What occurs to the atoms of reactants in a chemical reaction?

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Thus option C is correct option.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because different chemicals condense at different temperatures.

Therefore,  option C is correct option.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:

Wheat

Explanation:

1. Heat

2. Eat

3. Tea

4. Wheat. You are wheat.

Answer:

Wheat, heat, eat, tea

Explanation:

The mass of silicon, Si produced from the reaction is 329.41 g

SiCl₄ + 2Mg —> 2MgCl₂ + Si

Molar mass of SiCl₄ = 28 + (35.5×4) = 170 g/mol

Mass of SiCl₄ from the balanced equation = 1 × 170 = 170 g

Molar mass of Si = 28 g/mol

Mass of Si from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

Therefore,

2 Kg (i.e 2000 g) of SiCl₄ will react to produce = (2000 × 28) / 170 = 329.41 g of Si

Thus, 329.41 g of Si were obtained from the reaction

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Answer:

Explanation:

B

Answer:

the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Explanation:    

Given the data in the question and the figure below;

N2 BALANCE

(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)

0.82 × ( mole rate in ) = 0.95 × ( mole rate out)

mole rate in = 0.95 × ( mole rate out) / 0.82

mole rate in = 1.1585365853 × ( mole rate out)

now;

HEXANE BALANCE

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate  --- equ 1

but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane

we know that;

density of hexane is 0.6548 g/mL

and molar mass of hexane is 86.18 g/mol

so,

condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)

condensate = 11.3970758876

now lets substitute into equation 1

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate

⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876

⇒ 0.158536585354(mole rate out) = 11.3970758876

mole rate out = 11.3970758876 / 0.158536585354

mole rate out =  71.889247 ≈ 71.9 moles/min

Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Answer:

Molar mass of O is = 16

Molar mass of O2 = 32

In this letter, express gratitude to your uncle, a university professor, for his invitation and congratulate him on his achievements.

Here are the steps to be followed:

By following these steps, you can write a thoughtful and appreciative letter to your uncle, expressing your gratitude for his invitation and congratulating him on his achievements.

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Answer:

8 protons, 10 electrons.

Explanation:

the -2 charge adds 2 electrons–hence, you have 10 electrons while protons remain at 8.

Answer:Changes of state are physical changes. They occur when matter absorbs or loses energy. Processes in which matter changes between liquid and solid states are freezing and melting. Processes in which matter changes between liquid and gaseous states are vaporization, evaporation, and condensation

Explanation:

Don't worry I got your back!

MAAAAAAAAAAAARKKKKKKKKKKKKKKKKK MEEEEEEEEEEEEEEEE AAAAAAAAAASSSSSSSSSSSSS BBBBBBBBBBBBBBRRRRRRRRRRRRRRRRAAAAAAAAIIIIIIIIIIIIIIIIIIIIIINNNNNNNNNNNNLLLLLLLLLLLLLLYYYYYYYYYYYYYEEEEEEEEEEEEEESSSSSSSSSSSSSSTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

Answer: 0.85 hertz

Explanation: Calculator said so also 0.85 is decimal form for 85

Answer:

o

Explanation:

it is not a gas because the particles do not move freely it may be a liquid or a solid partly and mostly liquidized.

Chlorine and Aluminum atoms shielding effect on their outer electrons is in chlorine there is 7 electron and in aluminum there is poor shielding effect so the greater size of aluminum

An electron is the s sublevel shied electron present in the p sublevel of the same principal energy level and the electron shielding refer to the blocking of valence shell electron attraction by the nucleus due to the presence of inner shell electron and electron in an s orbital can shielding p electron at the same energy level because of the spherical shape of the s orbital and valence electron are the number of electron present in the outermost shell of an atom and now the last shell of the chlorine atom has 7 electron in it and in aluminum there is poor shielding effect so the greater size of aluminum

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Answer:

C=5

H=12

O=2•8=16

Second one

C=1•5=5

H=2•6=12

O=10+6=16

Explanation:

Answer: 1.8 micrograms, 1.8 milligrams, 1.8 grams, 1.8 kilograms

Explanation:

Taking into account the definition of sensible heat, the mass of copper in the sample is 277.06 grams.

When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure (physical state), it is called sensible heat.

The expression that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of sensible heat:

1600 J = 0.385 J/gC× m× 15 C

Solving:

1600 J = 5.775 J/g× m

1600 J÷ 5.775 J/g= m

277.06 g= m

Finally, the mass of copper in this case is 277.06 grams.

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The balanced oxidation-reduction equation for the destruction of cyanate ion waste solution from gold-mining operations by treatment with hypochlorite ion in basic solution is:

OCN⁻(aq) + OCl⁻(aq) + 2OH⁻(aq) → CO₂⁻(aq) + N₂(g) + Cl⁻(aq) + H₂O(l)

In this reaction, the cyanate ion (OCN⁻) is oxidized to carbon dioxide (CO₂⁻) and nitrogen gas (N₂), while the hypochlorite ion (OCl⁻) is reduced to chloride ion (Cl⁻). The reaction takes place in basic solution, which provides the hydroxide ions (OH⁻) needed to neutralize the acidic H⁺ ions produced during the oxidation of the cyanate ion.

The reaction is exothermic, releasing heat energy as the products form. This reaction is an effective way to dispose of the cyanate ion waste generated by gold-mining operations, as it converts the hazardous waste into harmless gases and ions.

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The amount of heat required to vaporize 181.20 g of ethanol would be 170.1 kJ.

Using the formula:

Q = n ∆Hvap

where:

Moles of 181.20 g of ethanol = 181.20 g / 46.07 g/mol = 3.933 mol

Substituting the values:

Q = 3.933 mol x 43.3 kJ/mol = 170.1 kJ

In other words, the amount of heat required to vaporize 181.20 g of ethanol is 170.1 kJ.

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The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

C6H12O2

Explanation:

The Jones reagent is a reagent in organic chemistry used to convert primary alcohols to carboxylic acids and secondary alcohols to ketones. Recall that tertiary alcohols can not be oxidized.

The compound  2-methyl-2,3-pentandiol contains one secondary and one tertiary alcohol. The secondary alcohol is oxidized to a ketone while the tertiary alcohol is not oxidized.

Hence the product of the oxidation using Jones reagent is 2-Hydroxy-2-methyl-3-pentanone with the molecular formula C6H12O2.

Answer:

An heater, Oven, sun, and fireplaces

Chose which ever you want

Answer: A

Explanation: Geologists classify rocks by looking at their chemical and mineralogical composition then at the the size and shape of their component minerals then at any texture.

Answer:

To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).

Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.

In this way, your reasoning is correct and it is probably a mistake in the book.

Answer:

No

Explanation:

AgNO₃ + KCl --> AgCl + KNO₃

This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.

The flow of water in a pipe and the flow of electrons in a wire are both examples of fluid flow and are caused by different physical phenomena.

The flow of water in a pipe is caused by a pressure difference, also known as a pressure gradient, between two points. If the pressure at one end of the pipe is higher than the pressure at the other end, water will flow from the high-pressure end to the low-pressure end. The flow rate will depend on the pressure difference, the diameter of the pipe, and the viscosity of the fluid.

The flow of electrons in a wire, on the other hand, is caused by a difference in electrical potential, also known as a voltage difference, between two points. If the voltage at one end of the wire is higher than the voltage at the other end, electrons will flow from the high-voltage end to the low-voltage end. The flow rate will depend on the voltage difference, the resistance of the wire, and the number of electrons available to flow.

In summary, the cause of the flow of water in a pipe is a pressure difference, while the cause of the flow of electrons in a wire is a voltage difference.

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Interdisciplinary science is a cooperative process that combines the knowledge and skills of qualified professionals from two or more fields.

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No, this statement is not correct. A weak base will not completely dissociate and accept all of the hydrogen ions released from the acid.

Instead, a weak base will partially dissociate and accept some of the hydrogen ions, helping to buffer the drop in pH but not completely preventing it. This is why weak bases are used as buffers in solutions, as they can help to maintain a relatively stable pH even when an acid is added. However, they will not completely prevent a drop in pH like a strong base would.

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If Sherman suggests that reproduction always creates individuals with adaptive traits, then he/she is not correct because variation may lead to non-adaptive phenotypes.

The presence of genetic variation in individuals of a given population is not adaptive per se, but instead, it provides the raw material for natural selection that leads to the differential survival and reproduction of the most adaptive phenotypes.

The genetic variation in individuals of a given population does not crate adaptive traits and it may derive from sexual reproduction.

Therefore, with this data, we can see that the presence of genetic variation in individuals of a given population may or not be adaptive in the function of the environment in which the individual produced by means of sexual reproduction is developed and therefore it is an advantage for the population but the individual may be harmful.

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