The Net magnetic field will be at the left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.
Case I
As the current in both wires is not equal, the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which is to the Left.
Case II
It is similar to the case I, as the current in both wires is not equal, and the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which in this case is to the Right.
Case III
As the current in both wires is the same and equal to 3 A, the net magnetic field will be zero in the middle. Which is in Between.
Case IV
As the current flowing in the wire is opposite in the direction, the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.
Case V
It is similar to the above case IV, as the current flowing in the wire is opposite in the direction, and the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.
Therefore, the Net magnetic field will be at left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.
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Which form of energy increases when a spring is compressed?
Answer:
When the spring compresses, elastic potential energy increases.
Answer:
the answer is b
Explanation:
elastic potential energy
⦁ A certain resistor is required to dissipate 0.25 W, what standard rating should be used?
Answer:A
Explanation:
A current-carrying gold wire has diameter 0.88 mm. The electric field in the wire is0.55 V/m. (Assume the resistivity ofgold is 2.44 10-8 Ω · m.)
(a) What is the current carried by thewire?
1 A
(b) What is the potential difference between two points in the wire6.3 m apart?
2 V
(c) What is the resistance of a 6.3 mlength of the same wire?
3 Ω
Hi there!
a)
We know that the resistance of the wire is equivalent to:
\(R = \frac{\rho L}{A}\)
R = Resistance (Ω)
ρ = Resistivity (Ωm)
L = Length (m)
A = Cross-sectional area (m²)
We can relate the voltage to an electric field by:
\(V = Ed \\\\V = El\)
V = Potential Difference (V)
E = Electric Field (V/m)
l = Length of wire (m)
And Ohm's Law:
\(V =iR\)
i = Current (A)
V = Potential Difference (V)
R = Resistance (Ω)
We do not know the length, so we can solve using the above relationships.
\(V = iR\\\\V = i\frac{\rho L}{A}\\\\\frac{V}{L} = E = i\frac{\rho}{A}\\\\i = \frac{EA}{\rho} = \frac{.55 \times \pi (0.00044^2)}{(2.44 \times 10^{-8})}} = \boxed{13.71 A}\)
b)
We know that V = Ed (Electric field × distance), so:
\(V = 0.55 \times 6.3 = \boxed{3.465 V}\)
c)
Calculate the resistance using the above equation.
\(R = \frac{\rho L}{A}\\\\R = \frac{(2.44\times 10^{-8})(6.3)}{\pi(0.044^2)} = \boxed{2.527 \times 10^{-5} \Omega}\)
The three displacement vectors in the drawing have magnitudes of A = 5.93 m, B=5.53 m, and C=3.99 m. Find the resultant
((a) magnitude and (b) directional angle) of the three vectors by means of the component method. Express the directional angle as an angle above the positive or negative x axis which is less than 90°.
The magnitude of the resultant vector R is 4.12m, and the directional angle of the resultant vector is -86.2° above the negative x-axis.
The three displacement vectors have magnitudes of A = 5.93 m, B=5.53 m, and C=3.99 m. Using the component method, we can write each vector in terms of its x and y components. The x and y components of the vector are given as follows; Vector A: Ax = A cos(65.0°) = 5.93 cos(65.0°) = 2.55 m Ay = A sin(65.0°) = 5.93 sin(65.0°) = 5.28 mVectorB: Bx = B cos(150°) = 5.53 cos(150°) = -2.74 m By = B sin(150°) = 5.53 sin(150°) = 2.83 mVector C: Cx = C cos(270°) = 3.99 cos(270°) = 0 m Cy = C sin(270°) = 3.99 sin(270°) = -3.99 m.The x component of the resultant vector, Rx is given by; Rx = Ax + Bx + Cx = 2.55 - 2.74 + 0 = -0.19 m.The y component of the resultant vector, Ry is given by; Ry = Ay + By + Cy = 5.28 + 2.83 - 3.99 = 4.12 m.The magnitude of the resultant vector R is given by; \(R = \sqrt(Rx^2 + Ry^2) = \sqrt(0.19^2 + 4.12^2) = 4.12 m.\)Therefore, the magnitude of the resultant vector is 4.12 m.The directional angle of the resultant vector is given by; \(\theta = tan^{-1}(Ry/Rx) = tan^{-1}(-4.12/0.19) = -86.2\textdegree\)Therefore, the directional angle of the resultant vector is -86.2° above the negative x-axis, which is less than 90°.For more such questions on the resultant vector:
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How many times a minute does a boat bob up and down on ocean waves that have a wavelength of 35.6 m and a propagation speed of 4.68 m/s? (the answer may not be a whole number)
Answer:
It will bob 7.887640449 times a minute
Explanation:
I hope this is correct!!
what is the change of entropy if 536 g of gold are melted?
Answer: Therefore, the change in entropy when 536 g of gold are melted is 0.132 J/K.
Explanation: To calculate the change in entropy when 536 g of gold are melted, we need to know the entropy of fusion of gold and the temperature at which it melts.
The entropy of fusion of gold is 2.35 J/g·K, and the melting point of gold is 1064 °C or 1337 K.
The change in entropy when gold is melted can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat absorbed during the process, and T is the temperature at which the process occurs.
The heat absorbed when gold is melted can be calculated using the formula:
Q = m × ΔH_fus
where m is the mass of the gold and ΔH_fus is the enthalpy of fusion of gold, which is 64.9 kJ/mol.
Converting the mass of gold to moles:
536 g / 196.97 g/mol = 2.72 mol
The heat absorbed by the gold when it is melted is:
Q = 2.72 mol × 64.9 kJ/mol = 176.2 kJ
Finally, we can calculate the change in entropy:
ΔS = Q/T = 176.2 kJ / 1337 K = 0.132 J/K
Are these bones axial, appendicular
or both?
Answer:
Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.
Explanation:
In Niels Bohr's 1913 model of the atom, the electron is in a circular orbit around a nucleus. An electron is 7.60 10-11 m from a nucleus traveling in a circular orbit with a speed of 2.45 106 m/s. (a) What is the magnitude of the magnetic moment due to the electron's motion?
Answer:
14.896 x 10^-24
Explanation:
Mo = (evr)/2e = electron = 1.6 x 10^-19v = velocityr = radius =7.60 x 10^-11Doubling the amplitude of a sound wave will ?
A) Double the speed of the sound and cause it to have a higher pitch
B) Havel the speed of sound and cause it to have a lower pitch
C) Leave the speed of sound unchanged, but cause the sound to be louder
D) Leave the speed of sound unchanged and cause the sound to have a lower pitch
Answer:
(C) is correct option.
Explanation:
The loudness of sound wave determines its amplitude. If the sound is loud, it will have more amplitude while if the sound is soft, it will have less amplitude.
On doubling the amplitude of sound wave, it will become more loud.
Doubling the amplitude of a sound wave will leave the speed of sound unchanged, but cause the sound to be louder. Hence, the correct option is (C).
A wave reflects off a certain boundary. The reflected wave has the same amplitude
and orientation as the incident wave. What is this the result of?
A. The wave experienced destructive interference.
B. The wave experienced constructive interference.
C. The wave reflected off of a free boundary.
D. The wave reflected off of a fixed boundary.
If the reflected wave has the same amplitude and orientation as the incident wave, it is because the wave experienced destructive interference.
option A.
What is destructive interference?
Destructive interference occurs when waves come together so that they completely cancel each other out. When two waves destructively interfere, they must have the same amplitude in opposite directions.
So when a wave reflects off a certain boundary and the reflected wave has the same amplitude and orientation as the incident wave, it is because both waves interfere destructively.
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12. A car travels in a straight line with an average velocity of 80 km/h for 2.5h and then an average velocity of 40 km/h from 1.5 h (a) what is the total displacement for the 4 h trip? (b) What is the average velocity for the total trip?
Answer:
a. Total displacement = 140 km/h
b. Average velocity = 35 km/h
Explanation:
Given the following data;
Average velocity A = 80 km/h
Time A = 2.5 hours
Average velocity B = 40 km/h
Time B = 1.5 hours
a. To find the total displacement for the 4 h trip;
Total time = Time A + Time B
Total time = 2.5 + 1.5
Total time = 4 hours
Next, we would determine the displacement at each velocity.
Mathematically, displacement is given by the formula;
Displacement = velocity * time
Substituting into the formula, we have;
Displacement A = 80 * 2.5
Displacement A = 200 km/h
Displacement B = 40 * 1.5
Displacement B = 60 km/h
Total displacement = Displacement A - Displacement B
Total displacement = 200 - 60
Total displacement = 140 km/h
b. To find the average velocity for the total trip;
Mathematically, the average velocity of an object is given by the formula;
\( Average \; velocity = \frac {total \; displacement}{total \; time} \)
Substituting into the formula, we have;
\( Average \; velocity = \frac {140}{4} \)
Average velocity = 35 km/h
2. Find the value of A in the unit vector 0.4î+ 0.8ĵ+ λk.
There is no A in the vector, so I assume you mean λ.
The magnitude of any unit vector is 1, so
\(\|0.4\,\vec\imath + 0.8\,\vec\jmath + \lambda \,\vec k\| = \sqrt{0.4^2 + 0.8^2 + \lambda^2} = 1\)
Square both sides and solve.
\(0.4^2 + 0.8^2 + \lambda^2 = 1^2 \implies \lambda = \boxed{\pm \sqrt{0.2}}\)
In hiking, what fitness component is required of you
Two objects with masses of m1 = 3.70 kg and m2 = 5.70 kg are connected by a light string that passes over a frictionless pulley, as in the figure below. Answer parts a-c.
(a) The tension in the string is determined as 19.6 N.
(b) The acceleration of each object is 5.3 m/s².
(c) The distance each object will move in the first second if it started from rest is 2.65 m.
What is the tension in the string?(a) The tension in the string is the resultant weight of the masses and magnitude is calculated as follows;
T = ( 5.7 kg - 3.7 kg ) x 9.8 m/s²
T = 19.6 N
(b) The acceleration of each object is calculated as follows;
a = T / m
where;
m is the mass T is the tensiona = 19.6 N / 3.7 kg
a = 5.3 m/s²
(c) The distance each object will move in the first second if it started from rest is calculated as;
s = ut + ¹/₂at²
where;
u is the initial velocity = 0s = 0 + ¹/₂(5.3)(1²)
s = 2.65 m
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The archerfish uses a remarkable method for catching insects sitting on branches or leaves above the waterline. The fish rises to the surface and then shoots out a stream of water precisely aimed to knock the insect off its perch into the water, where the archerfish gobbles it up. Scientists have measured the speed of the water stream exiting the fish's mouth to be 3.7 m/s. An archerfish spots an insect sitting 18 cm above the waterline and a horizontal distance of 28 cm away. The fish aims its stream at an angle of 39° from the waterline.
Required:
Determine the height above the waterline that the stream reaches at the horizontal position of the insect.
Answer:
The fish gobbles the mosquito at height 18 cm.
Explanation:
Initial velocity, u = 3.7 m/s
horizontal distance, d = 28 cm
Angle, A = 39 degree
Let the time is t.
Horizontal distance = horizontal velocity x time
d = u cos A x t
0.28 = 3.7 cos 39 x t
t = 0.097 s
Let the height is h.
Use the second equation of motion
\(h =u t-0.5 gt^2\\\\h= u sin A t - 0.5 gt^2\\\\h= 3.7 sin 39 \times 0.097 - 0.5\times 9.8\times 0.097\times0.097\\\\h =0.226 -0.046 \\\\h=0.18 m=18 cm\)
A car mass 600kg starts from rest moving uniform acceleration 0.2 m/s^2 after 60 seconds collides with stationary pick up van of mass 400kg gets locked with it and moves together with velocity 7.2 m/s
a) DOES THE PHENOMENON OF THE STEM SUPPORT THE PRINCIPLE OF CONSERVATION OF MOMENTUM? GIVE YOUR OPINION BY MATHEMATICAL ANALYSIS.
Answer:
The given phenomenon supports the Principle of Conservation of momentum.
Explanation:
law of conservation of momentum
Initial Momentum = Final Momentum
So, first we calculate initial momentum of the system:
Initial Momentum = m1*u1 + m2*u2
and we are given
m1 = mass of car = 600 kg
m2 = mass of van = 400 kg
u1 = Initial Speed of Car
to find the initial speed we use equation of motion
Vf = Vi + at
Vf = 0 m/s + (0.2 m/s²)(60 s)
Vf = u₁ = 12 m/s
u₂ = Initial Speed of Van = 0 m/s
Therefore,
Initial Momentum = (600 kg)(12 m/s) + (400 kg)(0 m/s)
Initial Momentum = 7200 Ns .........(1)
final momentum = m₁v₁ + m₂v₂
where,
v₁ = v₂ = final speed of car+van (both locked ) = 7.2 m/s
Therefore,
Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)
Final Momentum = 7200 Ns -------- (2)
on comparing (1) and (2)
Initial momentum = Final Momentum
Hence, the phenomenon of the system supports the principle of conservation of momentum.
7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.
The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.
What is centrifugal force?when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.
It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.
The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.
To simulate gravity for the inhabitants, the concept of the centrifugal force is used.
Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.
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4. A student travels 20 km South, and 14 km East. What is the student's displacement?
a. 24.4 km SE
b. 772 km SE
c. 11 km NE
d. 4 km NE
Answer:
d. 4 km NE
Explanation:
Give me brainliest if that helped!
A 20 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 80 N to the left
Explanation:
it will move to thr left?
Who has the best dog ever!?!?
Answer:
10x10=100
snoopy ofc :)
Answer:
Labrador Retriever.
hope it will help you
A stone of mass 100g is projected upwards with an initial velocity of u. The stone reaches a maximum height of s. What initial velocity would the stone have to be projected with to reach a maximum height of 2s.2uu square root 24u8u
u√2
Explanation:The mass, m = 100 g
m = 100/1000 g
m = 0.1 kg
Using the equation of motion below for upward motion
\(\begin{gathered} v_f^2=v_i^2-2gH \\ \\ where: \\ v_f=final\text{ velocity} \\ \\ v_i=initial\text{ velocity} \\ \\ H=height \end{gathered}\)At maximum height, vf = 0 m/s
\(\begin{gathered} 0=v_i^2-2gH \\ \\ v_i^2=2gH \\ \\ v_i=\sqrt{2gH} \end{gathered}\)When maximum height, H = s, initial velocity = u
\(v_i=\sqrt{2gs}\text{ = u}\)When maximum height, H = 2s
\(\begin{gathered} v_i=\sqrt{2g(2s)} \\ \\ v_i=\sqrt{4gs} \\ \\ v_i=\sqrt{2}\times\sqrt{2gs} \\ \\ v_i=\sqrt{2}u \\ \\ v_i=u\sqrt{2} \end{gathered}\)The initial velcoity that the stone has to be projected with to reach a maximum height of 2s = u√2
A 15 kg box is pushed with a force of 35 N in the +x direction, and the box accelerates to the right. It does not accelerate up or down
The box accelerates to the right due to the applied force of 35 N in the +x direction.
Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:
acceleration = net force / mass
acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)
Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.
Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.
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Mr. Bateman creates a standing wave in the front of the classroom with the spring. S nodes form. The distance from Mr. Bateman to the cabinet is 6m. If a student times the spring moving back and forth and gets 0.2s for one cycle of the spring, how fast are the
waves moving?
Answer:
The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.
In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.
The answer is 30 m/s.
Explanation:
A scientist makes a model of Earth's water by drawing 100 drops of water, all the same size. How many of the 100 drops represent ocean water?
A.3
B.50
C.75
D.97
Answer:
D
Explanation:
If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)
A driver wearing a seat beat decelerates at roughly the same rate as the car it self. Since many modern cars have a "crumble zone" built into the front of the car, let us assume that the car decelerates of a distance of 0.9 m. What is the net force acting on a 65 kg driver who is driving at 18 m/sec and comes to rest in this distance
Answer:
11,700Newton
Explanation:
According to Newton's second law, Force = mass × acceleration
Given mass = 65kg.
Acceleration if the car can be gotten using one of the equation of motion as shown.
v² = u²+2as
v is the final velocity = 18m/s
u is the initial velocity = 0m/s
a is the acceleration
s is the distance travelled = 0.9m
On substitution;
18² = 0²+2a(0.9)
18² = 1.8a
a = 324/1.8
a = 180m/²
Net force acting on the body = 65×180
Net force acting on the body = 11,700Newton
In an amusement park water slide, people slide down an essentially frictionless tube. The top of the slide is 3.1 m above the bottom where they exit the slide, moving horizontally, 1.4 m above a swimming pool.
What horizontal distance do they travel from the exit point before hitting the water?
They travel a horizontal distance of 4.17 m from the exit point before hitting the water.
What is the law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.
height of the slid: h = 3.1 m
horizontal movement above swimming pool: s = 1.4 m
Let the horizonal speed of the people at the end of the water slide= v
Using energy conservation
mgh = 1/2 mv²
v = √(2gh)
Again time taken for falling s = 1.4 m under gravitation:
t = √(2s/g)
Hence, the horizontal distance travelled = speed × time
= √(2gh)×√(2s/g)
= √(4hs)
= √(4 × 3.1 × 1.4)
= 4.17 m.
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Platinum is used in resistance thermometer for industrial applications because of?
platinum is used because it is more stable, provides accurate results and has a broad temperature range.
In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.
The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.
This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point in the sunlight is equal to the pressure at any other point not in the sunlight.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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what is the equivalent resistance of the circuit shown below?
The equivalent resistance of the circuit shown is 23 ohms.
Option A is correct.
What is resistance?Resistance is described as the opposition that a substance offers to the flow of electric current.
In a series circuit, all components are connected end-to-end to form a single path for current flow.
In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.
We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) + 1 /(50+ 50)
I/R = 0.04
R = 25 ohms.
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