chemical equation are always present on the right side as these are the chemicals we end with.

Thus, we can conclude that the statement, chemicals that you begin with found on the left side of the equation, describes reactant and where they are in a chemical equation.