What resonant frequency would you expect from blowing across the top of an empty soda bottle that is 20 cm deep, if you assumed it was a closed tube

Answers

Answer 1

If you were to blow across the top of an empty soda bottle that is 20 cm deep, you would expect a resonant frequency of approximately 171.5 Hz.

The resonant frequency of a closed tube can be determined using the formula \(f = (n * v) / (4 * L)\), where f is the resonant frequency, n is the harmonic number (usually the fundamental frequency is considered, n = 1), v is the speed of sound, and L is the length of the tube.

In this case, the soda bottle can be considered a closed tube, with the length L being the depth of the bottle, which is 20 cm (or 0.2 m). The speed of sound in air is approximately 343 m/s.

Plugging these values into the formula, we can calculate the resonant frequency:

\(f = (1 * 343 m/s) / (4 * 0.2 m)\)

f ≈ 171.5 Hz

Therefore, blowing across the top of the empty soda bottle, assuming it acts as a closed tube, would likely produce a resonant frequency of approximately 171.5 Hz(or approximately 425 Hz for the fundamental frequency). This is the frequency at which the air column inside the bottle will resonate and produce a clear, amplified sound.

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Related Questions

How can we find velocity?*

Answers

Answer: discplacement/change in time = average velocity.

Explanation:

There is a formula for velocity which is given above

Please help! A hydrogen atom is place in a 15. T external magnetic field. What is the wavelength of EM emission for a transition from spin up to spin down?

Answers

The wavelength of the EM emission for a transition from spin up to spin down in a hydrogen atom placed in a 15. T external magnetic field is approximately 1.424 x 10⁻⁷ meters.

The wavelength of electromagnetic (EM) emission for a transition from spin up to spin down in a hydrogen atom placed in a 15. T external magnetic field can be calculated using the formula:

λ = (h / (4π m e B))

Where: -

λ is the wavelength of the EM emission,

h is the Planck's constant (6.626 x 10⁻³⁴ J s),

π is a mathematical constant (approximately 3.14159),

m e is the mass of the electron (9.109 x 10⁻³¹ kg),

B is the magnetic field strength (15. T).

Let's substitute the given values into the formula and solve for the wavelength:

λ = (6.626 x 10⁻³⁴ J s) / (4π * 9.109 x 10⁻³¹ kg * 15. T)

Before performing the calculation, we need to convert the magnetic field strength from Tesla (T) to Weber per square meter (Wb/m²).

1 Tesla (T) is equal to 1 Weber per square meter (Wb/m²).

Therefore, the magnetic field strength remains the same. Now, let's perform the calculation:

λ = (6.626 x 10⁻³⁴ J s) / (4π * 9.109 x 10⁻³¹ kg * 15. T)

λ = (6.626 x 10⁻³⁴ J s) / (4 * 3.14159 * 9.109 x 10⁻³¹ kg * 15. T)

λ ≈ 1.424 x 10⁻⁷ m

Therefore, when a hydrogen atom is placed in a 15. T external magnetic field, the wavelength of the electromagnetic emission (EM emission) during a transition from spin up to spin down is about. 1.424 x 10⁷ meters.

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Please help me with physics! And provide a quick explanation. Offering 100 points and brainliest!

Please help me with physics! And provide a quick explanation. Offering 100 points and brainliest!

Answers

Answer:

I think it's b and I'm sorry if it's wrong

Given ↷

Two masses oscillating together with each of their time period as ,'T'

To find↷New time period ,'T'Answer↷

Option B

Time period is independent of mass so it will remain same irrespective of the mass on the spring so the new time period would be the exact same as the previous one.Solution↷

we know that,

The time period of a mass 'm' on a spring of spring constant 'k' can be strategize by the following equation :

\( \huge \rightarrow \: T \: = 2π \sqrt{ \frac{m}{k} } \)

m⇢mass of the body [kg]k⇢spring constant [Nm^-1]

According to the question,

The new mass would be 2mThe new spring constant would be 2k

so,

The new time period would be

\( \huge \rightarrow \: T ' \: = 2π \sqrt{ \frac{2m}{2k} } \)

\( \huge \rightarrow \: T ' \: = 2π \sqrt{ \frac{m}{k} } \)

\( \huge \rightarrow \: T ' \: = T\)

Hence ,option B is correct ✓

One pipe can fill a tank in 20 minutes, while another takes 30 minutes to fill the same tank. How long would it take the two pipes together to fill the tank?

Answers

Answer: 12 minutes

Explanation:


Which two measuring devices would most likely be used to measure the speed of
water in a stream?

Answers

Answer:

Below:

Explanation:

The most common method used by the USGS for measuring velocity is with a current meter. However, a variety of advanced equipment can also be used to sense stage and measure streamflow. In the simplest method, a current meter turns with the flow of the river or stream.

Hope it helps...

It's Ms-Muska

A clown 2 m tall looks at himself in a full-length mirror (floor-to-ceiling). Where in the mirror must he look to see his feet?
O 1 m from the floor
O 50 cm from the floor
O 25 cm from the floor
O at the bottom of the mirror
O 1.5 m from the floor

Answers

The clown should look 1 m from the floor to see his feet in the full-length mirror.

The height of the clown is 2 m, and the mirror is a full-length mirror, which means it covers the entire height of the clown from the floor to the ceiling. Therefore, the clown's reflection in the mirror will also be 2 m tall.  

To see his feet in the mirror, the clown needs to look at the same distance from the floor as the distance between his feet and the floor. Since the clown's height is 2 m and his feet are at the bottom, 1 m away from the floor, he needs to look at a distance of 1 m from the floor to see his feet in the mirror. Therefore, the correct answer is "O 1 m from the floor."

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A worker applies a horizontal force to the top edge of a crate to get it to tip forward. If the crate has a mass of 60 kg and is 1.6 m tall and 0.80 m in depth and width, what is the minimum force needed to make the crate start tipping?

Answers

The minimum force needed to make the crate start tipping is 294 N.

To find the minimum force required, we need to determine the point at which the torque created by the applied force overcomes the torque created by the crate's weight.

At the tipping point, the applied force acts at a distance equal to the height of the crate (1.6 m), and the weight of the crate acts at a distance of half the crate's depth (0.4 m).
The formula for torque is: torque = force × distance
At the tipping point, the torques balance each other, so:
applied_force × height = weight × (depth/2)
Let's calculate the crate's weight: weight = mass × gravitational_acceleration
weight = 60 kg × 9.8 m/s² = 588 N
Now, we can find the applied force:
applied_force × 1.6 m = 588 N × 0.4 m
applied_force = (588 N × 0.4 m) / 1.6 m
applied_force = 294 N


Summary: The minimum force required to make a 60 kg crate with dimensions 1.6 m x 0.8 m x 0.8 m start tipping is 294 N.

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What happens to the current in a circuit if a 10Ω resistor is removed and replaced by a 20Ω resistor? (voltage stays the same)

Current will increase

Current will not travel through the circuit

Current will stay the same

Current will decrease

Answers

If a 10Ω resistor is removed and replaced by a 20Ω resistor, at constant voltage, the current will decrease.

Ohms law

This law states that, the current flowing in a conductor is directly proportional to the voltage in the conductor.

V = IR

where;

V is the voltage of the conductotI is the currentR is the resistance

I = V/R

At constant voltage, when the value of the resistance increases, the value of the current in the ciircuit wil decrease.

Thus, if a 10Ω resistor is removed and replaced by a 20Ω resistor, at constant voltage, the current will decrease.

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You use a knife to cut a piece of bread. What kind of simple machine are you
using?
A. Wedge
B. Inclined plane
C. Screw
O D. Lever

Answers

Answer:

the answer is A.) Wedge

A knife to cut a piece of bread is a A. Wedge

What is a simple machine?

A simple machine, any of several devices with few or no moving parts that are used to modify motion and the magnitude of a force in order to perform work.

since , a wedge is a simple machine  with two inclined planes which when put together forms a sharped edge, which forms a triangular shaped tool which can be used to separate portion of  two objects .

hence , a knife to cut a piece of bread is a A. Wedge

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What is this? Any help?

What is this? Any help?

Answers

Answer:

the third one

Explanation:

she is using a card instead of paper

If 1 kg = 1000g, 3 kg is

Answers

Answer:

3000g

hope this helps<3

3000g man come on bro do better bro

The____is a wedge-shaped thickening in the middle layer of the eyeball that controls the shape of the lens.

Answers

The Ciliary body is a wedge-shaped thickening in the middle layer of the eyeball that controls the shape of the lens.

The middle layer of the eye's wall contains the ciliary body.

The ring-shaped muscle that modifies the shape of the lens when the eye focuses is part of the ciliary body, which is located behind the iris.

Additionally, it creates the transparent liquid that fills the space between the iris and the cornea.

The ciliary muscle, which regulates the lens's shape, and the ciliary epithelium, which creates aqueous humor, are both components of the eye's ciliary body (wedge shaped opening).

In the ciliary body's non-pigmented region, the aqueous humor is created. The ciliary body is a component of the uvea, the layer of tissue that nourishes and oxygenates the tissues of the eyes.

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HELP pleaseee which nucleus completes the following equation?

HELP pleaseee which nucleus completes the following equation?

Answers

Answer:

its D

Explanation:

i just got it correct on a. p. e. x. :)

AJUTOR VA ROG LA FIZICA IMI TREBUIE NOTA!!!!!!!!!!

AJUTOR VA ROG LA FIZICA IMI TREBUIE NOTA!!!!!!!!!!

Answers

Answer:

gkcfgggxg hhfdc ghgffgccvvc

bjvhgf

Explanation:

gjhghujj bhhgghj

The interaction energy of london force is inversely proportional to sixth power of the distance between two interacting particles but their magnitude depends upon.

Answers

The magnitude of London dispersion forces depends on the polarizability of the interacting particles, which determines their ability to induce temporary dipoles.

The interaction energy of these forces is inversely proportional to the sixth power of the distance between the particles.

London dispersion forces, also known as van-der Waals forces, are weak intermolecular forces that occur between all atoms and molecules. These forces arise from temporary fluctuations in electron distribution, creating instantaneous dipoles. The magnitude of London forces depends on the polarizability of the particles involved. Polarizability refers to the ease with which the electron cloud of an atom or molecule can be distorted.

Larger, more easily distorted electron clouds have higher polarizability and can induce greater temporary dipoles in neighboring particles.

The interaction energy of London dispersion forces follows an inverse sixth power relationship with distance. As the particles move closer together, the electron clouds become more distorted, resulting in stronger instantaneous dipoles. The energy of interaction decreases rapidly with distance due to the inverse sixth power relationship, which means that even slight changes in distance can have a significant impact on the strength of these forces.

Consequently, particles that are very close together experience much stronger London forces compared to those that are farther apart.

In summary, the magnitude of London dispersion forces depends on the polarizability of the interacting particles, while the interaction energy is inversely proportional to the sixth power of the distance between them.

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Three 45 ohm lightbulbs and three 75 ohm lightbulbs are connected in series. (a) what is the total resistance of the circuit? (b) what is their resistance if all six are wired in parallel?

Answers

a) The total resistance of the circuit in which three 45 ohm lightbulbs and three 75 ohm light bulbs connected in series is 360 ohm.

b) The total resistance of the circuit if all six are wired in parallel is 28.57 ohm.

a) In order to find the series total resistance, we need to add all resistances,

Req = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ = 45 + 45 + 45 + 75 + 75 + 75 = 135+ 225 = 360 ohm

b) Now, since the resistances are in parallel, we need to use the expression below,

1/Req = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + 1/R₅ + 1/R₆

Putting in the values,

1/Req = 1/45 + 1/45 + 1/45 + 1/75 + 1/75 + 1/75

1/Req = 1/0.035

Req = 28.57 ohm

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The Doppler method allows us to find a planet's semimajor axis using just the orbital period and the star's mass (Mathematical Insight Finding Orbital Distances for Extrasolar Planets). Part A Imagine that a new planet is discovered orbiting a 2 MSun star with a period of 4 days . What is its semimajor axis

Answers

The semimajor axis of the new planet orbiting a 2 MSun star with a 4-day period is approximately 0.05 AU.

The Doppler method allows astronomers to find the semimajor axis of an extrasolar planet's orbit by measuring its orbital period and the mass of the star it orbits.

For a new planet discovered orbiting a 2 MSun star with a period of 4 days, we can use the formula a = [\(P^2\)G(M+M*)\(/4\pi ^2\)]\(^(^1^/^3^)\), where P is the orbital period, G is the gravitational constant, M is the mass of the planet, and M* is the mass of the star.

Assuming the planet has a negligible mass compared to the star, we can simplify the formula to a = [(2MSun)(4 days)\(^2\)G/4\(\pi ^2\)]^(1/3), which yields a semimajor axis of approximately 0.05 AU.

This means the planet orbits its star at a distance of about 7.5 million km.

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chapter 5 - problem 30. a negative charge is placed at the center of a ring of uniform positive charge. what is the motion (if any) of the charge? what if the charge were placed at a point on the axis of the ring other than the center?

Answers

Answer:

There is no motion of the charge except along the axis of the ring.

(All charges on the ring are equivalent, with no net force perpendicular to the axis of the ring)

The electric potential of the axis of the ring decreases as the charge is moved away from the center of the ring,

The force on the negative charge will always be directed towards the center of the ring. (It would take work to move the charge "away" from the ring)

for the given state of stress, determine the normal and shearing stresses after the element has been rotated (a) 25o clockwise, (b) 10o counterclockwise.

Answers

The normal and shearing stresses after the element has been rotated 10° is 53.8 Mpa.

Stress is defined as the resisting force per unit area. It is expressed in N/m2.In engineering problems, the transformation of stress mainly deals with plane stress, in which two of the faces of the cubic element are free from stress. Suppose if z axis is chosen perpendicular to these two faces, we can ignore

Such a situation is called plane stress condition.The planes which have maximum and minimum normal stresses observed are known as principal planes. In these planes, the shear will be zero.

Principal stresses: The normal stresses in the principal planes are called principal stresses. Assume that a state of plane stress exists at a point G with stresses as,The standard element for plane stress at a point G is shown below:

Determine the shearing stress after the element rotated through

counter-clock wise.

Calculation:-

Tx'y' = - σx - σy/2 sin2θ + Txycos2θ

        = - (-60 - 90) + 30 cos (2× 10°)

       = 53.8 Mpa

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An experiment was set up to investigate the cooling of water in two flasks. One flasks was painted shiny white. The other was painted Matt black. The starting temperature of the hot water poured into both flasks was 80 degrees. Explain what other quantity had to be kept the same in both flasks to make the experiment fair.

Answers

Answer:

add add more hot water in the flask painted shiny white while less of it in the one painted Matt black

Explanation:

Let's name the flasks A and B respectively

flask A due to the nature of its exterior will tend to reflect heat from the environment thus will need more hot water while flask B since it painted in Matt black the heat will be absorbed from the environment thus will require less hot water

Playing shortstop, you pick up a ground ball and throw it to second base. The ball is thrown horizontally with a speed of 13 m/s directly toward point A. When the ball reaches the second baseman 0,44 s later, it is caught at point B. How far were you from the second baseman? What is the distance of the vertical drop, the distance between point A and point B.

Answers

You were approximately 5.72 meters away from the second baseman. The vertical drop or distance between point A and point B was approximately 0.4576 meters.

To determine the distance between you (the shortstop) and the second baseman, we can use the formula for horizontal distance (d) traveled by an object moving at a constant horizontal velocity:

d = v * t

where:

- d is the horizontal distance traveled,

- v is the horizontal velocity of the ball,

- t is the time taken.

Given that the horizontal velocity (v) is 13 m/s and the time (t) is 0.44 s, we can calculate the horizontal distance (d) as follows:

d = 13 m/s * 0.44 s = 5.72 meters

So, you were approximately 5.72 meters away from the second baseman.

To find the vertical drop or the distance between point A and point B, we need to calculate the vertical component of the ball's motion. Since the ball is thrown horizontally, it will experience a constant vertical acceleration due to gravity.

The formula to calculate the distance (d) traveled vertically in free fall is:

d = 1/2 * g * t²

where:

- d is the vertical distance traveled,

- g is the acceleration due to gravity (approximately 9.8 m/s²),

- t is the time taken.

Given that the time (t) is 0.44 s, we can calculate the vertical distance (d) as follows:

d = 1/2 * 9.8 m/s² * (0.44 s)² = 0.4576 meters

So, the vertical drop or the distance between point A and point B is approximately 0.4576 meters.

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Describe a simple pendulum and, What kind of motion does it execute?

Answers

AnswerA simple pendulum is defined as an object that has a small mass, also known as the pendulum bob, which is suspended from a wire or string of negligible mass. When displaced, a pendulum will oscillate around its equilibrium point due to momentum in balance with the restoring force of gravity.A simple pendulum is defined as an object that has a small mass, also known as the pendulum bob, which is suspended from a wire or string of negligible mass. When displaced, a pendulum will oscillate around its equilibrium point due to momentum in balance with the restoring force of gravity.The repetitive to and fro motion of a pendulum is an example of periodic motion.

I am unique even though there are billions of me no two are the same what am I


AND IT'S NOT A FINGER-PRINT

Answers

I think the answer is Snow flakes

Since every ice crystal takes a different route to the ground. They will float through various clouds with various temperatures and moisture contents, which will cause the ice crystal to develop in a distinctive manner.

What make snowflakes unique?

A snowflake's shape changes as it flies through the atmosphere, thus no two are ever the same. Even two flakes floating side by side will each be blown through various vapour and humidity levels to produce a genuinely unique shape.

One of the most recognizable representations of winter weather are snowflakes. There are an unlimited amount of conceivable shapes for snowflakes, and each one is distinct.

Therefore, snowflakes unique even though there are billions.Even two floating flakes will each be exposed to different vapour and humidity conditions, creating a really distinctive form.

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Two 0.55-kg basketballs, each with a radius of 14 cm , are just touching. How much energy is required to change the separation between the centers of the basketballs to 1.1 m? (Ignore any other gravitational interactions.)

Answers

Answer:

The amount of energy required is 4.08 J.

Explanation:

Given,m1 = m2 = 0.55-kgR = 14 cm = 0.14 m The distance between the two basketballs d = 1.1 m

Energy required to change the separation between the centers of the basketballs to 1.1 m is given by the formula; E = K1 + K2 - U where K1 = kinetic energy of ball 1K2 = kinetic energy of ball 2U = potential energy

Let's calculate K1,K2, and U: K1 = 0.5 mv²where m = mass of ball v = velocity of ball Initial velocity of ball = 0 m/s Final velocity of ball v = 0.5 m/sK1 = 0.5 × 0.55 × (0.5)²= 0.069 JK2 = 0.5 mv² Initial velocity of ball = 0 m/s .

Final velocity of ball v = - 0.5 m/sK2 = 0.5 × 0.55 × (- 0.5)²= 0.069 J Let's find out the potential energy; U = (kQ1Q2) / d

where Q1 = Q2 = Q d = distance between the centers of two balls U = (kQ²) / d where k = Coulomb's constant = 8.99 × 10⁹ Nm²/C²Q = charge on a ball = 0 (because it is an uncharged object) U = 0.

Therefore, E = K1 + K2 - U= 0.069 + 0.069 - 0= 0.138 J Therefore, the amount of energy required is 4.08 J.

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The acceleration of a particular sports car is proportional to the difference between 300 km/h and the velocity of this sports car. If this machine can accelerate from rest to 135 km/h in 10 s, how long will it take for the car to accelerate from rest to 270 km/h ? It would take second(s). (Round to one decimal place as needed.)

Answers

It would take 4.1 seconds for the car to accelerate from rest to 270 km/h.

So, the acceleration can be written as a = k(300 - v)

where k is the constant of proportionality and v is the velocity of the car in km/h.

It is known that, when the car is at rest, i.e., v = 0, it can accelerate from rest to 135 km/h in 10 s.

So, we can write;135 = k(300 - 0) => k = 135/300 => k = 0.45

Now, we are to find the time taken by the car to accelerate from rest to 270 km/h.

Let t be the time taken.

So, the velocity of the car after time t is given by;

v = 300 - 270e^(-0.45t)

Putting v = 0 in the above equation,

we get;

0 = 300 - 270e^(-0.45t)

  => e^(-0.45t) = 10/9

  => -0.45t = ln(10/9)

  => t = 4.1 sec

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2. What is responsible for mudslides, rockfalls, and landslides

Answers

Answer:

Flash flooding or ongoing heavy rain can be precursors to landslides, mud/debris flows, and even rockfalls. ... Rockfalls are often caused by erosion of earth around larger rocks that then become loose and fall. Earthquakes can also lead to landslides and rockfalls.

Explanation:

It is a geological process called erosion.

an object is located inside the focal point of a concave mirror. will the image of the objectr be nearer or farther from the observer than the object tiself? explain

Answers

When an object is placed inside the focal point of a concave mirror, the image formed will be virtual, upright, and magnified.

This occurs because the light rays reflecting off the mirror diverge and never intersect on the real side of the mirror. Instead, they appear to converge on the virtual side, behind the mirror.

As a result, the image of the object will be farther from the observer than the object itself. The observer will see the image behind the mirror, which is not the actual position of the object, making it appear more distant than it truly is.

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Nikola Tesla and Thomas Edison were both pioneers when it came providing electricity to the people. Edison had hired the genius Tesla to work for him, but their differences, pride and personalities caused them to compete and publicly insult one another instead of working together. List 5 strategies these two could have used to help them work with others they disagree with.

Answers

Explanation:

In other to avoid a situation where their differences, pride, and personalities caused them to compete and publicly insult one another instead of working together they need to respectfully consider the viewpoints of each other, as well as assign individual roles that should be respected.

As distance ________________ between two objects, gravitational force will _________________. *
1 point
a. increases, increase
b. increases, decrease
c. decreases. increase

Answers

Answer:

b. increases, decrease

Explanation:

Consider a black body of surface area 20.0 cm² and temperature 5000 K .(j) Approximately how much power does the object radiate as visible light?

Answers

Visible light generally falls within the range of approximately 400-700 nanometers (nm). By applying Wien's displacement law, we can estimate the peak wavelength corresponding to the given temperature of 5000 K.

To calculate the approximate power radiated by the black body as visible light, we can use the Stefan-Boltzmann law and Wien's displacement law. The power emitted by a black body is given by the Stefan-Boltzmann law, while the fraction of power emitted as visible light can be estimated using Wien's displacement law.

The power radiated by a black body is given by the Stefan-Boltzmann law:

Power = σ * A * T^4,

where σ is the Stefan-Boltzmann constant (approximately 5.67 × 10^−8 W/(m^2·K^4)), A is the surface area of the black body (converted to square meters), and T is the temperature in Kelvin.

To estimate the fraction of power emitted as visible light, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a black body is inversely proportional to its temperature.

Visible light generally falls within the range of approximately 400-700 nanometers (nm). By applying Wien's displacement law, we can estimate the peak wavelength corresponding to the given temperature of 5000 K.

Combining these two laws, we can calculate the approximate power radiated by the black body as visible light.

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