Answer:B. Temperature
Explanation:The temperature of the star such as Sun is measured. Using this measurement, its peak wavelength and energy can be determined.For determination of wavelength, Wien's displacement law is used. This law states that, the sun like body emits all kinds of wavelengths and thus is nearly a black body.For black body, the peak wavelength emitted is inversely proportional to the temperature of the body. From the wavelength, energy can be calculated.Temperature is the property which is primarily responsible for determining the type of electromagnetic energy and peak wavelength emitted by star.
WILL GIVE BRAINLY AND 100 POINTS A toy rocket of mass 12kg is launched upwards with an initial velocity of 3m/s. Use conservation of energy to determine how high it flies.
36 feet I'm hoping because that's what I got
Answer:
Its should be 46 feet.
Explanation:
Im so sorry if im wrong. Im learning this too rn. ahahh
Imagine that you have three circuit elements: a single bulb, a piece of wire, and a battery. You start by keeping these three elements separate and unconnected. You use a voltmeter to measure the voltage across each of the three elements. Then, you connect the bulb, wire, and battery together to form a complete circuit, so that the bulb lights up. You repeat the measurements you made before, using the voltmeter to measure the voltage across each element while it is in the complete circuit. For the questions below, assume that the battery and the wire are ideal.
a. Compare the voltage across the battery: a) when the battery is by itself vs b) when the battery is part of the complete circuit. Is the voltage across the battery different in these two situations, or is the voltage the same? Explain your answer.
b. Compare the voltage across the bulb: a) when the bulb is by itself vs b) when the bulb is part of the complete circuit. Is the voltage across the bulb different in these two situations, or is it the same? Explain.
c. Now compare the voltage across the piece of wire: a) when the wire is by itself vs b) when the wire is part of the complete circuit. Is the voltage across the piece of wire different in these two situations, or is it the same? Explain your answer.
d. Now consider only the situation in which the battery, wire, and bulb have been arranged to form a complete circuit in which the bulb lights up. For this situation, rank i) the voltage across the battery, ii) the voltage across the bulb, and iii) the voltage across the piece of wire, according to their absolute values, from greatest to smallest. If any are the same, or if any are zero, state that explicitly. Explain your reasoning.
Answer:
A) two voltages are equal, B) the two voltages are different
C) voltage is the same V = 0, D) V_{battery} = V_{Lamp} > V_{wire}
Explanation:
For this exercise, it is asked to build a circuit with the plug, the lamp and the battery, the circuit must be a series circuit
Before connecting the battery voltage is Vo as they indicate that it is ideal there are no losses, the voltages of the other elements are zero.
A) Voltages battery
a) single battery Vo
b) the battery is connected to the lamp this takes something current, but the electromotive force does not change therefore the voltage is Vo; This is because the battery's energy comes from a chemical reaction of the elements inside it.
in summary the two voltages are equal
B) voltage Lamp
a) when the bulb is single, its voltage is zero V = 0
since it has no energy
b) when in the circuit V = V₀ - V_r
where V_r is the voltage across the wire, due to its resistance, the energy for these voltages is given by the battery
in this case the two voltages are different
C) the voltage across the wire
a) unconnected V = 0
b) connected V = V₀ - V_L
where V_L is the voltage across the lamp due to its resistance
we can write the wire voltage
V_r = i R
as they indicate that the wire is ideal, its resistance is zero R = 0, consequently
V_r = 0
the voltage is the same V = 0
D) circuit voltage
For this part we must write Ohm's law for this circuit
V₀ = V_L + V_r
where V₀ is the battery voltage, V_L and V_r are the voltage of the lamp and the wire, respectively.
The voltage of each element is
V_L = i R_L
V_r = i R
This is a series circuit so the current is also constant
V₀ = i (R_L + R)
therefore the voltage in the battery is the highest V₀
the voltage across the wire if it is ideal is zero V_r = 0, if it is ideal its resistance is zero
therefore the voltage on the lamp is equal to the voltage of the battery
V_{battery} = V_{Lamp} > V_{wire}
A Scientists want to place a 2600 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191 x 1023 kg
rmars = 3.397 x 106 m
G = 6.67428 x 10-11 N-m^2/kg^2
This What I found and calculated
time it take the satellite to complete one revolution = 9.2 hours The speed the satellite have to be in a perfectly circular orbit = 1985 m/s
Well the question I just can't get the right answer for.
What should the radius of the orbit be (measured from the center of Mars), if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
The radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.
What is Orbit?
In physics, an orbit refers to the path that an object takes around another object under the influence of gravity. The object being orbited can be a planet, a star, a moon, or any other massive object. The object in orbit is constantly pulled towards the center of the object being orbited, but also has a forward velocity that keeps it moving in a curved path around the object
We can start by using the formula for the period of an orbit:
T = 2π √(r^3/GM)
where T is the period, r is the radius of the orbit, G is the gravitational constant, and M is the mass of the planet.
We can solve for r:
r = [(GMT^2)/(4π^2)]^(1/3)
We know that the satellite currently takes 9.2 hours to complete one revolution, so its current period is:
T1 = 9.2 hours = 33,120 seconds
We also know that we want the satellite to take 8 times longer to complete one revolution, so its new period will be:
T2 = 8 x T1 = 265,000 seconds
We can now plug in the given values into the equation to solve for the new radius:
r = [(G x mmars x T2^2)/(4π^2)]^(1/3)
r = [(6.67428 x 10^-11 N-m^2/kg^2) x (6.4191 x 10^23 kg) x (265,000 s)^2 / (4π^2)]^(1/3)
r ≈ 1.38 x 10^7 meters
However, we were asked for the radius measured from the center of Mars, so we need to subtract the radius of Mars to find the altitude above the surface:
altitude = r - rmars = 1.38 x 10^7 meters - 3.397 x 10^6 meters ≈ 1.04 x 10^7 meters
Therefore, the radius of the orbit, measured from the center of Mars, should be approximately 1.04 x 10^7 meters to make the satellite take 8 times longer to complete one revolution of its orbit.
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In Canadian football, after a touchdown the team has the opportunity to earn one more point by kicking the ball over the bar between the goal posts. The bar is 10.0 ft above the ground, and the ball is kicked from ground level, 36.0 ft horizontally from the bar in (Figure 1). Football regulations are stated in English units, but convert to SI units for this problem.
Answer:
it will go in my boy they get that tuchdown
Explanation:
because I said so
The bar would have been 3.048 meters above the ground and the goalpost would have been 10.9728 meters away as per the SI units.
What is a unit of measurement?
A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
1 feet = 0.3048 meters
10 feet = 10×0.3048 meters
=3.048 meters
1 feet = 0.3048 meters
36.0 feet = 36×0.3048 meters
=10.9728 meters
According to SI measurements, the goalpost would have been 10.9728 meters away and the bar would have been 3.048 meters above the ground.
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therwise express your answer in terms of g.
1. A 10 kg box with an initial velocity of 2 m/s slows to rest over a distance of 10 meters on
a level surface. What is the size of the frictional force on the box? What is the size of the
normal force on the box? What is the ratio of the frictional force to the normal force?
The size of the frictional force on the box is 2N
The size of the normal force on the box is 98.1 N
The ratio of the frictional force to the normal force is 0.02
What is the size of the frictional force acting on the body?The size of the frictional force on the box is calculated as follows:
Total force acting on the box = Net force + Normal force
Hence;
Normal force = Total force - Net force
Net force on the box = mass * acceleration
From the formula, v² = u² + 2as
where a = acceleration
v = final velocity
u = initial velocity
s = distance
a = v² - u² / 2s
v = 0 m/s
u = 2 m/s
s = 10 m
a = 0 - 2² / 2 * 10
a = - 0.2 m/s²
Net force = 10 * -0.2 m/s²
Net force = 2 N
The frictional force = Stopping Force = Net force
Hence, frictional force = 2 N.
Normal force = mass * g
Normal force = 10 * 9.81
Normal force = 98.1 N
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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What are the major sources of energy utilized during a 100 meter race, a 1000 meter race, and a marathon
Answer:
The energy from food and then from plants and then from sun.
As sun is the ultimate source of energy.
Explanation:
Distance = 100 m, 1000m, marathon
As the distance is covered by the person, so the muscular energy is used and thus the energy comes form out food.
As we know that the energy can neither be created nor be destroyed it can transform from one form to another.
So, the energy form the food which we consume is converted into the kinetic energy as we run.
which statements describe the Gironde ecosystem
Answer:
Gironde Ecosystem is an important biological and cultural area.
Explanation:
An object accelerates 3.0 m/s2 when a force of 6.0 N is applied to it. What is the mass of the object?
Answer:
2 kgExplanation:
The mass of the object can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{6}{3} \\ \)
We have the final answer as
2 kgHope this helps you
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
When scientists look at very distant galaxies through powerful telescopes, they see the galaxies as they were millions or billions of year ago. Why is this?
Answer:
speed of light
Explanation:
the sun's light is 8 mins behind imaging that a billion fold
A car, initially traveling at 2.0 miles per hour, comes to rest in 8.6 s. What was its acceleration in this time?
Given:
the speed of the car is
\(u=2.0\text{ mi/h}\)Time during which it comes to rest
\(t=8.6\text{ s}\)Required: acceleration is to be calculated
Explanation:
first, convert the speed from miles per hour to meters per second
in doing so we use a conversion factor
that is given as
\(1\text{ mi/h= 0.447 m/s}\)Then the speed is ,
\(\begin{gathered} u=2.0\text{ }\times0.447 \\ u=0.894\text{ m/s} \end{gathered}\)now calculate the acceleration,
we know that
\(v=u+at\)where v is the final velocity that is zero because finally, the car comes to rest.
plugging all the values in the above relation, we get
\(\begin{gathered} 0=0.894\text{ m/s }+a\times8.6\text{ s} \\ a=-\frac{0.894}{8.6} \\ a=-0.10\text{ m/s}^2 \end{gathered}\)negative sign shows that acceleration in the opposite direction
Thus, the acceleration is
\(0.10\text{ m/s}^2\)a parallel-plate capacitor is charged by a battery, and the battery is then disconnected from the capacitor. because the charges on the capacitor plates are opposite in sign, they attract each other. hence, it takes positive work to increase the plate separation. show that the external work done when the plate separation is increased leads to an increase in the energy stored in the capacitor.
When the plate separation is increased, the capacitance decreases, To keep the charge constant when the capacitance diminishes, the voltage between the plates increases. As a result, the energy stored in the capacitor grows. As a result, increasing the plate gap causes an increase in the amount of energy stored in the capacitor.
When a parallel-plate capacitor is charged by a battery and then disconnected, the energy stored in the capacitor is given by the formula:
U = (1/2) * C * V^2
Where U is the stored energy, C is the capacitance, and V is the voltage across the plates. When the plate separation is increased, the capacitance decreases, as the formula for capacitance is:
C = (ε * A) / d
Here, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates.
Since the battery is disconnected, the charge Q on the plates remains constant. The relationship between charge, capacitance, and voltage is given by:
Q = C * V
As the capacitance decreases, the voltage across the plates increases in order to keep the charge constant. This, in turn, increases the energy stored in the capacitor. Therefore, the external work done when the plate separation is increased leads to an increase in the energy stored in the capacitor.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A mass on a string is swung in a circle of radius 0.75m at 7.0m/s.what its rate of acceleration.
Explanation:
ac = v^2/r
= (7.0 m/s)^2/(0.75 m)
= 65 m/s^2
What happens to the resistance of a wire as it gets wider
Answer:
it snaps
Explanation:
the more force you put on it, the wired out it gets than it snaps. I think
Power output of an engine is with work (w=60,000) during 60 s Calculate the power of this work?*
Answer:
The power output of the engine is 1,000 Watt
Explanation:
Mechanical Power
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
The engine does a work of W=60,000 J during t=60 s. Calculate the power:
\(\displaystyle P=\frac {60,000}{60}\)
P = 1,000 Watt
The power output of the engine is 1,000 Watt
Kinetic energy depends on which two things
Answer:
Explanation: relationship between the object and the observer's frame of reference.
The density of blood is 2kg/m.convert to g/cm
Explanation:
if we convert it into g/cm it'll be
2000 grams
If a dolphin swims at 1.85 m/s, how far will the dolphin have traveled after 6.0 s?
The distance traveled by by the dolphin is determined as 11.1 m.
What is distance?The distance traveled by an object is the product of speed and time of motion of the object. It measures the total path covered by the object.
The distance traveled by by the dolphin is calculated as follows;
Distance = speed x time of motion
Distance = 1.85 m/s x 6 s
Distance = 11.1 m
Thus, the distance traveled by by the dolphin is determined as 11.1 m.
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Write the percent as a fraction or a mixed number in simplest form.
7%
A box of mass m is pulled at an angle 0 by a force F, along a frictionless surface. The box accelerates to the right,
F
m
What is the magnitude of the normal force?
Answer:
The magnitude of the normal force is equal to the weight of the box multiplied by the cosine of the angle θ.
Explanation:
When a box is pulled along a frictionless surface at an angle θ, the normal force acting on the box is perpendicular to the surface and opposes the force of gravity.
In this case, the box is accelerating to the right, which means the force F is greater than the force of gravity pulling the box downward.
The magnitude of the normal force (N) can be determined by breaking down the forces in the vertical direction:
Sum of vertical forces = 0
N - mg * cos(θ) = 0
Here, mg * cos(θ) represents the vertical component of the weight of the box, which is balanced by the normal force.
Rearranging the equation, we have:
N = mg * cos(θ)
A ball is launched from the surface of a planet. Air resistance and other frictional forces are neglected. The graph shows the position of the ball every 0.20 s.
a. Use this graph to determine:
I. The components of the initial velocity of the ball
II. The angle to the horizontal the ball was launched at
III. The acceleration of free fall on this planet.
b. Make a copy of the graph and draw two arrows to represent the velocity and the acceleration vectors of the ball at t = 1.0 s.
c. The ball is now launched under identical conditions from the surface of a different planet where the acceleration due to gravity is twice as large. Draw the path of the ball on your graph.
The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.
What are the velocities ?Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.
What is time ?Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.
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A subatomic particle X spontaneously decays into two particles, A and B, each of rest energy 1.40 × 10^2 MeV. The particles fly off in opposite directions, each with speed 0.827c relative to an inertial reference frame S. What is the total energy of particle A?
Answer:
E = 389 MeV
Explanation:
The total energy of particle A, will be equal to the sum of rest mass energy and relative energy of particle A. Therefore,
Total Energy of A = E = Rest Mass Energy + Relative Energy
Using Einstein's Equation: E = mc²
E = m₀c² + mc²
From Einstein's Special Theory of Relativity, we know that:
m = m₀/[√(1-v²/c²)]
Therefore,
E = m₀c² + m₀c²/[√(1-v²/c²)]
E = m₀c²[1 + 1/√(1-v²/c²)]
where,
m₀c² = rest mass energy = 140 MeV
v = relative speed = 0.827 c
Therefore,
E = (140 MeV)[1 + 1/√(1 - (0.827c)²/c²)]
E = (140 MeV)(2.78)
E = 389 MeV
1. Using the graph, calculate the displacement for the section labeled A.
А
B
D
The Send
Direction of propagation of light is:________a. in all directions irrespective of polarization b. parallel to the polarization c. perpendicular to the polarization d. not dependent on polarization
Answer:
Perpendicular to the polarization
Explanation:
In this question, we are interested in selecting the option that best complete the question.
The direction of propagation of light is perpendicular to the polarization. Polarized and unpolarized light behave in different manners.
In unpolarized light, the oscillation of the magnetic and electric occurs in all directions to the propagated light.
However, in the case of polarized light, there is a restriction of the electric field oscillation. And thus, it only oscillates in a direction which is perpendicular to the propagation light
Which description tells two processes scientists think move Earth's lithospheric plates?
Responses
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and friction between the plate and the asthenosphere
gravity acting on the edges of plates and friction between the plate and the asthenosphere
convection in the mantle and pressure of magma on the edge of the plate
The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.
What is the Earth's lithosphere?The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.
The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.
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Answer: convection in the mantle and pressure of magma on the edge of the plate
Explanation: I took the unit test
What is the main purpose for learning about significant figures in science and/or technology courses? Give a detailed answer without plagiarism.
The significant figure of a value or measurement is the number of important digits that it contains
The main purpose for learning about significant figures in science and/or technology courses is precision of measurements.
In science and technology experiments and reseaches, we always want to ensure that measured values are as close to the true values as possible. This is because any deviation from the true value can invalidate the result of the experiment. Also, errors due to repeated approximations can have cummulative effects on the experimental results.
Therefore, the knowledge of significant figures is useful in science and technology to be able to record values of experimental measurements as close as possible to the actual value.
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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