51 ml of 0.060 m naf is mixed with 17 ml of 0.15 m sr(no3)2. calculate the concentration of f- in the final solution. assume volumes can be added. (ksp for srf2 = 2.0×10-10) 0.00012 M 0.015 M 0.0075 M 0.038 M 0.045 M
Answers
The concentration of F- in the final solution is C) 0.038 M.
To find the concentration of F- in the final solution, we need to first calculate the moles of F- and SrF2 formed when the two solutions are mixed.
Moles of F- = (51 ml x 0.060 M) = 0.00306 moles
Moles of Sr(NO3)2 = (17 ml x 0.15 M) = 0.00255 moles
Since the molar ratio of F- to Sr(NO3)2 in the reaction is 2:1, the limiting reactant is Sr(NO3)2. Thus, all of the Sr(NO3)2 will react with 0.001275 moles of F- to form SrF2.
The equilibrium expression for the dissolution of SrF2 is: Ksp = [Sr2+][F-]2
Using the initial volumes and concentrations, we can calculate the initial moles of Sr2+:
Moles of Sr2+ = (17 ml x 0.15 M) = 0.00255 moles
At equilibrium, the concentration of F- will be equal to the concentration of the excess F- ions present in solution (i.e. the moles of F- not used in forming SrF2, divided by the total volume of the solution):
[F-] = (0.00306 - 0.001275)/(51 ml + 17 ml) = 0.038 M
Therefore, the concentration of F- in the final solution is 0.038 M.
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Related Questions
For each set below rank the bonds according to strength.A) Cl-Cl, I-I, Br-BrB) Si-F, Si-I, Si-Cl
Answers
For the first set, we can rank the bonds according to strength based on their bond dissociation energies (BDEs).Thus, the ranking from strongest to weakest is I-I, Br-Br, Cl-Cl.
For the second set, we can use a similar approach.Chlorine is in between. Thus, the ranking from strongest to weakest is Si-F, Si-Cl, Si-I.
A) In the first set, we have the halogens Cl-Cl, I-I, and Br-Br. The bond strength depends on the size of the atoms and the overlapping of their electron clouds. As we move down the periodic table, atomic size increases, resulting in weaker bond strength due to less overlap between electron clouds. So, the ranking of bond strength for set A would be as follows:
1. Cl-Cl (strongest)
2. Br-Br
3. I-I (weakest)
B) In the second set, we have Si-F, Si-I, and Si-Cl. In this case, bond strength is determined by the difference in electronegativity between silicon and the other atoms. The greater the electronegativity difference, the stronger the bond. The electronegativity values for silicon, fluorine, iodine, and chlorine are approximately 1.8, 3.98, 2.66, and 3.16, respectively. Based on these values, the ranking of bond strength for set B would be:
1. Si-F (strongest)
2. Si-Cl
3. Si-I (weakest)
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Physics is ______ about
how things move and why things move
Answers
Answer: Physics is about
how things move and why things move
Explanation:
What is the chemical name for Iridium(V) Oxide?
Answers
Answer: Iro2
Explanation:
Iro2 compound name
Iridium(IV) oxide
Names
Chemical formula IrO2
Molar mass 224.22 g/mol
Appearance blue-black solid
Density 11.66 g/cm3
27 more rows
The chemical name for Iridium(v) oxide is Ir02
In a galvanic cell, a spontaneous redox reaction occurs. However,the reactants are separated such that the transfer of electrons isforced to occur across a wire. The resulting electricity ismeasured in volts (\rm V) and is the sum of the potentials of the oxidation andreduction half-reactions:
{E^\circ}_{\rm cell} = {E^\circ}_{\rm ox} + {E^\circ}_{\rm red}
A table of standard reduction potentials gives{E^\circ}_{\rm red}values for common half-reactions.
Reduction half-reaction E(\rm V)
\rm Ag^+{(aq)}+e^- \rightarrow Ag{(s)} 0.80
\rm Cu^{2+}{(aq)}+2e^- \rightarrow Cu{(s)} 0.34
\rm Ni^{2+}{(aq)}+2e^- \rightarrow Ni{(s)} -0.26
\rm Fe^{2+}{(aq)}+2e^- \rightarrow Fe{(s)} -0.45
\rm Zn^{2+}{(aq)}+2e^- \rightarrow Zn{(s)} -0.76
By reversing any of these reduction half-reactions, you getthe corresponding oxidation half-reaction, for which{E^\circ}_{\rm ox}has the opposite sign of{E^\circ}_{\rm red}.
Part A
Calculate the standard potential for thefollowing galvanic cell:
\rm Ni (s)~ | ~ Ni^{2+}{(aq)}~ | ~Ag^{+}{(aq)}~ |~ Ag {(s)}
Express your answer numerically involts.
{E^\circ}_{\rm cell}= \rm V
Answers
The standard potential for the given galvanic cell is 1.06 V.
To calculate the standard potential for the galvanic cell Ni(s) | Ni2+(aq) | Ag+(aq) | Ag(s), you need to follow these steps:
1. Identify the oxidation and reduction half-reactions:
Ni(s) → Ni2+(aq) + 2e- (oxidation half-reaction)
Ag+(aq) + e- → Ag(s) (reduction half-reaction)
2. Find the standard reduction potentials (E°red) for each half-reaction from the table:
E°red(Ni2+ + 2e- → Ni(s)) = -0.26 V
E°red(Ag+ + e- → Ag(s)) = 0.80 V
3. Reverse the oxidation half-reaction and find its standard potential (E°ox) by changing the sign of E°red:
E°ox(Ni(s) → Ni2+(aq) + 2e-) = 0.26 V
4. Calculate the standard potential for the galvanic cell (E°cell) using the formula E°cell = E°ox + E°red:
E°cell = 0.26 V + 0.80 V
5. Obtain the final answer:
E°cell = 1.06 V
So, the standard potential for the given galvanic cell is 1.06 V.
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sodium atoms emit light with a wavelength of 330 nm when an electron moves from a 4p orbital to a 3s orbital. what is the energy difference between the orbitals in kj/mol
Answers
The energy difference between the orbitals can be calculated from bohr's model.
According to the bohr's model, the electrons are in continuous motion round the nucleus closed orbits of definite energy level. as the distance of the cell increases from the nucleus ,energy level of cell increases..as long as electron occupy a definite energy level, it doesn't radiate out energy. The emission of energy occurs only when electron jumps from one level to other.
E= h c/ λ
Sodium atom emit light with a wavelength of 330nm when an electron moves from a 4p orbital to a 3s orbital.
λ=330nm
h=6.625 .10-34 (Planck's constant)
c= 3.0 .108m/s-1
putting the values in the expression of Energy we get the energy difference.
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What are abiotic factors of the ecosystem
Answers
Answer:
Abiotic factors are the non-living components of the ecosystem, including its chemical and physical factors.
Hope this helps.
Answer:
Abiotic factors of ecoystem are non-living creatures present on ecosystem.
Can someone help me with these three questions? please
Answers
Answer:
23 43 45 43
Explanation:
20.00 mL of a 0.077 M solution of silver nitrate, AgNO3, is mixed with 30.00 mL of a 0.043 M solution of sodium acetate, NaC2H3O2. Does a precipitate form? The Ksp of AgC2H3O2 is 2.5*10^-3. Include the calculated ion product in answer.
Answers
Here's link\(^{}\) to the answer:
bit.\(^{}\)ly/3gVQKw3
The reaction between NH3 and O₂ produces 21.8 g of NO gas and some water. Determine the percent yield if the theoretical yield is 27.9 g of NO
gas. Please show your work on a scrap piece of paper.
128.0%
78.1 %
1.28 %
0.78%
Answers
So do 21.8g/27.9g = 0.78
Multiply by 100 to get a percent
0.78 x 100 = 78.1%
Lily replicates an experiment that found that the number of calories in a particular food is 50 kcal. She obtained data from
five trials: 50 kcal 72 kcal, 50 kcal, 12 kcal, and 50 kcal. Which best desribes her data results? A. accurate B. incorrect C. invalid D. precise
Answers
Answer:
invalid
Explanation:
Just imagine doing this experiment MULTIPLE TIMES and one of the trials you get 72 Kcal while in another u get 12kcal. It doesn't make sense. Somewhere in the experiment she went wrong. So its invalid
what is the mass of 3 moles of oxygen
Answers
the safety air bag in automobiles are inflated by nitrogen gas by the rapid decomposition of sodium azide:
Answers
sodium azide (NaN3) is used to inflate the safety airbags in automobiles (g) This airbag should be filled with N2 at a pressure of 1.15 atm and temperature of 26.0°C. It has a volume of 36 L.
Modern automobiles use numerous technical components and subsystems, each of which performs a specific design function. Some of these have thousands of individual pieces and were made possible by new or improved technologies, such as electronic computers, high-strength polymers, and novel alloys of steel and nonferrous metals. Air pollution, safety regulations, and global manufacturer competition, among other things, have all contributed to the development of some subsystems.
With an estimated 1.4 billion in use worldwide, passenger vehicles have become the main form of family transportation. In the United States, where more than three trillion miles (almost five trillion kilometers) are traveled annually, roughly one-fourth of these are located.
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How can a town stop beach erosion without causing erosion in other places?
Answers
Answer:
Present beach erosion prevention methods include sand dunes, vegetation, seawalls, sandbags, and sand fences. Based on the research conducted, it is evident that new ways to prevent erosion must be obtained. Each way that is currently used has extensive negative effects on beaches and their natural tendencies.
Explanation:
A student decides to conduct an investigation to determine the boiling points of water and ethanol. The student will heat samples of water and ethanol, and measure the temperature at which the samples boil. The student will conduct the investigation three times. Which aspect is missing from the experimental design?.
Answers
The aspect of the experiment that is missing from the experimental design for the determination of the boiling points of water and ethanol is deciding on the appropriate equipment.
The correct option is C.
What are experiments?Experiments are scientific procedures that are designed to test a hypothesis in order to prove or disprove the hypothesis.
Also, experiments are done to make discoveries as well as to repeat or confirm a fact.
In designing an experiment, the following components of the experimental design are necessary:
determining the proceduredetermining what data to collectdeciding on the appropriate equipmentdeciding on the number of trials to performFor example, in an experiment to determine the boiling points of water and ethanol, appropriate equipment such as a thermometer is needed.
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Complete question:
A student decides to conduct an investigation to determine the boiling points of water and ethanol. The student will heat samples of water and ethanol, and measure the temperature at which the samples boil. The student will conduct the investigation three times. Which aspect is missing from the experimental design?
determining the procedure
determining what data to collect
deciding on the appropriate equipment
deciding on the number of trials to perform
Electrical Bonding Evidence Quick Check
1. melting point, boiling point, surface tension, and vapor essence
2. deciding on appropriate equipment
3. mix ice with water until equilibrium is reached but some ice remains that is no longer melting
4. it ensures that results are accurate
5. the student should take the average of the results from all four trials
hope i helped ya muah xx
PLEASE HELP!!!!!!! (in a few minutes please)
Answers
B
Hope this helped you, have a good day bro cya)
Answer: Although metamorphic rocks typically form deep in the planet's crust, they are often exposed on the surface of the Earth.
Explanation:
what chest electrode is placed on the fifth intercostal space on the mid-clavicular line?
Answers
The chest electrode placed on the fifth intercostal space on the mid-clavicular line is known as the V4 electrode. V4 is part of the precordial electrodes used in a standard 12-lead electrocardiogram (ECG) to assess the electrical activity of the heart.
The placement of these electrodes is crucial for obtaining an accurate ECG, which helps healthcare professionals diagnose and monitor various cardiac conditions.
The V4 electrode is positioned on the left side of the chest in line with the middle of the clavicle (collarbone), at the level of the fifth intercostal space. To locate this space, one should palpate the ribcage and count down from the first rib until the fifth rib space is found. Proper electrode placement ensures that the ECG will accurately capture the electrical signals originating from the heart.
Other precordial electrodes, such as V1, V2, V3, V5, and V6, are also strategically placed on specific areas of the chest to obtain a comprehensive view of the heart's electrical activity. Collectively, the information from all 12 leads provides a detailed picture of the heart's functioning, assisting in the diagnosis of heart conditions and guiding treatment decisions.
In conclusion, the V4 electrode plays a vital role in electrocardiography, as its placement on the fifth intercostal space on the mid-clavicular line enables healthcare professionals to monitor the heart's electrical activity and make informed decisions about patient care.
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The solubility of sodium chloride decreases as temperature increases.
True
False
Answers
Yes the increase in temperature of sodium chloride will cause a decrease in it solubility.
Answer is True
Solubility of Sodium ChlorideSodium chloride is a type of salt whose solubility decreased with increased temperature, this is quite unusual to other solute.
With the case of Sodium Chloride, this principle is applied in purifications like re-crystallization which is used to recover solute in solvents
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WILL GIVE BRANILIEST!!!
Calculate the number of grams in 0.586 mole of each of the following substances?
a) Water, H2O.
= ___ g H2O
b) Glucose, C6H12O6, a sugar in grape juice and honey.
= ____ g C6H12O6
c) Methane, CH4.
= ____ g CH4
Answers
Answer:
Explanation:
H2O: 18.015 g/mol
0.586 mol H2O x 18.015 g/mol H2O x 1 mol H20 = 10.557 g H20
C6H12O6: 180.156 g/mol
0.586 mol C6H12O6 x 180.156 g/mol C6H12O6 x 1 mol = 105.571 g C6H12O6
CH4: 16.043 g/mol
0.586 mol CH4 x 16.043 g/mol x 1 mol CH4 = 9.401 g CH4
you've been considering what part of the united states to settle in after you complete your degree. you just learned about radon-222. which of these areas you are considering would expose you to the highest concentration?
Answers
To determine which area you should settle in after completing your degree, you should consider the average concentrations of Radon-222 in each of the areas you are considering. Radon-222 is a naturally occurring, radioactive gas that is released from the ground and can have a large impact on human health if present in high enough concentrations. Generally, the highest average concentrations of Radon-222 in the United States are found in the Appalachian region, especially in the states of Pennsylvania, West Virginia, Maryland, and parts of Virginia and New York. Therefore, settling in one of these areas would expose you to the highest concentrations of Radon-222.
As per the given statement, "You've been considering what part of the United States to settle in after you complete your degree. You just learned about radon-222.
Which of these areas you are considering would expose you to the highest concentration?
"If someone is thinking of settling in the United States after completing their studies and is concerned about exposure to radon-222, the area that would expose them to the highest concentration would be the area with the most uranium-rich soil.
What is radon-222?
Radon-222 is a radioactive gas that is colorless, tasteless, and odorless. Radon-222 is one of the primary decay products of radium-226, which is formed by the decay of uranium-238. Radon-222, in turn, decays to form polonium-218 and other radioactive particles that can damage lung tissue. Therefore, the area with the most uranium-rich soil would expose an individual to the highest concentration of radon-222.
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Juanita learns that gray tree frogs and green tree frogs both live in the southern United States. The gray tree frogs live in forests and blend in with the bark on the trees. The green tree frogs blend in with the tall reeds and grasses of the wetland areas. Natural selection helps the gray tree frogs in the forests and the green tree frogs in wetlands.
What is natural selection?
Answers
Natural selection is a process where by more or less traits are evident in populations which help them to adapt, survive and reproduce in their environment.
Natural selection explained.Natural selection is the fundamental mechanism of evolution in biological populations. Natural selection is a process where by more or less traits are evident in populations which help them to adapt, survive and reproduce in their environment.
The major component of natural selection are.
Variation and this means that organisms in a population can have various genotypic or phenotypic variations.Selective pressure ; the environment exert selective pressure which can be biotic ( predation, competition) or abiotic which can be temperature and so on. The environment determine the selective pressure that will be advantageous or disadvantageous.Differential reproduction : organisms with advantageous reproductive traits will be able to survive reproductive stage and produce more organisms.Natural selection help organisms to adapt and survive in their environments.
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Consider the reaction: H2(g) + I2(g) 2HI(g) A reaction mixture in a 3.67 L flask at a certain temperature initially contains a mixture of 0.763 grams of H2 and 96.9 grams of I2. At equilibrium, the flask contains 90.4 grams if HI. Calculate the equilibrium constant for this reaction at this temperature. Show your work using an ICE table.
(a) This experiment is separated into parts I and II.
What are the [Fe3+] and [SCN- ] before mixing in each part?
Part A Part B
[Fe3+] = [Fe3+] =
[SCN-] = [SCN-] =
(b) Briefly, explain why the concentrations of the Fe3+ and SCNare different in the two parts of the experiment.
Answers
(a) Before mixing in each part:
Part A: [Fe3+] = 0 M, [SCN-] = 0.002 M
Part B: [Fe3+] = 0.002 M, [SCN-] = 0 M
(b) The concentrations of the Fe3+ and SCN are different in the two parts of the experiment because they are added in different steps.
(a)
Part A: Before mixing, there is no Fe3+ or SCN- present. The Fe3+ is added to the SCN- solution to initiate the reaction, so their initial concentrations are both 0 M.
Part B: Before mixing, Fe(NO3)3 is added to water to form a solution with [Fe3+] = 0.002 M. KSCN is then added, but it does not initially contain any SCN-, so [SCN-] = 0 M.
(b)
The concentrations of Fe3+ and SCN- are different in the two parts of the experiment because they are added in different steps.
In Part A, Fe3+ is added to a solution containing KSCN, so the initial concentration of SCN- is higher than that of Fe3+. In Part B, Fe3+ and KSCN are added separately to water, so their initial concentrations are not equal.To know more about initial concentrations click here:
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Read the following statements and answer: i. Ozone protects us from sun’s harmful radiations. ii. Ozone absorbs the UV radiations from the sun and breaks down to oxygen iii. Oxygen acts as a protective shield. a. Statement i and ii are correct, but iii is false. b. Statement i and ii are false, but iii is correct. c. Statement i is true, ii and iii are false. d. All are correct statements.
Answers
Answer:
d. all statements are correct
Explanation:
There are molecules of methane in 0.123 mol of methane (CH4)?
A. 0.615
B. 2.04 x 10^-25
C. 7.40 x 10^22
D. 2.46 x 10^-2
Answers
There are 7.405 × 10²² molecules in 0.123 moles of methane (option C).
How to calculate number of molecules?The number of molecules in a substance can be used by multiplying the number of moles by Avogadro's number as follows:
no of molecules = no of moles × Avogadro's number
Avogadro's number is the number of atoms present in 12 grams of isotopically pure carbon-12, being 6.02214076 × 10²³.
According to this question, methane has 0.123 moles. The number of molecules is as follows;
no of molecules = 0.123 × 6.02 × 10²³
no of molecules = 7.405 × 10²² molecules
Therefore, 7.405 × 10²² molecules is the number of molecules in 0.123 moles of methane.
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Calculate the unit cell edge length for an 81wt%Fe−19wt% V alloy. All of the vanadium is in solid solution, and, at room temperature the crystal structure for this alloy is BCC. Show all steps. What is the effect of increasing the temperature in this problem? (80 pts)
Answers
The temperature of the crystal is increased, the vibrations of the atoms will become greater, the atoms will have more energy and will move further from their equilibrium position
Given that the alloy is an 81 wt% Fe−19 wt% V alloy, and all vanadium is in solid solution. At room temperature, the crystal structure for this alloy is BCC.
We have to find the unit cell edge length, a and the effect of increasing the temperature.
To calculate the unit cell edge length for an 81 wt% Fe−19 wt% V alloy, we will use the formula;
For BCC, the number of atoms per unit cell (Z) = 2a^3/Z^3Where Z is the coordination number for a BCC lattice.
For BCC, Z= 8 (number of atoms in a unit cell).We know that the atomic weight of Fe and V is 55.85 g/mol and 50.94 g/mol respectively.
Atomic weight of the given alloy = 81 × 55.85 + 19 × 50.94 = 2967.74Atomic radius of Fe = 0.126 nm
Atomic radius of V = 0.134 nm
Now, Unit cell edge length a = 4/√3 × r
Where r = (rFe + rV) /2 = (0.126 + 0.134) / 2 = 0.130 nm
Hence a = 0.287 nm
At room temperature, the crystal structure for this alloy is BCC.
The effect of increasing temperature on this alloy is that it will expand. The lattice parameter will increase and the unit cell edge length will also increase.
When the temperature of the crystal is increased, the vibrations of the atoms will become greater, the atoms will have more energy and will move further from their equilibrium position. This increased movement will cause the lattice to expand, causing the unit cell edge length to increase.
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What are the products we get out of this
reaction? (check picture)
Answers
Explanation:
two compounds because element is the very smallest part of any mixture
Explain, in terms of the reaction rates, why the concentrations of the reactants and products remain constant in this system.
Answers
Explanation:
In a chemical reaction, the rates at which reactants are converted into products depend on various factors, including temperature, pressure, and concentration of the reactants. When the concentrations of reactants and products remain constant in a system, it typically indicates that the forward and reverse reaction rates are equal, resulting in a state of chemical equilibrium.
At equilibrium, the concentrations of reactants and products do not change over time, because the rates of the forward and reverse reactions are balanced. This occurs when the rate of the forward reaction, which converts reactants into products, is equal to the rate of the reverse reaction, which converts products back into reactants. As a result, the concentrations of both reactants and products remain constant.
The concept of Le Chatelier's principle can help explain why concentrations of reactants and products remain constant at equilibrium. According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the system will adjust in a way that opposes the change. For example, if the concentration of a reactant is increased, the system will shift towards the side with fewer moles of reactant in order to restore the equilibrium. Similarly, if the concentration of a product is increased, the system will shift towards the side with fewer moles of product.
As a result of these shifts, the rates of the forward and reverse reactions will be adjusted to restore equilibrium, and the concentrations of reactants and products will remain constant. If the concentration of a reactant or product decreases, the system will shift in the opposite direction to restore equilibrium. This dynamic balancing of the forward and reverse reaction rates is what allows the concentrations of reactants and products to remain constant at equilibrium in a closed system.
what would be the symptoms for an air-cooled condenser where the air leaving the condenser is hitting a barrier and recirculating?
Answers
One thing that would be the symptoms for an air-cooled condenser where the air leaving the condenser is hitting a barrier and recirculating is: that there is less heat transfer from the refrigerant to the surrounding environment. Hence this will cause heat to accumulate in the condenser, making the cooling system inefficient.
What is a condenser?A condenser is a heat transfer used in heat transfer systems to cool a gaseous component and condense it into a liquid condition. The latent heat is released by the material and redistributed to the surrounding environment as a result.
The condenser's function is to accept high-pressure gas from the compressor and convert it to liquid. It does this by heat transfer or the notion that heat always moves from a warmer to a colder substance.
The condenser coil, evaporator, expansion valve, and compressor are the components. Each is critical to the overall performance of your unit.
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Which statement accurately describes
the inner planets
Answers
Answer:
The inner planets are also called terrestrial planets.
Explanation:
Mg(s) + 2 HCl (aq) _MGCL2 (Aq) + H2 (g) the total pressure of gas collected over water is 740.0 mmhg and the temperature is 21.5 ‘c what is the pressures of hydrogen gas formed in mmhg?
Answers
The pressure of hydrogen gas formed is 720.8 mmHg.
What is Partial Pressure ?The pressure exerted by a (specified) component in a mixture of gases.
We have to understand one thing that the Hydrogen, which is collected over water, will be mixed with water vapor.
This means that the total pressure of the mixture will have two components.
the partial pressure of Hydrogenthe vapor pressure of water at 21.5 CThe vapor pressure of water at that temperature is approximately
19.231 mmHg.
This means that
\(\rm P_{total} = P_{hydrogen} + \; P_{water vapor}\)
740 = \(\rm P_{hydrogen}\) + 19.231
\(\rm P_{hydrogen}\) = 740-19.231
\(\rm P_{hydrogen}\) = 720.8 mmHg
Therefore the pressure of hydrogen gas formed is 720.8 mmHg.
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Explain how you would calculate the total change in bond energy for the reaction h2 cl2 -> 2hcl. how would you know if the reaction was endothermic or exothermic? state your answer in 3-5 sentences.
Answers
Subtract the bond energy of the products from the bond energy of the reactants to find the overall change in bond energy for the reaction H2(g) + Cl2(g) -> 2HCl(g).
Connection energy is the amount of energy needed to break a chemical bond. Reference tables include the bond energy values for each bond in the reactants and products.
The reaction is exothermic (release energy) if the bond energy of the products is larger than the bond energy of the reactants, and the difference indicates the quantity of energy released. If the product bond energy is smaller than the reactant bond energy, the reaction is endothermic (absorbs energy), and the difference denotes the quantity of energy absorbed.
As a result, if the computed total change in bond energy is negative, the reaction is exothermic; otherwise, it is endothermic.
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