Energy change is the conversion of the energy stored in reactants to products. In the reaction between hydrogen and iodine, the energy change is -7 kJ/mol. Thus, option D is correct.
What is total energy change?Total energy change is the conversion of the energy from a substance to another when the reactant undergoes modification to produce a product.
The reaction is given as,
H₂ + I₂ → 2HI
In the reaction, the bonds between H-H and I-I are broken to release energy that produces two H-I bonds as the product.
Given,
H-H bond = 436 kJ/mol
I-I bond = 151 kJ/mol
H-I bond = 297 kJ/mol
So, 436 kJ/mol + 151 kJ/mol - 2x297 kJ/mol = -7 kJ/mol
Therefore, -7 kJ/mol is the total energy change in the reaction involving hydrogen and iodine.
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If you had a jar of cream and shook it up does the jar weigh the same
Select all that apply. The last element in any period always has: the lowest atomic mass because it is a gas five electrons in the outermost energy level eight electrons in the outermost energy level the properties of a noble gas.
The closing element in any period usually has eight electrons within the outermost strength stage the houses of a noble gas.
An element is a substance that can't be damaged down into every other substance. There are approximately a hundred factors, each with its own kind of atom. the whole thing in the universe includes atoms of at least one or more factors. The periodic desk lists all of the recognized elements, grouping collectively people with comparable houses.
An element is an essential object that can't be without problems damaged into smaller pieces. In chemistry and physics, an element is a substance that can't be broken down by non-nuclear reactions. In computing and mathematics, an detail is a wonderful piece of a bigger machine or set. Carbon, oxygen, hydrogen, gold, silver, and iron are examples of factors. every element consists of just one atom shape.
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The last element in any period always has :
1.) Eight electrons in the outermost energy level,
2.) The properties of a noble gas.
An element is a substance that can not be damaged down into a simpler layout. They may be distinguished by means of a completely unique atomic range. The elements are organized via their atomic variety in the periodic table, which highlights elements with similar residences.
Carbon is the most important detail to existence. With out this detail, existence as we are aware of it might not exist. As yo u will see , carbon is the vital element in compounds essential for lifestyles.
Kinds of elements :
1.) The elements are categorized as metallic, non-metal, and metalloid.
2.) The intense left aspect factors inside the periodic desk are metals, as an example, sodium, calcium, caesium, and many others.
3) Elements on the right side are usually known as non-metals, carbon, chlorine, oxygen, and many others.
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Use the following information to answer numbers 20-22: Start with a 30M sucrose solution. Then you do a serial dilution by making 100 mL of a 1/10 dilution and repeat THREE more times. 20. Show the calculation for the first dilution. (1 pt) Answer: 21. Draw and label a diagram of the serial dilution with volumes and concentrations of the stock and dilution beakers. (2 pts) Answer: 22. Show your concentration calculations. (1 pt) Answer:
The concentrations for the second, third, and fourth dilutions would be 0.3M, 0.03M, and 0.003M, respectively.
In a serial dilution, a concentrated solution is successively diluted to obtain solutions with lower concentrations. In this case, starting with a 30M sucrose solution, a series of four 1/10 dilutions are performed. The first dilution involves making 100 mL of the 1/10 dilution. To answer question 20, the calculation for the first dilution needs to be shown. For question 21, a diagram of the serial dilution with labeled volumes and concentrations of the stock and dilution beakers needs to be drawn. Finally, for question 22, the concentration calculations for each dilution step need to be provided.
To calculate the first dilution, we need to determine the concentration of the resulting solution. Since it is a 1/10 dilution, the concentration would be 1/10 times the original concentration. Therefore, the concentration of the first dilution would be 30M / 10 = 3M.
For question 21, a diagram needs to be drawn to illustrate the serial dilution process. The diagram should include the stock solution with a volume of 30M, the first dilution beaker with a volume of 100 mL and a concentration of 3M, and labels indicating the volumes and concentrations at each step of the dilution process.
For question 22, the concentration calculations for each dilution step need to be provided. Starting with the first dilution at 3M, subsequent dilutions would be 1/10 of the previous concentration. Therefore, the concentrations for the second, third, and fourth dilutions would be 0.3M, 0.03M, and 0.003M, respectively.
Overall, these calculations and the diagram represent the process and concentrations involved in the serial dilution of the 30M sucrose solution.
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How many electrons in an atom can have n = 5, I = 3?
- 14
- 2
- 6
- 10
Answer: answer is 10
Explanation:
Which reaction would cause an increase in entropy?
Answer:
The other guy is completely wrong.
The answer is B.SO2CI2 (g) > SO2 (g)+CI2(g)
Explanation:
A P E X
mass , volume, and density are all properties of what
Answer: Physical properties
Explanation: Can be measured without changing a substance's chemical identity.
Which of the following correctly describes globalization? (1 point)
O Globalization is the increase in income inequality within developed countries.
O Globalization is the process of integration among individuals, businesses, and governments.
Globalization is the increase in the value of knowledge and information within an economy.
O Globalization is the process of decreasing per-unit costs with increasing production.
According to the context, globalization is the process of integration among individuals, businesses and governments.
What is globalization?It is a historical process of global integration in the economic, political, technological, social and cultural spheres.
It is characterized by a progressive integration and interaction between countries, people and institutions with the expansion of capitalism and democracy, and with values such as multiculturalism and diversity.
Therefore, we can conclude that according to the context, globalization is the process of integration among individuals, businesses and governments.
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How does warm water at the surface of the ocean
become colder?
Answer:
Explanation:
Heat energy always moves from hot to cold. The sunlight doesn't reach certain parts of the ocean due to it being so deep. The water above it absorbs it. So because this top water absorbs all the heat/energy, it is a lot warmer and is constantly transferring heat to the colder parts through kinetic energy. The warmer water has particles that have way more kinetic energy than the cold particles below it. And more kinetic energy means more movement, so that's why they transfer their heat to the colder particles.
I dont actually know if Im correct or not. Im just guessing based on what I know about physics.
BRAINLIEST AWARD!! Why is potassium nitrate a solute in a .3M potassium nitrate solution? Please explain:D
Answer:
In a .3M KNO3 solution, the KNO3 is dissolved in water. Water is the solvent and KNO3 is the solute, because the solute is what is dissolved. Also, all potassium compounds and nitrate compounds are soluble, so you know that KNO3 dissociates into K+ and NO3- in water.
Scientists hardly question scientific theories and test them
for validity.
Answer:
idk
Explanation:
Answer:
i would say because they normally have an opinion of their own, or know information on the subject alrady
vitamin d is formed in the skin and hydroxylated in two places before it is in its active form of 1,25-dihydroxy vitamin d. where does the second hydroxylation occur?
The second hydroxylation of vitamin D occurs primarily in the kidneys.
Vitamin D undergoes a two-step hydroxylation process to become its active form, 1,25-dihydroxy vitamin D (calcitriol). The first hydroxylation occurs in the liver, where vitamin D is converted to 25-hydroxy vitamin D (calcidiol). This is the major circulating form of vitamin D in the bloodstream.
After the initial hydroxylation in the liver, the second hydroxylation takes place primarily in the kidneys. Here, the enzyme 1-alpha-hydroxylase acts on 25-hydroxy vitamin D, converting it into the biologically active form, 1,25-dihydroxy vitamin D (calcitriol). This active form of vitamin D plays a crucial role in regulating calcium and phosphate metabolism, bone health, and overall immune function.
It is worth noting that certain other tissues and organs, such as the skin, intestines, and immune cells, also possess the capability to carry out the second hydroxylation to a lesser extent. However, the kidneys are the primary site for this conversion, contributing to the majority of the circulating active vitamin D in the body.
Overall, the second hydroxylation of vitamin D primarily occurs in the kidneys, where 25-hydroxy vitamin D is converted to 1,25-dihydroxy vitamin D, the biologically active form of vitamin D.
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at a certain temperature and pressure, 1 l of co2 gas weighs 1.15 g. what is the mass of 1 l of nh3 gas at the same temperature and pressure?
At a certain temperature and pressure, 1L of NH3 gas will have a mass of 0.066g.
At a certain temperature and pressure, 1L of CO2 gas weighs 1.15g. The mass of 1L of NH3 gas at the same temperature and pressure can be calculated using the Ideal Gas Law. This law states that PV = nRT, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles, R is the ideal gas constant, and T is the temperature of the gas.
To calculate the mass of 1L of NH3 gas, the number of moles of NH3 must first be calculated. The molecular weight of NH3 is 17.03 g/mol. Therefore, 1 mole of NH3 gas will have a mass of 17.03g. Since the volume of 1L of NH3 is also 1L, the number of moles of NH3 can be calculated using the Ideal Gas Law equation.
PV = nRT
n = PV/RT
Plugging in the values for P, V, R, and T (1.15g, 1L, 0.0821 atm L/mol K, and 298 K, respectively), the number of moles of NH3 can be calculated as:
n = 1.15g * 1L / (0.0821 atm L/mol K * 298 K) = 0.0039 mol
To calculate the mass of 1L of NH3 gas, the number of moles must be multiplied by the molecular weight of NH3.
Mass = 0.0039 mol * 17.03 g/mol = 0.066g
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james chadwick discovered this particle, which was the last of the subatomic particles to be characterized.
James chadwick discovered this particle neutron also neutrino called as is last of the subatomic particles to be characterized.
In 1932 james chadwick announced that the core also contained a new uncharged particle, which he called the neutron. neutron is also called neutrino he proved the existence of neutrons elementary particles devoid of any electrical charge. james chadwick was an English physicist who was awarded the 1935 Nobel prize in physics for his discovery of the neutron in 1932.
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Consider the reaction in chemical equilibrium.
COCl₂(g) <—> CO(g) + Cl₂(g)
Which is the correct equation for K?
O K= [COCI₂]²/[CO][Cl₂]
O K= [COCl₂]/[CO][Cl₂]
O K= [CO][Cl₂]/[CoCl₂]
O K= [CO][Cl₂]/[COCI₂]²
The equilibrium constant has a definite value for every reversible reaction at a particular temperature. However it varies with change in temperature and it is independent of the initial concentration of the reactants. Here the expression of K is [CO][Cl₂]/[CoCl₂]. The correct option is C.
The ratio of the product of the molar concentrations of the products to that of the reactants with each concentration term raised to a power equal to its coefficient in the balanced chemical equation is called the equilibrium constant.
Here the equilibrium constant for the reaction is:
K = [CO][Cl₂]/[CoCl₂]
Thus the correct option is C.
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the compound k3au(cn)6 is a potassium salt of a gold cyanide complex-ion that is key to the most commonly used leaching process during gold mining. what is the charge on the complex-ion? A. +3 B. 0 C. -3 D. -6 E. +1
The charge on the complex-ion in the compound K3Au(CN)6 is -3.
This is because each cyanide ion (CN-) has a charge of -1, and there are six of them. Additionally, the overall charge of the compound must be neutral since it is a salt, and potassium (K+) has a charge of +1, so there must be three potassium ions to balance out the charge of the complex-ion. Therefore, the correct answer is C. The compound K3Au(CN)6 is a potassium salt of a gold cyanide complex-ion. In this compound, the complex-ion is Au(CN)6^3-. The overall charge on the complex-ion is -3 (Option C). This negative charge is balanced by three potassium ions (K+), each having a charge of +1, resulting in a neutral compound.
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given that the mean relating atomic mass of chlorine gas is 35.5 and contains a mixture of two isotopes of mass number 35 and 37 . Calculate the ratio of each isotope in the naturally occurring element
The abundance of isotope 35 = 75%
The abundance of isotope 37 = 25%
Ratio isotope 35 : isotope 37 = 3 : 1
Further explanationGiven
Ar Cl = 35.5
Two isotopes of mass number 35 and 37
Required
The ratio of each isotope
Solution
If the abundance of isotope 35 is x%, then the abundance of isotope 37 is (100-x)%
35.5 = x%.35 + (100-x)%.37
35.5 = 0.35x+0.37(100-x)
35.5=0.35x-0.37x+37
0.02x=1.5
x=75
1SnO2 + 2H2 = 1Sn + 2 H2O. What is the theoretical yield of Sn that you
will produce if you start with 6.5 grams H2?
Answer: 193 grams
Explanation:
The gram-formula mass of elemental hydrogen is about 2 g/mol, meaning that if you consume 6.5 grams of elemental hydrogen, you will consume 6.5/2 = 3.25 moles.
This means that since for every 2 moles of hydrogen consumed, 1 mole of tin is produced, we need to find the mass of 3.25/2 = 1.625 moles of tin.
Since tin has an atomic mass of 118.71 g/mol, the theoretical yield of Sn is (118.71)(1.625) = 193 grams.
Using the provided data, determine the temperatures at which the following hypothetical reaction will be nonspontaneous under standard conditions
A + B ? 2C + D
?S°rxn = -490.1 J/K
?H°rxn = -156.8 kJ
A. at all temperatures below 312.5 °C
B. at no temperatures
C. at all temperatures above 312.5 °C
D. at all temperatures
E. at all temperatures below 46.9 °C
F. at all temperatures above 46.9 ° C
The temperatures at which the hypothetical reaction will be nonspontaneous under standard conditions are all temperatures above 312.5 °C.
To determine the temperatures at which the reaction will be nonspontaneous, we need to consider the Gibbs free energy change (ΔG) of the reaction. The relationship between ΔG, ΔH (enthalpy change), and ΔS (entropy change) is given by the equation ΔG = ΔH - TΔS, where T is the temperature in Kelvin.
In this case, we are given ΔS°rxn = -490.1 J/K and ΔH°rxn = -156.8 kJ. Since ΔS and ΔH are both negative, we can infer that the reaction is entropy decreasing and exothermic.
For a spontaneous reaction, ΔG must be negative. When ΔH is negative and ΔS is positive, the reaction will be spontaneous at all temperatures. However, in this case, both ΔH and ΔS are negative.
At high temperatures, the negative term -TΔS will become more significant and will dominate the equation. As a result, ΔG will become positive (nonspontaneous). Therefore, the reaction will be nonspontaneous at all temperatures above 312.5 °C.
The temperatures at which the hypothetical reaction will be nonspontaneous under standard conditions are all temperatures above 312.5 °C.
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If you have 144 moles of As , you need moles of NaOH use it all up
ANSWER
The number of moles of NaOH is 432 moles
EXPLANATION
Given information
\(2\text{ As + 6NaOH }\rightarrow\text{ 2Na}_3AS_{O3}+\text{ 3H}_2\)The number of moles of As = 144 moles
Let x represents the number of moles of NaOH
From the above reaction, you will see that 2 moles of As react with 6 moles of NaOH
The next step is to find the number of moles of NaOH using a stoichiometry ratio
\(\begin{gathered} 2\text{ moles of As }\rightarrow\text{ 6 moles of NaOH} \\ 144\text{ moles of As }\rightarrow\text{ x moles of NaOH} \\ \text{ Cross multiply} \\ 2\text{ }\times\text{ x = 6 }\times144 \\ 2x\text{ = 864} \\ \text{ Divide both sides by 2} \\ \frac{2x}{2}\text{ = }\frac{864}{2} \\ x\text{ = 432 moles} \end{gathered}\)Hence, the number of moles of NaOH is 432 moles
assuming all orbitals are in the same energy level, which type of orbital has the lowest energy
Assuming all orbitals are in the same energy level, the orbital with the lowest energy is the s orbital.
In the context of the electronic structure of atoms, orbitals are grouped into different energy levels, with each energy level containing one or more sublevels. The energy levels are labeled using the principal quantum number (n), with higher values of n corresponding to higher energy levels.
Within a given energy level, the s orbital is always the orbital with the lowest energy. This is because the s orbital has a spherical shape and is located at the center of the atom. It is shielded from the nuclear charge by the other electrons in the atom, resulting in a lower energy compared to other orbitals within the same energy level.
The p orbitals, on the other hand, have slightly higher energy than the s orbital within the same energy level. The p orbitals are dum bbell-shaped and are oriented along the x, y, and z axes. They have a higher energy due to their orientation and their closer proximity to the nucleus.
Similarly, the d and f orbitals, which exist in higher energy levels, have even higher energies compared to the s and p orbitals within their respective energy levels.
Therefore, if all the orbitals are in the same energy level, the s orbital will have the lowest energy among them.
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Which of the following are constitutional isomers of octane? Select all that apply.
A. 3-ethyl-2-methylpentane
B. 2-methylpropane
C. 2,2-dimethylpropane
D. 2,3,3-trimethylpentane
The correct options are A, C, and D.
The constitutional isomers of octane are: A. 3-ethyl-2-methylpentaneC. 2,2-dimethylpropaneD. 2,3,3-trimethylpentaneThe isomers of a molecule can have different physical and chemical properties from each other. Constitutional isomers, also known as structural isomers, are compounds that have the same molecular formula but differ in how their atoms are arranged.
They can have different physical properties, chemical properties, boiling points, and melting points. Octane has the molecular formula C8H18, which means it has eight carbon atoms and eighteen hydrogen atoms. The possible constitutional isomers of octane are numerous.
The four options given in the question as below: A. 3-ethyl-2-methylpentaneB. 2-methylpropaneC. 2,2-dimethylpropaneD. 2,3,3-trimethylpentaneOut of the given options, 3-ethyl-2-methylpentane, 2,2-dimethylpropane and 2,3,3-trimethylpentane are the constitutional isomers of octane. Therefore, the correct options are A, C, and D. Answer: A, C, and D
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The word "atom" comes from the Greek word
Answer:
1) atomos. 2) uncuttable.
Explanation:
none
copper has a density of 9g/mL. if 25 g of copper is placed in a dry 100 mL graduated cylinder, how many mL's of water are needed to fill the graduated cylinder to the 100 mL line?
The amount of water needed to fill the graduated cylinder to the 100 mL line would be 97.22 mL
Density problemThe density of a substance is mathematically given as:
Density = mass (in grams)/ volume (in liters)
In this case, the density of a copper that weighs 25 g is given as 9g/mL. Thus, the volume of the copper can be deduced.
volume = mass/density = 25/9 = 2.78 L
The volume of the copper is 2.78 L.
According to Archimedes's principle, a solid will always displace its own volume when dropped into a liquid.
Therefore, if the copper is placed in a 100 mL graduated cylinder, the amount of water needed to fill up the cylinder to the 100 mL mark would be:
100 - 2.78 = 97.22 mL
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in the rate law the exponents associated with the concentration of each reactant are referred to as the order of the reaction with respect to that reactant. why are we not able to use the stoichiometric coefficients in the balanced equation for the orders in the rate law?
A chemical reaction's rate and the concentrations of the reactants involved are correlated by an expression known as the rate law, commonly referred to as the rate equation.
In a rate law, what do the exponents stand for?The rate equation's "orders," the exponents a and b, must be established empirically. The exponents are added to determine the reaction's overall order. In other words, the reaction is third order overall if a=1 and b=2.
By adding together the different orders, the reaction's overall order can be determined. For instance, the overall order is 2 if the reaction is first order with regard to both A and B (a = 1 and b = 1). This is referred to as a global second order response.
Finding a Rate Law's Exponents from Initial Rates (Experimental Data)
The concentrations of all the species for which data are provided should be included in the rate law. ...Consider the experimental data's ratios for the various rates.Delete common phrases, then find the exponent that doesn't disappear.The molar concentrations of the reactants are used by the rate law to calculate the reaction rate. Because there are more molecules colliding and reacting with one another, reactions often proceed more quickly at higher reactant concentrations.
The exponents of a rate law's concentration terms are added to determine its order. The rate law of a reaction can be utilized to better understand the makeup of the reaction mixture once it has been established.
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2. A 20-year-old woman goes to the Emergency Department due to symptoms of palpitations, dizziness, sweating, and paresthesia that have not resolved over the past several days. Her history suggests an anxiety disorder, and blood gases and electrolytes are ordered. Her doctor prescribes a benzodiazepine after a positron emission tomography (PET) scan shows increased perfusion in the anterior end of each temporal lobe. Which of the following blood gases would be expected at the time of admission of this patient?
A. pH 7.51; Pa co: 49 mm Hg: [HCO3] = 38 mEq/L; Anion Gap - 12 mEq/L
B. pH 7.44; Pa co2-25 mm Hg; [HCO3] = 16 mEq/L; Anion Gap = 12 mEq/L
C. pH 7.28: Pa coz 60 mm Hg: [HCO3] =26 mEq/L; Anion Gap = 12 mEq/L
D. pH 7.28: Pa co2 20 mm Hg: [HCO3] = 16 mEq/L: Anion Gap = 25 mEq/L
E. pH 7.51: Pa co2 20 mm Hg: [HCO3] = 24 mEq/L; Anion Gap = 12 mEq/L
The expected blood gas values for this patient at the time of admission of patient is option E. pH 7.51; PaCO₂ = 20 mm Hg; [HCO₃]⁻ = 24 mEq/L; Anion Gap = 12 mEq/L
A 20-year-old woman presents to the Emergency Department with persistent symptoms of palpitations, dizziness, sweating, and paresthesia. She has a history suggestive of an anxiety disorder.
To assess her condition, blood gases and electrolytes are ordered, and a positron emission tomography (PET) scan is performed. The PET scan reveals increased perfusion in the anterior portion of each temporal lobe. Based on these findings, the doctor prescribes a benzodiazepine medication.
The expected blood gas values at the time of admission can be determined by analyzing the given options:
A. pH 7.51; PaCO₂ = 49 mm Hg; [HCO₃]⁻ = 38 mEq/L; Anion Gap = 12 mEq/L
B. pH 7.44; PaCO₂ = 25 mm Hg; [HCO₃]⁻ = 16 mEq/L; Anion Gap = 12 mEq/L
C. pH 7.28; PaCO₂ = 60 mm Hg; [HCO₃]⁻ = 26 mEq/L; Anion Gap = 12 mEq/L
D. pH 7.28; PaCO₂ = 20 mm Hg; [HCO₃]⁻ = 16 mEq/L; Anion Gap = 25 mEq/L
E. pH 7.51; PaCO₂ = 20 mm Hg; [HCO₃]⁻ = 24 mEq/L; Anion Gap = 12 mEq/L
By evaluating the options, the most appropriate choice is:
E. pH 7.51; PaCO₂ = 20 mm Hg; [HCO₃]⁻ = 24 mEq/L; Anion Gap = 12 mEq/L
This option presents a higher pH (alkalosis) and a decreased PaCO₂ (respiratory alkalosis), which could be consistent with the patient's symptoms of hyperventilation due to anxiety. The [HCO₃]⁻ level within the normal range and a normal anion gap further support this interpretation.
In summary, the expected blood gas values for this patient at the time of admission are a higher pH, decreased PaCO₂, normal [HCO₃]⁻, and a normal anion gap, indicative of respiratory alkalosis likely caused by hyperventilation related to her anxiety disorder.
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If 100 yards = 1 football field, what is the length, in meters, of 4.9
football fields?
Show that each of these conditional statements is a tautology by using truth tables. a) (p∧q)→p b) p→(p∨q) c) ¬p→(p→q) d) (p∧q)→(p→q) 10. Show that each of these conditional statements is a tautology by using truth tables. [p∧(p→q)]→q 22. Show that (p→q)∧(p→r) and p→(q∧r) are logically equivalent. 23. Show that (p→r)∧(q→r) and (p∨q)→r are logically equivalent. 24. Show that (p→q)∨(p→r) and p→(q∨r) are logically equivalent.
This means that they are true for all possible combinations of truth values for p, q, and r
a) (p∧q)→p
p | q | p∧q | p→p
-- | -- | -- | --
T | T | T | T
T | F | F | T
F | T | F | T
F | F | F | T
b) p→(p∨q)
p | q | p∨q | p→(p∨q)
-- | -- | -- | --
T | T | T | T
T | F | T | T
F | T | T | T
F | F | F | T
c) ¬p→(p→q)
p | ¬p | p→q | ¬p→(p→q)
-- | -- | -- | --
T | F | T | F
F | T | F | T
d) (p∧q)→(p→q)
p | q | p∧q | p→q | (p∧q)→(p→q)
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | T | T
F | T | F | T | T
F | F | F | T | T
10. [p∧(p→q)]→q
p | q | p→q | p∧(p→q) | [p∧(p→q)]→q
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | F | F
F | T | T | F | F
F | F | T | F | F
22. (p→q)∧(p→r) and p→(q∧r)
p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | F | T | F
T | F | F | T | F | T | F
F | T | T | T | T | T | T
F | T | F | T | T | T | F
F | F | T | T | F | T | F
F | F | F | T | F | T | F
23. (p→r)∧(q→r) and (p∨q)→r
p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
24. (p→q)∨(p→r) and p→(q∨r)
p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
As you can see, all of the conditional statements are tautologies.
This means that they are true for all possible combinations of truth values for p, q, and r
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a) (p∧q)→p is shown as a tautology by using truth tables
b) p→(p∨q) is shown as a tautology by using truth tables
c) ¬p→(p→q) is shown as a tautology by using truth tables
d) (p∧q)→(p→q) is shown as a tautology by using truth tables
How do we explain?This can be explained as meaning that they are true for all possible combinations of truth values for p, q, and r
a)
for (p∧q)→p
p | q | p∧q | p→p
-- | -- | -- | --
T | T | T | T
T | F | F | T
F | T | F | T
F | F | F | T
b)
p→(p∨q)
p | q | p∨q | p→(p∨q)
-- | -- | -- | --
T | T | T | T
T | F | T | T
F | T | T | T
F | F | F | T
c) ¬p→(p→q)
p | ¬p | p→q | ¬p→(p→q)
-- | -- | -- | --
T | F | T | F
F | T | F | T
d) (p∧q)→(p→q)
p | q | p∧q | p→q | (p∧q)→(p→q)
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | T | T
F | T | F | T | T
F | F | F | T | T
10. [p∧(p→q)]→q
p | q | p→q | p∧(p→q) | [p∧(p→q)]→q
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | F | F
F | T | T | F | F
F | F | T | F | F
22. (p→q)∧(p→r) and p→(q∧r)
p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | F | T | F
T | F | F | T | F | T | F
F | T | T | T | T | T | T
F | T | F | T | T | T | F
F | F | T | T | F | T | F
F | F | F | T | F | T | F
23.
for (p→r)∧(q→r) and (p∨q)→r
p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
24.
(p→q)∨(p→r) and p→(q∨r)
p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
In conclusion, we see that all of the conditional statements are tautologiesand that they are true for all possible combinations of truth values for p, q, and r
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A gaseous sample of a substance is cooled at constant pressure. Which diagram best represents the situation if the final temperature is above the boiling point of the substance? A. a B. b C. c D. d Which diagram best represents the situation if the final temperature is below the boiling point but above the freezing point of the substance? A. a B. b C. c D. d
The best diagram for the first situation is c) C, and for the second situation, it is b) B.
For the first question, the diagram that best represents the situation where a gaseous sample of a substance is cooled at constant pressure and the final temperature is above the boiling point of the substance is diagram C.
In this diagram, the substance remains in the gaseous phase throughout the cooling process, and the temperature decreases until it reaches a point where it is above the boiling point, but still below the point where it would condense into a liquid.
For the second question, the diagram that best represents the situation where the final temperature is below the boiling point but above the freezing point of the substance is diagram B.
In this diagram, the substance goes through a phase transition from a gas to a liquid as the temperature decreases to the point where it is below the boiling point.
Once it reaches this point, the substance remains in the liquid phase as the temperature continues to decrease until it reaches a point where it is above the freezing point, but still below the point where it would solidify.
In summary, the best diagram for the first situation is C, and for the second situation, it is B.
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The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M it takes _____ min for it to decrease to 0.055 M.
It takes approximately 22.7 minutes for the concentration of reactant to decrease from 0.085 M to 0.055 M.
The first-order reaction rate law is given by:
rate = k[A]
where [A] is the concentration of reactant, and k is the rate constant.
The integrated rate law for a first-order reaction is:
ln([A]t/[A]₀) = -kt
where [A]t is the concentration of a reactant at time t, [A]₀ is the initial concentration, k is the rate constant, and t is time.
If we rearrange this equation, we get:
t = (1/k) * ln([A]₀/[A]t)
We are given that the half-life of the reaction is 13 minutes. This means that when t = 13 min, [A]t = 0.5[A]₀.
Using this information, we can solve for the rate constant:
0.5[A]₀ = [A]₀ * e^(-k*13)
0.5 = e^(-k*13)
ln(0.5) = -k*13
k = ln(2)/13
k ≈ 0.0532 min^-1
Now we can use the rate constant to solve for the time required for the concentration of reactant to decrease from 0.085 M to 0.055 M:
t = (1/k) * ln([A]₀/[A]t)
t = (1/0.0532 min^-1) * ln(0.085 M / 0.055 M)
t ≈ 22.7 min
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How many moles are in 1 gram of potassium chloride
0.0134 moles.
Explanation:
We will use conversion factors to solve this problem.
Potassium chloride has the chemical formula KCl.
1 gram of KCl is written on the left side of the conversion factor equation.
KCl has a molar mass of 74.5513 g/mol. This is found by adding together the atomic mass of each element. This means that 1 mole of KCl = 74.5513 grams
The conversion factor will look like this. To solve the equation we start with what is on the left, 1 gram. 1 is multiplied by the number in the numerator, and divided by the number in the denominator. When 1 is divided by 74.5513 it equals .0134. The unit grams cancel giving us our final answer in moles.
I hope this satisfied your request. Feel free to ask any questions. I apologize, my handwriting is a bit messy.