Answer:
y = -x-2
Step-by-step explanation:
We are given a slope of -1 and the y intercept of -2
The slope intercept form of the equation for a line is
y = mx+b
where m is the slope and b is the y intercept
y = -1x +-2
y = -x-2
Answer:
y=-x -2
Step-by-step explanation:
Slope-intercept form is
y=mx+b
where m is the slope and b is the y-intercept
We know that the slope is -1. We also know that the y-intercept is (0, -2). For this form, we can disregard the 0, and say the y intercept is just -2.
So, m is -1, and b is -2. Substitute the values into the equation.
y=mx+b
y=-1x+-2
Simplify
y= -x -2
This is the equation of the line in slope-intercept form.
Which expression is equivalent to 36+18 ANSWERS choices are in the picture
Answer:
6(6+3)
Step-by-step explanation:
think of it like two separate pierces that work together so you multiple 6 time 6 and 6 times 3 and the addition sign remains where it is.
a circle has radius 13 centimeters. suppose an arc on the circle as length 6π centimeters. what is the measure of the central angle whose radii define the arc?
Therefore, the measure of the central angle whose radii define the given arc is approximately 83.077 degrees.
The length of an arc on a circle is given by the formula:
Arc Length = (Central Angle / 360°) * Circumference
In this case, we know the arc length is 6π centimeters, and the radius of the circle is 13 centimeters. The circumference of the circle can be calculated using the formula:
Circumference = 2π * Radius
Substituting the radius value, we get:
Circumference = 2π * 13
= 26π
Now we can use the arc length formula to find the central angle:
6π = (Central Angle / 360°) * 26π
Dividing both sides of the equation by 26π:
6π / 26π = Central Angle / 360°
Simplifying:
6 / 26 = Central Angle / 360°
Cross-multiplying:
360° * 6 = 26 * Central Angle
2160° = 26 * Central Angle
Dividing both sides by 26:
2160° / 26 = Central Angle
Approximately:
Central Angle ≈ 83.077°
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if a bank account pay a monthly interest rate on deposits of 0.5%, what is the apr the bank will quote for this account?
To determine the Annual Percentage Rate (APR) based on a monthly interest rate, you can use the following formula:
APR = (1 + monthly interest rate)^12 - 1
In this case, the monthly interest rate is 0.5% or 0.005 (decimal form). Plugging it into the formula, we have:
APR = (1 + 0.005)^12 - 1
Calculating this expression:
APR = (1.005)^12 - 1
APR = 1.061678 - 1
APR ≈ 0.061678 or 6.17% (rounded to two decimal places)
Therefore, the bank would quote an APR of approximately 6.17% for this account.
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Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria: 95% confidence, within 5 percentage points, and a previous estimate of 0.25 288.12 0/2 pts Question 16 Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria: 95% confidence, within 5 percentage points, and a previous estimate is not known 384
the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria is 384.12, which can be rounded up to 385.
The minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria is as follows:
95% confidence, within 5 percentage points, and a previous estimate of 0.25.
The formula to calculate the sample size required for the study to determine the proportion is given by:
`n = Z²pq / E²`
Where n = sample size
Z = z-value (1.96 at 95% confidence interval)
E = margin of error
p = estimated proportion of the population
q = 1 - pp
q = estimated proportion of population without the condition (1 - 0.25 = 0.75)
Given,
Z = 1.96E = 0.05p = 0.25q = 0.75
Substituting these values in the above formula, we get;
`n = (1.96)²(0.25)(0.75) / (0.05)²``n = 384.16`
Therefore, the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria is 384.12, which can be rounded up to 385.
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Find the distance from the point to the given plane.
(−9, 5, 7), x − 2y − 4z = 8
Find the distance from the point to the given plane.
(1, −6, 6), 3x + 2y + 6z = 5
The distance from the point (1, -6, 6) to the plane 3x + 2y + 6z = 5 is approximately 3.142857.
To find the distance from a point to a plane, we can use the formula for the perpendicular distance. Let's solve the given problems:
1. For the point (-9, 5, 7) and the plane x - 2y - 4z = 8:
The coefficients of x, y, and z in the equation represent the normal vector of the plane, which is (1, -2, -4).
Using the formula for distance, we have:
Distance = \(|(1 * -9 + (-2) * 5 + (-4) * 7 - 8)| \sqrt(1^2 + (-2)^2 + (-4)^2)\)
= \(|-9 - 10 - 28 - 8| \sqrt(1 + 4 + 16)\)
= \(|-55| \sqrt(21)\)
= \(55 \sqrt (21).\)
Therefore, the distance from the point (-9, 5, 7) to the plane x - 2y - 4z = 8 is \(55 \sqrt(21)\).
2. For the point (1, -6, 6) and the plane 3x + 2y + 6z = 5:
The coefficients of x, y, and z in the equation give us the normal vector, which is (3, 2, 6).
Applying the distance formula, we get:
Distance = \(|(3 * 1 + 2 * (-6) + 6 * 6 - 5)| \sqrt(3^2 + 2^2 + 6^2)\)
= \(|3 - 12 + 36 - 5| \sqrt(9 + 4 + 36)\)
= \(|22| \sqrt(49)\)
= 22 / 7
= 3.142857 (rounded to 6 decimal places).
Therefore, the distance from the point (1, -6, 6) to the plane 3x + 2y + 6z = 5 is approximately 3.142857.
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A teacher is buying supplies for an upcoming art project. She buys x bottles of paint for $1.29 each. She buys 8 more canvases than bottles paint for $1.89 each. Her total pretax cost is $37.38. How many of each item is she buying?
Answer:
She is buying 7 bottles and 15 canvases of paint
Step-by-step explanation:
Answer:
7 bottles of paint and 15 canvases
Step-by-step explanation:
I'm letting x stand for the number of bottles of paint and y stand for the number of canvases
1.29x+1.89y=37.38
and y=x+8
Since the y value is isolated I can just substitute the right side of the y= equation into the original like so
1.29x+1.89(x+8)=37.38
I then distributed the 1.89 to each of the terms in the parentheses
1.29x+1.89x+15.12=37.38
I then combined like terms to get
3.18x+15.12=37.38
Then you subtract 15.12 from both sides to get
3.18x=22.26
and last we divide both sides by 3.18 to get
x=7
Now that we have x, we still need to solve for y, so I take the original equation y=x+8 and substitute in the value we solved for x to get
y=7+8
y=15
Don't forget the labels you gave each variable earlier in the problem when answering!
find the local maximums and minimums of f(x, y) = sin(x) sin(y) for 0 x ⇡ and 0 y ⇡
The local maximums of f(x,y) = sin(x)sin(y) occur at (nπ, mπ) and the local minimums occur at (nπ + π/2, mπ + π/2), where n and m are integers.
Where do the local maximums and minimums of f(x,y) = sin(x)sin(y) occur?The given function f(x,y) = sin(x)sin(y) is a product of two periodic functions, each with a period of 2π. Hence, the function f(x,y) also has a periodicity of 2π in both x and y directions. To find the local maximums and minimums of the function, we need to look for points where the partial derivatives with respect to x and y are equal to zero.
Taking the partial derivative of f(x,y) with respect to x, we get cos(x)sin(y), which is equal to zero at points (nπ, mπ), where n and m are integers. Similarly, taking the partial derivative of f(x,y) with respect to y, we get cos(y)sin(x), which is also equal to zero at points (nπ, mπ). Therefore, the local maximums of f(x,y) occur at these points.
On the other hand, taking the partial derivative of f(x,y) with respect to x, we get cos(x)sin(y), which is equal to π/2 at points (nπ + π/2, mπ), where n and m are integers. Similarly, taking the partial derivative of f(x,y) with respect to y, we get cos(y)sin(x), which is equal to π/2 at points (nπ, mπ + π/2). Therefore, the local minimums of f(x,y) occur at these points.
In summary, the local maximums of f(x,y) = sin(x)sin(y) occur at (nπ, mπ) and the local minimums occur at (nπ + π/2, mπ + π/2), where n and m are integers.
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Find the solution of the differential equation dydx=y2 4 that satisfies the initial condition y(7)=0
The particular solution to the differential equation with the initial condition y(7) = 0 is:
(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x - 7.
To solve the given differential equation, we can use the method of separation of variables. Here's the step-by-step solution:
Step 1: Write the given differential equation in the form dy/dx = f(x, y).
In this case, dy/dx = y² - 4.
Step 2: Separate the variables by moving terms involving y to one side and terms involving x to the other side:
dy / (y² - 4) = dx.
Step 3: Integrate both sides of the equation:
∫ dy / (y² - 4) = ∫ dx.
Let's solve each integral separately:
For the left-hand side integral:
Let's express the denominator as the difference of squares: y² - 4 = (y - 2)(y + 2).
Using partial fractions, we can decompose the left-hand side integral:
1 / (y² - 4) = A / (y - 2) + B / (y + 2).
Multiply both sides by (y - 2)(y + 2):
1 = A(y + 2) + B(y - 2).
Expanding the equation:
1 = (A + B)y + 2A - 2B.
By equating the coefficients of the like terms on both sides:
A + B = 0, and
2A - 2B = 1.
Solving these equations simultaneously:
From the first equation, A = -B.
Substituting A = -B in the second equation:
2(-B) - 2B = 1,
-4B = 1,
B = -1/4.
Substituting the value of B in the first equation:
A + (-1/4) = 0,
A = 1/4.
Therefore, the decomposition of the left-hand side integral becomes:
1 / (y² - 4) = 1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2)).
Integrating both sides:
∫ (1 / (y² - 4)) dy = ∫ (1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2))) dy.
Integrating the right-hand side:
∫ (1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2))) dy
= (1/4) * ln|y - 2| - (1/4) * ln|y + 2| + C₁,
where C₁ is the constant of integration.
For the right-hand side integral:
∫ dx = x + C₂,
where C₂ is the constant of integration.
Combining the results:
(1/4) * ln|y - 2| - (1/4) * ln|y + 2| + C₁ = x + C₂.
Simplifying the equation:
(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x + (C₂ - C₁).
Combining the constants of integration:
C = C₂ - C₁, where C is a new constant.
Finally, we have the solution to the differential equation that satisfies the initial condition:
(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x + C.
To find the value of the constant C, we use the initial condition y(7) = 0:
(1/4) * ln|0 - 2| - (1/4) * ln|0 + 2| = 7 + C.
Simplifying the equation:
(1/4) * ln|-2| - (1/4) * ln|2| = 7 + C,
(1/4) * ln(2) - (1/4) * ln(2) = 7 + C,
0 = 7 + C,
C = -7.
Therefore, the differential equation with the initial condition y(7) = 0 has the following specific solution:
(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x - 7.
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if x is a discrete uniform random variable ranging from one to eight, find p(x < 6).
The probability that x is less than 6 is 5/8.
If x is a discrete uniform random variable ranging from one to eight, then each value from one to eight is equally likely to occur, and the probability of any particular value is 1/8.
To find p(x < 6), we need to add up the probabilities of all the values of x that are less than 6:
p(x < 6) = p(x = 1) + p(x = 2) + p(x = 3) + p(x = 4) + p(x = 5)
Since x is a discrete uniform random variable, the probability of each of these values is 1/8, so we can substitute that into the equation:
p(x < 6) = (1/8) + (1/8) + (1/8) + (1/8) + (1/8)
Simplifying, we get:
p(x < 6) = 5/8
Therefore, the probability that x is less than 6 is 5/8.
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20 POINTS
if you dont know the answer please dont answer
12x+24y=48
Answer:
x=2 y=1
Step-by-step explanation:
12 times 2 equals 24
24 time 1 equals 24
24+24=48
HELP DUE IN 10 MINS!
x =??
Answer:
x = 11
Step-by-step explanation:
Using Secants ad Segments Theorem we can say;
(x + 7) (7) = (15 + 6) (6)
7x + 49 = (21) (6)
7x + 49 = 126
7x = 77
x = 11
Hope this helps!
If f(x)= x³ + 7x²-x and g(x)=x²-3, what is the degree of g(f(x))?
•2
•3
•6
•8
g(x) = x^2 - 3
f(x) = x^3+7x^2-x
Start with the g(x) function. Replace every x with f(x)
g(x) = x^2 - 3
g(f(x)) = ( f(x) )^2 - 3
Then replace the f(x) on the right side with x^3+7x^2-x
g(f(x)) = (x^3+7x^2-x)^2 - 3
The highest term inside the parenthesis is x^3. Squaring this leads to (x^3)^2 = x^(3*2) = x^6
So the highest exponent found in g(f(x)) is 6, meaning the degree of is 6
Marian Plunket owns her own business and is considering an investment. if she undertakes the investment, it will pay $28,000 at the end of each of the new 3 years. the opportunity requires an initial investment of $7,000 plus an additional investment at the end of the second year of $35,000. what is the NPV of this opportunity if the interest rate is 8% per year? Should Marian take it?
The NPV is positive, it is worth taking the Investment.
Net Present Value (NPV) is an assessment method that determines the attractiveness of an investment. It is a technique that determines whether an investment has a positive or negative present value.
This method involves determining the future cash inflows and outflows and adjusting them to their present value. This helps determine the profitability of the investment, taking into account the time value of money and inflation.The formula for calculating NPV is:
NPV = Σ [CFt / (1 + r)t] – CIWhere CFt = the expected cash flow in period t, r = the discount rate, and CI = the initial investment.
The given problem can be solved by using the following steps:
Calculate the present value (PV) of the expected cash inflows:
Year 1: $28,000 / (1 + 0.08)¹ = $25,925.93Year 2: $28,000 / (1 + 0.08)² = $24,009.11Year 3: $28,000 / (1 + 0.08)³ = $22,173.78Total PV = $72,108.82
Calculate the PV of the initial investment: CI = $7,000 / (1 + 0.08)¹ + $35,000 / (1 + 0.08)²CI = $37,287.43Calculate the NPV by subtracting the initial investment from the total PV: NPV = $72,108.82 – $37,287.43 = $34,821.39
Since the NPV is positive, it is worth taking the investment.
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Tom wants to put up Christmas lights around his house.
His house is a rectangle which is 35m long and 15m wide.
How many metres of lights will Tom need to go all around his house?
Answer:
525 meters
Step-by-step explanation:
Tom needs 100 meters of lights to go all around his house if Tom wants to put up Christmas lights around his house.
What is a rectangle?It is defined as the two-dimensional geometry in which the angle between the adjacent sides is 90 degrees. It is a type of quadrilateral.
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
It is given that:
Tom wants to put up Christmas lights around his house.
His house is a rectangle that is 35m long and 15m wide.
To find the how many meters of lights will Tom need to go all around his house.
Find the perimeter of the rectangle:
The perimeter of the rectangle = 2(length + width)
Length = 35 m
Width = 15 m
The perimeter of the rectangle = 2(35 + 15)
The perimeter of the rectangle = 2(50)
The perimeter of the rectangle = 100
Thus, Tom needs 100 meters of lights to go all around his house if Tom wants to put up Christmas lights around his house.
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What is the slope of the line that contains the points (-3,-5/2), and (3, -8)?
Answer: need brainliest
Step-by-step explanation:
\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{-\frac{5}{2}})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{\left( -\frac{5}{2} \right)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}} \implies \cfrac{-8+\frac{5}{2}}{3+3}\implies \cfrac{~ \frac{ -16+5}{2 } ~}{6}\implies \cfrac{~ \frac{ -11}{ 2} ~}{6} \\\\\\ \cfrac{~ \frac{ -11}{ 2} ~}{\frac{6}{1}}\implies \cfrac{ -11}{ 2}\cdot \cfrac{1}{6}\implies -\cfrac{11}{12}\)
9.- Suma de fuerzas
4
45N + SON + 25N
4
4
127N 200N + 1250N
4
1
355N + 40N + 30N + 20N
Answer:
multiply
Step-by-step explanation:
2345567 in the subtract 578431111
Is 9.90 equal to greater than or less than 9.9
Answer:
Equal to.
Step-by-step explanation:
The 0 at the end of 9.90 does not add any value to the number because its 0.
Answer:
It is equal.
Step-by-step explanation:
9.90 = 9.9 , it's the same as the 0 does not count on it.
The original price of an iPad is $429. The sale price is 30% off the original price. What is the sale price of the iPad? Show your work.
Answer:
297.3
Step-by-step explanation:
30% of 429 is 128.7
429 which is the original price - 128.7 which is the price off = 297.3
Answer:
$300.30
Step-by-step explanation:
100% - 30% = 70%
429 * 0.70 = 300.30
Therefore the sale price of the ipad is $300.30!
Please mark brainliest and have a nice day!
The length of a rectangle is 2 Inches less than three times its width, and its perimeter is 36 Inches. Find the width of the
rectangle
Answer: Width = 5 inches
Concept:
Here, we need to know the idea of the perimeter.
A perimeter is a path that encompasses/surrounds/outlines a shape.
Perimeter of rectangle = 2 (w + l)
w = width
l = length
If you are still confused, please refer to the attachment below for a graphical explanation.
Solve:
w = w
l = 3w - 2
P = 36 inches
Given formula
P = 2 (w + l)
Substitute the value into the formula
36 = 2 (w + 3w - 2)
Simplify values in the parentheses
36 = 2 (4w -2)
Divide 2 on both sides
36 / 2 = 2 (4w - 2) / 2
18 = 4w - 2
Add 2 on both sides
18 + 2 = 4w - 2 + 2
20 = 4w
Divide 4 on both sides
20 / 4 = 4w / 4
w = 5
Hope this helps!! :)
Please let me know if you have any questions
BACK NEXT You're cooking a recipe that requires \frac{3}{5} 5 3 cup of flour, but you only want to make \frac{1}{3} 3 1 of the recipe. Which answer shows the correct amount of flour you need in the most reduced form? A \frac{1}{5} 5 1
Answer:
1/5
Step-by-step explanation:
1/3 of 3/5 is 1/5
The amount of flour you need is 1/5 cup.
what is the difference 2/5(d-10)-2/3(d+6)
The difference between 2/5(d-10)-2/3(d+6) is -56.
Firstly simplifying the terms to find the difference. Simplifying the first part -
Rewriting the expression
Expression 1 = 2/5(d - 10)
Multiplying the terms with the bracket
Expression 1 = 2d/5 - ((2×10)/5)
Multiplying the terms on Right Hand Side
Expression 1 = 2d/5 - 2×2
Performing multiplication
Expression 1 = 2d/5 - 4
Simplifying the second part -
Rewriting the expression
Expression 2 = 2/5(d + 6)
Multiplying the terms with the bracket
Expression 2 = 2d/5 + ((2×6)/5)
Multiplying the terms on Right Hand Side
Expression 2 = 2d/5 - 12×5
Performing multiplication
Expression 2 = 2d/5 - 60
Subtracting expression 2 from expression 1
Difference = 2d/5 - 60 - (2d/5 - 4)
2d/5 will be subtracted to give 0
Difference = - 60 + 4
Performing subtraction
Difference = - 56
Therefore, the difference between mentioned expressions is -56.
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an lti system has the frequency response function h(ω)=1/(jω 3). compute the output if the input is
The output of the LTI system with frequency response function \(h(w) = 1/(jw^3)\), given an input\(x(t)\), is:
\(y(t)\)= inverse Fourier transform of \([1/(jw^3) X(w)]\)
To compute the output of an LTI system with frequency response function \(h(w) = 1/(jw^3)\), given an input x(t), we can use the Fourier transform:
\(H(w)\) = Fourier transform of \(h(t)\)
\(X(w)\) = Fourier transform of \(x(t)\)
\(Y(w) = H(w) X(w)\)
\(Y(w)\) is the Fourier transform of the output \(y(t)\).
Using the given frequency response function, we have:
\(H(w) = 1/(jw^3)\)
Taking the Fourier transform of the input \(x(t)\), we have:
\(X(w)\) = Fourier transform of \(x(t)\)
And multiplying \(H(w)\) and\(X(w)\), we get:
\(Y(w) = H(w) X(w) = 1/(jw^3) X(w)\)
Taking the inverse Fourier transform of \(Y(w)\), we get the output \(y(t)\):
\(y(t)\) = inverse Fourier transform of \(Y(w)\)
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. given a sphere, a great circle of the sphere is a circle on the sphere whose diameter is also a diameter of the sphere. for a given positive integer n, the surface of a sphere is divided into several regions by n great circles, and each region is colored black or white. we say that a coloring is good if any two adjacent regions (that share an arc as boundary, not just a finite number of points) have different colors. find, with proof, all positive integers n such that in every good coloring with n great circles, the sum of the areas of the black regions is equal to the sum of the areas of the white regions.
The only positive integers n that satisfy the condition for every good coloring of a sphere with n great circles, where the sum of the areas of black regions is equal to the sum of the areas of white regions, are powers of 2.
Let's consider the case where n is not a power of 2. If n has an odd prime factor p, then the coloring of the sphere can be arranged in a way that creates a contradiction. We can divide the sphere into p equal parts using p great circles. In each part, we can color half of it black and the other half white. Since p is odd, we will have a larger number of black regions than white regions, leading to an imbalance in their areas.
On the other hand, if n is a power of 2, we can prove by induction that it satisfies the condition. For n = 2, we can divide the sphere into two equal hemispheres and color them differently. Now, assume that for some k, the condition holds for n = \(2^k\). To prove it for n = \(2^{(k+1)}\), we can take the sphere divided by \(2^k\) great circles and replicate it k times, creating a larger sphere divided by \(2^{(k+1)}\) great circles. By alternating the colors of the replicated regions, we ensure that adjacent regions have different colors, and the areas of black and white regions remain balanced.
Hence, the only positive integers n that satisfy the condition are powers of 2.
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A social scientist measures the number of minutes (per day) that a small hypothetical population of college students spends online. Student Score Student Score A 62 F 91 B 86 G 98 C 84 H 98 D 72 I 86 E 94 J 31
(a) What is the range of data in this population? min
(b) What is the IQR of data in this population? min
(c) What is the SIQR of data in this population? min
(d) What is the population variance?
(e) What is the population standard deviation? (Round your answer to two decimal places.) min
a) the range of data in this population is 67 minutes.b) The IQR of data in this population is 22 minutes.c)the SIQR of data in this population is 11 minutes.d) the population variance is approximately 323.52 minutes squared.e)the population standard deviation is approximately 17.99 minutes.
(a) To find the range of data, we subtract the minimum value from the maximum value.
Minimum value: 31 minutes
Maximum value: 98 minutes
Range = Maximum value - Minimum value
Range = 98 - 31
Range = 67 minutes
Therefore, the range of data in this population is 67 minutes.
(b) To find the interquartile range (IQR), we need to arrange the data in ascending order. The IQR is the difference between the upper quartile (Q3) and the lower quartile (Q1).
Arranging the data in ascending order:
31, 62, 72, 84, 86, 91, 94, 98, 98
Q1 = 72 minutes
Q3 = 94 minutes
IQR = Q3 - Q1
IQR = 94 - 72
IQR = 22 minutes
Therefore, the IQR of data in this population is 22 minutes.
(c) The semi-interquartile range (SIQR) is half the value of the interquartile range.
SIQR = IQR / 2
SIQR = 22 / 2
SIQR = 11 minutes
Therefore, the SIQR of data in this population is 11 minutes.
(d) To find the population variance, we use the formula:
Population Variance = (Σ(X - μ)^2) / N
where Σ represents the sum of, X represents each individual score, μ represents the mean, and N represents the number of scores.
First, we need to calculate the mean:
Mean = (62 + 86 + 84 + 72 + 94 + 91 + 98 + 98 + 86 + 31) / 10
Mean = 802 / 10
Mean = 80.2
Next, we calculate the sum of squared differences from the mean:
(62 - 80.2)^2 + (86 - 80.2)^2 + (84 - 80.2)^2 + (72 - 80.2)^2 + (94 - 80.2)^2 + (91 - 80.2)^2 + (98 - 80.2)^2 + (98 - 80.2)^2 + (86 - 80.2)^2 + (31 - 80.2)^2
= 3235.16
Population Variance = 3235.16 / 10
Population Variance ≈ 323.52
Therefore, the population variance is approximately 323.52 minutes squared.
(e) To find the population standard deviation, we take the square root of the population variance.
Population Standard Deviation = √(Population Variance)
Population Standard Deviation ≈ √(323.52)
Population Standard Deviation ≈ 17.99 minutes (rounded to two decimal places)
Therefore, the population standard deviation is approximately 17.99 minutes.
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Can anybody help me please?
Use double integrals to compute the area of the region in the first quadrant bounded by y=e x
and x=ln4. The area of the region is (Simplify your answer.)
The double integral can be used to compute the area of a region. Here's how to calculate the area of the region in the first quadrant bounded by y=e^x and x=ln 4 using double integrals.
We have to define our limits of integration: Now, we can integrate over these limits to obtain the area of the region Therefore, the area of the region in the first quadrant bounded by y=e^x and x=ln 4 is 3.
Here's how to calculate the area of the region in the first quadrant bounded by y=e^x and x=ln 4 using double integrals. Now, we can integrate over these limits to obtain the area of the region Therefore, the area of the region in the first quadrant bounded by y=e^x and x=ln 4 is 3.
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A side of a square is 2 inches. Using the area formula A = s determine the area of the square.
Answer:
A = 576 square inches
Step-by-step explanation:
s = 2⁴ inches
A (Area) = s²
A (Area) = (2⁴)²
A = 2^8
A = 576
the function f is defined by f(x)=e−x(x2 2x) . at what values of x does f have a relative maximum?
Answer:f
Step-by-step explanation:
its not that hard
The function is concave up for x < 1 and concave down for x > 1 because the second derivative is positive for x < 1 and negative for x > 1. As a result, the critical point at x < 1 is a relative maximum.
What is function?A function is an equation with just one solution for y for every x. A function produces exactly one output for each input of a certain type. Instead of y, it is common to call a function f(x) or g(x). f(2) indicates that we should discover our function's value when x equals 2. A function is an equation that depicts the connection between an input x and an output y, with precisely one output for each input. Another name for input is domain, while another one for output is range.
Here,
The derivative of the function f(x) can be found by taking the derivative of the expression e^(-x) (x^2 + 2x) using the product rule:
f'(x) = -e^(-x) (x^2 + 2x) + e^(-x) (2x + 2) = 2e^(-x) - 2xe^(-x) (x + 1)
Setting f'(x) equal to zero and solving for x gives us the critical points:
0 = 2e^(-x) - 2xe^(-x).(x + 1)
2xe^(-x).(x + 1) = 2e^(-x)
x(x + 1) = e^x
x^2 + x - e^x = 0
Next, we determine the concavity of the function at the critical points by analyzing the second derivative of the function:
f''(x) = 2e^(-x) + 2xe^(-x) + 2xe^(-x).(x + 1) - 2e^(-x).(x + 1)
= 2e^(-x).(1 - x)
Since the second derivative is positive for x < 1 and negative for x > 1, the function is concave up for x < 1 and concave down for x > 1. Thus, the critical point at x < 1 corresponds to a relative maximum.
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The lengths of pregnancies in a small rural village are normally distributed with a mean of 270 days and a standard deviation of 14 days. In what range would you expect to find the middle 98% of most pregnancies
We would expect to find the middle 98% of most pregnancies in the small rural village in the range of approximately 237 to 303 days.
We can use the properties of the normal distribution to determine the range in which we would expect to find the middle 98% of most pregnancies in the small rural village.
First, we need to find the z-scores associated with the upper and lower tails of the distribution that exclude the middle 2%. We can use a standard normal distribution table or calculator to find these values:
For the upper tail, the z-score is 2.33 (corresponding to a probability of 0.01 or 1%).
For the lower tail, the z-score is -2.33 (corresponding to a probability of 0.01 or 1%).
Next, we can use the formula for transforming a z-score into an actual value:
z = (x - μ) / σ
where z is the z-score, x is the actual value, μ is the mean, and σ is the standard deviation.
Substituting the values we know, we can solve for the upper and lower limits of the range:
For the upper limit:
2.33 = (x - 270) / 14
x - 270 = 32.62
x = 302.62
For the lower limit:
-2.33 = (x - 270) / 14
x - 270 = -32.62
x = 237.38
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Consider the set S = (v₁ = (1,0,0), v₂ = (0, 1,0), v₁ = (0, 0, 1), v₁ = (1, 1, 0), v = (1, 1, 1)). a) Give a subset of vectors from this set that is linearly independent but does not span R³. Explain why your answer works. b) Give a subset of vectors from this set that spans R³ but is not linearly independent. Explain why your answer works.
The subset S' = {(1,0,0), (0,1,0), (0,0,1)} is linearly independent but does not span R³, while the subset S'' = {(1,0,0), (0,1,0), (0,0,1), (1,1,0)} spans R³ but is not linearly independent.
a) To find a subset of vectors that is linearly independent but does not span R³, we can choose the subset S' = {(1,0,0), (0,1,0), (0,0,1)}. This subset forms the standard basis for R³, and it is linearly independent because no vector in the subset can be written as a linear combination of the others. However, it does not span R³ because it does not include vectors that have non-zero entries in all three components. For example, the vector (1,1,1) cannot be expressed as a linear combination of the vectors in S'.
b) To find a subset of vectors that spans R³ but is not linearly independent, we can choose the subset S'' = {(1,0,0), (0,1,0), (0,0,1), (1,1,0)}. This subset includes the vectors necessary to reach any point in R³ through linear combinations, satisfying the criterion for spanning R³. However, it is not linearly independent because the vector (1,1,0) can be written as a linear combination of the other three vectors. Specifically, (1,1,0) = (1,0,0) + (0,1,0).
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