What is the work done to slow a 1.8 x 10^5 kg train car from 60 m/s to 20 m/s? O-2.9 x 10^8 J O-1.3 x 10^3 J O 3.1 x 10^5 J O 6.1 x 10^4 J 2.9 x 10^6 J

Answer:

Because they don't have a telescope to magnify so close

Explanation:

Hope it works for you :)

Answer:

scientists can't see inside a atom because the atoms cant be seen by anything                      hope it help :)

Explanation:

Answer:

Respect the client’s decision

Explanation:

just took the test

Answer: Respect the client's decision

Explanation: Either way the professional would know not to do anything rash and it is the client's decision whether or not they want to move forward, it would have obviously been a touchy subject if they were that reluctant.

It's 1.44N

Explanation:

To calculate the acceleration you would do 1.97-0.53 which is 1.44N

The amount of the charge flowing through the terminals of the battery is found to be 0.084C.

The voltage of the battery is given to be 12 V and the capacitance of the capacitor is given to be 7 micro F.

As per the standard relations, the amount of the charge flowing through the terminal of the battery will be given by,

Q = CV

Where,

Q is the charge through the battery,

C is the capacitance of the capacitor,

V is the voltage of the battery.

Putting all the values,

Q = 12 x 7/1000

Q = 0.084 C.

So, the charge flowing is 0.084 C.

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Answer:Chuyển động đều là chuyển động có vận tốc không thay đổi theo thời gian

Explanation:

Answer:

P = 5880  J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

\(P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J\)

So, the required potential energy is equal to 5880  J.

Answer:

Because of its position or shape.

Answer:

I believe it is 13,419 joules.

Explanation:

I could be very wrong, please fact check me

Quotas are used by nations in international trade to control the amount of trade that occurs between them and other nations.

Governmental restrictions on the amount of a specific commodity that can be imported into a nation are known as import quotas. Such quotas are typically implemented to safeguard indigenous sectors and weaker producers.

Import quotas provide the advantage of maintaining domestic pricing, enabling domestic companies to capture a larger market share, and protecting emerging sectors. Its negative impact on efficiency is one drawback. Additionally, they do not generate revenue for the government and provide opportunity for corruption.

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So far, beyond the solar system, the extrasolar planets found have been mostly larger planets, similar in size to gas giants like Jupiter or Neptune.

These planets are easier to detect due to their greater mass and the effect they have on their host stars, making them more noticeable through various detection methods such as the transit method and radial velocity method. As technology advances, scientists are discovering more smaller, Earth-like extrasolar planets as well.

An exoplanet or extrasolar planet is a planet outside the Solar System. The first possible evidence of an exoplanet was noted in 1917 but was not recognized as such. The first confirmation of detection occurred in 1992. A different planet, initially detected in 1988, was confirmed in 2003. As of 1 May 2023, there are 5,366 confirmed exoplanets in 3,962 planetary systems, with 856 systems having more than one planet. The James Webb Space Telescope (JWST) is expected to discover more exoplanets, and also much more about exoplanets, including composition, environmental conditions and potential for life.

Therefor, beyond the solar system, the extrasolar planets found have been mostly larger planets, similar in size to gas giants like Jupiter or Neptune.

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The force of gravity between two magnets is really considerably smaller than the magnetic force, despite the fact that two magnets correctly aligned would attract and stay together firmly.

Any two mass-containing things in the cosmos are subject to the basic natural force of gravity. According to the formula F = G * m1 * m2 / r2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, the gravitational force between two objects varies in strength depending on their masses and the distance between them. The magnetic fields of two magnets are what create the force between them. Two magnets are aligned properly and it causes them to stick together tightly.

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In order to chill a 750mL bottle of champagne using a bucket of ice at 0 degrees Celsius, approximately 249 grams of ice must melt. The specific heat capacity of ice is approximately 2.09 J/g°C.

To determine the amount of ice that needs to melt, we can use the principles of thermodynamics. First, we need to calculate the heat lost by the champagne and the heat gained by the melting ice. The heat lost by the champagne can be calculated using the equation Q = mcΔT, where Q is the heat lost, m is the mass of the champagne, c is the specific heat capacity of champagne, and ΔT is the change in temperature. Similarly, the heat gained by the ice can be calculated using the same equation, where m is the mass of the ice and c is the specific heat capacity of ice.

Given that the initial temperature of the champagne is 25 degrees Celsius and the final temperature is 8 degrees Celsius, ΔT for the champagne is 25 - 8 = 17 degrees Celsius. The specific heat capacity of champagne is approximately the same as water, which is 4.18 J/g°C. Therefore, the heat lost by the champagne is Q = (750g)(4.18 J/g°C)(17°C) = 53,595 J.

Since the ice is at 0 degrees Celsius, ΔT for the ice is 0 - (-8) = 8 degrees Celsius. The specific heat capacity of ice is approximately 2.09 J/g°C. Therefore, the heat gained by the ice is equal to the heat lost by the champagne, which is 53,595 J. Using the equation Q = mcΔT and solving for the mass of ice (m), we can rearrange the equation to m = Q / (cΔT). Plugging in the values, we get m = 53,595 J / (2.09 J/g°C * 8°C) ≈ 249 grams.

Therefore, approximately 249 grams of ice must melt in order to chill the champagne from 25 degrees Celsius to 8 degrees Celsius in a bucket of ice at 0 degrees Celsius.

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Resistance  =  (voltage) divided by (current)

                                              =  (120 V)  /  (0.5 Amp)

                                              =          240 ohms .

Answer:

1.)When you arrive from school and you smell cookies baking in the kitchen your brain will tell you that you are hungry and that you should go to the kitchen at that point your sense organs like your nose helps you to detect that something is baking(cookies)and your nervous system (brain)will tell you that you are hungry and it will command/direct your brain to go to the kitchen then for you to eat the cookies and drink the milk the digestive system is going go help you to chew,swallow and digest the food which has been taken and when you also run to the kitchen at the beginning your brain will direct your skeletal and muscular system because the skeletons and muscles work hand in hand,and when you finish your meal the body will circulate some nutrients or minerals from the food or snack taken to other parts of the body for energy.

2.)When you sleep the whole body is asleep except the heart which needs to continue circulating blood around the whole system and sometimes the brain may not rest when you are sleeping it may continue to do it's work that's why some people usually sleep walk or sleep talk,it means the brain is not at rest and still doing some things....Thank you for the question I hope it is very useful to you.

Solve the given problem as

The actual things we are seeing if we see the bright flash of a meteor are a pea-sized particle and the surrounding air as the particle burns up in our atmosphere.

A meteor is a space rock that enters the atmosphere of the earth and produces a streak of light in the sky. Sometimes, people refer to them as shooting stars. When meteoroids enter the earth's atmosphere, they become meteors.

The night sky can be illuminated by meteors, also known as shooting stars, which are bits of space dust and debris that burn up in the Earth's atmosphere.

A pea-sized particle burns up in our atmosphere, and the surrounding air In other words, you do not see the particle itself, but only the effects it has on the surrounding air as it burns up.

Thus, we are seeing burned particles or dust when we see meteors.

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Answer:

Explanation: The pebble is taking up the space where the water was which will make the water go higher in the cylinder.

The acceleration of the bowling ball at the moment it is released from your hand is 15 m/s².

To calculate the acceleration, we will use Newton's second law of motion, which states that Force (F) equals mass (m) times acceleration (a). Mathematically, it is represented as:
F = m * a
We are given the force (F) as 300 N and the mass (m) as 20 kg. We need to find the acceleration (a). Rearranging the formula to solve for acceleration, we get:
a = F / m
Substituting the given values:
a = 300 N / 20 kg
a = 15 m/s²
When you apply a 300 N force to a 20 kg bowling ball, it will experience an acceleration of 15 m/s² at the moment it is released from your hand.

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Answer:

42,000 lbs

Explanation:

100 kg is 210 lbs.

200 x 210 lbs =

42,000 lbs

The weight of the car is product of its mass and acceleration due to gravity of earth. Hence, the weight of the 200 kg car is 1960 N.

The gravitational force of an object is the force by which attracts other objects into its center of mass. Earth attracts every objects into its center and that is why we are all standing on the ground.

The weight we experience on earth is  due to this gravitational force and it decreases when we move far from earth. The acceleration due to gravity is the acceleration by which an object accelerates downwards due to earth's gravity  (g).

Weight of an object  = mass × g

g for earth = 9.8 m/s²

mass of the car = 200 Kg.

then, weight = 200 kg × 9.8 m/s² = 1960 N.

Therefore, the weight of the car is 1960 N.

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Coronal polishing is a dental procedure used to remove plaque and calculus from teeth.Here are three things that can be damaged during coronal polishing:Teeth ,Gum tissue and Tooth enamel.

1. Enamel: Coronal polishing involves the use of an abrasive instrument to remove plaque and calculus from the teeth. If the instrument is used too harshly or too frequently, it can wear away the enamel on the teeth. This can lead to increased sensitivity, cavities, and an increased risk of tooth decay.

2. Gingiva: Coronal polishing can also damage the gingiva, or the soft tissue surrounding the teeth. If the instrument is used too harshly, it can cause gingival abrasion, which is the removal of healthy gum tissue. This can lead to increased gum sensitivity, as well as an increased risk of periodontal disease.

3. Tooth Structure: Coronal polishing can also damage the underlying tooth structure. If the instrument is used too aggressively, it can cause chips, fractures, and internal damage to the tooth. This can lead to pain, increased sensitivity, and an increased risk of tooth decay.

Coronal polishing is an important part of preventive dentistry, but it should be done properly to avoid any damage. It is best to consult a dentist before undergoing coronal polishing, as they can provide guidance on the best way to perform the procedure.

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Explanation:

because the molecules are closer together and more tightly bonded in solids

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Answer:

2.53m/s

Explanation:

Initial momentum in a system= Final momentum in a system

65kg*3m/s+12kg*0m/s=(65kg+12kg)*v

195kgm/s=77kg*v

v=2.53m/s

At  b Fx =0 of the labeled x-coordinates is the force on the marble zero.

As per the details share in the given figure,

Are as bellow,

At b x-coordinates is zero as,

A spherical or elliptical coordinate system known as the geographic coordinate system is used to measure and transmit positions on Earth as latitude and longitude. Of the many spatial reference systems in use, it is the most basic, traditional, and often utilized. It also serves as the foundation for the majority of other systems.

F = -dU/dx ,

Depending on whether F is lowest or maximal, v.

B is the regional minimum in the presented graph.

The slope of the provided curve's tangent at b is thus zero.

A line's slope, often known as its gradient, is a numerical representation of the line's elevation change and course.

so dv/dx =0

Therefore at b Fx =0

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Note:- The correct question would be as bellow,

A marble moves along the x-axis. The potential-energy function is shown in the figure below.

(a) At which of the labeled x-coordinates is the force on the marble zero?

abcd

Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

\(R_{t} = 341.7 \: \Omega\)

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

\( R' = R_{1} + R_{2} + R_{3} \)

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.  

Entonces:

\( R' = 3R \)

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)

\( R'' = \frac{3}{4}R \)

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)

Esta resistencia está ahora en paralelo con R₇, entonces:

\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)

\( R'''' = \frac{11}{15}R \)

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

\(V-i_{1}R-i_{3}R=0\) (1)

Malla 2

\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)

Malla 3

\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)

Recordemos tambien que:

\(i_{1}=i_{2}+i_{3}\) (4)

\(i_{2}=i_{4}+i_{5}\) (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

\(i_{1}=3/13\: A\)

\(i_{2}=4/65\: A\)

\(i_{3}=11/65\: A\)

\(i_{4}=1/65\: A\)

\(i_{5}=3/65\: A\)

Finalmente:

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Answer:

111dB

Explanation:

First, find the intensity of the sound using the formula I = Power / 4 x pi x radius ^2

So

60.0 / (4 x 3.14 (6.25)^2)

= 0.122

Then plug that into the equation to find sound level, which is 10log( I / Io)

Io being (1 x 10^-12)

So

10log(0.122 / 1 x 10^-12)

= 111dB

Hope this helps :)

The reason the charged balloon stuck to a wall is because the frictional force generated during the rubbing of the balloon against the blanket led to the buildup of static electricity on the surface of the balloon.

Olivia rubs an inflated balloon against a blanket and then "sticks" the balloon to the wall (neutral) where it stays without moving. The reason the charged balloon stuck to a wall is because the frictional force generated during the rubbing of the balloon against the blanket led to the buildup of static electricity on the surface of the balloon. As a result, the balloon becomes electrically charged and can be used to demonstrate basic principles of electrostatics.The charged balloon adheres to the wall because of the attraction between opposite charges. In this case, the wall may have a neutral or slightly charged surface, and when the charged balloon is brought near it, it induces an opposite charge on the wall. This attraction between the opposite charges allows the balloon to stick to the wall until the charge dissipates or is neutralized.

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