what isomers are possible for pt(cn)2(nh3)2 (where cn– is c-bonded)?

Answers

Answer 1

There are two possible isomers for the complex Pt(CN)₂(NH₃)₂ when CN– is C-bonded. These isomers are called cis and trans isomers.

1. Cis isomer: In this isomer, both CN– ligands and both NH₃ ligands are positioned adjacent to each other around the platinum (Pt) center. This arrangement results in a square planar geometry with a 90-degree angle between the similar ligands (CN– and NH₃).

2. Trans isomer: In this isomer, the CN– ligands and NH₃ ligands are positioned opposite each other around the platinum (Pt) center. This arrangement also results in a square planar geometry but with a 180-degree angle between the similar ligands (CN– and NH₃).

These two isomers have different properties due to their different spatial arrangements.

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Related Questions

The volcano remains at level 4, the second-highest level on the
country’s volcano-alert system, which means a hazardous eruption
could happen in hours or days. Scientists say the threat of a major
eruption remains high because PHIVOLCS has

Answers

It appears to be related to a volcanic activity alert system in a certain country. The statement mentions that a volcano is currently at level 4, which is the second-highest level on the country's volcano-alert system.

A volcano is a graphical representation of the relationship between the energy changes and reaction progress in a chemical reaction. It is commonly used to describe acid-base reactions, where the reactants and products have different acid-base properties.

The volcano plot is a graph with the reaction rate or activity of a catalyst on the y-axis and the reaction-free energy or potential on the x-axis. It is named after its shape, which resembles a volcano with a peak representing the maximum reaction rate or activity.

The position of a reactant or catalyst on the volcano plot determines its ability to promote the reaction. If it is to the left of the peak, the reaction is thermodynamically favorable but kinetically slow. If it is to the right of the peak, the reaction is kinetically favorable but thermodynamically less favorable.

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Help!! I’ll mark you Brainliest.!

Help!! Ill mark you Brainliest.!

Answers

Answer:

For 5 pts? gimme that

Explanation:

Answer:

Explanation:

if you know what those phrases mean, then you can look them up and draw those pictures you find, as well as add the definition of each.

An ion has 26 protons, 28 neutrons, and 24 electrons. Which element is this ion? a. Xe b. Ni c. Fe d. Mg e. Cr

Answers

The ion that has 26 protons, 28 neutrons, and 24 electrons is Iron (Fe) (option c).

An element can be determined by the number of protons in the nucleus of its atom. The number of protons present in an atom is referred to as the atomic number of the element.

This means that the number of protons in an atom is unique to a specific element.

Iron (Fe) has 26 protons in the nucleus of its atom.

Therefore, an ion with 26 protons is an ion of the element iron (Fe).

Magnesium (Mg) has 12 protons, Chromium (Cr) has 24 protons, Xenon (Xe) has 54 protons and Nickel (Ni) has 28 protons.

Thus, an ion which has 26 protons, 28 neutrons, and 24 electrons  is Fe (option c)

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Which of the following has the greatest mass?
Select one:
a.They all have the same mass.
b.One mole of gold.
c.One mole of mercury.
d.One mole of barium.

Answers

Answer:

I guess one mole. of mercury

Explanation:

because mercury is denser

The one that has the  greatest mass

c. One mole of mercury.

How to find the greatest mass

To determine which of the given options has the greatest mass, we need to compare the molar masses of the substances.

The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

The molar masses of the given substances are:

Gold (Au): 197.0 g/mol

Mercury (Hg): 200.6 g/mol

Barium (Ba): 137.3 g/mol

Comparing the molar masses, we can see that one mole of mercury (Hg) has the greatest mass among the options provided.

Therefore, the correct answer is:

c. One mole of mercury.

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explain what keeps the electrons confined in the space surrounding the nucleus

Answers

Answer:

Electrons are trapped inside the atom because of the attraction forces with positively charged protons that are found in the nucleus.

4. Perform the following calculations, and express the answer in the correct units and number of significant figures.

7.945 J + 82.3 J - 0.02 J


0.0012 m - 0.000 45 m - 0.000 11 m


500 g + 432 g + 2 g

Answers

90.225J

90.225J56.0012m

90.225J56.0012m934g

Calculation of the given expressions

7.945 J + 82.3 J - 0.02 J

The rule of BODMAS should be obeyed, thus

= (7.945 J + 82.3 J) - 0.02 J

= 90.245 J - 0.02 J

= 90.225J

0.0012 m - 0.000 45 m - 0.000 11 m

= 56.0012m

500 g + 432 g + 2 g

= 934g

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ASAP. Which pair of elements will form an ionic bond.

1. carbon and oxygen

2.carbon and chlorine

3.nitrogen and oxygen

4.barium and chlorine



PLEASE HELP!!!!!!!

Answers

4 because barium is ionic and chlorine is covelent

Which of the following groups is matched with a correct anatomical feature?
A) foraminifera→silicon-rich tests
B) dinoflagellata→holdfast
C) diatoms→tests made of cellulose
D) phaeophyta (brown algae)→
blade

Answers

Among the given options, the correct match between a group and its anatomical feature is: C) Diatoms → tests made of cellulose.

Diatoms are a type of algae belonging to the phylum Bacillariophyta. They are known for their intricate and delicate cell walls called tests or frustules. These tests are composed primarily of silica, making option A incorrect. Dinoflagellates (option B) are unicellular organisms that possess two flagella and do not have a holdfast. Phaeophyta, or brown algae (option D), have structures called blades that serve as their leaf-like photosynthetic organs. Hence, the correct match is diatoms having tests made of cellulose.

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how many more grams should be added​

how many more grams should be added

Answers

Answer:

50?

I think but not 100% sure if not lmk

Silicon has the same type of macromolecular structure as diamond.
(i) Explain why one atom of either element can form four covalent bonds.

Answers

Since each silicon atom shares its four outer electrons with another silicon atom, silicon has a massive covalent structure.

How big of a covalent structure is it?

Giant Covalent Structures is its name. Solids with enormous covalent structures have very high melting points. Strong covalent connections connect each of the atoms, which must be disrupted in order to melt the material. Examples include silicon dioxide, graphite (a form of carbon), and diamond.

At normal temperature, giant covalent compounds are solids and have extremely high melting and boiling temperatures. Due to the strength of covalent bonds, melting and boiling these massive structures requires a lot of energy.

It has a large number of silicon and oxygen atoms. The structure of its atoms is connected throughout.

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what type of chemical bond forms between two atoms bearing opposite charges?

Answers

Ionic bonds are created when two oppositely charged ions are attracted to one another by electrostatic force. A chemical element is uniquely defined by its atoms, which are tiny pieces of substance.

An atom is made up of a core nucleus and one or more negatively charged electrons that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present. Any elementary particle of matter with at least one proton is referred to as an atom. Examples of atoms are neon (N) and hydrogen (H) (Ne). Chemistry's fundamental building component is an atom. It is the lowest fraction of substance into which electrically charged particles cannot be released. It is also the smallest piece of substance with chemical element-like characteristics.

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What is the maximum number of electrons that can occupy any atomic orbital?

Answers

Answer:

only 2 electrons can be occupied in atomic orbital.

Aluminium is extracted from aluminium oxide. the formula mass of aluminium oxide is al2o3 the relative formula mass of aluminium oxide is 102 calculate the percentage of aluminium in aluminium oxide

Answers

The relative atomic mass of aluminium (Al) is 27, and the relative atomic mass of oxygen (O) is 16. Therefore, the relative formula mass of aluminium oxide (Al2O3) is:

(2 x 27) + (3 x 16) = 54 + 48 = 102

To calculate the percentage of aluminium in aluminium oxide, we need to determine the mass of the aluminium in the compound. Since there are two aluminium atoms in each molecule of aluminium oxide, the mass of the aluminium is:

(2 x 27) = 54

Therefore, the percentage of aluminium in aluminium oxide is:

(54 / 102) x 100% = 52.94%

So, the percentage of aluminium in aluminium oxide is approximately 52.94%.

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What are water turbines used for?

Answers

Answer:

A water turbine is used to convert the energy contained in water, potential energy or kinetic energy, into mechanical or electrical energy. There are two types of water turbines, the reaction water turbine, and the impulse water turbine.

Explanation:

Answer:

Water turbines are used to take energy whether it may be kinetic or potential from the water and convert that energy into mechanical, or electrical energy.

Explanation:

what is the molecular formula of zinc nitrate by criss cross method​

Answers

Explanation:

zinc nitrate

zn no3

valency :

2 -1

So, zn(no3)2

How many grams are in 6. 95X1024 molecules of SF6?

Answers

The grams are in the 6.95 × 10²⁴ molecules of the SF₆ is 0.0790 grams.

The number of the molecules of SF₆ =  6.95 × 10²⁴ molecules

The molar mass of the SF₆  = 146 g/mol

The one mole of the substance =  6.022 × 10²³ molecules

The number of the moles in the 6.95 × 10²⁴ molecules = 6.95 × 10²⁴ /  6.022 × 10²³

The number of the moles = 11.54 moles

The grams in the 11.54 moles = 11.54 / 146

                                                 = 0.0790 grams

Thus, the 0.0790 grams present in the 6.95 × 10²⁴ molecules of the SF₆ .

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why do smokers have a more difficult time getting rid of bronchitis
A. Their lungs shrink over time
B. They cough more than other people
C. Smoking damages the cilia in the respiratory system
D. Smokers are only able to access one lung

Answers

Answer:

C. Smoking damages the cilia in the respiratory system

Answer:

C. Smoking damages the cilia in the respiratory system.

Explanation:

Hope this helped.

Which of the following solutes, dissolved in 1000 g of water, would provide the greatest number of particles?A) 0.030 mol of urea, CO(NH2)2B) 0.030 mol of acetic acid, CH3COOHC) 0.030 mol of ammonium nitrate, NH4NO3D) 0.030 mol of calcium sulfate, CaSO4E) 0.030 mol of barium chloride, BaCl2

Answers

The solute that would provide the greatest number of particles when dissolved in 1000 g of water is ammonium nitrate (NH4NO3).

To determine which solute would provide the greatest number of particles when dissolved in 1000 g of water, we need to consider the dissociation or ionization of each compound.

A) Urea, CO(NH2)2: Urea does not dissociate or ionize in water. It remains as a single molecule. Therefore, it would provide only one particle.

B) Acetic acid, CH3COOH: Acetic acid partially dissociates into acetate ions (CH3COO-) and hydrogen ions (H+) in water. So, it would provide more than one particle.

C) Ammonium nitrate, NH4NO3: Ammonium nitrate dissociates into ammonium ions (NH4+) and nitrate ions (NO3-) in water. It would provide more than one particle.

D) Calcium sulfate, CaSO4: Calcium sulfate dissociates into calcium ions (Ca2+) and sulfate ions (SO42-) in water. It would provide more than one particle.

E) Barium chloride, BaCl2: Barium chloride dissociates into barium ions (Ba2+) and chloride ions (Cl-) in water. It would provide more than one particle.

From the given options, it is clear that options B, C, D, and E would provide more than one particle. Among these, the compound with the greatest number of particles would be the one that dissociates into the most ions.

Looking at the formulas, we can see that ammonium nitrate (NH4NO3) would dissociate into the most ions. It would provide a total of four particles: two ammonium ions (NH4+) and two nitrate ions (NO3-).

Therefore, the correct answer is:

C) 0.030 mol of ammonium nitrate, NH4NO3

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The liquid phase reaction A + B —r C occurs in an isothermal. continuously stirred batch reactor. Given that the initial concentration of A is 80 1nol.-"'1n3 and the initial concentration of B is 8'0 1nol.-"'1n3, what. is the reaction time needed to achieve 95% conversion of the limiting,T reactant" The reaction is first order in A and B and the second order rate constant is LOE-«i 1n3..-"'1nol..-"'s.

Answers

The reaction time needed to achieve 95% conversion of the limiting reactant is approximately 46.05 seconds.

To find the reaction time needed to achieve 95% conversion of the limiting reactant in an isothermal continuously stirred batch reactor, we need to use the first order rate equation:

ln(C₀/C) = kt

Where:
- C₀ is the initial concentration of the reactant
- C is the concentration of the reactant at a given time t
- k is the rate constant of the reaction
- t is the reaction time

In this case, the reaction is first order in both reactants, A and B. So, we need to consider the reactant with the lowest initial concentration as the limiting reactant.

Given:
Initial concentration of A (C₀,A) = 80 mol/L
Initial concentration of B (C₀,B) = 80 mol/L

Since both A and B are present in equal amounts initially, we can consider either A or B as the limiting reactant. Let's assume A is the limiting reactant.

To achieve 95% conversion of A, we need to find the concentration of A at that point, which is (5/100) times the initial concentration of A:
C = (5/100) * C₀,A

Now, substituting the values in the first order rate equation, we get:
ln(C₀,A/C) = k * t

Rearranging the equation, we have:
t = ln(C₀,A/C) / k

Substituting the values given in the problem:
C₀,A = 80 mol/L
C = (5/100) * C₀,A = (5/100) * 80 mol/L = 4 mol/L
k = 1E-3 L/mol/s

Calculating the reaction time:
t = ln(80/4) / (1E-3)

Simplifying the expression:
t = ln(20) / (1E-3)

Using a calculator, we find:
t ≈ 46.05 s

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what is the difference between condensation and accretion? both describe a process by which particles grow atom by atom, but accretion happens at cold temperatures while condensation occurs at hot temperatures. both describe a process by which particles grow atom by atom, but accretion happens at hot temperatures while condensation occurs at cold temperatures. condensation is the sticking together of solid particles, while during accretion, particles grow an atom or molecule at a time. during condensation, particles grow an atom or molecule at a time, while accretion is the sticking together of solid particles. need help?

Answers

Condensation is a process of conversion of the gaseous phase into liquid phase whereas accretion is a process of accumulation of small particles into larger ones over a period of time.

Condensation is the process by which water vapor in the air is changed into liquid water it's generally the opposite of evaporation. Condensation is crucial to the water cycle because it is responsible for the formation of clouds.

Accretion is the accumulation of smaller particles into a massive object by gravitationally pulling more matter towards itself, typically gaseous matter, in an accretion process. Most astronomical objects, such as galaxies, stars, and planets, are formed by the same accretion processes itself.

Accretion from natural causes, that  adds soil, sand, and also other types of earth to the part of a person's property that generally borders water. While this occurs very slowly, a piece of property may grow a lot overtime and also may increase its value.

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Oxygen is packaged in cylinders for medical use. A “D” cylinder contains 3.00L of O2 at 137atm of pressure. If the cylinder is left open what will the volume of O2 in the cylinder be? SHOW WORK!!

Answers

The volume of the cylinder is 411 L

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as-

                         PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Initial volume = 3 L

Initial pressure = 137 atm

Final pressure = atmospheric pressure = 1 atm

P₁V₁ = P₂V₂

137 × 3 = 1 × V₂

V₂ = 411 L

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Non-ferrous metal is NOT hardenable by heat treatment; it must
gain strength through a process such as tempering. Is this
statement TRUE or FALSE?
Group of answer choices
True
False

Answers

The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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Plzzzz helppp this submits in 5 minutes plzzzzz helpppp meeeee



List five predictions of climate change and the effects on earth by the year 2100




Answers

Answer:

Predictions:

1. Half of the world will be cold and the other half will be hot, which will cause unbalanced state of climate on Earth.

2. The whole world will start to get hotter and there will be no winters or rain which causes water shortage, unable to grow crops. Polar ice is melting is an example.

3. Floods can come, because water level in sea is rising and it could kill all of us.

4. Earthquake can occur because in the Bible Jesus tells about earthquakes, etc at the second coming of Jesus.

Explanation:

1. personal connections describe your reaction to the events in act i. why might you want to continue reading? explain.

Answers

Readers may want to continue reading a work if they are intrigued by the characters, interested in the plot, or invested in the themes and messages presented.

Why will a reader continue reading?

In general, act sets the stage for the rest of the work, introducing key characters, establishing conflicts, and setting the tone and mood.

If a reader finds these elements compelling or engaging, they may be motivated to continue reading to see how the story unfolds and how the characters develop. Additionally, Act I may introduce questions or mysteries that pique the reader's curiosity and encourage them to keep reading to find the answers.

Thus, a reader may want to continue reading a work if they are in interested in the plot.

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4. What is free energy?

Answers

Answer:

A thermodynamic quantity equivalent to the capacity of a system to do work.

Explanation:

Please help and answer this

Please help and answer this

Answers

According to the observations, work of scientist uses evidence while work of an engineer uses a practical approach.

What are observations?

Observations are defined as a set of statements or facts which are recorded while conducting an experiment.Observations are made through sensing changes in the variables of the experiment.

It is specifically defined as an act of knowing or recording the changes in the variables of the experiment.Recording observations holds importance as recording observations avoid the experiment to be repeated over and over again.

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Fe +0₂--Fe₂O3
35. What type of reaction is given

Answers

synthesis because the elements all come together

How many grams of au(iii) nitrate must be weighed in order to obtain exactly 3.00 grams of gold atoms?

Answers

Therefore, you would need to weigh approximately 5.16 grams of Au(III) nitrate to obtain exactly 3.00 grams of gold atoms.

To calculate the grams of Au(III) nitrate needed to obtain 3.00 grams of gold atoms, you'll need to consider the molar mass and stoichiometry.

First, find the molar mass of Au(III) nitrate (Au(NO3)3) by adding the atomic masses of each element:

Au (197 g/mol) + 3x N (14 g/mol) + 9x O (16 g/mol)

= 339 g/mol.

Next, determine the ratio of gold atoms to Au(III) nitrate in the balanced chemical equation. In this case, it's 1:1.

Now, divide the molar mass of Au(III) nitrate by the molar mass of gold atoms (197 g/mol) to get the ratio of grams of Au(III) nitrate to grams of gold atoms:

339 g/mol ÷ 197 g/mol = 1.72 g/mol.

Finally, multiply the ratio by the desired amount of gold atoms (3.00 g) to find the grams of Au(III) nitrate needed:

1.72 g/mol x 3.00 g = 5.16 grams.

Therefore, you would need to weigh approximately 5.16 grams of Au(III) nitrate to obtain exactly 3.00 grams of gold atoms.

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Four aluminum samples are each reacted with separate 1 m copper sulfate solution under the same conditions of temperature and pressure. Which aluminum sample would react most rapidly? Pellets, gram, powder, or ribbon

Answers

The aluminium sample that would react most rapidly with the copper sulfate solution under the same conditions of temperature and pressure would be the powder.

Thus, the correct answer is the powder (C).

The powder hаs the lаrgest surfаce аreа аvаilаble for reаction, аllowing for more collisions between the аluminum аtoms аnd the copper sulfаte solution. The copper sulfаte is аn inorgаnic compound thаt combines sulfur with copper. The greаter the surfаce аreа, the fаster the reаction rаte. Therefore, the powder would reаct most rаpidly compаred to the pellets, grаm, or ribbon.

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Mercury melts at -39°C and boils at 356.9°C. What is its state at -20°C?

Answers

Answer:

At -20°C the mercury state will be liquid

Explanation:

The melting point of a substance is the temperature at which it changes from solid state to a liquid state, and the boiling point is the temperature at which it changes from liquid state to a gaseous state.

If mercury melts at -39°C and boils at 356.9°C, it means that if the temperature is lower than -39°C, mercury will remain al solid state. Between -39°C and 356.9°C, the state of mercury will be liquid and, above 356.9°C mercury will remain at gaseous state.

So, at -20°C the mercury state will be liquid, because that temperature it is between -39°C and 356.9°C.

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Skip drove 55.6 miles on Saturday, and 42 1/2 miles on Sunday. How many miles did he drive during the entire weekend? what two numbers does square root 128 lie between Johnson-Nyquist noise is typically a problem in very low voltage circuits. The output of such a low voltage circuit must then be amplified to be measured, yet the noise also gets amplified too. The amplified noise compromises our measurements of the signal. Lets assume that the resistance in that low power circuit cannot be changed.And, of course, the bandwidth of the circuit cannot be changed either as the circuit must meet the requirements of the problem being solved. By examining the J-N equation, what is the ONLY way we could reduce (to, say a 10th of the amount) of noise in the low voltage circuit? E and F are supplementary. If mE = (9x 38) and mF = (2x + 42), find mF. * research designs are classified into three traditional categories: exploratory, descriptive, and causal. explain each type of these traditional research designs and list one example of each. Find the value of x or y so that the line passing through the two points has the given slope16. (-3, y), (-9, -2); m = 1 What element of music does drum play? Complete LineCountAnalyzer. Java:Screenshots of code:* LineCountAnalyzer: this class maintains a count of the number * of lines of text. Only lines of length>0 are counted. Publipublic String getReportstr() { return null;Copyable code:/** LineCountAnalyzer: this class maintains a count of the number* of lines of text. Only lines of length>0 are counted. */public class LineCountAnalyzer implements TextAnalyzer {//TODO1: write the rest of this class. 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In mid-August 2002, the multinational communications and life sciences company, formerly a part of Hewlett-Packard Co., said problems with the ERP components in Oracle's e-Business Suite 11e software froze production for the equivalent of a week, leading to the massive losses. The Oracle system handles about half of the company's worldwide production of test, measurement, and monitoring products and almost all of its financial operations, as well as functions such as order handling and shipping. Agilent was in the process of migrating as many as 2,200 legacy applications that it inherited from HP to Oracle. As part of the switchover, approximately 6,000 orders in the internally developed legacy systems had to be converted to an Oracle-friendly format, an Agilent spokeswoman said from company headquarters in Palo Alto, California. She said the configuration process had problems requiring correction. In a statement last week, Agilent President and CEO Ned Barnholt said the disruptions to the business after implementing the ERP system were "more extensive than we expected." An Agilent spokeswoman said the issue wasn't the quality of the Oracle application, but rather the "very complex nature of the enterprise resource planning implementation." For its part, Oracle Corp. said it's working closely with Agilent. "At Oracle, we are fully committed to all of our customers for the long haul and support them in any way necessary," the company said in a statement. "We have a strong relationship with Agilent, and both companies believe the implementation is stable." Agilent also had a takeaway lesson: "Enterprise resource planning implementations are a lot more than software packages," the company said in a statement. They are a fundamental transformation of a company's business processes. People, processes, policies, the company's culture are all factors that should be taken into consideration when implementing a major enterprise system." According to one analyst, ERP disasters are often caused by the user company itself. Joshua Greenbaum, an analyst at Enterprise Applications Consulting, said 99 percent of such rollout fiascoes are caused by "management's inability to spec out their own requirements and the implementer's inability to implement those specs." Russ Berrie and Co. After a three-year saga that included a $10.3 million financial hit from the failed installation of packaged applications, teddy bear maker Russ Berrie and Co. (www.russberrie.com) was taking another crack at replacing its legacy business systems. The Oakland, New Jersey-based distributor of toys and gifts finalized plans to roll out J. D. Edwards & Co.'s One World Xe suite of enterprise resource planning (ERP), customer relationship management, and financial applications. The multimillion-dollar project was scheduled to be done in phases over the next 18 months. Russ Berrie CIO Michael Saunders said that the company, which had sales of $225 million during the first nine months of 2001, hoped the One World System would help it reach $1 billion in annual revenue in the coming years. Within the next 12 months, he said, Russ Berrie planned to begin installing the applications one department at a time, starting with a stand-alone implementation in purchasing. "We're not going big bang." Saunders said. "We're mitigating implementation risks by taking a phased-in approach." The company had reason to be cautious. Three years before, a Y2K- related migration from its homegrown distribution, financial, and customer service systems to packaged ERP applications experienced major system failures. Saunders said the problems were severe enough for Russ Berrie to take many of the new applications off-line and return to their old systems. Saunders wouldn't identify the software vendors that were involved in the failed implementation, but sources said that SAP AG's applications were part of the 1999 project. A spokesman at SAP confirmed that Russ Berrie was one of its customers, but he declined to offer further details because of pending litigation between the two companies. Joshua Greenbaum of Enterprise Applications Consulting said it appeared that Russ Berrie "bit off more than they could chew" on the 1999 project. Companywide rollouts are especially risky for midsize businesses like Russ Berrie, Greenbaum said. Questions: 1. Suggest the business values of ERP systems for the two companies mentioned in the case? 2. What were the main reasons Agilent Technologies Inc. experienced failures in implementing the ERP systems? your going to need geogebra for the graphing so just search up geogebra and going to the ready for test part and just click on the classic one Please Help! History!! Will give brainliest and please don't get it off the internet!SHORT ANSWER RESPONSE In your opinion, was the United States, the USSR, or Cuba more to blame for the Cuban missile crisis? please help on #4it would help me if you show your work because I don't understand how to do this What are the 5 most important Bill of Rights? The table shows the data from a random sample of fish that are collected from and then released into a lake. Type of Fish Bass Eel GarNumber of Fish 92 56 52How many bass are estimated to be present if a sample of 1,000 fish are collected in the lake? Explain how you arrived at your solution. You have just graduated from MSU, and have landed a job with a starting salary of $75,000 per year. You have decided to bisy a house, and you have $10,000 saved up from your part-time job at Qdoba. The Eighth National Bank of DeWitt is offering to give you a 30 -year mortgage at 8.7% annual interest with monthly payments, but they will not give you a loan that will involve monthly payments of more than 25% of your income. Assuming you will borrow as much as you can from this bank, and assuming closing costs of 4% of the amount borrowed, what is the highest price you will be able to pay for the house? can anyone define lifeor define what is life?