The battery's emf has to be -108.75 volts for a 2a current to pass through a 5.00 v battery.
Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero. The conservation of energy, or to put it another way, is the characteristic of Kirchhoff's law which states that the algebraic sum of each voltage in the loop must equal zero.
Do a series/parallel reduction first. Apply Kirchhoff's laws now to get the answer.
ΔV adefa =0 or − (20Ω) × (2A) × 5V − (20Ω) × I2
= 0 or I2
= −2.25A
I1 + I2 = 2A or I1 = 2A − ( −2.25A ) = 4.25A
ΔV adefa = 0 or (15Ω) × (4.25A) + ϵ − (20Ω) (−2.25A) = 0
ϵ = −108.75V; Reversing polarity is necessary.
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what heavy element was the chernobyl nuclear accelarators supposed to make?
Answer
plutonium
Explanation:
brainliest please
How would the pollution from 2 coal plants compare if the first plant were twice as energy efficient as the second one?
The pollution from the first plant would be half that of the second plant for the same amount of energy produced.
The energy efficiency of a coal plant refers to the amount of energy produced per unit of fuel consumed. If the first plant is twice as energy efficient as the second plant, it means that it can produce the same amount of energy using half the amount of fuel.
Since pollution from coal plants is directly proportional to the amount of fuel consumed, the first plant would produce half the pollution of the second plant for the same amount of energy produced. This assumes that the two plants have the same level of emissions per unit of fuel consumed, which may not necessarily be the case.
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There is a filing cabinent that is 52 in. tall and 15 in. wide. The center of gravity of the cabinet is right at the center. To what angle can the cabinet be tipped before it falls over?
Answer:
16 degrees
Explanation:
The tipping point of the cabinet is sketched below.
A rope is vibrating so as to form the standing wave pattern shown at the right. 1.How many nodes are present in the rope?2.What harmonic is shown in the pattern?3.A guitar string has a fundamental frequency of 120 Hz. What is the frequency of the third harmonic of the string?
We will have the following:
1. There are 5 nodes.
2. The harmonic shown is the 4th harmonic.
3. We will detemrine the 3rd harmonic as follows:
\(\lambda_3=\frac{3}{2}(120Hz)\Rightarrow\lambda_3=180Hz\)Iu Metallic bonding is similar to iconic bonding because
Answer:
In an ionic bond the valence electrons are transferred from the metal
Explanation:
The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 18°. The transition should be rounded with what minimum radius so that cars traveling 95 km/h will not leave the road
Answer:
74.7 m
Explanation:
You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.
AccelerationThe acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...
g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²
RadiusThe radius of an arc and the speed of travel are related to the normal acceleration by ...
r = v²/a
where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.
The speed of 95 km/h can be translated to m/s by ...
(95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s
RadiusUsing the above relation to find the radius, we get ...
r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m
The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.
__
Additional comment
In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.
An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.
Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.
the velocity of an object must include these two things ________ and _________
will give brainlest
Answer:
The velocity of an object must include these two things displacement and time.
Explanation:
Hope this helps you. Have a nice day^_^
Please mark as brainliest. It helps a lot. :)
Find the emitted power per square meter of peak intensity for a 3000 K object that emits thermal radiation. Express your answer to three significant figures and include the appropriate units. H MÅ 0 = ? P= Value Units Submit Request Answer oblem 5.58 SUDITI NcqucstATIS WEL
The peak wavelength for peak intensity of 3000 K is 967 nm and peak wavelength for peak intensity of 50,000K will be 58nm.
What is Power?
Power is the amount of energy which is transferred or converted per unit of time taken. In the International System of Units, the unit of power is the watt (W), which is equal to one joule per second.
Stefan-Boltzmann constant = 5.67 × 10⁻⁸ Wm²
Peak intensity = 2000 K
P = (5.67 × 10⁻⁸) × (3000)⁴
P = 4.59 × 10⁶
P = 459 2700 watts of power per square meter.
Peak intensity = 3000 K
Using Wein law,
λ max = 0.29/ 7
λ max = 0.29/ 3000 = 9.67 × 10⁻⁵ = 967 nm
Same method as above will be used for 50,000 K
P = 3.56 × 10¹¹ W/m²
P = 356.00.000000000 W/m²
λ (Peak) = 58nm
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Two protons (charge q
= 1.602·10-19 C) move at the same speed v=
1.6 ·105 m/s in opposite directions parallel to the x-axis. At the instant when they are at the same x-position, the proton moving in the negative direction is at distance r=
0.7 m in the positive y-direction with respect to the one moving in the positive direction.
What is the magnetic field direction at the point of the proton moving in the negative direction?
+x
-x
+y
-y
+z
-z
What is the magnetic force direction experienced by the proton moving in the negative direction?
+x
-x
+y
-y
+z
-z
The magnetic field at the point of the proton moving in the negative direction is equal to 1.84 ×10⁻¹⁴ T.
The magnetic force experienced by the proton moving in the negative direction is equal to 4.71 x 10⁻²⁸ N.
What is the magnetic field due to proton?The magnitude of the magnetic field due to the proton at distance 'r' moving in the negative direction is determined as follows;
F = q.v.B = (kq²)/r²
q.v.B = kq²/r²
B = kq/vr²
Where, k is the coulomb's constant, r is the distance between two protons, q is the charge of the protons, and v is the proton's speed.
Given the charge on the proton, q = 1.602 × 10⁻¹⁹C
The speed of the proton, v = 1.6 × 10⁵ m/s
B = (9 × 10⁹ × 1.602 × 10⁻¹⁹) / (1.6 x 10⁵ m/s × 0.7 × 0.7)
B = 18.39 × 10⁻¹⁵ T
B = 1.84 ×10⁻¹⁴ T
The magnetic force in the negative direction experienced by the proton is calculated as follows;
F = qvB
F = 1.602 × 10⁻¹⁹× 1.6 x 10⁵ × 18.39 × 10⁻¹⁵ T
F = 47.1 × 10⁻²⁹ N
F = 4.71 × 10⁻²⁸ N
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A high-quality diamond may be quite clear and colorless, transmitting all visible wavelengths with little absorption. Explain how it can sparkle with flashes of brilliant color when illuminated by white light.
Answer:refraction
Explanation:
The light that enters a diamond emerges only at certain points, and these points shine because many rays have been directed towards them. This process is called as Refraction.
What is Refraction?Refraction is defined as the redirection of a wave as it travels from one medium to another whereas redirection can be caused by a change in the speed of the wave or by a change in the medium.
Refraction of light is one of the most common observed phenomena, but other waves such as sound waves and water waves also experience refraction which makes it possible for us to have optical instruments such as magnifying lenses, lenses and prisms. It is due to refraction of light that we are able to focus light on our retina.
A high-quality diamond may be quite clear and colorless, transmitting all visible wavelengths with little absorption that is called as refraction.
Thus, the light that enters a diamond emerges only at certain points, and these points shine because many rays have been directed towards them. This process is called as Refraction.
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draw a graph of the voltmeter reading versus ammeter readings.
The VI graph helps us to find Resistance.
It was used by Ohm which is well known as ohms law.
Where are you likely to find a cooling coil located in the ductwork?
A. A medium-sized office
B. A large apartment building
C. A single-family home
D. A large factory
Cooling coil is a part of air conditioner and you are likely to find it located in the ductwork of a large apartment building. Hence, option (B) is correct.
What is cooling coil?The cooling coils are a part made up of tubes made of various materials that allow a fluid to move through them. These tubes also have an exterior contact with air or another gas, which enables a heat exchange.
In the fluid that flows through the cooling coils, either water or a refrigerant may be present.
The cooling coils are elements that cool or warm the air in a cooling system intended for comfort.
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A 70kg boy is running at about 9m/s. find its kinetic energy
\(\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2\)
\(\\ \sf\longmapsto K.E=\dfrac{1}{2}(70)(9)^2\)
\(\\ \sf\longmapsto K.E=35(81)\)
\(\\ \sf\longmapsto K.E=2835J\)
Answer:
KE=2,835J
Explanation:
KE=1/2mv²
given :
m=70kg
v=9m/s
KE=1/2(70)(9)²
KE=2,835J
. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth
A. The weight of the mass on the earth is 117.6 N
A. The weight of the mass on the moon is 19.56 N
How do i determine the weight of the mass?Weight is defined as follow:
Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Now we shall determine the weight. Details below:
A. Weight on earth
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Weight on earth (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 9.8
Weight on earth = 117.6 N
B. Weight on moon
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Acceleration due to gravity on moon (g) = (1/6) × 9.8 = 1.63 m/s² Weight on moon (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 1.63
Weight on moon = 19.56 N
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Complete question:
The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon
What is the term that describes waves that require a medium through which to travel?
Answer:
Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.
What is the runner’s speed when he runs 100 meters in 14.1 seconds?
Answer:
7.09
Explanation:
What is the equation used to find the angle of refraction? Identify each variable. (1 point)
Answer:
pictures please
Explanation:
I need a picture so I can tell you
how many legs a cow has
Ite
Ite
A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000
kilometers (km). In this model, which planet would have a diameter of approximately 12
cm? (1 point)
le
Iter
o Jupiter
o Mars
0 Saturn
o Earth
Answer:
12 cm * 10^4 km / cm = 1.2 * 10^5 km
Published diameter of Saturn = 1.206 * 10^5 km
A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km). In this model, then the planet which have a diameter of approximately 12 centimeters would be Saturn, therefore the correct answer is option C.
What is the scale factor?It is defined as the multiplication factor used for the design of an object with respect to some other object. the scale is generally used to design prototype designs of large objects. It is also used in interior design planning rooms.
It is multiplied by the design dimension to get the actual size of the object or product.
As given in the problem a student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km).
1 centimeter = 10,000 kilometers
12 centimeter = 1.2 ×10⁵ kilometers
Saturn has an approximate diameter of 1.2 ×10⁵ kilometers.
Thus, the correct answer is option C.
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(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire
From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is 6.4 * 10^7 .
What is Hookes law?According to Hooke's law, the force is directly proportional to the extension of the wire.
Given that;
F = Ke
F = 240N
e = 0.8 mm or 0.0008m
K = F/e
K = 240N/0.0008m
K = 3.0 * 10^5 N/m
Now;
Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3
= 6.4 * 10^7
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HELP!! 15 points!!!
Which statements describe a situation in which work is being done? Select three options.
A mover carries a box up a flight of stairs.
A mover carries a box across a room.
Wind blows against a steel table anchored to the ground.
Wind blows a pool chair across the yard.
A weightlifter lifts a barbell off the ground.
A weightlifter holds a barbell above the head.
Answer:
wind blows a pool chair across the yard
Explanation:
The question is asking about forces at work like air resistance wich is pushing the chair across the yard. Work is when a force pushes pulls so when air resistance is pushing the chair because of the big surface area that is doing work.
Examine the image and assess the relationship of the atoms shown by
The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).
During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.
What is a change in chemistry?A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.
Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.
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Compare the magnitude of the centripetal acceleration of the car while moving from D to A, to the magnitude of the centripetal acceleration of the car while moving from B to C.
ANSWER:
Twice as great
STEP-BY-STEP EXPLANATION:
The centripetal acceleration is equal:
\(a=\frac{s^2}{r}\)We know that the velocity is constant, therefore, we calculate in both cases the magnitude of the centripetal acceleration:
\(\begin{gathered} \frac{20^2}{100}=\frac{20^2}{50} \\ 4=8 \\ r=\frac{8}{4}=2 \end{gathered}\)Therefore, the centripetal acceleration from D to A is twice the centripetal acceleration from B to C.
Tendons are, essentially, elastic cords stretched between two fixed ends; as such, they can support standing waves. These resonances can be undesirable. The Achilles tendon connects the heel with a muscle in the calf. A woman has a 20-cm long tendon with a cross-section area of 130 mm^2. The density of tendon tissue is 1100 kg/m^3.
Required:
For a reasonable tension of 600 , what will be the fundamental resonant frequency of her Achilles tendon?
Answer:
161.938 Hz
Explanation:
the computation of the fundamental resonant frequency is shown below
p = 1100 kg/m^3
A = 130 mm^2
= 130 ×10^-6 m^2
T = 600 N
L = 20 cm
= 0.2 m
Now the linear density of tendon is
= 1100 kg/m^3 × 130 ×10^-6
= 0.143 kg/m
Now the wave of the string is
= √600 ÷ √0.143
= 64.775 m/s
Now finally the fundamental resonant frequency is
= 64.775 ÷ (2 × 0.2)
=161.938 Hz
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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1. A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if
the penny falls straight down, with what speed would it hit the ground?
identify two reasons why the speed with which the penny
hits the ground may not be exactly what is calculated and predicted.
Answer:
9.8m/s
Explanation:
Answer: The speed 1934
laws of vector addition
Answer:
laws ig .
Explanation:
Convert an acceleration of 12m/s^2 to km/h^2
Answer:
43.2
because to convert from m/sec to kmph we need to multiply by 3600/1000
4. What light color passes through the atmosphere and retracts toward the moon?
A. Red
. B. Blue
C. Orange
D. Green
Answer:blue
Explanation:
The lift does work on the passengers.
A family and the lift have a total mass of 1050 kg.
The gravitational field strength is 10 N/kg.
The lift carries them up a distance of 15 m.
Calculate the work done by the lift.
Write down an assumption that you have made in doing this calculation
The work done by the lift with a mass of 1050 kg and a gravitational field strength is 10 N/kg and a height of 15m is 157.5kJ
The work done is the amount of work done in lifting the object to a certain distance. The work done is the product of mass, gravitational field, and height.
Work done = m×g×h
mass (m) = 1050 kg
g = 10 N/kg
height (h) = 15m
W = m×g×h
= 1050×10×15
= 157.5 kJ
Thus, the work done(W) = 157.5 kJ.
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