PLS PLS PLS HELP ME!??(

Answer:

3/8

Step-by-step explanation:

1/4+1/8

2/8+1/8

=

3/8

3/8

1+2 to equal 3, which is all the numerators above the least common denimonater 8

In this problem

Looking at the graph

The domain is all real numbers greater than or equal to -3 and less than -1

therefore

The domain is the interval

if two angles are vertical what is the m = 28.

What a vertical angle?

if two angles are vertical

Then

m 2x+7= m

4x-14=m

So,

         2x+7 = 4x - 14

          4x - 2x = 14 + 7

           2x = 21

            x = 21/2

put value of x

2x+7= m ⇒  2 × 21/2 + 7

               = 21 + 7 = 28

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Answer:

Rational, Natural Number, Whole Number,Integer

Step-by-step explanation:

A natural number is also a whole number.

Every integer is a rational number.

Every natural number is a whole number, integer, and a rational number.

Every whole number is a natural number, integer, and a rational number.

We can write a computer program to generate all possible combinations of five elements of the set S and compute M for each combination, where M is a maximum and S is the set of work booths

As Janet drives through several toll booths on her way home from work, we need to find out if there are a couple of these toll booths that are less than 10 miles away. Let the toll booths be represented by real numbers. Let the set of toll booths be S = {a, b, c, d, e, f} where a < b < c < d < e < f.

For example, a is the distance from the starting point to the first travel cabin, b is the distance between the first and second travel cabin, and so on. We can represent the distance between any two toll booths as the difference of two numbers in the set S. Let's find the difference between the positions of the toll booths by subtracting them.

The possible differences between two toll booths are given by the set D = {b - a, c - b, d - c, e - d, f - e}. We have to check if any difference is less than 10 miles or not. To check whether any difference is less than 10 miles or not, let's take the largest difference and subtract the smallest difference.

This gives us the maximum difference between two transport cabins, which we can then compare to 10. Let M be the maximum difference and m be the minimum difference.

M = max{b - a, c - b, d - c, e - d, f - e}

m = min{b - a, c - b, d - c, e - d, f - e}

So M - m will be less than 10 miles if and only if M < 10 + m. Now, since S has six elements, there are five differences, and we need to find the minimum value of M for all possible five-element options in S.

To do this, we can write a computer program to generate all possible combinations of five elements of the set S and calculate M for each combination. The minimum value of M is the answer. Therefore, we can confirm if there are a couple of these travel cabins that are less than 10 miles apart or not.

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Answer:

3.33333 or 3

Step-by-step explanation:

i just did 1/3*10 because w to z is 10.

While you look behind to see how many people you beat, you are gathering information for your Competitive intelligence via the use of social comparison.

Competitive intelligence is a process of learning as much as possible outside oneself to increase one's competition level.

It tells us about our position in the competition or market .it helps in self-improvement and skill development.

Social comparison helps in determining our own worth in society.

You are gathering information for your Competitive intelligence via the use of social comparison.

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Answer:

17.6 years (roughly)

Step-by-step explanation:

ok so let's consider the amount of cobalt-60 to be: \(m\) kg of cobalt.

We can model the decay of that cobalt given its half-life of \(5.3\) as:

\(f(t) = m(\frac{1}{2})^{\frac{t}{5.3}}\)

where \(t\) is the time in years.

Now, for 90% of the cobalt to decay, we get the following equation:

\(\frac{m}{10}=m\times (\frac{1}{2})^\frac{t}{5.3}\\ \\ \frac{1}{10}=(\frac{1}{2})^\frac{t}{5.3}\)

and by using logarithms, we can find t.

\(log(\frac{1}{10})=log(\frac{1}{2}^\frac{t}{5.3})\\ \\ log(1)-log(10)=\frac{t}{5.3} log(\frac{1}{2})\\\\(log(1)=0)\\\\ -log(10)=\frac{t}{5.3} [log(1)-log(2)]\\\\(log[10]=1) \\\\\)

\(-1=(\frac{t}{5.3} )\times -log(2)\\\\\\\frac{t}{5.3}=\frac{1}{log(2)}\\ \\t=\frac{5.3}{log(2)}=17.6 years\) (roughly)

The following values are as follows: a) Mean = 0.6, b) standard deviation = 0.073 and c) Probability is 0.0855

a) As the number of samples is large enough which is up to 30 then the mean of the average number of moths in 30 traps is given as 0.6, given from the central limit theorem.

b) The population deviation divided by the square root of the sample size gives the standard deviation value.

standard derivation = σ/ \(\sqrt{n}\) = 0.4 / \(\sqrt{30}\) = 0.4/ 5.477 = 0.073

c) The probability that an approximately normally distributed data with the standard deviation, σ, with a sample size of n is greater than a number, x, and a mean, μ, is given by

1 - P (X < x)= P (X > x)

= 1 - P(z< x- µ/ σ/\(\sqrt{n}\))

Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that the average number of moths in 30 traps is greater than 0.7 is given by:

1 -P (X - 0.7) = P (X > 0.7)

= 1 - P(z < \(\frac{0.7-0.6}{0.073}\)) = 1 - P(z < 1.369)

= 1 - 0.91455 = 0.0855

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Given, Principal amount (P) = $2000, Annual interest rate (r) = 12% and Compounded quarterly (n)We need to calculate how much is in the account at the end of each compounding period

Using the formula to calculate compound interest:A = P(1 + r/n)^(nt)Where, A is the amount, P is the principal, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time in years.Let's calculate the amount at the end of each quarter.1st quarter: t = 0.25A = $2000(1 + 0.12/4)^(4 × 0.25)A = $2000(1 + 0.03)^1A = $2000(1.03)A = $2060Amount at the end of the first quarter is $2060.2nd quarter: t = 0.5A = $2000(1 + 0.12/4)^(4 × 0.5)A = $2000(1 + 0.03)^2A = $2000(1.0609)A = $2121.80Amount at the end of the second quarter is $2121.80.3rd quarter: t = 0.75A = $2000(1 + 0.12/4)^(4 × 0.75)A = $2000(1 + 0.03)^3A = $2000(1.0927)A = $2185.40 Amount at the end of the third quarter is $2185.40.4th quarter: t = 1A = $2000(1 + 0.12/4)^(4 × 1)A = $2000(1 + 0.03)^4A = $2000(1.1255)A = $2251Amount at the end of the fourth quarter is $2251.

The total interest can be calculated as follows:Total interest = A - PTotal interest = $2251 - $2000Total interest = $251The annual percentage yield (APY) can be calculated as follows:APY = (1 + r/n)^n - 1APY = (1 + 0.12/4)^4 - 1APY = 0.126825APY = 12.68% (rounded to two decimals)Hence, the amount at the end of each compounding period is:First quarter: $2060Second quarter: $2121.80Third quarter: $2185.40Fourth quarter: $2251The total interest is $251.The annual percentage yield (APY) is 12.68% (rounded to two decimals).

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The correct answer is total interest earned amount  in the account at the end of each compounding period is  $250 and the APT is 12.55%.

Given data:

Principal amount of co= $2000APR

= 12% per year

Compounding frequency = Quarterly

Compounding period = 1 year

Calculation of interest and amount in the account at the end of each compounding period is shown below:

Interest for 1st quarter:

Rate of interest for 1 quarter = 12%/4 = 3%

Interest = (3/100) × $2000 = $60

Amount in the account = $2000 + $60 = $2060

Interest for 2nd quarter:

Rate of interest for 2 quarter = 12%/4 = 3%

Interest = (3/100) × $2060 = $61.8 ≈ $61

Amount in the account = $2060 + $61 = $2121

Interest for 3rd quarter:Rate of interest for 3 quarter = 12%/4 = 3%

Interest = (3/100) × $2121 = $63.63 ≈ $63

Amount in the account = $2121 + $63 = $2184

Interest for 4th quarter:

Rate of interest for 4 quarter = 12%/4 = 3%Interest = (3/100) × $2184 = $65.52 ≈ $66

Amount in the account = $2184 + $66 = $2250

Total interest for the year = $60 + $61 + $63 + $66 = $250APR

when interest is compounded annually = 12%

Compounding frequency = Quarterly

So, APT = (1 + 12%/4)^4 - 1 = 12.55% (rounded to 2 decimal places)\

Therefore, the amount in the account at the end of each compounding period is as follows:

First quarter: $2060

Second quarter: $2121

Third quarter: $2184

Fourth quarter: $2250

Total interest earned for the year is $250 and APT is 12.55%.

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Answer:

260 / 5 = 52

Step-by-step explanation:

give brainliest please

The particular solution is: y = e^(1/75 x^3 + ln(7)) or equivalently: y = 7e^(1/75 x^3) This is the solution to the separable differential equation dy/dx = x^2/25 that satisfies the initial condition x(0) = 7.

the separable differential equation and find the particular solution.

First, let's rewrite the given equation as a separable equation:
dy/dx = x^2/25

To separate the variables, divide both sides by x^2 and multiply by dx:
(1/x^2) dx = (1/25) dy

Now, integrate both sides with respect to their respective variables:
∫(1/x^2) dx = ∫(1/25) dy

The integrals are:
-1/x = y/25 + C

To find the particular solution satisfying the initial condition x(0) = 7, we need to correct the initial condition, as x(0) should be in the form of y(0) for it to be relevant to our equation. Assuming the correct initial condition is y(7) = 0, let's plug in the values for x and y:

-1/7 = 0/25 + C

Solve for C:
C = -1/7

Now, plug C back into the equation to get the particular solution:
-1/x = y/25 - 1/7

This is the particular solution to the given separable differential equation with the initial condition y(7) = 0.

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The first part of the trip took approximately 6.39 hours and the second part of the trip took approximately 5.84 hours.

In this problem, we are given the distance, total time, and average speeds for two parts of a plane trip.

Using the formula for average speed

Distance = average speed x time,

We can set up two equations and solve for the times spent flying at each speed.

We define t₁ as the time spent flying at 115 mph and t₂ as the time spent flying at 125 mph.

From the equation

730 miles = 115 mph x t₁,

we solve for t₁ and get

t₁ = 6.391304347826087 hours.

Similarly, from the equation

730 miles = 125 mph x t₂,

we solve for t₂ and get

t₂ = 5.84 hours.

Therefore, the plane flew at an average speed of 115 mph for approximately 6.39 hours and at an average speed of 125 mph for approximately 5.84 hours.

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Therefore, the line tangent to the curve at the point (1, π) is represented by the equation y = -2πx + 3π.

To find the slope of the curve and the tline tangen to the curve at the point (1, π), we can differentiate the given equation implicitly with respect to x.

The given equation is \(5x^2y\) - πcos(y) = 6π.

Differentiating both sides with respect to x:

\(10xy + 5x^2(dy/dx) + πsin(y)(dy/dx) = 0.\)

Now, substitute the values x = 1 and y = π into the equation:

\(10(1)(π) + 5(1)^2(dy/dx) + πsin(π)(dy/dx) = 0.\)

Simplifying, we have:

10π + 5(dy/dx) + 0 = 0.

5(dy/dx) = -10π.

dy/dx = -2π.

Therefore, the slope of the curve at the point (1, π) is -2π.

To find the equation of the tangent line, we use the point-slope form:

y - y1 = m(x - x1),

where (x1, y1) is the point (1, π) and m is the slope -2π.

Substituting the values, we have:

y - π = -2π(x - 1).

Expanding and simplifying, we get:

y = -2πx + 2π + π.

y = -2πx + 3π.

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Answer:

(14, - 3 )

Step-by-step explanation:

Under the translation < 6, 0 >

Add 6 to the x- coordinate and 0 to the y- coordinate, that is

B(8, - 3 ) → B'(8 + 6, - 3 + 0 ) → B'(14, - 3 )

Reliability and internal validity are both important concepts in qualitative research, but they refer to different aspects of the research design and findings. Here are the key differences between reliability and internal validity in qualitative research:

Reliability:

1. Reliability refers to the consistency and stability of the research findings. It focuses on the extent to which the study can produce consistent results when the research is conducted again under similar conditions.

2. In qualitative research, reliability is often assessed through methods like inter-coder reliability, where multiple researchers independently analyze the same data and compare their findings to determine the level of agreement.

3. The aim of establishing reliability is to ensure that the findings are not influenced by random errors or variations in data interpretation, and that the results can be replicated or confirmed by other researchers.

4. Reliability is particularly important in ensuring the trustworthiness and credibility of qualitative research, as it enhances the confidence in the accuracy and consistency of the findings.

Internal Validity:

1. Internal validity refers to the extent to which a study provides accurate and valid conclusions about the causal relationship between variables within the specific research context.

2. In qualitative research, internal validity is concerned with factors that may influence the accuracy and validity of the findings, such as researcher bias, participant bias, or threats to the credibility of the data.

3. Researchers strive to establish internal validity by employing rigorous methods such as triangulation, member checking, and reflexivity, to ensure that the interpretations and conclusions are grounded in the data and not distorted by external factors.

4. Internal validity is crucial in qualitative research to establish the trustworthiness and rigor of the study. It ensures that the conclusions drawn from the data are valid within the specific research context and can be confidently attributed to the phenomena being studied.

In summary, reliability focuses on the consistency and stability of the research findings, while internal validity concerns the accuracy and validity of the conclusions drawn from the data. Both concepts are essential for ensuring the quality and trustworthiness of qualitative research, but they address different dimensions of research quality.

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Given:

Required:

To find the value of nr.

Explanation:

The Snell's law is

Whenever a set X is a subset of set Y, we say the Y is a superset of X and we write, Y ⊇ AX.

Symbol ⊇ is used to denote ‘is a super set of’

The cost, excluding interest, is $648. The cost per computer is $64.80

The manufacturer charges 11% interest. Finance charge: $180 Days: 40 days Banker's year: 360 days Cost per computer formula: Interest = Principal × Rate × Time/ 360% × 100

Let the cost of the computers be x dollars and the cost per computer be y dollars. Cost of the computers = x Cost per computer = y Total finance charge with interest = $180 Total days in banker's year = 360 Rate = 11% Principal = x Time in days = 40 days + 360 days= 400 days Interest = (x * 11 * 400)/(360 * 100)= (11x/360) * 400 Interest + x = 180 + x10x/36 = 180x = $648. The cost of the computers excluding interest is $648.The cost per computer is $64.80. (cost per computer = $648/10)Therefore, The cost, excluding interest, is $648. The cost per computer is $64.80.

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Answer:

150 Miles

Step-by-step explanation:

Let's say it takes x time to get there.

X x 30=(8 - 6) x 50 (The distance is the same)

30X=400 - 50X=7 X=5 hours.

So the distance is 5 x 30=150 miles.

Answer:

f(x) and g(x) are the quadratic functions that open UP.

Answer:

what do u need help with?

Answer:

p^10

Step-by-step explanation:

when they're set up like that you multiple thw exponents to get what the new one would be ao 5 * 2 = 10.

Answer:

\({( {p}^{2} ) }^{5} = {p}^{2 \times 5} \\ = {p}^{10} \)

Answer:

Option B is the best way to write the underlined parts of sentences 2 and 3.

Sentence 2: They have a special finish that helps.

Sentence 3: The finish helps the swimmer glide through the water.

Option B provides a clear and concise way to connect the two sentences and convey the idea that the special finish of the swimsuits helps the swimmer glide through the water. It avoids any ambiguity or redundancy in the language.

En total, Juan gastó $205.25. 1 kilo de queso cuesta $90. 1/2 kilo de jamón cuesta $60. Si comprara un kilo de tortilla, un kilo de pepino y un kilo de jamón, Juan gastaría $129. Si Juan tiene $430, puede comprar 3 kilos de jamón, 1 kilo de queso, 5 kilos de pepino y 1 2/3 de tortillas.

Dado que Juan compró 1/4 de pepino que cuesta $3, 1 1/2 de jamón que cuesta $120, 1/3 de tortillas que cuesta $6 y 4/8 de queso que cuesta $45, para determinar cuánto dinero gastó en total, cuánto cuesta un kilo de queso, cuánto cuesta medio kilo de jamón, cuánto gastaría si comprara un kilo de tortilla, un kilo de pepino, y un kilo de jamón y, si Juan tiene $430, qué puede comprar sin que le sobre ni un peso, se deben realizar los siguientes cálculos:

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The definite integral of 0.2 * x^5 from 0 to 1, approximated to six decimal places using a power series, is 0.033333.

The definite integral of 0.2 * x^5 from 0 to 1 using a power series with an accuracy of six decimal places. To do this, we can use the power series representation of the integrand and then integrate term by term.

1. Find the power series representation of the integrand:
The integrand is a polynomial, 0.2 * x^5, so its power series representation is simply itself.

2. Integrate term by term:
Now, we integrate the power series term by term. In this case, we have only one term, which is 0.2 * x^5.
∫(0.2 * x^5) dx = (0.2/6) * x^6 + C = (1/30) * x^6 + C

3. Evaluate the definite integral:
Now, we can find the definite integral by evaluating the antiderivative at the given limits (0 and 1):
i = [(1/30) * (1^6)] - [(1/30) * (0^6)] = (1/30)

4. Convert to a decimal:
i ≈ 0.033333

Thus, the definite integral of 0.2 * x^5 from 0 to 1, approximated to six decimal places using a power series, is 0.033333.

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The probability of the data vale more extreme than 3.65 is 0.000131.

First of all given that x(value) = μ+3.65σ , where μ is the mean and σ is the standard deviation.

we know that z-score = (x - μ)/σ

z-score = (μ+3.65σ - μ)/σ

z = 3.65σ/σ

z = 3.65

From the normal distribution table,

P(z>3.65) = 0.000131

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